TSTP Solution File: NUM576+3 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM576+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:27:42 EDT 2022

% Result   : Theorem 0.72s 0.87s
% Output   : Refutation 0.72s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   13 (   8 unt;   1 nHn;  13 RR)
%            Number of literals    :   27 (   0 equ;  17 neg)
%            Maximal clause size   :    5 (   2 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   5 con; 0-1 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(14,axiom,
    aElementOf0(xi,szNzAzT0),
    file('NUM576+3.p',unknown),
    [] ).

cnf(15,axiom,
    aElementOf0(xj,szNzAzT0),
    file('NUM576+3.p',unknown),
    [] ).

cnf(16,axiom,
    ~ equal(xj,xi),
    file('NUM576+3.p',unknown),
    [] ).

cnf(24,axiom,
    ~ sdtlseqdt0(szszuzczcdt0(xj),xi),
    file('NUM576+3.p',unknown),
    [] ).

cnf(25,axiom,
    ~ sdtlseqdt0(szszuzczcdt0(xi),xj),
    file('NUM576+3.p',unknown),
    [] ).

cnf(105,axiom,
    ( ~ aElementOf0(u,szNzAzT0)
    | ~ aElementOf0(v,szNzAzT0)
    | sdtlseqdt0(v,u)
    | sdtlseqdt0(szszuzczcdt0(u),v) ),
    file('NUM576+3.p',unknown),
    [] ).

cnf(140,axiom,
    ( ~ sdtlseqdt0(u,v)
    | ~ sdtlseqdt0(v,u)
    | ~ aElementOf0(u,szNzAzT0)
    | ~ aElementOf0(v,szNzAzT0)
    | equal(v,u) ),
    file('NUM576+3.p',unknown),
    [] ).

cnf(233,plain,
    ( ~ aElementOf0(xj,szNzAzT0)
    | ~ sdtlseqdt0(xj,xi)
    | ~ sdtlseqdt0(xi,xj)
    | ~ aElementOf0(xi,szNzAzT0) ),
    inference(res,[status(thm),theory(equality)],[140,16]),
    [iquote('0:Res:140.4,16.0')] ).

cnf(244,plain,
    ( ~ aElementOf0(xj,szNzAzT0)
    | ~ aElementOf0(xi,szNzAzT0)
    | sdtlseqdt0(xj,xi) ),
    inference(res,[status(thm),theory(equality)],[105,25]),
    [iquote('0:Res:105.3,25.0')] ).

cnf(252,plain,
    ( ~ aElementOf0(xi,szNzAzT0)
    | ~ aElementOf0(xj,szNzAzT0)
    | sdtlseqdt0(xi,xj) ),
    inference(res,[status(thm),theory(equality)],[105,24]),
    [iquote('0:Res:105.3,24.0')] ).

cnf(259,plain,
    sdtlseqdt0(xj,xi),
    inference(mrr,[status(thm)],[244,15,14]),
    [iquote('0:MRR:244.0,244.1,15.0,14.0')] ).

cnf(260,plain,
    sdtlseqdt0(xi,xj),
    inference(mrr,[status(thm)],[252,14,15]),
    [iquote('0:MRR:252.0,252.1,14.0,15.0')] ).

cnf(266,plain,
    $false,
    inference(mrr,[status(thm)],[233,15,259,260,14]),
    [iquote('0:MRR:233.0,233.1,233.2,233.3,15.0,259.0,260.0,14.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : NUM576+3 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n008.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Tue Jul  5 10:24:08 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.72/0.87  
% 0.72/0.87  SPASS V 3.9 
% 0.72/0.87  SPASS beiseite: Proof found.
% 0.72/0.87  % SZS status Theorem
% 0.72/0.87  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.72/0.87  SPASS derived 24 clauses, backtracked 0 clauses, performed 0 splits and kept 235 clauses.
% 0.72/0.87  SPASS allocated 102457 KBytes.
% 0.72/0.87  SPASS spent	0:00:00.52 on the problem.
% 0.72/0.87  		0:00:00.04 for the input.
% 0.72/0.87  		0:00:00.43 for the FLOTTER CNF translation.
% 0.72/0.87  		0:00:00.00 for inferences.
% 0.72/0.87  		0:00:00.00 for the backtracking.
% 0.72/0.87  		0:00:00.02 for the reduction.
% 0.72/0.87  
% 0.72/0.87  
% 0.72/0.87  Here is a proof with depth 1, length 13 :
% 0.72/0.87  % SZS output start Refutation
% See solution above
% 0.72/0.87  Formulae used in the proof : m__3856 m__ mLessTotal mLessASymm
% 0.72/0.87  
%------------------------------------------------------------------------------