TSTP Solution File: NUM551+3 by Duper---1.0
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% File : Duper---1.0
% Problem : NUM551+3 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n024.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:56:13 EDT 2023
% Result : Theorem 5.62s 5.89s
% Output : Proof 5.62s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : NUM551+3 : TPTP v8.1.2. Released v4.0.0.
% 0.12/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n024.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Fri Aug 25 09:40:09 EDT 2023
% 0.13/0.34 % CPUTime :
% 5.62/5.89 SZS status Theorem for theBenchmark.p
% 5.62/5.89 SZS output start Proof for theBenchmark.p
% 5.62/5.89 Clause #2 (by assumption #[]): Eq (∀ (W0 : Iota), aSet0 W0 → ∀ (W1 : Iota), aElementOf0 W1 W0 → aElement0 W1) True
% 5.62/5.89 Clause #65 (by assumption #[]): Eq (And (And (aSet0 xQ) (isFinite0 xQ)) (Eq (sbrdtbr0 xQ) xk)) True
% 5.62/5.89 Clause #66 (by assumption #[]): Eq (Not (Or (Not (Exists fun W0 => aElementOf0 W0 xQ)) (Eq xQ slcrc0))) True
% 5.62/5.89 Clause #67 (by assumption #[]): Eq (Not (Exists fun W0 => And (aElement0 W0) (aElementOf0 W0 xQ))) True
% 5.62/5.89 Clause #85 (by clausification #[2]): ∀ (a : Iota), Eq (aSet0 a → ∀ (W1 : Iota), aElementOf0 W1 a → aElement0 W1) True
% 5.62/5.89 Clause #86 (by clausification #[85]): ∀ (a : Iota), Or (Eq (aSet0 a) False) (Eq (∀ (W1 : Iota), aElementOf0 W1 a → aElement0 W1) True)
% 5.62/5.89 Clause #87 (by clausification #[86]): ∀ (a a_1 : Iota), Or (Eq (aSet0 a) False) (Eq (aElementOf0 a_1 a → aElement0 a_1) True)
% 5.62/5.89 Clause #88 (by clausification #[87]): ∀ (a a_1 : Iota), Or (Eq (aSet0 a) False) (Or (Eq (aElementOf0 a_1 a) False) (Eq (aElement0 a_1) True))
% 5.62/5.89 Clause #952 (by clausification #[67]): Eq (Exists fun W0 => And (aElement0 W0) (aElementOf0 W0 xQ)) False
% 5.62/5.89 Clause #953 (by clausification #[952]): ∀ (a : Iota), Eq (And (aElement0 a) (aElementOf0 a xQ)) False
% 5.62/5.89 Clause #954 (by clausification #[953]): ∀ (a : Iota), Or (Eq (aElement0 a) False) (Eq (aElementOf0 a xQ) False)
% 5.62/5.89 Clause #972 (by clausification #[65]): Eq (And (aSet0 xQ) (isFinite0 xQ)) True
% 5.62/5.89 Clause #975 (by clausification #[972]): Eq (aSet0 xQ) True
% 5.62/5.89 Clause #977 (by superposition #[975, 88]): ∀ (a : Iota), Or (Eq True False) (Or (Eq (aElementOf0 a xQ) False) (Eq (aElement0 a) True))
% 5.62/5.89 Clause #1000 (by clausification #[66]): Eq (Or (Not (Exists fun W0 => aElementOf0 W0 xQ)) (Eq xQ slcrc0)) False
% 5.62/5.89 Clause #1002 (by clausification #[1000]): Eq (Not (Exists fun W0 => aElementOf0 W0 xQ)) False
% 5.62/5.89 Clause #1063 (by clausification #[1002]): Eq (Exists fun W0 => aElementOf0 W0 xQ) True
% 5.62/5.89 Clause #1064 (by clausification #[1063]): ∀ (a : Iota), Eq (aElementOf0 (skS.0 11 a) xQ) True
% 5.62/5.89 Clause #1081 (by clausification #[977]): ∀ (a : Iota), Or (Eq (aElementOf0 a xQ) False) (Eq (aElement0 a) True)
% 5.62/5.89 Clause #1082 (by superposition #[1081, 1064]): ∀ (a : Iota), Or (Eq (aElement0 (skS.0 11 a)) True) (Eq False True)
% 5.62/5.89 Clause #1097 (by clausification #[1082]): ∀ (a : Iota), Eq (aElement0 (skS.0 11 a)) True
% 5.62/5.89 Clause #1103 (by superposition #[1097, 954]): ∀ (a : Iota), Or (Eq True False) (Eq (aElementOf0 (skS.0 11 a) xQ) False)
% 5.62/5.89 Clause #1137 (by clausification #[1103]): ∀ (a : Iota), Eq (aElementOf0 (skS.0 11 a) xQ) False
% 5.62/5.89 Clause #1138 (by superposition #[1137, 1064]): Eq False True
% 5.62/5.89 Clause #1139 (by clausification #[1138]): False
% 5.62/5.89 SZS output end Proof for theBenchmark.p
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