TSTP Solution File: NUM632+1 by iProver---3.9
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : iProver---3.9
% Problem : NUM632+1 : TPTP v8.2.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : run_iprover %s %d THM
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Mon Jun 24 12:54:56 EDT 2024
% Result : Theorem 1.66s 1.18s
% Output : CNFRefutation 1.66s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 3
% Syntax : Number of formulae : 13 ( 13 unt; 0 def)
% Number of atoms : 13 ( 12 equ)
% Maximal formula atoms : 1 ( 1 avg)
% Number of connectives : 4 ( 4 ~; 0 |; 0 &)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 2 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 2 ( 0 usr; 1 prp; 0-2 aty)
% Number of functors : 6 ( 6 usr; 4 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn 0 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(f112,axiom,
szDzizrdt0(xd) = sdtlpdtrp0(xd,xn),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',m__5321) ).
fof(f114,axiom,
sdtlpdtrp0(xd,xn) = sdtlpdtrp0(xc,xQ),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',m__5568) ).
fof(f115,conjecture,
szDzizrdt0(xd) = sdtlpdtrp0(xc,xQ),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',m__) ).
fof(f116,negated_conjecture,
szDzizrdt0(xd) != sdtlpdtrp0(xc,xQ),
inference(negated_conjecture,[],[f115]) ).
fof(f124,plain,
szDzizrdt0(xd) != sdtlpdtrp0(xc,xQ),
inference(flattening,[],[f116]) ).
fof(f555,plain,
szDzizrdt0(xd) = sdtlpdtrp0(xd,xn),
inference(cnf_transformation,[],[f112]) ).
fof(f557,plain,
sdtlpdtrp0(xd,xn) = sdtlpdtrp0(xc,xQ),
inference(cnf_transformation,[],[f114]) ).
fof(f558,plain,
szDzizrdt0(xd) != sdtlpdtrp0(xc,xQ),
inference(cnf_transformation,[],[f124]) ).
cnf(c_265,plain,
sdtlpdtrp0(xd,xn) = szDzizrdt0(xd),
inference(cnf_transformation,[],[f555]) ).
cnf(c_267,plain,
sdtlpdtrp0(xc,xQ) = sdtlpdtrp0(xd,xn),
inference(cnf_transformation,[],[f557]) ).
cnf(c_268,negated_conjecture,
sdtlpdtrp0(xc,xQ) != szDzizrdt0(xd),
inference(cnf_transformation,[],[f558]) ).
cnf(c_1823,plain,
sdtlpdtrp0(xc,xQ) = szDzizrdt0(xd),
inference(light_normalisation,[status(thm)],[c_267,c_265]) ).
cnf(c_1824,plain,
$false,
inference(forward_subsumption_resolution,[status(thm)],[c_1823,c_268]) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : NUM632+1 : TPTP v8.2.0. Released v4.0.0.
% 0.03/0.12 % Command : run_iprover %s %d THM
% 0.12/0.34 % Computer : n018.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 300
% 0.12/0.34 % DateTime : Sun Jun 23 02:53:54 EDT 2024
% 0.12/0.34 % CPUTime :
% 0.20/0.48 Running first-order theorem proving
% 0.20/0.48 Running: /export/starexec/sandbox/solver/bin/run_problem --schedule fof_schedule --heuristic_context casc_unsat --no_cores 8 /export/starexec/sandbox/benchmark/theBenchmark.p 300
% 1.66/1.18 % SZS status Started for theBenchmark.p
% 1.66/1.18 % SZS status Theorem for theBenchmark.p
% 1.66/1.18
% 1.66/1.18 %---------------- iProver v3.9 (pre CASC 2024/SMT-COMP 2024) ----------------%
% 1.66/1.18
% 1.66/1.18 ------ iProver source info
% 1.66/1.18
% 1.66/1.18 git: date: 2024-06-12 09:56:46 +0000
% 1.66/1.18 git: sha1: 4869ab62f0a3398f9d3a35e6db7918ebd3847e49
% 1.66/1.18 git: non_committed_changes: false
% 1.66/1.18
% 1.66/1.18 ------ Parsing...
% 1.66/1.18 ------ Clausification by vclausify_rel & Parsing by iProver...
% 1.66/1.18
% 1.66/1.18 ------ Preprocessing...
% 1.66/1.18
% 1.66/1.18 % SZS status Theorem for theBenchmark.p
% 1.66/1.18
% 1.66/1.18 % SZS output start CNFRefutation for theBenchmark.p
% See solution above
% 1.66/1.18
% 1.66/1.18
%------------------------------------------------------------------------------