TSTP Solution File: NUM501+1 by ePrincess---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : ePrincess---1.0
% Problem  : NUM501+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : ePrincess-casc -timeout=%d %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 08:45:11 EDT 2022

% Result   : Theorem 23.82s 7.00s
% Output   : Proof 67.88s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : NUM501+1 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.13  % Command  : ePrincess-casc -timeout=%d %s
% 0.13/0.34  % Computer : n021.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Thu Jul  7 16:04:19 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.62/0.64          ____       _                          
% 0.62/0.64    ___  / __ \_____(_)___  ________  __________
% 0.62/0.64   / _ \/ /_/ / ___/ / __ \/ ___/ _ \/ ___/ ___/
% 0.62/0.64  /  __/ ____/ /  / / / / / /__/  __(__  |__  ) 
% 0.62/0.64  \___/_/   /_/  /_/_/ /_/\___/\___/____/____/  
% 0.62/0.64  
% 0.62/0.64  A Theorem Prover for First-Order Logic
% 0.62/0.64  (ePrincess v.1.0)
% 0.62/0.64  
% 0.62/0.64  (c) Philipp Rümmer, 2009-2015
% 0.62/0.64  (c) Peter Backeman, 2014-2015
% 0.62/0.64  (contributions by Angelo Brillout, Peter Baumgartner)
% 0.62/0.64  Free software under GNU Lesser General Public License (LGPL).
% 0.62/0.64  Bug reports to peter@backeman.se
% 0.62/0.64  
% 0.62/0.64  For more information, visit http://user.uu.se/~petba168/breu/
% 0.62/0.64  
% 0.62/0.64  Loading /export/starexec/sandbox/benchmark/theBenchmark.p ...
% 0.73/0.70  Prover 0: Options:  -triggersInConjecture -genTotalityAxioms -tightFunctionScopes -clausifier=simple -reverseFunctionalityPropagation +boolFunsAsPreds -triggerStrategy=allMaximal -resolutionMethod=nonUnifying +ignoreQuantifiers -generateTriggers=all
% 1.92/1.07  Prover 0: Preprocessing ...
% 3.81/1.61  Prover 0: Constructing countermodel ...
% 19.44/5.98  Prover 1: Options:  +triggersInConjecture -genTotalityAxioms -tightFunctionScopes -clausifier=simple +reverseFunctionalityPropagation -boolFunsAsPreds -triggerStrategy=maximal -resolutionMethod=normal +ignoreQuantifiers -generateTriggers=all
% 19.79/6.11  Prover 1: Preprocessing ...
% 20.77/6.27  Prover 1: Constructing countermodel ...
% 23.82/6.99  Prover 1: proved (1009ms)
% 23.82/7.00  Prover 0: stopped
% 23.82/7.00  
% 23.82/7.00  No countermodel exists, formula is valid
% 23.82/7.00  % SZS status Theorem for theBenchmark
% 23.82/7.00  
% 23.82/7.00  Generating proof ... found it (size 2791)
% 65.70/28.79  
% 65.70/28.79  % SZS output start Proof for theBenchmark
% 65.70/28.79  Assumed formulas after preprocessing and simplification: 
% 65.70/28.79  | (0)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] :  ? [v5] : ( ~ (v5 = 0) &  ~ (v4 = 0) &  ~ (v3 = 0) &  ~ (xk = sz10) &  ~ (xk = sz00) &  ~ (xp = xm) &  ~ (xp = xn) &  ~ (sz10 = sz00) & isPrime0(xr) = 0 & isPrime0(xp) = 0 & sdtsldt0(v2, xp) = xk & doDivides0(xr, v2) = v5 & doDivides0(xr, xk) = 0 & doDivides0(xp, v2) = 0 & sdtlseqdt0(xp, xm) = v4 & sdtlseqdt0(xp, xn) = v3 & sdtlseqdt0(xm, xp) = 0 & sdtlseqdt0(xn, xp) = 0 & sdtasdt0(xn, xm) = v2 & sdtpldt0(v0, xp) = v1 & sdtpldt0(xn, xm) = v0 & aNaturalNumber0(xr) = 0 & aNaturalNumber0(xp) = 0 & aNaturalNumber0(xm) = 0 & aNaturalNumber0(xn) = 0 & aNaturalNumber0(sz10) = 0 & aNaturalNumber0(sz00) = 0 &  ~ (isPrime0(sz10) = 0) &  ~ (isPrime0(sz00) = 0) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] :  ! [v10] :  ! [v11] : (v8 = v7 | v6 = sz00 |  ~ (sdtlseqdt0(v9, v10) = v11) |  ~ (sdtasdt0(v6, v8) = v10) |  ~ (sdtasdt0(v6, v7) = v9) |  ? [v12] :  ? [v13] :  ? [v14] :  ? [v15] :  ? [v16] :  ? [v17] :  ? [v18] : (sdtlseqdt0(v16, v17) = v18 & sdtlseqdt0(v7, v8) = v15 & sdtasdt0(v8, v6) = v17 & sdtasdt0(v7, v6) = v16 & aNaturalNumber0(v8) = v14 & aNaturalNumber0(v7) = v13 & aNaturalNumber0(v6) = v12 & ( ~ (v15 = 0) |  ~ (v14 = 0) |  ~ (v13 = 0) |  ~ (v12 = 0) | (v18 = 0 & v11 = 0 &  ~ (v17 = v16) &  ~ (v10 = v9))))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] :  ! [v10] :  ! [v11] : (v7 = v6 |  ~ (sdtlseqdt0(v9, v10) = v11) |  ~ (sdtlseqdt0(v6, v7) = 0) |  ~ (sdtpldt0(v7, v8) = v10) |  ~ (sdtpldt0(v6, v8) = v9) |  ? [v12] :  ? [v13] :  ? [v14] :  ? [v15] : ((sdtlseqdt0(v13, v14) = v15 & sdtpldt0(v8, v7) = v14 & sdtpldt0(v8, v6) = v13 & aNaturalNumber0(v8) = v12 & ( ~ (v12 = 0) | (v15 = 0 & v11 = 0 &  ~ (v14 = v13) &  ~ (v10 = v9)))) | (aNaturalNumber0(v7) = v13 & aNaturalNumber0(v6) = v12 & ( ~ (v13 = 0) |  ~ (v12 = 0))))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] :  ! [v10] :  ! [v11] : (v6 = sz00 |  ~ (sdtsldt0(v10, v6) = v11) |  ~ (sdtsldt0(v7, v6) = v8) |  ~ (sdtasdt0(v9, v7) = v10) |  ? [v12] :  ? [v13] :  ? [v14] : ((doDivides0(v6, v7) = v14 & aNaturalNumber0(v7) = v13 & aNaturalNumber0(v6) = v12 & ( ~ (v14 = 0) |  ~ (v13 = 0) |  ~ (v12 = 0))) | (sdtasdt0(v9, v8) = v13 & aNaturalNumber0(v9) = v12 & ( ~ (v12 = 0) | v13 = v11)))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] :  ! [v10] :  ! [v11] : ( ~ (sdtasdt0(v6, v8) = v10) |  ~ (sdtasdt0(v6, v7) = v9) |  ~ (sdtpldt0(v9, v10) = v11) |  ? [v12] :  ? [v13] :  ? [v14] :  ? [v15] :  ? [v16] :  ? [v17] :  ? [v18] :  ? [v19] :  ? [v20] : (sdtasdt0(v15, v6) = v17 & sdtasdt0(v8, v6) = v19 & sdtasdt0(v7, v6) = v18 & sdtasdt0(v6, v15) = v16 & sdtpldt0(v18, v19) = v20 & sdtpldt0(v7, v8) = v15 & aNaturalNumber0(v8) = v14 & aNaturalNumber0(v7) = v13 & aNaturalNumber0(v6) = v12 & ( ~ (v14 = 0) |  ~ (v13 = 0) |  ~ (v12 = 0) | (v20 = v17 & v16 = v11)))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] :  ! [v10] : (v10 = 0 |  ~ (doDivides0(v6, v9) = v10) |  ~ (sdtpldt0(v7, v8) = v9) |  ? [v11] :  ? [v12] :  ? [v13] :  ? [v14] :  ? [v15] : (doDivides0(v6, v8) = v15 & doDivides0(v6, v7) = v14 & aNaturalNumber0(v8) = v13 & aNaturalNumber0(v7) = v12 & aNaturalNumber0(v6) = v11 & ( ~ (v15 = 0) |  ~ (v14 = 0) |  ~ (v13 = 0) |  ~ (v12 = 0) |  ~ (v11 = 0)))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] :  ! [v10] : (v8 = v7 | v6 = sz00 |  ~ (sdtasdt0(v6, v8) = v10) |  ~ (sdtasdt0(v6, v7) = v9) |  ~ (aNaturalNumber0(v6) = 0) |  ? [v11] :  ? [v12] :  ? [v13] :  ? [v14] : (sdtasdt0(v8, v6) = v14 & sdtasdt0(v7, v6) = v13 & aNaturalNumber0(v8) = v12 & aNaturalNumber0(v7) = v11 & ( ~ (v12 = 0) |  ~ (v11 = 0) | ( ~ (v14 = v13) &  ~ (v10 = v9))))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] :  ! [v10] : (v8 = v7 |  ~ (sdtpldt0(v6, v8) = v10) |  ~ (sdtpldt0(v6, v7) = v9) |  ? [v11] :  ? [v12] :  ? [v13] :  ? [v14] :  ? [v15] : (sdtpldt0(v8, v6) = v15 & sdtpldt0(v7, v6) = v14 & aNaturalNumber0(v8) = v13 & aNaturalNumber0(v7) = v12 & aNaturalNumber0(v6) = v11 & ( ~ (v13 = 0) |  ~ (v12 = 0) |  ~ (v11 = 0) | ( ~ (v15 = v14) &  ~ (v10 = v9))))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] :  ! [v10] : ( ~ (sdtasdt0(v9, v8) = v10) |  ~ (sdtasdt0(v6, v7) = v9) |  ? [v11] :  ? [v12] :  ? [v13] :  ? [v14] :  ? [v15] : (sdtasdt0(v7, v8) = v14 & sdtasdt0(v6, v14) = v15 & aNaturalNumber0(v8) = v13 & aNaturalNumber0(v7) = v12 & aNaturalNumber0(v6) = v11 & ( ~ (v13 = 0) |  ~ (v12 = 0) |  ~ (v11 = 0) | v15 = v10))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] :  ! [v10] : ( ~ (sdtpldt0(v9, v8) = v10) |  ~ (sdtpldt0(v6, v7) = v9) |  ? [v11] :  ? [v12] :  ? [v13] :  ? [v14] :  ? [v15] : (sdtpldt0(v7, v8) = v14 & sdtpldt0(v6, v14) = v15 & aNaturalNumber0(v8) = v13 & aNaturalNumber0(v7) = v12 & aNaturalNumber0(v6) = v11 & ( ~ (v13 = 0) |  ~ (v12 = 0) |  ~ (v11 = 0) | v15 = v10))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v9 = v8 | v6 = sz00 |  ~ (sdtsldt0(v7, v6) = v8) |  ~ (sdtasdt0(v6, v9) = v7) |  ? [v10] :  ? [v11] :  ? [v12] : (( ~ (v10 = 0) & aNaturalNumber0(v9) = v10) | (doDivides0(v6, v7) = v12 & aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v12 = 0) |  ~ (v11 = 0) |  ~ (v10 = 0))))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v9 = v8 |  ~ (sdtmndt0(v7, v6) = v8) |  ~ (sdtpldt0(v6, v9) = v7) |  ? [v10] :  ? [v11] :  ? [v12] : (( ~ (v10 = 0) & aNaturalNumber0(v9) = v10) | (sdtlseqdt0(v6, v7) = v12 & aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v12 = 0) |  ~ (v11 = 0) |  ~ (v10 = 0))))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v9 = v7 | v6 = sz00 |  ~ (sdtsldt0(v7, v6) = v8) |  ~ (sdtasdt0(v6, v8) = v9) |  ? [v10] :  ? [v11] :  ? [v12] : (doDivides0(v6, v7) = v12 & aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v12 = 0) |  ~ (v11 = 0) |  ~ (v10 = 0)))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v9 = v7 |  ~ (sdtmndt0(v7, v6) = v8) |  ~ (sdtpldt0(v6, v8) = v9) |  ? [v10] :  ? [v11] :  ? [v12] : (sdtlseqdt0(v6, v7) = v12 & aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v12 = 0) |  ~ (v11 = 0) |  ~ (v10 = 0)))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v9 = 0 | v6 = sz00 |  ~ (sdtlseqdt0(v7, v8) = v9) |  ~ (sdtasdt0(v7, v6) = v8) |  ? [v10] :  ? [v11] : (aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v11 = 0) |  ~ (v10 = 0)))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v9 = 0 |  ~ (doDivides0(v6, v8) = v9) |  ~ (doDivides0(v6, v7) = 0) |  ? [v10] :  ? [v11] :  ? [v12] :  ? [v13] : (doDivides0(v7, v8) = v13 & aNaturalNumber0(v8) = v12 & aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v13 = 0) |  ~ (v12 = 0) |  ~ (v11 = 0) |  ~ (v10 = 0)))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v9 = 0 |  ~ (sdtlseqdt0(v6, v8) = v9) |  ~ (sdtlseqdt0(v6, v7) = 0) |  ? [v10] :  ? [v11] :  ? [v12] :  ? [v13] : (sdtlseqdt0(v7, v8) = v13 & aNaturalNumber0(v8) = v12 & aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v13 = 0) |  ~ (v12 = 0) |  ~ (v11 = 0) |  ~ (v10 = 0)))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v8 = 0 |  ~ (doDivides0(v6, v7) = v8) |  ~ (sdtasdt0(v6, v9) = v7) |  ? [v10] :  ? [v11] : (( ~ (v10 = 0) & aNaturalNumber0(v9) = v10) | (aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v11 = 0) |  ~ (v10 = 0))))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v8 = 0 |  ~ (sdtlseqdt0(v6, v7) = v8) |  ~ (sdtpldt0(v6, v9) = v7) |  ? [v10] :  ? [v11] : (( ~ (v10 = 0) & aNaturalNumber0(v9) = v10) | (aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v11 = 0) |  ~ (v10 = 0))))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v7 = v6 |  ~ (sdtsldt0(v9, v8) = v7) |  ~ (sdtsldt0(v9, v8) = v6)) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v7 = v6 |  ~ (doDivides0(v9, v8) = v7) |  ~ (doDivides0(v9, v8) = v6)) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v7 = v6 |  ~ (iLess0(v9, v8) = v7) |  ~ (iLess0(v9, v8) = v6)) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v7 = v6 |  ~ (sdtmndt0(v9, v8) = v7) |  ~ (sdtmndt0(v9, v8) = v6)) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v7 = v6 |  ~ (sdtlseqdt0(v9, v8) = v7) |  ~ (sdtlseqdt0(v9, v8) = v6)) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v7 = v6 |  ~ (sdtasdt0(v9, v8) = v7) |  ~ (sdtasdt0(v9, v8) = v6)) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v7 = v6 |  ~ (sdtpldt0(v9, v8) = v7) |  ~ (sdtpldt0(v9, v8) = v6)) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : (v6 = sz00 |  ~ (sdtsldt0(v7, v6) = v8) |  ~ (sdtasdt0(v6, v8) = v9) |  ? [v10] :  ? [v11] :  ? [v12] : ((v10 = 0 & aNaturalNumber0(v8) = 0) | (doDivides0(v6, v7) = v12 & aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v12 = 0) |  ~ (v11 = 0) |  ~ (v10 = 0))))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : ( ~ (doDivides0(v8, v9) = 0) |  ~ (sdtasdt0(v6, v7) = v9) |  ? [v10] :  ? [v11] :  ? [v12] :  ? [v13] :  ? [v14] :  ? [v15] :  ? [v16] :  ? [v17] :  ? [v18] : (isPrime0(v8) = v13 & doDivides0(v8, v7) = v18 & doDivides0(v8, v6) = v17 & iLess0(v15, v1) = v16 & sdtpldt0(v14, v8) = v15 & sdtpldt0(v6, v7) = v14 & aNaturalNumber0(v8) = v12 & aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v16 = 0) |  ~ (v13 = 0) |  ~ (v12 = 0) |  ~ (v11 = 0) |  ~ (v10 = 0) | v18 = 0 | v17 = 0))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : ( ~ (doDivides0(v6, v9) = 0) |  ~ (sdtpldt0(v7, v8) = v9) |  ? [v10] :  ? [v11] :  ? [v12] :  ? [v13] :  ? [v14] : (doDivides0(v6, v8) = v14 & doDivides0(v6, v7) = v13 & aNaturalNumber0(v8) = v12 & aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v13 = 0) |  ~ (v12 = 0) |  ~ (v11 = 0) |  ~ (v10 = 0) | v14 = 0))) &  ! [v6] :  ! [v7] :  ! [v8] :  ! [v9] : ( ~ (sdtmndt0(v7, v6) = v8) |  ~ (sdtpldt0(v6, v8) = v9) |  ? [v10] :  ? [v11] :  ? [v12] : ((v10 = 0 & aNaturalNumber0(v8) = 0) | (sdtlseqdt0(v6, v7) = v12 & aNaturalNumber0(v7) = v11 & aNaturalNumber0(v6) = v10 & ( ~ (v12 = 0) |  ~ (v11 = 0) |  ~ (v10 = 0))))) &  ! [v6] :  ! [v7] :  ! [v8] : (v8 = 0 | v7 = v6 |  ~ (iLess0(v6, v7) = v8) |  ? [v9] :  ? [v10] :  ? [v11] : (sdtlseqdt0(v6, v7) = v11 & aNaturalNumber0(v7) = v10 & aNaturalNumber0(v6) = v9 & ( ~ (v11 = 0) |  ~ (v10 = 0) |  ~ (v9 = 0)))) &  ! [v6] :  ! [v7] :  ! [v8] : (v8 = 0 |  ~ (sdtlseqdt0(v6, v7) = v8) |  ? [v9] :  ? [v10] :  ? [v11] : (sdtlseqdt0(v7, v6) = v11 & aNaturalNumber0(v7) = v10 & aNaturalNumber0(v6) = v9 & ( ~ (v10 = 0) |  ~ (v9 = 0) | (v11 = 0 &  ~ (v7 = v6))))) &  ! [v6] :  ! [v7] :  ! [v8] : (v7 = v6 |  ~ (isPrime0(v8) = v7) |  ~ (isPrime0(v8) = v6)) &  ! [v6] :  ! [v7] :  ! [v8] : (v7 = v6 |  ~ (aNaturalNumber0(v8) = v7) |  ~ (aNaturalNumber0(v8) = v6)) &  ! [v6] :  ! [v7] :  ! [v8] : ( ~ (sdtasdt0(v6, v7) = v8) |  ? [v9] :  ? [v10] :  ? [v11] : (sdtasdt0(v7, v6) = v11 & aNaturalNumber0(v7) = v10 & aNaturalNumber0(v6) = v9 & ( ~ (v10 = 0) |  ~ (v9 = 0) | v11 = v8))) &  ! [v6] :  ! [v7] :  ! [v8] : ( ~ (sdtasdt0(v6, v7) = v8) |  ? [v9] :  ? [v10] :  ? [v11] : (aNaturalNumber0(v8) = v11 & aNaturalNumber0(v7) = v10 & aNaturalNumber0(v6) = v9 & ( ~ (v10 = 0) |  ~ (v9 = 0) | v11 = 0))) &  ! [v6] :  ! [v7] :  ! [v8] : ( ~ (sdtpldt0(v6, v7) = v8) |  ? [v9] :  ? [v10] :  ? [v11] : (sdtpldt0(v7, v6) = v11 & aNaturalNumber0(v7) = v10 & aNaturalNumber0(v6) = v9 & ( ~ (v10 = 0) |  ~ (v9 = 0) | v11 = v8))) &  ! [v6] :  ! [v7] :  ! [v8] : ( ~ (sdtpldt0(v6, v7) = v8) |  ? [v9] :  ? [v10] :  ? [v11] : (aNaturalNumber0(v8) = v11 & aNaturalNumber0(v7) = v10 & aNaturalNumber0(v6) = v9 & ( ~ (v10 = 0) |  ~ (v9 = 0) | v11 = 0))) &  ! [v6] :  ! [v7] : (v7 = v6 | v7 = sz10 |  ~ (isPrime0(v6) = 0) |  ~ (doDivides0(v7, v6) = 0) |  ? [v8] : (( ~ (v8 = 0) & aNaturalNumber0(v7) = v8) | ( ~ (v8 = 0) & aNaturalNumber0(v6) = v8))) &  ! [v6] :  ! [v7] : (v7 = v6 |  ~ (sdtlseqdt0(v6, v7) = 0) |  ? [v8] :  ? [v9] :  ? [v10] : (sdtlseqdt0(v7, v6) = v10 & aNaturalNumber0(v7) = v9 & aNaturalNumber0(v6) = v8 & ( ~ (v10 = 0) |  ~ (v9 = 0) |  ~ (v8 = 0)))) &  ! [v6] :  ! [v7] : (v7 = sz00 | v6 = sz00 |  ~ (sdtasdt0(v6, v7) = sz00) |  ? [v8] :  ? [v9] : (aNaturalNumber0(v7) = v9 & aNaturalNumber0(v6) = v8 & ( ~ (v9 = 0) |  ~ (v8 = 0)))) &  ! [v6] :  ! [v7] : (v7 = sz00 |  ~ (doDivides0(v6, v7) = 0) |  ? [v8] :  ? [v9] :  ? [v10] : (sdtlseqdt0(v6, v7) = v10 & aNaturalNumber0(v7) = v9 & aNaturalNumber0(v6) = v8 & ( ~ (v9 = 0) |  ~ (v8 = 0) | v10 = 0))) &  ! [v6] :  ! [v7] : (v7 = sz00 |  ~ (sdtpldt0(v6, v7) = sz00) |  ? [v8] :  ? [v9] : (aNaturalNumber0(v7) = v9 & aNaturalNumber0(v6) = v8 & ( ~ (v9 = 0) |  ~ (v8 = 0)))) &  ! [v6] :  ! [v7] : (v7 = 0 | v6 = sz10 | v6 = sz00 |  ~ (isPrime0(v6) = v7) |  ? [v8] :  ? [v9] :  ? [v10] : ((v10 = 0 & v9 = 0 &  ~ (v8 = v6) &  ~ (v8 = sz10) & doDivides0(v8, v6) = 0 & aNaturalNumber0(v8) = 0) | ( ~ (v8 = 0) & aNaturalNumber0(v6) = v8))) &  ! [v6] :  ! [v7] : (v7 = 0 | v6 = sz10 | v6 = sz00 |  ~ (sdtlseqdt0(sz10, v6) = v7) |  ? [v8] : ( ~ (v8 = 0) & aNaturalNumber0(v6) = v8)) &  ! [v6] :  ! [v7] : (v7 = 0 |  ~ (sdtlseqdt0(v6, v6) = v7) |  ? [v8] : ( ~ (v8 = 0) & aNaturalNumber0(v6) = v8)) &  ! [v6] :  ! [v7] : (v6 = sz00 |  ~ (sdtpldt0(v6, v7) = sz00) |  ? [v8] :  ? [v9] : (aNaturalNumber0(v7) = v9 & aNaturalNumber0(v6) = v8 & ( ~ (v9 = 0) |  ~ (v8 = 0)))) &  ! [v6] :  ! [v7] : ( ~ (doDivides0(v6, v7) = 0) |  ? [v8] :  ? [v9] :  ? [v10] : ((v10 = v7 & v9 = 0 & sdtasdt0(v6, v8) = v7 & aNaturalNumber0(v8) = 0) | (aNaturalNumber0(v7) = v9 & aNaturalNumber0(v6) = v8 & ( ~ (v9 = 0) |  ~ (v8 = 0))))) &  ! [v6] :  ! [v7] : ( ~ (sdtlseqdt0(v6, v7) = 0) |  ? [v8] :  ? [v9] :  ? [v10] : ((v10 = v7 & v9 = 0 & sdtpldt0(v6, v8) = v7 & aNaturalNumber0(v8) = 0) | (aNaturalNumber0(v7) = v9 & aNaturalNumber0(v6) = v8 & ( ~ (v9 = 0) |  ~ (v8 = 0))))) &  ! [v6] :  ! [v7] : ( ~ (sdtasdt0(sz10, v6) = v7) |  ? [v8] :  ? [v9] : (sdtasdt0(v6, sz10) = v9 & aNaturalNumber0(v6) = v8 & ( ~ (v8 = 0) | (v9 = v6 & v7 = v6)))) &  ! [v6] :  ! [v7] : ( ~ (sdtasdt0(sz00, v6) = v7) |  ? [v8] :  ? [v9] : (sdtasdt0(v6, sz00) = v9 & aNaturalNumber0(v6) = v8 & ( ~ (v8 = 0) | (v9 = sz00 & v7 = sz00)))) &  ! [v6] :  ! [v7] : ( ~ (sdtpldt0(sz00, v6) = v7) |  ? [v8] :  ? [v9] : (sdtpldt0(v6, sz00) = v9 & aNaturalNumber0(v6) = v8 & ( ~ (v8 = 0) | (v9 = v6 & v7 = v6)))) &  ! [v6] : (v6 = sz10 | v6 = sz00 |  ~ (aNaturalNumber0(v6) = 0) |  ? [v7] : (isPrime0(v7) = 0 & doDivides0(v7, v6) = 0 & aNaturalNumber0(v7) = 0)))
% 66.03/28.86  | Instantiating (0) with all_0_0_0, all_0_1_1, all_0_2_2, all_0_3_3, all_0_4_4, all_0_5_5 yields:
% 66.03/28.86  | (1)  ~ (all_0_0_0 = 0) &  ~ (all_0_1_1 = 0) &  ~ (all_0_2_2 = 0) &  ~ (xk = sz10) &  ~ (xk = sz00) &  ~ (xp = xm) &  ~ (xp = xn) &  ~ (sz10 = sz00) & isPrime0(xr) = 0 & isPrime0(xp) = 0 & sdtsldt0(all_0_3_3, xp) = xk & doDivides0(xr, all_0_3_3) = all_0_0_0 & doDivides0(xr, xk) = 0 & doDivides0(xp, all_0_3_3) = 0 & sdtlseqdt0(xp, xm) = all_0_1_1 & sdtlseqdt0(xp, xn) = all_0_2_2 & sdtlseqdt0(xm, xp) = 0 & sdtlseqdt0(xn, xp) = 0 & sdtasdt0(xn, xm) = all_0_3_3 & sdtpldt0(all_0_5_5, xp) = all_0_4_4 & sdtpldt0(xn, xm) = all_0_5_5 & aNaturalNumber0(xr) = 0 & aNaturalNumber0(xp) = 0 & aNaturalNumber0(xm) = 0 & aNaturalNumber0(xn) = 0 & aNaturalNumber0(sz10) = 0 & aNaturalNumber0(sz00) = 0 &  ~ (isPrime0(sz10) = 0) &  ~ (isPrime0(sz00) = 0) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] :  ! [v5] : (v2 = v1 | v0 = sz00 |  ~ (sdtlseqdt0(v3, v4) = v5) |  ~ (sdtasdt0(v0, v2) = v4) |  ~ (sdtasdt0(v0, v1) = v3) |  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] :  ? [v10] :  ? [v11] :  ? [v12] : (sdtlseqdt0(v10, v11) = v12 & sdtlseqdt0(v1, v2) = v9 & sdtasdt0(v2, v0) = v11 & sdtasdt0(v1, v0) = v10 & aNaturalNumber0(v2) = v8 & aNaturalNumber0(v1) = v7 & aNaturalNumber0(v0) = v6 & ( ~ (v9 = 0) |  ~ (v8 = 0) |  ~ (v7 = 0) |  ~ (v6 = 0) | (v12 = 0 & v5 = 0 &  ~ (v11 = v10) &  ~ (v4 = v3))))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] :  ! [v5] : (v1 = v0 |  ~ (sdtlseqdt0(v3, v4) = v5) |  ~ (sdtlseqdt0(v0, v1) = 0) |  ~ (sdtpldt0(v1, v2) = v4) |  ~ (sdtpldt0(v0, v2) = v3) |  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] : ((sdtlseqdt0(v7, v8) = v9 & sdtpldt0(v2, v1) = v8 & sdtpldt0(v2, v0) = v7 & aNaturalNumber0(v2) = v6 & ( ~ (v6 = 0) | (v9 = 0 & v5 = 0 &  ~ (v8 = v7) &  ~ (v4 = v3)))) | (aNaturalNumber0(v1) = v7 & aNaturalNumber0(v0) = v6 & ( ~ (v7 = 0) |  ~ (v6 = 0))))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] :  ! [v5] : (v0 = sz00 |  ~ (sdtsldt0(v4, v0) = v5) |  ~ (sdtsldt0(v1, v0) = v2) |  ~ (sdtasdt0(v3, v1) = v4) |  ? [v6] :  ? [v7] :  ? [v8] : ((doDivides0(v0, v1) = v8 & aNaturalNumber0(v1) = v7 & aNaturalNumber0(v0) = v6 & ( ~ (v8 = 0) |  ~ (v7 = 0) |  ~ (v6 = 0))) | (sdtasdt0(v3, v2) = v7 & aNaturalNumber0(v3) = v6 & ( ~ (v6 = 0) | v7 = v5)))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] :  ! [v5] : ( ~ (sdtasdt0(v0, v2) = v4) |  ~ (sdtasdt0(v0, v1) = v3) |  ~ (sdtpldt0(v3, v4) = v5) |  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] :  ? [v10] :  ? [v11] :  ? [v12] :  ? [v13] :  ? [v14] : (sdtasdt0(v9, v0) = v11 & sdtasdt0(v2, v0) = v13 & sdtasdt0(v1, v0) = v12 & sdtasdt0(v0, v9) = v10 & sdtpldt0(v12, v13) = v14 & sdtpldt0(v1, v2) = v9 & aNaturalNumber0(v2) = v8 & aNaturalNumber0(v1) = v7 & aNaturalNumber0(v0) = v6 & ( ~ (v8 = 0) |  ~ (v7 = 0) |  ~ (v6 = 0) | (v14 = v11 & v10 = v5)))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] : (v4 = 0 |  ~ (doDivides0(v0, v3) = v4) |  ~ (sdtpldt0(v1, v2) = v3) |  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] : (doDivides0(v0, v2) = v9 & doDivides0(v0, v1) = v8 & aNaturalNumber0(v2) = v7 & aNaturalNumber0(v1) = v6 & aNaturalNumber0(v0) = v5 & ( ~ (v9 = 0) |  ~ (v8 = 0) |  ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0)))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] : (v2 = v1 | v0 = sz00 |  ~ (sdtasdt0(v0, v2) = v4) |  ~ (sdtasdt0(v0, v1) = v3) |  ~ (aNaturalNumber0(v0) = 0) |  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] : (sdtasdt0(v2, v0) = v8 & sdtasdt0(v1, v0) = v7 & aNaturalNumber0(v2) = v6 & aNaturalNumber0(v1) = v5 & ( ~ (v6 = 0) |  ~ (v5 = 0) | ( ~ (v8 = v7) &  ~ (v4 = v3))))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] : (v2 = v1 |  ~ (sdtpldt0(v0, v2) = v4) |  ~ (sdtpldt0(v0, v1) = v3) |  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] : (sdtpldt0(v2, v0) = v9 & sdtpldt0(v1, v0) = v8 & aNaturalNumber0(v2) = v7 & aNaturalNumber0(v1) = v6 & aNaturalNumber0(v0) = v5 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) | ( ~ (v9 = v8) &  ~ (v4 = v3))))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] : ( ~ (sdtasdt0(v3, v2) = v4) |  ~ (sdtasdt0(v0, v1) = v3) |  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] : (sdtasdt0(v1, v2) = v8 & sdtasdt0(v0, v8) = v9 & aNaturalNumber0(v2) = v7 & aNaturalNumber0(v1) = v6 & aNaturalNumber0(v0) = v5 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) | v9 = v4))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] : ( ~ (sdtpldt0(v3, v2) = v4) |  ~ (sdtpldt0(v0, v1) = v3) |  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] : (sdtpldt0(v1, v2) = v8 & sdtpldt0(v0, v8) = v9 & aNaturalNumber0(v2) = v7 & aNaturalNumber0(v1) = v6 & aNaturalNumber0(v0) = v5 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) | v9 = v4))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = v2 | v0 = sz00 |  ~ (sdtsldt0(v1, v0) = v2) |  ~ (sdtasdt0(v0, v3) = v1) |  ? [v4] :  ? [v5] :  ? [v6] : (( ~ (v4 = 0) & aNaturalNumber0(v3) = v4) | (doDivides0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0))))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = v2 |  ~ (sdtmndt0(v1, v0) = v2) |  ~ (sdtpldt0(v0, v3) = v1) |  ? [v4] :  ? [v5] :  ? [v6] : (( ~ (v4 = 0) & aNaturalNumber0(v3) = v4) | (sdtlseqdt0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0))))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = v1 | v0 = sz00 |  ~ (sdtsldt0(v1, v0) = v2) |  ~ (sdtasdt0(v0, v2) = v3) |  ? [v4] :  ? [v5] :  ? [v6] : (doDivides0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0)))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = v1 |  ~ (sdtmndt0(v1, v0) = v2) |  ~ (sdtpldt0(v0, v2) = v3) |  ? [v4] :  ? [v5] :  ? [v6] : (sdtlseqdt0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0)))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = 0 | v0 = sz00 |  ~ (sdtlseqdt0(v1, v2) = v3) |  ~ (sdtasdt0(v1, v0) = v2) |  ? [v4] :  ? [v5] : (aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v5 = 0) |  ~ (v4 = 0)))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = 0 |  ~ (doDivides0(v0, v2) = v3) |  ~ (doDivides0(v0, v1) = 0) |  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] : (doDivides0(v1, v2) = v7 & aNaturalNumber0(v2) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0)))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = 0 |  ~ (sdtlseqdt0(v0, v2) = v3) |  ~ (sdtlseqdt0(v0, v1) = 0) |  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] : (sdtlseqdt0(v1, v2) = v7 & aNaturalNumber0(v2) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0)))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v2 = 0 |  ~ (doDivides0(v0, v1) = v2) |  ~ (sdtasdt0(v0, v3) = v1) |  ? [v4] :  ? [v5] : (( ~ (v4 = 0) & aNaturalNumber0(v3) = v4) | (aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v5 = 0) |  ~ (v4 = 0))))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v2 = 0 |  ~ (sdtlseqdt0(v0, v1) = v2) |  ~ (sdtpldt0(v0, v3) = v1) |  ? [v4] :  ? [v5] : (( ~ (v4 = 0) & aNaturalNumber0(v3) = v4) | (aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v5 = 0) |  ~ (v4 = 0))))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (sdtsldt0(v3, v2) = v1) |  ~ (sdtsldt0(v3, v2) = v0)) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (doDivides0(v3, v2) = v1) |  ~ (doDivides0(v3, v2) = v0)) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (iLess0(v3, v2) = v1) |  ~ (iLess0(v3, v2) = v0)) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (sdtmndt0(v3, v2) = v1) |  ~ (sdtmndt0(v3, v2) = v0)) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (sdtlseqdt0(v3, v2) = v1) |  ~ (sdtlseqdt0(v3, v2) = v0)) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (sdtasdt0(v3, v2) = v1) |  ~ (sdtasdt0(v3, v2) = v0)) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (sdtpldt0(v3, v2) = v1) |  ~ (sdtpldt0(v3, v2) = v0)) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v0 = sz00 |  ~ (sdtsldt0(v1, v0) = v2) |  ~ (sdtasdt0(v0, v2) = v3) |  ? [v4] :  ? [v5] :  ? [v6] : ((v4 = 0 & aNaturalNumber0(v2) = 0) | (doDivides0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0))))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : ( ~ (doDivides0(v2, v3) = 0) |  ~ (sdtasdt0(v0, v1) = v3) |  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] :  ? [v10] :  ? [v11] :  ? [v12] : (isPrime0(v2) = v7 & doDivides0(v2, v1) = v12 & doDivides0(v2, v0) = v11 & iLess0(v9, all_0_4_4) = v10 & sdtpldt0(v8, v2) = v9 & sdtpldt0(v0, v1) = v8 & aNaturalNumber0(v2) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v10 = 0) |  ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0) | v12 = 0 | v11 = 0))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : ( ~ (doDivides0(v0, v3) = 0) |  ~ (sdtpldt0(v1, v2) = v3) |  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] : (doDivides0(v0, v2) = v8 & doDivides0(v0, v1) = v7 & aNaturalNumber0(v2) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0) | v8 = 0))) &  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : ( ~ (sdtmndt0(v1, v0) = v2) |  ~ (sdtpldt0(v0, v2) = v3) |  ? [v4] :  ? [v5] :  ? [v6] : ((v4 = 0 & aNaturalNumber0(v2) = 0) | (sdtlseqdt0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0))))) &  ! [v0] :  ! [v1] :  ! [v2] : (v2 = 0 | v1 = v0 |  ~ (iLess0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (sdtlseqdt0(v0, v1) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v5 = 0) |  ~ (v4 = 0) |  ~ (v3 = 0)))) &  ! [v0] :  ! [v1] :  ! [v2] : (v2 = 0 |  ~ (sdtlseqdt0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (sdtlseqdt0(v1, v0) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v4 = 0) |  ~ (v3 = 0) | (v5 = 0 &  ~ (v1 = v0))))) &  ! [v0] :  ! [v1] :  ! [v2] : (v1 = v0 |  ~ (isPrime0(v2) = v1) |  ~ (isPrime0(v2) = v0)) &  ! [v0] :  ! [v1] :  ! [v2] : (v1 = v0 |  ~ (aNaturalNumber0(v2) = v1) |  ~ (aNaturalNumber0(v2) = v0)) &  ! [v0] :  ! [v1] :  ! [v2] : ( ~ (sdtasdt0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (sdtasdt0(v1, v0) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v4 = 0) |  ~ (v3 = 0) | v5 = v2))) &  ! [v0] :  ! [v1] :  ! [v2] : ( ~ (sdtasdt0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (aNaturalNumber0(v2) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v4 = 0) |  ~ (v3 = 0) | v5 = 0))) &  ! [v0] :  ! [v1] :  ! [v2] : ( ~ (sdtpldt0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (sdtpldt0(v1, v0) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v4 = 0) |  ~ (v3 = 0) | v5 = v2))) &  ! [v0] :  ! [v1] :  ! [v2] : ( ~ (sdtpldt0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (aNaturalNumber0(v2) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v4 = 0) |  ~ (v3 = 0) | v5 = 0))) &  ! [v0] :  ! [v1] : (v1 = v0 | v1 = sz10 |  ~ (isPrime0(v0) = 0) |  ~ (doDivides0(v1, v0) = 0) |  ? [v2] : (( ~ (v2 = 0) & aNaturalNumber0(v1) = v2) | ( ~ (v2 = 0) & aNaturalNumber0(v0) = v2))) &  ! [v0] :  ! [v1] : (v1 = v0 |  ~ (sdtlseqdt0(v0, v1) = 0) |  ? [v2] :  ? [v3] :  ? [v4] : (sdtlseqdt0(v1, v0) = v4 & aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v4 = 0) |  ~ (v3 = 0) |  ~ (v2 = 0)))) &  ! [v0] :  ! [v1] : (v1 = sz00 | v0 = sz00 |  ~ (sdtasdt0(v0, v1) = sz00) |  ? [v2] :  ? [v3] : (aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0)))) &  ! [v0] :  ! [v1] : (v1 = sz00 |  ~ (doDivides0(v0, v1) = 0) |  ? [v2] :  ? [v3] :  ? [v4] : (sdtlseqdt0(v0, v1) = v4 & aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0) | v4 = 0))) &  ! [v0] :  ! [v1] : (v1 = sz00 |  ~ (sdtpldt0(v0, v1) = sz00) |  ? [v2] :  ? [v3] : (aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0)))) &  ! [v0] :  ! [v1] : (v1 = 0 | v0 = sz10 | v0 = sz00 |  ~ (isPrime0(v0) = v1) |  ? [v2] :  ? [v3] :  ? [v4] : ((v4 = 0 & v3 = 0 &  ~ (v2 = v0) &  ~ (v2 = sz10) & doDivides0(v2, v0) = 0 & aNaturalNumber0(v2) = 0) | ( ~ (v2 = 0) & aNaturalNumber0(v0) = v2))) &  ! [v0] :  ! [v1] : (v1 = 0 | v0 = sz10 | v0 = sz00 |  ~ (sdtlseqdt0(sz10, v0) = v1) |  ? [v2] : ( ~ (v2 = 0) & aNaturalNumber0(v0) = v2)) &  ! [v0] :  ! [v1] : (v1 = 0 |  ~ (sdtlseqdt0(v0, v0) = v1) |  ? [v2] : ( ~ (v2 = 0) & aNaturalNumber0(v0) = v2)) &  ! [v0] :  ! [v1] : (v0 = sz00 |  ~ (sdtpldt0(v0, v1) = sz00) |  ? [v2] :  ? [v3] : (aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0)))) &  ! [v0] :  ! [v1] : ( ~ (doDivides0(v0, v1) = 0) |  ? [v2] :  ? [v3] :  ? [v4] : ((v4 = v1 & v3 = 0 & sdtasdt0(v0, v2) = v1 & aNaturalNumber0(v2) = 0) | (aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0))))) &  ! [v0] :  ! [v1] : ( ~ (sdtlseqdt0(v0, v1) = 0) |  ? [v2] :  ? [v3] :  ? [v4] : ((v4 = v1 & v3 = 0 & sdtpldt0(v0, v2) = v1 & aNaturalNumber0(v2) = 0) | (aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0))))) &  ! [v0] :  ! [v1] : ( ~ (sdtasdt0(sz10, v0) = v1) |  ? [v2] :  ? [v3] : (sdtasdt0(v0, sz10) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v2 = 0) | (v3 = v0 & v1 = v0)))) &  ! [v0] :  ! [v1] : ( ~ (sdtasdt0(sz00, v0) = v1) |  ? [v2] :  ? [v3] : (sdtasdt0(v0, sz00) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v2 = 0) | (v3 = sz00 & v1 = sz00)))) &  ! [v0] :  ! [v1] : ( ~ (sdtpldt0(sz00, v0) = v1) |  ? [v2] :  ? [v3] : (sdtpldt0(v0, sz00) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v2 = 0) | (v3 = v0 & v1 = v0)))) &  ! [v0] : (v0 = sz10 | v0 = sz00 |  ~ (aNaturalNumber0(v0) = 0) |  ? [v1] : (isPrime0(v1) = 0 & doDivides0(v1, v0) = 0 & aNaturalNumber0(v1) = 0))
