TSTP Solution File: NUM610+1 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : NUM610+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:28:04 EDT 2022
% Result : Theorem 0.49s 0.69s
% Output : Refutation 0.49s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 6
% Syntax : Number of clauses : 11 ( 6 unt; 0 nHn; 11 RR)
% Number of literals : 24 ( 0 equ; 17 neg)
% Maximal clause size : 6 ( 2 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-2 aty)
% Number of functors : 6 ( 6 usr; 6 con; 0-0 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(13,axiom,
aSet0(xO),
file('NUM610+1.p',unknown),
[] ).
cnf(22,axiom,
aSubsetOf0(xQ,xO),
file('NUM610+1.p',unknown),
[] ).
cnf(26,axiom,
aSubsetOf0(xP,xQ),
file('NUM610+1.p',unknown),
[] ).
cnf(27,axiom,
~ aSubsetOf0(xP,xO),
file('NUM610+1.p',unknown),
[] ).
cnf(75,axiom,
( ~ aSet0(u)
| ~ aSubsetOf0(v,u)
| aSet0(v) ),
file('NUM610+1.p',unknown),
[] ).
cnf(155,axiom,
( ~ aSet0(u)
| ~ aSet0(v)
| ~ aSet0(w)
| ~ aSubsetOf0(u,v)
| ~ aSubsetOf0(v,w)
| aSubsetOf0(u,w) ),
file('NUM610+1.p',unknown),
[] ).
cnf(215,plain,
( ~ aSet0(u)
| ~ aSubsetOf0(v,u)
| ~ aSubsetOf0(w,v)
| aSubsetOf0(w,u) ),
inference(mrr,[status(thm)],[155,75]),
[iquote('0:MRR:155.0,155.1,75.2,75.2')] ).
cnf(228,plain,
( ~ aSet0(xO)
| ~ aSubsetOf0(xP,u)
| ~ aSubsetOf0(u,xO) ),
inference(res,[status(thm),theory(equality)],[215,27]),
[iquote('0:Res:215.3,27.0')] ).
cnf(233,plain,
( ~ aSubsetOf0(u,xO)
| ~ aSubsetOf0(xP,u) ),
inference(mrr,[status(thm)],[228,13]),
[iquote('0:MRR:228.0,13.0')] ).
cnf(260,plain,
~ aSubsetOf0(xP,xQ),
inference(res,[status(thm),theory(equality)],[22,233]),
[iquote('0:Res:22.0,233.0')] ).
cnf(262,plain,
$false,
inference(mrr,[status(thm)],[260,26]),
[iquote('0:MRR:260.0,26.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12 % Problem : NUM610+1 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.13 % Command : run_spass %d %s
% 0.12/0.34 % Computer : n008.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 600
% 0.12/0.34 % DateTime : Wed Jul 6 16:57:53 EDT 2022
% 0.12/0.34 % CPUTime :
% 0.49/0.69
% 0.49/0.69 SPASS V 3.9
% 0.49/0.69 SPASS beiseite: Proof found.
% 0.49/0.69 % SZS status Theorem
% 0.49/0.69 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.49/0.69 SPASS derived 28 clauses, backtracked 0 clauses, performed 0 splits and kept 211 clauses.
% 0.49/0.69 SPASS allocated 101073 KBytes.
% 0.49/0.69 SPASS spent 0:00:00.33 on the problem.
% 0.49/0.69 0:00:00.04 for the input.
% 0.49/0.69 0:00:00.25 for the FLOTTER CNF translation.
% 0.49/0.69 0:00:00.00 for inferences.
% 0.49/0.69 0:00:00.00 for the backtracking.
% 0.49/0.69 0:00:00.02 for the reduction.
% 0.49/0.69
% 0.49/0.69
% 0.49/0.69 Here is a proof with depth 2, length 11 :
% 0.49/0.69 % SZS output start Refutation
% See solution above
% 0.49/0.69 Formulae used in the proof : m__4908 m__5093 m__5195 m__ mDefSub mSubTrans
% 0.49/0.69
%------------------------------------------------------------------------------