TSTP Solution File: NUM852+2 by Twee---2.4.2

View Problem - Process Solution

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% File     : Twee---2.4.2
% Problem  : NUM852+2 : TPTP v8.1.2. Released v4.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n032.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 11:58:39 EDT 2023

% Result   : Theorem 0.13s 0.35s
% Output   : Proof 0.13s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.09  % Problem  : NUM852+2 : TPTP v8.1.2. Released v4.1.0.
% 0.00/0.09  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.08/0.29  % Computer : n032.cluster.edu
% 0.08/0.29  % Model    : x86_64 x86_64
% 0.08/0.29  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.08/0.29  % Memory   : 8042.1875MB
% 0.08/0.29  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.08/0.29  % CPULimit : 300
% 0.08/0.29  % WCLimit  : 300
% 0.08/0.29  % DateTime : Fri Aug 25 10:30:57 EDT 2023
% 0.08/0.29  % CPUTime  : 
% 0.13/0.35  Command-line arguments: --set-join --lhs-weight 1 --no-flatten-goal --complete-subsets --goal-heuristic
% 0.13/0.35  
% 0.13/0.35  % SZS status Theorem
% 0.13/0.35  
% 0.13/0.35  % SZS output start Proof
% 0.13/0.35  Take the following subset of the input axioms:
% 0.13/0.35    fof('ass(cond(270, 0), 0)', axiom, ![Vd418, Vd419]: vmul(Vd418, Vd419)=vmul(Vd419, Vd418)).
% 0.13/0.35    fof('ass(cond(281, 0), 0)', axiom, ![Vd432, Vd433, Vd434]: vmul(Vd432, vplus(Vd433, Vd434))=vplus(vmul(Vd432, Vd433), vmul(Vd432, Vd434))).
% 0.13/0.35    fof('def(cond(conseq(axiom(3)), 11), 1)', axiom, ![Vd193, Vd194]: (greater(Vd194, Vd193) <=> ?[Vd196]: Vd194=vplus(Vd193, Vd196))).
% 0.13/0.35    fof('holds(conseq_conjunct1(conseq(304)), 483, 0)', axiom, greater(vd481, vd480)).
% 0.13/0.35    fof('holds(conseq_conjunct1(conseq_conjunct2(conseq(304))), 484, 0)', conjecture, greater(vmul(vd481, vd469), vmul(vd480, vd469))).
% 0.13/0.35  
% 0.13/0.35  Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.13/0.35  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.13/0.35  We repeatedly replace C & s=t => u=v by the two clauses:
% 0.13/0.35    fresh(y, y, x1...xn) = u
% 0.13/0.35    C => fresh(s, t, x1...xn) = v
% 0.13/0.35  where fresh is a fresh function symbol and x1..xn are the free
% 0.13/0.35  variables of u and v.
% 0.13/0.35  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.13/0.35  input problem has no model of domain size 1).
% 0.13/0.35  
% 0.13/0.35  The encoding turns the above axioms into the following unit equations and goals:
% 0.13/0.35  
% 0.13/0.35  Axiom 1 (holds(conseq_conjunct1(conseq(304)), 483, 0)): greater(vd481, vd480) = true2.
% 0.13/0.35  Axiom 2 (ass(cond(270, 0), 0)): vmul(X, Y) = vmul(Y, X).
% 0.13/0.35  Axiom 3 (def(cond(conseq(axiom(3)), 11), 1)_1): fresh(X, X, Y, Z) = Z.
% 0.13/0.35  Axiom 4 (def(cond(conseq(axiom(3)), 11), 1)): fresh5(X, X, Y, Z) = true2.
% 0.13/0.35  Axiom 5 (def(cond(conseq(axiom(3)), 11), 1)_1): fresh(greater(X, Y), true2, Y, X) = vplus(Y, vd196(Y, X)).
% 0.13/0.35  Axiom 6 (def(cond(conseq(axiom(3)), 11), 1)): fresh5(X, vplus(Y, Z), Y, X) = greater(X, Y).
% 0.13/0.35  Axiom 7 (ass(cond(281, 0), 0)): vmul(X, vplus(Y, Z)) = vplus(vmul(X, Y), vmul(X, Z)).
% 0.13/0.35  
% 0.13/0.35  Goal 1 (holds(conseq_conjunct1(conseq_conjunct2(conseq(304))), 484, 0)): greater(vmul(vd481, vd469), vmul(vd480, vd469)) = true2.
% 0.13/0.35  Proof:
% 0.13/0.35    greater(vmul(vd481, vd469), vmul(vd480, vd469))
% 0.13/0.35  = { by axiom 2 (ass(cond(270, 0), 0)) R->L }
% 0.13/0.35    greater(vmul(vd481, vd469), vmul(vd469, vd480))
% 0.13/0.35  = { by axiom 2 (ass(cond(270, 0), 0)) R->L }
% 0.13/0.35    greater(vmul(vd469, vd481), vmul(vd469, vd480))
% 0.13/0.35  = { by axiom 3 (def(cond(conseq(axiom(3)), 11), 1)_1) R->L }
% 0.13/0.35    greater(vmul(vd469, fresh(true2, true2, vd480, vd481)), vmul(vd469, vd480))
% 0.13/0.35  = { by axiom 1 (holds(conseq_conjunct1(conseq(304)), 483, 0)) R->L }
% 0.13/0.35    greater(vmul(vd469, fresh(greater(vd481, vd480), true2, vd480, vd481)), vmul(vd469, vd480))
% 0.13/0.35  = { by axiom 5 (def(cond(conseq(axiom(3)), 11), 1)_1) }
% 0.13/0.35    greater(vmul(vd469, vplus(vd480, vd196(vd480, vd481))), vmul(vd469, vd480))
% 0.13/0.35  = { by axiom 7 (ass(cond(281, 0), 0)) }
% 0.13/0.35    greater(vplus(vmul(vd469, vd480), vmul(vd469, vd196(vd480, vd481))), vmul(vd469, vd480))
% 0.13/0.35  = { by axiom 6 (def(cond(conseq(axiom(3)), 11), 1)) R->L }
% 0.13/0.35    fresh5(vplus(vmul(vd469, vd480), vmul(vd469, vd196(vd480, vd481))), vplus(vmul(vd469, vd480), vmul(vd469, vd196(vd480, vd481))), vmul(vd469, vd480), vplus(vmul(vd469, vd480), vmul(vd469, vd196(vd480, vd481))))
% 0.13/0.35  = { by axiom 4 (def(cond(conseq(axiom(3)), 11), 1)) }
% 0.13/0.35    true2
% 0.13/0.35  % SZS output end Proof
% 0.13/0.35  
% 0.13/0.35  RESULT: Theorem (the conjecture is true).
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