TSTP Solution File: NUM632+1 by Duper---1.0
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% File : Duper---1.0
% Problem : NUM632+1 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n026.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:56:37 EDT 2023
% Result : Theorem 3.92s 4.08s
% Output : Proof 3.92s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : NUM632+1 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14 % Command : duper %s
% 0.14/0.36 % Computer : n026.cluster.edu
% 0.14/0.36 % Model : x86_64 x86_64
% 0.14/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36 % Memory : 8042.1875MB
% 0.14/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36 % CPULimit : 300
% 0.14/0.36 % WCLimit : 300
% 0.14/0.36 % DateTime : Fri Aug 25 16:55:03 EDT 2023
% 0.14/0.36 % CPUTime :
% 3.92/4.08 SZS status Theorem for theBenchmark.p
% 3.92/4.08 SZS output start Proof for theBenchmark.p
% 3.92/4.08 Clause #110 (by assumption #[]): Eq (Eq (sdtlpdtrp0 xd xn) (szDzizrdt0 xd)) True
% 3.92/4.08 Clause #112 (by assumption #[]): Eq (Eq (sdtlpdtrp0 xc xQ) (sdtlpdtrp0 xd xn)) True
% 3.92/4.08 Clause #113 (by assumption #[]): Eq (Not (Eq (sdtlpdtrp0 xc xQ) (szDzizrdt0 xd))) True
% 3.92/4.08 Clause #322 (by clausification #[110]): Eq (sdtlpdtrp0 xd xn) (szDzizrdt0 xd)
% 3.92/4.08 Clause #444 (by clausification #[113]): Eq (Eq (sdtlpdtrp0 xc xQ) (szDzizrdt0 xd)) False
% 3.92/4.08 Clause #445 (by clausification #[444]): Ne (sdtlpdtrp0 xc xQ) (szDzizrdt0 xd)
% 3.92/4.08 Clause #446 (by clausification #[112]): Eq (sdtlpdtrp0 xc xQ) (sdtlpdtrp0 xd xn)
% 3.92/4.08 Clause #447 (by forward demodulation #[446, 322]): Eq (sdtlpdtrp0 xc xQ) (szDzizrdt0 xd)
% 3.92/4.08 Clause #448 (by forward contextual literal cutting #[447, 445]): False
% 3.92/4.08 SZS output end Proof for theBenchmark.p
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