%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : NUM550+3 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n007.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:56:12 EDT 2023

% Result   : Theorem 5.09s 5.29s
% Output   : Proof 5.09s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem    : NUM550+3 : TPTP v8.1.2. Released v4.0.0.
% 0.07/0.13  % Command    : duper %s
% 0.14/0.34  % Computer : n007.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 300
% 0.14/0.34  % DateTime   : Fri Aug 25 13:01:41 EDT 2023
% 0.14/0.34  % CPUTime    : 
% 5.09/5.29  SZS status Theorem for theBenchmark.p
% 5.09/5.29  SZS output start Proof for theBenchmark.p
% 5.09/5.29  Clause #23 (by assumption #[]): Eq (aElementOf0 sz00 szNzAzT0) True
% 5.09/5.29  Clause #51 (by assumption #[]): Eq (Eq (slbdtrb0 sz00) slcrc0) True
% 5.09/5.29  Clause #55 (by assumption #[]): Eq (∀ (W0 : Iota), aElementOf0 W0 szNzAzT0 → Eq (sbrdtbr0 (slbdtrb0 W0)) W0) True
% 5.09/5.29  Clause #61 (by assumption #[]): Eq (And (And (aSet0 xS) (aSet0 xT)) (Ne xk sz00)) True
% 5.09/5.29  Clause #65 (by assumption #[]): Eq (And (And (aSet0 xQ) (isFinite0 xQ)) (Eq (sbrdtbr0 xQ) xk)) True
% 5.09/5.29  Clause #66 (by assumption #[]): Eq (Not (Not (And (Not (Exists fun W0 => aElementOf0 W0 xQ)) (Eq xQ slcrc0)))) True
% 5.09/5.29  Clause #83 (by clausification #[51]): Eq (slbdtrb0 sz00) slcrc0
% 5.09/5.29  Clause #201 (by clausification #[55]): ∀ (a : Iota), Eq (aElementOf0 a szNzAzT0 → Eq (sbrdtbr0 (slbdtrb0 a)) a) True
% 5.09/5.29  Clause #202 (by clausification #[201]): ∀ (a : Iota), Or (Eq (aElementOf0 a szNzAzT0) False) (Eq (Eq (sbrdtbr0 (slbdtrb0 a)) a) True)
% 5.09/5.29  Clause #203 (by clausification #[202]): ∀ (a : Iota), Or (Eq (aElementOf0 a szNzAzT0) False) (Eq (sbrdtbr0 (slbdtrb0 a)) a)
% 5.09/5.29  Clause #204 (by superposition #[203, 23]): Or (Eq (sbrdtbr0 (slbdtrb0 sz00)) sz00) (Eq False True)
% 5.09/5.29  Clause #207 (by clausification #[204]): Eq (sbrdtbr0 (slbdtrb0 sz00)) sz00
% 5.09/5.29  Clause #208 (by forward demodulation #[207, 83]): Eq (sbrdtbr0 slcrc0) sz00
% 5.09/5.29  Clause #356 (by clausification #[61]): Eq (Ne xk sz00) True
% 5.09/5.29  Clause #358 (by clausification #[356]): Ne xk sz00
% 5.09/5.29  Clause #956 (by clausification #[65]): Eq (Eq (sbrdtbr0 xQ) xk) True
% 5.09/5.29  Clause #958 (by clausification #[956]): Eq (sbrdtbr0 xQ) xk
% 5.09/5.29  Clause #988 (by clausification #[66]): Eq (Not (And (Not (Exists fun W0 => aElementOf0 W0 xQ)) (Eq xQ slcrc0))) False
% 5.09/5.29  Clause #989 (by clausification #[988]): Eq (And (Not (Exists fun W0 => aElementOf0 W0 xQ)) (Eq xQ slcrc0)) True
% 5.09/5.29  Clause #990 (by clausification #[989]): Eq (Eq xQ slcrc0) True
% 5.09/5.29  Clause #992 (by clausification #[990]): Eq xQ slcrc0
% 5.09/5.29  Clause #994 (by backward demodulation #[992, 958]): Eq (sbrdtbr0 slcrc0) xk
% 5.09/5.29  Clause #1019 (by superposition #[994, 208]): Eq xk sz00
% 5.09/5.29  Clause #1020 (by forward contextual literal cutting #[1019, 358]): False
% 5.09/5.29  SZS output end Proof for theBenchmark.p
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