TSTP Solution File: NUM844+1 by Duper---1.0
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%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : NUM844+1 : TPTP v8.1.2. Released v4.1.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:57:56 EDT 2023
% Result : Theorem 4.67s 4.91s
% Output : Proof 4.67s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : NUM844+1 : TPTP v8.1.2. Released v4.1.0.
% 0.00/0.14 % Command : duper %s
% 0.18/0.34 % Computer : n018.cluster.edu
% 0.18/0.34 % Model : x86_64 x86_64
% 0.18/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.18/0.34 % Memory : 8042.1875MB
% 0.18/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.18/0.34 % CPULimit : 300
% 0.18/0.34 % WCLimit : 300
% 0.18/0.34 % DateTime : Fri Aug 25 13:34:43 EDT 2023
% 0.18/0.35 % CPUTime :
% 4.67/4.91 SZS status Theorem for theBenchmark.p
% 4.67/4.91 SZS output start Proof for theBenchmark.p
% 4.67/4.91 Clause #0 (by assumption #[]): Eq
% 4.67/4.91 (Not
% 4.67/4.91 (Eq (vplus (vmul vd411 vd413) (vplus vd413 (vsucc vd411))) (vplus (vmul vd411 vd413) (vplus (vsucc vd411) vd413))))
% 4.67/4.91 True
% 4.67/4.91 Clause #44 (by assumption #[]): Eq (∀ (Vd78 Vd79 : Iota), Eq (vplus Vd79 Vd78) (vplus Vd78 Vd79)) True
% 4.67/4.91 Clause #65 (by clausification #[0]): Eq (Eq (vplus (vmul vd411 vd413) (vplus vd413 (vsucc vd411))) (vplus (vmul vd411 vd413) (vplus (vsucc vd411) vd413)))
% 4.67/4.91 False
% 4.67/4.91 Clause #66 (by clausification #[65]): Ne (vplus (vmul vd411 vd413) (vplus vd413 (vsucc vd411))) (vplus (vmul vd411 vd413) (vplus (vsucc vd411) vd413))
% 4.67/4.91 Clause #1407 (by clausification #[44]): ∀ (a : Iota), Eq (∀ (Vd79 : Iota), Eq (vplus Vd79 a) (vplus a Vd79)) True
% 4.67/4.91 Clause #1408 (by clausification #[1407]): ∀ (a a_1 : Iota), Eq (Eq (vplus a a_1) (vplus a_1 a)) True
% 4.67/4.91 Clause #1409 (by clausification #[1408]): ∀ (a a_1 : Iota), Eq (vplus a a_1) (vplus a_1 a)
% 4.67/4.91 Clause #1410 (by backward positive simplify reflect #[1409, 66]): False
% 4.67/4.91 SZS output end Proof for theBenchmark.p
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