TSTP Solution File: NUM671^1 by cocATP---0.2.0

View Problem - Process Solution

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% File     : cocATP---0.2.0
% Problem  : NUM671^1 : TPTP v7.0.0. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n144.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.625MB
% OS       : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan  8 13:11:23 EST 2018

% Result   : Theorem 0.39s
% Output   : Proof 0.39s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : NUM671^1 : TPTP v7.0.0. Released v3.7.0.
% 0.02/0.03  % Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.02/0.23  % Computer : n144.star.cs.uiowa.edu
% 0.02/0.23  % Model    : x86_64 x86_64
% 0.02/0.23  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.23  % Memory   : 32218.625MB
% 0.02/0.23  % OS       : Linux 3.10.0-693.2.2.el7.x86_64
% 0.02/0.23  % CPULimit : 300
% 0.02/0.23  % DateTime : Fri Jan  5 12:14:19 CST 2018
% 0.02/0.23  % CPUTime  : 
% 0.02/0.25  Python 2.7.13
% 0.39/0.59  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.39/0.59  FOF formula (<kernel.Constant object at 0x2b41e78288c0>, <kernel.Type object at 0x2b41e78286c8>) of role type named nat_type
% 0.39/0.59  Using role type
% 0.39/0.59  Declaring nat:Type
% 0.39/0.59  FOF formula (<kernel.Constant object at 0x2b41e7903dd0>, <kernel.Constant object at 0x2b41e78284d0>) of role type named x
% 0.39/0.59  Using role type
% 0.39/0.59  Declaring x:nat
% 0.39/0.59  FOF formula (<kernel.Constant object at 0x2b41e7828680>, <kernel.Constant object at 0x2b41e78284d0>) of role type named y
% 0.39/0.59  Using role type
% 0.39/0.59  Declaring y:nat
% 0.39/0.59  FOF formula (<kernel.Constant object at 0x2b41e78288c0>, <kernel.Constant object at 0x2b41e78284d0>) of role type named z
% 0.39/0.59  Using role type
% 0.39/0.59  Declaring z:nat
% 0.39/0.59  FOF formula (((eq nat) x) y) of role axiom named i
% 0.39/0.59  A new axiom: (((eq nat) x) y)
% 0.39/0.59  FOF formula (<kernel.Constant object at 0x2b41e7828368>, <kernel.DependentProduct object at 0x2b41e78288c0>) of role type named pl
% 0.39/0.59  Using role type
% 0.39/0.59  Declaring pl:(nat->(nat->nat))
% 0.39/0.59  FOF formula (((eq nat) ((pl x) z)) ((pl y) z)) of role conjecture named satz19b
% 0.39/0.59  Conjecture to prove = (((eq nat) ((pl x) z)) ((pl y) z)):Prop
% 0.39/0.59  We need to prove ['(((eq nat) ((pl x) z)) ((pl y) z))']
% 0.39/0.59  Parameter nat:Type.
% 0.39/0.59  Parameter x:nat.
% 0.39/0.59  Parameter y:nat.
% 0.39/0.59  Parameter z:nat.
% 0.39/0.59  Axiom i:(((eq nat) x) y).
% 0.39/0.59  Parameter pl:(nat->(nat->nat)).
% 0.39/0.59  Trying to prove (((eq nat) ((pl x) z)) ((pl y) z))
% 0.39/0.59  Found i0:=(i (fun (x0:nat)=> (P ((pl x0) z)))):((P ((pl x) z))->(P ((pl y) z)))
% 0.39/0.59  Found (i (fun (x0:nat)=> (P ((pl x0) z)))) as proof of ((P ((pl x) z))->(P ((pl y) z)))
% 0.39/0.59  Found (fun (P:(nat->Prop))=> (i (fun (x0:nat)=> (P ((pl x0) z))))) as proof of ((P ((pl x) z))->(P ((pl y) z)))
% 0.39/0.59  Found (fun (P:(nat->Prop))=> (i (fun (x0:nat)=> (P ((pl x0) z))))) as proof of (((eq nat) ((pl x) z)) ((pl y) z))
% 0.39/0.59  Got proof (fun (P:(nat->Prop))=> (i (fun (x0:nat)=> (P ((pl x0) z)))))
% 0.39/0.59  Time elapsed = 0.081612s
% 0.39/0.59  node=7 cost=-87.000000 depth=2
% 0.39/0.59::::::::::::::::::::::
% 0.39/0.59  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.39/0.59  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.39/0.59  (fun (P:(nat->Prop))=> (i (fun (x0:nat)=> (P ((pl x0) z)))))
% 0.39/0.59  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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