TSTP Solution File: NUM894_1 by SPASS+T---2.2.22
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% File : SPASS+T---2.2.22
% Problem : NUM894_1 : TPTP v8.1.0. Released v5.0.0.
% Transfm : none
% Format : tptp:raw
% Command : spasst-tptp-script %s %d
% Computer : n011.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:39:13 EDT 2022
% Result : Theorem 0.82s 1.10s
% Output : Refutation 0.82s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.14 % Problem : NUM894_1 : TPTP v8.1.0. Released v5.0.0.
% 0.08/0.14 % Command : spasst-tptp-script %s %d
% 0.14/0.36 % Computer : n011.cluster.edu
% 0.14/0.36 % Model : x86_64 x86_64
% 0.14/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36 % Memory : 8042.1875MB
% 0.14/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36 % CPULimit : 300
% 0.14/0.36 % WCLimit : 600
% 0.14/0.36 % DateTime : Tue Jul 5 03:28:22 EDT 2022
% 0.14/0.36 % CPUTime :
% 0.22/0.51 % Using integer theory
% 0.82/1.10
% 0.82/1.10
% 0.82/1.10 % SZS status Theorem for /tmp/SPASST_16911_n011.cluster.edu
% 0.82/1.10
% 0.82/1.10 SPASS V 2.2.22 in combination with yices.
% 0.82/1.10 SPASS beiseite: Proof found by SMT.
% 0.82/1.10 Problem: /tmp/SPASST_16911_n011.cluster.edu
% 0.82/1.10 SPASS derived 17 clauses, backtracked 0 clauses and kept 41 clauses.
% 0.82/1.10 SPASS backtracked 1 times (1 times due to theory inconsistency).
% 0.82/1.10 SPASS allocated 6222 KBytes.
% 0.82/1.10 SPASS spent 0:00:00.01 on the problem.
% 0.82/1.10 0:00:00.00 for the input.
% 0.82/1.10 0:00:00.00 for the FLOTTER CNF translation.
% 0.82/1.10 0:00:00.00 for inferences.
% 0.82/1.10 0:00:00.00 for the backtracking.
% 0.82/1.10 0:00:00.00 for the reduction.
% 0.82/1.10 0:00:00.00 for interacting with the SMT procedure.
% 0.82/1.10
% 0.82/1.10
% 0.82/1.10 % SZS output start CNFRefutation for /tmp/SPASST_16911_n011.cluster.edu
% 0.82/1.10
% 0.82/1.10 % Here is a proof with depth 0, length 3 :
% 0.82/1.10 1[0:Inp] || lesseq(skc3,skc2)* -> .
% 0.82/1.10 2[0:Inp] || -> less(skc3,plus(skc2,1))*.
% 0.82/1.10 55(e)[0:ThR:2,1] || -> .
% 0.82/1.10
% 0.82/1.10 % SZS output end CNFRefutation for /tmp/SPASST_16911_n011.cluster.edu
% 0.82/1.10
% 0.82/1.10 Formulae used in the proof : fof_less_successor
% 0.82/1.10
% 0.82/1.10 SPASS+T ended
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