TSTP Solution File: PUZ063-2 by SOS---2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : SOS---2.0
% Problem : PUZ063-2 : TPTP v8.1.0. Released v3.2.0.
% Transfm : none
% Format : tptp:raw
% Command : sos-script %s
% Computer : n019.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 18:27:05 EDT 2022
% Result : Unsatisfiable 0.13s 0.36s
% Output : Refutation 0.13s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12 % Problem : PUZ063-2 : TPTP v8.1.0. Released v3.2.0.
% 0.06/0.13 % Command : sos-script %s
% 0.13/0.34 % Computer : n019.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Sat May 28 20:57:41 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.13/0.36
% 0.13/0.36 -------- PROOF --------
% 0.13/0.36 % SZS status Unsatisfiable
% 0.13/0.36 % SZS output start Refutation
% 0.13/0.36 ----- Otter 3.2, August 2001 -----
% 0.13/0.36 The process was started by sandbox on n019.cluster.edu,
% 0.13/0.36 Sat May 28 20:57:41 2022
% 0.13/0.36 The command was "./sos". The process ID is 22260.
% 0.13/0.36
% 0.13/0.36 set(prolog_style_variables).
% 0.13/0.36 set(auto).
% 0.13/0.36 dependent: set(auto1).
% 0.13/0.36 dependent: set(process_input).
% 0.13/0.36 dependent: clear(print_kept).
% 0.13/0.36 dependent: clear(print_new_demod).
% 0.13/0.36 dependent: clear(print_back_demod).
% 0.13/0.36 dependent: clear(print_back_sub).
% 0.13/0.36 dependent: set(control_memory).
% 0.13/0.36 dependent: assign(max_mem, 12000).
% 0.13/0.36 dependent: assign(pick_given_ratio, 4).
% 0.13/0.36 dependent: assign(stats_level, 1).
% 0.13/0.36 dependent: assign(pick_semantic_ratio, 3).
% 0.13/0.36 dependent: assign(sos_limit, 5000).
% 0.13/0.36 dependent: assign(max_weight, 60).
% 0.13/0.36 clear(print_given).
% 0.13/0.36
% 0.13/0.36 list(usable).
% 0.13/0.36
% 0.13/0.36 SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 0.13/0.36
% 0.13/0.36 All clauses are units, and equality is present; the
% 0.13/0.36 strategy will be Knuth-Bendix with positive clauses in sos.
% 0.13/0.36
% 0.13/0.36 dependent: set(knuth_bendix).
% 0.13/0.36 dependent: set(para_from).
% 0.13/0.36 dependent: set(para_into).
% 0.13/0.36 dependent: clear(para_from_right).
% 0.13/0.36 dependent: clear(para_into_right).
% 0.13/0.36 dependent: set(para_from_vars).
% 0.13/0.36 dependent: set(eq_units_both_ways).
% 0.13/0.36 dependent: set(dynamic_demod_all).
% 0.13/0.36 dependent: set(dynamic_demod).
% 0.13/0.36 dependent: set(order_eq).
% 0.13/0.36 dependent: set(back_demod).
% 0.13/0.36 dependent: set(lrpo).
% 0.13/0.36
% 0.13/0.36 ------------> process usable:
% 0.13/0.36
% 0.13/0.36 ------------> process sos:
% 0.13/0.36
% 0.13/0.36 ----> UNIT CONFLICT at 0.00 sec ----> 7 [binary,6.1,2.1] {-} $F.
% 0.13/0.36
% 0.13/0.36 Length of proof is 1. Level of proof is 1.
% 0.13/0.36
% 0.13/0.36 ---------------- PROOF ----------------
% 0.13/0.36 % SZS status Unsatisfiable
% 0.13/0.36 % SZS output start Refutation
% 0.13/0.36
% 0.13/0.36 1 [] {-} -c_in(c_union(c_emptyset,v_u,t_a),c_Mutil_Otiling(v_A,t_a),tc_set(t_a)).
% 0.13/0.36 2 [] {-} c_in(v_u,c_Mutil_Otiling(v_A,t_a),tc_set(t_a)).
% 0.13/0.36 4,3 [] {-} c_union(c_emptyset,A,B)=A.
% 0.13/0.36 6 [back_demod,1,demod,4] {-} -c_in(v_u,c_Mutil_Otiling(v_A,t_a),tc_set(t_a)).
% 0.13/0.36 7 [binary,6.1,2.1] {-} $F.
% 0.13/0.36
% 0.13/0.36 % SZS output end Refutation
% 0.13/0.36 ------------ end of proof -------------
% 0.13/0.36
% 0.13/0.36
% 0.13/0.36 Search stopped by max_proofs option.
% 0.13/0.36
% 0.13/0.36
% 0.13/0.36 Search stopped by max_proofs option.
% 0.13/0.36
% 0.13/0.36 ============ end of search ============
% 0.13/0.36
% 0.13/0.36 That finishes the proof of the theorem.
% 0.13/0.36
% 0.13/0.36 Process 22260 finished Sat May 28 20:57:41 2022
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