% 66.03/28.88  |
% 66.03/28.88  | Applying alpha-rule on (1) yields:
% 66.03/28.88  | (2) sdtasdt0(xn, xm) = all_0_3_3
% 66.03/28.88  | (3)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (sdtpldt0(v3, v2) = v1) |  ~ (sdtpldt0(v3, v2) = v0))
% 66.03/28.88  | (4)  ~ (isPrime0(sz10) = 0)
% 66.03/28.88  | (5)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = v1 | v0 = sz00 |  ~ (sdtsldt0(v1, v0) = v2) |  ~ (sdtasdt0(v0, v2) = v3) |  ? [v4] :  ? [v5] :  ? [v6] : (doDivides0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0))))
% 66.03/28.88  | (6)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] : (v4 = 0 |  ~ (doDivides0(v0, v3) = v4) |  ~ (sdtpldt0(v1, v2) = v3) |  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] : (doDivides0(v0, v2) = v9 & doDivides0(v0, v1) = v8 & aNaturalNumber0(v2) = v7 & aNaturalNumber0(v1) = v6 & aNaturalNumber0(v0) = v5 & ( ~ (v9 = 0) |  ~ (v8 = 0) |  ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0))))
% 66.03/28.88  | (7)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : ( ~ (doDivides0(v2, v3) = 0) |  ~ (sdtasdt0(v0, v1) = v3) |  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] :  ? [v10] :  ? [v11] :  ? [v12] : (isPrime0(v2) = v7 & doDivides0(v2, v1) = v12 & doDivides0(v2, v0) = v11 & iLess0(v9, all_0_4_4) = v10 & sdtpldt0(v8, v2) = v9 & sdtpldt0(v0, v1) = v8 & aNaturalNumber0(v2) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v10 = 0) |  ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0) | v12 = 0 | v11 = 0)))
% 66.03/28.88  | (8)  ! [v0] : (v0 = sz10 | v0 = sz00 |  ~ (aNaturalNumber0(v0) = 0) |  ? [v1] : (isPrime0(v1) = 0 & doDivides0(v1, v0) = 0 & aNaturalNumber0(v1) = 0))
% 66.03/28.88  | (9)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v0 = sz00 |  ~ (sdtsldt0(v1, v0) = v2) |  ~ (sdtasdt0(v0, v2) = v3) |  ? [v4] :  ? [v5] :  ? [v6] : ((v4 = 0 & aNaturalNumber0(v2) = 0) | (doDivides0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0)))))
% 66.03/28.88  | (10) aNaturalNumber0(xr) = 0
% 66.03/28.88  | (11) sdtlseqdt0(xp, xm) = all_0_1_1
% 66.03/28.88  | (12) aNaturalNumber0(xp) = 0
% 66.03/28.88  | (13)  ~ (xk = sz00)
% 66.03/28.88  | (14)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] : (v2 = v1 | v0 = sz00 |  ~ (sdtasdt0(v0, v2) = v4) |  ~ (sdtasdt0(v0, v1) = v3) |  ~ (aNaturalNumber0(v0) = 0) |  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] : (sdtasdt0(v2, v0) = v8 & sdtasdt0(v1, v0) = v7 & aNaturalNumber0(v2) = v6 & aNaturalNumber0(v1) = v5 & ( ~ (v6 = 0) |  ~ (v5 = 0) | ( ~ (v8 = v7) &  ~ (v4 = v3)))))
% 66.03/28.88  | (15)  ! [v0] :  ! [v1] :  ! [v2] : (v1 = v0 |  ~ (isPrime0(v2) = v1) |  ~ (isPrime0(v2) = v0))
% 66.03/28.88  | (16) aNaturalNumber0(sz10) = 0
% 66.03/28.88  | (17)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (sdtlseqdt0(v3, v2) = v1) |  ~ (sdtlseqdt0(v3, v2) = v0))
% 66.03/28.88  | (18)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] :  ! [v5] : (v0 = sz00 |  ~ (sdtsldt0(v4, v0) = v5) |  ~ (sdtsldt0(v1, v0) = v2) |  ~ (sdtasdt0(v3, v1) = v4) |  ? [v6] :  ? [v7] :  ? [v8] : ((doDivides0(v0, v1) = v8 & aNaturalNumber0(v1) = v7 & aNaturalNumber0(v0) = v6 & ( ~ (v8 = 0) |  ~ (v7 = 0) |  ~ (v6 = 0))) | (sdtasdt0(v3, v2) = v7 & aNaturalNumber0(v3) = v6 & ( ~ (v6 = 0) | v7 = v5))))
% 66.03/28.88  | (19)  ! [v0] :  ! [v1] : ( ~ (sdtasdt0(sz00, v0) = v1) |  ? [v2] :  ? [v3] : (sdtasdt0(v0, sz00) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v2 = 0) | (v3 = sz00 & v1 = sz00))))
% 66.03/28.88  | (20) sdtlseqdt0(xp, xn) = all_0_2_2
% 66.03/28.88  | (21)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = 0 |  ~ (sdtlseqdt0(v0, v2) = v3) |  ~ (sdtlseqdt0(v0, v1) = 0) |  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] : (sdtlseqdt0(v1, v2) = v7 & aNaturalNumber0(v2) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0))))
% 66.03/28.88  | (22) isPrime0(xr) = 0
% 66.03/28.88  | (23)  ~ (all_0_1_1 = 0)
% 66.03/28.88  | (24)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] : (v2 = v1 |  ~ (sdtpldt0(v0, v2) = v4) |  ~ (sdtpldt0(v0, v1) = v3) |  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] : (sdtpldt0(v2, v0) = v9 & sdtpldt0(v1, v0) = v8 & aNaturalNumber0(v2) = v7 & aNaturalNumber0(v1) = v6 & aNaturalNumber0(v0) = v5 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) | ( ~ (v9 = v8) &  ~ (v4 = v3)))))
% 66.03/28.88  | (25)  ! [v0] :  ! [v1] : ( ~ (sdtpldt0(sz00, v0) = v1) |  ? [v2] :  ? [v3] : (sdtpldt0(v0, sz00) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v2 = 0) | (v3 = v0 & v1 = v0))))
% 66.03/28.89  | (26)  ! [v0] :  ! [v1] : (v1 = v0 |  ~ (sdtlseqdt0(v0, v1) = 0) |  ? [v2] :  ? [v3] :  ? [v4] : (sdtlseqdt0(v1, v0) = v4 & aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v4 = 0) |  ~ (v3 = 0) |  ~ (v2 = 0))))
% 66.03/28.89  | (27)  ! [v0] :  ! [v1] :  ! [v2] : ( ~ (sdtasdt0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (sdtasdt0(v1, v0) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v4 = 0) |  ~ (v3 = 0) | v5 = v2)))
% 66.03/28.89  | (28)  ! [v0] :  ! [v1] : (v1 = sz00 |  ~ (sdtpldt0(v0, v1) = sz00) |  ? [v2] :  ? [v3] : (aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0))))
% 66.03/28.89  | (29)  ! [v0] :  ! [v1] : (v1 = v0 | v1 = sz10 |  ~ (isPrime0(v0) = 0) |  ~ (doDivides0(v1, v0) = 0) |  ? [v2] : (( ~ (v2 = 0) & aNaturalNumber0(v1) = v2) | ( ~ (v2 = 0) & aNaturalNumber0(v0) = v2)))
% 66.03/28.89  | (30)  ~ (isPrime0(sz00) = 0)
% 66.03/28.89  | (31)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (sdtsldt0(v3, v2) = v1) |  ~ (sdtsldt0(v3, v2) = v0))
% 66.03/28.89  | (32)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (doDivides0(v3, v2) = v1) |  ~ (doDivides0(v3, v2) = v0))
% 66.03/28.89  | (33)  ! [v0] :  ! [v1] : ( ~ (sdtlseqdt0(v0, v1) = 0) |  ? [v2] :  ? [v3] :  ? [v4] : ((v4 = v1 & v3 = 0 & sdtpldt0(v0, v2) = v1 & aNaturalNumber0(v2) = 0) | (aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0)))))
% 66.03/28.89  | (34)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = v2 | v0 = sz00 |  ~ (sdtsldt0(v1, v0) = v2) |  ~ (sdtasdt0(v0, v3) = v1) |  ? [v4] :  ? [v5] :  ? [v6] : (( ~ (v4 = 0) & aNaturalNumber0(v3) = v4) | (doDivides0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0)))))
% 66.03/28.89  | (35) sdtlseqdt0(xm, xp) = 0
% 66.03/28.89  | (36) aNaturalNumber0(xm) = 0
% 66.03/28.89  | (37)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v2 = 0 |  ~ (doDivides0(v0, v1) = v2) |  ~ (sdtasdt0(v0, v3) = v1) |  ? [v4] :  ? [v5] : (( ~ (v4 = 0) & aNaturalNumber0(v3) = v4) | (aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v5 = 0) |  ~ (v4 = 0)))))
% 66.03/28.89  | (38) doDivides0(xp, all_0_3_3) = 0
% 66.03/28.89  | (39)  ~ (all_0_2_2 = 0)
% 66.03/28.89  | (40)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : ( ~ (doDivides0(v0, v3) = 0) |  ~ (sdtpldt0(v1, v2) = v3) |  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] : (doDivides0(v0, v2) = v8 & doDivides0(v0, v1) = v7 & aNaturalNumber0(v2) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0) | v8 = 0)))
% 66.03/28.89  | (41) aNaturalNumber0(sz00) = 0
% 66.03/28.89  | (42)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v2 = 0 |  ~ (sdtlseqdt0(v0, v1) = v2) |  ~ (sdtpldt0(v0, v3) = v1) |  ? [v4] :  ? [v5] : (( ~ (v4 = 0) & aNaturalNumber0(v3) = v4) | (aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v5 = 0) |  ~ (v4 = 0)))))
% 66.03/28.89  | (43)  ! [v0] :  ! [v1] :  ! [v2] : ( ~ (sdtpldt0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (aNaturalNumber0(v2) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v4 = 0) |  ~ (v3 = 0) | v5 = 0)))
% 66.03/28.89  | (44)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] :  ! [v5] : (v2 = v1 | v0 = sz00 |  ~ (sdtlseqdt0(v3, v4) = v5) |  ~ (sdtasdt0(v0, v2) = v4) |  ~ (sdtasdt0(v0, v1) = v3) |  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] :  ? [v10] :  ? [v11] :  ? [v12] : (sdtlseqdt0(v10, v11) = v12 & sdtlseqdt0(v1, v2) = v9 & sdtasdt0(v2, v0) = v11 & sdtasdt0(v1, v0) = v10 & aNaturalNumber0(v2) = v8 & aNaturalNumber0(v1) = v7 & aNaturalNumber0(v0) = v6 & ( ~ (v9 = 0) |  ~ (v8 = 0) |  ~ (v7 = 0) |  ~ (v6 = 0) | (v12 = 0 & v5 = 0 &  ~ (v11 = v10) &  ~ (v4 = v3)))))
% 66.03/28.89  | (45)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] : ( ~ (sdtasdt0(v3, v2) = v4) |  ~ (sdtasdt0(v0, v1) = v3) |  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] : (sdtasdt0(v1, v2) = v8 & sdtasdt0(v0, v8) = v9 & aNaturalNumber0(v2) = v7 & aNaturalNumber0(v1) = v6 & aNaturalNumber0(v0) = v5 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) | v9 = v4)))
% 66.22/28.89  | (46)  ! [v0] :  ! [v1] :  ! [v2] : (v1 = v0 |  ~ (aNaturalNumber0(v2) = v1) |  ~ (aNaturalNumber0(v2) = v0))
% 66.22/28.89  | (47) sdtsldt0(all_0_3_3, xp) = xk
% 66.22/28.89  | (48)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (sdtasdt0(v3, v2) = v1) |  ~ (sdtasdt0(v3, v2) = v0))
% 66.22/28.89  | (49)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] : ( ~ (sdtpldt0(v3, v2) = v4) |  ~ (sdtpldt0(v0, v1) = v3) |  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] : (sdtpldt0(v1, v2) = v8 & sdtpldt0(v0, v8) = v9 & aNaturalNumber0(v2) = v7 & aNaturalNumber0(v1) = v6 & aNaturalNumber0(v0) = v5 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) | v9 = v4)))
% 66.22/28.89  | (50)  ! [v0] :  ! [v1] : (v1 = sz00 | v0 = sz00 |  ~ (sdtasdt0(v0, v1) = sz00) |  ? [v2] :  ? [v3] : (aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0))))
% 66.22/28.89  | (51) isPrime0(xp) = 0
% 66.22/28.89  | (52)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (sdtmndt0(v3, v2) = v1) |  ~ (sdtmndt0(v3, v2) = v0))
% 66.22/28.89  | (53) aNaturalNumber0(xn) = 0
% 66.22/28.89  | (54) doDivides0(xr, xk) = 0
% 66.22/28.89  | (55)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = v1 |  ~ (sdtmndt0(v1, v0) = v2) |  ~ (sdtpldt0(v0, v2) = v3) |  ? [v4] :  ? [v5] :  ? [v6] : (sdtlseqdt0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0))))
% 66.22/28.89  | (56)  ! [v0] :  ! [v1] : (v1 = 0 | v0 = sz10 | v0 = sz00 |  ~ (isPrime0(v0) = v1) |  ? [v2] :  ? [v3] :  ? [v4] : ((v4 = 0 & v3 = 0 &  ~ (v2 = v0) &  ~ (v2 = sz10) & doDivides0(v2, v0) = 0 & aNaturalNumber0(v2) = 0) | ( ~ (v2 = 0) & aNaturalNumber0(v0) = v2)))
% 66.22/28.89  | (57)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = 0 | v0 = sz00 |  ~ (sdtlseqdt0(v1, v2) = v3) |  ~ (sdtasdt0(v1, v0) = v2) |  ? [v4] :  ? [v5] : (aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v5 = 0) |  ~ (v4 = 0))))
% 66.22/28.89  | (58) sdtpldt0(all_0_5_5, xp) = all_0_4_4
% 66.22/28.89  | (59)  ~ (sz10 = sz00)
% 66.22/28.89  | (60)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : ( ~ (sdtmndt0(v1, v0) = v2) |  ~ (sdtpldt0(v0, v2) = v3) |  ? [v4] :  ? [v5] :  ? [v6] : ((v4 = 0 & aNaturalNumber0(v2) = 0) | (sdtlseqdt0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0)))))
% 66.22/28.90  | (61) doDivides0(xr, all_0_3_3) = all_0_0_0
% 66.22/28.90  | (62)  ! [v0] :  ! [v1] :  ! [v2] : ( ~ (sdtasdt0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (aNaturalNumber0(v2) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v4 = 0) |  ~ (v3 = 0) | v5 = 0)))
% 66.22/28.90  | (63)  ! [v0] :  ! [v1] : (v1 = 0 | v0 = sz10 | v0 = sz00 |  ~ (sdtlseqdt0(sz10, v0) = v1) |  ? [v2] : ( ~ (v2 = 0) & aNaturalNumber0(v0) = v2))
% 66.22/28.90  | (64)  ! [v0] :  ! [v1] : (v0 = sz00 |  ~ (sdtpldt0(v0, v1) = sz00) |  ? [v2] :  ? [v3] : (aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0))))
% 66.22/28.90  | (65)  ~ (all_0_0_0 = 0)
% 66.22/28.90  | (66)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = 0 |  ~ (doDivides0(v0, v2) = v3) |  ~ (doDivides0(v0, v1) = 0) |  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] : (doDivides0(v1, v2) = v7 & aNaturalNumber0(v2) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v7 = 0) |  ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0))))
% 66.22/28.90  | (67)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v1 = v0 |  ~ (iLess0(v3, v2) = v1) |  ~ (iLess0(v3, v2) = v0))
% 66.22/28.90  | (68)  ~ (xk = sz10)
% 66.22/28.90  | (69)  ! [v0] :  ! [v1] :  ! [v2] : (v2 = 0 | v1 = v0 |  ~ (iLess0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (sdtlseqdt0(v0, v1) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v5 = 0) |  ~ (v4 = 0) |  ~ (v3 = 0))))
% 66.22/28.90  | (70)  ! [v0] :  ! [v1] : ( ~ (sdtasdt0(sz10, v0) = v1) |  ? [v2] :  ? [v3] : (sdtasdt0(v0, sz10) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v2 = 0) | (v3 = v0 & v1 = v0))))
% 66.22/28.90  | (71)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] : (v3 = v2 |  ~ (sdtmndt0(v1, v0) = v2) |  ~ (sdtpldt0(v0, v3) = v1) |  ? [v4] :  ? [v5] :  ? [v6] : (( ~ (v4 = 0) & aNaturalNumber0(v3) = v4) | (sdtlseqdt0(v0, v1) = v6 & aNaturalNumber0(v1) = v5 & aNaturalNumber0(v0) = v4 & ( ~ (v6 = 0) |  ~ (v5 = 0) |  ~ (v4 = 0)))))
% 66.22/28.90  | (72)  ! [v0] :  ! [v1] : (v1 = 0 |  ~ (sdtlseqdt0(v0, v0) = v1) |  ? [v2] : ( ~ (v2 = 0) & aNaturalNumber0(v0) = v2))
% 66.22/28.90  | (73) sdtpldt0(xn, xm) = all_0_5_5
% 66.22/28.90  | (74)  ~ (xp = xn)
% 66.22/28.90  | (75)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] :  ! [v5] : ( ~ (sdtasdt0(v0, v2) = v4) |  ~ (sdtasdt0(v0, v1) = v3) |  ~ (sdtpldt0(v3, v4) = v5) |  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] :  ? [v10] :  ? [v11] :  ? [v12] :  ? [v13] :  ? [v14] : (sdtasdt0(v9, v0) = v11 & sdtasdt0(v2, v0) = v13 & sdtasdt0(v1, v0) = v12 & sdtasdt0(v0, v9) = v10 & sdtpldt0(v12, v13) = v14 & sdtpldt0(v1, v2) = v9 & aNaturalNumber0(v2) = v8 & aNaturalNumber0(v1) = v7 & aNaturalNumber0(v0) = v6 & ( ~ (v8 = 0) |  ~ (v7 = 0) |  ~ (v6 = 0) | (v14 = v11 & v10 = v5))))
% 66.22/28.90  | (76)  ! [v0] :  ! [v1] : ( ~ (doDivides0(v0, v1) = 0) |  ? [v2] :  ? [v3] :  ? [v4] : ((v4 = v1 & v3 = 0 & sdtasdt0(v0, v2) = v1 & aNaturalNumber0(v2) = 0) | (aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0)))))
% 66.22/28.90  | (77) sdtlseqdt0(xn, xp) = 0
% 66.22/28.90  | (78)  ! [v0] :  ! [v1] :  ! [v2] : ( ~ (sdtpldt0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (sdtpldt0(v1, v0) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v4 = 0) |  ~ (v3 = 0) | v5 = v2)))
% 66.22/28.90  | (79)  ! [v0] :  ! [v1] :  ! [v2] :  ! [v3] :  ! [v4] :  ! [v5] : (v1 = v0 |  ~ (sdtlseqdt0(v3, v4) = v5) |  ~ (sdtlseqdt0(v0, v1) = 0) |  ~ (sdtpldt0(v1, v2) = v4) |  ~ (sdtpldt0(v0, v2) = v3) |  ? [v6] :  ? [v7] :  ? [v8] :  ? [v9] : ((sdtlseqdt0(v7, v8) = v9 & sdtpldt0(v2, v1) = v8 & sdtpldt0(v2, v0) = v7 & aNaturalNumber0(v2) = v6 & ( ~ (v6 = 0) | (v9 = 0 & v5 = 0 &  ~ (v8 = v7) &  ~ (v4 = v3)))) | (aNaturalNumber0(v1) = v7 & aNaturalNumber0(v0) = v6 & ( ~ (v7 = 0) |  ~ (v6 = 0)))))
% 66.22/28.90  | (80)  ~ (xp = xm)
% 66.22/28.90  | (81)  ! [v0] :  ! [v1] : (v1 = sz00 |  ~ (doDivides0(v0, v1) = 0) |  ? [v2] :  ? [v3] :  ? [v4] : (sdtlseqdt0(v0, v1) = v4 & aNaturalNumber0(v1) = v3 & aNaturalNumber0(v0) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0) | v4 = 0)))
% 66.22/28.90  | (82)  ! [v0] :  ! [v1] :  ! [v2] : (v2 = 0 |  ~ (sdtlseqdt0(v0, v1) = v2) |  ? [v3] :  ? [v4] :  ? [v5] : (sdtlseqdt0(v1, v0) = v5 & aNaturalNumber0(v1) = v4 & aNaturalNumber0(v0) = v3 & ( ~ (v4 = 0) |  ~ (v3 = 0) | (v5 = 0 &  ~ (v1 = v0)))))
% 66.22/28.90  |
% 66.22/28.90  | Using (22) and (4) yields:
% 66.22/28.90  | (83)  ~ (xr = sz10)
% 66.22/28.90  |
% 66.22/28.90  | Using (51) and (4) yields:
% 66.22/28.90  | (84)  ~ (xp = sz10)
% 66.22/28.90  |
% 66.22/28.90  | Using (22) and (30) yields:
% 66.22/28.90  | (85)  ~ (xr = sz00)
% 66.22/28.90  |
% 66.22/28.90  | Using (51) and (30) yields:
% 66.22/28.90  | (86)  ~ (xp = sz00)
% 66.22/28.90  |
% 66.22/28.90  | Instantiating formula (66) with all_0_0_0, all_0_3_3, xk, xr and discharging atoms doDivides0(xr, all_0_3_3) = all_0_0_0, doDivides0(xr, xk) = 0, yields:
% 66.22/28.90  | (87) all_0_0_0 = 0 |  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] : (doDivides0(xk, all_0_3_3) = v3 & aNaturalNumber0(all_0_3_3) = v2 & aNaturalNumber0(xr) = v0 & aNaturalNumber0(xk) = v1 & ( ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0)))
% 66.22/28.90  |
% 66.22/28.90  | Instantiating formula (81) with xk, xr and discharging atoms doDivides0(xr, xk) = 0, yields:
% 66.22/28.90  | (88) xk = sz00 |  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(xr, xk) = v2 & aNaturalNumber0(xr) = v0 & aNaturalNumber0(xk) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.22/28.90  |
% 66.22/28.90  | Instantiating formula (76) with xk, xr and discharging atoms doDivides0(xr, xk) = 0, yields:
% 66.22/28.90  | (89)  ? [v0] :  ? [v1] :  ? [v2] : ((v2 = xk & v1 = 0 & sdtasdt0(xr, v0) = xk & aNaturalNumber0(v0) = 0) | (aNaturalNumber0(xr) = v0 & aNaturalNumber0(xk) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0))))
% 66.22/28.90  |
% 66.22/28.90  | Instantiating formula (81) with all_0_3_3, xp and discharging atoms doDivides0(xp, all_0_3_3) = 0, yields:
% 66.22/28.91  | (90) all_0_3_3 = sz00 |  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(xp, all_0_3_3) = v2 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (76) with all_0_3_3, xp and discharging atoms doDivides0(xp, all_0_3_3) = 0, yields:
% 66.22/28.91  | (91)  ? [v0] :  ? [v1] :  ? [v2] : ((v2 = all_0_3_3 & v1 = 0 & sdtasdt0(xp, v0) = all_0_3_3 & aNaturalNumber0(v0) = 0) | (aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0))))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (33) with xp, xm and discharging atoms sdtlseqdt0(xm, xp) = 0, yields:
% 66.22/28.91  | (92)  ? [v0] :  ? [v1] :  ? [v2] : ((v2 = xp & v1 = 0 & sdtpldt0(xm, v0) = xp & aNaturalNumber0(v0) = 0) | (aNaturalNumber0(xp) = v1 & aNaturalNumber0(xm) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0))))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (33) with xp, xn and discharging atoms sdtlseqdt0(xn, xp) = 0, yields:
% 66.22/28.91  | (93)  ? [v0] :  ? [v1] :  ? [v2] : ((v2 = xp & v1 = 0 & sdtpldt0(xn, v0) = xp & aNaturalNumber0(v0) = 0) | (aNaturalNumber0(xp) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0))))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (7) with all_0_3_3, xp, xm, xn and discharging atoms doDivides0(xp, all_0_3_3) = 0, sdtasdt0(xn, xm) = all_0_3_3, yields:
% 66.22/28.91  | (94)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] : (isPrime0(xp) = v3 & doDivides0(xp, xm) = v8 & doDivides0(xp, xn) = v7 & iLess0(v5, all_0_4_4) = v6 & sdtpldt0(v4, xp) = v5 & sdtpldt0(xn, xm) = v4 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xm) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v6 = 0) |  ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v8 = 0 | v7 = 0))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (19) with all_0_3_3, xm yields:
% 66.22/28.91  | (95)  ~ (sdtasdt0(sz00, xm) = all_0_3_3) |  ? [v0] :  ? [v1] : (sdtasdt0(xm, sz00) = v1 & aNaturalNumber0(xm) = v0 & ( ~ (v0 = 0) | (v1 = sz00 & all_0_3_3 = sz00)))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (27) with all_0_3_3, xm, xn and discharging atoms sdtasdt0(xn, xm) = all_0_3_3, yields:
% 66.22/28.91  | (96)  ? [v0] :  ? [v1] :  ? [v2] : (sdtasdt0(xm, xn) = v2 & aNaturalNumber0(xm) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = all_0_3_3))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (62) with all_0_3_3, xm, xn and discharging atoms sdtasdt0(xn, xm) = all_0_3_3, yields:
% 66.22/28.91  | (97)  ? [v0] :  ? [v1] :  ? [v2] : (aNaturalNumber0(all_0_3_3) = v2 & aNaturalNumber0(xm) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (78) with all_0_4_4, xp, all_0_5_5 and discharging atoms sdtpldt0(all_0_5_5, xp) = all_0_4_4, yields:
% 66.22/28.91  | (98)  ? [v0] :  ? [v1] :  ? [v2] : (sdtpldt0(xp, all_0_5_5) = v2 & aNaturalNumber0(all_0_5_5) = v0 & aNaturalNumber0(xp) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = all_0_4_4))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (43) with all_0_4_4, xp, all_0_5_5 and discharging atoms sdtpldt0(all_0_5_5, xp) = all_0_4_4, yields:
% 66.22/28.91  | (99)  ? [v0] :  ? [v1] :  ? [v2] : (aNaturalNumber0(all_0_4_4) = v2 & aNaturalNumber0(all_0_5_5) = v0 & aNaturalNumber0(xp) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (49) with all_0_4_4, all_0_5_5, xp, xm, xn and discharging atoms sdtpldt0(all_0_5_5, xp) = all_0_4_4, sdtpldt0(xn, xm) = all_0_5_5, yields:
% 66.22/28.91  | (100)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(xm, xp) = v3 & sdtpldt0(xn, v3) = v4 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xm) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_0_4_4))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (78) with all_0_5_5, xm, xn and discharging atoms sdtpldt0(xn, xm) = all_0_5_5, yields:
% 66.22/28.91  | (101)  ? [v0] :  ? [v1] :  ? [v2] : (sdtpldt0(xm, xn) = v2 & aNaturalNumber0(xm) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = all_0_5_5))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (43) with all_0_5_5, xm, xn and discharging atoms sdtpldt0(xn, xm) = all_0_5_5, yields:
% 66.22/28.91  | (102)  ? [v0] :  ? [v1] :  ? [v2] : (aNaturalNumber0(all_0_5_5) = v2 & aNaturalNumber0(xm) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (8) with xr and discharging atoms aNaturalNumber0(xr) = 0, yields:
% 66.22/28.91  | (103) xr = sz10 | xr = sz00 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xr) = 0 & aNaturalNumber0(v0) = 0)
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (8) with xp and discharging atoms aNaturalNumber0(xp) = 0, yields:
% 66.22/28.91  | (104) xp = sz10 | xp = sz00 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xp) = 0 & aNaturalNumber0(v0) = 0)
% 66.22/28.91  |
% 66.22/28.91  | Instantiating formula (8) with xn and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.22/28.91  | (105) xn = sz10 | xn = sz00 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xn) = 0 & aNaturalNumber0(v0) = 0)
% 66.22/28.91  |
% 66.22/28.91  | Instantiating (102) with all_12_0_6, all_12_1_7, all_12_2_8 yields:
% 66.22/28.91  | (106) aNaturalNumber0(all_0_5_5) = all_12_0_6 & aNaturalNumber0(xm) = all_12_1_7 & aNaturalNumber0(xn) = all_12_2_8 & ( ~ (all_12_1_7 = 0) |  ~ (all_12_2_8 = 0) | all_12_0_6 = 0)
% 66.22/28.91  |
% 66.22/28.91  | Applying alpha-rule on (106) yields:
% 66.22/28.91  | (107) aNaturalNumber0(all_0_5_5) = all_12_0_6
% 66.22/28.91  | (108) aNaturalNumber0(xm) = all_12_1_7
% 66.22/28.91  | (109) aNaturalNumber0(xn) = all_12_2_8
% 66.22/28.91  | (110)  ~ (all_12_1_7 = 0) |  ~ (all_12_2_8 = 0) | all_12_0_6 = 0
% 66.22/28.91  |
% 66.22/28.91  | Instantiating (101) with all_14_0_9, all_14_1_10, all_14_2_11 yields:
% 66.22/28.91  | (111) sdtpldt0(xm, xn) = all_14_0_9 & aNaturalNumber0(xm) = all_14_1_10 & aNaturalNumber0(xn) = all_14_2_11 & ( ~ (all_14_1_10 = 0) |  ~ (all_14_2_11 = 0) | all_14_0_9 = all_0_5_5)
% 66.22/28.91  |
% 66.22/28.91  | Applying alpha-rule on (111) yields:
% 66.22/28.91  | (112) sdtpldt0(xm, xn) = all_14_0_9
% 66.22/28.91  | (113) aNaturalNumber0(xm) = all_14_1_10
% 66.22/28.91  | (114) aNaturalNumber0(xn) = all_14_2_11
% 66.22/28.91  | (115)  ~ (all_14_1_10 = 0) |  ~ (all_14_2_11 = 0) | all_14_0_9 = all_0_5_5
% 66.22/28.91  |
% 66.22/28.91  | Instantiating (98) with all_16_0_12, all_16_1_13, all_16_2_14 yields:
% 66.22/28.91  | (116) sdtpldt0(xp, all_0_5_5) = all_16_0_12 & aNaturalNumber0(all_0_5_5) = all_16_2_14 & aNaturalNumber0(xp) = all_16_1_13 & ( ~ (all_16_1_13 = 0) |  ~ (all_16_2_14 = 0) | all_16_0_12 = all_0_4_4)
% 66.22/28.91  |
% 66.22/28.91  | Applying alpha-rule on (116) yields:
% 66.22/28.91  | (117) sdtpldt0(xp, all_0_5_5) = all_16_0_12
% 66.22/28.91  | (118) aNaturalNumber0(all_0_5_5) = all_16_2_14
% 66.22/28.91  | (119) aNaturalNumber0(xp) = all_16_1_13
% 66.22/28.91  | (120)  ~ (all_16_1_13 = 0) |  ~ (all_16_2_14 = 0) | all_16_0_12 = all_0_4_4
% 66.22/28.91  |
% 66.22/28.91  | Instantiating (93) with all_18_0_15, all_18_1_16, all_18_2_17 yields:
% 66.22/28.91  | (121) (all_18_0_15 = xp & all_18_1_16 = 0 & sdtpldt0(xn, all_18_2_17) = xp & aNaturalNumber0(all_18_2_17) = 0) | (aNaturalNumber0(xp) = all_18_1_16 & aNaturalNumber0(xn) = all_18_2_17 & ( ~ (all_18_1_16 = 0) |  ~ (all_18_2_17 = 0)))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating (92) with all_19_0_18, all_19_1_19, all_19_2_20 yields:
% 66.22/28.91  | (122) (all_19_0_18 = xp & all_19_1_19 = 0 & sdtpldt0(xm, all_19_2_20) = xp & aNaturalNumber0(all_19_2_20) = 0) | (aNaturalNumber0(xp) = all_19_1_19 & aNaturalNumber0(xm) = all_19_2_20 & ( ~ (all_19_1_19 = 0) |  ~ (all_19_2_20 = 0)))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating (91) with all_20_0_21, all_20_1_22, all_20_2_23 yields:
% 66.22/28.91  | (123) (all_20_0_21 = all_0_3_3 & all_20_1_22 = 0 & sdtasdt0(xp, all_20_2_23) = all_0_3_3 & aNaturalNumber0(all_20_2_23) = 0) | (aNaturalNumber0(all_0_3_3) = all_20_1_22 & aNaturalNumber0(xp) = all_20_2_23 & ( ~ (all_20_1_22 = 0) |  ~ (all_20_2_23 = 0)))
% 66.22/28.91  |
% 66.22/28.91  | Instantiating (89) with all_21_0_24, all_21_1_25, all_21_2_26 yields:
% 66.22/28.91  | (124) (all_21_0_24 = xk & all_21_1_25 = 0 & sdtasdt0(xr, all_21_2_26) = xk & aNaturalNumber0(all_21_2_26) = 0) | (aNaturalNumber0(xr) = all_21_2_26 & aNaturalNumber0(xk) = all_21_1_25 & ( ~ (all_21_1_25 = 0) |  ~ (all_21_2_26 = 0)))
% 66.22/28.92  |
% 66.22/28.92  | Instantiating (97) with all_22_0_27, all_22_1_28, all_22_2_29 yields:
% 66.22/28.92  | (125) aNaturalNumber0(all_0_3_3) = all_22_0_27 & aNaturalNumber0(xm) = all_22_1_28 & aNaturalNumber0(xn) = all_22_2_29 & ( ~ (all_22_1_28 = 0) |  ~ (all_22_2_29 = 0) | all_22_0_27 = 0)
% 66.22/28.92  |
% 66.22/28.92  | Applying alpha-rule on (125) yields:
% 66.22/28.92  | (126) aNaturalNumber0(all_0_3_3) = all_22_0_27
% 66.22/28.92  | (127) aNaturalNumber0(xm) = all_22_1_28
% 66.22/28.92  | (128) aNaturalNumber0(xn) = all_22_2_29
% 66.22/28.92  | (129)  ~ (all_22_1_28 = 0) |  ~ (all_22_2_29 = 0) | all_22_0_27 = 0
% 66.22/28.92  |
% 66.22/28.92  | Instantiating (100) with all_24_0_30, all_24_1_31, all_24_2_32, all_24_3_33, all_24_4_34 yields:
% 66.22/28.92  | (130) sdtpldt0(xm, xp) = all_24_1_31 & sdtpldt0(xn, all_24_1_31) = all_24_0_30 & aNaturalNumber0(xp) = all_24_2_32 & aNaturalNumber0(xm) = all_24_3_33 & aNaturalNumber0(xn) = all_24_4_34 & ( ~ (all_24_2_32 = 0) |  ~ (all_24_3_33 = 0) |  ~ (all_24_4_34 = 0) | all_24_0_30 = all_0_4_4)
% 66.22/28.92  |
% 66.22/28.92  | Applying alpha-rule on (130) yields:
% 66.22/28.92  | (131)  ~ (all_24_2_32 = 0) |  ~ (all_24_3_33 = 0) |  ~ (all_24_4_34 = 0) | all_24_0_30 = all_0_4_4
% 66.22/28.92  | (132) aNaturalNumber0(xm) = all_24_3_33
% 66.22/28.92  | (133) sdtpldt0(xn, all_24_1_31) = all_24_0_30
% 66.22/28.92  | (134) aNaturalNumber0(xn) = all_24_4_34
% 66.22/28.92  | (135) sdtpldt0(xm, xp) = all_24_1_31
% 66.22/28.92  | (136) aNaturalNumber0(xp) = all_24_2_32
% 66.22/28.92  |
% 66.22/28.92  | Instantiating (99) with all_26_0_35, all_26_1_36, all_26_2_37 yields:
% 66.22/28.92  | (137) aNaturalNumber0(all_0_4_4) = all_26_0_35 & aNaturalNumber0(all_0_5_5) = all_26_2_37 & aNaturalNumber0(xp) = all_26_1_36 & ( ~ (all_26_1_36 = 0) |  ~ (all_26_2_37 = 0) | all_26_0_35 = 0)
% 66.22/28.92  |
% 66.22/28.92  | Applying alpha-rule on (137) yields:
% 66.22/28.92  | (138) aNaturalNumber0(all_0_4_4) = all_26_0_35
% 66.22/28.92  | (139) aNaturalNumber0(all_0_5_5) = all_26_2_37
% 66.22/28.92  | (140) aNaturalNumber0(xp) = all_26_1_36
% 66.22/28.92  | (141)  ~ (all_26_1_36 = 0) |  ~ (all_26_2_37 = 0) | all_26_0_35 = 0
% 66.22/28.92  |
% 66.22/28.92  | Instantiating (96) with all_28_0_38, all_28_1_39, all_28_2_40 yields:
% 66.22/28.92  | (142) sdtasdt0(xm, xn) = all_28_0_38 & aNaturalNumber0(xm) = all_28_1_39 & aNaturalNumber0(xn) = all_28_2_40 & ( ~ (all_28_1_39 = 0) |  ~ (all_28_2_40 = 0) | all_28_0_38 = all_0_3_3)
% 66.22/28.92  |
% 66.22/28.92  | Applying alpha-rule on (142) yields:
% 66.22/28.92  | (143) sdtasdt0(xm, xn) = all_28_0_38
% 66.22/28.92  | (144) aNaturalNumber0(xm) = all_28_1_39
% 66.22/28.92  | (145) aNaturalNumber0(xn) = all_28_2_40
% 66.22/28.92  | (146)  ~ (all_28_1_39 = 0) |  ~ (all_28_2_40 = 0) | all_28_0_38 = all_0_3_3
% 66.22/28.92  |
% 66.22/28.92  | Instantiating (94) with all_30_0_41, all_30_1_42, all_30_2_43, all_30_3_44, all_30_4_45, all_30_5_46, all_30_6_47, all_30_7_48, all_30_8_49 yields:
% 66.22/28.92  | (147) isPrime0(xp) = all_30_5_46 & doDivides0(xp, xm) = all_30_0_41 & doDivides0(xp, xn) = all_30_1_42 & iLess0(all_30_3_44, all_0_4_4) = all_30_2_43 & sdtpldt0(all_30_4_45, xp) = all_30_3_44 & sdtpldt0(xn, xm) = all_30_4_45 & aNaturalNumber0(xp) = all_30_6_47 & aNaturalNumber0(xm) = all_30_7_48 & aNaturalNumber0(xn) = all_30_8_49 & ( ~ (all_30_2_43 = 0) |  ~ (all_30_5_46 = 0) |  ~ (all_30_6_47 = 0) |  ~ (all_30_7_48 = 0) |  ~ (all_30_8_49 = 0) | all_30_0_41 = 0 | all_30_1_42 = 0)
% 66.22/28.92  |
% 66.22/28.92  | Applying alpha-rule on (147) yields:
% 66.22/28.92  | (148) iLess0(all_30_3_44, all_0_4_4) = all_30_2_43
% 66.22/28.92  | (149) doDivides0(xp, xm) = all_30_0_41
% 66.22/28.92  | (150) isPrime0(xp) = all_30_5_46
% 66.22/28.92  | (151) aNaturalNumber0(xp) = all_30_6_47
% 66.22/28.92  | (152) sdtpldt0(all_30_4_45, xp) = all_30_3_44
% 66.22/28.92  | (153) aNaturalNumber0(xn) = all_30_8_49
% 66.22/28.92  | (154)  ~ (all_30_2_43 = 0) |  ~ (all_30_5_46 = 0) |  ~ (all_30_6_47 = 0) |  ~ (all_30_7_48 = 0) |  ~ (all_30_8_49 = 0) | all_30_0_41 = 0 | all_30_1_42 = 0
% 66.22/28.92  | (155) sdtpldt0(xn, xm) = all_30_4_45
% 66.22/28.92  | (156) aNaturalNumber0(xm) = all_30_7_48
% 66.22/28.92  | (157) doDivides0(xp, xn) = all_30_1_42
% 66.22/28.92  |
% 66.22/28.92  +-Applying beta-rule and splitting (87), into two cases.
