TSTP Solution File: NUN067+2 by SOS---2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : SOS---2.0
% Problem : NUN067+2 : TPTP v8.1.0. Released v7.3.0.
% Transfm : none
% Format : tptp:raw
% Command : sos-script %s
% Computer : n017.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 16:38:30 EDT 2022
% Result : Theorem 0.21s 0.43s
% Output : Refutation 0.21s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.13 % Problem : NUN067+2 : TPTP v8.1.0. Released v7.3.0.
% 0.07/0.14 % Command : sos-script %s
% 0.15/0.35 % Computer : n017.cluster.edu
% 0.15/0.35 % Model : x86_64 x86_64
% 0.15/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35 % Memory : 8042.1875MB
% 0.15/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.35 % CPULimit : 300
% 0.15/0.35 % WCLimit : 600
% 0.15/0.35 % DateTime : Thu Jun 2 03:59:12 EDT 2022
% 0.15/0.35 % CPUTime :
% 0.15/0.37 ----- Otter 3.2, August 2001 -----
% 0.15/0.37 The process was started by sandbox2 on n017.cluster.edu,
% 0.15/0.37 Thu Jun 2 03:59:12 2022
% 0.15/0.37 The command was "./sos". The process ID is 20727.
% 0.15/0.37
% 0.15/0.37 set(prolog_style_variables).
% 0.15/0.37 set(auto).
% 0.15/0.37 dependent: set(auto1).
% 0.15/0.37 dependent: set(process_input).
% 0.15/0.37 dependent: clear(print_kept).
% 0.15/0.37 dependent: clear(print_new_demod).
% 0.15/0.37 dependent: clear(print_back_demod).
% 0.15/0.37 dependent: clear(print_back_sub).
% 0.15/0.37 dependent: set(control_memory).
% 0.15/0.37 dependent: assign(max_mem, 12000).
% 0.15/0.37 dependent: assign(pick_given_ratio, 4).
% 0.15/0.37 dependent: assign(stats_level, 1).
% 0.15/0.37 dependent: assign(pick_semantic_ratio, 3).
% 0.15/0.37 dependent: assign(sos_limit, 5000).
% 0.15/0.37 dependent: assign(max_weight, 60).
% 0.15/0.37 clear(print_given).
% 0.15/0.37
% 0.15/0.37 formula_list(usable).
% 0.15/0.37
% 0.15/0.37 SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=4.
% 0.15/0.37
% 0.15/0.37 This ia a non-Horn set with equality. The strategy will be
% 0.15/0.37 Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.15/0.37 unit deletion, with positive clauses in sos and nonpositive
% 0.15/0.37 clauses in usable.
% 0.15/0.37
% 0.15/0.37 dependent: set(knuth_bendix).
% 0.15/0.37 dependent: set(para_from).
% 0.15/0.37 dependent: set(para_into).
% 0.15/0.37 dependent: clear(para_from_right).
% 0.15/0.37 dependent: clear(para_into_right).
% 0.15/0.37 dependent: set(para_from_vars).
% 0.15/0.37 dependent: set(eq_units_both_ways).
% 0.15/0.37 dependent: set(dynamic_demod_all).
% 0.15/0.37 dependent: set(dynamic_demod).
% 0.15/0.37 dependent: set(order_eq).
% 0.15/0.37 dependent: set(back_demod).
% 0.15/0.37 dependent: set(lrpo).
% 0.15/0.37 dependent: set(hyper_res).
% 0.15/0.37 dependent: set(unit_deletion).
% 0.15/0.37 dependent: set(factor).
% 0.15/0.37
% 0.15/0.37 ------------> process usable:
% 0.15/0.37
% 0.15/0.37 ------------> process sos:
% 0.15/0.37 Following clause subsumed by 46 during input processing: 0 [copy,46,flip.1] {-} A=A.
% 0.15/0.37 46 back subsumes 11.
% 0.15/0.37 50 back subsumes 37.
% 0.15/0.37 50 back subsumes 35.
% 0.15/0.37 50 back subsumes 32.
% 0.15/0.37 50 back subsumes 30.
% 0.15/0.37 50 back subsumes 26.
% 0.15/0.37 50 back subsumes 2.
