TSTP Solution File: NUM854+2 by SOS---2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : SOS---2.0
% Problem : NUM854+2 : TPTP v8.1.0. Released v4.1.0.
% Transfm : none
% Format : tptp:raw
% Command : sos-script %s
% Computer : n015.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:22:41 EDT 2022
% Result : Theorem 0.20s 0.43s
% Output : Refutation 0.20s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12 % Problem : NUM854+2 : TPTP v8.1.0. Released v4.1.0.
% 0.11/0.13 % Command : sos-script %s
% 0.12/0.34 % Computer : n015.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 600
% 0.12/0.34 % DateTime : Wed Jul 6 23:50:34 EDT 2022
% 0.12/0.35 % CPUTime :
% 0.12/0.37 ----- Otter 3.2, August 2001 -----
% 0.12/0.37 The process was started by sandbox2 on n015.cluster.edu,
% 0.12/0.37 Wed Jul 6 23:50:34 2022
% 0.12/0.37 The command was "./sos". The process ID is 15798.
% 0.12/0.37
% 0.12/0.37 set(prolog_style_variables).
% 0.12/0.37 set(auto).
% 0.12/0.37 dependent: set(auto1).
% 0.12/0.37 dependent: set(process_input).
% 0.12/0.37 dependent: clear(print_kept).
% 0.12/0.37 dependent: clear(print_new_demod).
% 0.12/0.37 dependent: clear(print_back_demod).
% 0.12/0.37 dependent: clear(print_back_sub).
% 0.12/0.37 dependent: set(control_memory).
% 0.12/0.37 dependent: assign(max_mem, 12000).
% 0.12/0.37 dependent: assign(pick_given_ratio, 4).
% 0.12/0.37 dependent: assign(stats_level, 1).
% 0.12/0.37 dependent: assign(pick_semantic_ratio, 3).
% 0.12/0.37 dependent: assign(sos_limit, 5000).
% 0.12/0.37 dependent: assign(max_weight, 60).
% 0.12/0.37 clear(print_given).
% 0.12/0.37
% 0.12/0.37 formula_list(usable).
% 0.12/0.37
% 0.12/0.37 SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=3.
% 0.12/0.37
% 0.12/0.37 This ia a non-Horn set with equality. The strategy will be
% 0.12/0.37 Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.12/0.37 unit deletion, with positive clauses in sos and nonpositive
% 0.12/0.37 clauses in usable.
% 0.12/0.37
% 0.12/0.37 dependent: set(knuth_bendix).
% 0.12/0.37 dependent: set(para_from).
% 0.12/0.37 dependent: set(para_into).
% 0.12/0.37 dependent: clear(para_from_right).
% 0.12/0.37 dependent: clear(para_into_right).
% 0.12/0.37 dependent: set(para_from_vars).
% 0.12/0.37 dependent: set(eq_units_both_ways).
% 0.12/0.37 dependent: set(dynamic_demod_all).
% 0.12/0.37 dependent: set(dynamic_demod).
% 0.12/0.37 dependent: set(order_eq).
% 0.12/0.37 dependent: set(back_demod).
% 0.12/0.37 dependent: set(lrpo).
% 0.12/0.37 dependent: set(hyper_res).
% 0.12/0.37 dependent: set(unit_deletion).
% 0.12/0.37 dependent: set(factor).
% 0.12/0.37
% 0.12/0.37 ------------> process usable:
% 0.12/0.37
% 0.12/0.37 ------------> process sos:
% 0.12/0.37 Following clause subsumed by 30 during input processing: 0 [copy,30,flip.1] {-} vmul(A,B)=vmul(B,A).
% 0.12/0.37 Following clause subsumed by 40 during input processing: 0 [copy,40,flip.1] {-} A=A.
% 0.12/0.37 Following clause subsumed by 31 during input processing: 0 [copy,41,flip.1] {-} vmul(vsucc(A),B)=vplus(vmul(A,B),B).
% 0.12/0.37 Following clause subsumed by 34 during input processing: 0 [copy,42,flip.1] {-} vmul(A,vsucc(B))=vplus(vmul(A,B),A).
