TSTP Solution File: NUM835+2 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : NUM835+2 : TPTP v8.1.0. Released v4.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:22:30 EDT 2022

% Result   : Theorem 0.40s 0.61s
% Output   : Refutation 0.40s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : NUM835+2 : TPTP v8.1.0. Released v4.1.0.
% 0.00/0.12  % Command  : sos-script %s
% 0.12/0.33  % Computer : n015.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Wed Jul  6 08:01:48 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.18/0.35  ----- Otter 3.2, August 2001 -----
% 0.18/0.35  The process was started by sandbox on n015.cluster.edu,
% 0.18/0.35  Wed Jul  6 08:01:48 2022
% 0.18/0.35  The command was "./sos".  The process ID is 21238.
% 0.18/0.35  
% 0.18/0.35  set(prolog_style_variables).
% 0.18/0.35  set(auto).
% 0.18/0.35     dependent: set(auto1).
% 0.18/0.35     dependent: set(process_input).
% 0.18/0.35     dependent: clear(print_kept).
% 0.18/0.35     dependent: clear(print_new_demod).
% 0.18/0.35     dependent: clear(print_back_demod).
% 0.18/0.35     dependent: clear(print_back_sub).
% 0.18/0.35     dependent: set(control_memory).
% 0.18/0.35     dependent: assign(max_mem, 12000).
% 0.18/0.35     dependent: assign(pick_given_ratio, 4).
% 0.18/0.35     dependent: assign(stats_level, 1).
% 0.18/0.35     dependent: assign(pick_semantic_ratio, 3).
% 0.18/0.35     dependent: assign(sos_limit, 5000).
% 0.18/0.35     dependent: assign(max_weight, 60).
% 0.18/0.35  clear(print_given).
% 0.18/0.35  
% 0.18/0.35  formula_list(usable).
% 0.18/0.35  
% 0.18/0.35  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=4.
% 0.18/0.35  
% 0.18/0.35  This ia a non-Horn set with equality.  The strategy will be
% 0.18/0.35  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.18/0.35  unit deletion, with positive clauses in sos and nonpositive
% 0.18/0.35  clauses in usable.
% 0.18/0.35  
% 0.18/0.35     dependent: set(knuth_bendix).
% 0.18/0.35     dependent: set(para_from).
% 0.18/0.35     dependent: set(para_into).
% 0.18/0.35     dependent: clear(para_from_right).
% 0.18/0.35     dependent: clear(para_into_right).
% 0.18/0.35     dependent: set(para_from_vars).
% 0.18/0.35     dependent: set(eq_units_both_ways).
% 0.18/0.35     dependent: set(dynamic_demod_all).
% 0.18/0.35     dependent: set(dynamic_demod).
% 0.18/0.35     dependent: set(order_eq).
% 0.18/0.35     dependent: set(back_demod).
% 0.18/0.35     dependent: set(lrpo).
% 0.18/0.35     dependent: set(hyper_res).
% 0.18/0.35     dependent: set(unit_deletion).
% 0.18/0.35     dependent: set(factor).
% 0.18/0.35  
% 0.18/0.35  ------------> process usable:
% 0.18/0.35    Following clause subsumed by 2 during input processing: 0 [flip.1] {-} vplus(vd151,A)!=vd165|m(vsucc(vd165)).
% 0.18/0.35    Following clause subsumed by 2 during input processing: 0 [flip.1] {-} vplus(vd151,A)!=vd165|vsucc(vplus(vd151,A))=vplus(vd151,vsucc(A)).
% 0.18/0.35    Following clause subsumed by 2 during input processing: 0 [flip.1,flip.2] {-} vplus(vd151,A)!=vd165|vsucc(vplus(vd151,A))=vsucc(vd165).
% 0.18/0.35    Following clause subsumed by 4 during input processing: 0 [flip.1] {-} vplus(vd165,A)!=vd151|A=v1|m(vsucc(vd165)).
% 0.18/0.35    Following clause subsumed by 4 during input processing: 0 [flip.1,flip.3] {-} vplus(vd165,A)!=vd151|A=v1|vplus(vsucc(vd165),vskolem3)=vplus(vplus(vd165,v1),vskolem3).
% 0.18/0.35    Following clause subsumed by 4 during input processing: 0 [flip.1,flip.3] {-} vplus(vd165,A)!=vd151|A=v1|vplus(vplus(vd165,v1),vskolem3)=vplus(vd165,vplus(v1,vskolem3)).
% 0.18/0.35    Following clause subsumed by 4 during input processing: 0 [unit_del,4,flip.1] {-} vplus(vd165,A)!=vd151|A=v1.
% 0.18/0.35    Following clause subsumed by 4 during input processing: 0 [flip.1] {-} vplus(vd165,A)!=vd151|A=v1|vsucc(vskolem3)=vplus(v1,vskolem3).
% 0.18/0.35    Following clause subsumed by 4 during input processing: 0 [flip.1] {-} vplus(vd165,A)!=vd151|A=v1|A=vsucc(vskolem3).
% 0.18/0.35    Following clause subsumed by 4 during input processing: 0 [flip.1] {-} vplus(vd165,A)!=vd151|A!=v1|m(vsucc(vd165)).
% 0.18/0.35    Following clause subsumed by 4 during input processing: 0 [flip.1,flip.3] {-} vplus(vd165,A)!=vd151|A!=v1|vsucc(vd165)=vplus(vd165,v1).
% 0.18/0.35    Following clause subsumed by 4 during input processing: 0 [unit_del,4,flip.1] {-} vplus(vd165,A)!=vd151|A!=v1.
