TSTP Solution File: PUZ130+1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : PUZ130+1 : TPTP v8.1.0. Released v4.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n019.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:11:39 EDT 2022

% Result   : Theorem 1.62s 1.84s
% Output   : Refutation 1.62s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :   11
% Syntax   : Number of clauses     :   17 (  13 unt;   0 nHn;  17 RR)
%            Number of literals    :   25 (   3 equ;   9 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    9 (   7 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   3 con; 0-1 aty)
%            Number of variables   :    6 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ dog(A)
    | pet(A) ),
    file('PUZ130+1.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ cat(A)
    | pet(A) ),
    file('PUZ130+1.p',unknown),
    [] ).

cnf(8,axiom,
    ( ~ cat(A)
    | ~ dog(B)
    | ~ chased(B,A)
    | hates(owner_of(A),owner_of(B)) ),
    file('PUZ130+1.p',unknown),
    [] ).

cnf(9,axiom,
    ( ~ human(A)
    | ~ pet(B)
    | ~ owner(A,B)
    | A = owner_of(B) ),
    file('PUZ130+1.p',unknown),
    [] ).

cnf(11,axiom,
    ~ hates(jon,jon),
    file('PUZ130+1.p',unknown),
    [] ).

cnf(14,axiom,
    cat(garfield),
    file('PUZ130+1.p',unknown),
    [] ).

cnf(16,axiom,
    dog(odie),
    file('PUZ130+1.p',unknown),
    [] ).

cnf(19,axiom,
    human(jon),
    file('PUZ130+1.p',unknown),
    [] ).

cnf(20,axiom,
    owner(jon,odie),
    file('PUZ130+1.p',unknown),
    [] ).

cnf(21,axiom,
    owner(jon,garfield),
    file('PUZ130+1.p',unknown),
    [] ).

cnf(24,axiom,
    chased(odie,garfield),
    file('PUZ130+1.p',unknown),
    [] ).

cnf(28,plain,
    pet(garfield),
    inference(hyper,[status(thm)],[14,2]),
    [iquote('hyper,14,2')] ).

cnf(34,plain,
    pet(odie),
    inference(hyper,[status(thm)],[16,1]),
    [iquote('hyper,16,1')] ).

cnf(62,plain,
    owner_of(odie) = jon,
    inference(flip,[status(thm),theory(equality)],[inference(hyper,[status(thm)],[34,9,19,20])]),
    [iquote('hyper,34,9,19,20,flip.1')] ).

cnf(67,plain,
    owner_of(garfield) = jon,
    inference(flip,[status(thm),theory(equality)],[inference(hyper,[status(thm)],[21,9,19,28])]),
    [iquote('hyper,21,9,19,28,flip.1')] ).

cnf(72,plain,
    hates(jon,jon),
    inference(demod,[status(thm),theory(equality)],[inference(hyper,[status(thm)],[24,8,14,16]),67,62]),
    [iquote('hyper,24,8,14,16,demod,67,62')] ).