% 66.22/28.92  |-Branch one:
% 66.22/28.92  | (158) all_0_0_0 = 0
% 66.22/28.92  |
% 66.22/28.92  	| Equations (158) can reduce 65 to:
% 66.22/28.92  	| (159) $false
% 66.22/28.92  	|
% 66.22/28.92  	|-The branch is then unsatisfiable
% 66.22/28.92  |-Branch two:
% 66.22/28.92  | (65)  ~ (all_0_0_0 = 0)
% 66.22/28.92  | (161)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] : (doDivides0(xk, all_0_3_3) = v3 & aNaturalNumber0(all_0_3_3) = v2 & aNaturalNumber0(xr) = v0 & aNaturalNumber0(xk) = v1 & ( ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0)))
% 66.22/28.92  |
% 66.22/28.92  	| Instantiating (161) with all_36_0_50, all_36_1_51, all_36_2_52, all_36_3_53 yields:
% 66.22/28.92  	| (162) doDivides0(xk, all_0_3_3) = all_36_0_50 & aNaturalNumber0(all_0_3_3) = all_36_1_51 & aNaturalNumber0(xr) = all_36_3_53 & aNaturalNumber0(xk) = all_36_2_52 & ( ~ (all_36_0_50 = 0) |  ~ (all_36_1_51 = 0) |  ~ (all_36_2_52 = 0) |  ~ (all_36_3_53 = 0))
% 66.22/28.92  	|
% 66.22/28.92  	| Applying alpha-rule on (162) yields:
% 66.22/28.92  	| (163) aNaturalNumber0(xr) = all_36_3_53
% 66.22/28.92  	| (164) doDivides0(xk, all_0_3_3) = all_36_0_50
% 66.22/28.92  	| (165)  ~ (all_36_0_50 = 0) |  ~ (all_36_1_51 = 0) |  ~ (all_36_2_52 = 0) |  ~ (all_36_3_53 = 0)
% 66.22/28.92  	| (166) aNaturalNumber0(xk) = all_36_2_52
% 66.22/28.92  	| (167) aNaturalNumber0(all_0_3_3) = all_36_1_51
% 66.22/28.92  	|
% 66.22/28.92  	+-Applying beta-rule and splitting (88), into two cases.
% 66.22/28.92  	|-Branch one:
% 66.22/28.92  	| (168) xk = sz00
% 66.22/28.92  	|
% 66.22/28.92  		| Equations (168) can reduce 13 to:
% 66.22/28.92  		| (159) $false
% 66.22/28.92  		|
% 66.22/28.92  		|-The branch is then unsatisfiable
% 66.22/28.92  	|-Branch two:
% 66.22/28.92  	| (13)  ~ (xk = sz00)
% 66.22/28.92  	| (171)  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(xr, xk) = v2 & aNaturalNumber0(xr) = v0 & aNaturalNumber0(xk) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.22/28.92  	|
% 66.22/28.92  		| Instantiating (171) with all_41_0_54, all_41_1_55, all_41_2_56 yields:
% 66.22/28.92  		| (172) sdtlseqdt0(xr, xk) = all_41_0_54 & aNaturalNumber0(xr) = all_41_2_56 & aNaturalNumber0(xk) = all_41_1_55 & ( ~ (all_41_1_55 = 0) |  ~ (all_41_2_56 = 0) | all_41_0_54 = 0)
% 66.22/28.92  		|
% 66.22/28.92  		| Applying alpha-rule on (172) yields:
% 66.22/28.92  		| (173) sdtlseqdt0(xr, xk) = all_41_0_54
% 66.22/28.92  		| (174) aNaturalNumber0(xr) = all_41_2_56
% 66.22/28.92  		| (175) aNaturalNumber0(xk) = all_41_1_55
% 66.22/28.93  		| (176)  ~ (all_41_1_55 = 0) |  ~ (all_41_2_56 = 0) | all_41_0_54 = 0
% 66.22/28.93  		|
% 66.22/28.93  		+-Applying beta-rule and splitting (103), into two cases.
% 66.22/28.93  		|-Branch one:
% 66.22/28.93  		| (177) xr = sz00
% 66.22/28.93  		|
% 66.22/28.93  			| Equations (177) can reduce 85 to:
% 66.22/28.93  			| (159) $false
% 66.22/28.93  			|
% 66.22/28.93  			|-The branch is then unsatisfiable
% 66.22/28.93  		|-Branch two:
% 66.22/28.93  		| (85)  ~ (xr = sz00)
% 66.22/28.93  		| (180) xr = sz10 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xr) = 0 & aNaturalNumber0(v0) = 0)
% 66.22/28.93  		|
% 66.22/28.93  			+-Applying beta-rule and splitting (104), into two cases.
% 66.22/28.93  			|-Branch one:
% 66.22/28.93  			| (181) xp = sz00
% 66.22/28.93  			|
% 66.22/28.93  				| Equations (181) can reduce 86 to:
% 66.22/28.93  				| (159) $false
% 66.22/28.93  				|
% 66.22/28.93  				|-The branch is then unsatisfiable
% 66.22/28.93  			|-Branch two:
% 66.22/28.93  			| (86)  ~ (xp = sz00)
% 66.22/28.93  			| (184) xp = sz10 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xp) = 0 & aNaturalNumber0(v0) = 0)
% 66.22/28.93  			|
% 66.22/28.93  				+-Applying beta-rule and splitting (180), into two cases.
% 66.22/28.93  				|-Branch one:
% 66.22/28.93  				| (185) xr = sz10
% 66.22/28.93  				|
% 66.22/28.93  					| Equations (185) can reduce 83 to:
% 66.22/28.93  					| (159) $false
% 66.22/28.93  					|
% 66.22/28.93  					|-The branch is then unsatisfiable
% 66.22/28.93  				|-Branch two:
% 66.22/28.93  				| (83)  ~ (xr = sz10)
% 66.22/28.93  				| (188)  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xr) = 0 & aNaturalNumber0(v0) = 0)
% 66.22/28.93  				|
% 66.22/28.93  					| Instantiating (188) with all_53_0_57 yields:
% 66.22/28.93  					| (189) isPrime0(all_53_0_57) = 0 & doDivides0(all_53_0_57, xr) = 0 & aNaturalNumber0(all_53_0_57) = 0
% 66.22/28.93  					|
% 66.22/28.93  					| Applying alpha-rule on (189) yields:
% 66.22/28.93  					| (190) isPrime0(all_53_0_57) = 0
% 66.22/28.93  					| (191) doDivides0(all_53_0_57, xr) = 0
% 66.22/28.93  					| (192) aNaturalNumber0(all_53_0_57) = 0
% 66.22/28.93  					|
% 66.22/28.93  					+-Applying beta-rule and splitting (184), into two cases.
% 66.22/28.93  					|-Branch one:
% 66.22/28.93  					| (193) xp = sz10
% 66.22/28.93  					|
% 66.22/28.93  						| Equations (193) can reduce 84 to:
% 66.22/28.93  						| (159) $false
% 66.22/28.93  						|
% 66.22/28.93  						|-The branch is then unsatisfiable
% 66.22/28.93  					|-Branch two:
% 66.22/28.93  					| (84)  ~ (xp = sz10)
% 66.22/28.93  					| (196)  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xp) = 0 & aNaturalNumber0(v0) = 0)
% 66.22/28.93  					|
% 66.22/28.93  						| Instantiating (196) with all_58_0_58 yields:
% 66.22/28.93  						| (197) isPrime0(all_58_0_58) = 0 & doDivides0(all_58_0_58, xp) = 0 & aNaturalNumber0(all_58_0_58) = 0
% 66.22/28.93  						|
% 66.22/28.93  						| Applying alpha-rule on (197) yields:
% 66.22/28.93  						| (198) isPrime0(all_58_0_58) = 0
% 66.22/28.93  						| (199) doDivides0(all_58_0_58, xp) = 0
% 66.22/28.93  						| (200) aNaturalNumber0(all_58_0_58) = 0
% 66.22/28.93  						|
% 66.22/28.93  						| Using (198) and (4) yields:
% 66.22/28.93  						| (201)  ~ (all_58_0_58 = sz10)
% 66.22/28.93  						|
% 66.22/28.93  						| Using (198) and (30) yields:
% 66.22/28.93  						| (202)  ~ (all_58_0_58 = sz00)
% 66.22/28.93  						|
% 66.22/28.93  						| Using (190) and (4) yields:
% 66.22/28.93  						| (203)  ~ (all_53_0_57 = sz10)
% 66.22/28.93  						|
% 66.22/28.93  						| Using (190) and (30) yields:
% 66.22/28.93  						| (204)  ~ (all_53_0_57 = sz00)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (15) with xp, all_30_5_46, 0 and discharging atoms isPrime0(xp) = all_30_5_46, isPrime0(xp) = 0, yields:
% 66.22/28.93  						| (205) all_30_5_46 = 0
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (3) with all_0_5_5, xp, all_30_3_44, all_0_4_4 and discharging atoms sdtpldt0(all_0_5_5, xp) = all_0_4_4, yields:
% 66.22/28.93  						| (206) all_30_3_44 = all_0_4_4 |  ~ (sdtpldt0(all_0_5_5, xp) = all_30_3_44)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (3) with xn, xm, all_30_4_45, all_0_5_5 and discharging atoms sdtpldt0(xn, xm) = all_30_4_45, sdtpldt0(xn, xm) = all_0_5_5, yields:
% 66.22/28.93  						| (207) all_30_4_45 = all_0_5_5
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with xr, all_36_1_51, 0 and discharging atoms aNaturalNumber0(xr) = 0, yields:
% 66.22/28.93  						| (208) all_36_1_51 = 0 |  ~ (aNaturalNumber0(xr) = all_36_1_51)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with xp, all_36_1_51, 0 and discharging atoms aNaturalNumber0(xp) = 0, yields:
% 66.22/28.93  						| (209) all_36_1_51 = 0 |  ~ (aNaturalNumber0(xp) = all_36_1_51)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with xm, all_36_1_51, 0 and discharging atoms aNaturalNumber0(xm) = 0, yields:
% 66.22/28.93  						| (210) all_36_1_51 = 0 |  ~ (aNaturalNumber0(xm) = all_36_1_51)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with xn, all_36_1_51, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.22/28.93  						| (211) all_36_1_51 = 0 |  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with sz10, all_36_1_51, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.22/28.93  						| (212) all_36_1_51 = 0 |  ~ (aNaturalNumber0(sz10) = all_36_1_51)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with sz00, all_36_1_51, 0 and discharging atoms aNaturalNumber0(sz00) = 0, yields:
% 66.22/28.93  						| (213) all_36_1_51 = 0 |  ~ (aNaturalNumber0(sz00) = all_36_1_51)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with all_0_3_3, all_36_1_51, 0 and discharging atoms aNaturalNumber0(all_0_3_3) = all_36_1_51, yields:
% 66.22/28.93  						| (214) all_36_1_51 = 0 |  ~ (aNaturalNumber0(all_0_3_3) = 0)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with xm, all_22_0_27, 0 and discharging atoms aNaturalNumber0(xm) = 0, yields:
% 66.22/28.93  						| (215) all_22_0_27 = 0 |  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with xn, all_22_0_27, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.22/28.93  						| (216) all_22_0_27 = 0 |  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with sz10, all_22_0_27, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.22/28.93  						| (217) all_22_0_27 = 0 |  ~ (aNaturalNumber0(sz10) = all_22_0_27)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with all_0_3_3, all_22_0_27, 0 and discharging atoms aNaturalNumber0(all_0_3_3) = all_22_0_27, yields:
% 66.22/28.93  						| (218) all_22_0_27 = 0 |  ~ (aNaturalNumber0(all_0_3_3) = 0)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with all_0_3_3, all_22_0_27, all_36_1_51 and discharging atoms aNaturalNumber0(all_0_3_3) = all_36_1_51, aNaturalNumber0(all_0_3_3) = all_22_0_27, yields:
% 66.22/28.93  						| (219) all_36_1_51 = all_22_0_27
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with xr, all_26_0_35, 0 and discharging atoms aNaturalNumber0(xr) = 0, yields:
% 66.22/28.93  						| (220) all_26_0_35 = 0 |  ~ (aNaturalNumber0(xr) = all_26_0_35)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with xp, all_26_0_35, 0 and discharging atoms aNaturalNumber0(xp) = 0, yields:
% 66.22/28.93  						| (221) all_26_0_35 = 0 |  ~ (aNaturalNumber0(xp) = all_26_0_35)
% 66.22/28.93  						|
% 66.22/28.93  						| Instantiating formula (46) with xn, all_26_0_35, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.22/28.94  						| (222) all_26_0_35 = 0 |  ~ (aNaturalNumber0(xn) = all_26_0_35)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_4_4, all_26_0_35, 0 and discharging atoms aNaturalNumber0(all_0_4_4) = all_26_0_35, yields:
% 66.22/28.94  						| (223) all_26_0_35 = 0 |  ~ (aNaturalNumber0(all_0_4_4) = 0)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_4_4, all_26_0_35, all_36_1_51 and discharging atoms aNaturalNumber0(all_0_4_4) = all_26_0_35, yields:
% 66.22/28.94  						| (224) all_36_1_51 = all_26_0_35 |  ~ (aNaturalNumber0(all_0_4_4) = all_36_1_51)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_4_4, all_26_0_35, all_22_0_27 and discharging atoms aNaturalNumber0(all_0_4_4) = all_26_0_35, yields:
% 66.22/28.94  						| (225) all_26_0_35 = all_22_0_27 |  ~ (aNaturalNumber0(all_0_4_4) = all_22_0_27)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xr, all_26_2_37, 0 and discharging atoms aNaturalNumber0(xr) = 0, yields:
% 66.22/28.94  						| (226) all_26_2_37 = 0 |  ~ (aNaturalNumber0(xr) = all_26_2_37)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xm, all_26_2_37, 0 and discharging atoms aNaturalNumber0(xm) = 0, yields:
% 66.22/28.94  						| (227) all_26_2_37 = 0 |  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xn, all_26_2_37, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.22/28.94  						| (228) all_26_2_37 = 0 |  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with sz00, all_26_2_37, 0 and discharging atoms aNaturalNumber0(sz00) = 0, yields:
% 66.22/28.94  						| (229) all_26_2_37 = 0 |  ~ (aNaturalNumber0(sz00) = all_26_2_37)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_26_2_37, 0 and discharging atoms aNaturalNumber0(all_0_5_5) = all_26_2_37, yields:
% 66.22/28.94  						| (230) all_26_2_37 = 0 |  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_26_2_37, all_36_1_51 and discharging atoms aNaturalNumber0(all_0_5_5) = all_26_2_37, yields:
% 66.22/28.94  						| (231) all_36_1_51 = all_26_2_37 |  ~ (aNaturalNumber0(all_0_5_5) = all_36_1_51)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_26_2_37, all_22_0_27 and discharging atoms aNaturalNumber0(all_0_5_5) = all_26_2_37, yields:
% 66.22/28.94  						| (232) all_26_2_37 = all_22_0_27 |  ~ (aNaturalNumber0(all_0_5_5) = all_22_0_27)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_26_2_37, all_26_0_35 and discharging atoms aNaturalNumber0(all_0_5_5) = all_26_2_37, yields:
% 66.22/28.94  						| (233) all_26_0_35 = all_26_2_37 |  ~ (aNaturalNumber0(all_0_5_5) = all_26_0_35)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xr, all_16_2_14, 0 and discharging atoms aNaturalNumber0(xr) = 0, yields:
% 66.22/28.94  						| (234) all_16_2_14 = 0 |  ~ (aNaturalNumber0(xr) = all_16_2_14)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xp, all_16_2_14, 0 and discharging atoms aNaturalNumber0(xp) = 0, yields:
% 66.22/28.94  						| (235) all_16_2_14 = 0 |  ~ (aNaturalNumber0(xp) = all_16_2_14)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xm, all_16_2_14, 0 and discharging atoms aNaturalNumber0(xm) = 0, yields:
% 66.22/28.94  						| (236) all_16_2_14 = 0 |  ~ (aNaturalNumber0(xm) = all_16_2_14)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xn, all_16_2_14, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.22/28.94  						| (237) all_16_2_14 = 0 |  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with sz10, all_16_2_14, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.22/28.94  						| (238) all_16_2_14 = 0 |  ~ (aNaturalNumber0(sz10) = all_16_2_14)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_16_2_14, 0 and discharging atoms aNaturalNumber0(all_0_5_5) = all_16_2_14, yields:
% 66.22/28.94  						| (239) all_16_2_14 = 0 |  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_16_2_14, all_36_1_51 and discharging atoms aNaturalNumber0(all_0_5_5) = all_16_2_14, yields:
% 66.22/28.94  						| (240) all_36_1_51 = all_16_2_14 |  ~ (aNaturalNumber0(all_0_5_5) = all_36_1_51)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_16_2_14, all_26_0_35 and discharging atoms aNaturalNumber0(all_0_5_5) = all_16_2_14, yields:
% 66.22/28.94  						| (241) all_26_0_35 = all_16_2_14 |  ~ (aNaturalNumber0(all_0_5_5) = all_26_0_35)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_16_2_14, all_26_2_37 and discharging atoms aNaturalNumber0(all_0_5_5) = all_26_2_37, aNaturalNumber0(all_0_5_5) = all_16_2_14, yields:
% 66.22/28.94  						| (242) all_26_2_37 = all_16_2_14
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xr, all_12_0_6, 0 and discharging atoms aNaturalNumber0(xr) = 0, yields:
% 66.22/28.94  						| (243) all_12_0_6 = 0 |  ~ (aNaturalNumber0(xr) = all_12_0_6)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xp, all_12_0_6, 0 and discharging atoms aNaturalNumber0(xp) = 0, yields:
% 66.22/28.94  						| (244) all_12_0_6 = 0 |  ~ (aNaturalNumber0(xp) = all_12_0_6)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xm, all_12_0_6, 0 and discharging atoms aNaturalNumber0(xm) = 0, yields:
% 66.22/28.94  						| (245) all_12_0_6 = 0 |  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xn, all_12_0_6, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.22/28.94  						| (246) all_12_0_6 = 0 |  ~ (aNaturalNumber0(xn) = all_12_0_6)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with sz10, all_12_0_6, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.22/28.94  						| (247) all_12_0_6 = 0 |  ~ (aNaturalNumber0(sz10) = all_12_0_6)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with sz00, all_12_0_6, 0 and discharging atoms aNaturalNumber0(sz00) = 0, yields:
% 66.22/28.94  						| (248) all_12_0_6 = 0 |  ~ (aNaturalNumber0(sz00) = all_12_0_6)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_12_0_6, all_36_1_51 and discharging atoms aNaturalNumber0(all_0_5_5) = all_12_0_6, yields:
% 66.22/28.94  						| (249) all_36_1_51 = all_12_0_6 |  ~ (aNaturalNumber0(all_0_5_5) = all_36_1_51)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_12_0_6, all_22_0_27 and discharging atoms aNaturalNumber0(all_0_5_5) = all_12_0_6, yields:
% 66.22/28.94  						| (250) all_22_0_27 = all_12_0_6 |  ~ (aNaturalNumber0(all_0_5_5) = all_22_0_27)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_12_0_6, all_26_0_35 and discharging atoms aNaturalNumber0(all_0_5_5) = all_12_0_6, yields:
% 66.22/28.94  						| (251) all_26_0_35 = all_12_0_6 |  ~ (aNaturalNumber0(all_0_5_5) = all_26_0_35)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with all_0_5_5, all_12_0_6, all_26_2_37 and discharging atoms aNaturalNumber0(all_0_5_5) = all_26_2_37, aNaturalNumber0(all_0_5_5) = all_12_0_6, yields:
% 66.22/28.94  						| (252) all_26_2_37 = all_12_0_6
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xr, all_41_2_56, 0 and discharging atoms aNaturalNumber0(xr) = all_41_2_56, aNaturalNumber0(xr) = 0, yields:
% 66.22/28.94  						| (253) all_41_2_56 = 0
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xp, all_41_2_56, 0 and discharging atoms aNaturalNumber0(xp) = 0, yields:
% 66.22/28.94  						| (254) all_41_2_56 = 0 |  ~ (aNaturalNumber0(xp) = all_41_2_56)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xm, all_41_2_56, 0 and discharging atoms aNaturalNumber0(xm) = 0, yields:
% 66.22/28.94  						| (255) all_41_2_56 = 0 |  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 66.22/28.94  						|
% 66.22/28.94  						| Instantiating formula (46) with xn, all_41_2_56, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.22/28.95  						| (256) all_41_2_56 = 0 |  ~ (aNaturalNumber0(xn) = all_41_2_56)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_41_2_56, all_36_1_51 and discharging atoms aNaturalNumber0(xr) = all_41_2_56, yields:
% 66.22/28.95  						| (257) all_41_2_56 = all_36_1_51 |  ~ (aNaturalNumber0(xr) = all_36_1_51)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_41_2_56, all_22_0_27 and discharging atoms aNaturalNumber0(xr) = all_41_2_56, yields:
% 66.22/28.95  						| (258) all_41_2_56 = all_22_0_27 |  ~ (aNaturalNumber0(xr) = all_22_0_27)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_41_2_56, all_26_0_35 and discharging atoms aNaturalNumber0(xr) = all_41_2_56, yields:
% 66.22/28.95  						| (259) all_41_2_56 = all_26_0_35 |  ~ (aNaturalNumber0(xr) = all_26_0_35)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_41_2_56, all_26_2_37 and discharging atoms aNaturalNumber0(xr) = all_41_2_56, yields:
% 66.22/28.95  						| (260) all_41_2_56 = all_26_2_37 |  ~ (aNaturalNumber0(xr) = all_26_2_37)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_41_2_56, all_12_0_6 and discharging atoms aNaturalNumber0(xr) = all_41_2_56, yields:
% 66.22/28.95  						| (261) all_41_2_56 = all_12_0_6 |  ~ (aNaturalNumber0(xr) = all_12_0_6)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xp, all_36_3_53, 0 and discharging atoms aNaturalNumber0(xp) = 0, yields:
% 66.22/28.95  						| (262) all_36_3_53 = 0 |  ~ (aNaturalNumber0(xp) = all_36_3_53)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xm, all_36_3_53, 0 and discharging atoms aNaturalNumber0(xm) = 0, yields:
% 66.22/28.95  						| (263) all_36_3_53 = 0 |  ~ (aNaturalNumber0(xm) = all_36_3_53)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xn, all_36_3_53, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.22/28.95  						| (264) all_36_3_53 = 0 |  ~ (aNaturalNumber0(xn) = all_36_3_53)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_36_3_53, all_36_1_51 and discharging atoms aNaturalNumber0(xr) = all_36_3_53, yields:
% 66.22/28.95  						| (265) all_36_1_51 = all_36_3_53 |  ~ (aNaturalNumber0(xr) = all_36_1_51)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_36_3_53, all_22_0_27 and discharging atoms aNaturalNumber0(xr) = all_36_3_53, yields:
% 66.22/28.95  						| (266) all_36_3_53 = all_22_0_27 |  ~ (aNaturalNumber0(xr) = all_22_0_27)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_36_3_53, all_26_0_35 and discharging atoms aNaturalNumber0(xr) = all_36_3_53, yields:
% 66.22/28.95  						| (267) all_36_3_53 = all_26_0_35 |  ~ (aNaturalNumber0(xr) = all_26_0_35)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_36_3_53, all_26_2_37 and discharging atoms aNaturalNumber0(xr) = all_36_3_53, yields:
% 66.22/28.95  						| (268) all_36_3_53 = all_26_2_37 |  ~ (aNaturalNumber0(xr) = all_26_2_37)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_36_3_53, all_16_2_14 and discharging atoms aNaturalNumber0(xr) = all_36_3_53, yields:
% 66.22/28.95  						| (269) all_36_3_53 = all_16_2_14 |  ~ (aNaturalNumber0(xr) = all_16_2_14)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_36_3_53, all_12_0_6 and discharging atoms aNaturalNumber0(xr) = all_36_3_53, yields:
% 66.22/28.95  						| (270) all_36_3_53 = all_12_0_6 |  ~ (aNaturalNumber0(xr) = all_12_0_6)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xr, all_36_3_53, all_41_2_56 and discharging atoms aNaturalNumber0(xr) = all_41_2_56, aNaturalNumber0(xr) = all_36_3_53, yields:
% 66.22/28.95  						| (271) all_41_2_56 = all_36_3_53
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_41_1_55, 0 and discharging atoms aNaturalNumber0(xk) = all_41_1_55, yields:
% 66.22/28.95  						| (272) all_41_1_55 = 0 |  ~ (aNaturalNumber0(xk) = 0)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xp, all_41_1_55, 0 and discharging atoms aNaturalNumber0(xp) = 0, yields:
% 66.22/28.95  						| (273) all_41_1_55 = 0 |  ~ (aNaturalNumber0(xp) = all_41_1_55)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xm, all_41_1_55, 0 and discharging atoms aNaturalNumber0(xm) = 0, yields:
% 66.22/28.95  						| (274) all_41_1_55 = 0 |  ~ (aNaturalNumber0(xm) = all_41_1_55)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xn, all_41_1_55, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.22/28.95  						| (275) all_41_1_55 = 0 |  ~ (aNaturalNumber0(xn) = all_41_1_55)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_41_1_55, all_36_1_51 and discharging atoms aNaturalNumber0(xk) = all_41_1_55, yields:
% 66.22/28.95  						| (276) all_41_1_55 = all_36_1_51 |  ~ (aNaturalNumber0(xk) = all_36_1_51)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_41_1_55, all_22_0_27 and discharging atoms aNaturalNumber0(xk) = all_41_1_55, yields:
% 66.22/28.95  						| (277) all_41_1_55 = all_22_0_27 |  ~ (aNaturalNumber0(xk) = all_22_0_27)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_41_1_55, all_26_0_35 and discharging atoms aNaturalNumber0(xk) = all_41_1_55, yields:
% 66.22/28.95  						| (278) all_41_1_55 = all_26_0_35 |  ~ (aNaturalNumber0(xk) = all_26_0_35)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_41_1_55, all_26_2_37 and discharging atoms aNaturalNumber0(xk) = all_41_1_55, yields:
% 66.22/28.95  						| (279) all_41_1_55 = all_26_2_37 |  ~ (aNaturalNumber0(xk) = all_26_2_37)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_41_1_55, all_16_2_14 and discharging atoms aNaturalNumber0(xk) = all_41_1_55, yields:
% 66.22/28.95  						| (280) all_41_1_55 = all_16_2_14 |  ~ (aNaturalNumber0(xk) = all_16_2_14)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_41_1_55, all_41_2_56 and discharging atoms aNaturalNumber0(xk) = all_41_1_55, yields:
% 66.22/28.95  						| (281) all_41_1_55 = all_41_2_56 |  ~ (aNaturalNumber0(xk) = all_41_2_56)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_41_1_55, all_36_3_53 and discharging atoms aNaturalNumber0(xk) = all_41_1_55, yields:
% 66.22/28.95  						| (282) all_41_1_55 = all_36_3_53 |  ~ (aNaturalNumber0(xk) = all_36_3_53)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_36_2_52, 0 and discharging atoms aNaturalNumber0(xk) = all_36_2_52, yields:
% 66.22/28.95  						| (283) all_36_2_52 = 0 |  ~ (aNaturalNumber0(xk) = 0)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xp, all_36_2_52, 0 and discharging atoms aNaturalNumber0(xp) = 0, yields:
% 66.22/28.95  						| (284) all_36_2_52 = 0 |  ~ (aNaturalNumber0(xp) = all_36_2_52)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xm, all_36_2_52, 0 and discharging atoms aNaturalNumber0(xm) = 0, yields:
% 66.22/28.95  						| (285) all_36_2_52 = 0 |  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xn, all_36_2_52, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.22/28.95  						| (286) all_36_2_52 = 0 |  ~ (aNaturalNumber0(xn) = all_36_2_52)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_36_2_52, all_22_0_27 and discharging atoms aNaturalNumber0(xk) = all_36_2_52, yields:
% 66.22/28.95  						| (287) all_36_2_52 = all_22_0_27 |  ~ (aNaturalNumber0(xk) = all_22_0_27)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_36_2_52, all_26_0_35 and discharging atoms aNaturalNumber0(xk) = all_36_2_52, yields:
% 66.22/28.95  						| (288) all_36_2_52 = all_26_0_35 |  ~ (aNaturalNumber0(xk) = all_26_0_35)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_36_2_52, all_16_2_14 and discharging atoms aNaturalNumber0(xk) = all_36_2_52, yields:
% 66.22/28.95  						| (289) all_36_2_52 = all_16_2_14 |  ~ (aNaturalNumber0(xk) = all_16_2_14)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_36_2_52, all_12_0_6 and discharging atoms aNaturalNumber0(xk) = all_36_2_52, yields:
% 66.22/28.95  						| (290) all_36_2_52 = all_12_0_6 |  ~ (aNaturalNumber0(xk) = all_12_0_6)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_36_2_52, all_41_2_56 and discharging atoms aNaturalNumber0(xk) = all_36_2_52, yields:
% 66.22/28.95  						| (291) all_41_2_56 = all_36_2_52 |  ~ (aNaturalNumber0(xk) = all_41_2_56)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_36_2_52, all_36_3_53 and discharging atoms aNaturalNumber0(xk) = all_36_2_52, yields:
% 66.22/28.95  						| (292) all_36_2_52 = all_36_3_53 |  ~ (aNaturalNumber0(xk) = all_36_3_53)
% 66.22/28.95  						|
% 66.22/28.95  						| Instantiating formula (46) with xk, all_36_2_52, all_41_1_55 and discharging atoms aNaturalNumber0(xk) = all_41_1_55, aNaturalNumber0(xk) = all_36_2_52, yields:
% 66.54/28.95  						| (293) all_41_1_55 = all_36_2_52
% 66.54/28.95  						|
% 66.54/28.95  						| Instantiating formula (46) with xp, all_30_6_47, all_36_1_51 and discharging atoms aNaturalNumber0(xp) = all_30_6_47, yields:
% 66.54/28.95  						| (294) all_36_1_51 = all_30_6_47 |  ~ (aNaturalNumber0(xp) = all_36_1_51)
% 66.54/28.95  						|
% 66.54/28.95  						| Instantiating formula (46) with xp, all_30_6_47, all_22_0_27 and discharging atoms aNaturalNumber0(xp) = all_30_6_47, yields:
% 66.54/28.95  						| (295) all_30_6_47 = all_22_0_27 |  ~ (aNaturalNumber0(xp) = all_22_0_27)
% 66.54/28.95  						|
% 66.54/28.95  						| Instantiating formula (46) with xp, all_30_6_47, all_26_0_35 and discharging atoms aNaturalNumber0(xp) = all_30_6_47, yields:
% 66.54/28.96  						| (296) all_30_6_47 = all_26_0_35 |  ~ (aNaturalNumber0(xp) = all_26_0_35)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_30_6_47, all_26_2_37 and discharging atoms aNaturalNumber0(xp) = all_30_6_47, yields:
% 66.54/28.96  						| (297) all_30_6_47 = all_26_2_37 |  ~ (aNaturalNumber0(xp) = all_26_2_37)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_30_6_47, all_16_2_14 and discharging atoms aNaturalNumber0(xp) = all_30_6_47, yields:
% 66.54/28.96  						| (298) all_30_6_47 = all_16_2_14 |  ~ (aNaturalNumber0(xp) = all_16_2_14)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_30_6_47, all_12_0_6 and discharging atoms aNaturalNumber0(xp) = all_30_6_47, yields:
% 66.54/28.96  						| (299) all_30_6_47 = all_12_0_6 |  ~ (aNaturalNumber0(xp) = all_12_0_6)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_30_6_47, all_41_2_56 and discharging atoms aNaturalNumber0(xp) = all_30_6_47, yields:
% 66.54/28.96  						| (300) all_41_2_56 = all_30_6_47 |  ~ (aNaturalNumber0(xp) = all_41_2_56)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_30_6_47, all_36_3_53 and discharging atoms aNaturalNumber0(xp) = all_30_6_47, yields:
% 66.54/28.96  						| (301) all_36_3_53 = all_30_6_47 |  ~ (aNaturalNumber0(xp) = all_36_3_53)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_30_6_47, all_41_1_55 and discharging atoms aNaturalNumber0(xp) = all_30_6_47, yields:
% 66.54/28.96  						| (302) all_41_1_55 = all_30_6_47 |  ~ (aNaturalNumber0(xp) = all_41_1_55)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_26_1_36, 0 and discharging atoms aNaturalNumber0(xp) = all_26_1_36, aNaturalNumber0(xp) = 0, yields:
% 66.54/28.96  						| (303) all_26_1_36 = 0
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_26_1_36, all_36_1_51 and discharging atoms aNaturalNumber0(xp) = all_26_1_36, yields:
% 66.54/28.96  						| (304) all_36_1_51 = all_26_1_36 |  ~ (aNaturalNumber0(xp) = all_36_1_51)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_26_1_36, all_22_0_27 and discharging atoms aNaturalNumber0(xp) = all_26_1_36, yields:
% 66.54/28.96  						| (305) all_26_1_36 = all_22_0_27 |  ~ (aNaturalNumber0(xp) = all_22_0_27)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_26_1_36, all_26_0_35 and discharging atoms aNaturalNumber0(xp) = all_26_1_36, yields:
% 66.54/28.96  						| (306) all_26_0_35 = all_26_1_36 |  ~ (aNaturalNumber0(xp) = all_26_0_35)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_26_1_36, all_26_2_37 and discharging atoms aNaturalNumber0(xp) = all_26_1_36, yields:
% 66.54/28.96  						| (307) all_26_1_36 = all_26_2_37 |  ~ (aNaturalNumber0(xp) = all_26_2_37)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_26_1_36, all_16_2_14 and discharging atoms aNaturalNumber0(xp) = all_26_1_36, yields:
% 66.54/28.96  						| (308) all_26_1_36 = all_16_2_14 |  ~ (aNaturalNumber0(xp) = all_16_2_14)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_26_1_36, all_12_0_6 and discharging atoms aNaturalNumber0(xp) = all_26_1_36, yields:
% 66.54/28.96  						| (309) all_26_1_36 = all_12_0_6 |  ~ (aNaturalNumber0(xp) = all_12_0_6)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_26_1_36, all_41_2_56 and discharging atoms aNaturalNumber0(xp) = all_26_1_36, yields:
% 66.54/28.96  						| (310) all_41_2_56 = all_26_1_36 |  ~ (aNaturalNumber0(xp) = all_41_2_56)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_26_1_36, all_36_3_53 and discharging atoms aNaturalNumber0(xp) = all_26_1_36, yields:
% 66.54/28.96  						| (311) all_36_3_53 = all_26_1_36 |  ~ (aNaturalNumber0(xp) = all_36_3_53)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_26_1_36, all_36_2_52 and discharging atoms aNaturalNumber0(xp) = all_26_1_36, yields:
% 66.54/28.96  						| (312) all_36_2_52 = all_26_1_36 |  ~ (aNaturalNumber0(xp) = all_36_2_52)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_26_1_36, all_30_6_47 and discharging atoms aNaturalNumber0(xp) = all_30_6_47, aNaturalNumber0(xp) = all_26_1_36, yields:
% 66.54/28.96  						| (313) all_30_6_47 = all_26_1_36
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_24_2_32, all_36_1_51 and discharging atoms aNaturalNumber0(xp) = all_24_2_32, yields:
% 66.54/28.96  						| (314) all_36_1_51 = all_24_2_32 |  ~ (aNaturalNumber0(xp) = all_36_1_51)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_24_2_32, all_22_0_27 and discharging atoms aNaturalNumber0(xp) = all_24_2_32, yields:
% 66.54/28.96  						| (315) all_24_2_32 = all_22_0_27 |  ~ (aNaturalNumber0(xp) = all_22_0_27)
% 66.54/28.96  						|
% 66.54/28.96  						| Instantiating formula (46) with xp, all_24_2_32, all_26_0_35 and discharging atoms aNaturalNumber0(xp) = all_24_2_32, yields:
% 66.56/28.96  						| (316) all_26_0_35 = all_24_2_32 |  ~ (aNaturalNumber0(xp) = all_26_0_35)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_24_2_32, all_26_2_37 and discharging atoms aNaturalNumber0(xp) = all_24_2_32, yields:
% 66.56/28.96  						| (317) all_26_2_37 = all_24_2_32 |  ~ (aNaturalNumber0(xp) = all_26_2_37)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_24_2_32, all_16_2_14 and discharging atoms aNaturalNumber0(xp) = all_24_2_32, yields:
% 66.56/28.96  						| (318) all_24_2_32 = all_16_2_14 |  ~ (aNaturalNumber0(xp) = all_16_2_14)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_24_2_32, all_41_2_56 and discharging atoms aNaturalNumber0(xp) = all_24_2_32, yields:
% 66.56/28.96  						| (319) all_41_2_56 = all_24_2_32 |  ~ (aNaturalNumber0(xp) = all_41_2_56)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_24_2_32, all_36_3_53 and discharging atoms aNaturalNumber0(xp) = all_24_2_32, yields:
% 66.56/28.96  						| (320) all_36_3_53 = all_24_2_32 |  ~ (aNaturalNumber0(xp) = all_36_3_53)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_24_2_32, all_30_6_47 and discharging atoms aNaturalNumber0(xp) = all_30_6_47, aNaturalNumber0(xp) = all_24_2_32, yields:
% 66.56/28.96  						| (321) all_30_6_47 = all_24_2_32
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_16_1_13, all_22_0_27 and discharging atoms aNaturalNumber0(xp) = all_16_1_13, yields:
% 66.56/28.96  						| (322) all_22_0_27 = all_16_1_13 |  ~ (aNaturalNumber0(xp) = all_22_0_27)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_16_1_13, all_26_0_35 and discharging atoms aNaturalNumber0(xp) = all_16_1_13, yields:
% 66.56/28.96  						| (323) all_26_0_35 = all_16_1_13 |  ~ (aNaturalNumber0(xp) = all_26_0_35)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_16_1_13, all_26_2_37 and discharging atoms aNaturalNumber0(xp) = all_16_1_13, yields:
% 66.56/28.96  						| (324) all_26_2_37 = all_16_1_13 |  ~ (aNaturalNumber0(xp) = all_26_2_37)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_16_1_13, all_16_2_14 and discharging atoms aNaturalNumber0(xp) = all_16_1_13, yields:
% 66.56/28.96  						| (325) all_16_1_13 = all_16_2_14 |  ~ (aNaturalNumber0(xp) = all_16_2_14)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_16_1_13, all_12_0_6 and discharging atoms aNaturalNumber0(xp) = all_16_1_13, yields:
% 66.56/28.96  						| (326) all_16_1_13 = all_12_0_6 |  ~ (aNaturalNumber0(xp) = all_12_0_6)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_16_1_13, all_41_2_56 and discharging atoms aNaturalNumber0(xp) = all_16_1_13, yields:
% 66.56/28.96  						| (327) all_41_2_56 = all_16_1_13 |  ~ (aNaturalNumber0(xp) = all_41_2_56)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_16_1_13, all_36_3_53 and discharging atoms aNaturalNumber0(xp) = all_16_1_13, yields:
% 66.56/28.96  						| (328) all_36_3_53 = all_16_1_13 |  ~ (aNaturalNumber0(xp) = all_36_3_53)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_16_1_13, all_36_2_52 and discharging atoms aNaturalNumber0(xp) = all_16_1_13, yields:
% 66.56/28.96  						| (329) all_36_2_52 = all_16_1_13 |  ~ (aNaturalNumber0(xp) = all_36_2_52)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xp, all_16_1_13, all_26_1_36 and discharging atoms aNaturalNumber0(xp) = all_26_1_36, aNaturalNumber0(xp) = all_16_1_13, yields:
% 66.56/28.96  						| (330) all_26_1_36 = all_16_1_13
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_30_7_48, 0 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, aNaturalNumber0(xm) = 0, yields:
% 66.56/28.96  						| (331) all_30_7_48 = 0
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xn, all_30_7_48, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.56/28.96  						| (332) all_30_7_48 = 0 |  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with sz00, all_30_7_48, 0 and discharging atoms aNaturalNumber0(sz00) = 0, yields:
% 66.56/28.96  						| (333) all_30_7_48 = 0 |  ~ (aNaturalNumber0(sz00) = all_30_7_48)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_30_7_48, all_22_0_27 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, yields:
% 66.56/28.96  						| (334) all_30_7_48 = all_22_0_27 |  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_30_7_48, all_26_0_35 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, yields:
% 66.56/28.96  						| (335) all_30_7_48 = all_26_0_35 |  ~ (aNaturalNumber0(xm) = all_26_0_35)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_30_7_48, all_26_2_37 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, yields:
