TSTP Solution File: NUM970_5 by Duper---1.0
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%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : NUM970_5 : TPTP v8.1.2. Released v6.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n026.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:58:28 EDT 2023
% Result : Theorem 8.41s 8.56s
% Output : Proof 8.41s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : NUM970_5 : TPTP v8.1.2. Released v6.0.0.
% 0.00/0.14 % Command : duper %s
% 0.15/0.35 % Computer : n026.cluster.edu
% 0.15/0.35 % Model : x86_64 x86_64
% 0.15/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35 % Memory : 8042.1875MB
% 0.15/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.35 % CPULimit : 300
% 0.15/0.36 % WCLimit : 300
% 0.15/0.36 % DateTime : Fri Aug 25 15:30:02 EDT 2023
% 0.15/0.36 % CPUTime :
% 8.41/8.56 SZS status Theorem for theBenchmark.p
% 8.41/8.56 SZS output start Proof for theBenchmark.p
% 8.41/8.56 Clause #11 (by assumption #[]): Eq
% 8.41/8.56 (∀ (A : Type),
% 8.41/8.56 linordered_idom A →
% 8.41/8.56 ∀ (A2 : A), ord_less_eq A (zero_zero A) (power_power A A2 (number_number_of nat (bit0 (bit1 pls)))))
% 8.41/8.56 True
% 8.41/8.56 Clause #33 (by assumption #[]): Eq (Eq pls (zero_zero int)) True
% 8.41/8.56 Clause #97 (by assumption #[]): Eq (linordered_idom int) True
% 8.41/8.56 Clause #132 (by assumption #[]): Eq (Not (ord_less_eq int (zero_zero int) (power_power int s (number_number_of nat (bit0 (bit1 pls)))))) True
% 8.41/8.56 Clause #179 (by clausification #[33]): Eq pls (zero_zero int)
% 8.41/8.56 Clause #240 (by clausification #[11]): ∀ (a : Type),
% 8.41/8.56 Eq
% 8.41/8.56 (linordered_idom a →
% 8.41/8.56 ∀ (A2 : a), ord_less_eq a (zero_zero a) (power_power a A2 (number_number_of nat (bit0 (bit1 pls)))))
% 8.41/8.56 True
% 8.41/8.56 Clause #241 (by clausification #[240]): ∀ (a : Type),
% 8.41/8.56 Or (Eq (linordered_idom a) False)
% 8.41/8.56 (Eq (∀ (A2 : a), ord_less_eq a (zero_zero a) (power_power a A2 (number_number_of nat (bit0 (bit1 pls))))) True)
% 8.41/8.56 Clause #242 (by clausification #[241]): ∀ (a : Type) (a_1 : a),
% 8.41/8.56 Or (Eq (linordered_idom a) False)
% 8.41/8.56 (Eq (ord_less_eq a (zero_zero a) (power_power a a_1 (number_number_of nat (bit0 (bit1 pls))))) True)
% 8.41/8.56 Clause #243 (by superposition #[242, 97]): ∀ (a : int),
% 8.41/8.56 Or (Eq (ord_less_eq int (zero_zero int) (power_power int a (number_number_of nat (bit0 (bit1 pls))))) True)
% 8.41/8.56 (Eq False True)
% 8.41/8.56 Clause #1505 (by clausification #[132]): Eq (ord_less_eq int (zero_zero int) (power_power int s (number_number_of nat (bit0 (bit1 pls))))) False
% 8.41/8.56 Clause #1506 (by forward demodulation #[1505, 179]): Eq (ord_less_eq int pls (power_power int s (number_number_of nat (bit0 (bit1 pls))))) False
% 8.41/8.56 Clause #1750 (by clausification #[243]): ∀ (a : int), Eq (ord_less_eq int (zero_zero int) (power_power int a (number_number_of nat (bit0 (bit1 pls))))) True
% 8.41/8.56 Clause #1751 (by forward demodulation #[1750, 179]): ∀ (a : int), Eq (ord_less_eq int pls (power_power int a (number_number_of nat (bit0 (bit1 pls))))) True
% 8.41/8.56 Clause #1752 (by superposition #[1751, 1506]): Eq True False
% 8.41/8.56 Clause #1763 (by clausification #[1752]): False
% 8.41/8.56 SZS output end Proof for theBenchmark.p
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