%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM587+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:27:49 EDT 2022

% Result   : Theorem 0.52s 0.73s
% Output   : Refutation 0.52s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   11 (   8 unt;   0 nHn;  11 RR)
%            Number of literals    :   17 (   0 equ;  10 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    5 (   2 avg)
%            Number of predicates  :    5 (   4 usr;   1 prp; 0-2 aty)
%            Number of functors    :   14 (  14 usr;   9 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(4,axiom,
    aSet0(xT),
    file('NUM587+1.p',unknown),
    [] ).

cnf(15,axiom,
    ~ aElementOf0(xx,xT),
    file('NUM587+1.p',unknown),
    [] ).

cnf(33,axiom,
    aSubsetOf0(sdtlcdtrc0(xc,szDzozmdt0(xc)),xT),
    file('NUM587+1.p',unknown),
    [] ).

cnf(60,axiom,
    equal(sdtlpdtrp0(xc,sdtpldt0(xQ,szmzizndt0(sdtlpdtrp0(xN,xi)))),xx),
    file('NUM587+1.p',unknown),
    [] ).

cnf(77,axiom,
    aElementOf0(sdtlpdtrp0(xc,sdtpldt0(xQ,szmzizndt0(sdtlpdtrp0(xN,xi)))),sdtlcdtrc0(xc,szDzozmdt0(xc))),
    file('NUM587+1.p',unknown),
    [] ).

cnf(78,axiom,
    ( ~ aSet0(u)
    | ~ aElementOf0(v,w)
    | ~ aSubsetOf0(w,u)
    | aElementOf0(v,u) ),
    file('NUM587+1.p',unknown),
    [] ).

cnf(177,plain,
    aElementOf0(xx,sdtlcdtrc0(xc,szDzozmdt0(xc))),
    inference(rew,[status(thm),theory(equality)],[60,77]),
    [iquote('0:Rew:60.0,77.0')] ).

cnf(197,plain,
    ( ~ aSet0(xT)
    | ~ aSubsetOf0(u,xT)
    | ~ aElementOf0(xx,u) ),
    inference(res,[status(thm),theory(equality)],[78,15]),
    [iquote('0:Res:78.3,15.0')] ).

cnf(204,plain,
    ( ~ aSubsetOf0(u,xT)
    | ~ aElementOf0(xx,u) ),
    inference(mrr,[status(thm)],[197,4]),
    [iquote('0:MRR:197.0,4.0')] ).

cnf(224,plain,
    ~ aElementOf0(xx,sdtlcdtrc0(xc,szDzozmdt0(xc))),
    inference(res,[status(thm),theory(equality)],[33,204]),
    [iquote('0:Res:33.0,204.0')] ).

cnf(226,plain,
    $false,
    inference(mrr,[status(thm)],[224,177]),
    [iquote('0:MRR:224.0,177.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : NUM587+1 : TPTP v8.1.0. Released v4.0.0.
% 0.06/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n014.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Thu Jul  7 04:02:52 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.52/0.73  
% 0.52/0.73  SPASS V 3.9 
% 0.52/0.73  SPASS beiseite: Proof found.
% 0.52/0.73  % SZS status Theorem
% 0.52/0.73  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.52/0.73  SPASS derived 30 clauses, backtracked 0 clauses, performed 0 splits and kept 190 clauses.
% 0.52/0.73  SPASS allocated 101048 KBytes.
% 0.52/0.73  SPASS spent	0:00:00.38 on the problem.
% 0.52/0.73  		0:00:00.04 for the input.
% 0.52/0.73  		0:00:00.29 for the FLOTTER CNF translation.
% 0.52/0.73  		0:00:00.00 for inferences.
% 0.52/0.73  		0:00:00.00 for the backtracking.
% 0.52/0.73  		0:00:00.02 for the reduction.
% 0.52/0.73  
% 0.52/0.73  
% 0.52/0.73  Here is a proof with depth 2, length 11 :
% 0.52/0.73  % SZS output start Refutation
% See solution above
% 0.52/0.73  Formulae used in the proof : m__3291 m__ m__3453 m__4263 mDefSub
% 0.52/0.73  
%------------------------------------------------------------------------------