TSTP Solution File: NUM519+1 by Metis---2.4
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%------------------------------------------------------------------------------
% File : Metis---2.4
% Problem : NUM519+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : metis --show proof --show saturation %s
% Computer : n021.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 12:27:22 EDT 2022
% Result : Theorem 0.18s 0.36s
% Output : CNFRefutation 0.18s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 4
% Syntax : Number of formulae : 14 ( 8 unt; 0 def)
% Number of atoms : 20 ( 0 equ)
% Maximal formula atoms : 2 ( 1 avg)
% Number of connectives : 15 ( 9 ~; 4 |; 0 &)
% ( 0 <=>; 2 =>; 0 <=; 0 <~>)
% Maximal formula depth : 4 ( 2 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 2 ( 1 usr; 1 prp; 0-2 aty)
% Number of functors : 4 ( 4 usr; 4 con; 0-0 aty)
% Number of variables : 0 ( 0 sgn 0 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(m__2449,hypothesis,
( doDivides0(xr,xn)
| doDivides0(xr,xm) ) ).
fof(m__2487,hypothesis,
~ doDivides0(xr,xn) ).
fof(m__2698,hypothesis,
~ doDivides0(xr,xm) ).
fof(m__,conjecture,
( doDivides0(xp,xn)
| doDivides0(xp,xm) ) ).
fof(subgoal_0,plain,
( ~ doDivides0(xp,xn)
=> doDivides0(xp,xm) ),
inference(strip,[],[m__]) ).
fof(negate_0_0,plain,
~ ( ~ doDivides0(xp,xn)
=> doDivides0(xp,xm) ),
inference(negate,[],[subgoal_0]) ).
fof(normalize_0_0,plain,
( doDivides0(xr,xm)
| doDivides0(xr,xn) ),
inference(canonicalize,[],[m__2449]) ).
fof(normalize_0_1,plain,
~ doDivides0(xr,xm),
inference(canonicalize,[],[m__2698]) ).
fof(normalize_0_2,plain,
~ doDivides0(xr,xn),
inference(canonicalize,[],[m__2487]) ).
cnf(refute_0_0,plain,
( doDivides0(xr,xm)
| doDivides0(xr,xn) ),
inference(canonicalize,[],[normalize_0_0]) ).
cnf(refute_0_1,plain,
~ doDivides0(xr,xm),
inference(canonicalize,[],[normalize_0_1]) ).
cnf(refute_0_2,plain,
doDivides0(xr,xn),
inference(resolve,[$cnf( doDivides0(xr,xm) )],[refute_0_0,refute_0_1]) ).
cnf(refute_0_3,plain,
~ doDivides0(xr,xn),
inference(canonicalize,[],[normalize_0_2]) ).
cnf(refute_0_4,plain,
$false,
inference(resolve,[$cnf( doDivides0(xr,xn) )],[refute_0_2,refute_0_3]) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : NUM519+1 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.13 % Command : metis --show proof --show saturation %s
% 0.12/0.33 % Computer : n021.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Thu Jul 7 05:23:04 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.12/0.34 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% 0.18/0.36 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.18/0.36
% 0.18/0.36 % SZS output start CNFRefutation for /export/starexec/sandbox/benchmark/theBenchmark.p
% See solution above
% 0.18/0.36
%------------------------------------------------------------------------------