TSTP Solution File: NUM582+1 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM582+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n023.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:27:45 EDT 2022

% Result   : Theorem 0.72s 0.90s
% Output   : Refutation 0.72s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    8
%            Number of leaves      :   11
% Syntax   : Number of clauses     :   23 (   9 unt;   0 nHn;  23 RR)
%            Number of literals    :   52 (   0 equ;  36 neg)
%            Maximal clause size   :    6 (   2 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    7 (   6 usr;   1 prp; 0-2 aty)
%            Number of functors    :    9 (   9 usr;   8 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(2,axiom,
    aSet0(szNzAzT0),
    file('NUM582+1.p',unknown),
    [] ).

cnf(3,axiom,
    isCountable0(szNzAzT0),
    file('NUM582+1.p',unknown),
    [] ).

cnf(9,axiom,
    aElementOf0(sz00,szNzAzT0),
    file('NUM582+1.p',unknown),
    [] ).

cnf(11,axiom,
    aSubsetOf0(xS,szNzAzT0),
    file('NUM582+1.p',unknown),
    [] ).

cnf(13,axiom,
    aElementOf0(xi,szNzAzT0),
    file('NUM582+1.p',unknown),
    [] ).

cnf(23,axiom,
    equal(sdtlpdtrp0(xN,sz00),xS),
    file('NUM582+1.p',unknown),
    [] ).

cnf(24,axiom,
    ~ aSubsetOf0(sdtlpdtrp0(xN,xi),xS),
    file('NUM582+1.p',unknown),
    [] ).

cnf(34,axiom,
    ( ~ aElementOf0(u,szNzAzT0)
    | sdtlseqdt0(sz00,u) ),
    file('NUM582+1.p',unknown),
    [] ).

cnf(45,axiom,
    ( ~ aSet0(u)
    | ~ aSubsetOf0(v,u)
    | aSet0(v) ),
    file('NUM582+1.p',unknown),
    [] ).

cnf(108,axiom,
    ( ~ sdtlseqdt0(u,v)
    | ~ aElementOf0(u,szNzAzT0)
    | ~ aElementOf0(v,szNzAzT0)
    | aSubsetOf0(sdtlpdtrp0(xN,v),sdtlpdtrp0(xN,u)) ),
    file('NUM582+1.p',unknown),
    [] ).

cnf(121,axiom,
    ( ~ aSet0(u)
    | ~ aSet0(v)
    | ~ aSet0(w)
    | ~ aSubsetOf0(u,v)
    | ~ aSubsetOf0(v,w)
    | aSubsetOf0(u,w) ),
    file('NUM582+1.p',unknown),
    [] ).

cnf(172,plain,
    ( ~ aSet0(u)
    | ~ aSubsetOf0(v,u)
    | ~ aSubsetOf0(w,v)
    | aSubsetOf0(w,u) ),
    inference(mrr,[status(thm)],[121,45]),
    [iquote('0:MRR:121.0,121.1,45.2,45.2')] ).

cnf(179,plain,
    ( ~ aSet0(xS)
    | ~ aSubsetOf0(u,xS)
    | ~ aSubsetOf0(sdtlpdtrp0(xN,xi),u) ),
    inference(res,[status(thm),theory(equality)],[172,24]),
    [iquote('0:Res:172.3,24.0')] ).

cnf(254,plain,
    ( ~ aSet0(szNzAzT0)
    | aSet0(xS) ),
    inference(res,[status(thm),theory(equality)],[11,45]),
    [iquote('0:Res:11.0,45.1')] ).

cnf(258,plain,
    aSet0(xS),
    inference(ssi,[status(thm)],[254,3,2]),
    [iquote('0:SSi:254.0,3.0,2.0')] ).

cnf(259,plain,
    ( ~ aSubsetOf0(u,xS)
    | ~ aSubsetOf0(sdtlpdtrp0(xN,xi),u) ),
    inference(mrr,[status(thm)],[179,258]),
    [iquote('0:MRR:179.0,258.0')] ).

cnf(2069,plain,
    ( ~ sdtlseqdt0(sz00,u)
    | ~ aElementOf0(sz00,szNzAzT0)
    | ~ aElementOf0(u,szNzAzT0)
    | aSubsetOf0(sdtlpdtrp0(xN,u),xS) ),
    inference(spr,[status(thm),theory(equality)],[23,108]),
    [iquote('0:SpR:23.0,108.3')] ).

cnf(2075,plain,
    ( ~ sdtlseqdt0(u,xi)
    | ~ aElementOf0(u,szNzAzT0)
    | ~ aElementOf0(xi,szNzAzT0)
    | ~ aSubsetOf0(sdtlpdtrp0(xN,u),xS) ),
    inference(res,[status(thm),theory(equality)],[108,259]),
    [iquote('0:Res:108.3,259.1')] ).

cnf(2076,plain,
    ( ~ aElementOf0(u,szNzAzT0)
    | aSubsetOf0(sdtlpdtrp0(xN,u),xS) ),
    inference(mrr,[status(thm)],[2069,34,9]),
    [iquote('0:MRR:2069.0,2069.1,34.1,9.0')] ).

cnf(2078,plain,
    ( ~ sdtlseqdt0(u,xi)
    | ~ aElementOf0(u,szNzAzT0)
    | ~ aSubsetOf0(sdtlpdtrp0(xN,u),xS) ),
    inference(mrr,[status(thm)],[2075,13]),
    [iquote('0:MRR:2075.2,13.0')] ).

cnf(2079,plain,
    ( ~ sdtlseqdt0(u,xi)
    | ~ aElementOf0(u,szNzAzT0) ),
    inference(mrr,[status(thm)],[2078,2076]),
    [iquote('0:MRR:2078.2,2076.1')] ).

cnf(2083,plain,
    ( ~ aElementOf0(xi,szNzAzT0)
    | ~ aElementOf0(sz00,szNzAzT0) ),
    inference(res,[status(thm),theory(equality)],[34,2079]),
    [iquote('0:Res:34.1,2079.0')] ).

cnf(2090,plain,
    $false,
    inference(mrr,[status(thm)],[2083,13,9]),
    [iquote('0:MRR:2083.0,2083.1,13.0,9.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : NUM582+1 : TPTP v8.1.0. Released v4.0.0.
% 0.13/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n023.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Wed Jul  6 23:53:26 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.72/0.90  
% 0.72/0.90  SPASS V 3.9 
% 0.72/0.90  SPASS beiseite: Proof found.
% 0.72/0.90  % SZS status Theorem
% 0.72/0.90  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.72/0.90  SPASS derived 1416 clauses, backtracked 119 clauses, performed 9 splits and kept 874 clauses.
% 0.72/0.90  SPASS allocated 101012 KBytes.
% 0.72/0.90  SPASS spent	0:00:00.54 on the problem.
% 0.72/0.90  		0:00:00.04 for the input.
% 0.72/0.90  		0:00:00.24 for the FLOTTER CNF translation.
% 0.72/0.90  		0:00:00.02 for inferences.
% 0.72/0.90  		0:00:00.00 for the backtracking.
% 0.72/0.90  		0:00:00.19 for the reduction.
% 0.72/0.90  
% 0.72/0.90  
% 0.72/0.90  Here is a proof with depth 3, length 23 :
% 0.72/0.90  % SZS output start Refutation
% See solution above
% 0.72/0.90  Formulae used in the proof : mNATSet mZeroNum m__3435 m__3989 m__3623 m__ mZeroLess mDefSub m__3754 mSubTrans
% 0.72/0.90  
%------------------------------------------------------------------------------