% 0.15/0.37
% 0.15/0.37 ======= end of input processing =======
% 0.15/0.41
% 0.15/0.41 Model 1 (0.00 seconds, 0 Inserts)
% 0.15/0.41
% 0.15/0.41 Stopped by limit on number of solutions
% 0.15/0.41
% 0.15/0.41
% 0.15/0.41 -------------- Softie stats --------------
% 0.15/0.41
% 0.15/0.41 UPDATE_STOP: 300
% 0.15/0.41 SFINDER_TIME_LIMIT: 2
% 0.15/0.41 SHORT_CLAUSE_CUTOFF: 4
% 0.15/0.41 number of clauses in intial UL: 9
% 0.15/0.41 number of clauses initially in problem: 33
% 0.15/0.41 percentage of clauses intially in UL: 27
% 0.15/0.41 percentage of distinct symbols occuring in initial UL: 34
% 0.15/0.41 percent of all initial clauses that are short: 100
% 0.15/0.41 absolute distinct symbol count: 26
% 0.15/0.41 distinct predicate count: 5
% 0.15/0.41 distinct function count: 20
% 0.15/0.41 distinct constant count: 1
% 0.15/0.41
% 0.15/0.41 ---------- no more Softie stats ----------
% 0.15/0.41
% 0.15/0.41
% 0.15/0.41
% 0.15/0.41 Model 2 (0.00 seconds, 0 Inserts)
% 0.15/0.41
% 0.15/0.41 Stopped by limit on number of solutions
% 0.15/0.41
% 0.15/0.41 =========== start of search ===========
% 0.21/0.43
% 0.21/0.43 -------- PROOF --------
% 0.21/0.43 % SZS status Theorem
% 0.21/0.43 % SZS output start Refutation
% 0.21/0.43
% 0.21/0.43 -----> EMPTY CLAUSE at 0.03 sec ----> 64 [hyper,58,10,50,57] {-} $F.
% 0.21/0.43
% 0.21/0.43 Length of proof is 4. Level of proof is 3.
% 0.21/0.43
% 0.21/0.43 ---------------- PROOF ----------------
% 0.21/0.43 % SZS status Theorem
% 0.21/0.43 % SZS output start Refutation
% 0.21/0.43
% 0.21/0.43 1 [] {+} -r1(A)|A=$c1.
% 0.21/0.43 10 [] {+} -r1(A)|A!=B| -r2(C,B).
% 0.21/0.43 12 [] {+} r2(A,$f4(B,A)).
% 0.21/0.43 42 [] {-} r1($f20(A)).
% 0.21/0.43 43 [] {-} A=$f20(A).
% 0.21/0.43 45,44 [copy,43,flip.1] {-} $f20(A)=A.
% 0.21/0.43 50 [back_demod,42,demod,45] {-} r1(A).
% 0.21/0.43 57 [para_into,12.1.2,1.2.1,unit_del,50] {-} r2(A,$c1).
% 0.21/0.43 58 [hyper,50,1] {-} A=$c1.
% 0.21/0.43 64 [hyper,58,10,50,57] {-} $F.
% 0.21/0.43
% 0.21/0.43 % SZS output end Refutation
% 0.21/0.43 ------------ end of proof -------------
% 0.21/0.43
% 0.21/0.43
% 0.21/0.43 Search stopped by max_proofs option.
% 0.21/0.43
% 0.21/0.43
% 0.21/0.43 Search stopped by max_proofs option.
% 0.21/0.43
% 0.21/0.43 ============ end of search ============
% 0.21/0.43
% 0.21/0.43 ----------- soft-scott stats ----------
% 0.21/0.43
% 0.21/0.43 true clauses given 0 (0.0%)
% 0.21/0.43 false clauses given 4
% 0.21/0.43
% 0.21/0.43 FALSE TRUE
% 0.21/0.43 3 1 1
% 0.21/0.43 4 3 0
% 0.21/0.43 5 3 0
% 0.21/0.43 6 3 2
% 0.21/0.43 7 3 0
% 0.21/0.43 8 4 0
% 0.21/0.43 9 3 0
% 0.21/0.43 11 0 2
% 0.21/0.43 12 1 0
% 0.21/0.43 14 0 1
% 0.21/0.43 tot: 21 6 (22.2% true)
% 0.21/0.43
% 0.21/0.43
% 0.21/0.43 Model 2 (0.00 seconds, 0 Inserts)
% 0.21/0.43
% 0.21/0.43 That finishes the proof of the theorem.
% 0.21/0.43
% 0.21/0.43 Process 20727 finished Thu Jun 2 03:59:12 2022
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