TSTP Solution File: NUM561+2 by Duper---1.0
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% File : Duper---1.0
% Problem : NUM561+2 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n020.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:56:16 EDT 2023
% Result : Theorem 219.54s 219.80s
% Output : Proof 219.54s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : NUM561+2 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13 % Command : duper %s
% 0.14/0.35 % Computer : n020.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Fri Aug 25 14:03:45 EDT 2023
% 0.14/0.35 % CPUTime :
% 219.54/219.80 SZS status Theorem for theBenchmark.p
% 219.54/219.80 SZS output start Proof for theBenchmark.p
% 219.54/219.80 Clause #69 (by assumption #[]): Eq (aElementOf0 xx (szDzozmdt0 xF)) True
% 219.54/219.80 Clause #70 (by assumption #[]): Eq
% 219.54/219.80 (Not
% 219.54/219.80 (Or (Exists fun W0 => And (aElementOf0 W0 (szDzozmdt0 xF)) (Eq (sdtlpdtrp0 xF W0) (sdtlpdtrp0 xF xx)))
% 219.54/219.80 (aElementOf0 (sdtlpdtrp0 xF xx) (sdtlcdtrc0 xF (szDzozmdt0 xF)))))
% 219.54/219.80 True
% 219.54/219.80 Clause #907 (by clausification #[70]): Eq
% 219.54/219.80 (Or (Exists fun W0 => And (aElementOf0 W0 (szDzozmdt0 xF)) (Eq (sdtlpdtrp0 xF W0) (sdtlpdtrp0 xF xx)))
% 219.54/219.80 (aElementOf0 (sdtlpdtrp0 xF xx) (sdtlcdtrc0 xF (szDzozmdt0 xF))))
% 219.54/219.80 False
% 219.54/219.80 Clause #909 (by clausification #[907]): Eq (Exists fun W0 => And (aElementOf0 W0 (szDzozmdt0 xF)) (Eq (sdtlpdtrp0 xF W0) (sdtlpdtrp0 xF xx))) False
% 219.54/219.80 Clause #59298 (by clausification #[909]): ∀ (a : Iota), Eq (And (aElementOf0 a (szDzozmdt0 xF)) (Eq (sdtlpdtrp0 xF a) (sdtlpdtrp0 xF xx))) False
% 219.54/219.80 Clause #59299 (by clausification #[59298]): ∀ (a : Iota), Or (Eq (aElementOf0 a (szDzozmdt0 xF)) False) (Eq (Eq (sdtlpdtrp0 xF a) (sdtlpdtrp0 xF xx)) False)
% 219.54/219.80 Clause #59300 (by clausification #[59299]): ∀ (a : Iota), Or (Eq (aElementOf0 a (szDzozmdt0 xF)) False) (Ne (sdtlpdtrp0 xF a) (sdtlpdtrp0 xF xx))
% 219.54/219.80 Clause #59301 (by superposition #[59300, 69]): Or (Ne (sdtlpdtrp0 xF xx) (sdtlpdtrp0 xF xx)) (Eq False True)
% 219.54/219.80 Clause #59303 (by clausification #[59301]): Ne (sdtlpdtrp0 xF xx) (sdtlpdtrp0 xF xx)
% 219.54/219.80 Clause #59304 (by eliminate resolved literals #[59303]): False
% 219.54/219.80 SZS output end Proof for theBenchmark.p
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