%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM578+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:27:43 EDT 2022

% Result   : Theorem 0.50s 0.67s
% Output   : Refutation 0.50s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   12 (   7 unt;   2 nHn;  12 RR)
%            Number of literals    :   22 (   0 equ;  12 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    9 (   9 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(13,axiom,
    aElementOf0(xi,szNzAzT0),
    file('NUM578+1.p',unknown),
    [] ).

cnf(14,axiom,
    aElementOf0(xj,szNzAzT0),
    file('NUM578+1.p',unknown),
    [] ).

cnf(15,axiom,
    ~ equal(xj,xi),
    file('NUM578+1.p',unknown),
    [] ).

cnf(44,axiom,
    equal(szmzizndt0(sdtlpdtrp0(xN,xj)),szmzizndt0(sdtlpdtrp0(xN,xi))),
    file('NUM578+1.p',unknown),
    [] ).

cnf(63,axiom,
    ( equal(xj,xi)
    | sdtlseqdt0(szszuzczcdt0(xj),xi)
    | sdtlseqdt0(szszuzczcdt0(xi),xj) ),
    file('NUM578+1.p',unknown),
    [] ).

cnf(136,axiom,
    ( ~ aElementOf0(u,szNzAzT0)
    | ~ aElementOf0(v,szNzAzT0)
    | ~ sdtlseqdt0(szszuzczcdt0(v),u)
    | ~ equal(szmzizndt0(sdtlpdtrp0(xN,u)),szmzizndt0(sdtlpdtrp0(xN,v))) ),
    file('NUM578+1.p',unknown),
    [] ).

cnf(169,plain,
    ( sdtlseqdt0(szszuzczcdt0(xj),xi)
    | sdtlseqdt0(szszuzczcdt0(xi),xj) ),
    inference(mrr,[status(thm)],[63,15]),
    [iquote('0:MRR:63.0,15.0')] ).

cnf(198,plain,
    ( ~ aElementOf0(xi,szNzAzT0)
    | ~ sdtlseqdt0(szszuzczcdt0(xi),xj)
    | ~ aElementOf0(xj,szNzAzT0) ),
    inference(res,[status(thm),theory(equality)],[44,136]),
    [iquote('0:Res:44.0,136.0')] ).

cnf(204,plain,
    ( ~ aElementOf0(xj,szNzAzT0)
    | ~ sdtlseqdt0(szszuzczcdt0(xj),xi)
    | ~ aElementOf0(xi,szNzAzT0) ),
    inference(res,[status(thm),theory(equality)],[44,136]),
    [iquote('0:Res:44.0,136.0')] ).

cnf(238,plain,
    ~ sdtlseqdt0(szszuzczcdt0(xi),xj),
    inference(mrr,[status(thm)],[198,13,14]),
    [iquote('0:MRR:198.0,198.2,13.0,14.0')] ).

cnf(239,plain,
    sdtlseqdt0(szszuzczcdt0(xj),xi),
    inference(mrr,[status(thm)],[169,238]),
    [iquote('0:MRR:169.1,238.0')] ).

cnf(240,plain,
    $false,
    inference(mrr,[status(thm)],[204,14,239,13]),
    [iquote('0:MRR:204.0,204.1,204.2,14.0,239.0,13.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : NUM578+1 : TPTP v8.1.0. Released v4.0.0.
% 0.04/0.13  % Command  : run_spass %d %s
% 0.12/0.35  % Computer : n015.cluster.edu
% 0.12/0.35  % Model    : x86_64 x86_64
% 0.12/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.35  % Memory   : 8042.1875MB
% 0.12/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.35  % CPULimit : 300
% 0.12/0.35  % WCLimit  : 600
% 0.12/0.35  % DateTime : Wed Jul  6 09:22:48 EDT 2022
% 0.12/0.35  % CPUTime  : 
% 0.50/0.67  
% 0.50/0.67  SPASS V 3.9 
% 0.50/0.67  SPASS beiseite: Proof found.
% 0.50/0.67  % SZS status Theorem
% 0.50/0.67  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.50/0.67  SPASS derived 47 clauses, backtracked 0 clauses, performed 0 splits and kept 177 clauses.
% 0.50/0.67  SPASS allocated 100987 KBytes.
% 0.50/0.67  SPASS spent	0:00:00.31 on the problem.
% 0.50/0.67  		0:00:00.04 for the input.
% 0.50/0.67  		0:00:00.23 for the FLOTTER CNF translation.
% 0.50/0.67  		0:00:00.00 for inferences.
% 0.50/0.67  		0:00:00.00 for the backtracking.
% 0.50/0.67  		0:00:00.01 for the reduction.
% 0.50/0.67  
% 0.50/0.67  
% 0.50/0.67  Here is a proof with depth 1, length 12 :
% 0.50/0.67  % SZS output start Refutation
% See solution above
% 0.50/0.67  Formulae used in the proof : m__3856 m__ m__3856_02
% 0.50/0.67  
%------------------------------------------------------------------------------