% 66.56/28.96  						| (336) all_30_7_48 = all_26_2_37 |  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_30_7_48, all_16_2_14 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, yields:
% 66.56/28.96  						| (337) all_30_7_48 = all_16_2_14 |  ~ (aNaturalNumber0(xm) = all_16_2_14)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_30_7_48, all_12_0_6 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, yields:
% 66.56/28.96  						| (338) all_30_7_48 = all_12_0_6 |  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_30_7_48, all_41_2_56 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, yields:
% 66.56/28.96  						| (339) all_41_2_56 = all_30_7_48 |  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_30_7_48, all_36_3_53 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, yields:
% 66.56/28.96  						| (340) all_36_3_53 = all_30_7_48 |  ~ (aNaturalNumber0(xm) = all_36_3_53)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_30_7_48, all_41_1_55 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, yields:
% 66.56/28.96  						| (341) all_41_1_55 = all_30_7_48 |  ~ (aNaturalNumber0(xm) = all_41_1_55)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_30_7_48, all_36_2_52 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, yields:
% 66.56/28.96  						| (342) all_36_2_52 = all_30_7_48 |  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xn, all_28_1_39, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.56/28.96  						| (343) all_28_1_39 = 0 |  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with sz10, all_28_1_39, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.56/28.96  						| (344) all_28_1_39 = 0 |  ~ (aNaturalNumber0(sz10) = all_28_1_39)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_28_1_39, all_36_1_51 and discharging atoms aNaturalNumber0(xm) = all_28_1_39, yields:
% 66.56/28.96  						| (345) all_36_1_51 = all_28_1_39 |  ~ (aNaturalNumber0(xm) = all_36_1_51)
% 66.56/28.96  						|
% 66.56/28.96  						| Instantiating formula (46) with xm, all_28_1_39, all_22_0_27 and discharging atoms aNaturalNumber0(xm) = all_28_1_39, yields:
% 66.56/28.96  						| (346) all_28_1_39 = all_22_0_27 |  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_28_1_39, all_41_2_56 and discharging atoms aNaturalNumber0(xm) = all_28_1_39, yields:
% 66.56/28.97  						| (347) all_41_2_56 = all_28_1_39 |  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_28_1_39, all_36_3_53 and discharging atoms aNaturalNumber0(xm) = all_28_1_39, yields:
% 66.56/28.97  						| (348) all_36_3_53 = all_28_1_39 |  ~ (aNaturalNumber0(xm) = all_36_3_53)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_28_1_39, all_36_2_52 and discharging atoms aNaturalNumber0(xm) = all_28_1_39, yields:
% 66.56/28.97  						| (349) all_36_2_52 = all_28_1_39 |  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_28_1_39, all_30_7_48 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, aNaturalNumber0(xm) = all_28_1_39, yields:
% 66.56/28.97  						| (350) all_30_7_48 = all_28_1_39
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_24_3_33, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.56/28.97  						| (351) all_24_3_33 = 0 |  ~ (aNaturalNumber0(xn) = all_24_3_33)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with sz00, all_24_3_33, 0 and discharging atoms aNaturalNumber0(sz00) = 0, yields:
% 66.56/28.97  						| (352) all_24_3_33 = 0 |  ~ (aNaturalNumber0(sz00) = all_24_3_33)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_24_3_33, all_22_0_27 and discharging atoms aNaturalNumber0(xm) = all_24_3_33, yields:
% 66.56/28.97  						| (353) all_24_3_33 = all_22_0_27 |  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_24_3_33, all_26_0_35 and discharging atoms aNaturalNumber0(xm) = all_24_3_33, yields:
% 66.56/28.97  						| (354) all_26_0_35 = all_24_3_33 |  ~ (aNaturalNumber0(xm) = all_26_0_35)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_24_3_33, all_26_2_37 and discharging atoms aNaturalNumber0(xm) = all_24_3_33, yields:
% 66.56/28.97  						| (355) all_26_2_37 = all_24_3_33 |  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_24_3_33, all_16_2_14 and discharging atoms aNaturalNumber0(xm) = all_24_3_33, yields:
% 66.56/28.97  						| (356) all_24_3_33 = all_16_2_14 |  ~ (aNaturalNumber0(xm) = all_16_2_14)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_24_3_33, all_12_0_6 and discharging atoms aNaturalNumber0(xm) = all_24_3_33, yields:
% 66.56/28.97  						| (357) all_24_3_33 = all_12_0_6 |  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_24_3_33, all_41_2_56 and discharging atoms aNaturalNumber0(xm) = all_24_3_33, yields:
% 66.56/28.97  						| (358) all_41_2_56 = all_24_3_33 |  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_24_3_33, all_41_1_55 and discharging atoms aNaturalNumber0(xm) = all_24_3_33, yields:
% 66.56/28.97  						| (359) all_41_1_55 = all_24_3_33 |  ~ (aNaturalNumber0(xm) = all_41_1_55)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_24_3_33, all_36_2_52 and discharging atoms aNaturalNumber0(xm) = all_24_3_33, yields:
% 66.56/28.97  						| (360) all_36_2_52 = all_24_3_33 |  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_24_3_33, all_30_7_48 and discharging atoms aNaturalNumber0(xm) = all_30_7_48, aNaturalNumber0(xm) = all_24_3_33, yields:
% 66.56/28.97  						| (361) all_30_7_48 = all_24_3_33
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_22_1_28, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.56/28.97  						| (362) all_22_1_28 = 0 |  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with sz10, all_22_1_28, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.56/28.97  						| (363) all_22_1_28 = 0 |  ~ (aNaturalNumber0(sz10) = all_22_1_28)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with sz00, all_22_1_28, 0 and discharging atoms aNaturalNumber0(sz00) = 0, yields:
% 66.56/28.97  						| (364) all_22_1_28 = 0 |  ~ (aNaturalNumber0(sz00) = all_22_1_28)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_22_1_28, all_22_0_27 and discharging atoms aNaturalNumber0(xm) = all_22_1_28, yields:
% 66.56/28.97  						| (365) all_22_0_27 = all_22_1_28 |  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_22_1_28, all_26_0_35 and discharging atoms aNaturalNumber0(xm) = all_22_1_28, yields:
% 66.56/28.97  						| (366) all_26_0_35 = all_22_1_28 |  ~ (aNaturalNumber0(xm) = all_26_0_35)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_22_1_28, all_26_2_37 and discharging atoms aNaturalNumber0(xm) = all_22_1_28, yields:
% 66.56/28.97  						| (367) all_26_2_37 = all_22_1_28 |  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_22_1_28, all_16_2_14 and discharging atoms aNaturalNumber0(xm) = all_22_1_28, yields:
% 66.56/28.97  						| (368) all_22_1_28 = all_16_2_14 |  ~ (aNaturalNumber0(xm) = all_16_2_14)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_22_1_28, all_12_0_6 and discharging atoms aNaturalNumber0(xm) = all_22_1_28, yields:
% 66.56/28.97  						| (369) all_22_1_28 = all_12_0_6 |  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_22_1_28, all_36_3_53 and discharging atoms aNaturalNumber0(xm) = all_22_1_28, yields:
% 66.56/28.97  						| (370) all_36_3_53 = all_22_1_28 |  ~ (aNaturalNumber0(xm) = all_36_3_53)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_22_1_28, all_41_1_55 and discharging atoms aNaturalNumber0(xm) = all_22_1_28, yields:
% 66.56/28.97  						| (371) all_41_1_55 = all_22_1_28 |  ~ (aNaturalNumber0(xm) = all_41_1_55)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_22_1_28, all_36_2_52 and discharging atoms aNaturalNumber0(xm) = all_22_1_28, yields:
% 66.56/28.97  						| (372) all_36_2_52 = all_22_1_28 |  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_22_1_28, all_28_1_39 and discharging atoms aNaturalNumber0(xm) = all_28_1_39, aNaturalNumber0(xm) = all_22_1_28, yields:
% 66.56/28.97  						| (373) all_28_1_39 = all_22_1_28
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_14_1_10, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.56/28.97  						| (374) all_14_1_10 = 0 |  ~ (aNaturalNumber0(xn) = all_14_1_10)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_14_1_10, all_36_1_51 and discharging atoms aNaturalNumber0(xm) = all_14_1_10, yields:
% 66.56/28.97  						| (375) all_36_1_51 = all_14_1_10 |  ~ (aNaturalNumber0(xm) = all_36_1_51)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_14_1_10, all_22_0_27 and discharging atoms aNaturalNumber0(xm) = all_14_1_10, yields:
% 66.56/28.97  						| (376) all_22_0_27 = all_14_1_10 |  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_14_1_10, all_26_0_35 and discharging atoms aNaturalNumber0(xm) = all_14_1_10, yields:
% 66.56/28.97  						| (377) all_26_0_35 = all_14_1_10 |  ~ (aNaturalNumber0(xm) = all_26_0_35)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_14_1_10, all_26_2_37 and discharging atoms aNaturalNumber0(xm) = all_14_1_10, yields:
% 66.56/28.97  						| (378) all_26_2_37 = all_14_1_10 |  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_14_1_10, all_16_2_14 and discharging atoms aNaturalNumber0(xm) = all_14_1_10, yields:
% 66.56/28.97  						| (379) all_16_2_14 = all_14_1_10 |  ~ (aNaturalNumber0(xm) = all_16_2_14)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_14_1_10, all_12_0_6 and discharging atoms aNaturalNumber0(xm) = all_14_1_10, yields:
% 66.56/28.97  						| (380) all_14_1_10 = all_12_0_6 |  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_14_1_10, all_41_2_56 and discharging atoms aNaturalNumber0(xm) = all_14_1_10, yields:
% 66.56/28.97  						| (381) all_41_2_56 = all_14_1_10 |  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_14_1_10, all_36_3_53 and discharging atoms aNaturalNumber0(xm) = all_14_1_10, yields:
% 66.56/28.97  						| (382) all_36_3_53 = all_14_1_10 |  ~ (aNaturalNumber0(xm) = all_36_3_53)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_14_1_10, all_36_2_52 and discharging atoms aNaturalNumber0(xm) = all_14_1_10, yields:
% 66.56/28.97  						| (383) all_36_2_52 = all_14_1_10 |  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_14_1_10, all_28_1_39 and discharging atoms aNaturalNumber0(xm) = all_28_1_39, aNaturalNumber0(xm) = all_14_1_10, yields:
% 66.56/28.97  						| (384) all_28_1_39 = all_14_1_10
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_12_1_7, 0 and discharging atoms aNaturalNumber0(xn) = 0, yields:
% 66.56/28.97  						| (385) all_12_1_7 = 0 |  ~ (aNaturalNumber0(xn) = all_12_1_7)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with sz10, all_12_1_7, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.56/28.97  						| (386) all_12_1_7 = 0 |  ~ (aNaturalNumber0(sz10) = all_12_1_7)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_12_1_7, all_36_1_51 and discharging atoms aNaturalNumber0(xm) = all_12_1_7, yields:
% 66.56/28.97  						| (387) all_36_1_51 = all_12_1_7 |  ~ (aNaturalNumber0(xm) = all_36_1_51)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_12_1_7, all_22_0_27 and discharging atoms aNaturalNumber0(xm) = all_12_1_7, yields:
% 66.56/28.97  						| (388) all_22_0_27 = all_12_1_7 |  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_12_1_7, all_26_0_35 and discharging atoms aNaturalNumber0(xm) = all_12_1_7, yields:
% 66.56/28.97  						| (389) all_26_0_35 = all_12_1_7 |  ~ (aNaturalNumber0(xm) = all_26_0_35)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_12_1_7, all_26_2_37 and discharging atoms aNaturalNumber0(xm) = all_12_1_7, yields:
% 66.56/28.97  						| (390) all_26_2_37 = all_12_1_7 |  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_12_1_7, all_12_0_6 and discharging atoms aNaturalNumber0(xm) = all_12_1_7, yields:
% 66.56/28.97  						| (391) all_12_0_6 = all_12_1_7 |  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_12_1_7, all_41_2_56 and discharging atoms aNaturalNumber0(xm) = all_12_1_7, yields:
% 66.56/28.97  						| (392) all_41_2_56 = all_12_1_7 |  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_12_1_7, all_36_2_52 and discharging atoms aNaturalNumber0(xm) = all_12_1_7, yields:
% 66.56/28.97  						| (393) all_36_2_52 = all_12_1_7 |  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xm, all_12_1_7, all_14_1_10 and discharging atoms aNaturalNumber0(xm) = all_14_1_10, aNaturalNumber0(xm) = all_12_1_7, yields:
% 66.56/28.97  						| (394) all_14_1_10 = all_12_1_7
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with sz10, all_30_8_49, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.56/28.97  						| (395) all_30_8_49 = 0 |  ~ (aNaturalNumber0(sz10) = all_30_8_49)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_30_8_49, all_26_0_35 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.97  						| (396) all_30_8_49 = all_26_0_35 |  ~ (aNaturalNumber0(xn) = all_26_0_35)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_30_8_49, all_26_2_37 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.97  						| (397) all_30_8_49 = all_26_2_37 |  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_30_8_49, all_16_2_14 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.97  						| (398) all_30_8_49 = all_16_2_14 |  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_30_8_49, all_12_0_6 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.97  						| (399) all_30_8_49 = all_12_0_6 |  ~ (aNaturalNumber0(xn) = all_12_0_6)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_30_8_49, all_41_2_56 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.97  						| (400) all_41_2_56 = all_30_8_49 |  ~ (aNaturalNumber0(xn) = all_41_2_56)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_30_8_49, all_36_3_53 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.97  						| (401) all_36_3_53 = all_30_8_49 |  ~ (aNaturalNumber0(xn) = all_36_3_53)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_30_8_49, all_36_2_52 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.97  						| (402) all_36_2_52 = all_30_8_49 |  ~ (aNaturalNumber0(xn) = all_36_2_52)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_30_8_49, all_30_7_48 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.97  						| (403) all_30_7_48 = all_30_8_49 |  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_30_8_49, all_28_1_39 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.97  						| (404) all_30_8_49 = all_28_1_39 |  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 66.56/28.97  						|
% 66.56/28.97  						| Instantiating formula (46) with xn, all_30_8_49, all_24_3_33 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.97  						| (405) all_30_8_49 = all_24_3_33 |  ~ (aNaturalNumber0(xn) = all_24_3_33)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_30_8_49, all_22_1_28 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.98  						| (406) all_30_8_49 = all_22_1_28 |  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_30_8_49, all_14_1_10 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.98  						| (407) all_30_8_49 = all_14_1_10 |  ~ (aNaturalNumber0(xn) = all_14_1_10)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_30_8_49, all_12_1_7 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, yields:
% 66.56/28.98  						| (408) all_30_8_49 = all_12_1_7 |  ~ (aNaturalNumber0(xn) = all_12_1_7)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with sz10, all_28_2_40, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.56/28.98  						| (409) all_28_2_40 = 0 |  ~ (aNaturalNumber0(sz10) = all_28_2_40)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with sz00, all_28_2_40, 0 and discharging atoms aNaturalNumber0(sz00) = 0, yields:
% 66.56/28.98  						| (410) all_28_2_40 = 0 |  ~ (aNaturalNumber0(sz00) = all_28_2_40)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_36_1_51 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (411) all_36_1_51 = all_28_2_40 |  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_22_0_27 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (412) all_28_2_40 = all_22_0_27 |  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_26_0_35 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (413) all_28_2_40 = all_26_0_35 |  ~ (aNaturalNumber0(xn) = all_26_0_35)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_26_2_37 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (414) all_28_2_40 = all_26_2_37 |  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_16_2_14 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (415) all_28_2_40 = all_16_2_14 |  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_12_0_6 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (416) all_28_2_40 = all_12_0_6 |  ~ (aNaturalNumber0(xn) = all_12_0_6)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_41_2_56 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (417) all_41_2_56 = all_28_2_40 |  ~ (aNaturalNumber0(xn) = all_41_2_56)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_36_3_53 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (418) all_36_3_53 = all_28_2_40 |  ~ (aNaturalNumber0(xn) = all_36_3_53)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_41_1_55 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (419) all_41_1_55 = all_28_2_40 |  ~ (aNaturalNumber0(xn) = all_41_1_55)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_30_7_48 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (420) all_30_7_48 = all_28_2_40 |  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_28_1_39 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (421) all_28_1_39 = all_28_2_40 |  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_22_1_28 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (422) all_28_2_40 = all_22_1_28 |  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_28_2_40, all_30_8_49 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, aNaturalNumber0(xn) = all_28_2_40, yields:
% 66.56/28.98  						| (423) all_30_8_49 = all_28_2_40
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with sz10, all_24_4_34, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.56/28.98  						| (424) all_24_4_34 = 0 |  ~ (aNaturalNumber0(sz10) = all_24_4_34)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_24_4_34, all_36_1_51 and discharging atoms aNaturalNumber0(xn) = all_24_4_34, yields:
% 66.56/28.98  						| (425) all_36_1_51 = all_24_4_34 |  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_24_4_34, all_22_0_27 and discharging atoms aNaturalNumber0(xn) = all_24_4_34, yields:
% 66.56/28.98  						| (426) all_24_4_34 = all_22_0_27 |  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_24_4_34, all_16_2_14 and discharging atoms aNaturalNumber0(xn) = all_24_4_34, yields:
% 66.56/28.98  						| (427) all_24_4_34 = all_16_2_14 |  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_24_4_34, all_12_0_6 and discharging atoms aNaturalNumber0(xn) = all_24_4_34, yields:
% 66.56/28.98  						| (428) all_24_4_34 = all_12_0_6 |  ~ (aNaturalNumber0(xn) = all_12_0_6)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_24_4_34, all_41_1_55 and discharging atoms aNaturalNumber0(xn) = all_24_4_34, yields:
% 66.56/28.98  						| (429) all_41_1_55 = all_24_4_34 |  ~ (aNaturalNumber0(xn) = all_41_1_55)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_24_4_34, all_36_2_52 and discharging atoms aNaturalNumber0(xn) = all_24_4_34, yields:
% 66.56/28.98  						| (430) all_36_2_52 = all_24_4_34 |  ~ (aNaturalNumber0(xn) = all_36_2_52)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_24_4_34, all_30_7_48 and discharging atoms aNaturalNumber0(xn) = all_24_4_34, yields:
% 66.56/28.98  						| (431) all_30_7_48 = all_24_4_34 |  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_24_4_34, all_28_1_39 and discharging atoms aNaturalNumber0(xn) = all_24_4_34, yields:
% 66.56/28.98  						| (432) all_28_1_39 = all_24_4_34 |  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_24_4_34, all_12_1_7 and discharging atoms aNaturalNumber0(xn) = all_24_4_34, yields:
% 66.56/28.98  						| (433) all_24_4_34 = all_12_1_7 |  ~ (aNaturalNumber0(xn) = all_12_1_7)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_24_4_34, all_28_2_40 and discharging atoms aNaturalNumber0(xn) = all_28_2_40, aNaturalNumber0(xn) = all_24_4_34, yields:
% 66.56/28.98  						| (434) all_28_2_40 = all_24_4_34
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with sz10, all_22_2_29, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.56/28.98  						| (435) all_22_2_29 = 0 |  ~ (aNaturalNumber0(sz10) = all_22_2_29)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with sz00, all_22_2_29, 0 and discharging atoms aNaturalNumber0(sz00) = 0, yields:
% 66.56/28.98  						| (436) all_22_2_29 = 0 |  ~ (aNaturalNumber0(sz00) = all_22_2_29)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_36_1_51 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (437) all_36_1_51 = all_22_2_29 |  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_22_0_27 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (438) all_22_0_27 = all_22_2_29 |  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_26_0_35 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (439) all_26_0_35 = all_22_2_29 |  ~ (aNaturalNumber0(xn) = all_26_0_35)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_26_2_37 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (440) all_26_2_37 = all_22_2_29 |  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_16_2_14 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (441) all_22_2_29 = all_16_2_14 |  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_12_0_6 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (442) all_22_2_29 = all_12_0_6 |  ~ (aNaturalNumber0(xn) = all_12_0_6)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_36_3_53 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (443) all_36_3_53 = all_22_2_29 |  ~ (aNaturalNumber0(xn) = all_36_3_53)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_36_2_52 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (444) all_36_2_52 = all_22_2_29 |  ~ (aNaturalNumber0(xn) = all_36_2_52)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_30_7_48 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (445) all_30_7_48 = all_22_2_29 |  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_28_1_39 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (446) all_28_1_39 = all_22_2_29 |  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_24_3_33 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (447) all_24_3_33 = all_22_2_29 |  ~ (aNaturalNumber0(xn) = all_24_3_33)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_22_1_28 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (448) all_22_1_28 = all_22_2_29 |  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_14_1_10 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (449) all_22_2_29 = all_14_1_10 |  ~ (aNaturalNumber0(xn) = all_14_1_10)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_22_2_29, all_24_4_34 and discharging atoms aNaturalNumber0(xn) = all_24_4_34, aNaturalNumber0(xn) = all_22_2_29, yields:
% 66.56/28.98  						| (450) all_24_4_34 = all_22_2_29
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, 0 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, aNaturalNumber0(xn) = 0, yields:
% 66.56/28.98  						| (451) all_14_2_11 = 0
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with sz10, all_14_2_11, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.56/28.98  						| (452) all_14_2_11 = 0 |  ~ (aNaturalNumber0(sz10) = all_14_2_11)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with sz00, all_14_2_11, 0 and discharging atoms aNaturalNumber0(sz00) = 0, yields:
% 66.56/28.98  						| (453) all_14_2_11 = 0 |  ~ (aNaturalNumber0(sz00) = all_14_2_11)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_36_1_51 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (454) all_36_1_51 = all_14_2_11 |  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_22_0_27 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (455) all_22_0_27 = all_14_2_11 |  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_26_2_37 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (456) all_26_2_37 = all_14_2_11 |  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_16_2_14 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (457) all_16_2_14 = all_14_2_11 |  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_41_2_56 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (458) all_41_2_56 = all_14_2_11 |  ~ (aNaturalNumber0(xn) = all_41_2_56)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_36_3_53 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (459) all_36_3_53 = all_14_2_11 |  ~ (aNaturalNumber0(xn) = all_36_3_53)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_41_1_55 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (460) all_41_1_55 = all_14_2_11 |  ~ (aNaturalNumber0(xn) = all_41_1_55)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_28_1_39 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (461) all_28_1_39 = all_14_2_11 |  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_24_3_33 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (462) all_24_3_33 = all_14_2_11 |  ~ (aNaturalNumber0(xn) = all_24_3_33)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_22_1_28 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (463) all_22_1_28 = all_14_2_11 |  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_14_1_10 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (464) all_14_1_10 = all_14_2_11 |  ~ (aNaturalNumber0(xn) = all_14_1_10)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_12_1_7 and discharging atoms aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (465) all_14_2_11 = all_12_1_7 |  ~ (aNaturalNumber0(xn) = all_12_1_7)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_14_2_11, all_22_2_29 and discharging atoms aNaturalNumber0(xn) = all_22_2_29, aNaturalNumber0(xn) = all_14_2_11, yields:
% 66.56/28.98  						| (466) all_22_2_29 = all_14_2_11
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with sz10, all_12_2_8, 0 and discharging atoms aNaturalNumber0(sz10) = 0, yields:
% 66.56/28.98  						| (467) all_12_2_8 = 0 |  ~ (aNaturalNumber0(sz10) = all_12_2_8)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_12_2_8, all_36_1_51 and discharging atoms aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.98  						| (468) all_36_1_51 = all_12_2_8 |  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_12_2_8, all_22_0_27 and discharging atoms aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.98  						| (469) all_22_0_27 = all_12_2_8 |  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 66.56/28.98  						|
% 66.56/28.98  						| Instantiating formula (46) with xn, all_12_2_8, all_26_0_35 and discharging atoms aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.98  						| (470) all_26_0_35 = all_12_2_8 |  ~ (aNaturalNumber0(xn) = all_26_0_35)
% 66.56/28.99  						|
% 66.56/28.99  						| Instantiating formula (46) with xn, all_12_2_8, all_26_2_37 and discharging atoms aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.99  						| (471) all_26_2_37 = all_12_2_8 |  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 66.56/28.99  						|
% 66.56/28.99  						| Instantiating formula (46) with xn, all_12_2_8, all_41_2_56 and discharging atoms aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.99  						| (472) all_41_2_56 = all_12_2_8 |  ~ (aNaturalNumber0(xn) = all_41_2_56)
% 66.56/28.99  						|
% 66.56/28.99  						| Instantiating formula (46) with xn, all_12_2_8, all_41_1_55 and discharging atoms aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.99  						| (473) all_41_1_55 = all_12_2_8 |  ~ (aNaturalNumber0(xn) = all_41_1_55)
% 66.56/28.99  						|
% 66.56/28.99  						| Instantiating formula (46) with xn, all_12_2_8, all_36_2_52 and discharging atoms aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.99  						| (474) all_36_2_52 = all_12_2_8 |  ~ (aNaturalNumber0(xn) = all_36_2_52)
% 66.56/28.99  						|
% 66.56/28.99  						| Instantiating formula (46) with xn, all_12_2_8, all_30_7_48 and discharging atoms aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.99  						| (475) all_30_7_48 = all_12_2_8 |  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 66.56/28.99  						|
% 66.56/28.99  						| Instantiating formula (46) with xn, all_12_2_8, all_24_3_33 and discharging atoms aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.99  						| (476) all_24_3_33 = all_12_2_8 |  ~ (aNaturalNumber0(xn) = all_24_3_33)
% 66.56/28.99  						|
% 66.56/28.99  						| Instantiating formula (46) with xn, all_12_2_8, all_22_1_28 and discharging atoms aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.99  						| (477) all_22_1_28 = all_12_2_8 |  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 66.56/28.99  						|
% 66.56/28.99  						| Instantiating formula (46) with xn, all_12_2_8, all_14_1_10 and discharging atoms aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.99  						| (478) all_14_1_10 = all_12_2_8 |  ~ (aNaturalNumber0(xn) = all_14_1_10)
% 66.56/28.99  						|
% 66.56/28.99  						| Instantiating formula (46) with xn, all_12_2_8, all_30_8_49 and discharging atoms aNaturalNumber0(xn) = all_30_8_49, aNaturalNumber0(xn) = all_12_2_8, yields:
% 66.56/28.99  						| (479) all_30_8_49 = all_12_2_8
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (253,271) yields a new equation:
% 66.56/28.99  						| (480) all_36_3_53 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (313,321) yields a new equation:
% 66.56/28.99  						| (481) all_26_1_36 = all_24_2_32
% 66.56/28.99  						|
% 66.56/28.99  						| Simplifying 481 yields:
% 66.56/28.99  						| (482) all_26_1_36 = all_24_2_32
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (331,361) yields a new equation:
% 66.56/28.99  						| (483) all_24_3_33 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (350,361) yields a new equation:
% 66.56/28.99  						| (484) all_28_1_39 = all_24_3_33
% 66.56/28.99  						|
% 66.56/28.99  						| Simplifying 484 yields:
% 66.56/28.99  						| (485) all_28_1_39 = all_24_3_33
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (423,479) yields a new equation:
% 66.56/28.99  						| (486) all_28_2_40 = all_12_2_8
% 66.56/28.99  						|
% 66.56/28.99  						| Simplifying 486 yields:
% 66.56/28.99  						| (487) all_28_2_40 = all_12_2_8
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (384,373) yields a new equation:
% 66.56/28.99  						| (488) all_22_1_28 = all_14_1_10
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (485,373) yields a new equation:
% 66.56/28.99  						| (489) all_24_3_33 = all_22_1_28
% 66.56/28.99  						|
% 66.56/28.99  						| Simplifying 489 yields:
% 66.56/28.99  						| (490) all_24_3_33 = all_22_1_28
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (434,487) yields a new equation:
% 66.56/28.99  						| (491) all_24_4_34 = all_12_2_8
% 66.56/28.99  						|
% 66.56/28.99  						| Simplifying 491 yields:
% 66.56/28.99  						| (492) all_24_4_34 = all_12_2_8
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (303,482) yields a new equation:
% 66.56/28.99  						| (493) all_24_2_32 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (330,482) yields a new equation:
% 66.56/28.99  						| (494) all_24_2_32 = all_16_1_13
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (252,242) yields a new equation:
% 66.56/28.99  						| (495) all_16_2_14 = all_12_0_6
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (494,493) yields a new equation:
% 66.56/28.99  						| (496) all_16_1_13 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Simplifying 496 yields:
% 66.56/28.99  						| (497) all_16_1_13 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (490,483) yields a new equation:
% 66.56/28.99  						| (498) all_22_1_28 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Simplifying 498 yields:
% 66.56/28.99  						| (499) all_22_1_28 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (450,492) yields a new equation:
% 66.56/28.99  						| (500) all_22_2_29 = all_12_2_8
% 66.56/28.99  						|
% 66.56/28.99  						| Simplifying 500 yields:
% 66.56/28.99  						| (501) all_22_2_29 = all_12_2_8
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (488,499) yields a new equation:
% 66.56/28.99  						| (502) all_14_1_10 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Simplifying 502 yields:
% 66.56/28.99  						| (503) all_14_1_10 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (466,501) yields a new equation:
% 66.56/28.99  						| (504) all_14_2_11 = all_12_2_8
% 66.56/28.99  						|
% 66.56/28.99  						| Simplifying 504 yields:
% 66.56/28.99  						| (505) all_14_2_11 = all_12_2_8
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (394,503) yields a new equation:
% 66.56/28.99  						| (506) all_12_1_7 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Simplifying 506 yields:
% 66.56/28.99  						| (507) all_12_1_7 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (451,505) yields a new equation:
% 66.56/28.99  						| (508) all_12_2_8 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (508,505) yields a new equation:
% 66.56/28.99  						| (451) all_14_2_11 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (508,501) yields a new equation:
% 66.56/28.99  						| (510) all_22_2_29 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (508,492) yields a new equation:
% 66.56/28.99  						| (511) all_24_4_34 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (495,242) yields a new equation:
% 66.56/28.99  						| (252) all_26_2_37 = all_12_0_6
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (493,482) yields a new equation:
% 66.56/28.99  						| (303) all_26_1_36 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (508,487) yields a new equation:
% 66.56/28.99  						| (514) all_28_2_40 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (499,373) yields a new equation:
% 66.56/28.99  						| (515) all_28_1_39 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (508,479) yields a new equation:
% 66.56/28.99  						| (516) all_30_8_49 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (483,361) yields a new equation:
% 66.56/28.99  						| (331) all_30_7_48 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| Combining equations (480,271) yields a new equation:
% 66.56/28.99  						| (253) all_41_2_56 = 0
% 66.56/28.99  						|
% 66.56/28.99  						| From (205) and (150) follows:
% 66.56/28.99  						| (51) isPrime0(xp) = 0
% 66.56/28.99  						|
% 66.56/28.99  						| From (207) and (152) follows:
% 66.56/28.99  						| (520) sdtpldt0(all_0_5_5, xp) = all_30_3_44
% 66.56/28.99  						|
% 66.56/28.99  						| From (207) and (155) follows:
% 66.56/28.99  						| (73) sdtpldt0(xn, xm) = all_0_5_5
% 66.56/28.99  						|
% 66.56/28.99  						| From (219) and (167) follows:
% 66.56/28.99  						| (126) aNaturalNumber0(all_0_3_3) = all_22_0_27
% 66.56/28.99  						|
% 66.56/28.99  						| From (495) and (118) follows:
% 66.56/28.99  						| (107) aNaturalNumber0(all_0_5_5) = all_12_0_6
% 66.56/28.99  						|
% 66.56/28.99  						| From (480) and (163) follows:
% 66.56/28.99  						| (10) aNaturalNumber0(xr) = 0
% 66.56/28.99  						|
% 66.56/28.99  						| From (293) and (175) follows:
% 66.56/28.99  						| (166) aNaturalNumber0(xk) = all_36_2_52
% 66.56/28.99  						|
% 66.56/28.99  						| From (497) and (119) follows:
% 66.56/28.99  						| (12) aNaturalNumber0(xp) = 0
% 66.56/28.99  						|
% 66.56/28.99  						| From (507) and (108) follows:
% 66.56/28.99  						| (36) aNaturalNumber0(xm) = 0
% 66.56/28.99  						|
% 66.56/28.99  						| From (508) and (109) follows:
% 66.56/28.99  						| (53) aNaturalNumber0(xn) = 0
% 66.56/28.99  						|
% 66.56/28.99  						+-Applying beta-rule and splitting (121), into two cases.