% 0.12/0.37
% 0.12/0.37 ======= end of input processing =======
% 0.20/0.42
% 0.20/0.42 Model 1 (0.00 seconds, 0 Inserts)
% 0.20/0.42
% 0.20/0.42 Stopped by limit on number of solutions
% 0.20/0.42
% 0.20/0.42
% 0.20/0.42 -------------- Softie stats --------------
% 0.20/0.42
% 0.20/0.42 UPDATE_STOP: 300
% 0.20/0.42 SFINDER_TIME_LIMIT: 2
% 0.20/0.42 SHORT_CLAUSE_CUTOFF: 4
% 0.20/0.42 number of clauses in intial UL: 20
% 0.20/0.42 number of clauses initially in problem: 38
% 0.20/0.42 percentage of clauses intially in UL: 52
% 0.20/0.42 percentage of distinct symbols occuring in initial UL: 66
% 0.20/0.42 percent of all initial clauses that are short: 100
% 0.20/0.42 absolute distinct symbol count: 15
% 0.20/0.42 distinct predicate count: 3
% 0.20/0.42 distinct function count: 7
% 0.20/0.42 distinct constant count: 5
% 0.20/0.42
% 0.20/0.42 ---------- no more Softie stats ----------
% 0.20/0.42
% 0.20/0.42
% 0.20/0.42
% 0.20/0.42 Model 2 (0.00 seconds, 0 Inserts)
% 0.20/0.42
% 0.20/0.42 Stopped by limit on number of solutions
% 0.20/0.42
% 0.20/0.42 =========== start of search ===========
% 0.20/0.43
% 0.20/0.43 -------- PROOF --------
% 0.20/0.43 % SZS status Theorem
% 0.20/0.43 % SZS output start Refutation
% 0.20/0.43
% 0.20/0.43 ----> UNIT CONFLICT at 0.02 sec ----> 53 [binary,52.1,1.1] {+} $F.
% 0.20/0.43
% 0.20/0.43 Length of proof is 1. Level of proof is 1.
% 0.20/0.43
% 0.20/0.43 ---------------- PROOF ----------------
% 0.20/0.43 % SZS status Theorem
% 0.20/0.43 % SZS output start Refutation
% 0.20/0.43
% 0.20/0.43 1 [] {+} -greater(vmul(vd508,vd511),vmul(vd509,vd511)).
% 0.20/0.43 7 [] {+} -greater(A,B)|greater(vmul(A,C),vmul(B,C)).
% 0.20/0.43 24 [] {-} greater(vd508,vd509).
% 0.20/0.43 52 [hyper,24,7] {-} greater(vmul(vd508,A),vmul(vd509,A)).
% 0.20/0.43 53 [binary,52.1,1.1] {+} $F.
% 0.20/0.43
% 0.20/0.43 % SZS output end Refutation
% 0.20/0.43 ------------ end of proof -------------
% 0.20/0.43
% 0.20/0.43
% 0.20/0.43 Search stopped by max_proofs option.
% 0.20/0.43
% 0.20/0.43
% 0.20/0.43 Search stopped by max_proofs option.
% 0.20/0.43
% 0.20/0.43 ============ end of search ============
% 0.20/0.43
% 0.20/0.43 ----------- soft-scott stats ----------
% 0.20/0.43
% 0.20/0.43 true clauses given 0 (0.0%)
% 0.20/0.43 false clauses given 2
% 0.20/0.43
% 0.20/0.43 FALSE TRUE
% 0.20/0.43 3 0 2
% 0.20/0.43 5 2 0
% 0.20/0.43 7 1 2
% 0.20/0.43 9 0 1
% 0.20/0.43 10 4 2
% 0.20/0.43 11 1 0
% 0.20/0.43 13 1 0
% 0.20/0.43 17 0 1
% 0.20/0.43 tot: 9 8 (47.1% true)
% 0.20/0.43
% 0.20/0.43
% 0.20/0.43 Model 2 (0.00 seconds, 0 Inserts)
% 0.20/0.43
% 0.20/0.43 That finishes the proof of the theorem.
% 0.20/0.43
% 0.20/0.43 Process 15798 finished Wed Jul 6 23:50:34 2022
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