% 0.18/0.35    Following clause subsumed by 6 during input processing: 0 [flip.1] {-} vd165!=vd151|m(vsucc(vd165)).
% 0.18/0.35    Following clause subsumed by 6 during input processing: 0 [flip.1] {-} vd165!=vd151|vplus(vd165,v1)=vplus(vd151,v1).
% 0.18/0.35    Following clause subsumed by 6 during input processing: 0 [flip.1] {-} vd165!=vd151|vsucc(vd165)=vplus(vd165,v1).
% 0.18/0.35  
% 0.18/0.35  ------------> process sos:
% 0.18/0.35    Following clause subsumed by 13 during input processing: 0 [demod,19] {-} vplus(A,v1)=vplus(v1,A).
% 0.18/0.35    Following clause subsumed by 13 during input processing: 0 [copy,13,flip.1] {-} vplus(A,B)=vplus(B,A).
% 0.18/0.35    Following clause subsumed by 26 during input processing: 0 [copy,26,flip.1] {-} A=A.
% 0.18/0.35    Following clause subsumed by 23 during input processing: 0 [copy,28,flip.1] {-} vplus(A,vplus(v1,B))=vplus(v1,vplus(A,B)).
% 0.18/0.35  
% 0.18/0.35  ======= end of input processing =======
% 0.40/0.61  
% 0.40/0.61  Stopped by limit on insertions
% 0.40/0.61  
% 0.40/0.61  
% 0.40/0.61  Failed to model usable list: disabling FINDER
% 0.40/0.61  
% 0.40/0.61  
% 0.40/0.61  
% 0.40/0.61  -------------- Softie stats --------------
% 0.40/0.61  
% 0.40/0.61  UPDATE_STOP: 300
% 0.40/0.61  SFINDER_TIME_LIMIT: 2
% 0.40/0.61  SHORT_CLAUSE_CUTOFF: 4
% 0.40/0.61  number of clauses in intial UL: 7
% 0.40/0.61  number of clauses initially in problem: 17
% 0.40/0.61  percentage of clauses intially in UL: 41
% 0.40/0.61  percentage of distinct symbols occuring in initial UL: 70
% 0.40/0.61  percent of all initial clauses that are short: 100
% 0.40/0.61  absolute distinct symbol count: 10
% 0.40/0.61     distinct predicate count: 2
% 0.40/0.61     distinct function count: 5
% 0.40/0.61     distinct constant count: 3
% 0.40/0.61  
% 0.40/0.61  ---------- no more Softie stats ----------
% 0.40/0.61  
% 0.40/0.61  
% 0.40/0.61  
% 0.40/0.61  =========== start of search ===========
% 0.40/0.61  
% 0.40/0.61  -------- PROOF -------- 
% 0.40/0.61  % SZS status Theorem
% 0.40/0.61  % SZS output start Refutation
% 0.40/0.61  
% 0.40/0.61  -----> EMPTY CLAUSE at   0.23 sec ----> 114 [hyper,31,35,unit_del,6,4] {-} $F.
% 0.40/0.61  
% 0.40/0.61  Length of proof is 7.  Level of proof is 2.
% 0.40/0.61  
% 0.40/0.61  ---------------- PROOF ----------------
% 0.40/0.61  % SZS status Theorem
% 0.40/0.61  % SZS output start Refutation
% 0.40/0.61  
% 0.40/0.61  1 [] {-} vd165!=vplus(vd151,A).
% 0.40/0.61  2 [copy,1,flip.1] {+} vplus(vd151,A)!=vd165.
% 0.40/0.61  3 [] {-} vd151!=vplus(vd165,A).
% 0.40/0.61  4 [copy,3,flip.1] {+} vplus(vd165,A)!=vd151.
% 0.40/0.61  5 [] {-} vd151!=vd165.
% 0.40/0.61  6 [copy,5,flip.1] {+} vd165!=vd151.
% 0.40/0.61  7 [] {-} -m(A)|B=A|B=vplus(A,$f1(B,A))|A=vplus(B,$f2(B,A)).
% 0.40/0.61  8 [copy,7,flip.3,flip.4] {+} -m(A)|B=A|vplus(A,$f1(B,A))=B|vplus(B,$f2(B,A))=A.
% 0.40/0.61  10 [] {+} m(A)|B!=vplus(A,C).
% 0.40/0.61  13 [] {-} vplus(A,B)=vplus(B,A).
% 0.40/0.61  30 [hyper,13,10] {-} m(A).
% 0.40/0.61  31 [para_into,13.1.1,8.4.1,unit_del,30,flip.1] {-} vplus($f2(A,B),A)=B|A=B|vplus(B,$f1(A,B))=A.
% 0.40/0.61  35 [para_from,13.1.1,2.1.1] {-} vplus(A,vd151)!=vd165.
% 0.40/0.61  114 [hyper,31,35,unit_del,6,4] {-} $F.
% 0.40/0.61  
% 0.40/0.61  % SZS output end Refutation
% 0.40/0.61  ------------ end of proof -------------
% 0.40/0.61  
% 0.40/0.61  
% 0.40/0.61  Search stopped by max_proofs option.
% 0.40/0.61  
% 0.40/0.61  
% 0.40/0.61  Search stopped by max_proofs option.
% 0.40/0.61  
% 0.40/0.61  ============ end of search ============
% 0.40/0.61  
% 0.40/0.61  That finishes the proof of the theorem.
% 0.40/0.61  
% 0.40/0.61  Process 21238 finished Wed Jul  6 08:01:48 2022
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