%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : NUM701^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n019.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:57:14 EDT 2023

% Result   : Theorem 3.57s 3.78s
% Output   : Proof 3.57s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : NUM701^1 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.13  % Command    : duper %s
% 0.14/0.34  % Computer : n019.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Fri Aug 25 11:24:13 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 3.57/3.78  SZS status Theorem for theBenchmark.p
% 3.57/3.78  SZS output start Proof for theBenchmark.p
% 3.57/3.78  Clause #0 (by assumption #[]): Eq (less y (suc x)) True
% 3.57/3.78  Clause #1 (by assumption #[]): Eq (∀ (Xx Xy : nat), less Xy (pl Xx n_1) → lessis Xy Xx) True
% 3.57/3.78  Clause #2 (by assumption #[]): Eq (∀ (Xx : nat), Eq (suc Xx) (pl Xx n_1)) True
% 3.57/3.78  Clause #3 (by assumption #[]): Eq (Not (lessis y x)) True
% 3.57/3.78  Clause #4 (by clausification #[3]): Eq (lessis y x) False
% 3.57/3.78  Clause #5 (by clausification #[1]): ∀ (a : nat), Eq (∀ (Xy : nat), less Xy (pl a n_1) → lessis Xy a) True
% 3.57/3.78  Clause #6 (by clausification #[5]): ∀ (a a_1 : nat), Eq (less a (pl a_1 n_1) → lessis a a_1) True
% 3.57/3.78  Clause #7 (by clausification #[6]): ∀ (a a_1 : nat), Or (Eq (less a (pl a_1 n_1)) False) (Eq (lessis a a_1) True)
% 3.57/3.78  Clause #8 (by clausification #[2]): ∀ (a : nat), Eq (Eq (suc a) (pl a n_1)) True
% 3.57/3.78  Clause #9 (by clausification #[8]): ∀ (a : nat), Eq (suc a) (pl a n_1)
% 3.57/3.78  Clause #10 (by backward demodulation #[9, 7]): ∀ (a a_1 : nat), Or (Eq (less a (suc a_1)) False) (Eq (lessis a a_1) True)
% 3.57/3.78  Clause #11 (by superposition #[10, 0]): Or (Eq (lessis y x) True) (Eq False True)
% 3.57/3.78  Clause #12 (by clausification #[11]): Eq (lessis y x) True
% 3.57/3.78  Clause #13 (by superposition #[12, 4]): Eq True False
% 3.57/3.78  Clause #14 (by clausification #[13]): False
% 3.57/3.78  SZS output end Proof for theBenchmark.p
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