%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : NUM550+1 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:56:12 EDT 2023

% Result   : Theorem 8.75s 8.97s
% Output   : Proof 8.75s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.11  % Problem    : NUM550+1 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.12  % Command    : duper %s
% 0.11/0.32  % Computer : n008.cluster.edu
% 0.11/0.32  % Model    : x86_64 x86_64
% 0.11/0.32  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.32  % Memory   : 8042.1875MB
% 0.11/0.32  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.11/0.32  % CPULimit   : 300
% 0.11/0.32  % WCLimit    : 300
% 0.11/0.32  % DateTime   : Fri Aug 25 10:14:17 EDT 2023
% 0.11/0.32  % CPUTime    : 
% 8.75/8.97  SZS status Theorem for theBenchmark.p
% 8.75/8.97  SZS output start Proof for theBenchmark.p
% 8.75/8.97  Clause #23 (by assumption #[]): Eq (aElementOf0 sz00 szNzAzT0) True
% 8.75/8.97  Clause #51 (by assumption #[]): Eq (Eq (slbdtrb0 sz00) slcrc0) True
% 8.75/8.97  Clause #55 (by assumption #[]): Eq (∀ (W0 : Iota), aElementOf0 W0 szNzAzT0 → Eq (sbrdtbr0 (slbdtrb0 W0)) W0) True
% 8.75/8.97  Clause #61 (by assumption #[]): Eq (And (And (aSet0 xS) (aSet0 xT)) (Ne xk sz00)) True
% 8.75/8.97  Clause #65 (by assumption #[]): Eq (And (And (aSet0 xQ) (isFinite0 xQ)) (Eq (sbrdtbr0 xQ) xk)) True
% 8.75/8.97  Clause #66 (by assumption #[]): Eq (Not (Ne xQ slcrc0)) True
% 8.75/8.97  Clause #81 (by clausification #[66]): Eq (Ne xQ slcrc0) False
% 8.75/8.97  Clause #82 (by clausification #[81]): Eq xQ slcrc0
% 8.75/8.97  Clause #90 (by clausification #[51]): Eq (slbdtrb0 sz00) slcrc0
% 8.75/8.97  Clause #243 (by clausification #[55]): ∀ (a : Iota), Eq (aElementOf0 a szNzAzT0 → Eq (sbrdtbr0 (slbdtrb0 a)) a) True
% 8.75/8.97  Clause #244 (by clausification #[243]): ∀ (a : Iota), Or (Eq (aElementOf0 a szNzAzT0) False) (Eq (Eq (sbrdtbr0 (slbdtrb0 a)) a) True)
% 8.75/8.97  Clause #245 (by clausification #[244]): ∀ (a : Iota), Or (Eq (aElementOf0 a szNzAzT0) False) (Eq (sbrdtbr0 (slbdtrb0 a)) a)
% 8.75/8.97  Clause #246 (by superposition #[245, 23]): Or (Eq (sbrdtbr0 (slbdtrb0 sz00)) sz00) (Eq False True)
% 8.75/8.97  Clause #266 (by clausification #[246]): Eq (sbrdtbr0 (slbdtrb0 sz00)) sz00
% 8.75/8.97  Clause #267 (by forward demodulation #[266, 90]): Eq (sbrdtbr0 slcrc0) sz00
% 8.75/8.97  Clause #355 (by clausification #[61]): Eq (Ne xk sz00) True
% 8.75/8.97  Clause #357 (by clausification #[355]): Ne xk sz00
% 8.75/8.97  Clause #908 (by clausification #[65]): Eq (Eq (sbrdtbr0 xQ) xk) True
% 8.75/8.97  Clause #910 (by clausification #[908]): Eq (sbrdtbr0 xQ) xk
% 8.75/8.97  Clause #911 (by forward demodulation #[910, 82]): Eq (sbrdtbr0 slcrc0) xk
% 8.75/8.97  Clause #912 (by superposition #[911, 267]): Eq xk sz00
% 8.75/8.97  Clause #913 (by forward contextual literal cutting #[912, 357]): False
% 8.75/8.97  SZS output end Proof for theBenchmark.p
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