TSTP Solution File: NUM555+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : NUM555+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n004.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:19:28 EDT 2022

% Result   : Theorem 1.44s 1.64s
% Output   : Refutation 1.44s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : NUM555+1 : TPTP v8.1.0. Released v4.0.0.
% 0.06/0.13  % Command  : sos-script %s
% 0.13/0.34  % Computer : n004.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Wed Jul  6 01:20:38 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.19/0.40  ----- Otter 3.2, August 2001 -----
% 0.19/0.40  The process was started by sandbox2 on n004.cluster.edu,
% 0.19/0.40  Wed Jul  6 01:20:38 2022
% 0.19/0.40  The command was "./sos".  The process ID is 6080.
% 0.19/0.40  
% 0.19/0.40  set(prolog_style_variables).
% 0.19/0.40  set(auto).
% 0.19/0.40     dependent: set(auto1).
% 0.19/0.40     dependent: set(process_input).
% 0.19/0.40     dependent: clear(print_kept).
% 0.19/0.40     dependent: clear(print_new_demod).
% 0.19/0.40     dependent: clear(print_back_demod).
% 0.19/0.40     dependent: clear(print_back_sub).
% 0.19/0.40     dependent: set(control_memory).
% 0.19/0.40     dependent: assign(max_mem, 12000).
% 0.19/0.40     dependent: assign(pick_given_ratio, 4).
% 0.19/0.40     dependent: assign(stats_level, 1).
% 0.19/0.40     dependent: assign(pick_semantic_ratio, 3).
% 0.19/0.40     dependent: assign(sos_limit, 5000).
% 0.19/0.40     dependent: assign(max_weight, 60).
% 0.19/0.40  clear(print_given).
% 0.19/0.40  
% 0.19/0.40  formula_list(usable).
% 0.19/0.40  
% 0.19/0.40  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=8.
% 0.19/0.40  
% 0.19/0.40  This ia a non-Horn set with equality.  The strategy will be
% 0.19/0.40  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.19/0.40  unit deletion, with positive clauses in sos and nonpositive
% 0.19/0.40  clauses in usable.
% 0.19/0.40  
% 0.19/0.40     dependent: set(knuth_bendix).
% 0.19/0.40     dependent: set(para_from).
% 0.19/0.40     dependent: set(para_into).
% 0.19/0.40     dependent: clear(para_from_right).
% 0.19/0.40     dependent: clear(para_into_right).
% 0.19/0.40     dependent: set(para_from_vars).
% 0.19/0.40     dependent: set(eq_units_both_ways).
% 0.19/0.40     dependent: set(dynamic_demod_all).
% 0.19/0.40     dependent: set(dynamic_demod).
% 0.19/0.40     dependent: set(order_eq).
% 0.19/0.40     dependent: set(back_demod).
% 0.19/0.40     dependent: set(lrpo).
% 0.19/0.40     dependent: set(hyper_res).
% 0.19/0.40     dependent: set(unit_deletion).
% 0.19/0.40     dependent: set(factor).
% 0.19/0.40  
% 0.19/0.40  ------------> process usable:
% 0.19/0.40    Following clause subsumed by 104 during input processing: 0 [] {-} -aElementOf0(xx,xQ).
% 0.19/0.40  113 back subsumes 112.
% 0.19/0.40  
% 0.19/0.40  ------------> process sos:
% 0.19/0.40    Following clause subsumed by 154 during input processing: 0 [copy,154,flip.1] {-} A=A.
% 0.19/0.40  154 back subsumes 123.
% 0.19/0.40  154 back subsumes 118.
% 0.19/0.40  154 back subsumes 117.
% 0.19/0.40  154 back subsumes 115.
% 0.19/0.40  154 back subsumes 111.
% 0.19/0.40  154 back subsumes 105.
% 0.19/0.40  
% 0.19/0.40  ======= end of input processing =======
% 0.75/0.96  
% 0.75/0.96  Stopped by limit on insertions
% 0.75/0.96  
% 0.75/0.96  
% 0.75/0.96  Failed to model usable list: disabling FINDER
% 0.75/0.96  
% 0.75/0.96  
% 0.75/0.96  
% 0.75/0.96  -------------- Softie stats --------------
% 0.75/0.96  
% 0.75/0.96  UPDATE_STOP: 300
% 0.75/0.96  SFINDER_TIME_LIMIT: 2
% 0.75/0.96  SHORT_CLAUSE_CUTOFF: 4
% 0.75/0.96  number of clauses in intial UL: 122
% 0.75/0.96  number of clauses initially in problem: 144
% 0.75/0.96  percentage of clauses intially in UL: 84
% 0.75/0.96  percentage of distinct symbols occuring in initial UL: 92
% 0.75/0.96  percent of all initial clauses that are short: 100
% 0.75/0.96  absolute distinct symbol count: 38
% 0.75/0.96     distinct predicate count: 9
% 0.75/0.96     distinct function count: 19
% 0.75/0.96     distinct constant count: 10
% 0.75/0.96  
% 0.75/0.96  ---------- no more Softie stats ----------
% 0.75/0.96  
% 0.75/0.96  
% 0.75/0.96  
% 0.75/0.96  =========== start of search ===========
% 1.44/1.64  
% 1.44/1.64  -------- PROOF -------- 
% 1.44/1.64  % SZS status Theorem
% 1.44/1.64  % SZS output start Refutation
% 1.44/1.64  
% 1.44/1.64  ----> UNIT CONFLICT at   1.23 sec ----> 3924 [binary,3923.1,104.1] {-} $F.
% 1.44/1.64  
% 1.44/1.64  Length of proof is 1.  Level of proof is 1.
% 1.44/1.64  
% 1.44/1.64  ---------------- PROOF ----------------
% 1.44/1.64  % SZS status Theorem
% 1.44/1.64  % SZS output start Refutation
% 1.44/1.64  
% 1.44/1.64  26 [] {+} -aSet0(A)| -aElement0(B)|C!=sdtmndt0(A,B)| -aElementOf0(D,C)|aElementOf0(D,A).
% 1.44/1.64  104 [] {+} -aElementOf0(xx,xQ).
% 1.44/1.64  144 [] {-} aSet0(xQ).
% 1.44/1.64  148 [] {-} aElement0(xy).
% 1.44/1.64  153 [] {-} aElementOf0(xx,sdtmndt0(xQ,xy)).
% 1.44/1.64  154 [] {-} A=A.
% 1.44/1.64  3923 [hyper,153,26,144,148,154] {-} aElementOf0(xx,xQ).
% 1.44/1.64  3924 [binary,3923.1,104.1] {-} $F.
% 1.44/1.64  
% 1.44/1.64  % SZS output end Refutation
% 1.44/1.64  ------------ end of proof -------------
% 1.44/1.64  
% 1.44/1.64  
% 1.44/1.64  Search stopped by max_proofs option.
% 1.44/1.64  
% 1.44/1.64  
% 1.44/1.64  Search stopped by max_proofs option.
% 1.44/1.64  
% 1.44/1.64  ============ end of search ============
% 1.44/1.64  
% 1.44/1.64  That finishes the proof of the theorem.
% 1.44/1.64  
% 1.44/1.64  Process 6080 finished Wed Jul  6 01:20:39 2022
%------------------------------------------------------------------------------