%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM545+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:27:21 EDT 2022

% Result   : Theorem 0.18s 0.52s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   14 (   8 unt;   2 nHn;  14 RR)
%            Number of literals    :   20 (   0 equ;   9 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    4 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   2 prp; 0-2 aty)
%            Number of functors    :    7 (   7 usr;   3 con; 0-1 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(8,axiom,
    aElementOf0(skf10(u),xS),
    file('NUM545+2.p',unknown),
    [] ).

cnf(11,axiom,
    ( aElementOf0(szmzazxdt0(xS),xS)
    | skC0 ),
    file('NUM545+2.p',unknown),
    [] ).

cnf(18,axiom,
    ( ~ aElementOf0(u,xS)
    | ~ skC0 ),
    file('NUM545+2.p',unknown),
    [] ).

cnf(25,axiom,
    ( ~ aElementOf0(u,xS)
    | aElementOf0(u,szNzAzT0) ),
    file('NUM545+2.p',unknown),
    [] ).

cnf(26,axiom,
    ( aSubsetOf0(xS,slbdtrb0(szszuzczcdt0(szmzazxdt0(xS))))
    | skC0 ),
    file('NUM545+2.p',unknown),
    [] ).

cnf(29,axiom,
    ( ~ aElementOf0(u,szNzAzT0)
    | aElementOf0(szszuzczcdt0(u),szNzAzT0) ),
    file('NUM545+2.p',unknown),
    [] ).

cnf(32,axiom,
    ( ~ aElementOf0(u,szNzAzT0)
    | ~ aSubsetOf0(xS,slbdtrb0(u)) ),
    file('NUM545+2.p',unknown),
    [] ).

cnf(129,plain,
    ~ skC0,
    inference(res,[status(thm),theory(equality)],[8,18]),
    [iquote('0:Res:8.0,18.0')] ).

cnf(163,plain,
    aElementOf0(szmzazxdt0(xS),xS),
    inference(mrr,[status(thm)],[11,129]),
    [iquote('0:MRR:11.1,129.0')] ).

cnf(165,plain,
    aSubsetOf0(xS,slbdtrb0(szszuzczcdt0(szmzazxdt0(xS)))),
    inference(mrr,[status(thm)],[26,129]),
    [iquote('0:MRR:26.1,129.0')] ).

cnf(182,plain,
    ~ aElementOf0(szszuzczcdt0(szmzazxdt0(xS)),szNzAzT0),
    inference(res,[status(thm),theory(equality)],[165,32]),
    [iquote('0:Res:165.0,32.0')] ).

cnf(193,plain,
    aElementOf0(szmzazxdt0(xS),szNzAzT0),
    inference(res,[status(thm),theory(equality)],[163,25]),
    [iquote('0:Res:163.0,25.0')] ).

cnf(206,plain,
    ~ aElementOf0(szmzazxdt0(xS),szNzAzT0),
    inference(res,[status(thm),theory(equality)],[29,182]),
    [iquote('0:Res:29.1,182.0')] ).

cnf(208,plain,
    $false,
    inference(mrr,[status(thm)],[206,193]),
    [iquote('0:MRR:206.0,193.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.11  % Problem  : NUM545+2 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n020.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Fri Jul  8 00:34:28 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.18/0.52  
% 0.18/0.52  SPASS V 3.9 
% 0.18/0.52  SPASS beiseite: Proof found.
% 0.18/0.52  % SZS status Theorem
% 0.18/0.52  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.18/0.52  SPASS derived 47 clauses, backtracked 0 clauses, performed 0 splits and kept 148 clauses.
% 0.18/0.52  SPASS allocated 99097 KBytes.
% 0.18/0.52  SPASS spent	0:00:00.17 on the problem.
% 0.18/0.52  		0:00:00.04 for the input.
% 0.18/0.52  		0:00:00.10 for the FLOTTER CNF translation.
% 0.18/0.52  		0:00:00.00 for inferences.
% 0.18/0.52  		0:00:00.00 for the backtracking.
% 0.18/0.52  		0:00:00.01 for the reduction.
% 0.18/0.52  
% 0.18/0.52  
% 0.18/0.52  Here is a proof with depth 2, length 14 :
% 0.18/0.52  % SZS output start Refutation
% See solution above
% 0.18/0.52  Formulae used in the proof : m__ mZeroNum m__2035 m__1986 mSuccNum
% 0.18/0.52  
%------------------------------------------------------------------------------