TSTP Solution File: NUM660^1 by cocATP---0.2.0

View Problem - Process Solution

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% File     : cocATP---0.2.0
% Problem  : NUM660^1 : TPTP v7.0.0. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n129.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.625MB
% OS       : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan  8 13:11:20 EST 2018

% Result   : Theorem 1.09s
% Output   : Proof 1.09s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : NUM660^1 : TPTP v7.0.0. Released v3.7.0.
% 0.00/0.03  % Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.03/0.23  % Computer : n129.star.cs.uiowa.edu
% 0.03/0.23  % Model    : x86_64 x86_64
% 0.03/0.23  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.03/0.23  % Memory   : 32218.625MB
% 0.03/0.23  % OS       : Linux 3.10.0-693.2.2.el7.x86_64
% 0.03/0.23  % CPULimit : 300
% 0.03/0.23  % DateTime : Fri Jan  5 11:45:29 CST 2018
% 0.03/0.23  % CPUTime  : 
% 0.07/0.26  Python 2.7.13
% 1.09/1.48  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 1.09/1.48  FOF formula (<kernel.Constant object at 0x2ac4b33b1a70>, <kernel.Type object at 0x2ac4b33b1368>) of role type named nat_type
% 1.09/1.48  Using role type
% 1.09/1.48  Declaring nat:Type
% 1.09/1.48  FOF formula (<kernel.Constant object at 0x2ac4b30c7680>, <kernel.Constant object at 0x2ac4b33b14d0>) of role type named x
% 1.09/1.48  Using role type
% 1.09/1.48  Declaring x:nat
% 1.09/1.48  FOF formula (<kernel.Constant object at 0x2ac4b33b1c20>, <kernel.Constant object at 0x2ac4b33b14d0>) of role type named y
% 1.09/1.48  Using role type
% 1.09/1.48  Declaring y:nat
% 1.09/1.48  FOF formula (<kernel.Constant object at 0x2ac4b33b1a70>, <kernel.DependentProduct object at 0x2ac4b33b15a8>) of role type named more
% 1.09/1.48  Using role type
% 1.09/1.48  Declaring more:(nat->(nat->Prop))
% 1.09/1.48  FOF formula ((((more x) y)->False)->(((eq nat) x) y)) of role axiom named m
% 1.09/1.48  A new axiom: ((((more x) y)->False)->(((eq nat) x) y))
% 1.09/1.48  FOF formula (<kernel.Constant object at 0x2ac4b30caef0>, <kernel.DependentProduct object at 0x2ac4b33b1560>) of role type named less
% 1.09/1.48  Using role type
% 1.09/1.48  Declaring less:(nat->(nat->Prop))
% 1.09/1.48  FOF formula (forall (Xx:nat) (Xy:nat), (((more Xx) Xy)->((less Xy) Xx))) of role axiom named satz11
% 1.09/1.48  A new axiom: (forall (Xx:nat) (Xy:nat), (((more Xx) Xy)->((less Xy) Xx)))
% 1.09/1.48  FOF formula ((((less y) x)->False)->(((eq nat) y) x)) of role conjecture named satz13
% 1.09/1.48  Conjecture to prove = ((((less y) x)->False)->(((eq nat) y) x)):Prop
% 1.09/1.48  We need to prove ['((((less y) x)->False)->(((eq nat) y) x))']
% 1.09/1.48  Parameter nat:Type.
% 1.09/1.48  Parameter x:nat.
% 1.09/1.48  Parameter y:nat.
% 1.09/1.48  Parameter more:(nat->(nat->Prop)).
% 1.09/1.48  Axiom m:((((more x) y)->False)->(((eq nat) x) y)).
% 1.09/1.48  Parameter less:(nat->(nat->Prop)).
% 1.09/1.48  Axiom satz11:(forall (Xx:nat) (Xy:nat), (((more Xx) Xy)->((less Xy) Xx))).
% 1.09/1.48  Trying to prove ((((less y) x)->False)->(((eq nat) y) x))
% 1.09/1.48  Found eq_ref00:=(eq_ref0 x):(((eq nat) x) x)
% 1.09/1.48  Found (eq_ref0 x) as proof of (P x)
% 1.09/1.48  Found ((eq_ref nat) x) as proof of (P x)
% 1.09/1.48  Found ((eq_ref nat) x) as proof of (P x)
% 1.09/1.48  Found satz11000:=(satz1100 x1):((less y) x)
% 1.09/1.48  Found (satz1100 x1) as proof of ((less y) x)
% 1.09/1.48  Found ((satz110 y) x1) as proof of ((less y) x)
% 1.09/1.49  Found (((satz11 x) y) x1) as proof of ((less y) x)
% 1.09/1.49  Found (((satz11 x) y) x1) as proof of ((less y) x)
% 1.09/1.49  Found (x0 (((satz11 x) y) x1)) as proof of False
% 1.09/1.49  Found (fun (x1:((more x) y))=> (x0 (((satz11 x) y) x1))) as proof of False
% 1.09/1.49  Found (fun (x1:((more x) y))=> (x0 (((satz11 x) y) x1))) as proof of (((more x) y)->False)
% 1.09/1.49  Found ((m0 (fun (x1:((more x) y))=> (x0 (((satz11 x) y) x1)))) ((eq_ref nat) x)) as proof of (((eq nat) y) x)
% 1.09/1.49  Found ((m0 (fun (x1:((more x) y))=> (x0 (((satz11 x) y) x1)))) ((eq_ref nat) x)) as proof of (((eq nat) y) x)
% 1.09/1.49  Found (((fun (x00:(((more x) y)->False))=> ((m x00) (fun (x1:nat)=> (((eq nat) x1) x)))) (fun (x1:((more x) y))=> (x0 (((satz11 x) y) x1)))) ((eq_ref nat) x)) as proof of (((eq nat) y) x)
% 1.09/1.49  Found (fun (x0:(((less y) x)->False))=> (((fun (x00:(((more x) y)->False))=> ((m x00) (fun (x1:nat)=> (((eq nat) x1) x)))) (fun (x1:((more x) y))=> (x0 (((satz11 x) y) x1)))) ((eq_ref nat) x))) as proof of (((eq nat) y) x)
% 1.09/1.49  Found (fun (x0:(((less y) x)->False))=> (((fun (x00:(((more x) y)->False))=> ((m x00) (fun (x1:nat)=> (((eq nat) x1) x)))) (fun (x1:((more x) y))=> (x0 (((satz11 x) y) x1)))) ((eq_ref nat) x))) as proof of ((((less y) x)->False)->(((eq nat) y) x))
% 1.09/1.49  Got proof (fun (x0:(((less y) x)->False))=> (((fun (x00:(((more x) y)->False))=> ((m x00) (fun (x1:nat)=> (((eq nat) x1) x)))) (fun (x1:((more x) y))=> (x0 (((satz11 x) y) x1)))) ((eq_ref nat) x)))
% 1.09/1.49  Time elapsed = 0.765775s
% 1.09/1.49  node=160 cost=237.000000 depth=11
% 1.09/1.49::::::::::::::::::::::
% 1.09/1.49  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 1.09/1.49  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 1.09/1.49  (fun (x0:(((less y) x)->False))=> (((fun (x00:(((more x) y)->False))=> ((m x00) (fun (x1:nat)=> (((eq nat) x1) x)))) (fun (x1:((more x) y))=> (x0 (((satz11 x) y) x1)))) ((eq_ref nat) x)))
% 1.09/1.49  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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