TSTP Solution File: NUM844+2 by SOS---2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : SOS---2.0
% Problem : NUM844+2 : TPTP v8.1.0. Released v4.1.0.
% Transfm : none
% Format : tptp:raw
% Command : sos-script %s
% Computer : n029.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:22:35 EDT 2022
% Result : Theorem 0.50s 0.69s
% Output : Refutation 0.50s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12 % Problem : NUM844+2 : TPTP v8.1.0. Released v4.1.0.
% 0.06/0.13 % Command : sos-script %s
% 0.12/0.33 % Computer : n029.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Tue Jul 5 04:59:42 EDT 2022
% 0.12/0.34 % CPUTime :
% 0.12/0.35 ----- Otter 3.2, August 2001 -----
% 0.12/0.35 The process was started by sandbox2 on n029.cluster.edu,
% 0.12/0.35 Tue Jul 5 04:59:42 2022
% 0.12/0.35 The command was "./sos". The process ID is 2188.
% 0.12/0.35
% 0.12/0.35 set(prolog_style_variables).
% 0.12/0.35 set(auto).
% 0.12/0.35 dependent: set(auto1).
% 0.12/0.35 dependent: set(process_input).
% 0.12/0.35 dependent: clear(print_kept).
% 0.12/0.35 dependent: clear(print_new_demod).
% 0.12/0.35 dependent: clear(print_back_demod).
% 0.12/0.35 dependent: clear(print_back_sub).
% 0.12/0.35 dependent: set(control_memory).
% 0.12/0.35 dependent: assign(max_mem, 12000).
% 0.12/0.35 dependent: assign(pick_given_ratio, 4).
% 0.12/0.35 dependent: assign(stats_level, 1).
% 0.12/0.35 dependent: assign(pick_semantic_ratio, 3).
% 0.12/0.35 dependent: assign(sos_limit, 5000).
% 0.12/0.35 dependent: assign(max_weight, 60).
% 0.12/0.35 clear(print_given).
% 0.12/0.35
% 0.12/0.35 formula_list(usable).
% 0.12/0.35
% 0.12/0.35 SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=2.
% 0.12/0.35
% 0.12/0.35 This ia a non-Horn set with equality. The strategy will be
% 0.12/0.35 Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.12/0.35 unit deletion, with positive clauses in sos and nonpositive
% 0.12/0.35 clauses in usable.
% 0.12/0.35
% 0.12/0.35 dependent: set(knuth_bendix).
% 0.12/0.35 dependent: set(para_from).
% 0.12/0.35 dependent: set(para_into).
% 0.12/0.35 dependent: clear(para_from_right).
% 0.12/0.35 dependent: clear(para_into_right).
% 0.12/0.35 dependent: set(para_from_vars).
% 0.12/0.35 dependent: set(eq_units_both_ways).
% 0.12/0.35 dependent: set(dynamic_demod_all).
% 0.12/0.35 dependent: set(dynamic_demod).
% 0.12/0.35 dependent: set(order_eq).
% 0.12/0.35 dependent: set(back_demod).
% 0.12/0.35 dependent: set(lrpo).
% 0.12/0.35 dependent: set(hyper_res).
% 0.12/0.35 dependent: set(unit_deletion).
% 0.12/0.35 dependent: set(factor).
% 0.12/0.35
% 0.12/0.35 ------------> process usable:
% 0.12/0.35
% 0.12/0.35 ------------> process sos:
% 0.12/0.35 Following clause subsumed by 30 during input processing: 0 [demod,36] {-} vplus(A,v1)=vplus(v1,A).
% 0.12/0.35 Following clause subsumed by 30 during input processing: 0 [copy,30,flip.1] {-} vplus(A,B)=vplus(B,A).
% 0.12/0.35 Following clause subsumed by 43 during input processing: 0 [copy,43,flip.1] {-} A=A.
