TSTP Solution File: PUZ129+2 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : PUZ129+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 18:27:09 EDT 2022

% Result   : Theorem 0.86s 1.07s
% Output   : Refutation 0.86s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.14  % Problem  : PUZ129+2 : TPTP v8.1.0. Released v4.0.0.
% 0.14/0.15  % Command  : sos-script %s
% 0.14/0.36  % Computer : n020.cluster.edu
% 0.14/0.36  % Model    : x86_64 x86_64
% 0.14/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36  % Memory   : 8042.1875MB
% 0.14/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36  % CPULimit : 300
% 0.14/0.36  % WCLimit  : 600
% 0.14/0.36  % DateTime : Sat May 28 21:13:54 EDT 2022
% 0.14/0.37  % CPUTime  : 
% 0.14/0.39  ----- Otter 3.2, August 2001 -----
% 0.14/0.39  The process was started by sandbox on n020.cluster.edu,
% 0.14/0.39  Sat May 28 21:13:54 2022
% 0.14/0.39  The command was "./sos".  The process ID is 29153.
% 0.14/0.39  
% 0.14/0.39  set(prolog_style_variables).
% 0.14/0.39  set(auto).
% 0.14/0.39     dependent: set(auto1).
% 0.14/0.39     dependent: set(process_input).
% 0.14/0.39     dependent: clear(print_kept).
% 0.14/0.39     dependent: clear(print_new_demod).
% 0.14/0.39     dependent: clear(print_back_demod).
% 0.14/0.39     dependent: clear(print_back_sub).
% 0.14/0.39     dependent: set(control_memory).
% 0.14/0.39     dependent: assign(max_mem, 12000).
% 0.14/0.39     dependent: assign(pick_given_ratio, 4).
% 0.14/0.39     dependent: assign(stats_level, 1).
% 0.14/0.39     dependent: assign(pick_semantic_ratio, 3).
% 0.14/0.39     dependent: assign(sos_limit, 5000).
% 0.14/0.39     dependent: assign(max_weight, 60).
% 0.14/0.39  clear(print_given).
% 0.14/0.39  
% 0.14/0.39  formula_list(usable).
% 0.14/0.39  
% 0.14/0.39  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=4.
% 0.14/0.39  
% 0.14/0.39  This is a Horn set with equality.  The strategy will be
% 0.14/0.39  Knuth-Bendix and hyper_res, with positive clauses in
% 0.14/0.39  sos and nonpositive clauses in usable.
% 0.14/0.39  
% 0.14/0.39     dependent: set(knuth_bendix).
% 0.14/0.39     dependent: set(para_from).
% 0.14/0.39     dependent: set(para_into).
% 0.14/0.39     dependent: clear(para_from_right).
% 0.14/0.39     dependent: clear(para_into_right).
% 0.14/0.39     dependent: set(para_from_vars).
% 0.14/0.39     dependent: set(eq_units_both_ways).
% 0.14/0.39     dependent: set(dynamic_demod_all).
% 0.14/0.39     dependent: set(dynamic_demod).
% 0.14/0.39     dependent: set(order_eq).
% 0.14/0.39     dependent: set(back_demod).
% 0.14/0.39     dependent: set(lrpo).
% 0.14/0.39     dependent: set(hyper_res).
% 0.14/0.39     dependent: clear(order_hyper).
% 0.14/0.39  
% 0.14/0.39  ------------> process usable:
% 0.14/0.39  
% 0.14/0.39  ------------> process sos:
% 0.14/0.39    Following clause subsumed by 26 during input processing: 0 [copy,26,flip.1] {-} A=A.
% 0.14/0.39  
% 0.14/0.39  ======= end of input processing =======
% 0.40/0.57  
% 0.40/0.57  Model 1 (0.00 seconds, 0 Inserts)
% 0.40/0.57  
% 0.40/0.57  Stopped by limit on number of solutions
% 0.40/0.57  
% 0.40/0.57  
% 0.40/0.57  -------------- Softie stats --------------
% 0.40/0.57  
% 0.40/0.57  UPDATE_STOP: 300
% 0.40/0.57  SFINDER_TIME_LIMIT: 2
% 0.40/0.57  SHORT_CLAUSE_CUTOFF: 4
% 0.40/0.57  number of clauses in intial UL: 15
% 0.40/0.57  number of clauses initially in problem: 20
% 0.40/0.57  percentage of clauses intially in UL: 75
% 0.40/0.57  percentage of distinct symbols occuring in initial UL: 89
% 0.40/0.57  percent of all initial clauses that are short: 100
% 0.40/0.57  absolute distinct symbol count: 19
% 0.40/0.57     distinct predicate count: 5
% 0.40/0.57     distinct function count: 6
% 0.40/0.57     distinct constant count: 8
% 0.40/0.57  
% 0.40/0.57  ---------- no more Softie stats ----------
% 0.40/0.57  
% 0.40/0.57  
% 0.40/0.57  
% 0.40/0.57  Stopped by limit on insertions
% 0.40/0.57  
% 0.40/0.57  =========== start of search ===========
% 0.86/1.07  
% 0.86/1.07  -------- PROOF -------- 
% 0.86/1.07  % SZS status Theorem
% 0.86/1.07  % SZS output start Refutation
% 0.86/1.07  
% 0.86/1.07  Stopped by limit on insertions
% 0.86/1.07  
% 0.86/1.07  Stopped by limit on insertions
% 0.86/1.07  
% 0.86/1.07  Model 2 [ 1 0 194 ] (0.00 seconds, 250000 Inserts)
% 0.86/1.07  
% 0.86/1.07  Stopped by limit on insertions
% 0.86/1.07  
% 0.86/1.07  Model 3 [ 1 0 95 ] (0.00 seconds, 250000 Inserts)
% 0.86/1.07  
% 0.86/1.07  Stopped by limit on insertions
% 0.86/1.07  
% 0.86/1.07  Model 4 [ 1 1 116 ] (0.00 seconds, 250000 Inserts)
% 0.86/1.07  
% 0.86/1.07  Stopped by limit on insertions
% 0.86/1.07  
% 0.86/1.07  Model 5 [ 1 0 199 ] (0.00 seconds, 250000 Inserts)
% 0.86/1.07  
% 0.86/1.07  Stopped by limit on insertions
% 0.86/1.07  
% 0.86/1.07  Model 6 [ 1 0 366 ] (0.00 seconds, 250000 Inserts)
% 0.86/1.07  
% 0.86/1.07  -----> EMPTY CLAUSE at   0.66 sec ----> 42 [hyper,41,4,27,26] {-} $F.