% 66.56/28.99  						|-Branch one:
% 66.56/28.99  						| (529) all_18_0_15 = xp & all_18_1_16 = 0 & sdtpldt0(xn, all_18_2_17) = xp & aNaturalNumber0(all_18_2_17) = 0
% 66.56/28.99  						|
% 66.56/28.99  							| Applying alpha-rule on (529) yields:
% 66.56/28.99  							| (530) all_18_0_15 = xp
% 66.56/28.99  							| (531) all_18_1_16 = 0
% 66.56/28.99  							| (532) sdtpldt0(xn, all_18_2_17) = xp
% 66.56/28.99  							| (533) aNaturalNumber0(all_18_2_17) = 0
% 66.56/28.99  							|
% 66.56/28.99  							+-Applying beta-rule and splitting (129), into two cases.
% 66.56/28.99  							|-Branch one:
% 66.56/28.99  							| (534)  ~ (all_22_1_28 = 0)
% 66.56/28.99  							|
% 66.56/28.99  								| Equations (499) can reduce 534 to:
% 66.56/28.99  								| (159) $false
% 66.56/28.99  								|
% 66.56/28.99  								|-The branch is then unsatisfiable
% 66.56/28.99  							|-Branch two:
% 66.56/28.99  							| (499) all_22_1_28 = 0
% 66.56/28.99  							| (537)  ~ (all_22_2_29 = 0) | all_22_0_27 = 0
% 66.56/28.99  							|
% 66.56/28.99  								+-Applying beta-rule and splitting (122), into two cases.
% 66.56/28.99  								|-Branch one:
% 66.56/28.99  								| (538) all_19_0_18 = xp & all_19_1_19 = 0 & sdtpldt0(xm, all_19_2_20) = xp & aNaturalNumber0(all_19_2_20) = 0
% 66.56/28.99  								|
% 66.56/28.99  									| Applying alpha-rule on (538) yields:
% 66.56/28.99  									| (539) all_19_0_18 = xp
% 66.56/28.99  									| (540) all_19_1_19 = 0
% 66.56/28.99  									| (541) sdtpldt0(xm, all_19_2_20) = xp
% 66.56/28.99  									| (542) aNaturalNumber0(all_19_2_20) = 0
% 66.56/28.99  									|
% 66.56/28.99  									+-Applying beta-rule and splitting (110), into two cases.
% 66.56/28.99  									|-Branch one:
% 66.56/28.99  									| (543)  ~ (all_12_1_7 = 0)
% 66.56/28.99  									|
% 66.56/28.99  										| Equations (507) can reduce 543 to:
% 66.56/28.99  										| (159) $false
% 66.56/28.99  										|
% 66.56/28.99  										|-The branch is then unsatisfiable
% 66.56/28.99  									|-Branch two:
% 66.56/28.99  									| (507) all_12_1_7 = 0
% 66.56/28.99  									| (546)  ~ (all_12_2_8 = 0) | all_12_0_6 = 0
% 66.56/28.99  									|
% 66.56/28.99  										+-Applying beta-rule and splitting (115), into two cases.
% 66.56/28.99  										|-Branch one:
% 66.56/28.99  										| (547)  ~ (all_14_1_10 = 0)
% 66.56/28.99  										|
% 66.56/28.99  											| Equations (503) can reduce 547 to:
% 66.56/28.99  											| (159) $false
% 66.56/28.99  											|
% 66.56/28.99  											|-The branch is then unsatisfiable
% 66.56/28.99  										|-Branch two:
% 66.56/28.99  										| (503) all_14_1_10 = 0
% 66.56/28.99  										| (550)  ~ (all_14_2_11 = 0) | all_14_0_9 = all_0_5_5
% 66.56/28.99  										|
% 66.56/28.99  											+-Applying beta-rule and splitting (537), into two cases.
% 66.56/28.99  											|-Branch one:
% 66.56/28.99  											| (551)  ~ (all_22_2_29 = 0)
% 66.56/28.99  											|
% 66.56/28.99  												| Equations (510) can reduce 551 to:
% 66.56/28.99  												| (159) $false
% 66.56/28.99  												|
% 66.56/28.99  												|-The branch is then unsatisfiable
% 66.56/28.99  											|-Branch two:
% 66.56/28.99  											| (510) all_22_2_29 = 0
% 66.56/28.99  											| (554) all_22_0_27 = 0
% 66.56/28.99  											|
% 66.56/28.99  												| Combining equations (554,219) yields a new equation:
% 66.56/28.99  												| (555) all_36_1_51 = 0
% 66.56/28.99  												|
% 66.56/28.99  												| From (554) and (126) follows:
% 66.56/28.99  												| (556) aNaturalNumber0(all_0_3_3) = 0
% 66.56/29.00  												|
% 66.56/29.00  												+-Applying beta-rule and splitting (123), into two cases.
% 66.56/29.00  												|-Branch one:
% 66.56/29.00  												| (557) all_20_0_21 = all_0_3_3 & all_20_1_22 = 0 & sdtasdt0(xp, all_20_2_23) = all_0_3_3 & aNaturalNumber0(all_20_2_23) = 0
% 66.56/29.00  												|
% 66.56/29.00  													| Applying alpha-rule on (557) yields:
% 66.56/29.00  													| (558) all_20_0_21 = all_0_3_3
% 66.56/29.00  													| (559) all_20_1_22 = 0
% 66.56/29.00  													| (560) sdtasdt0(xp, all_20_2_23) = all_0_3_3
% 66.56/29.00  													| (561) aNaturalNumber0(all_20_2_23) = 0
% 66.56/29.00  													|
% 66.56/29.00  													+-Applying beta-rule and splitting (550), into two cases.
% 66.56/29.00  													|-Branch one:
% 66.56/29.00  													| (562)  ~ (all_14_2_11 = 0)
% 66.56/29.00  													|
% 66.56/29.00  														| Equations (451) can reduce 562 to:
% 66.56/29.00  														| (159) $false
% 66.56/29.00  														|
% 66.56/29.00  														|-The branch is then unsatisfiable
% 66.56/29.00  													|-Branch two:
% 66.56/29.00  													| (451) all_14_2_11 = 0
% 66.56/29.00  													| (565) all_14_0_9 = all_0_5_5
% 66.56/29.00  													|
% 66.56/29.00  														| From (565) and (112) follows:
% 66.56/29.00  														| (566) sdtpldt0(xm, xn) = all_0_5_5
% 66.56/29.00  														|
% 66.56/29.00  														+-Applying beta-rule and splitting (546), into two cases.
% 66.56/29.00  														|-Branch one:
% 66.56/29.00  														| (567)  ~ (all_12_2_8 = 0)
% 66.56/29.00  														|
% 66.56/29.00  															| Equations (508) can reduce 567 to:
% 66.56/29.00  															| (159) $false
% 66.56/29.00  															|
% 66.56/29.00  															|-The branch is then unsatisfiable
% 66.56/29.00  														|-Branch two:
% 66.56/29.00  														| (508) all_12_2_8 = 0
% 66.56/29.00  														| (570) all_12_0_6 = 0
% 66.56/29.00  														|
% 66.56/29.00  															| Combining equations (570,495) yields a new equation:
% 66.56/29.00  															| (571) all_16_2_14 = 0
% 66.56/29.00  															|
% 66.56/29.00  															| Combining equations (570,252) yields a new equation:
% 66.56/29.00  															| (572) all_26_2_37 = 0
% 66.56/29.00  															|
% 66.56/29.00  															| From (570) and (107) follows:
% 66.56/29.00  															| (573) aNaturalNumber0(all_0_5_5) = 0
% 66.56/29.00  															|
% 66.56/29.00  															+-Applying beta-rule and splitting (141), into two cases.
% 66.56/29.00  															|-Branch one:
% 66.56/29.00  															| (574)  ~ (all_26_1_36 = 0)
% 66.56/29.00  															|
% 66.56/29.00  																| Equations (303) can reduce 574 to:
% 66.56/29.00  																| (159) $false
% 66.56/29.00  																|
% 66.56/29.00  																|-The branch is then unsatisfiable
% 66.56/29.00  															|-Branch two:
% 66.56/29.00  															| (303) all_26_1_36 = 0
% 66.56/29.00  															| (577)  ~ (all_26_2_37 = 0) | all_26_0_35 = 0
% 66.56/29.00  															|
% 66.56/29.00  																+-Applying beta-rule and splitting (131), into two cases.
% 66.56/29.00  																|-Branch one:
% 66.56/29.00  																| (578)  ~ (all_24_2_32 = 0)
% 66.56/29.00  																|
% 66.56/29.00  																	| Equations (493) can reduce 578 to:
% 66.56/29.00  																	| (159) $false
% 66.56/29.00  																	|
% 66.56/29.00  																	|-The branch is then unsatisfiable
% 66.56/29.00  																|-Branch two:
% 66.56/29.00  																| (493) all_24_2_32 = 0
% 66.56/29.00  																| (581)  ~ (all_24_3_33 = 0) |  ~ (all_24_4_34 = 0) | all_24_0_30 = all_0_4_4
% 66.56/29.00  																|
% 66.56/29.00  																	+-Applying beta-rule and splitting (581), into two cases.
% 66.56/29.00  																	|-Branch one:
% 66.56/29.00  																	| (582)  ~ (all_24_3_33 = 0)
% 66.56/29.00  																	|
% 66.56/29.00  																		| Equations (483) can reduce 582 to:
% 66.56/29.00  																		| (159) $false
% 66.56/29.00  																		|
% 66.56/29.00  																		|-The branch is then unsatisfiable
% 66.56/29.00  																	|-Branch two:
% 66.56/29.00  																	| (483) all_24_3_33 = 0
% 66.56/29.00  																	| (585)  ~ (all_24_4_34 = 0) | all_24_0_30 = all_0_4_4
% 66.56/29.00  																	|
% 66.56/29.00  																		+-Applying beta-rule and splitting (585), into two cases.
% 66.56/29.00  																		|-Branch one:
% 66.56/29.00  																		| (586)  ~ (all_24_4_34 = 0)
% 66.56/29.00  																		|
% 66.56/29.00  																			| Equations (511) can reduce 586 to:
% 66.56/29.00  																			| (159) $false
% 66.56/29.00  																			|
% 66.56/29.00  																			|-The branch is then unsatisfiable
% 66.56/29.00  																		|-Branch two:
% 66.56/29.00  																		| (511) all_24_4_34 = 0
% 66.56/29.00  																		| (589) all_24_0_30 = all_0_4_4
% 66.56/29.00  																		|
% 66.56/29.00  																			| From (589) and (133) follows:
% 66.56/29.00  																			| (590) sdtpldt0(xn, all_24_1_31) = all_0_4_4
% 66.56/29.00  																			|
% 66.56/29.00  																			+-Applying beta-rule and splitting (577), into two cases.
% 66.56/29.00  																			|-Branch one:
% 66.56/29.00  																			| (591)  ~ (all_26_2_37 = 0)
% 66.56/29.00  																			|
% 66.56/29.00  																				| Equations (572) can reduce 591 to:
% 66.56/29.00  																				| (159) $false
% 66.56/29.00  																				|
% 66.56/29.00  																				|-The branch is then unsatisfiable
% 66.56/29.00  																			|-Branch two:
% 66.56/29.00  																			| (572) all_26_2_37 = 0
% 66.56/29.00  																			| (594) all_26_0_35 = 0
% 66.56/29.00  																			|
% 66.56/29.00  																				| From (594) and (138) follows:
% 66.56/29.00  																				| (595) aNaturalNumber0(all_0_4_4) = 0
% 66.56/29.00  																				|
% 66.56/29.00  																				+-Applying beta-rule and splitting (146), into two cases.
% 66.56/29.00  																				|-Branch one:
% 66.56/29.00  																				| (596)  ~ (all_28_1_39 = 0)
% 66.56/29.00  																				|
% 66.56/29.00  																					| Equations (515) can reduce 596 to:
% 66.56/29.00  																					| (159) $false
% 66.56/29.00  																					|
% 66.56/29.00  																					|-The branch is then unsatisfiable
% 66.56/29.00  																				|-Branch two:
% 66.56/29.00  																				| (515) all_28_1_39 = 0
% 66.56/29.00  																				| (599)  ~ (all_28_2_40 = 0) | all_28_0_38 = all_0_3_3
% 66.56/29.00  																				|
% 66.56/29.00  																					+-Applying beta-rule and splitting (120), into two cases.
% 66.56/29.00  																					|-Branch one:
% 66.56/29.00  																					| (600)  ~ (all_16_1_13 = 0)
% 66.56/29.00  																					|
% 66.56/29.00  																						| Equations (497) can reduce 600 to:
% 66.56/29.00  																						| (159) $false
% 66.56/29.00  																						|
% 66.56/29.00  																						|-The branch is then unsatisfiable
% 66.56/29.00  																					|-Branch two:
% 66.56/29.00  																					| (497) all_16_1_13 = 0
% 66.56/29.00  																					| (603)  ~ (all_16_2_14 = 0) | all_16_0_12 = all_0_4_4
% 66.56/29.00  																					|
% 66.56/29.00  																						+-Applying beta-rule and splitting (599), into two cases.
% 66.56/29.00  																						|-Branch one:
% 66.56/29.00  																						| (604)  ~ (all_28_2_40 = 0)
% 66.56/29.00  																						|
% 66.56/29.00  																							| Equations (514) can reduce 604 to:
% 66.56/29.00  																							| (159) $false
% 66.56/29.00  																							|
% 66.56/29.00  																							|-The branch is then unsatisfiable
% 66.56/29.00  																						|-Branch two:
% 66.56/29.00  																						| (514) all_28_2_40 = 0
% 66.56/29.00  																						| (607) all_28_0_38 = all_0_3_3
% 66.56/29.00  																						|
% 66.56/29.00  																							| From (607) and (143) follows:
% 66.56/29.00  																							| (608) sdtasdt0(xm, xn) = all_0_3_3
% 66.56/29.00  																							|
% 66.56/29.00  																							+-Applying beta-rule and splitting (603), into two cases.
% 66.56/29.00  																							|-Branch one:
% 66.56/29.00  																							| (609)  ~ (all_16_2_14 = 0)
% 66.56/29.00  																							|
% 66.56/29.00  																								| Equations (571) can reduce 609 to:
% 66.56/29.00  																								| (159) $false
% 66.56/29.00  																								|
% 66.56/29.00  																								|-The branch is then unsatisfiable
% 66.56/29.00  																							|-Branch two:
% 66.56/29.00  																							| (571) all_16_2_14 = 0
% 66.56/29.00  																							| (612) all_16_0_12 = all_0_4_4
% 66.56/29.00  																							|
% 66.56/29.00  																								| From (612) and (117) follows:
% 66.56/29.00  																								| (613) sdtpldt0(xp, all_0_5_5) = all_0_4_4
% 66.56/29.00  																								|
% 66.56/29.00  																								+-Applying beta-rule and splitting (206), into two cases.
% 66.56/29.00  																								|-Branch one:
% 66.56/29.00  																								| (614)  ~ (sdtpldt0(all_0_5_5, xp) = all_30_3_44)
% 66.56/29.00  																								|
% 66.56/29.00  																									| Using (520) and (614) yields:
% 66.56/29.00  																									| (615) $false
% 66.56/29.00  																									|
% 66.56/29.00  																									|-The branch is then unsatisfiable
% 66.56/29.00  																								|-Branch two:
% 66.56/29.00  																								| (520) sdtpldt0(all_0_5_5, xp) = all_30_3_44
% 66.56/29.00  																								| (617) all_30_3_44 = all_0_4_4
% 66.56/29.00  																								|
% 66.56/29.00  																									| From (617) and (520) follows:
% 66.56/29.00  																									| (58) sdtpldt0(all_0_5_5, xp) = all_0_4_4
% 66.56/29.00  																									|
% 66.56/29.00  																									| Instantiating formula (29) with all_58_0_58, xp and discharging atoms isPrime0(xp) = 0, doDivides0(all_58_0_58, xp) = 0, yields:
% 66.56/29.00  																									| (619) all_58_0_58 = xp | all_58_0_58 = sz10 |  ? [v0] : (( ~ (v0 = 0) & aNaturalNumber0(all_58_0_58) = v0) | ( ~ (v0 = 0) & aNaturalNumber0(xp) = v0))
% 66.56/29.00  																									|
% 66.56/29.00  																									| Instantiating formula (81) with xp, all_58_0_58 and discharging atoms doDivides0(all_58_0_58, xp) = 0, yields:
% 66.56/29.00  																									| (620) xp = sz00 |  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(all_58_0_58, xp) = v2 & aNaturalNumber0(all_58_0_58) = v0 & aNaturalNumber0(xp) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.56/29.00  																									|
% 66.56/29.00  																									| Instantiating formula (76) with xp, all_58_0_58 and discharging atoms doDivides0(all_58_0_58, xp) = 0, yields:
% 66.56/29.00  																									| (621)  ? [v0] :  ? [v1] :  ? [v2] : ((v2 = xp & v1 = 0 & sdtasdt0(all_58_0_58, v0) = xp & aNaturalNumber0(v0) = 0) | (aNaturalNumber0(all_58_0_58) = v0 & aNaturalNumber0(xp) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0))))
% 66.77/29.00  																									|
% 66.77/29.00  																									| Instantiating formula (29) with all_53_0_57, xr and discharging atoms isPrime0(xr) = 0, doDivides0(all_53_0_57, xr) = 0, yields:
% 66.77/29.00  																									| (622) all_53_0_57 = xr | all_53_0_57 = sz10 |  ? [v0] : (( ~ (v0 = 0) & aNaturalNumber0(all_53_0_57) = v0) | ( ~ (v0 = 0) & aNaturalNumber0(xr) = v0))
% 66.77/29.00  																									|
% 66.77/29.00  																									| Instantiating formula (81) with xr, all_53_0_57 and discharging atoms doDivides0(all_53_0_57, xr) = 0, yields:
% 66.77/29.00  																									| (623) xr = sz00 |  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(all_53_0_57, xr) = v2 & aNaturalNumber0(all_53_0_57) = v0 & aNaturalNumber0(xr) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.77/29.00  																									|
% 66.77/29.00  																									| Instantiating formula (66) with all_30_0_41, xm, all_0_3_3, xp and discharging atoms doDivides0(xp, all_0_3_3) = 0, doDivides0(xp, xm) = all_30_0_41, yields:
% 66.77/29.00  																									| (624) all_30_0_41 = 0 |  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] : (doDivides0(all_0_3_3, xm) = v3 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xm) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0)))
% 66.77/29.00  																									|
% 66.77/29.00  																									| Instantiating formula (81) with xm, xp yields:
% 66.77/29.00  																									| (625) xm = sz00 |  ~ (doDivides0(xp, xm) = 0) |  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(xp, xm) = v2 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xm) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.77/29.00  																									|
% 66.77/29.00  																									| Instantiating formula (66) with all_30_1_42, xn, all_0_3_3, xp and discharging atoms doDivides0(xp, all_0_3_3) = 0, doDivides0(xp, xn) = all_30_1_42, yields:
% 66.77/29.00  																									| (626) all_30_1_42 = 0 |  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] : (doDivides0(all_0_3_3, xn) = v3 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xn) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0)))
% 66.77/29.00  																									|
% 66.77/29.00  																									| Instantiating formula (81) with xn, xp yields:
% 66.77/29.00  																									| (627) xn = sz00 |  ~ (doDivides0(xp, xn) = 0) |  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(xp, xn) = v2 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xn) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.77/29.00  																									|
% 66.77/29.00  																									| Instantiating formula (9) with all_0_3_3, xk, all_0_3_3, xp and discharging atoms sdtsldt0(all_0_3_3, xp) = xk, yields:
% 66.77/29.00  																									| (628) xp = sz00 |  ~ (sdtasdt0(xp, xk) = all_0_3_3) |  ? [v0] :  ? [v1] :  ? [v2] : ((v0 = 0 & aNaturalNumber0(xk) = 0) | (doDivides0(xp, all_0_3_3) = v2 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0))))
% 66.77/29.00  																									|
% 66.77/29.00  																									| Instantiating formula (34) with all_20_2_23, xk, all_0_3_3, xp and discharging atoms sdtsldt0(all_0_3_3, xp) = xk, sdtasdt0(xp, all_20_2_23) = all_0_3_3, yields:
% 66.77/29.00  																									| (629) all_20_2_23 = xk | xp = sz00 |  ? [v0] :  ? [v1] :  ? [v2] : (( ~ (v0 = 0) & aNaturalNumber0(all_20_2_23) = v0) | (doDivides0(xp, all_0_3_3) = v2 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0))))
% 66.77/29.00  																									|
% 66.77/29.00  																									| Instantiating formula (7) with all_0_3_3, xp, all_20_2_23, xp and discharging atoms doDivides0(xp, all_0_3_3) = 0, sdtasdt0(xp, all_20_2_23) = all_0_3_3, yields:
% 66.77/29.00  																									| (630)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] : (isPrime0(xp) = v3 & doDivides0(xp, all_20_2_23) = v8 & doDivides0(xp, xp) = v7 & iLess0(v5, all_0_4_4) = v6 & sdtpldt0(v4, xp) = v5 & sdtpldt0(xp, all_20_2_23) = v4 & aNaturalNumber0(all_20_2_23) = v1 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xp) = v0 & ( ~ (v6 = 0) |  ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v8 = 0 | v7 = 0))
% 66.77/29.00  																									|
% 66.77/29.00  																									| Instantiating formula (50) with all_20_2_23, xp yields:
% 66.77/29.00  																									| (631) all_20_2_23 = sz00 | xp = sz00 |  ~ (sdtasdt0(xp, all_20_2_23) = sz00) |  ? [v0] :  ? [v1] : (aNaturalNumber0(all_20_2_23) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0)))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (27) with all_0_3_3, all_20_2_23, xp and discharging atoms sdtasdt0(xp, all_20_2_23) = all_0_3_3, yields:
% 66.77/29.01  																									| (632)  ? [v0] :  ? [v1] :  ? [v2] : (sdtasdt0(all_20_2_23, xp) = v2 & aNaturalNumber0(all_20_2_23) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = all_0_3_3))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (7) with all_0_3_3, xp, xn, xm and discharging atoms doDivides0(xp, all_0_3_3) = 0, sdtasdt0(xm, xn) = all_0_3_3, yields:
% 66.77/29.01  																									| (633)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] : (isPrime0(xp) = v3 & doDivides0(xp, xm) = v7 & doDivides0(xp, xn) = v8 & iLess0(v5, all_0_4_4) = v6 & sdtpldt0(v4, xp) = v5 & sdtpldt0(xm, xn) = v4 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xm) = v0 & aNaturalNumber0(xn) = v1 & ( ~ (v6 = 0) |  ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v8 = 0 | v7 = 0))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (19) with all_0_3_3, xn yields:
% 66.77/29.01  																									| (634)  ~ (sdtasdt0(sz00, xn) = all_0_3_3) |  ? [v0] :  ? [v1] : (sdtasdt0(xn, sz00) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v0 = 0) | (v1 = sz00 & all_0_3_3 = sz00)))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (40) with xp, all_19_2_20, xm, all_58_0_58 and discharging atoms doDivides0(all_58_0_58, xp) = 0, sdtpldt0(xm, all_19_2_20) = xp, yields:
% 66.77/29.01  																									| (635)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (doDivides0(all_58_0_58, all_19_2_20) = v4 & doDivides0(all_58_0_58, xm) = v3 & aNaturalNumber0(all_58_0_58) = v0 & aNaturalNumber0(all_19_2_20) = v2 & aNaturalNumber0(xm) = v1 & ( ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = 0))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (49) with all_0_4_4, xp, all_0_5_5, all_19_2_20, xm and discharging atoms sdtpldt0(xp, all_0_5_5) = all_0_4_4, sdtpldt0(xm, all_19_2_20) = xp, yields:
% 66.77/29.01  																									| (636)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(all_19_2_20, all_0_5_5) = v3 & sdtpldt0(xm, v3) = v4 & aNaturalNumber0(all_19_2_20) = v1 & aNaturalNumber0(all_0_5_5) = v2 & aNaturalNumber0(xm) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_0_4_4))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (78) with xp, all_19_2_20, xm and discharging atoms sdtpldt0(xm, all_19_2_20) = xp, yields:
% 66.77/29.01  																									| (637)  ? [v0] :  ? [v1] :  ? [v2] : (sdtpldt0(all_19_2_20, xm) = v2 & aNaturalNumber0(all_19_2_20) = v1 & aNaturalNumber0(xm) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = xp))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (78) with all_24_1_31, xp, xm and discharging atoms sdtpldt0(xm, xp) = all_24_1_31, yields:
% 66.77/29.01  																									| (638)  ? [v0] :  ? [v1] :  ? [v2] : (sdtpldt0(xp, xm) = v2 & aNaturalNumber0(xp) = v1 & aNaturalNumber0(xm) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = all_24_1_31))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (43) with all_24_1_31, xp, xm and discharging atoms sdtpldt0(xm, xp) = all_24_1_31, yields:
% 66.77/29.01  																									| (639)  ? [v0] :  ? [v1] :  ? [v2] : (aNaturalNumber0(all_24_1_31) = v2 & aNaturalNumber0(xp) = v1 & aNaturalNumber0(xm) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (49) with all_0_4_4, all_0_5_5, xp, xn, xm and discharging atoms sdtpldt0(all_0_5_5, xp) = all_0_4_4, sdtpldt0(xm, xn) = all_0_5_5, yields:
% 66.77/29.01  																									| (640)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(xm, v3) = v4 & sdtpldt0(xn, xp) = v3 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xm) = v0 & aNaturalNumber0(xn) = v1 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_0_4_4))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (24) with all_0_5_5, all_24_1_31, xn, xp, xm and discharging atoms sdtpldt0(xm, xp) = all_24_1_31, sdtpldt0(xm, xn) = all_0_5_5, yields:
% 66.77/29.01  																									| (641) xp = xn |  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(xp, xm) = v3 & sdtpldt0(xn, xm) = v4 & aNaturalNumber0(xp) = v1 & aNaturalNumber0(xm) = v0 & aNaturalNumber0(xn) = v2 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | ( ~ (v4 = v3) &  ~ (all_24_1_31 = all_0_5_5))))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (24) with all_24_1_31, all_0_5_5, xp, xn, xm and discharging atoms sdtpldt0(xm, xp) = all_24_1_31, sdtpldt0(xm, xn) = all_0_5_5, yields:
% 66.77/29.01  																									| (642) xp = xn |  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(xp, xm) = v4 & sdtpldt0(xn, xm) = v3 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xm) = v0 & aNaturalNumber0(xn) = v1 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | ( ~ (v4 = v3) &  ~ (all_24_1_31 = all_0_5_5))))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (78) with all_0_4_4, all_24_1_31, xn and discharging atoms sdtpldt0(xn, all_24_1_31) = all_0_4_4, yields:
% 66.77/29.01  																									| (643)  ? [v0] :  ? [v1] :  ? [v2] : (sdtpldt0(all_24_1_31, xn) = v2 & aNaturalNumber0(all_24_1_31) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = all_0_4_4))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (43) with all_0_4_4, all_24_1_31, xn and discharging atoms sdtpldt0(xn, all_24_1_31) = all_0_4_4, yields:
% 66.77/29.01  																									| (644)  ? [v0] :  ? [v1] :  ? [v2] : (aNaturalNumber0(all_24_1_31) = v1 & aNaturalNumber0(all_0_4_4) = v2 & aNaturalNumber0(xn) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (40) with xp, all_18_2_17, xn, all_58_0_58 and discharging atoms doDivides0(all_58_0_58, xp) = 0, sdtpldt0(xn, all_18_2_17) = xp, yields:
% 66.77/29.01  																									| (645)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (doDivides0(all_58_0_58, all_18_2_17) = v4 & doDivides0(all_58_0_58, xn) = v3 & aNaturalNumber0(all_58_0_58) = v0 & aNaturalNumber0(all_18_2_17) = v2 & aNaturalNumber0(xn) = v1 & ( ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = 0))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (49) with all_0_4_4, xp, all_0_5_5, all_18_2_17, xn and discharging atoms sdtpldt0(xp, all_0_5_5) = all_0_4_4, sdtpldt0(xn, all_18_2_17) = xp, yields:
% 66.77/29.01  																									| (646)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(all_18_2_17, all_0_5_5) = v3 & sdtpldt0(xn, v3) = v4 & aNaturalNumber0(all_18_2_17) = v1 & aNaturalNumber0(all_0_5_5) = v2 & aNaturalNumber0(xn) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_0_4_4))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (78) with xp, all_18_2_17, xn and discharging atoms sdtpldt0(xn, all_18_2_17) = xp, yields:
% 66.77/29.01  																									| (647)  ? [v0] :  ? [v1] :  ? [v2] : (sdtpldt0(all_18_2_17, xn) = v2 & aNaturalNumber0(all_18_2_17) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = xp))
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (8) with all_58_0_58 and discharging atoms aNaturalNumber0(all_58_0_58) = 0, yields:
% 66.77/29.01  																									| (648) all_58_0_58 = sz10 | all_58_0_58 = sz00 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, all_58_0_58) = 0 & aNaturalNumber0(v0) = 0)
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (8) with all_53_0_57 and discharging atoms aNaturalNumber0(all_53_0_57) = 0, yields:
% 66.77/29.01  																									| (649) all_53_0_57 = sz10 | all_53_0_57 = sz00 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, all_53_0_57) = 0 & aNaturalNumber0(v0) = 0)
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (8) with all_20_2_23 and discharging atoms aNaturalNumber0(all_20_2_23) = 0, yields:
% 66.77/29.01  																									| (650) all_20_2_23 = sz10 | all_20_2_23 = sz00 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, all_20_2_23) = 0 & aNaturalNumber0(v0) = 0)
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating formula (8) with xk yields:
% 66.77/29.01  																									| (651) xk = sz10 | xk = sz00 |  ~ (aNaturalNumber0(xk) = 0) |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xk) = 0 & aNaturalNumber0(v0) = 0)
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating (647) with all_157_0_59, all_157_1_60, all_157_2_61 yields:
% 66.77/29.01  																									| (652) sdtpldt0(all_18_2_17, xn) = all_157_0_59 & aNaturalNumber0(all_18_2_17) = all_157_1_60 & aNaturalNumber0(xn) = all_157_2_61 & ( ~ (all_157_1_60 = 0) |  ~ (all_157_2_61 = 0) | all_157_0_59 = xp)
% 66.77/29.01  																									|
% 66.77/29.01  																									| Applying alpha-rule on (652) yields:
% 66.77/29.01  																									| (653) sdtpldt0(all_18_2_17, xn) = all_157_0_59
% 66.77/29.01  																									| (654) aNaturalNumber0(all_18_2_17) = all_157_1_60
% 66.77/29.01  																									| (655) aNaturalNumber0(xn) = all_157_2_61
% 66.77/29.01  																									| (656)  ~ (all_157_1_60 = 0) |  ~ (all_157_2_61 = 0) | all_157_0_59 = xp
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating (645) with all_159_0_62, all_159_1_63, all_159_2_64, all_159_3_65, all_159_4_66 yields:
% 66.77/29.01  																									| (657) doDivides0(all_58_0_58, all_18_2_17) = all_159_0_62 & doDivides0(all_58_0_58, xn) = all_159_1_63 & aNaturalNumber0(all_58_0_58) = all_159_4_66 & aNaturalNumber0(all_18_2_17) = all_159_2_64 & aNaturalNumber0(xn) = all_159_3_65 & ( ~ (all_159_1_63 = 0) |  ~ (all_159_2_64 = 0) |  ~ (all_159_3_65 = 0) |  ~ (all_159_4_66 = 0) | all_159_0_62 = 0)
% 66.77/29.01  																									|
% 66.77/29.01  																									| Applying alpha-rule on (657) yields:
% 66.77/29.01  																									| (658) aNaturalNumber0(xn) = all_159_3_65
% 66.77/29.01  																									| (659) doDivides0(all_58_0_58, all_18_2_17) = all_159_0_62
% 66.77/29.01  																									| (660)  ~ (all_159_1_63 = 0) |  ~ (all_159_2_64 = 0) |  ~ (all_159_3_65 = 0) |  ~ (all_159_4_66 = 0) | all_159_0_62 = 0
% 66.77/29.01  																									| (661) aNaturalNumber0(all_18_2_17) = all_159_2_64
% 66.77/29.01  																									| (662) doDivides0(all_58_0_58, xn) = all_159_1_63
% 66.77/29.01  																									| (663) aNaturalNumber0(all_58_0_58) = all_159_4_66
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating (640) with all_161_0_67, all_161_1_68, all_161_2_69, all_161_3_70, all_161_4_71 yields:
% 66.77/29.01  																									| (664) sdtpldt0(xm, all_161_1_68) = all_161_0_67 & sdtpldt0(xn, xp) = all_161_1_68 & aNaturalNumber0(xp) = all_161_2_69 & aNaturalNumber0(xm) = all_161_4_71 & aNaturalNumber0(xn) = all_161_3_70 & ( ~ (all_161_2_69 = 0) |  ~ (all_161_3_70 = 0) |  ~ (all_161_4_71 = 0) | all_161_0_67 = all_0_4_4)
% 66.77/29.01  																									|
% 66.77/29.01  																									| Applying alpha-rule on (664) yields:
% 66.77/29.01  																									| (665) sdtpldt0(xm, all_161_1_68) = all_161_0_67
% 66.77/29.01  																									| (666) aNaturalNumber0(xn) = all_161_3_70
% 66.77/29.01  																									| (667) aNaturalNumber0(xp) = all_161_2_69
% 66.77/29.01  																									| (668) aNaturalNumber0(xm) = all_161_4_71
% 66.77/29.01  																									| (669) sdtpldt0(xn, xp) = all_161_1_68
% 66.77/29.01  																									| (670)  ~ (all_161_2_69 = 0) |  ~ (all_161_3_70 = 0) |  ~ (all_161_4_71 = 0) | all_161_0_67 = all_0_4_4
% 66.77/29.01  																									|
% 66.77/29.01  																									| Instantiating (639) with all_163_0_72, all_163_1_73, all_163_2_74 yields:
% 66.77/29.01  																									| (671) aNaturalNumber0(all_24_1_31) = all_163_0_72 & aNaturalNumber0(xp) = all_163_1_73 & aNaturalNumber0(xm) = all_163_2_74 & ( ~ (all_163_1_73 = 0) |  ~ (all_163_2_74 = 0) | all_163_0_72 = 0)
% 66.77/29.01  																									|
% 66.77/29.01  																									| Applying alpha-rule on (671) yields:
% 66.77/29.01  																									| (672) aNaturalNumber0(all_24_1_31) = all_163_0_72
% 66.77/29.01  																									| (673) aNaturalNumber0(xp) = all_163_1_73
% 66.77/29.01  																									| (674) aNaturalNumber0(xm) = all_163_2_74
% 66.77/29.02  																									| (675)  ~ (all_163_1_73 = 0) |  ~ (all_163_2_74 = 0) | all_163_0_72 = 0
% 66.77/29.02  																									|
% 66.77/29.02  																									| Instantiating (644) with all_165_0_75, all_165_1_76, all_165_2_77 yields:
% 66.77/29.02  																									| (676) aNaturalNumber0(all_24_1_31) = all_165_1_76 & aNaturalNumber0(all_0_4_4) = all_165_0_75 & aNaturalNumber0(xn) = all_165_2_77 & ( ~ (all_165_1_76 = 0) |  ~ (all_165_2_77 = 0) | all_165_0_75 = 0)
% 66.77/29.02  																									|
% 66.77/29.02  																									| Applying alpha-rule on (676) yields:
% 66.77/29.02  																									| (677) aNaturalNumber0(all_24_1_31) = all_165_1_76
% 66.77/29.02  																									| (678) aNaturalNumber0(all_0_4_4) = all_165_0_75
% 66.77/29.02  																									| (679) aNaturalNumber0(xn) = all_165_2_77
% 66.77/29.02  																									| (680)  ~ (all_165_1_76 = 0) |  ~ (all_165_2_77 = 0) | all_165_0_75 = 0
% 66.77/29.02  																									|
% 66.77/29.02  																									| Instantiating (643) with all_167_0_78, all_167_1_79, all_167_2_80 yields:
% 66.77/29.02  																									| (681) sdtpldt0(all_24_1_31, xn) = all_167_0_78 & aNaturalNumber0(all_24_1_31) = all_167_1_79 & aNaturalNumber0(xn) = all_167_2_80 & ( ~ (all_167_1_79 = 0) |  ~ (all_167_2_80 = 0) | all_167_0_78 = all_0_4_4)
% 66.77/29.02  																									|
% 66.77/29.02  																									| Applying alpha-rule on (681) yields:
% 66.77/29.02  																									| (682) sdtpldt0(all_24_1_31, xn) = all_167_0_78
% 66.77/29.02  																									| (683) aNaturalNumber0(all_24_1_31) = all_167_1_79
% 66.77/29.02  																									| (684) aNaturalNumber0(xn) = all_167_2_80
% 66.77/29.02  																									| (685)  ~ (all_167_1_79 = 0) |  ~ (all_167_2_80 = 0) | all_167_0_78 = all_0_4_4
% 66.77/29.02  																									|
% 66.77/29.02  																									| Instantiating (646) with all_169_0_81, all_169_1_82, all_169_2_83, all_169_3_84, all_169_4_85 yields:
% 66.77/29.02  																									| (686) sdtpldt0(all_18_2_17, all_0_5_5) = all_169_1_82 & sdtpldt0(xn, all_169_1_82) = all_169_0_81 & aNaturalNumber0(all_18_2_17) = all_169_3_84 & aNaturalNumber0(all_0_5_5) = all_169_2_83 & aNaturalNumber0(xn) = all_169_4_85 & ( ~ (all_169_2_83 = 0) |  ~ (all_169_3_84 = 0) |  ~ (all_169_4_85 = 0) | all_169_0_81 = all_0_4_4)
% 66.77/29.02  																									|
% 66.77/29.02  																									| Applying alpha-rule on (686) yields:
% 66.77/29.02  																									| (687) sdtpldt0(all_18_2_17, all_0_5_5) = all_169_1_82
% 66.77/29.02  																									| (688) aNaturalNumber0(xn) = all_169_4_85
% 66.77/29.02  																									| (689) aNaturalNumber0(all_18_2_17) = all_169_3_84
% 66.77/29.02  																									| (690) sdtpldt0(xn, all_169_1_82) = all_169_0_81
% 66.77/29.02  																									| (691) aNaturalNumber0(all_0_5_5) = all_169_2_83
% 66.77/29.02  																									| (692)  ~ (all_169_2_83 = 0) |  ~ (all_169_3_84 = 0) |  ~ (all_169_4_85 = 0) | all_169_0_81 = all_0_4_4
% 66.77/29.02  																									|
% 66.77/29.02  																									| Instantiating (638) with all_171_0_86, all_171_1_87, all_171_2_88 yields:
% 66.77/29.02  																									| (693) sdtpldt0(xp, xm) = all_171_0_86 & aNaturalNumber0(xp) = all_171_1_87 & aNaturalNumber0(xm) = all_171_2_88 & ( ~ (all_171_1_87 = 0) |  ~ (all_171_2_88 = 0) | all_171_0_86 = all_24_1_31)
% 66.77/29.02  																									|
% 66.77/29.02  																									| Applying alpha-rule on (693) yields:
% 66.77/29.02  																									| (694) sdtpldt0(xp, xm) = all_171_0_86
% 66.77/29.02  																									| (695) aNaturalNumber0(xp) = all_171_1_87
% 66.77/29.02  																									| (696) aNaturalNumber0(xm) = all_171_2_88
% 66.77/29.02  																									| (697)  ~ (all_171_1_87 = 0) |  ~ (all_171_2_88 = 0) | all_171_0_86 = all_24_1_31
% 66.77/29.02  																									|
% 66.77/29.02  																									| Instantiating (637) with all_173_0_89, all_173_1_90, all_173_2_91 yields:
% 66.77/29.02  																									| (698) sdtpldt0(all_19_2_20, xm) = all_173_0_89 & aNaturalNumber0(all_19_2_20) = all_173_1_90 & aNaturalNumber0(xm) = all_173_2_91 & ( ~ (all_173_1_90 = 0) |  ~ (all_173_2_91 = 0) | all_173_0_89 = xp)
% 66.77/29.02  																									|
% 66.77/29.02  																									| Applying alpha-rule on (698) yields:
% 66.77/29.02  																									| (699) sdtpldt0(all_19_2_20, xm) = all_173_0_89
% 66.77/29.02  																									| (700) aNaturalNumber0(all_19_2_20) = all_173_1_90
% 66.77/29.02  																									| (701) aNaturalNumber0(xm) = all_173_2_91
% 66.77/29.02  																									| (702)  ~ (all_173_1_90 = 0) |  ~ (all_173_2_91 = 0) | all_173_0_89 = xp
% 66.77/29.02  																									|
% 66.77/29.02  																									| Instantiating (636) with all_175_0_92, all_175_1_93, all_175_2_94, all_175_3_95, all_175_4_96 yields:
% 66.77/29.02  																									| (703) sdtpldt0(all_19_2_20, all_0_5_5) = all_175_1_93 & sdtpldt0(xm, all_175_1_93) = all_175_0_92 & aNaturalNumber0(all_19_2_20) = all_175_3_95 & aNaturalNumber0(all_0_5_5) = all_175_2_94 & aNaturalNumber0(xm) = all_175_4_96 & ( ~ (all_175_2_94 = 0) |  ~ (all_175_3_95 = 0) |  ~ (all_175_4_96 = 0) | all_175_0_92 = all_0_4_4)
% 66.77/29.02  																									|
% 66.77/29.02  																									| Applying alpha-rule on (703) yields:
