TSTP Solution File: NUM674^1 by cocATP---0.2.0

View Problem - Process Solution

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% File     : cocATP---0.2.0
% Problem  : NUM674^1 : TPTP v7.0.0. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n072.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.625MB
% OS       : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan  8 13:11:24 EST 2018

% Result   : Theorem 0.39s
% Output   : Proof 0.39s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : NUM674^1 : TPTP v7.0.0. Released v3.7.0.
% 0.00/0.04  % Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.03/0.23  % Computer : n072.star.cs.uiowa.edu
% 0.03/0.23  % Model    : x86_64 x86_64
% 0.03/0.23  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.03/0.23  % Memory   : 32218.625MB
% 0.03/0.23  % OS       : Linux 3.10.0-693.2.2.el7.x86_64
% 0.03/0.24  % CPULimit : 300
% 0.03/0.24  % DateTime : Fri Jan  5 12:24:33 CST 2018
% 0.03/0.24  % CPUTime  : 
% 0.06/0.28  Python 2.7.13
% 0.39/0.82  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.39/0.82  FOF formula (<kernel.Constant object at 0x2ba49b194830>, <kernel.Type object at 0x2ba49b194200>) of role type named nat_type
% 0.39/0.82  Using role type
% 0.39/0.82  Declaring nat:Type
% 0.39/0.82  FOF formula (<kernel.Constant object at 0x2ba49b191128>, <kernel.Constant object at 0x2ba49b194758>) of role type named x
% 0.39/0.82  Using role type
% 0.39/0.82  Declaring x:nat
% 0.39/0.82  FOF formula (<kernel.Constant object at 0x2ba49b194128>, <kernel.Constant object at 0x2ba49b194758>) of role type named y
% 0.39/0.82  Using role type
% 0.39/0.82  Declaring y:nat
% 0.39/0.82  FOF formula (<kernel.Constant object at 0x2ba49b194830>, <kernel.Constant object at 0x2ba49b194758>) of role type named z
% 0.39/0.82  Using role type
% 0.39/0.82  Declaring z:nat
% 0.39/0.82  FOF formula (((eq nat) x) y) of role axiom named i
% 0.39/0.82  A new axiom: (((eq nat) x) y)
% 0.39/0.82  FOF formula (<kernel.Constant object at 0x2ba49b181680>, <kernel.DependentProduct object at 0x2ba49b194368>) of role type named pl
% 0.39/0.82  Using role type
% 0.39/0.82  Declaring pl:(nat->(nat->nat))
% 0.39/0.82  FOF formula (((eq nat) ((pl z) x)) ((pl z) y)) of role conjecture named satz19e
% 0.39/0.82  Conjecture to prove = (((eq nat) ((pl z) x)) ((pl z) y)):Prop
% 0.39/0.82  We need to prove ['(((eq nat) ((pl z) x)) ((pl z) y))']
% 0.39/0.82  Parameter nat:Type.
% 0.39/0.82  Parameter x:nat.
% 0.39/0.82  Parameter y:nat.
% 0.39/0.82  Parameter z:nat.
% 0.39/0.82  Axiom i:(((eq nat) x) y).
% 0.39/0.82  Parameter pl:(nat->(nat->nat)).
% 0.39/0.82  Trying to prove (((eq nat) ((pl z) x)) ((pl z) y))
% 0.39/0.82  Found i0:=(i (fun (x0:nat)=> (P ((pl z) x0)))):((P ((pl z) x))->(P ((pl z) y)))
% 0.39/0.82  Found (i (fun (x0:nat)=> (P ((pl z) x0)))) as proof of ((P ((pl z) x))->(P ((pl z) y)))
% 0.39/0.82  Found (fun (P:(nat->Prop))=> (i (fun (x0:nat)=> (P ((pl z) x0))))) as proof of ((P ((pl z) x))->(P ((pl z) y)))
% 0.39/0.82  Found (fun (P:(nat->Prop))=> (i (fun (x0:nat)=> (P ((pl z) x0))))) as proof of (((eq nat) ((pl z) x)) ((pl z) y))
% 0.39/0.82  Got proof (fun (P:(nat->Prop))=> (i (fun (x0:nat)=> (P ((pl z) x0)))))
% 0.39/0.82  Time elapsed = 0.081442s
% 0.39/0.82  node=8 cost=-85.000000 depth=2
% 0.39/0.82::::::::::::::::::::::
% 0.39/0.82  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.39/0.82  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.39/0.82  (fun (P:(nat->Prop))=> (i (fun (x0:nat)=> (P ((pl z) x0)))))
% 0.39/0.82  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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