cnf(73,plain,
    $false,
    inference(binary,[status(thm)],[72,11]),
    [iquote('binary,72.1,11.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem  : PUZ130+1 : TPTP v8.1.0. Released v4.1.0.
% 0.10/0.12  % Command  : otter-tptp-script %s
% 0.12/0.34  % Computer : n019.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 300
% 0.12/0.34  % DateTime : Wed Jul 27 01:51:07 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 1.62/1.83  ----- Otter 3.3f, August 2004 -----
% 1.62/1.83  The process was started by sandbox2 on n019.cluster.edu,
% 1.62/1.83  Wed Jul 27 01:51:07 2022
% 1.62/1.83  The command was "./otter".  The process ID is 21034.
% 1.62/1.83  
% 1.62/1.83  set(prolog_style_variables).
% 1.62/1.83  set(auto).
% 1.62/1.83     dependent: set(auto1).
% 1.62/1.83     dependent: set(process_input).
% 1.62/1.83     dependent: clear(print_kept).
% 1.62/1.83     dependent: clear(print_new_demod).
% 1.62/1.83     dependent: clear(print_back_demod).
% 1.62/1.83     dependent: clear(print_back_sub).
% 1.62/1.83     dependent: set(control_memory).
% 1.62/1.83     dependent: assign(max_mem, 12000).
% 1.62/1.83     dependent: assign(pick_given_ratio, 4).
% 1.62/1.83     dependent: assign(stats_level, 1).
% 1.62/1.83     dependent: assign(max_seconds, 10800).
% 1.62/1.83  clear(print_given).
% 1.62/1.83  
% 1.62/1.83  formula_list(usable).
% 1.62/1.83  all A (A=A).
% 1.62/1.83  exists A cat(A).
% 1.62/1.83  cat(garfield).
% 1.62/1.83  exists A dog(A).
% 1.62/1.83  dog(odie).
% 1.62/1.83  exists A pet(A).
% 1.62/1.83  all A (dog(A)->pet(A)).
% 1.62/1.83  all A (cat(A)->pet(A)).
% 1.62/1.83  exists A human(A).
% 1.62/1.83  human(jon).
% 1.62/1.83  all A (pet(A)->human(owner_of(A))).
% 1.62/1.83  all X (pet(X)-> (exists Y (human(Y)&owner(X,Y)))).
% 1.62/1.83  owner(jon,odie).
% 1.62/1.83  owner(jon,garfield).
% 1.62/1.83  all X ((all X (cat(X)->owner(jon,X)))->X=garfield).
% 1.62/1.83  all X ((all X (dog(X)->owner(jon,X)))->X=odie).
% 1.62/1.83  all X Y (cat(X)&dog(Y)-> (chased(Y,X)->hates(owner_of(X),owner_of(Y)))).
% 1.62/1.83  all X Y (human(X)&pet(Y)-> (owner(X,Y)<->X=owner_of(Y))).
% 1.62/1.83  chased(odie,garfield).
% 1.62/1.83  -hates(jon,jon).
% 1.62/1.83  end_of_list.
% 1.62/1.83  
% 1.62/1.83  -------> usable clausifies to:
% 1.62/1.83  
% 1.62/1.83  list(usable).
% 1.62/1.83  0 [] A=A.
% 1.62/1.83  0 [] cat($c1).
% 1.62/1.83  0 [] cat(garfield).
% 1.62/1.83  0 [] dog($c2).
% 1.62/1.83  0 [] dog(odie).
% 1.62/1.83  0 [] pet($c3).
% 1.62/1.83  0 [] -dog(A)|pet(A).
% 1.62/1.83  0 [] -cat(A)|pet(A).
% 1.62/1.83  0 [] human($c4).
% 1.62/1.83  0 [] human(jon).
% 1.62/1.83  0 [] -pet(A)|human(owner_of(A)).
% 1.62/1.83  0 [] -pet(X)|human($f1(X)).
% 1.62/1.83  0 [] -pet(X)|owner(X,$f1(X)).
% 1.62/1.83  0 [] owner(jon,odie).
% 1.62/1.83  0 [] owner(jon,garfield).
% 1.62/1.83  0 [] cat($f2(X))|X=garfield.
% 1.62/1.83  0 [] -owner(jon,$f2(X))|X=garfield.
% 1.62/1.83  0 [] dog($f3(X))|X=odie.
% 1.62/1.83  0 [] -owner(jon,$f3(X))|X=odie.
% 1.62/1.83  0 [] -cat(X)| -dog(Y)| -chased(Y,X)|hates(owner_of(X),owner_of(Y)).
% 1.62/1.83  0 [] -human(X)| -pet(Y)| -owner(X,Y)|X=owner_of(Y).
% 1.62/1.83  0 [] -human(X)| -pet(Y)|owner(X,Y)|X!=owner_of(Y).
% 1.62/1.83  0 [] chased(odie,garfield).
% 1.62/1.83  0 [] -hates(jon,jon).
% 1.62/1.83  end_of_list.
% 1.62/1.83  
% 1.62/1.83  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=4.
% 1.62/1.83  
% 1.62/1.83  This ia a non-Horn set with equality.  The strategy will be
% 1.62/1.84  Knuth-Bendix, ordered hyper_res, factoring, and unit
% 1.62/1.84  deletion, with positive clauses in sos and nonpositive
% 1.62/1.84  clauses in usable.
% 1.62/1.84  
% 1.62/1.84     dependent: set(knuth_bendix).
% 1.62/1.84     dependent: set(anl_eq).
% 1.62/1.84     dependent: set(para_from).
% 1.62/1.84     dependent: set(para_into).
% 1.62/1.84     dependent: clear(para_from_right).