% 66.77/29.02  																									| (704) aNaturalNumber0(all_19_2_20) = all_175_3_95
% 66.77/29.02  																									| (705) aNaturalNumber0(all_0_5_5) = all_175_2_94
% 66.77/29.02  																									| (706) aNaturalNumber0(xm) = all_175_4_96
% 66.77/29.02  																									| (707) sdtpldt0(all_19_2_20, all_0_5_5) = all_175_1_93
% 66.77/29.02  																									| (708) sdtpldt0(xm, all_175_1_93) = all_175_0_92
% 66.77/29.02  																									| (709)  ~ (all_175_2_94 = 0) |  ~ (all_175_3_95 = 0) |  ~ (all_175_4_96 = 0) | all_175_0_92 = all_0_4_4
% 66.77/29.02  																									|
% 66.77/29.02  																									| Instantiating (632) with all_177_0_97, all_177_1_98, all_177_2_99 yields:
% 66.77/29.02  																									| (710) sdtasdt0(all_20_2_23, xp) = all_177_0_97 & aNaturalNumber0(all_20_2_23) = all_177_1_98 & aNaturalNumber0(xp) = all_177_2_99 & ( ~ (all_177_1_98 = 0) |  ~ (all_177_2_99 = 0) | all_177_0_97 = all_0_3_3)
% 66.77/29.02  																									|
% 66.77/29.02  																									| Applying alpha-rule on (710) yields:
% 66.77/29.02  																									| (711) sdtasdt0(all_20_2_23, xp) = all_177_0_97
% 66.77/29.02  																									| (712) aNaturalNumber0(all_20_2_23) = all_177_1_98
% 66.77/29.02  																									| (713) aNaturalNumber0(xp) = all_177_2_99
% 66.77/29.02  																									| (714)  ~ (all_177_1_98 = 0) |  ~ (all_177_2_99 = 0) | all_177_0_97 = all_0_3_3
% 66.77/29.02  																									|
% 66.77/29.02  																									| Instantiating (630) with all_179_0_100, all_179_1_101, all_179_2_102, all_179_3_103, all_179_4_104, all_179_5_105, all_179_6_106, all_179_7_107, all_179_8_108 yields:
% 66.77/29.02  																									| (715) isPrime0(xp) = all_179_5_105 & doDivides0(xp, all_20_2_23) = all_179_0_100 & doDivides0(xp, xp) = all_179_1_101 & iLess0(all_179_3_103, all_0_4_4) = all_179_2_102 & sdtpldt0(all_179_4_104, xp) = all_179_3_103 & sdtpldt0(xp, all_20_2_23) = all_179_4_104 & aNaturalNumber0(all_20_2_23) = all_179_7_107 & aNaturalNumber0(xp) = all_179_6_106 & aNaturalNumber0(xp) = all_179_8_108 & ( ~ (all_179_2_102 = 0) |  ~ (all_179_5_105 = 0) |  ~ (all_179_6_106 = 0) |  ~ (all_179_7_107 = 0) |  ~ (all_179_8_108 = 0) | all_179_0_100 = 0 | all_179_1_101 = 0)
% 66.77/29.02  																									|
% 66.77/29.02  																									| Applying alpha-rule on (715) yields:
% 66.77/29.02  																									| (716)  ~ (all_179_2_102 = 0) |  ~ (all_179_5_105 = 0) |  ~ (all_179_6_106 = 0) |  ~ (all_179_7_107 = 0) |  ~ (all_179_8_108 = 0) | all_179_0_100 = 0 | all_179_1_101 = 0
% 66.77/29.02  																									| (717) doDivides0(xp, all_20_2_23) = all_179_0_100
% 66.77/29.02  																									| (718) iLess0(all_179_3_103, all_0_4_4) = all_179_2_102
% 66.77/29.02  																									| (719) aNaturalNumber0(xp) = all_179_8_108
% 66.77/29.02  																									| (720) aNaturalNumber0(xp) = all_179_6_106
% 66.77/29.02  																									| (721) isPrime0(xp) = all_179_5_105
% 66.77/29.02  																									| (722) doDivides0(xp, xp) = all_179_1_101
% 66.77/29.02  																									| (723) aNaturalNumber0(all_20_2_23) = all_179_7_107
% 66.77/29.02  																									| (724) sdtpldt0(xp, all_20_2_23) = all_179_4_104
% 66.77/29.02  																									| (725) sdtpldt0(all_179_4_104, xp) = all_179_3_103
% 66.77/29.02  																									|
% 66.77/29.02  																									| Instantiating (635) with all_182_0_112, all_182_1_113, all_182_2_114, all_182_3_115, all_182_4_116 yields:
% 66.77/29.02  																									| (726) doDivides0(all_58_0_58, all_19_2_20) = all_182_0_112 & doDivides0(all_58_0_58, xm) = all_182_1_113 & aNaturalNumber0(all_58_0_58) = all_182_4_116 & aNaturalNumber0(all_19_2_20) = all_182_2_114 & aNaturalNumber0(xm) = all_182_3_115 & ( ~ (all_182_1_113 = 0) |  ~ (all_182_2_114 = 0) |  ~ (all_182_3_115 = 0) |  ~ (all_182_4_116 = 0) | all_182_0_112 = 0)
% 66.77/29.02  																									|
% 66.77/29.02  																									| Applying alpha-rule on (726) yields:
% 66.77/29.02  																									| (727) aNaturalNumber0(all_19_2_20) = all_182_2_114
% 66.77/29.02  																									| (728) aNaturalNumber0(all_58_0_58) = all_182_4_116
% 66.77/29.02  																									| (729) aNaturalNumber0(xm) = all_182_3_115
% 66.77/29.02  																									| (730) doDivides0(all_58_0_58, xm) = all_182_1_113
% 66.77/29.02  																									| (731)  ~ (all_182_1_113 = 0) |  ~ (all_182_2_114 = 0) |  ~ (all_182_3_115 = 0) |  ~ (all_182_4_116 = 0) | all_182_0_112 = 0
% 66.77/29.02  																									| (732) doDivides0(all_58_0_58, all_19_2_20) = all_182_0_112
% 66.77/29.02  																									|
% 66.77/29.02  																									| Instantiating (633) with all_184_0_117, all_184_1_118, all_184_2_119, all_184_3_120, all_184_4_121, all_184_5_122, all_184_6_123, all_184_7_124, all_184_8_125 yields:
% 66.77/29.02  																									| (733) isPrime0(xp) = all_184_5_122 & doDivides0(xp, xm) = all_184_1_118 & doDivides0(xp, xn) = all_184_0_117 & iLess0(all_184_3_120, all_0_4_4) = all_184_2_119 & sdtpldt0(all_184_4_121, xp) = all_184_3_120 & sdtpldt0(xm, xn) = all_184_4_121 & aNaturalNumber0(xp) = all_184_6_123 & aNaturalNumber0(xm) = all_184_8_125 & aNaturalNumber0(xn) = all_184_7_124 & ( ~ (all_184_2_119 = 0) |  ~ (all_184_5_122 = 0) |  ~ (all_184_6_123 = 0) |  ~ (all_184_7_124 = 0) |  ~ (all_184_8_125 = 0) | all_184_0_117 = 0 | all_184_1_118 = 0)
% 66.77/29.02  																									|
% 66.77/29.02  																									| Applying alpha-rule on (733) yields:
% 66.77/29.02  																									| (734) doDivides0(xp, xn) = all_184_0_117
% 66.77/29.02  																									| (735) aNaturalNumber0(xm) = all_184_8_125
% 66.77/29.02  																									| (736) sdtpldt0(all_184_4_121, xp) = all_184_3_120
% 66.77/29.02  																									| (737) aNaturalNumber0(xp) = all_184_6_123
% 66.77/29.02  																									| (738)  ~ (all_184_2_119 = 0) |  ~ (all_184_5_122 = 0) |  ~ (all_184_6_123 = 0) |  ~ (all_184_7_124 = 0) |  ~ (all_184_8_125 = 0) | all_184_0_117 = 0 | all_184_1_118 = 0
% 66.77/29.02  																									| (739) isPrime0(xp) = all_184_5_122
% 66.77/29.02  																									| (740) doDivides0(xp, xm) = all_184_1_118
% 66.77/29.02  																									| (741) aNaturalNumber0(xn) = all_184_7_124
% 66.77/29.02  																									| (742) iLess0(all_184_3_120, all_0_4_4) = all_184_2_119
% 66.77/29.02  																									| (743) sdtpldt0(xm, xn) = all_184_4_121
% 66.77/29.02  																									|
% 66.77/29.02  																									| Instantiating (621) with all_186_0_126, all_186_1_127, all_186_2_128 yields:
% 66.77/29.02  																									| (744) (all_186_0_126 = xp & all_186_1_127 = 0 & sdtasdt0(all_58_0_58, all_186_2_128) = xp & aNaturalNumber0(all_186_2_128) = 0) | (aNaturalNumber0(all_58_0_58) = all_186_2_128 & aNaturalNumber0(xp) = all_186_1_127 & ( ~ (all_186_1_127 = 0) |  ~ (all_186_2_128 = 0)))
% 66.77/29.02  																									|
% 66.77/29.02  																									+-Applying beta-rule and splitting (623), into two cases.
% 66.77/29.02  																									|-Branch one:
% 66.77/29.02  																									| (177) xr = sz00
% 66.77/29.02  																									|
% 66.77/29.02  																										| Equations (177) can reduce 85 to:
% 66.77/29.02  																										| (159) $false
% 66.77/29.02  																										|
% 66.77/29.02  																										|-The branch is then unsatisfiable
% 66.77/29.02  																									|-Branch two:
% 66.77/29.02  																									| (85)  ~ (xr = sz00)
% 66.77/29.02  																									| (748)  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(all_53_0_57, xr) = v2 & aNaturalNumber0(all_53_0_57) = v0 & aNaturalNumber0(xr) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.77/29.02  																									|
% 66.77/29.02  																										| Instantiating (748) with all_191_0_129, all_191_1_130, all_191_2_131 yields:
% 66.77/29.02  																										| (749) sdtlseqdt0(all_53_0_57, xr) = all_191_0_129 & aNaturalNumber0(all_53_0_57) = all_191_2_131 & aNaturalNumber0(xr) = all_191_1_130 & ( ~ (all_191_1_130 = 0) |  ~ (all_191_2_131 = 0) | all_191_0_129 = 0)
% 66.77/29.02  																										|
% 66.77/29.02  																										| Applying alpha-rule on (749) yields:
% 66.77/29.02  																										| (750) sdtlseqdt0(all_53_0_57, xr) = all_191_0_129
% 66.77/29.02  																										| (751) aNaturalNumber0(all_53_0_57) = all_191_2_131
% 66.77/29.02  																										| (752) aNaturalNumber0(xr) = all_191_1_130
% 66.77/29.02  																										| (753)  ~ (all_191_1_130 = 0) |  ~ (all_191_2_131 = 0) | all_191_0_129 = 0
% 66.77/29.02  																										|
% 66.77/29.02  																										+-Applying beta-rule and splitting (648), into two cases.
% 66.77/29.02  																										|-Branch one:
% 66.77/29.02  																										| (754) all_58_0_58 = sz00
% 66.77/29.03  																										|
% 66.77/29.03  																											| Equations (754) can reduce 202 to:
% 66.77/29.03  																											| (159) $false
% 66.77/29.03  																											|
% 66.77/29.03  																											|-The branch is then unsatisfiable
% 66.77/29.03  																										|-Branch two:
% 66.77/29.03  																										| (202)  ~ (all_58_0_58 = sz00)
% 66.77/29.03  																										| (757) all_58_0_58 = sz10 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, all_58_0_58) = 0 & aNaturalNumber0(v0) = 0)
% 66.77/29.03  																										|
% 66.77/29.03  																											+-Applying beta-rule and splitting (649), into two cases.
% 66.77/29.03  																											|-Branch one:
% 66.77/29.03  																											| (758) all_53_0_57 = sz00
% 66.77/29.03  																											|
% 66.77/29.03  																												| Equations (758) can reduce 204 to:
% 66.77/29.03  																												| (159) $false
% 66.77/29.03  																												|
% 66.77/29.03  																												|-The branch is then unsatisfiable
% 66.77/29.03  																											|-Branch two:
% 66.77/29.03  																											| (204)  ~ (all_53_0_57 = sz00)
% 66.77/29.03  																											| (761) all_53_0_57 = sz10 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, all_53_0_57) = 0 & aNaturalNumber0(v0) = 0)
% 66.77/29.03  																											|
% 66.77/29.03  																												+-Applying beta-rule and splitting (620), into two cases.
% 66.77/29.03  																												|-Branch one:
% 66.77/29.03  																												| (181) xp = sz00
% 66.77/29.03  																												|
% 66.77/29.03  																													| Equations (181) can reduce 86 to:
% 66.77/29.03  																													| (159) $false
% 66.77/29.03  																													|
% 66.77/29.03  																													|-The branch is then unsatisfiable
% 66.77/29.03  																												|-Branch two:
% 66.77/29.03  																												| (86)  ~ (xp = sz00)
% 66.77/29.03  																												| (765)  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(all_58_0_58, xp) = v2 & aNaturalNumber0(all_58_0_58) = v0 & aNaturalNumber0(xp) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.77/29.03  																												|
% 66.77/29.03  																													| Instantiating (765) with all_203_0_132, all_203_1_133, all_203_2_134 yields:
% 66.77/29.03  																													| (766) sdtlseqdt0(all_58_0_58, xp) = all_203_0_132 & aNaturalNumber0(all_58_0_58) = all_203_2_134 & aNaturalNumber0(xp) = all_203_1_133 & ( ~ (all_203_1_133 = 0) |  ~ (all_203_2_134 = 0) | all_203_0_132 = 0)
% 66.77/29.03  																													|
% 66.77/29.03  																													| Applying alpha-rule on (766) yields:
% 66.77/29.03  																													| (767) sdtlseqdt0(all_58_0_58, xp) = all_203_0_132
% 66.77/29.03  																													| (768) aNaturalNumber0(all_58_0_58) = all_203_2_134
% 66.77/29.03  																													| (769) aNaturalNumber0(xp) = all_203_1_133
% 66.77/29.03  																													| (770)  ~ (all_203_1_133 = 0) |  ~ (all_203_2_134 = 0) | all_203_0_132 = 0
% 66.77/29.03  																													|
% 66.77/29.03  																													+-Applying beta-rule and splitting (757), into two cases.
% 66.77/29.03  																													|-Branch one:
% 66.77/29.03  																													| (771) all_58_0_58 = sz10
% 66.77/29.03  																													|
% 66.77/29.03  																														| Equations (771) can reduce 201 to:
% 66.77/29.03  																														| (159) $false
% 66.77/29.03  																														|
% 66.77/29.03  																														|-The branch is then unsatisfiable
% 66.77/29.03  																													|-Branch two:
% 66.77/29.03  																													| (201)  ~ (all_58_0_58 = sz10)
% 66.77/29.03  																													| (774)  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, all_58_0_58) = 0 & aNaturalNumber0(v0) = 0)
% 66.77/29.03  																													|
% 66.77/29.03  																														| Instantiating (774) with all_208_0_135 yields:
% 66.77/29.03  																														| (775) isPrime0(all_208_0_135) = 0 & doDivides0(all_208_0_135, all_58_0_58) = 0 & aNaturalNumber0(all_208_0_135) = 0
% 66.77/29.03  																														|
% 66.77/29.03  																														| Applying alpha-rule on (775) yields:
% 66.77/29.03  																														| (776) isPrime0(all_208_0_135) = 0
% 66.77/29.03  																														| (777) doDivides0(all_208_0_135, all_58_0_58) = 0
% 66.77/29.03  																														| (778) aNaturalNumber0(all_208_0_135) = 0
% 66.77/29.03  																														|
% 66.77/29.03  																														+-Applying beta-rule and splitting (761), into two cases.
% 66.77/29.03  																														|-Branch one:
% 66.77/29.03  																														| (779) all_53_0_57 = sz10
% 66.77/29.03  																														|
% 66.77/29.03  																															| Equations (779) can reduce 203 to:
% 66.77/29.03  																															| (159) $false
% 66.77/29.03  																															|
% 66.77/29.03  																															|-The branch is then unsatisfiable
% 66.77/29.03  																														|-Branch two:
% 66.77/29.03  																														| (203)  ~ (all_53_0_57 = sz10)
% 66.77/29.03  																														| (782)  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, all_53_0_57) = 0 & aNaturalNumber0(v0) = 0)
% 66.77/29.03  																														|
% 66.77/29.03  																															| Instantiating formula (32) with xp, xn, all_159_1_63, all_30_1_42 and discharging atoms doDivides0(xp, xn) = all_30_1_42, yields:
% 66.77/29.03  																															| (783) all_159_1_63 = all_30_1_42 |  ~ (doDivides0(xp, xn) = all_159_1_63)
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (32) with xp, xp, all_179_1_101, 0 and discharging atoms doDivides0(xp, xp) = all_179_1_101, yields:
% 66.77/29.03  																															| (784) all_179_1_101 = 0 |  ~ (doDivides0(xp, xp) = 0)
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (32) with xp, xm, all_184_1_118, all_30_0_41 and discharging atoms doDivides0(xp, xm) = all_184_1_118, doDivides0(xp, xm) = all_30_0_41, yields:
% 66.77/29.03  																															| (785) all_184_1_118 = all_30_0_41
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (32) with xp, xm, all_184_1_118, all_182_1_113 and discharging atoms doDivides0(xp, xm) = all_184_1_118, yields:
% 66.77/29.03  																															| (786) all_184_1_118 = all_182_1_113 |  ~ (doDivides0(xp, xm) = all_182_1_113)
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_58_0_58, all_182_4_116, 0 and discharging atoms aNaturalNumber0(all_58_0_58) = all_182_4_116, aNaturalNumber0(all_58_0_58) = 0, yields:
% 66.77/29.03  																															| (787) all_182_4_116 = 0
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_58_0_58, all_182_4_116, all_203_2_134 and discharging atoms aNaturalNumber0(all_58_0_58) = all_203_2_134, aNaturalNumber0(all_58_0_58) = all_182_4_116, yields:
% 66.77/29.03  																															| (788) all_203_2_134 = all_182_4_116
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_58_0_58, all_159_4_66, all_203_2_134 and discharging atoms aNaturalNumber0(all_58_0_58) = all_203_2_134, aNaturalNumber0(all_58_0_58) = all_159_4_66, yields:
% 66.77/29.03  																															| (789) all_203_2_134 = all_159_4_66
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_53_0_57, all_191_2_131, 0 and discharging atoms aNaturalNumber0(all_53_0_57) = all_191_2_131, aNaturalNumber0(all_53_0_57) = 0, yields:
% 66.77/29.03  																															| (790) all_191_2_131 = 0
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_24_1_31, all_163_0_72, all_167_1_79 and discharging atoms aNaturalNumber0(all_24_1_31) = all_167_1_79, aNaturalNumber0(all_24_1_31) = all_163_0_72, yields:
% 66.77/29.03  																															| (791) all_167_1_79 = all_163_0_72
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_20_2_23, all_179_7_107, 0 and discharging atoms aNaturalNumber0(all_20_2_23) = all_179_7_107, aNaturalNumber0(all_20_2_23) = 0, yields:
% 66.77/29.03  																															| (792) all_179_7_107 = 0
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_20_2_23, all_177_1_98, all_179_7_107 and discharging atoms aNaturalNumber0(all_20_2_23) = all_179_7_107, aNaturalNumber0(all_20_2_23) = all_177_1_98, yields:
% 66.77/29.03  																															| (793) all_179_7_107 = all_177_1_98
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_19_2_20, all_182_2_114, 0 and discharging atoms aNaturalNumber0(all_19_2_20) = all_182_2_114, aNaturalNumber0(all_19_2_20) = 0, yields:
% 66.77/29.03  																															| (794) all_182_2_114 = 0
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xk, all_182_2_114, all_36_2_52 and discharging atoms aNaturalNumber0(xk) = all_36_2_52, yields:
% 66.77/29.03  																															| (795) all_182_2_114 = all_36_2_52 |  ~ (aNaturalNumber0(xk) = all_182_2_114)
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_19_2_20, all_175_3_95, all_182_2_114 and discharging atoms aNaturalNumber0(all_19_2_20) = all_182_2_114, aNaturalNumber0(all_19_2_20) = all_175_3_95, yields:
% 66.77/29.03  																															| (796) all_182_2_114 = all_175_3_95
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_19_2_20, all_173_1_90, all_175_3_95 and discharging atoms aNaturalNumber0(all_19_2_20) = all_175_3_95, aNaturalNumber0(all_19_2_20) = all_173_1_90, yields:
% 66.77/29.03  																															| (797) all_175_3_95 = all_173_1_90
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_18_2_17, all_169_3_84, 0 and discharging atoms aNaturalNumber0(all_18_2_17) = all_169_3_84, aNaturalNumber0(all_18_2_17) = 0, yields:
% 66.77/29.03  																															| (798) all_169_3_84 = 0
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_18_2_17, all_159_2_64, all_169_3_84 and discharging atoms aNaturalNumber0(all_18_2_17) = all_169_3_84, aNaturalNumber0(all_18_2_17) = all_159_2_64, yields:
% 66.77/29.03  																															| (799) all_169_3_84 = all_159_2_64
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_18_2_17, all_157_1_60, all_159_2_64 and discharging atoms aNaturalNumber0(all_18_2_17) = all_159_2_64, aNaturalNumber0(all_18_2_17) = all_157_1_60, yields:
% 66.77/29.03  																															| (800) all_159_2_64 = all_157_1_60
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_0_4_4, all_165_0_75, 0 and discharging atoms aNaturalNumber0(all_0_4_4) = all_165_0_75, aNaturalNumber0(all_0_4_4) = 0, yields:
% 66.77/29.03  																															| (801) all_165_0_75 = 0
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_0_5_5, all_175_2_94, 0 and discharging atoms aNaturalNumber0(all_0_5_5) = all_175_2_94, aNaturalNumber0(all_0_5_5) = 0, yields:
% 66.77/29.03  																															| (802) all_175_2_94 = 0
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with all_0_5_5, all_169_2_83, all_175_2_94 and discharging atoms aNaturalNumber0(all_0_5_5) = all_175_2_94, aNaturalNumber0(all_0_5_5) = all_169_2_83, yields:
% 66.77/29.03  																															| (803) all_175_2_94 = all_169_2_83
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xr, all_191_1_130, 0 and discharging atoms aNaturalNumber0(xr) = all_191_1_130, aNaturalNumber0(xr) = 0, yields:
% 66.77/29.03  																															| (804) all_191_1_130 = 0
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xp, all_184_6_123, all_203_1_133 and discharging atoms aNaturalNumber0(xp) = all_203_1_133, aNaturalNumber0(xp) = all_184_6_123, yields:
% 66.77/29.03  																															| (805) all_203_1_133 = all_184_6_123
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xp, all_179_8_108, all_179_6_106 and discharging atoms aNaturalNumber0(xp) = all_179_6_106, aNaturalNumber0(xp) = all_179_8_108, yields:
% 66.77/29.03  																															| (806) all_179_6_106 = all_179_8_108
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xp, all_177_2_99, all_179_8_108 and discharging atoms aNaturalNumber0(xp) = all_179_8_108, aNaturalNumber0(xp) = all_177_2_99, yields:
% 66.77/29.03  																															| (807) all_179_8_108 = all_177_2_99
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xp, all_171_1_87, 0 and discharging atoms aNaturalNumber0(xp) = all_171_1_87, aNaturalNumber0(xp) = 0, yields:
% 66.77/29.03  																															| (808) all_171_1_87 = 0
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xp, all_171_1_87, all_203_1_133 and discharging atoms aNaturalNumber0(xp) = all_203_1_133, aNaturalNumber0(xp) = all_171_1_87, yields:
% 66.77/29.03  																															| (809) all_203_1_133 = all_171_1_87
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xp, all_171_1_87, all_177_2_99 and discharging atoms aNaturalNumber0(xp) = all_177_2_99, aNaturalNumber0(xp) = all_171_1_87, yields:
% 66.77/29.03  																															| (810) all_177_2_99 = all_171_1_87
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xp, all_163_1_73, all_203_1_133 and discharging atoms aNaturalNumber0(xp) = all_203_1_133, aNaturalNumber0(xp) = all_163_1_73, yields:
% 66.77/29.03  																															| (811) all_203_1_133 = all_163_1_73
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xp, all_161_2_69, all_179_6_106 and discharging atoms aNaturalNumber0(xp) = all_179_6_106, aNaturalNumber0(xp) = all_161_2_69, yields:
% 66.77/29.03  																															| (812) all_179_6_106 = all_161_2_69
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xm, all_182_3_115, all_184_8_125 and discharging atoms aNaturalNumber0(xm) = all_184_8_125, aNaturalNumber0(xm) = all_182_3_115, yields:
% 66.77/29.03  																															| (813) all_184_8_125 = all_182_3_115
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xm, all_175_4_96, all_182_3_115 and discharging atoms aNaturalNumber0(xm) = all_182_3_115, aNaturalNumber0(xm) = all_175_4_96, yields:
% 66.77/29.03  																															| (814) all_182_3_115 = all_175_4_96
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xm, all_173_2_91, 0 and discharging atoms aNaturalNumber0(xm) = all_173_2_91, aNaturalNumber0(xm) = 0, yields:
% 66.77/29.03  																															| (815) all_173_2_91 = 0
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xm, all_173_2_91, all_182_3_115 and discharging atoms aNaturalNumber0(xm) = all_182_3_115, aNaturalNumber0(xm) = all_173_2_91, yields:
% 66.77/29.03  																															| (816) all_182_3_115 = all_173_2_91
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xm, all_171_2_88, all_184_8_125 and discharging atoms aNaturalNumber0(xm) = all_184_8_125, aNaturalNumber0(xm) = all_171_2_88, yields:
% 66.77/29.03  																															| (817) all_184_8_125 = all_171_2_88
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xm, all_163_2_74, all_182_3_115 and discharging atoms aNaturalNumber0(xm) = all_182_3_115, aNaturalNumber0(xm) = all_163_2_74, yields:
% 66.77/29.03  																															| (818) all_182_3_115 = all_163_2_74
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xm, all_161_4_71, all_175_4_96 and discharging atoms aNaturalNumber0(xm) = all_175_4_96, aNaturalNumber0(xm) = all_161_4_71, yields:
% 66.77/29.03  																															| (819) all_175_4_96 = all_161_4_71
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xn, all_169_4_85, all_184_7_124 and discharging atoms aNaturalNumber0(xn) = all_184_7_124, aNaturalNumber0(xn) = all_169_4_85, yields:
% 66.77/29.03  																															| (820) all_184_7_124 = all_169_4_85
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xn, all_167_2_80, all_184_7_124 and discharging atoms aNaturalNumber0(xn) = all_184_7_124, aNaturalNumber0(xn) = all_167_2_80, yields:
% 66.77/29.03  																															| (821) all_184_7_124 = all_167_2_80
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xn, all_165_2_77, 0 and discharging atoms aNaturalNumber0(xn) = all_165_2_77, aNaturalNumber0(xn) = 0, yields:
% 66.77/29.03  																															| (822) all_165_2_77 = 0
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xn, all_161_3_70, all_169_4_85 and discharging atoms aNaturalNumber0(xn) = all_169_4_85, aNaturalNumber0(xn) = all_161_3_70, yields:
% 66.77/29.03  																															| (823) all_169_4_85 = all_161_3_70
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xn, all_161_3_70, all_165_2_77 and discharging atoms aNaturalNumber0(xn) = all_165_2_77, aNaturalNumber0(xn) = all_161_3_70, yields:
% 66.77/29.03  																															| (824) all_165_2_77 = all_161_3_70
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xn, all_159_3_65, all_169_4_85 and discharging atoms aNaturalNumber0(xn) = all_169_4_85, aNaturalNumber0(xn) = all_159_3_65, yields:
% 66.77/29.03  																															| (825) all_169_4_85 = all_159_3_65
% 66.77/29.03  																															|
% 66.77/29.03  																															| Instantiating formula (46) with xn, all_157_2_61, all_161_3_70 and discharging atoms aNaturalNumber0(xn) = all_161_3_70, aNaturalNumber0(xn) = all_157_2_61, yields:
% 66.77/29.03  																															| (826) all_161_3_70 = all_157_2_61
% 66.77/29.03  																															|
% 66.77/29.03  																															| Combining equations (811,805) yields a new equation:
% 66.77/29.03  																															| (827) all_184_6_123 = all_163_1_73
% 66.77/29.03  																															|
% 66.77/29.03  																															| Combining equations (809,805) yields a new equation:
% 66.77/29.04  																															| (828) all_184_6_123 = all_171_1_87
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (788,789) yields a new equation:
% 66.77/29.04  																															| (829) all_182_4_116 = all_159_4_66
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 829 yields:
% 66.77/29.04  																															| (830) all_182_4_116 = all_159_4_66
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (828,827) yields a new equation:
% 66.77/29.04  																															| (831) all_171_1_87 = all_163_1_73
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 831 yields:
% 66.77/29.04  																															| (832) all_171_1_87 = all_163_1_73
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (820,821) yields a new equation:
% 66.77/29.04  																															| (833) all_169_4_85 = all_167_2_80
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 833 yields:
% 66.77/29.04  																															| (834) all_169_4_85 = all_167_2_80
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (813,817) yields a new equation:
% 66.77/29.04  																															| (835) all_182_3_115 = all_171_2_88
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 835 yields:
% 66.77/29.04  																															| (836) all_182_3_115 = all_171_2_88
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (796,794) yields a new equation:
% 66.77/29.04  																															| (837) all_175_3_95 = 0
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 837 yields:
% 66.77/29.04  																															| (838) all_175_3_95 = 0
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (818,836) yields a new equation:
% 66.77/29.04  																															| (839) all_171_2_88 = all_163_2_74
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (816,836) yields a new equation:
% 66.77/29.04  																															| (840) all_173_2_91 = all_171_2_88
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 840 yields:
% 66.77/29.04  																															| (841) all_173_2_91 = all_171_2_88
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (814,836) yields a new equation:
% 66.77/29.04  																															| (842) all_175_4_96 = all_171_2_88
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 842 yields:
% 66.77/29.04  																															| (843) all_175_4_96 = all_171_2_88
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (787,830) yields a new equation:
% 66.77/29.04  																															| (844) all_159_4_66 = 0
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (806,812) yields a new equation:
% 66.77/29.04  																															| (845) all_179_8_108 = all_161_2_69
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 845 yields:
% 66.77/29.04  																															| (846) all_179_8_108 = all_161_2_69
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (793,792) yields a new equation:
% 66.77/29.04  																															| (847) all_177_1_98 = 0
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 847 yields:
% 66.77/29.04  																															| (848) all_177_1_98 = 0
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (807,846) yields a new equation:
% 66.77/29.04  																															| (849) all_177_2_99 = all_161_2_69
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 849 yields:
% 66.77/29.04  																															| (850) all_177_2_99 = all_161_2_69
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (810,850) yields a new equation:
% 66.77/29.04  																															| (851) all_171_1_87 = all_161_2_69
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 851 yields:
% 66.77/29.04  																															| (852) all_171_1_87 = all_161_2_69
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (802,803) yields a new equation:
% 66.77/29.04  																															| (853) all_169_2_83 = 0
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (797,838) yields a new equation:
% 66.77/29.04  																															| (854) all_173_1_90 = 0
% 66.77/29.04  																															|
% 66.77/29.04  																															| Simplifying 854 yields:
% 66.77/29.04  																															| (855) all_173_1_90 = 0
% 66.77/29.04  																															|
% 66.77/29.04  																															| Combining equations (843,819) yields a new equation:
% 66.93/29.04  																															| (856) all_171_2_88 = all_161_4_71
% 66.93/29.04  																															|
% 66.93/29.04  																															| Simplifying 856 yields:
% 66.93/29.04  																															| (857) all_171_2_88 = all_161_4_71
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (841,815) yields a new equation:
% 66.93/29.04  																															| (858) all_171_2_88 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Simplifying 858 yields:
% 66.93/29.04  																															| (859) all_171_2_88 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (852,832) yields a new equation:
% 66.93/29.04  																															| (860) all_163_1_73 = all_161_2_69
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (808,832) yields a new equation:
% 66.93/29.04  																															| (861) all_163_1_73 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (859,839) yields a new equation:
% 66.93/29.04  																															| (862) all_163_2_74 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (857,839) yields a new equation:
% 66.93/29.04  																															| (863) all_163_2_74 = all_161_4_71
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (799,798) yields a new equation:
% 66.93/29.04  																															| (864) all_159_2_64 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Simplifying 864 yields:
% 66.93/29.04  																															| (865) all_159_2_64 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (825,834) yields a new equation:
% 66.93/29.04  																															| (866) all_167_2_80 = all_159_3_65
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (823,834) yields a new equation:
% 66.93/29.04  																															| (867) all_167_2_80 = all_161_3_70
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (867,866) yields a new equation:
% 66.93/29.04  																															| (868) all_161_3_70 = all_159_3_65
% 66.93/29.04  																															|
% 66.93/29.04  																															| Simplifying 868 yields:
% 66.93/29.04  																															| (869) all_161_3_70 = all_159_3_65
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (824,822) yields a new equation:
% 66.93/29.04  																															| (870) all_161_3_70 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Simplifying 870 yields:
% 66.93/29.04  																															| (871) all_161_3_70 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (861,860) yields a new equation:
% 66.93/29.04  																															| (872) all_161_2_69 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (863,862) yields a new equation:
% 66.93/29.04  																															| (873) all_161_4_71 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Simplifying 873 yields:
% 66.93/29.04  																															| (874) all_161_4_71 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (826,869) yields a new equation:
% 66.93/29.04  																															| (875) all_159_3_65 = all_157_2_61
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (871,869) yields a new equation:
% 66.93/29.04  																															| (876) all_159_3_65 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (800,865) yields a new equation:
% 66.93/29.04  																															| (877) all_157_1_60 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Simplifying 877 yields:
% 66.93/29.04  																															| (878) all_157_1_60 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (875,876) yields a new equation:
% 66.93/29.04  																															| (879) all_157_2_61 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Simplifying 879 yields:
% 66.93/29.04  																															| (880) all_157_2_61 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (872,860) yields a new equation:
% 66.93/29.04  																															| (861) all_163_1_73 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (876,866) yields a new equation:
% 66.93/29.04  																															| (882) all_167_2_80 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| Combining equations (872,850) yields a new equation:
% 66.93/29.04  																															| (883) all_177_2_99 = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| From (844) and (663) follows:
% 66.93/29.04  																															| (200) aNaturalNumber0(all_58_0_58) = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| From (790) and (751) follows:
% 66.93/29.04  																															| (192) aNaturalNumber0(all_53_0_57) = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| From (848) and (712) follows:
% 66.93/29.04  																															| (561) aNaturalNumber0(all_20_2_23) = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| From (801) and (678) follows:
% 66.93/29.04  																															| (595) aNaturalNumber0(all_0_4_4) = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| From (853) and (691) follows:
% 66.93/29.04  																															| (573) aNaturalNumber0(all_0_5_5) = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| From (804) and (752) follows:
% 66.93/29.04  																															| (10) aNaturalNumber0(xr) = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| From (872) and (667) follows:
% 66.93/29.04  																															| (12) aNaturalNumber0(xp) = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| From (874) and (668) follows:
% 66.93/29.04  																															| (36) aNaturalNumber0(xm) = 0
% 66.93/29.04  																															|
% 66.93/29.04  																															| From (880) and (655) follows:
% 66.93/29.05  																															| (53) aNaturalNumber0(xn) = 0
% 66.93/29.05  																															|
% 66.93/29.05  																															+-Applying beta-rule and splitting (714), into two cases.
