TSTP Solution File: NUM568+1 by iProver---3.8

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%------------------------------------------------------------------------------
% File     : iProver---3.8
% Problem  : NUM568+1 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : run_iprover %s %d THM

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 11:31:31 EDT 2023

% Result   : Theorem 6.75s 1.62s
% Output   : CNFRefutation 6.75s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :   10
%            Number of leaves      :    5
% Syntax   : Number of formulae    :   25 (   9 unt;   0 def)
%            Number of atoms       :   55 (  28 equ)
%            Maximal formula atoms :    4 (   2 avg)
%            Number of connectives :   49 (  19   ~;  20   |;   8   &)
%                                         (   0 <=>;   2  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    6 (   3 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    3 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   3 con; 0-1 aty)
%            Number of variables   :   18 (   0 sgn;   9   !;   6   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(f27,axiom,
    ! [X0] :
      ( aElementOf0(X0,szNzAzT0)
     => ( ? [X1] :
            ( szszuzczcdt0(X1) = X0
            & aElementOf0(X1,szNzAzT0) )
        | sz00 = X0 ) ),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',mNatExtra) ).

fof(f74,axiom,
    aElementOf0(xK,szNzAzT0),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',m__3418) ).

fof(f79,axiom,
    sz00 != xK,
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',m__3520) ).

fof(f80,conjecture,
    ? [X0] :
      ( szszuzczcdt0(X0) = xK
      & aElementOf0(X0,szNzAzT0) ),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',m__) ).

fof(f81,negated_conjecture,
    ~ ? [X0] :
        ( szszuzczcdt0(X0) = xK
        & aElementOf0(X0,szNzAzT0) ),
    inference(negated_conjecture,[],[f80]) ).

fof(f121,plain,
    ! [X0] :
      ( ? [X1] :
          ( szszuzczcdt0(X1) = X0
          & aElementOf0(X1,szNzAzT0) )
      | sz00 = X0
      | ~ aElementOf0(X0,szNzAzT0) ),
    inference(ennf_transformation,[],[f27]) ).

fof(f122,plain,
    ! [X0] :
      ( ? [X1] :
          ( szszuzczcdt0(X1) = X0
          & aElementOf0(X1,szNzAzT0) )
      | sz00 = X0
      | ~ aElementOf0(X0,szNzAzT0) ),
    inference(flattening,[],[f121]) ).

fof(f190,plain,
    ! [X0] :
      ( szszuzczcdt0(X0) != xK
      | ~ aElementOf0(X0,szNzAzT0) ),
    inference(ennf_transformation,[],[f81]) ).

fof(f219,plain,
    ! [X0] :
      ( ? [X1] :
          ( szszuzczcdt0(X1) = X0
          & aElementOf0(X1,szNzAzT0) )
     => ( szszuzczcdt0(sK8(X0)) = X0
        & aElementOf0(sK8(X0),szNzAzT0) ) ),
    introduced(choice_axiom,[]) ).

fof(f220,plain,
    ! [X0] :
      ( ( szszuzczcdt0(sK8(X0)) = X0
        & aElementOf0(sK8(X0),szNzAzT0) )
      | sz00 = X0
      | ~ aElementOf0(X0,szNzAzT0) ),
    inference(skolemisation,[status(esa),new_symbols(skolem,[sK8])],[f122,f219]) ).

fof(f326,plain,
    ! [X0] :
      ( aElementOf0(sK8(X0),szNzAzT0)
      | sz00 = X0
      | ~ aElementOf0(X0,szNzAzT0) ),
    inference(cnf_transformation,[],[f220]) ).

fof(f327,plain,
    ! [X0] :
      ( szszuzczcdt0(sK8(X0)) = X0
      | sz00 = X0
      | ~ aElementOf0(X0,szNzAzT0) ),
    inference(cnf_transformation,[],[f220]) ).

fof(f420,plain,
    aElementOf0(xK,szNzAzT0),
    inference(cnf_transformation,[],[f74]) ).

fof(f431,plain,
    sz00 != xK,
    inference(cnf_transformation,[],[f79]) ).

fof(f432,plain,
    ! [X0] :
      ( szszuzczcdt0(X0) != xK
      | ~ aElementOf0(X0,szNzAzT0) ),
    inference(cnf_transformation,[],[f190]) ).

cnf(c_100,plain,
    ( ~ aElementOf0(X0,szNzAzT0)
    | szszuzczcdt0(sK8(X0)) = X0
    | X0 = sz00 ),
    inference(cnf_transformation,[],[f327]) ).

cnf(c_101,plain,
    ( ~ aElementOf0(X0,szNzAzT0)
    | X0 = sz00
    | aElementOf0(sK8(X0),szNzAzT0) ),
    inference(cnf_transformation,[],[f326]) ).

cnf(c_194,plain,
    aElementOf0(xK,szNzAzT0),
    inference(cnf_transformation,[],[f420]) ).

cnf(c_205,plain,
    sz00 != xK,
    inference(cnf_transformation,[],[f431]) ).

