TSTP Solution File: NUM582+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : NUM582+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n005.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:19:43 EDT 2022

% Result   : Theorem 1.72s 1.95s
% Output   : Refutation 1.72s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : NUM582+1 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.13  % Command  : sos-script %s
% 0.13/0.34  % Computer : n005.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Wed Jul  6 23:31:52 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.13/0.38  ----- Otter 3.2, August 2001 -----
% 0.13/0.38  The process was started by sandbox on n005.cluster.edu,
% 0.13/0.38  Wed Jul  6 23:31:52 2022
% 0.13/0.38  The command was "./sos".  The process ID is 28809.
% 0.13/0.38  
% 0.13/0.38  set(prolog_style_variables).
% 0.13/0.38  set(auto).
% 0.13/0.38     dependent: set(auto1).
% 0.13/0.38     dependent: set(process_input).
% 0.13/0.38     dependent: clear(print_kept).
% 0.13/0.38     dependent: clear(print_new_demod).
% 0.13/0.38     dependent: clear(print_back_demod).
% 0.13/0.38     dependent: clear(print_back_sub).
% 0.13/0.38     dependent: set(control_memory).
% 0.13/0.38     dependent: assign(max_mem, 12000).
% 0.13/0.38     dependent: assign(pick_given_ratio, 4).
% 0.13/0.38     dependent: assign(stats_level, 1).
% 0.13/0.38     dependent: assign(pick_semantic_ratio, 3).
% 0.13/0.38     dependent: assign(sos_limit, 5000).
% 0.13/0.38     dependent: assign(max_weight, 60).
% 0.13/0.38  clear(print_given).
% 0.13/0.38  
% 0.13/0.38  formula_list(usable).
% 0.13/0.38  
% 0.13/0.38  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=9.
% 0.13/0.38  
% 0.13/0.38  This ia a non-Horn set with equality.  The strategy will be
% 0.13/0.38  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.13/0.38  unit deletion, with positive clauses in sos and nonpositive
% 0.13/0.38  clauses in usable.
% 0.13/0.38  
% 0.13/0.38     dependent: set(knuth_bendix).
% 0.13/0.38     dependent: set(para_from).
% 0.13/0.38     dependent: set(para_into).
% 0.13/0.38     dependent: clear(para_from_right).
% 0.13/0.38     dependent: clear(para_into_right).
% 0.13/0.38     dependent: set(para_from_vars).
% 0.13/0.38     dependent: set(eq_units_both_ways).
% 0.13/0.38     dependent: set(dynamic_demod_all).
% 0.13/0.38     dependent: set(dynamic_demod).
% 0.13/0.38     dependent: set(order_eq).
% 0.13/0.38     dependent: set(back_demod).
% 0.13/0.38     dependent: set(lrpo).
% 0.13/0.38     dependent: set(hyper_res).
% 0.13/0.38     dependent: set(unit_deletion).
% 0.13/0.38     dependent: set(factor).
% 0.13/0.38  
% 0.13/0.38  ------------> process usable:
% 0.13/0.38    Following clause subsumed by 139 during input processing: 0 [] {-} xK!=sz00.
% 0.13/0.38  155 back subsumes 154.
% 0.13/0.38  
% 0.13/0.38  ------------> process sos:
% 0.13/0.38    Following clause subsumed by 210 during input processing: 0 [copy,210,flip.1] {-} A=A.
% 0.13/0.38  210 back subsumes 181.
% 0.13/0.38  210 back subsumes 165.
% 0.13/0.38  210 back subsumes 160.
% 0.13/0.38  210 back subsumes 159.
% 0.13/0.38  210 back subsumes 157.
% 0.13/0.38  210 back subsumes 153.
% 0.13/0.38  210 back subsumes 147.