% 0.12/0.35 Following clause subsumed by 40 during input processing: 0 [copy,55,flip.1] {-} vplus(A,vplus(v1,B))=vplus(v1,vplus(A,B)).
% 0.12/0.35
% 0.12/0.35 ======= end of input processing =======
% 0.19/0.39
% 0.19/0.39 Model 1 (0.00 seconds, 0 Inserts)
% 0.19/0.39
% 0.19/0.39 Stopped by limit on number of solutions
% 0.19/0.39
% 0.19/0.39
% 0.19/0.39 -------------- Softie stats --------------
% 0.19/0.39
% 0.19/0.39 UPDATE_STOP: 300
% 0.19/0.39 SFINDER_TIME_LIMIT: 2
% 0.19/0.39 SHORT_CLAUSE_CUTOFF: 4
% 0.19/0.39 number of clauses in intial UL: 2
% 0.19/0.39 number of clauses initially in problem: 24
% 0.19/0.39 percentage of clauses intially in UL: 8
% 0.19/0.39 percentage of distinct symbols occuring in initial UL: 50
% 0.19/0.39 percent of all initial clauses that are short: 100
% 0.19/0.39 absolute distinct symbol count: 12
% 0.19/0.39 distinct predicate count: 5
% 0.19/0.39 distinct function count: 4
% 0.19/0.39 distinct constant count: 3
% 0.19/0.39
% 0.19/0.39 ---------- no more Softie stats ----------
% 0.19/0.39
% 0.19/0.39
% 0.19/0.39
% 0.19/0.39 Model 2 (0.00 seconds, 0 Inserts)
% 0.19/0.39
% 0.19/0.39 Stopped by limit on number of solutions
% 0.19/0.39
% 0.19/0.39 =========== start of search ===========
% 0.50/0.69
% 0.50/0.69 -------- PROOF --------
% 0.50/0.69 % SZS status Theorem
% 0.50/0.69 % SZS output start Refutation
% 0.50/0.69
% 0.50/0.69 Model 3 (0.00 seconds, 0 Inserts)
% 0.50/0.69
% 0.50/0.69 Stopped by limit on number of solutions
% 0.50/0.69
% 0.50/0.69 Model 4 (0.00 seconds, 0 Inserts)
% 0.50/0.69
% 0.50/0.69 Stopped by limit on number of solutions
% 0.50/0.69
% 0.50/0.69 Model 5 (0.00 seconds, 0 Inserts)
% 0.50/0.69
% 0.50/0.69 Stopped by limit on number of solutions
% 0.50/0.69
% 0.50/0.69 Stopped by limit on insertions
% 0.50/0.69
% 0.50/0.69 Model 6 [ 1 1 542 ] (0.00 seconds, 250000 Inserts)
% 0.50/0.69
% 0.50/0.69 Model 7 (0.00 seconds, 250000 Inserts)
% 0.50/0.69
% 0.50/0.69 Stopped by limit on number of solutions
% 0.50/0.69
% 0.50/0.69 ----> UNIT CONFLICT at 0.30 sec ----> 371 [binary,369.1,50.1] {-} $F.
% 0.50/0.69
% 0.50/0.69 Length of proof is 7. Level of proof is 4.
% 0.50/0.69
% 0.50/0.69 ---------------- PROOF ----------------
% 0.50/0.69 % SZS status Theorem
% 0.50/0.69 % SZS output start Refutation
% 0.50/0.69
% 0.50/0.69 1 [] {-} vplus(vmul(vd411,vd413),vplus(vd413,vsucc(vd411)))!=vplus(vmul(vd411,vd413),vplus(vsucc(vd411),vd413)).
% 0.50/0.69 2 [copy,1,flip.1] {-} vplus(vmul(vd411,vd413),vplus(vsucc(vd411),vd413))!=vplus(vmul(vd411,vd413),vplus(vd413,vsucc(vd411))).
