TSTP Solution File: PUZ131_1 by Duper---1.0
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% File : Duper---1.0
% Problem : PUZ131_1 : TPTP v8.1.2. Released v5.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n025.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 13:14:49 EDT 2023
% Result : Theorem 3.46s 3.76s
% Output : Proof 3.46s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : PUZ131_1 : TPTP v8.1.2. Released v5.0.0.
% 0.00/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n025.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Sat Aug 26 23:07:23 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.46/3.76 SZS status Theorem for theBenchmark.p
% 3.46/3.76 SZS output start Proof for theBenchmark.p
% 3.46/3.76 Clause #4 (by assumption #[]): Eq (∀ (X : course), teaches (coordinatorof X) X) True
% 3.46/3.76 Clause #5 (by assumption #[]): Eq (∀ (X : student) (Y : course), enrolled X Y → ∀ (Z : professor), teaches Z Y → taughtby X Z) True
% 3.46/3.76 Clause #6 (by assumption #[]): Eq (enrolled michael csc410) True
% 3.46/3.76 Clause #7 (by assumption #[]): Eq (Eq (coordinatorof csc410) victor) True
% 3.46/3.76 Clause #8 (by assumption #[]): Eq (Not (taughtby michael victor)) True
% 3.46/3.76 Clause #9 (by clausification #[8]): Eq (taughtby michael victor) False
% 3.46/3.76 Clause #10 (by clausification #[7]): Eq (coordinatorof csc410) victor
% 3.46/3.76 Clause #11 (by clausification #[4]): ∀ (a : course), Eq (teaches (coordinatorof a) a) True
% 3.46/3.76 Clause #12 (by superposition #[11, 10]): Eq (teaches victor csc410) True
% 3.46/3.76 Clause #23 (by clausification #[5]): ∀ (a : student), Eq (∀ (Y : course), enrolled a Y → ∀ (Z : professor), teaches Z Y → taughtby a Z) True
% 3.46/3.76 Clause #24 (by clausification #[23]): ∀ (a : student) (a_1 : course), Eq (enrolled a a_1 → ∀ (Z : professor), teaches Z a_1 → taughtby a Z) True
% 3.46/3.76 Clause #25 (by clausification #[24]): ∀ (a : student) (a_1 : course),
% 3.46/3.76 Or (Eq (enrolled a a_1) False) (Eq (∀ (Z : professor), teaches Z a_1 → taughtby a Z) True)
% 3.46/3.76 Clause #26 (by clausification #[25]): ∀ (a : student) (a_1 : course) (a_2 : professor),
% 3.46/3.76 Or (Eq (enrolled a a_1) False) (Eq (teaches a_2 a_1 → taughtby a a_2) True)
% 3.46/3.76 Clause #27 (by clausification #[26]): ∀ (a : student) (a_1 : course) (a_2 : professor),
% 3.46/3.76 Or (Eq (enrolled a a_1) False) (Or (Eq (teaches a_2 a_1) False) (Eq (taughtby a a_2) True))
% 3.46/3.76 Clause #28 (by superposition #[27, 6]): ∀ (a : professor), Or (Eq (teaches a csc410) False) (Or (Eq (taughtby michael a) True) (Eq False True))
% 3.46/3.76 Clause #31 (by clausification #[28]): ∀ (a : professor), Or (Eq (teaches a csc410) False) (Eq (taughtby michael a) True)
% 3.46/3.76 Clause #32 (by superposition #[31, 12]): Or (Eq (taughtby michael victor) True) (Eq False True)
% 3.46/3.76 Clause #38 (by clausification #[32]): Eq (taughtby michael victor) True
% 3.46/3.76 Clause #39 (by superposition #[38, 9]): Eq True False
% 3.46/3.76 Clause #40 (by clausification #[39]): False
% 3.46/3.76 SZS output end Proof for theBenchmark.p
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