TSTP Solution File: NUM844+2 by SnakeForV---1.0
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%------------------------------------------------------------------------------
% File : SnakeForV---1.0
% Problem : NUM844+2 : TPTP v8.1.0. Released v4.1.0.
% Transfm : none
% Format : tptp:raw
% Command : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_uns --cores 0 -t %d %s
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Aug 31 18:02:33 EDT 2022
% Result : Theorem 0.21s 0.52s
% Output : Refutation 0.21s
% Verified :
% SZS Type : Refutation
% Derivation depth : 8
% Number of leaves : 6
% Syntax : Number of formulae : 25 ( 22 unt; 0 def)
% Number of atoms : 28 ( 22 equ)
% Maximal formula atoms : 2 ( 1 avg)
% Number of connectives : 9 ( 6 ~; 0 |; 3 &)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 4 ( 2 avg)
% Maximal term depth : 4 ( 2 avg)
% Number of predicates : 3 ( 1 usr; 1 prp; 0-2 aty)
% Number of functors : 6 ( 6 usr; 3 con; 0-2 aty)
% Number of variables : 16 ( 16 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(f86,plain,
$false,
inference(subsumption_resolution,[],[f85,f83]) ).
fof(f83,plain,
~ sP0(vplus(vmul(vd411,vd413),vplus(vd413,vplus(vd411,v1)))),
inference(forward_demodulation,[],[f77,f79]) ).
fof(f79,plain,
vplus(vd411,v1) = vplus(v1,vd411),
inference(backward_demodulation,[],[f63,f48]) ).
fof(f48,plain,
! [X0] : vmul(X0,v1) = X0,
inference(cnf_transformation,[],[f39]) ).
fof(f39,plain,
! [X0,X1] :
( vmul(X0,v1) = X0
& vplus(vmul(X0,X1),X0) = vmul(X0,vsucc(X1)) ),
inference(rectify,[],[f31]) ).
fof(f31,plain,
! [X1,X0] :
( vmul(X1,v1) = X1
& vmul(X1,vsucc(X0)) = vplus(vmul(X1,X0),X1) ),
inference(rectify,[],[f11]) ).
fof(f11,axiom,
! [X2,X1] :
( vmul(X1,vsucc(X2)) = vplus(vmul(X1,X2),X1)
& vmul(X1,v1) = X1 ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p','qu(cond(conseq(axiom(3)), 32), and(holds(definiens(249), 399, 0), holds(definiens(249), 398, 0)))') ).
fof(f63,plain,
vplus(vmul(vd411,v1),v1) = vplus(v1,vmul(vd411,v1)),
inference(definition_unfolding,[],[f44,f51]) ).
fof(f51,plain,
! [X0] : vplus(v1,X0) = vsucc(X0),
inference(cnf_transformation,[],[f27]) ).
fof(f27,plain,
! [X0] : vplus(v1,X0) = vsucc(X0),
inference(rectify,[],[f16]) ).
fof(f16,axiom,
! [X11] : vplus(v1,X11) = vsucc(X11),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p','ass(cond(43, 0), 0)') ).
fof(f44,plain,
vsucc(vmul(vd411,v1)) = vplus(vmul(vd411,v1),v1),
inference(cnf_transformation,[],[f7]) ).
fof(f7,axiom,
vsucc(vmul(vd411,v1)) = vplus(vmul(vd411,v1),v1),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p','holds(264, 412, 2)') ).
fof(f77,plain,
~ sP0(vplus(vmul(vd411,vd413),vplus(vd413,vplus(v1,vd411)))),
introduced(inequality_splitting_name_introduction,[new_symbols(naming,[sP0])]) ).
fof(f85,plain,
sP0(vplus(vmul(vd411,vd413),vplus(vd413,vplus(vd411,v1)))),
inference(backward_demodulation,[],[f81,f42]) ).
fof(f42,plain,
! [X0,X1] : vplus(X0,X1) = vplus(X1,X0),
inference(cnf_transformation,[],[f28]) ).
