TSTP Solution File: NUM561+2 by Duper---1.0

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% File     : Duper---1.0
% Problem  : NUM561+2 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:56:16 EDT 2023

% Result   : Theorem 219.54s 219.80s
% Output   : Proof 219.54s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : NUM561+2 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13  % Command    : duper %s
% 0.14/0.35  % Computer : n020.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Fri Aug 25 14:03:45 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 219.54/219.80  SZS status Theorem for theBenchmark.p
% 219.54/219.80  SZS output start Proof for theBenchmark.p
% 219.54/219.80  Clause #69 (by assumption #[]): Eq (aElementOf0 xx (szDzozmdt0 xF)) True
% 219.54/219.80  Clause #70 (by assumption #[]): Eq
% 219.54/219.80    (Not
% 219.54/219.80      (Or (Exists fun W0 => And (aElementOf0 W0 (szDzozmdt0 xF)) (Eq (sdtlpdtrp0 xF W0) (sdtlpdtrp0 xF xx)))
% 219.54/219.80        (aElementOf0 (sdtlpdtrp0 xF xx) (sdtlcdtrc0 xF (szDzozmdt0 xF)))))
% 219.54/219.80    True
% 219.54/219.80  Clause #907 (by clausification #[70]): Eq
% 219.54/219.80    (Or (Exists fun W0 => And (aElementOf0 W0 (szDzozmdt0 xF)) (Eq (sdtlpdtrp0 xF W0) (sdtlpdtrp0 xF xx)))
% 219.54/219.80      (aElementOf0 (sdtlpdtrp0 xF xx) (sdtlcdtrc0 xF (szDzozmdt0 xF))))
% 219.54/219.80    False
% 219.54/219.80  Clause #909 (by clausification #[907]): Eq (Exists fun W0 => And (aElementOf0 W0 (szDzozmdt0 xF)) (Eq (sdtlpdtrp0 xF W0) (sdtlpdtrp0 xF xx))) False
% 219.54/219.80  Clause #59298 (by clausification #[909]): ∀ (a : Iota), Eq (And (aElementOf0 a (szDzozmdt0 xF)) (Eq (sdtlpdtrp0 xF a) (sdtlpdtrp0 xF xx))) False
% 219.54/219.80  Clause #59299 (by clausification #[59298]): ∀ (a : Iota), Or (Eq (aElementOf0 a (szDzozmdt0 xF)) False) (Eq (Eq (sdtlpdtrp0 xF a) (sdtlpdtrp0 xF xx)) False)
% 219.54/219.80  Clause #59300 (by clausification #[59299]): ∀ (a : Iota), Or (Eq (aElementOf0 a (szDzozmdt0 xF)) False) (Ne (sdtlpdtrp0 xF a) (sdtlpdtrp0 xF xx))
% 219.54/219.80  Clause #59301 (by superposition #[59300, 69]): Or (Ne (sdtlpdtrp0 xF xx) (sdtlpdtrp0 xF xx)) (Eq False True)
% 219.54/219.80  Clause #59303 (by clausification #[59301]): Ne (sdtlpdtrp0 xF xx) (sdtlpdtrp0 xF xx)
% 219.54/219.80  Clause #59304 (by eliminate resolved literals #[59303]): False
% 219.54/219.80  SZS output end Proof for theBenchmark.p
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