TSTP Solution File: NUM565+3 by SPASS---3.9
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : NUM565+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n005.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:27:34 EDT 2022
% Result : Theorem 0.68s 0.90s
% Output : Refutation 0.68s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 5
% Syntax : Number of clauses : 11 ( 8 unt; 0 nHn; 11 RR)
% Number of literals : 16 ( 0 equ; 7 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-2 aty)
% Number of functors : 8 ( 8 usr; 6 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
aSet0(skc1),
file('NUM565+3.p',unknown),
[] ).
cnf(16,axiom,
equal(sz00,xK),
file('NUM565+3.p',unknown),
[] ).
cnf(18,axiom,
equal(sbrdtbr0(skc1),sz00),
file('NUM565+3.p',unknown),
[] ).
cnf(45,axiom,
~ equal(sdtlpdtrp0(xc,slcrc0),sdtlpdtrp0(xc,skc1)),
file('NUM565+3.p',unknown),
[] ).
cnf(70,axiom,
( ~ aSet0(u)
| ~ equal(sbrdtbr0(u),sz00)
| equal(u,slcrc0) ),
file('NUM565+3.p',unknown),
[] ).
cnf(204,plain,
equal(sbrdtbr0(skc1),xK),
inference(rew,[status(thm),theory(equality)],[16,18]),
[iquote('0:Rew:16.0,18.0')] ).
cnf(215,plain,
( ~ aSet0(u)
| ~ equal(sbrdtbr0(u),xK)
| equal(u,slcrc0) ),
inference(rew,[status(thm),theory(equality)],[16,70]),
[iquote('0:Rew:16.0,70.1')] ).
cnf(318,plain,
( ~ aSet0(skc1)
| equal(slcrc0,skc1) ),
inference(res,[status(thm),theory(equality)],[204,215]),
[iquote('0:Res:204.0,215.1')] ).
cnf(383,plain,
equal(slcrc0,skc1),
inference(mrr,[status(thm)],[318,1]),
[iquote('0:MRR:318.0,1.0')] ).
cnf(398,plain,
~ equal(sdtlpdtrp0(xc,skc1),sdtlpdtrp0(xc,skc1)),
inference(rew,[status(thm),theory(equality)],[383,45]),
[iquote('0:Rew:383.0,45.0')] ).
cnf(409,plain,
$false,
inference(obv,[status(thm),theory(equality)],[398]),
[iquote('0:Obv:398.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : NUM565+3 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.13 % Command : run_spass %d %s
% 0.13/0.34 % Computer : n005.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Fri Jul 8 02:16:37 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.68/0.90
% 0.68/0.90 SPASS V 3.9
% 0.68/0.90 SPASS beiseite: Proof found.
% 0.68/0.90 % SZS status Theorem
% 0.68/0.90 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.68/0.90 SPASS derived 157 clauses, backtracked 0 clauses, performed 0 splits and kept 222 clauses.
% 0.68/0.90 SPASS allocated 102343 KBytes.
% 0.68/0.90 SPASS spent 0:00:00.54 on the problem.
% 0.68/0.90 0:00:00.04 for the input.
% 0.68/0.90 0:00:00.45 for the FLOTTER CNF translation.
% 0.68/0.90 0:00:00.00 for inferences.
% 0.68/0.90 0:00:00.00 for the backtracking.
% 0.68/0.90 0:00:00.02 for the reduction.
% 0.68/0.90
% 0.68/0.90
% 0.68/0.90 Here is a proof with depth 1, length 11 :
% 0.68/0.90 % SZS output start Refutation
% See solution above
% 0.68/0.90 Formulae used in the proof : m__ m__3462 mCardEmpty
% 0.68/0.90
%------------------------------------------------------------------------------