fof(f28,plain,
! [X0,X1] : vplus(X0,X1) = vplus(X1,X0),
inference(rectify,[],[f14]) ).
fof(f14,axiom,
! [X8,X7] : vplus(X8,X7) = vplus(X7,X8),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p','ass(cond(61, 0), 0)') ).
fof(f81,plain,
sP0(vplus(vmul(vd411,vd413),vplus(vplus(vd411,v1),vd413))),
inference(backward_demodulation,[],[f78,f79]) ).
fof(f78,plain,
sP0(vplus(vmul(vd411,vd413),vplus(vplus(v1,vd411),vd413))),
inference(inequality_splitting,[],[f68,f77]) ).
fof(f68,plain,
vplus(vmul(vd411,vd413),vplus(vd413,vplus(v1,vd411))) != vplus(vmul(vd411,vd413),vplus(vplus(v1,vd411),vd413)),
inference(definition_unfolding,[],[f50,f51,f51]) ).
fof(f50,plain,
vplus(vmul(vd411,vd413),vplus(vd413,vsucc(vd411))) != vplus(vmul(vd411,vd413),vplus(vsucc(vd411),vd413)),
inference(cnf_transformation,[],[f25]) ).
fof(f25,plain,
vplus(vmul(vd411,vd413),vplus(vd413,vsucc(vd411))) != vplus(vmul(vd411,vd413),vplus(vsucc(vd411),vd413)),
inference(flattening,[],[f2]) ).
fof(f2,negated_conjecture,
vplus(vmul(vd411,vd413),vplus(vd413,vsucc(vd411))) != vplus(vmul(vd411,vd413),vplus(vsucc(vd411),vd413)),
inference(negated_conjecture,[],[f1]) ).
fof(f1,conjecture,
vplus(vmul(vd411,vd413),vplus(vd413,vsucc(vd411))) = vplus(vmul(vd411,vd413),vplus(vsucc(vd411),vd413)),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p','holds(266, 415, 3)') ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12 % Problem : NUM844+2 : TPTP v8.1.0. Released v4.1.0.
% 0.06/0.13 % Command : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_uns --cores 0 -t %d %s
% 0.14/0.34 % Computer : n016.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 300
% 0.14/0.34 % DateTime : Tue Aug 30 09:25:01 EDT 2022
% 0.14/0.34 % CPUTime :
% 0.21/0.50 % (31726)dis+1010_2:3_fs=off:fsr=off:nm=0:nwc=5.0:s2a=on:s2agt=32:i=82:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/82Mi)
% 0.21/0.51 % (31718)lrs+10_1:1_ins=3:sp=reverse_frequency:spb=goal:to=lpo:i=3:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/3Mi)
% 0.21/0.51 % (31718)First to succeed.
% 0.21/0.52 % (31718)Refutation found. Thanks to Tanya!
% 0.21/0.52 % SZS status Theorem for theBenchmark
% 0.21/0.52 % SZS output start Proof for theBenchmark
% See solution above
% 0.21/0.52 % (31718)------------------------------
% 0.21/0.52 % (31718)Version: Vampire 4.7 (commit 807e37dd9 on 2022-08-23 09:55:27 +0200)
% 0.21/0.52 % (31718)Linked with Z3 4.8.13.0 f03d756e086f81f2596157241e0decfb1c982299 z3-4.8.4-5390-gf03d756e0
% 0.21/0.52 % (31718)Termination reason: Refutation
% 0.21/0.52
% 0.21/0.52 % (31718)Memory used [KB]: 5884
% 0.21/0.52 % (31718)Time elapsed: 0.004 s
% 0.21/0.52 % (31718)Instructions burned: 2 (million)
% 0.21/0.52 % (31718)------------------------------
% 0.21/0.52 % (31718)------------------------------
% 0.21/0.52 % (31702)Success in time 0.163 s
%------------------------------------------------------------------------------