% 0.86/1.07  
% 0.86/1.07  Length of proof is 13.  Level of proof is 7.
% 0.86/1.07  
% 0.86/1.07  ---------------- PROOF ----------------
% 0.86/1.07  % SZS status Theorem
% 0.86/1.07  % SZS output start Refutation
% 0.86/1.07  
% 0.86/1.07  1 [] {+} -person(A)| -property1(A,honest,pos)| -property1(A,industrious,pos)|property1($f1(A),healthy,pos).
% 0.86/1.07  2 [] {-} -person(A)| -property1(A,honest,pos)| -property1(A,industrious,pos)|A=$f1(A).
% 0.86/1.07  3 [copy,2,flip.4] {+} -person(A)| -property1(A,honest,pos)| -property1(A,industrious,pos)|$f1(A)=A.
% 0.86/1.07  4 [] {+} -grocer(A)| -property1(B,healthy,pos)|A!=B.
% 0.86/1.07  5 [] {+} -grocer(A)| -property1(A,industrious,pos)|property1($f2(A),honest,pos).
% 0.86/1.07  6 [] {-} -grocer(A)| -property1(A,industrious,pos)|A=$f2(A).
% 0.86/1.07  7 [copy,6,flip.3] {+} -grocer(A)| -property1(A,industrious,pos)|$f2(A)=A.
% 0.86/1.07  8 [] {+} -cyclist(A)|property1($f3(A),industrious,pos).
% 0.86/1.07  9 [] {-} -cyclist(A)|A=$f3(A).
% 0.86/1.07  10 [copy,9,flip.2] {+} -cyclist(A)|$f3(A)=A.
% 0.86/1.07  19 [] {+} -cyclist(A)|person($f6(A)).
% 0.86/1.07  20 [] {-} -cyclist(A)|A=$f6(A).
% 0.86/1.07  21 [copy,20,flip.2] {+} -cyclist(A)|$f6(A)=A.
% 0.86/1.07  22 [] {-} grocer($c2).
% 0.86/1.07  23 [] {-} cyclist($c1).
% 0.86/1.07  25,24 [] {+} $c2=$c1.
% 0.86/1.07  26 [] {+} A=A.
% 0.86/1.07  27 [back_demod,22,demod,25] {-} grocer($c1).
% 0.86/1.07  29,28 [hyper,23,21] {+} $f6($c1)=$c1.
% 0.86/1.07  30 [hyper,23,19,demod,29] {+} person($c1).
% 0.86/1.07  32,31 [hyper,23,10] {+} $f3($c1)=$c1.
% 0.86/1.07  33 [hyper,23,8,demod,32] {+} property1($c1,industrious,pos).
% 0.86/1.07  37,36 [hyper,33,7,27] {+} $f2($c1)=$c1.
% 0.86/1.07  38 [hyper,33,5,27,demod,37] {+} property1($c1,honest,pos).
% 0.86/1.07  40,39 [hyper,38,3,30,33] {+} $f1($c1)=$c1.
% 0.86/1.07  41 [hyper,38,1,30,33,demod,40] {+} property1($c1,healthy,pos).
% 0.86/1.07  42 [hyper,41,4,27,26] {-} $F.
% 0.86/1.07  
% 0.86/1.07  % SZS output end Refutation
% 0.86/1.07  ------------ end of proof -------------
% 0.86/1.07  
% 0.86/1.07  
% 0.86/1.07  Search stopped by max_proofs option.
% 0.86/1.07  
% 0.86/1.07  
% 0.86/1.07  Search stopped by max_proofs option.
% 0.86/1.07  
% 0.86/1.07  ============ end of search ============
% 0.86/1.07  
% 0.86/1.07  ----------- soft-scott stats ----------
% 0.86/1.07  
% 0.86/1.07  true clauses given           6      (46.2%)
% 0.86/1.07  false clauses given          7
% 0.86/1.07  
% 0.86/1.07        FALSE     TRUE
% 0.86/1.07  tot:  0         0      (-nan% true)
% 0.86/1.07  
% 0.86/1.07  
% 0.86/1.07  Model 6 [ 1 0 366 ] (0.00 seconds, 250000 Inserts)
% 0.86/1.07  
% 0.86/1.07  That finishes the proof of the theorem.
% 0.86/1.07  
% 0.86/1.07  Process 29153 finished Sat May 28 21:13:55 2022
%------------------------------------------------------------------------------