% 0.13/0.38  
% 0.13/0.38  ======= end of input processing =======
% 0.68/0.86  
% 0.68/0.86  Stopped by limit on insertions
% 0.68/0.86  
% 0.68/0.86  
% 0.68/0.86  Failed to model usable list: disabling FINDER
% 0.68/0.86  
% 0.68/0.86  
% 0.68/0.86  
% 0.68/0.86  -------------- Softie stats --------------
% 0.68/0.86  
% 0.68/0.86  UPDATE_STOP: 300
% 0.68/0.86  SFINDER_TIME_LIMIT: 2
% 0.68/0.86  SHORT_CLAUSE_CUTOFF: 4
% 0.68/0.86  number of clauses in intial UL: 171
% 0.68/0.86  number of clauses initially in problem: 199
% 0.68/0.86  percentage of clauses intially in UL: 85
% 0.68/0.86  percentage of distinct symbols occuring in initial UL: 94
% 0.68/0.86  percent of all initial clauses that are short: 100
% 0.68/0.86  absolute distinct symbol count: 56
% 0.68/0.86     distinct predicate count: 10
% 0.68/0.86     distinct function count: 35
% 0.68/0.86     distinct constant count: 11
% 0.68/0.86  
% 0.68/0.86  ---------- no more Softie stats ----------
% 0.68/0.86  
% 0.68/0.86  
% 0.68/0.86  
% 0.68/0.86  =========== start of search ===========
% 1.63/1.86  
% 1.63/1.86  
% 1.63/1.86  Changing weight limit from 60 to 30.
% 1.63/1.86  
% 1.63/1.86  Resetting weight limit to 30 after 45 givens.
% 1.63/1.86  
% 1.72/1.95  
% 1.72/1.95  -------- PROOF -------- 
% 1.72/1.95  % SZS status Theorem
% 1.72/1.95  % SZS output start Refutation
% 1.72/1.95  
% 1.72/1.95  ----> UNIT CONFLICT at   1.56 sec ----> 6496 [binary,6495.1,146.1] {-} $F.
% 1.72/1.95  
% 1.72/1.95  Length of proof is 2.  Level of proof is 2.
% 1.72/1.95  
% 1.72/1.95  ---------------- PROOF ----------------
% 1.72/1.95  % SZS status Theorem
% 1.72/1.95  % SZS output start Refutation
% 1.72/1.95  
% 1.72/1.95  47 [] {+} -aElementOf0(A,szNzAzT0)|sdtlseqdt0(sz00,A).
% 1.72/1.95  144 [] {+} -aElementOf0(A,szNzAzT0)| -aElementOf0(B,szNzAzT0)| -sdtlseqdt0(B,A)|aSubsetOf0(sdtlpdtrp0(xN,A),sdtlpdtrp0(xN,B)).
% 1.72/1.95  146 [] {+} -aSubsetOf0(sdtlpdtrp0(xN,xi),xS).
% 1.72/1.95  185 [] {-} aElementOf0(sz00,szNzAzT0).
% 1.72/1.95  205,204 [] {-} sdtlpdtrp0(xN,sz00)=xS.
% 1.72/1.95  206 [] {-} aElementOf0(xi,szNzAzT0).
% 1.72/1.95  2101 [hyper,206,47] {-} sdtlseqdt0(sz00,xi).
% 1.72/1.95  6495 [hyper,2101,144,206,185,demod,205] {-} aSubsetOf0(sdtlpdtrp0(xN,xi),xS).
% 1.72/1.95  6496 [binary,6495.1,146.1] {-} $F.
% 1.72/1.95  
% 1.72/1.95  % SZS output end Refutation
% 1.72/1.95  ------------ end of proof -------------
% 1.72/1.95  
% 1.72/1.95  
% 1.72/1.95  Search stopped by max_proofs option.
% 1.72/1.95  
% 1.72/1.95  
% 1.72/1.95  Search stopped by max_proofs option.
% 1.72/1.95  
% 1.72/1.95  ============ end of search ============
% 1.72/1.95  
% 1.72/1.95  That finishes the proof of the theorem.
% 1.72/1.95  
% 1.72/1.95  Process 28809 finished Wed Jul  6 23:31:54 2022
%------------------------------------------------------------------------------