% 1.62/1.84     dependent: clear(para_into_right).
% 1.62/1.84     dependent: set(para_from_vars).
% 1.62/1.84     dependent: set(eq_units_both_ways).
% 1.62/1.84     dependent: set(dynamic_demod_all).
% 1.62/1.84     dependent: set(dynamic_demod).
% 1.62/1.84     dependent: set(order_eq).
% 1.62/1.84     dependent: set(back_demod).
% 1.62/1.84     dependent: set(lrpo).
% 1.62/1.84     dependent: set(hyper_res).
% 1.62/1.84     dependent: set(unit_deletion).
% 1.62/1.84     dependent: set(factor).
% 1.62/1.84  
% 1.62/1.84  ------------> process usable:
% 1.62/1.84  ** KEPT (pick-wt=4): 1 [] -dog(A)|pet(A).
% 1.62/1.84  ** KEPT (pick-wt=4): 2 [] -cat(A)|pet(A).
% 1.62/1.84  ** KEPT (pick-wt=5): 3 [] -pet(A)|human(owner_of(A)).
% 1.62/1.84  ** KEPT (pick-wt=5): 4 [] -pet(A)|human($f1(A)).
% 1.62/1.84  ** KEPT (pick-wt=6): 5 [] -pet(A)|owner(A,$f1(A)).
% 1.62/1.84  ** KEPT (pick-wt=7): 6 [] -owner(jon,$f2(A))|A=garfield.
% 1.62/1.84  ** KEPT (pick-wt=7): 7 [] -owner(jon,$f3(A))|A=odie.
% 1.62/1.84  ** KEPT (pick-wt=12): 8 [] -cat(A)| -dog(B)| -chased(B,A)|hates(owner_of(A),owner_of(B)).
% 1.62/1.84  ** KEPT (pick-wt=11): 9 [] -human(A)| -pet(B)| -owner(A,B)|A=owner_of(B).
% 1.62/1.84  ** KEPT (pick-wt=11): 10 [] -human(A)| -pet(B)|owner(A,B)|A!=owner_of(B).
% 1.62/1.84  ** KEPT (pick-wt=3): 11 [] -hates(jon,jon).
% 1.62/1.84  
% 1.62/1.84  ------------> process sos:
% 1.62/1.84  ** KEPT (pick-wt=3): 12 [] A=A.
% 1.62/1.84  ** KEPT (pick-wt=2): 13 [] cat($c1).
% 1.62/1.84  ** KEPT (pick-wt=2): 14 [] cat(garfield).
% 1.62/1.84  ** KEPT (pick-wt=2): 15 [] dog($c2).
% 1.62/1.84  ** KEPT (pick-wt=2): 16 [] dog(odie).
% 1.62/1.84  ** KEPT (pick-wt=2): 17 [] pet($c3).
% 1.62/1.84  ** KEPT (pick-wt=2): 18 [] human($c4).
% 1.62/1.84  ** KEPT (pick-wt=2): 19 [] human(jon).
% 1.62/1.84  ** KEPT (pick-wt=3): 20 [] owner(jon,odie).
% 1.62/1.84  ** KEPT (pick-wt=3): 21 [] owner(jon,garfield).
% 1.62/1.84  ** KEPT (pick-wt=6): 22 [] cat($f2(A))|A=garfield.
% 1.62/1.84  ** KEPT (pick-wt=6): 23 [] dog($f3(A))|A=odie.
% 1.62/1.84  ** KEPT (pick-wt=3): 24 [] chased(odie,garfield).
% 1.62/1.84    Following clause subsumed by 12 during input processing: 0 [copy,12,flip.1] A=A.
% 1.62/1.84  
% 1.62/1.84  ======= end of input processing =======
% 1.62/1.84  
% 1.62/1.84  =========== start of search ===========
% 1.62/1.84  
% 1.62/1.84  -------- PROOF -------- 
% 1.62/1.84  
% 1.62/1.84  ----> UNIT CONFLICT at   0.00 sec ----> 73 [binary,72.1,11.1] $F.
% 1.62/1.84  
% 1.62/1.84  Length of proof is 5.  Level of proof is 3.
% 1.62/1.84  
% 1.62/1.84  ---------------- PROOF ----------------
% 1.62/1.84  % SZS status Theorem
% 1.62/1.84  % SZS output start Refutation
% See solution above
% 1.62/1.84  ------------ end of proof -------------
% 1.62/1.84  
% 1.62/1.84  
% 1.62/1.84  Search stopped by max_proofs option.
% 1.62/1.84  
% 1.62/1.84  
% 1.62/1.84  Search stopped by max_proofs option.
% 1.62/1.84  
% 1.62/1.84  ============ end of search ============
% 1.62/1.84  
% 1.62/1.84  -------------- statistics -------------
% 1.62/1.84  clauses given                 15
% 1.62/1.84  clauses generated             67
% 1.62/1.84  clauses kept                  70
% 1.62/1.84  clauses forward subsumed      23
% 1.62/1.84  clauses back subsumed          0
% 1.62/1.84  Kbytes malloced              976
% 1.62/1.84  
% 1.62/1.84  ----------- times (seconds) -----------
% 1.62/1.84  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.62/1.84  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.62/1.84  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.62/1.84  
% 1.62/1.84  That finishes the proof of the theorem.
% 1.62/1.84  
% 1.62/1.84  Process 21034 finished Wed Jul 27 01:51:08 2022
% 1.62/1.84  Otter interrupted
% 1.62/1.84  PROOF FOUND
%------------------------------------------------------------------------------