% 0.50/0.69 8,7 [] {-} vplus(vplus(vmul(vd411,vd413),vd413),vsucc(vd411))=vplus(vmul(vd411,vd413),vplus(vd413,vsucc(vd411))).
% 0.50/0.69 9 [] {-} vplus(vmul(vsucc(vd411),vd413),vsucc(vd411))=vplus(vplus(vmul(vd411,vd413),vd413),vsucc(vd411)).
% 0.50/0.69 11,10 [copy,9,demod,8] {-} vplus(vmul(vsucc(vd411),vd413),vsucc(vd411))=vplus(vmul(vd411,vd413),vplus(vd413,vsucc(vd411))).
% 0.50/0.69 12 [] {-} vmul(vsucc(vd411),vsucc(vd413))=vplus(vmul(vsucc(vd411),vd413),vsucc(vd411)).
% 0.50/0.69 13 [copy,12,demod,11] {-} vmul(vsucc(vd411),vsucc(vd413))=vplus(vmul(vd411,vd413),vplus(vd413,vsucc(vd411))).
% 0.50/0.69 30 [] {+} vplus(A,B)=vplus(B,A).
% 0.50/0.69 34 [] {-} vplus(v1,A)=vsucc(A).
% 0.50/0.69 36,35 [copy,34,flip.1] {+} vsucc(A)=vplus(v1,A).
% 0.50/0.69 38,37 [] {+} vplus(vplus(A,B),C)=vplus(A,vplus(B,C)).
% 0.50/0.69 49,48 [back_demod,13,demod,36,36,36,flip.1] {+} vplus(vmul(vd411,vd413),vplus(vd413,vplus(v1,vd411)))=vmul(vplus(v1,vd411),vplus(v1,vd413)).
% 0.50/0.69 50 [back_demod,2,demod,36,38,36,49] {-} vplus(vmul(vd411,vd413),vplus(v1,vplus(vd411,vd413)))!=vmul(vplus(v1,vd411),vplus(v1,vd413)).
% 0.50/0.69 369 [para_into,48.1.1.2,30.1.1,demod,38] {-} vplus(vmul(vd411,vd413),vplus(v1,vplus(vd411,vd413)))=vmul(vplus(v1,vd411),vplus(v1,vd413)).
% 0.50/0.69 371 [binary,369.1,50.1] {-} $F.
% 0.50/0.69
% 0.50/0.69 % SZS output end Refutation
% 0.50/0.69 ------------ end of proof -------------
% 0.50/0.69
% 0.50/0.69
% 0.50/0.69 Search stopped by max_proofs option.
% 0.50/0.69
% 0.50/0.69
% 0.50/0.69 Search stopped by max_proofs option.
% 0.50/0.69
% 0.50/0.69 ============ end of search ============
% 0.50/0.69
% 0.50/0.69 ----------- soft-scott stats ----------
% 0.50/0.69
% 0.50/0.69 true clauses given 6 (28.6%)
% 0.50/0.69 false clauses given 15
% 0.50/0.69
% 0.50/0.69 FALSE TRUE
% 0.50/0.69 8 0 1
% 0.50/0.69 9 0 5
% 0.50/0.69 10 3 2
% 0.50/0.69 11 9 8
% 0.50/0.69 12 4 14
% 0.50/0.69 13 6 19
% 0.50/0.69 14 5 19
% 0.50/0.69 15 16 22
% 0.50/0.69 16 28 23
% 0.50/0.69 17 10 19
% 0.50/0.69 18 7 12
% 0.50/0.69 19 2 6
% 0.50/0.69 20 2 2
% 0.50/0.69 tot: 92 152 (62.3% true)
% 0.50/0.69
% 0.50/0.69
% 0.50/0.69 Model 7 (0.00 seconds, 250000 Inserts)
% 0.50/0.69
% 0.50/0.69 That finishes the proof of the theorem.
% 0.50/0.69
% 0.50/0.69 Process 2188 finished Tue Jul 5 04:59:42 2022
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