cnf(c_206,negated_conjecture,
    ( szszuzczcdt0(X0) != xK
    | ~ aElementOf0(X0,szNzAzT0) ),
    inference(cnf_transformation,[],[f432]) ).

cnf(c_18420,plain,
    ( szszuzczcdt0(sK8(xK)) = xK
    | sz00 = xK ),
    inference(superposition,[status(thm)],[c_194,c_100]) ).

cnf(c_18421,plain,
    szszuzczcdt0(sK8(xK)) = xK,
    inference(forward_subsumption_resolution,[status(thm)],[c_18420,c_205]) ).

cnf(c_18573,plain,
    ~ aElementOf0(sK8(xK),szNzAzT0),
    inference(superposition,[status(thm)],[c_18421,c_206]) ).

cnf(c_18579,plain,
    ( ~ aElementOf0(xK,szNzAzT0)
    | sz00 = xK ),
    inference(superposition,[status(thm)],[c_101,c_18573]) ).

cnf(c_18580,plain,
    $false,
    inference(forward_subsumption_resolution,[status(thm)],[c_18579,c_205,c_194]) ).


%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem  : NUM568+1 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14  % Command  : run_iprover %s %d THM
% 0.19/0.38  % Computer : n021.cluster.edu
% 0.19/0.38  % Model    : x86_64 x86_64
% 0.19/0.38  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.19/0.38  % Memory   : 8042.1875MB
% 0.19/0.38  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.19/0.38  % CPULimit : 300
% 0.19/0.38  % WCLimit  : 300
% 0.19/0.38  % DateTime : Fri Aug 25 12:00:11 EDT 2023
% 0.19/0.38  % CPUTime  : 
% 0.23/0.48  Running first-order theorem proving
% 0.23/0.48  Running: /export/starexec/sandbox2/solver/bin/run_problem --schedule fof_schedule --no_cores 8 /export/starexec/sandbox2/benchmark/theBenchmark.p 300
% 6.75/1.62  % SZS status Started for theBenchmark.p
% 6.75/1.62  % SZS status Theorem for theBenchmark.p
% 6.75/1.62  
% 6.75/1.62  %---------------- iProver v3.8 (pre SMT-COMP 2023/CASC 2023) ----------------%
% 6.75/1.62  
% 6.75/1.62  ------  iProver source info
% 6.75/1.62  
% 6.75/1.62  git: date: 2023-05-31 18:12:56 +0000
% 6.75/1.62  git: sha1: 8abddc1f627fd3ce0bcb8b4cbf113b3cc443d7b6
% 6.75/1.62  git: non_committed_changes: false
% 6.75/1.62  git: last_make_outside_of_git: false
% 6.75/1.62  
% 6.75/1.62  ------ Parsing...
% 6.75/1.62  ------ Clausification by vclausify_rel  & Parsing by iProver...
% 6.75/1.62  
% 6.75/1.62  ------ Preprocessing... sup_sim: 0  sf_s  rm: 1 0s  sf_e  pe_s  pe:1:0s pe:2:0s pe_e  sup_sim: 0  sf_s  rm: 2 0s  sf_e  pe_s  pe_e 
% 6.75/1.62  
% 6.75/1.62  ------ Preprocessing... gs_s  sp: 0 0s  gs_e  snvd_s sp: 0 0s snvd_e 
% 6.75/1.62  
% 6.75/1.62  ------ Preprocessing... sf_s  rm: 1 0s  sf_e  sf_s  rm: 0 0s  sf_e 
% 6.75/1.62  ------ Proving...
% 6.75/1.62  ------ Problem Properties 
% 6.75/1.62  
% 6.75/1.62  
% 6.75/1.62  clauses                                 150
% 6.75/1.62  conjectures                             1
% 6.75/1.62  EPR                                     36
% 6.75/1.62  Horn                                    111
% 6.75/1.62  unary                                   18
% 6.75/1.62  binary                                  18
% 6.75/1.62  lits                                    536
% 6.75/1.62  lits eq                                 79
% 6.75/1.62  fd_pure                                 0
% 6.75/1.62  fd_pseudo                               0
% 6.75/1.62  fd_cond                                 10
% 6.75/1.62  fd_pseudo_cond                          24
% 6.75/1.62  AC symbols                              0
% 6.75/1.62  
% 6.75/1.62  ------ Schedule dynamic 5 is on 
% 6.75/1.62  
% 6.75/1.62  ------ Input Options "--resolution_flag false --inst_lit_sel_side none" Time Limit: 10.
% 6.75/1.62  
% 6.75/1.62  
% 6.75/1.62  ------ 
% 6.75/1.62  Current options:
% 6.75/1.62  ------ 
% 6.75/1.62  
% 6.75/1.62  
% 6.75/1.62  
% 6.75/1.62  
% 6.75/1.62  ------ Proving...
% 6.75/1.62  
% 6.75/1.62  
% 6.75/1.62  % SZS status Theorem for theBenchmark.p
% 6.75/1.62  
% 6.75/1.62  % SZS output start CNFRefutation for theBenchmark.p
% See solution above
% 6.75/1.63  
% 6.75/1.63  
%------------------------------------------------------------------------------