% 66.93/29.05  																															|-Branch one:
% 66.93/29.05  																															| (893)  ~ (all_177_1_98 = 0)
% 66.93/29.05  																															|
% 66.93/29.05  																																| Equations (848) can reduce 893 to:
% 66.93/29.05  																																| (159) $false
% 66.93/29.05  																																|
% 66.93/29.05  																																|-The branch is then unsatisfiable
% 66.93/29.05  																															|-Branch two:
% 66.93/29.05  																															| (848) all_177_1_98 = 0
% 66.93/29.05  																															| (896)  ~ (all_177_2_99 = 0) | all_177_0_97 = all_0_3_3
% 66.93/29.05  																															|
% 66.93/29.05  																																+-Applying beta-rule and splitting (642), into two cases.
% 66.93/29.05  																																|-Branch one:
% 66.93/29.05  																																| (897) xp = xn
% 66.93/29.05  																																|
% 66.93/29.05  																																	| Equations (897) can reduce 74 to:
% 66.93/29.05  																																	| (159) $false
% 66.93/29.05  																																	|
% 66.93/29.05  																																	|-The branch is then unsatisfiable
% 66.93/29.05  																																|-Branch two:
% 66.93/29.05  																																| (74)  ~ (xp = xn)
% 66.93/29.05  																																| (900)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(xp, xm) = v4 & sdtpldt0(xn, xm) = v3 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xm) = v0 & aNaturalNumber0(xn) = v1 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | ( ~ (v4 = v3) &  ~ (all_24_1_31 = all_0_5_5))))
% 66.93/29.05  																																|
% 66.93/29.05  																																	| Instantiating (900) with all_227_0_137, all_227_1_138, all_227_2_139, all_227_3_140, all_227_4_141 yields:
% 66.93/29.05  																																	| (901) sdtpldt0(xp, xm) = all_227_0_137 & sdtpldt0(xn, xm) = all_227_1_138 & aNaturalNumber0(xp) = all_227_2_139 & aNaturalNumber0(xm) = all_227_4_141 & aNaturalNumber0(xn) = all_227_3_140 & ( ~ (all_227_2_139 = 0) |  ~ (all_227_3_140 = 0) |  ~ (all_227_4_141 = 0) | ( ~ (all_227_0_137 = all_227_1_138) &  ~ (all_24_1_31 = all_0_5_5)))
% 66.93/29.05  																																	|
% 66.93/29.05  																																	| Applying alpha-rule on (901) yields:
% 66.93/29.05  																																	| (902) aNaturalNumber0(xn) = all_227_3_140
% 66.93/29.05  																																	| (903)  ~ (all_227_2_139 = 0) |  ~ (all_227_3_140 = 0) |  ~ (all_227_4_141 = 0) | ( ~ (all_227_0_137 = all_227_1_138) &  ~ (all_24_1_31 = all_0_5_5))
% 66.93/29.05  																																	| (904) sdtpldt0(xn, xm) = all_227_1_138
% 66.93/29.05  																																	| (905) sdtpldt0(xp, xm) = all_227_0_137
% 66.93/29.05  																																	| (906) aNaturalNumber0(xp) = all_227_2_139
% 66.93/29.05  																																	| (907) aNaturalNumber0(xm) = all_227_4_141
% 66.93/29.05  																																	|
% 66.93/29.05  																																	+-Applying beta-rule and splitting (622), into two cases.
% 66.93/29.05  																																	|-Branch one:
% 66.93/29.05  																																	| (908) all_53_0_57 = xr
% 66.93/29.05  																																	|
% 66.93/29.05  																																		| From (908) and (192) follows:
% 66.93/29.05  																																		| (10) aNaturalNumber0(xr) = 0
% 66.93/29.05  																																		|
% 66.93/29.05  																																		+-Applying beta-rule and splitting (702), into two cases.
% 66.93/29.05  																																		|-Branch one:
% 66.93/29.05  																																		| (910)  ~ (all_173_1_90 = 0)
% 66.93/29.05  																																		|
% 66.93/29.05  																																			| Equations (855) can reduce 910 to:
% 66.93/29.05  																																			| (159) $false
% 66.93/29.05  																																			|
% 66.93/29.05  																																			|-The branch is then unsatisfiable
% 66.93/29.05  																																		|-Branch two:
% 66.93/29.05  																																		| (855) all_173_1_90 = 0
% 66.93/29.05  																																		| (913)  ~ (all_173_2_91 = 0) | all_173_0_89 = xp
% 66.93/29.05  																																		|
% 66.93/29.05  																																			+-Applying beta-rule and splitting (656), into two cases.
% 66.93/29.05  																																			|-Branch one:
% 66.93/29.05  																																			| (914)  ~ (all_157_1_60 = 0)
% 66.93/29.05  																																			|
% 66.93/29.05  																																				| Equations (878) can reduce 914 to:
% 66.93/29.05  																																				| (159) $false
% 66.93/29.05  																																				|
% 66.93/29.05  																																				|-The branch is then unsatisfiable
% 66.93/29.05  																																			|-Branch two:
% 66.93/29.05  																																			| (878) all_157_1_60 = 0
% 66.93/29.05  																																			| (917)  ~ (all_157_2_61 = 0) | all_157_0_59 = xp
% 66.93/29.05  																																			|
% 66.93/29.05  																																				+-Applying beta-rule and splitting (913), into two cases.
% 66.93/29.05  																																				|-Branch one:
% 66.93/29.05  																																				| (918)  ~ (all_173_2_91 = 0)
% 66.93/29.05  																																				|
% 66.93/29.05  																																					| Equations (815) can reduce 918 to:
% 66.93/29.05  																																					| (159) $false
% 66.93/29.05  																																					|
% 66.93/29.05  																																					|-The branch is then unsatisfiable
% 66.93/29.05  																																				|-Branch two:
% 66.93/29.05  																																				| (815) all_173_2_91 = 0
% 66.93/29.05  																																				| (921) all_173_0_89 = xp
% 66.93/29.05  																																				|
% 66.93/29.05  																																					| From (921) and (699) follows:
% 66.93/29.05  																																					| (922) sdtpldt0(all_19_2_20, xm) = xp
% 66.93/29.05  																																					|
% 66.93/29.05  																																					+-Applying beta-rule and splitting (917), into two cases.
% 66.93/29.05  																																					|-Branch one:
% 66.93/29.05  																																					| (923)  ~ (all_157_2_61 = 0)
% 66.93/29.05  																																					|
% 66.93/29.05  																																						| Equations (880) can reduce 923 to:
% 66.93/29.05  																																						| (159) $false
% 66.93/29.05  																																						|
% 66.93/29.05  																																						|-The branch is then unsatisfiable
% 66.93/29.05  																																					|-Branch two:
% 66.93/29.05  																																					| (880) all_157_2_61 = 0
% 66.93/29.05  																																					| (926) all_157_0_59 = xp
% 66.93/29.05  																																					|
% 66.93/29.05  																																						| From (926) and (653) follows:
% 66.93/29.05  																																						| (927) sdtpldt0(all_18_2_17, xn) = xp
% 66.93/29.05  																																						|
% 66.93/29.05  																																						+-Applying beta-rule and splitting (896), into two cases.
% 66.93/29.05  																																						|-Branch one:
% 66.93/29.05  																																						| (928)  ~ (all_177_2_99 = 0)
% 66.93/29.05  																																						|
% 66.93/29.05  																																							| Equations (883) can reduce 928 to:
% 66.93/29.05  																																							| (159) $false
% 66.93/29.05  																																							|
% 66.93/29.05  																																							|-The branch is then unsatisfiable
% 66.93/29.05  																																						|-Branch two:
% 66.93/29.05  																																						| (883) all_177_2_99 = 0
% 66.93/29.05  																																						| (931) all_177_0_97 = all_0_3_3
% 66.93/29.05  																																						|
% 66.93/29.05  																																							| From (931) and (711) follows:
% 66.93/29.05  																																							| (932) sdtasdt0(all_20_2_23, xp) = all_0_3_3
% 66.93/29.05  																																							|
% 66.93/29.05  																																							+-Applying beta-rule and splitting (675), into two cases.
% 66.93/29.05  																																							|-Branch one:
% 66.93/29.05  																																							| (933)  ~ (all_163_1_73 = 0)
% 66.93/29.05  																																							|
% 66.93/29.05  																																								| Equations (861) can reduce 933 to:
% 66.93/29.05  																																								| (159) $false
% 66.93/29.05  																																								|
% 66.93/29.05  																																								|-The branch is then unsatisfiable
% 66.93/29.05  																																							|-Branch two:
% 66.93/29.05  																																							| (861) all_163_1_73 = 0
% 66.93/29.05  																																							| (936)  ~ (all_163_2_74 = 0) | all_163_0_72 = 0
% 66.93/29.05  																																							|
% 66.93/29.05  																																								+-Applying beta-rule and splitting (936), into two cases.
% 66.93/29.05  																																								|-Branch one:
% 66.93/29.05  																																								| (937)  ~ (all_163_2_74 = 0)
% 66.93/29.05  																																								|
% 66.93/29.05  																																									| Equations (862) can reduce 937 to:
% 66.93/29.05  																																									| (159) $false
% 66.93/29.05  																																									|
% 66.93/29.05  																																									|-The branch is then unsatisfiable
% 66.93/29.05  																																								|-Branch two:
% 66.93/29.05  																																								| (862) all_163_2_74 = 0
% 66.93/29.05  																																								| (940) all_163_0_72 = 0
% 66.93/29.05  																																								|
% 66.93/29.05  																																									| Combining equations (940,791) yields a new equation:
% 66.93/29.05  																																									| (941) all_167_1_79 = 0
% 66.93/29.05  																																									|
% 66.93/29.05  																																									+-Applying beta-rule and splitting (685), into two cases.
% 66.93/29.05  																																									|-Branch one:
% 66.93/29.05  																																									| (942)  ~ (all_167_1_79 = 0)
% 66.93/29.05  																																									|
% 66.93/29.05  																																										| Equations (941) can reduce 942 to:
% 66.93/29.05  																																										| (159) $false
% 66.93/29.05  																																										|
% 66.93/29.05  																																										|-The branch is then unsatisfiable
% 66.93/29.05  																																									|-Branch two:
% 66.93/29.05  																																									| (941) all_167_1_79 = 0
% 66.93/29.05  																																									| (945)  ~ (all_167_2_80 = 0) | all_167_0_78 = all_0_4_4
% 66.93/29.05  																																									|
% 66.93/29.05  																																										+-Applying beta-rule and splitting (945), into two cases.
% 66.93/29.05  																																										|-Branch one:
% 66.93/29.05  																																										| (946)  ~ (all_167_2_80 = 0)
% 66.93/29.05  																																										|
% 66.93/29.05  																																											| Equations (882) can reduce 946 to:
% 66.93/29.05  																																											| (159) $false
% 66.93/29.05  																																											|
% 66.93/29.05  																																											|-The branch is then unsatisfiable
% 66.93/29.05  																																										|-Branch two:
% 66.93/29.05  																																										| (882) all_167_2_80 = 0
% 66.93/29.05  																																										| (949) all_167_0_78 = all_0_4_4
% 66.93/29.05  																																										|
% 66.93/29.05  																																											| From (949) and (682) follows:
% 66.93/29.05  																																											| (950) sdtpldt0(all_24_1_31, xn) = all_0_4_4
% 66.93/29.05  																																											|
% 66.93/29.05  																																											| Instantiating formula (3) with xn, xm, all_227_1_138, all_0_5_5 and discharging atoms sdtpldt0(xn, xm) = all_227_1_138, sdtpldt0(xn, xm) = all_0_5_5, yields:
% 66.93/29.05  																																											| (951) all_227_1_138 = all_0_5_5
% 66.93/29.05  																																											|
% 66.93/29.05  																																											| Instantiating formula (46) with xp, all_227_2_139, 0 and discharging atoms aNaturalNumber0(xp) = all_227_2_139, aNaturalNumber0(xp) = 0, yields:
% 66.93/29.05  																																											| (952) all_227_2_139 = 0
% 66.93/29.05  																																											|
% 66.93/29.05  																																											| Instantiating formula (46) with xm, all_227_4_141, 0 and discharging atoms aNaturalNumber0(xm) = all_227_4_141, aNaturalNumber0(xm) = 0, yields:
% 66.93/29.05  																																											| (953) all_227_4_141 = 0
% 66.93/29.05  																																											|
% 66.93/29.05  																																											| Instantiating formula (46) with xn, all_227_3_140, 0 and discharging atoms aNaturalNumber0(xn) = all_227_3_140, aNaturalNumber0(xn) = 0, yields:
% 66.93/29.05  																																											| (954) all_227_3_140 = 0
% 66.93/29.05  																																											|
% 66.93/29.05  																																											| From (951) and (904) follows:
% 66.93/29.05  																																											| (73) sdtpldt0(xn, xm) = all_0_5_5
% 66.93/29.05  																																											|
% 66.93/29.05  																																											| From (952) and (906) follows:
% 66.93/29.05  																																											| (12) aNaturalNumber0(xp) = 0
% 66.93/29.05  																																											|
% 66.93/29.05  																																											| From (953) and (907) follows:
% 66.93/29.05  																																											| (36) aNaturalNumber0(xm) = 0
% 66.93/29.05  																																											|
% 66.93/29.05  																																											| From (954) and (902) follows:
% 66.93/29.05  																																											| (53) aNaturalNumber0(xn) = 0
% 66.93/29.05  																																											|
% 66.93/29.05  																																											+-Applying beta-rule and splitting (744), into two cases.
% 66.93/29.05  																																											|-Branch one:
% 66.93/29.05  																																											| (959) all_186_0_126 = xp & all_186_1_127 = 0 & sdtasdt0(all_58_0_58, all_186_2_128) = xp & aNaturalNumber0(all_186_2_128) = 0
% 66.93/29.05  																																											|
% 66.93/29.05  																																												| Applying alpha-rule on (959) yields:
% 66.93/29.05  																																												| (960) all_186_0_126 = xp
% 66.93/29.05  																																												| (961) all_186_1_127 = 0
% 66.93/29.05  																																												| (962) sdtasdt0(all_58_0_58, all_186_2_128) = xp
% 66.93/29.05  																																												| (963) aNaturalNumber0(all_186_2_128) = 0
% 66.93/29.05  																																												|
% 66.93/29.05  																																												+-Applying beta-rule and splitting (629), into two cases.
% 66.93/29.05  																																												|-Branch one:
% 66.93/29.05  																																												| (181) xp = sz00
% 66.93/29.05  																																												|
% 66.93/29.05  																																													| Equations (181) can reduce 86 to:
% 66.93/29.05  																																													| (159) $false
% 66.93/29.05  																																													|
% 66.93/29.05  																																													|-The branch is then unsatisfiable
% 66.93/29.05  																																												|-Branch two:
% 66.93/29.05  																																												| (86)  ~ (xp = sz00)
% 66.93/29.05  																																												| (967) all_20_2_23 = xk |  ? [v0] :  ? [v1] :  ? [v2] : (( ~ (v0 = 0) & aNaturalNumber0(all_20_2_23) = v0) | (doDivides0(xp, all_0_3_3) = v2 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0))))
% 66.93/29.05  																																												|
% 66.93/29.05  																																													+-Applying beta-rule and splitting (967), into two cases.
% 66.93/29.05  																																													|-Branch one:
% 66.93/29.05  																																													| (968) all_20_2_23 = xk
% 66.93/29.06  																																													|
% 66.93/29.06  																																														| From (968) and (932) follows:
% 66.93/29.06  																																														| (969) sdtasdt0(xk, xp) = all_0_3_3
% 66.93/29.06  																																														|
% 66.93/29.06  																																														| From (968) and (560) follows:
% 66.93/29.06  																																														| (970) sdtasdt0(xp, xk) = all_0_3_3
% 66.93/29.06  																																														|
% 66.93/29.06  																																														| From (968) and (724) follows:
% 66.93/29.06  																																														| (971) sdtpldt0(xp, xk) = all_179_4_104
% 66.93/29.06  																																														|
% 66.93/29.06  																																														| From (968) and (561) follows:
% 66.93/29.06  																																														| (972) aNaturalNumber0(xk) = 0
% 66.93/29.06  																																														|
% 66.93/29.06  																																														+-Applying beta-rule and splitting (795), into two cases.
% 66.93/29.06  																																														|-Branch one:
% 66.93/29.06  																																														| (973)  ~ (aNaturalNumber0(xk) = all_182_2_114)
% 66.93/29.06  																																														|
% 66.93/29.06  																																															| From (794) and (973) follows:
% 66.93/29.06  																																															| (974)  ~ (aNaturalNumber0(xk) = 0)
% 66.93/29.06  																																															|
% 66.93/29.06  																																															| Using (972) and (974) yields:
% 66.93/29.06  																																															| (615) $false
% 66.93/29.06  																																															|
% 66.93/29.06  																																															|-The branch is then unsatisfiable
% 66.93/29.06  																																														|-Branch two:
% 66.93/29.06  																																														| (976) aNaturalNumber0(xk) = all_182_2_114
% 66.93/29.06  																																														| (977) all_182_2_114 = all_36_2_52
% 66.93/29.06  																																														|
% 66.93/29.06  																																															| Combining equations (977,794) yields a new equation:
% 66.93/29.06  																																															| (978) all_36_2_52 = 0
% 66.93/29.06  																																															|
% 66.93/29.06  																																															| Simplifying 978 yields:
% 66.93/29.06  																																															| (979) all_36_2_52 = 0
% 66.93/29.06  																																															|
% 66.93/29.06  																																															| Combining equations (979,293) yields a new equation:
% 66.93/29.06  																																															| (980) all_41_1_55 = 0
% 66.93/29.06  																																															|
% 66.93/29.06  																																															| From (979) and (166) follows:
% 66.93/29.06  																																															| (972) aNaturalNumber0(xk) = 0
% 66.93/29.06  																																															|
% 66.93/29.06  																																															+-Applying beta-rule and splitting (650), into two cases.
% 66.93/29.06  																																															|-Branch one:
% 66.93/29.06  																																															| (982) all_20_2_23 = sz00
% 66.93/29.06  																																															|
% 66.93/29.06  																																																| Combining equations (982,968) yields a new equation:
% 66.93/29.06  																																																| (168) xk = sz00
% 66.93/29.06  																																																|
% 66.93/29.06  																																																| Equations (168) can reduce 13 to:
% 66.93/29.06  																																																| (159) $false
% 66.93/29.06  																																																|
% 66.93/29.06  																																																|-The branch is then unsatisfiable
% 66.93/29.06  																																															|-Branch two:
% 66.93/29.06  																																															| (985)  ~ (all_20_2_23 = sz00)
% 66.93/29.06  																																															| (986) all_20_2_23 = sz10 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, all_20_2_23) = 0 & aNaturalNumber0(v0) = 0)
% 66.93/29.06  																																															|
% 66.93/29.06  																																																| Equations (968) can reduce 985 to:
% 66.93/29.06  																																																| (13)  ~ (xk = sz00)
% 66.93/29.06  																																																|
% 66.93/29.06  																																																+-Applying beta-rule and splitting (124), into two cases.
% 66.93/29.06  																																																|-Branch one:
% 66.93/29.06  																																																| (988) all_21_0_24 = xk & all_21_1_25 = 0 & sdtasdt0(xr, all_21_2_26) = xk & aNaturalNumber0(all_21_2_26) = 0
% 66.93/29.06  																																																|
% 66.93/29.06  																																																	| Applying alpha-rule on (988) yields:
% 66.93/29.06  																																																	| (989) all_21_0_24 = xk
% 66.93/29.06  																																																	| (990) all_21_1_25 = 0
% 66.93/29.06  																																																	| (991) sdtasdt0(xr, all_21_2_26) = xk
% 66.93/29.06  																																																	| (992) aNaturalNumber0(all_21_2_26) = 0
% 66.93/29.06  																																																	|
% 66.93/29.06  																																																	+-Applying beta-rule and splitting (651), into two cases.
% 66.93/29.06  																																																	|-Branch one:
% 66.93/29.06  																																																	| (974)  ~ (aNaturalNumber0(xk) = 0)
% 66.93/29.06  																																																	|
% 66.93/29.06  																																																		| Using (972) and (974) yields:
% 66.93/29.06  																																																		| (615) $false
% 66.93/29.06  																																																		|
% 66.93/29.06  																																																		|-The branch is then unsatisfiable
% 66.93/29.06  																																																	|-Branch two:
% 66.93/29.06  																																																	| (972) aNaturalNumber0(xk) = 0
% 66.93/29.06  																																																	| (996) xk = sz10 | xk = sz00 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xk) = 0 & aNaturalNumber0(v0) = 0)
% 66.93/29.06  																																																	|
% 66.93/29.06  																																																		+-Applying beta-rule and splitting (986), into two cases.
% 66.93/29.06  																																																		|-Branch one:
% 66.93/29.06  																																																		| (997) all_20_2_23 = sz10
% 66.93/29.06  																																																		|
% 66.93/29.06  																																																			| Combining equations (968,997) yields a new equation:
% 66.93/29.06  																																																			| (998) xk = sz10
% 66.93/29.06  																																																			|
% 66.93/29.06  																																																			| Simplifying 998 yields:
% 66.93/29.06  																																																			| (999) xk = sz10
% 66.93/29.06  																																																			|
% 66.93/29.06  																																																			| Equations (999) can reduce 68 to:
% 66.93/29.06  																																																			| (159) $false
% 66.93/29.06  																																																			|
% 66.93/29.06  																																																			|-The branch is then unsatisfiable
% 66.93/29.06  																																																		|-Branch two:
% 66.93/29.06  																																																		| (1001)  ~ (all_20_2_23 = sz10)
% 66.93/29.06  																																																		| (1002)  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, all_20_2_23) = 0 & aNaturalNumber0(v0) = 0)
% 66.93/29.06  																																																		|
% 66.93/29.06  																																																			| Instantiating (1002) with all_386_0_142 yields:
% 66.93/29.06  																																																			| (1003) isPrime0(all_386_0_142) = 0 & doDivides0(all_386_0_142, all_20_2_23) = 0 & aNaturalNumber0(all_386_0_142) = 0
% 66.93/29.06  																																																			|
% 66.93/29.06  																																																			| Applying alpha-rule on (1003) yields:
% 66.93/29.06  																																																			| (1004) isPrime0(all_386_0_142) = 0
% 66.93/29.06  																																																			| (1005) doDivides0(all_386_0_142, all_20_2_23) = 0
% 66.93/29.06  																																																			| (1006) aNaturalNumber0(all_386_0_142) = 0
% 66.93/29.06  																																																			|
% 66.93/29.06  																																																			| Equations (968) can reduce 1001 to:
% 66.93/29.06  																																																			| (68)  ~ (xk = sz10)
% 66.93/29.06  																																																			|
% 66.93/29.06  																																																			| From (968) and (1005) follows:
% 66.93/29.06  																																																			| (1008) doDivides0(all_386_0_142, xk) = 0
% 66.93/29.06  																																																			|
% 66.93/29.06  																																																			+-Applying beta-rule and splitting (619), into two cases.
% 66.93/29.06  																																																			|-Branch one:
% 66.93/29.06  																																																			| (1009) all_58_0_58 = xp
% 66.93/29.06  																																																			|
% 66.93/29.06  																																																				| Equations (1009) can reduce 202 to:
% 66.93/29.06  																																																				| (86)  ~ (xp = sz00)
% 66.93/29.06  																																																				|
% 66.93/29.06  																																																				| From (1009) and (777) follows:
% 66.93/29.06  																																																				| (1011) doDivides0(all_208_0_135, xp) = 0
% 66.93/29.06  																																																				|
% 66.93/29.06  																																																				| From (1009) and (199) follows:
% 66.93/29.06  																																																				| (1012) doDivides0(xp, xp) = 0
% 66.93/29.06  																																																				|
% 66.93/29.06  																																																				| From (1009) and (730) follows:
% 66.93/29.06  																																																				| (1013) doDivides0(xp, xm) = all_182_1_113
% 66.93/29.06  																																																				|
% 66.93/29.06  																																																				| From (1009) and (662) follows:
% 66.93/29.06  																																																				| (1014) doDivides0(xp, xn) = all_159_1_63
% 66.93/29.06  																																																				|
% 66.93/29.06  																																																				| From (1009) and (962) follows:
% 66.93/29.06  																																																				| (1015) sdtasdt0(xp, all_186_2_128) = xp
% 66.93/29.06  																																																				|
% 66.93/29.06  																																																				| From (1009) and (200) follows:
% 66.93/29.06  																																																				| (12) aNaturalNumber0(xp) = 0
% 66.93/29.06  																																																				|
% 66.93/29.06  																																																				+-Applying beta-rule and splitting (786), into two cases.
% 66.93/29.06  																																																				|-Branch one:
% 66.93/29.06  																																																				| (1017)  ~ (doDivides0(xp, xm) = all_182_1_113)
% 66.93/29.06  																																																				|
% 66.93/29.06  																																																					| Using (1013) and (1017) yields:
% 66.93/29.06  																																																					| (615) $false
% 66.93/29.06  																																																					|
% 66.93/29.06  																																																					|-The branch is then unsatisfiable
% 66.93/29.06  																																																				|-Branch two:
% 66.93/29.06  																																																				| (1013) doDivides0(xp, xm) = all_182_1_113
% 66.93/29.06  																																																				| (1020) all_184_1_118 = all_182_1_113
% 66.93/29.06  																																																				|
% 66.93/29.06  																																																					| Combining equations (785,1020) yields a new equation:
% 66.93/29.06  																																																					| (1021) all_182_1_113 = all_30_0_41
% 66.93/29.06  																																																					|
% 66.93/29.06  																																																					| From (1021) and (1013) follows:
% 66.93/29.06  																																																					| (149) doDivides0(xp, xm) = all_30_0_41
% 66.93/29.06  																																																					|
% 66.93/29.06  																																																					+-Applying beta-rule and splitting (641), into two cases.
% 66.93/29.06  																																																					|-Branch one:
% 66.93/29.06  																																																					| (897) xp = xn
% 66.93/29.06  																																																					|
% 66.93/29.06  																																																						| Equations (897) can reduce 74 to:
% 66.93/29.06  																																																						| (159) $false
% 66.93/29.06  																																																						|
% 66.93/29.06  																																																						|-The branch is then unsatisfiable
% 66.93/29.06  																																																					|-Branch two:
% 66.93/29.06  																																																					| (74)  ~ (xp = xn)
% 66.93/29.06  																																																					| (1026)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(xp, xm) = v3 & sdtpldt0(xn, xm) = v4 & aNaturalNumber0(xp) = v1 & aNaturalNumber0(xm) = v0 & aNaturalNumber0(xn) = v2 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | ( ~ (v4 = v3) &  ~ (all_24_1_31 = all_0_5_5))))
% 66.93/29.06  																																																					|
% 66.93/29.06  																																																						| Instantiating (1026) with all_404_0_143, all_404_1_144, all_404_2_145, all_404_3_146, all_404_4_147 yields:
% 66.93/29.06  																																																						| (1027) sdtpldt0(xp, xm) = all_404_1_144 & sdtpldt0(xn, xm) = all_404_0_143 & aNaturalNumber0(xp) = all_404_3_146 & aNaturalNumber0(xm) = all_404_4_147 & aNaturalNumber0(xn) = all_404_2_145 & ( ~ (all_404_2_145 = 0) |  ~ (all_404_3_146 = 0) |  ~ (all_404_4_147 = 0) | ( ~ (all_404_0_143 = all_404_1_144) &  ~ (all_24_1_31 = all_0_5_5)))
% 66.93/29.06  																																																						|
% 66.93/29.06  																																																						| Applying alpha-rule on (1027) yields:
% 66.93/29.06  																																																						| (1028) sdtpldt0(xn, xm) = all_404_0_143
% 66.93/29.06  																																																						| (1029) aNaturalNumber0(xp) = all_404_3_146
% 66.93/29.06  																																																						| (1030) aNaturalNumber0(xm) = all_404_4_147
% 66.93/29.07  																																																						| (1031) aNaturalNumber0(xn) = all_404_2_145
% 66.93/29.07  																																																						| (1032) sdtpldt0(xp, xm) = all_404_1_144
% 66.93/29.07  																																																						| (1033)  ~ (all_404_2_145 = 0) |  ~ (all_404_3_146 = 0) |  ~ (all_404_4_147 = 0) | ( ~ (all_404_0_143 = all_404_1_144) &  ~ (all_24_1_31 = all_0_5_5))
% 66.93/29.07  																																																						|
% 66.93/29.07  																																																						+-Applying beta-rule and splitting (783), into two cases.
% 66.93/29.07  																																																						|-Branch one:
% 66.93/29.07  																																																						| (1034)  ~ (doDivides0(xp, xn) = all_159_1_63)
% 66.93/29.07  																																																						|
% 66.93/29.07  																																																							| Using (1014) and (1034) yields:
% 66.93/29.07  																																																							| (615) $false
% 66.93/29.07  																																																							|
% 66.93/29.07  																																																							|-The branch is then unsatisfiable
% 66.93/29.07  																																																						|-Branch two:
% 66.93/29.07  																																																						| (1014) doDivides0(xp, xn) = all_159_1_63
% 66.93/29.07  																																																						| (1037) all_159_1_63 = all_30_1_42
% 66.93/29.07  																																																						|
% 66.93/29.07  																																																							| From (1037) and (1014) follows:
% 66.93/29.07  																																																							| (157) doDivides0(xp, xn) = all_30_1_42
% 66.93/29.07  																																																							|
% 66.93/29.07  																																																							+-Applying beta-rule and splitting (176), into two cases.
% 66.93/29.07  																																																							|-Branch one:
% 66.93/29.07  																																																							| (1039)  ~ (all_41_1_55 = 0)
% 66.93/29.07  																																																							|
% 66.93/29.07  																																																								| Equations (980) can reduce 1039 to:
% 66.93/29.07  																																																								| (159) $false
% 66.93/29.07  																																																								|
% 66.93/29.07  																																																								|-The branch is then unsatisfiable
% 66.93/29.07  																																																							|-Branch two:
% 66.93/29.07  																																																							| (980) all_41_1_55 = 0
% 66.93/29.07  																																																							| (1042)  ~ (all_41_2_56 = 0) | all_41_0_54 = 0
% 66.93/29.07  																																																							|
% 66.93/29.07  																																																								+-Applying beta-rule and splitting (996), into two cases.
% 66.93/29.07  																																																								|-Branch one:
% 66.93/29.07  																																																								| (168) xk = sz00
% 66.93/29.07  																																																								|
% 66.93/29.07  																																																									| Equations (168) can reduce 13 to:
% 66.93/29.07  																																																									| (159) $false
% 66.93/29.07  																																																									|
% 66.93/29.07  																																																									|-The branch is then unsatisfiable
% 66.93/29.07  																																																								|-Branch two:
% 66.93/29.07  																																																								| (13)  ~ (xk = sz00)
% 66.93/29.07  																																																								| (1046) xk = sz10 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xk) = 0 & aNaturalNumber0(v0) = 0)
% 66.93/29.07  																																																								|
% 66.93/29.07  																																																									+-Applying beta-rule and splitting (1042), into two cases.
% 66.93/29.07  																																																									|-Branch one:
% 66.93/29.07  																																																									| (1047)  ~ (all_41_2_56 = 0)
% 66.93/29.07  																																																									|
% 66.93/29.07  																																																										| Equations (253) can reduce 1047 to:
% 66.93/29.07  																																																										| (159) $false
% 66.93/29.07  																																																										|
% 66.93/29.07  																																																										|-The branch is then unsatisfiable
% 66.93/29.07  																																																									|-Branch two:
% 66.93/29.07  																																																									| (253) all_41_2_56 = 0
% 66.93/29.07  																																																									| (1050) all_41_0_54 = 0
% 66.93/29.07  																																																									|
% 66.93/29.07  																																																										+-Applying beta-rule and splitting (165), into two cases.
% 66.93/29.07  																																																										|-Branch one:
% 66.93/29.07  																																																										| (1051)  ~ (all_36_0_50 = 0)
% 66.93/29.07  																																																										|
% 66.93/29.07  																																																											+-Applying beta-rule and splitting (1046), into two cases.
% 66.93/29.07  																																																											|-Branch one:
% 66.93/29.07  																																																											| (999) xk = sz10
% 66.93/29.07  																																																											|
% 66.93/29.07  																																																												| Equations (999) can reduce 68 to:
% 66.93/29.07  																																																												| (159) $false
% 66.93/29.07  																																																												|
% 66.93/29.07  																																																												|-The branch is then unsatisfiable
% 66.93/29.07  																																																											|-Branch two:
% 66.93/29.07  																																																											| (68)  ~ (xk = sz10)
% 66.93/29.07  																																																											| (1055)  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xk) = 0 & aNaturalNumber0(v0) = 0)
% 66.93/29.07  																																																											|
% 66.93/29.07  																																																												| Instantiating (1055) with all_432_0_148 yields:
% 66.93/29.07  																																																												| (1056) isPrime0(all_432_0_148) = 0 & doDivides0(all_432_0_148, xk) = 0 & aNaturalNumber0(all_432_0_148) = 0
% 66.93/29.07  																																																												|
% 66.93/29.07  																																																												| Applying alpha-rule on (1056) yields:
% 66.93/29.07  																																																												| (1057) isPrime0(all_432_0_148) = 0
% 66.93/29.07  																																																												| (1058) doDivides0(all_432_0_148, xk) = 0
% 66.93/29.07  																																																												| (1059) aNaturalNumber0(all_432_0_148) = 0
% 66.93/29.07  																																																												|
% 66.93/29.07  																																																												+-Applying beta-rule and splitting (628), into two cases.
% 66.93/29.07  																																																												|-Branch one:
% 66.93/29.07  																																																												| (1060)  ~ (sdtasdt0(xp, xk) = all_0_3_3)
% 66.93/29.07  																																																												|
% 66.93/29.07  																																																													| Using (970) and (1060) yields:
% 66.93/29.07  																																																													| (615) $false
% 66.93/29.07  																																																													|
% 66.93/29.07  																																																													|-The branch is then unsatisfiable
% 66.93/29.07  																																																												|-Branch two:
% 66.93/29.07  																																																												| (970) sdtasdt0(xp, xk) = all_0_3_3
% 66.93/29.07  																																																												| (1063) xp = sz00 |  ? [v0] :  ? [v1] :  ? [v2] : ((v0 = 0 & aNaturalNumber0(xk) = 0) | (doDivides0(xp, all_0_3_3) = v2 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0))))
% 66.93/29.07  																																																												|
% 66.93/29.07  																																																													+-Applying beta-rule and splitting (784), into two cases.
% 66.93/29.07  																																																													|-Branch one:
% 66.93/29.07  																																																													| (1064)  ~ (doDivides0(xp, xp) = 0)
% 66.93/29.07  																																																													|
% 66.93/29.07  																																																														| Using (1012) and (1064) yields:
% 66.93/29.07  																																																														| (615) $false
% 66.93/29.07  																																																														|
% 66.93/29.07  																																																														|-The branch is then unsatisfiable
% 66.93/29.07  																																																													|-Branch two:
% 66.93/29.07  																																																													| (1012) doDivides0(xp, xp) = 0
% 66.93/29.07  																																																													| (1067) all_179_1_101 = 0
% 66.93/29.07  																																																													|
% 66.93/29.07  																																																														| From (1067) and (722) follows:
% 66.93/29.07  																																																														| (1012) doDivides0(xp, xp) = 0
% 66.93/29.07  																																																														|
% 66.93/29.07  																																																														+-Applying beta-rule and splitting (1063), into two cases.
% 66.93/29.07  																																																														|-Branch one:
% 66.93/29.07  																																																														| (181) xp = sz00
% 66.93/29.07  																																																														|
% 66.93/29.07  																																																															| Equations (181) can reduce 86 to:
% 66.93/29.07  																																																															| (159) $false
% 66.93/29.07  																																																															|
% 66.93/29.07  																																																															|-The branch is then unsatisfiable
% 66.93/29.07  																																																														|-Branch two:
% 66.93/29.07  																																																														| (86)  ~ (xp = sz00)
% 66.93/29.07  																																																														| (1072)  ? [v0] :  ? [v1] :  ? [v2] : ((v0 = 0 & aNaturalNumber0(xk) = 0) | (doDivides0(xp, all_0_3_3) = v2 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0))))
% 66.93/29.07  																																																														|
% 66.93/29.07  																																																															| Instantiating (1072) with all_456_0_152, all_456_1_153, all_456_2_154 yields:
% 66.93/29.07  																																																															| (1073) (all_456_2_154 = 0 & aNaturalNumber0(xk) = 0) | (doDivides0(xp, all_0_3_3) = all_456_0_152 & aNaturalNumber0(all_0_3_3) = all_456_1_153 & aNaturalNumber0(xp) = all_456_2_154 & ( ~ (all_456_0_152 = 0) |  ~ (all_456_1_153 = 0) |  ~ (all_456_2_154 = 0)))
% 66.93/29.07  																																																															|
% 66.93/29.07  																																																															| Instantiating formula (3) with xn, xm, all_404_0_143, all_0_5_5 and discharging atoms sdtpldt0(xn, xm) = all_404_0_143, sdtpldt0(xn, xm) = all_0_5_5, yields:
% 66.93/29.07  																																																															| (1074) all_404_0_143 = all_0_5_5
% 66.93/29.07  																																																															|
% 66.93/29.07  																																																															| Instantiating formula (46) with xp, all_404_3_146, 0 and discharging atoms aNaturalNumber0(xp) = all_404_3_146, aNaturalNumber0(xp) = 0, yields:
% 66.93/29.07  																																																															| (1075) all_404_3_146 = 0
% 66.93/29.07  																																																															|
% 66.93/29.07  																																																															| Instantiating formula (46) with xm, all_404_4_147, 0 and discharging atoms aNaturalNumber0(xm) = all_404_4_147, aNaturalNumber0(xm) = 0, yields:
% 66.93/29.07  																																																															| (1076) all_404_4_147 = 0
% 66.93/29.07  																																																															|
% 66.93/29.07  																																																															| Instantiating formula (46) with xn, all_404_2_145, 0 and discharging atoms aNaturalNumber0(xn) = all_404_2_145, aNaturalNumber0(xn) = 0, yields:
% 66.93/29.07  																																																															| (1077) all_404_2_145 = 0
% 66.93/29.07  																																																															|
% 66.93/29.07  																																																															| From (1074) and (1028) follows:
% 66.93/29.07  																																																															| (73) sdtpldt0(xn, xm) = all_0_5_5
% 66.93/29.07  																																																															|
% 66.93/29.07  																																																															| From (1075) and (1029) follows:
% 66.93/29.07  																																																															| (12) aNaturalNumber0(xp) = 0
% 66.93/29.07  																																																															|
% 66.93/29.07  																																																															| From (1076) and (1030) follows:
% 66.93/29.07  																																																															| (36) aNaturalNumber0(xm) = 0
% 66.93/29.07  																																																															|
% 66.93/29.07  																																																															| From (1077) and (1031) follows:
% 66.93/29.07  																																																															| (53) aNaturalNumber0(xn) = 0
% 66.93/29.07  																																																															|
% 66.93/29.07  																																																															+-Applying beta-rule and splitting (631), into two cases.
% 66.93/29.07  																																																															|-Branch one:
% 66.93/29.07  																																																															| (1082)  ~ (sdtasdt0(xp, all_20_2_23) = sz00)
% 66.93/29.07  																																																															|
% 66.93/29.07  																																																																| From (968) and (1082) follows:
% 66.93/29.07  																																																																| (1083)  ~ (sdtasdt0(xp, xk) = sz00)
% 66.93/29.07  																																																																|
% 66.93/29.07  																																																																+-Applying beta-rule and splitting (1073), into two cases.
% 66.93/29.07  																																																																|-Branch one:
% 66.93/29.07  																																																																| (1084) all_456_2_154 = 0 & aNaturalNumber0(xk) = 0
% 66.93/29.07  																																																																|
% 66.93/29.07  																																																																	| Applying alpha-rule on (1084) yields:
% 66.93/29.07  																																																																	| (1085) all_456_2_154 = 0
% 66.93/29.07  																																																																	| (972) aNaturalNumber0(xk) = 0
% 66.93/29.07  																																																																	|
% 66.93/29.07  																																																																	| Using (970) and (1083) yields:
% 66.93/29.07  																																																																	| (1087)  ~ (all_0_3_3 = sz00)
% 66.93/29.07  																																																																	|
% 66.93/29.07  																																																																	+-Applying beta-rule and splitting (95), into two cases.
% 66.93/29.07  																																																																	|-Branch one:
% 66.93/29.07  																																																																	| (1088)  ~ (sdtasdt0(sz00, xm) = all_0_3_3)
% 66.93/29.07  																																																																	|
% 66.93/29.07  																																																																		+-Applying beta-rule and splitting (90), into two cases.
% 66.93/29.07  																																																																		|-Branch one:
% 66.93/29.07  																																																																		| (1089) all_0_3_3 = sz00
% 66.93/29.07  																																																																		|
% 66.93/29.07  																																																																			| Equations (1089) can reduce 1087 to:
% 66.93/29.07  																																																																			| (159) $false
% 66.93/29.07  																																																																			|
% 66.93/29.07  																																																																			|-The branch is then unsatisfiable
% 66.93/29.07  																																																																		|-Branch two:
% 66.93/29.07  																																																																		| (1087)  ~ (all_0_3_3 = sz00)
% 66.93/29.07  																																																																		| (1092)  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(xp, all_0_3_3) = v2 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 66.93/29.07  																																																																		|
% 66.93/29.07  																																																																			| Instantiating (1092) with all_517_0_155, all_517_1_156, all_517_2_157 yields:
% 66.93/29.07  																																																																			| (1093) sdtlseqdt0(xp, all_0_3_3) = all_517_0_155 & aNaturalNumber0(all_0_3_3) = all_517_1_156 & aNaturalNumber0(xp) = all_517_2_157 & ( ~ (all_517_1_156 = 0) |  ~ (all_517_2_157 = 0) | all_517_0_155 = 0)
% 66.93/29.07  																																																																			|
% 66.93/29.07  																																																																			| Applying alpha-rule on (1093) yields:
% 66.93/29.07  																																																																			| (1094) sdtlseqdt0(xp, all_0_3_3) = all_517_0_155
% 66.93/29.07  																																																																			| (1095) aNaturalNumber0(all_0_3_3) = all_517_1_156
% 66.93/29.07  																																																																			| (1096) aNaturalNumber0(xp) = all_517_2_157
% 66.93/29.07  																																																																			| (1097)  ~ (all_517_1_156 = 0) |  ~ (all_517_2_157 = 0) | all_517_0_155 = 0
% 66.93/29.07  																																																																			|
% 66.93/29.07  																																																																			+-Applying beta-rule and splitting (634), into two cases.
% 66.93/29.07  																																																																			|-Branch one:
% 66.93/29.07  																																																																			| (1098)  ~ (sdtasdt0(sz00, xn) = all_0_3_3)
% 66.93/29.07  																																																																			|
% 66.93/29.07  																																																																				| Instantiating formula (46) with all_0_3_3, all_517_1_156, 0 and discharging atoms aNaturalNumber0(all_0_3_3) = all_517_1_156, aNaturalNumber0(all_0_3_3) = 0, yields:
% 66.93/29.08  																																																																				| (1099) all_517_1_156 = 0
% 66.93/29.08  																																																																				|
% 66.93/29.08  																																																																				| Instantiating formula (46) with xp, all_517_2_157, 0 and discharging atoms aNaturalNumber0(xp) = all_517_2_157, aNaturalNumber0(xp) = 0, yields:
% 66.93/29.08  																																																																				| (1100) all_517_2_157 = 0
% 66.93/29.08  																																																																				|
% 66.93/29.08  																																																																				| Using (2) and (1088) yields:
% 66.93/29.08  																																																																				| (1101)  ~ (xn = sz00)
% 66.93/29.08  																																																																				|
% 66.93/29.08  																																																																				| Using (608) and (1098) yields:
% 66.93/29.08  																																																																				| (1102)  ~ (xm = sz00)
% 66.93/29.08  																																																																				|
% 66.93/29.08  																																																																				| From (1099) and (1095) follows:
% 66.93/29.08  																																																																				| (556) aNaturalNumber0(all_0_3_3) = 0
% 66.93/29.08  																																																																				|
% 66.93/29.08  																																																																				| From (1100) and (1096) follows:
% 66.93/29.08  																																																																				| (12) aNaturalNumber0(xp) = 0
% 66.93/29.08  																																																																				|
% 66.93/29.08  																																																																				+-Applying beta-rule and splitting (627), into two cases.
% 66.93/29.08  																																																																				|-Branch one:
% 66.93/29.08  																																																																				| (1105)  ~ (doDivides0(xp, xn) = 0)
% 66.93/29.08  																																																																				|
% 66.93/29.08  																																																																					+-Applying beta-rule and splitting (625), into two cases.
% 66.93/29.08  																																																																					|-Branch one:
% 66.93/29.08  																																																																					| (1106)  ~ (doDivides0(xp, xm) = 0)
% 66.93/29.08  																																																																					|
% 66.93/29.08  																																																																						| Using (149) and (1106) yields:
% 66.93/29.08  																																																																						| (1107)  ~ (all_30_0_41 = 0)
% 66.93/29.08  																																																																						|
% 66.93/29.08  																																																																						| Using (157) and (1105) yields:
% 66.93/29.08  																																																																						| (1108)  ~ (all_30_1_42 = 0)
% 66.93/29.08  																																																																						|
% 66.93/29.08  																																																																						+-Applying beta-rule and splitting (626), into two cases.
% 66.93/29.08  																																																																						|-Branch one:
% 66.93/29.08  																																																																						| (1109) all_30_1_42 = 0
% 66.93/29.08  																																																																						|
% 66.93/29.08  																																																																							| Equations (1109) can reduce 1108 to:
% 66.93/29.08  																																																																							| (159) $false
% 66.93/29.08  																																																																							|
% 66.93/29.08  																																																																							|-The branch is then unsatisfiable
% 66.93/29.08  																																																																						|-Branch two:
% 66.93/29.08  																																																																						| (1108)  ~ (all_30_1_42 = 0)
% 66.93/29.08  																																																																						| (1112)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] : (doDivides0(all_0_3_3, xn) = v3 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xn) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0)))
% 66.93/29.08  																																																																						|
% 66.93/29.08  																																																																							| Instantiating (1112) with all_583_0_160, all_583_1_161, all_583_2_162, all_583_3_163 yields:
% 66.93/29.08  																																																																							| (1113) doDivides0(all_0_3_3, xn) = all_583_0_160 & aNaturalNumber0(all_0_3_3) = all_583_2_162 & aNaturalNumber0(xp) = all_583_3_163 & aNaturalNumber0(xn) = all_583_1_161 & ( ~ (all_583_0_160 = 0) |  ~ (all_583_1_161 = 0) |  ~ (all_583_2_162 = 0) |  ~ (all_583_3_163 = 0))
% 66.93/29.08  																																																																							|
% 66.93/29.08  																																																																							| Applying alpha-rule on (1113) yields:
% 66.93/29.08  																																																																							| (1114) aNaturalNumber0(xp) = all_583_3_163
% 66.93/29.08  																																																																							| (1115) aNaturalNumber0(all_0_3_3) = all_583_2_162
% 66.93/29.08  																																																																							| (1116) doDivides0(all_0_3_3, xn) = all_583_0_160
% 66.93/29.08  																																																																							| (1117)  ~ (all_583_0_160 = 0) |  ~ (all_583_1_161 = 0) |  ~ (all_583_2_162 = 0) |  ~ (all_583_3_163 = 0)
% 66.93/29.08  																																																																							| (1118) aNaturalNumber0(xn) = all_583_1_161
% 66.93/29.08  																																																																							|
% 66.93/29.08  																																																																							+-Applying beta-rule and splitting (624), into two cases.
% 66.93/29.08  																																																																							|-Branch one:
% 66.93/29.08  																																																																							| (1119) all_30_0_41 = 0
% 66.93/29.08  																																																																							|
% 66.93/29.08  																																																																								| Equations (1119) can reduce 1107 to:
% 66.93/29.08  																																																																								| (159) $false
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								|-The branch is then unsatisfiable
% 66.93/29.08  																																																																							|-Branch two:
% 66.93/29.08  																																																																							| (1107)  ~ (all_30_0_41 = 0)
% 66.93/29.08  																																																																							| (1122)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] : (doDivides0(all_0_3_3, xm) = v3 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xm) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0)))
% 66.93/29.08  																																																																							|
% 66.93/29.08  																																																																								| Instantiating (1122) with all_589_0_164, all_589_1_165, all_589_2_166, all_589_3_167 yields:
% 66.93/29.08  																																																																								| (1123) doDivides0(all_0_3_3, xm) = all_589_0_164 & aNaturalNumber0(all_0_3_3) = all_589_2_166 & aNaturalNumber0(xp) = all_589_3_167 & aNaturalNumber0(xm) = all_589_1_165 & ( ~ (all_589_0_164 = 0) |  ~ (all_589_1_165 = 0) |  ~ (all_589_2_166 = 0) |  ~ (all_589_3_167 = 0))
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| Applying alpha-rule on (1123) yields:
% 66.93/29.08  																																																																								| (1124)  ~ (all_589_0_164 = 0) |  ~ (all_589_1_165 = 0) |  ~ (all_589_2_166 = 0) |  ~ (all_589_3_167 = 0)
% 66.93/29.08  																																																																								| (1125) doDivides0(all_0_3_3, xm) = all_589_0_164
% 66.93/29.08  																																																																								| (1126) aNaturalNumber0(xp) = all_589_3_167
% 66.93/29.08  																																																																								| (1127) aNaturalNumber0(all_0_3_3) = all_589_2_166
% 66.93/29.08  																																																																								| (1128) aNaturalNumber0(xm) = all_589_1_165
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| Instantiating formula (46) with all_0_3_3, all_589_2_166, 0 and discharging atoms aNaturalNumber0(all_0_3_3) = all_589_2_166, aNaturalNumber0(all_0_3_3) = 0, yields:
% 66.93/29.08  																																																																								| (1129) all_589_2_166 = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| Instantiating formula (46) with all_0_3_3, all_583_2_162, all_589_2_166 and discharging atoms aNaturalNumber0(all_0_3_3) = all_589_2_166, aNaturalNumber0(all_0_3_3) = all_583_2_162, yields:
% 66.93/29.08  																																																																								| (1130) all_589_2_166 = all_583_2_162
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| Instantiating formula (46) with xp, all_589_3_167, 0 and discharging atoms aNaturalNumber0(xp) = all_589_3_167, aNaturalNumber0(xp) = 0, yields:
% 66.93/29.08  																																																																								| (1131) all_589_3_167 = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| Instantiating formula (46) with xp, all_583_3_163, all_589_3_167 and discharging atoms aNaturalNumber0(xp) = all_589_3_167, aNaturalNumber0(xp) = all_583_3_163, yields:
% 66.93/29.08  																																																																								| (1132) all_589_3_167 = all_583_3_163
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| Instantiating formula (46) with xm, all_589_1_165, 0 and discharging atoms aNaturalNumber0(xm) = all_589_1_165, aNaturalNumber0(xm) = 0, yields:
% 66.93/29.08  																																																																								| (1133) all_589_1_165 = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| Instantiating formula (46) with xn, all_583_1_161, 0 and discharging atoms aNaturalNumber0(xn) = all_583_1_161, aNaturalNumber0(xn) = 0, yields:
% 66.93/29.08  																																																																								| (1134) all_583_1_161 = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| Combining equations (1130,1129) yields a new equation:
% 66.93/29.08  																																																																								| (1135) all_583_2_162 = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| Simplifying 1135 yields:
% 66.93/29.08  																																																																								| (1136) all_583_2_162 = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| Combining equations (1132,1131) yields a new equation:
% 66.93/29.08  																																																																								| (1137) all_583_3_163 = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| Simplifying 1137 yields:
% 66.93/29.08  																																																																								| (1138) all_583_3_163 = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| From (1136) and (1115) follows:
% 66.93/29.08  																																																																								| (556) aNaturalNumber0(all_0_3_3) = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| From (1138) and (1114) follows:
% 66.93/29.08  																																																																								| (12) aNaturalNumber0(xp) = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| From (1133) and (1128) follows:
% 66.93/29.08  																																																																								| (36) aNaturalNumber0(xm) = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								| From (1134) and (1118) follows:
% 66.93/29.08  																																																																								| (53) aNaturalNumber0(xn) = 0
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																								+-Applying beta-rule and splitting (421), into two cases.
% 66.93/29.08  																																																																								|-Branch one:
% 66.93/29.08  																																																																								| (1143)  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																									| From (515) and (1143) follows:
% 66.93/29.08  																																																																									| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.08  																																																																									|
% 66.93/29.08  																																																																									| Using (53) and (1144) yields:
% 66.93/29.08  																																																																									| (615) $false
% 66.93/29.08  																																																																									|
% 66.93/29.08  																																																																									|-The branch is then unsatisfiable
% 66.93/29.08  																																																																								|-Branch two:
% 66.93/29.08  																																																																								| (1146) aNaturalNumber0(xn) = all_28_1_39
% 66.93/29.08  																																																																								| (1147) all_28_1_39 = all_28_2_40
% 66.93/29.08  																																																																								|
% 66.93/29.08  																																																																									| Combining equations (515,1147) yields a new equation:
% 66.93/29.08  																																																																									| (514) all_28_2_40 = 0
% 66.93/29.08  																																																																									|
% 66.93/29.08  																																																																									| Combining equations (514,1147) yields a new equation:
% 66.93/29.08  																																																																									| (515) all_28_1_39 = 0
% 66.93/29.08  																																																																									|
% 66.93/29.08  																																																																									| From (515) and (1146) follows:
% 66.93/29.08  																																																																									| (53) aNaturalNumber0(xn) = 0
% 66.93/29.08  																																																																									|
% 66.93/29.08  																																																																									+-Applying beta-rule and splitting (469), into two cases.
% 66.93/29.08  																																																																									|-Branch one:
% 66.93/29.08  																																																																									| (1151)  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 66.93/29.08  																																																																									|
% 66.93/29.08  																																																																										| From (554) and (1151) follows:
% 66.93/29.08  																																																																										| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.08  																																																																										|
% 66.93/29.08  																																																																										| Using (53) and (1144) yields:
% 66.93/29.08  																																																																										| (615) $false
% 66.93/29.08  																																																																										|
% 66.93/29.08  																																																																										|-The branch is then unsatisfiable
% 66.93/29.08  																																																																									|-Branch two:
% 66.93/29.08  																																																																									| (1154) aNaturalNumber0(xn) = all_22_0_27
% 66.93/29.08  																																																																									| (1155) all_22_0_27 = all_12_2_8
% 66.93/29.08  																																																																									|
% 66.93/29.08  																																																																										| Combining equations (554,1155) yields a new equation:
% 66.93/29.08  																																																																										| (508) all_12_2_8 = 0
% 66.93/29.08  																																																																										|
% 66.93/29.08  																																																																										| Combining equations (508,1155) yields a new equation:
% 66.93/29.08  																																																																										| (554) all_22_0_27 = 0
% 66.93/29.08  																																																																										|
% 66.93/29.08  																																																																										| From (554) and (1154) follows:
% 66.93/29.08  																																																																										| (53) aNaturalNumber0(xn) = 0
% 66.93/29.08  																																																																										|
% 66.93/29.08  																																																																										+-Applying beta-rule and splitting (408), into two cases.
% 66.93/29.08  																																																																										|-Branch one:
% 66.93/29.08  																																																																										| (1159)  ~ (aNaturalNumber0(xn) = all_12_1_7)
% 66.93/29.08  																																																																										|
% 66.93/29.08  																																																																											| From (507) and (1159) follows:
% 66.93/29.08  																																																																											| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.08  																																																																											|
% 66.93/29.08  																																																																											| Using (53) and (1144) yields:
% 66.93/29.08  																																																																											| (615) $false
% 66.93/29.08  																																																																											|
% 66.93/29.08  																																																																											|-The branch is then unsatisfiable
% 66.93/29.08  																																																																										|-Branch two:
% 66.93/29.08  																																																																										| (1162) aNaturalNumber0(xn) = all_12_1_7
% 66.93/29.08  																																																																										| (1163) all_30_8_49 = all_12_1_7
% 66.93/29.08  																																																																										|
% 66.93/29.08  																																																																											| Combining equations (516,1163) yields a new equation:
% 66.93/29.08  																																																																											| (507) all_12_1_7 = 0
% 66.93/29.08  																																																																											|
% 66.93/29.08  																																																																											| From (507) and (1162) follows:
% 66.93/29.08  																																																																											| (53) aNaturalNumber0(xn) = 0
% 66.93/29.08  																																																																											|
% 66.93/29.08  																																																																											+-Applying beta-rule and splitting (475), into two cases.
% 66.93/29.08  																																																																											|-Branch one:
% 66.93/29.08  																																																																											| (1166)  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 66.93/29.08  																																																																											|
% 66.93/29.08  																																																																												| From (331) and (1166) follows:
% 66.93/29.08  																																																																												| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.08  																																																																												|
% 66.93/29.08  																																																																												| Using (53) and (1144) yields:
% 66.93/29.08  																																																																												| (615) $false
% 66.93/29.08  																																																																												|
% 66.93/29.08  																																																																												|-The branch is then unsatisfiable
% 66.93/29.08  																																																																											|-Branch two:
% 66.93/29.08  																																																																											| (1169) aNaturalNumber0(xn) = all_30_7_48
% 66.93/29.08  																																																																											| (1170) all_30_7_48 = all_12_2_8
% 66.93/29.08  																																																																											|
% 66.93/29.08  																																																																												| Combining equations (331,1170) yields a new equation:
% 66.93/29.08  																																																																												| (508) all_12_2_8 = 0
% 66.93/29.08  																																																																												|
% 66.93/29.08  																																																																												| Combining equations (508,1170) yields a new equation:
% 66.93/29.08  																																																																												| (331) all_30_7_48 = 0
% 66.93/29.08  																																																																												|
% 66.93/29.08  																																																																												| From (331) and (1169) follows:
% 66.93/29.08  																																																																												| (53) aNaturalNumber0(xn) = 0
% 66.93/29.08  																																																																												|
% 66.93/29.08  																																																																												+-Applying beta-rule and splitting (400), into two cases.
% 66.93/29.08  																																																																												|-Branch one:
% 66.93/29.08  																																																																												| (1174)  ~ (aNaturalNumber0(xn) = all_41_2_56)
% 66.93/29.08  																																																																												|
% 66.93/29.08  																																																																													| From (253) and (1174) follows:
% 66.93/29.08  																																																																													| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.08  																																																																													|
% 66.93/29.08  																																																																													| Using (53) and (1144) yields:
% 66.93/29.08  																																																																													| (615) $false
% 66.93/29.08  																																																																													|
% 66.93/29.08  																																																																													|-The branch is then unsatisfiable
% 66.93/29.08  																																																																												|-Branch two:
% 66.93/29.08  																																																																												| (1177) aNaturalNumber0(xn) = all_41_2_56
% 66.93/29.08  																																																																												| (1178) all_41_2_56 = all_30_8_49
% 66.93/29.08  																																																																												|
% 66.93/29.08  																																																																													| Combining equations (253,1178) yields a new equation:
% 66.93/29.08  																																																																													| (516) all_30_8_49 = 0
% 66.93/29.08  																																																																													|
% 66.93/29.08  																																																																													| Combining equations (516,1178) yields a new equation:
% 66.93/29.08  																																																																													| (253) all_41_2_56 = 0
% 66.93/29.08  																																																																													|
% 66.93/29.08  																																																																													| From (253) and (1177) follows:
% 66.93/29.08  																																																																													| (53) aNaturalNumber0(xn) = 0
% 66.93/29.08  																																																																													|
% 66.93/29.08  																																																																													+-Applying beta-rule and splitting (463), into two cases.
% 66.93/29.08  																																																																													|-Branch one:
% 66.93/29.08  																																																																													| (1182)  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 66.93/29.08  																																																																													|
% 66.93/29.08  																																																																														| From (499) and (1182) follows:
% 66.93/29.08  																																																																														| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.08  																																																																														|
% 66.93/29.08  																																																																														| Using (53) and (1144) yields:
% 66.93/29.08  																																																																														| (615) $false
% 66.93/29.08  																																																																														|
% 66.93/29.08  																																																																														|-The branch is then unsatisfiable
% 66.93/29.08  																																																																													|-Branch two:
% 66.93/29.08  																																																																													| (1185) aNaturalNumber0(xn) = all_22_1_28
% 66.93/29.08  																																																																													| (1186) all_22_1_28 = all_14_2_11
% 66.93/29.08  																																																																													|
% 66.93/29.08  																																																																														| Combining equations (499,1186) yields a new equation:
% 66.93/29.08  																																																																														| (451) all_14_2_11 = 0
% 66.93/29.08  																																																																														|
% 66.93/29.08  																																																																														| Combining equations (451,1186) yields a new equation:
% 66.93/29.08  																																																																														| (499) all_22_1_28 = 0
% 66.93/29.08  																																																																														|
% 66.93/29.08  																																																																														| From (499) and (1185) follows:
% 66.93/29.08  																																																																														| (53) aNaturalNumber0(xn) = 0
% 66.93/29.08  																																																																														|
% 66.93/29.08  																																																																														+-Applying beta-rule and splitting (334), into two cases.
% 66.93/29.08  																																																																														|-Branch one:
% 66.93/29.08  																																																																														| (1190)  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 66.93/29.08  																																																																														|
% 66.93/29.08  																																																																															| From (554) and (1190) follows:
% 66.93/29.08  																																																																															| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.08  																																																																															|
% 66.93/29.08  																																																																															| Using (36) and (1191) yields:
% 66.93/29.08  																																																																															| (615) $false
% 66.93/29.08  																																																																															|
% 66.93/29.08  																																																																															|-The branch is then unsatisfiable
% 66.93/29.08  																																																																														|-Branch two:
% 66.93/29.08  																																																																														| (1193) aNaturalNumber0(xm) = all_22_0_27
% 66.93/29.08  																																																																														| (1194) all_30_7_48 = all_22_0_27
% 66.93/29.08  																																																																														|
% 66.93/29.08  																																																																															| Combining equations (331,1194) yields a new equation:
% 66.93/29.08  																																																																															| (554) all_22_0_27 = 0
% 66.93/29.08  																																																																															|
% 66.93/29.08  																																																																															| From (554) and (1193) follows:
% 66.93/29.08  																																																																															| (36) aNaturalNumber0(xm) = 0
% 66.93/29.08  																																																																															|
% 66.93/29.08  																																																																															+-Applying beta-rule and splitting (327), into two cases.
% 66.93/29.08  																																																																															|-Branch one:
% 66.93/29.08  																																																																															| (1197)  ~ (aNaturalNumber0(xp) = all_41_2_56)
% 66.93/29.08  																																																																															|
% 66.93/29.08  																																																																																| From (253) and (1197) follows:
% 66.93/29.08  																																																																																| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.08  																																																																																|
% 66.93/29.08  																																																																																| Using (12) and (1198) yields:
% 66.93/29.08  																																																																																| (615) $false
% 66.93/29.08  																																																																																|
% 66.93/29.08  																																																																																|-The branch is then unsatisfiable
% 66.93/29.08  																																																																															|-Branch two:
% 66.93/29.08  																																																																															| (1200) aNaturalNumber0(xp) = all_41_2_56
% 66.93/29.08  																																																																															| (1201) all_41_2_56 = all_16_1_13
% 66.93/29.08  																																																																															|
% 66.93/29.08  																																																																																| Combining equations (253,1201) yields a new equation:
% 66.93/29.08  																																																																																| (497) all_16_1_13 = 0
% 66.93/29.08  																																																																																|
% 66.93/29.08  																																																																																| Combining equations (497,1201) yields a new equation:
% 66.93/29.08  																																																																																| (253) all_41_2_56 = 0
% 66.93/29.08  																																																																																|
% 66.93/29.08  																																																																																| From (253) and (1200) follows:
% 66.93/29.08  																																																																																| (12) aNaturalNumber0(xp) = 0
% 66.93/29.08  																																																																																|
% 66.93/29.08  																																																																																+-Applying beta-rule and splitting (324), into two cases.
% 66.93/29.08  																																																																																|-Branch one:
% 66.93/29.08  																																																																																| (1205)  ~ (aNaturalNumber0(xp) = all_26_2_37)
% 66.93/29.08  																																																																																|
% 66.93/29.08  																																																																																	| From (572) and (1205) follows:
% 66.93/29.08  																																																																																	| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.08  																																																																																	|
% 66.93/29.08  																																																																																	| Using (12) and (1198) yields:
% 66.93/29.08  																																																																																	| (615) $false
% 66.93/29.08  																																																																																	|
% 66.93/29.08  																																																																																	|-The branch is then unsatisfiable
% 66.93/29.08  																																																																																|-Branch two:
% 66.93/29.08  																																																																																| (1208) aNaturalNumber0(xp) = all_26_2_37
% 66.93/29.09  																																																																																| (1209) all_26_2_37 = all_16_1_13
% 66.93/29.09  																																																																																|
% 66.93/29.09  																																																																																	| Combining equations (572,1209) yields a new equation:
% 66.93/29.09  																																																																																	| (497) all_16_1_13 = 0
% 66.93/29.09  																																																																																	|
% 66.93/29.09  																																																																																	| Combining equations (497,1209) yields a new equation:
% 66.93/29.09  																																																																																	| (572) all_26_2_37 = 0
% 66.93/29.09  																																																																																	|
% 66.93/29.09  																																																																																	| From (572) and (1208) follows:
% 66.93/29.09  																																																																																	| (12) aNaturalNumber0(xp) = 0
% 66.93/29.09  																																																																																	|
% 66.93/29.09  																																																																																	+-Applying beta-rule and splitting (316), into two cases.
% 66.93/29.09  																																																																																	|-Branch one:
% 66.93/29.09  																																																																																	| (1213)  ~ (aNaturalNumber0(xp) = all_26_0_35)
% 66.93/29.09  																																																																																	|
% 66.93/29.09  																																																																																		| From (594) and (1213) follows:
% 66.93/29.09  																																																																																		| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.09  																																																																																		|
% 66.93/29.09  																																																																																		| Using (12) and (1198) yields:
% 66.93/29.09  																																																																																		| (615) $false
% 66.93/29.09  																																																																																		|
% 66.93/29.09  																																																																																		|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																	|-Branch two:
% 66.93/29.09  																																																																																	| (1216) aNaturalNumber0(xp) = all_26_0_35
% 66.93/29.09  																																																																																	| (1217) all_26_0_35 = all_24_2_32
% 66.93/29.09  																																																																																	|
% 66.93/29.09  																																																																																		| Combining equations (594,1217) yields a new equation:
% 66.93/29.09  																																																																																		| (493) all_24_2_32 = 0
% 66.93/29.09  																																																																																		|
% 66.93/29.09  																																																																																		| Combining equations (493,1217) yields a new equation:
% 66.93/29.09  																																																																																		| (594) all_26_0_35 = 0
% 66.93/29.09  																																																																																		|
% 66.93/29.09  																																																																																		| From (594) and (1216) follows:
% 66.93/29.09  																																																																																		| (12) aNaturalNumber0(xp) = 0
% 66.93/29.09  																																																																																		|
% 66.93/29.09  																																																																																		+-Applying beta-rule and splitting (404), into two cases.
% 66.93/29.09  																																																																																		|-Branch one:
% 66.93/29.09  																																																																																		| (1143)  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 66.93/29.09  																																																																																		|
% 66.93/29.09  																																																																																			| From (515) and (1143) follows:
% 66.93/29.09  																																																																																			| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.09  																																																																																			|
% 66.93/29.09  																																																																																			| Using (53) and (1144) yields:
% 66.93/29.09  																																																																																			| (615) $false
% 66.93/29.09  																																																																																			|
% 66.93/29.09  																																																																																			|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																		|-Branch two:
% 66.93/29.09  																																																																																		| (1146) aNaturalNumber0(xn) = all_28_1_39
% 66.93/29.09  																																																																																		| (1225) all_30_8_49 = all_28_1_39
% 66.93/29.09  																																																																																		|
% 66.93/29.09  																																																																																			| Combining equations (516,1225) yields a new equation:
% 66.93/29.09  																																																																																			| (515) all_28_1_39 = 0
% 66.93/29.09  																																																																																			|
% 66.93/29.09  																																																																																			| Combining equations (515,1225) yields a new equation:
% 66.93/29.09  																																																																																			| (516) all_30_8_49 = 0
% 66.93/29.09  																																																																																			|
% 66.93/29.09  																																																																																			| From (515) and (1146) follows:
% 66.93/29.09  																																																																																			| (53) aNaturalNumber0(xn) = 0
% 66.93/29.09  																																																																																			|
% 66.93/29.09  																																																																																			+-Applying beta-rule and splitting (430), into two cases.
% 66.93/29.09  																																																																																			|-Branch one:
% 66.93/29.09  																																																																																			| (1229)  ~ (aNaturalNumber0(xn) = all_36_2_52)
% 66.93/29.09  																																																																																			|
% 66.93/29.09  																																																																																				| From (979) and (1229) follows:
% 66.93/29.09  																																																																																				| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.09  																																																																																				|
% 66.93/29.09  																																																																																				| Using (53) and (1144) yields:
% 66.93/29.09  																																																																																				| (615) $false
% 66.93/29.09  																																																																																				|
% 66.93/29.09  																																																																																				|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																			|-Branch two:
% 66.93/29.09  																																																																																			| (1232) aNaturalNumber0(xn) = all_36_2_52
% 66.93/29.09  																																																																																			| (1233) all_36_2_52 = all_24_4_34
% 66.93/29.09  																																																																																			|
% 66.93/29.09  																																																																																				| Combining equations (979,1233) yields a new equation:
% 66.93/29.09  																																																																																				| (511) all_24_4_34 = 0
% 66.93/29.09  																																																																																				|
% 66.93/29.09  																																																																																				| Combining equations (511,1233) yields a new equation:
% 66.93/29.09  																																																																																				| (979) all_36_2_52 = 0
% 66.93/29.09  																																																																																				|
% 66.93/29.09  																																																																																				| From (979) and (1232) follows:
% 66.93/29.09  																																																																																				| (53) aNaturalNumber0(xn) = 0
% 66.93/29.09  																																																																																				|
% 66.93/29.09  																																																																																				+-Applying beta-rule and splitting (302), into two cases.
% 66.93/29.09  																																																																																				|-Branch one:
% 66.93/29.09  																																																																																				| (1237)  ~ (aNaturalNumber0(xp) = all_41_1_55)
% 66.93/29.09  																																																																																				|
% 66.93/29.09  																																																																																					| From (980) and (1237) follows:
% 66.93/29.09  																																																																																					| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.09  																																																																																					|
% 66.93/29.09  																																																																																					| Using (12) and (1198) yields:
% 66.93/29.09  																																																																																					| (615) $false
% 66.93/29.09  																																																																																					|
% 66.93/29.09  																																																																																					|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																				|-Branch two:
% 66.93/29.09  																																																																																				| (1240) aNaturalNumber0(xp) = all_41_1_55
% 66.93/29.09  																																																																																				| (1241) all_41_1_55 = all_30_6_47
% 66.93/29.09  																																																																																				|
% 66.93/29.09  																																																																																					| Combining equations (980,1241) yields a new equation:
% 66.93/29.09  																																																																																					| (1242) all_30_6_47 = 0
% 66.93/29.09  																																																																																					|
% 66.93/29.09  																																																																																					| Combining equations (1242,1241) yields a new equation:
% 66.93/29.09  																																																																																					| (980) all_41_1_55 = 0
% 66.93/29.09  																																																																																					|
% 66.93/29.09  																																																																																					| From (980) and (1240) follows:
% 66.93/29.09  																																																																																					| (12) aNaturalNumber0(xp) = 0
% 66.93/29.09  																																																																																					|
% 66.93/29.09  																																																																																					+-Applying beta-rule and splitting (228), into two cases.
% 66.93/29.09  																																																																																					|-Branch one:
% 66.93/29.09  																																																																																					| (1245)  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 66.93/29.09  																																																																																					|
% 66.93/29.09  																																																																																						| From (572) and (1245) follows:
% 66.93/29.09  																																																																																						| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.09  																																																																																						|
% 66.93/29.09  																																																																																						| Using (53) and (1144) yields:
% 66.93/29.09  																																																																																						| (615) $false
% 66.93/29.09  																																																																																						|
% 66.93/29.09  																																																																																						|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																					|-Branch two:
% 66.93/29.09  																																																																																					| (1248) aNaturalNumber0(xn) = all_26_2_37
% 66.93/29.09  																																																																																					| (572) all_26_2_37 = 0
% 66.93/29.09  																																																																																					|
% 66.93/29.09  																																																																																						| From (572) and (1248) follows:
% 66.93/29.09  																																																																																						| (53) aNaturalNumber0(xn) = 0
% 66.93/29.09  																																																																																						|
% 66.93/29.09  																																																																																						+-Applying beta-rule and splitting (386), into two cases.
% 66.93/29.09  																																																																																						|-Branch one:
% 66.93/29.09  																																																																																						| (1251)  ~ (aNaturalNumber0(sz10) = all_12_1_7)
% 66.93/29.09  																																																																																						|
% 66.93/29.09  																																																																																							| From (507) and (1251) follows:
% 66.93/29.09  																																																																																							| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 66.93/29.09  																																																																																							|
% 66.93/29.09  																																																																																							| Using (16) and (1252) yields:
% 66.93/29.09  																																																																																							| (615) $false
% 66.93/29.09  																																																																																							|
% 66.93/29.09  																																																																																							|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																						|-Branch two:
% 66.93/29.09  																																																																																						| (1254) aNaturalNumber0(sz10) = all_12_1_7
% 66.93/29.09  																																																																																						| (507) all_12_1_7 = 0
% 66.93/29.09  																																																																																						|
% 66.93/29.09  																																																																																							| From (507) and (1254) follows:
% 66.93/29.09  																																																																																							| (16) aNaturalNumber0(sz10) = 0
% 66.93/29.09  																																																																																							|
% 66.93/29.09  																																																																																							+-Applying beta-rule and splitting (232), into two cases.
% 66.93/29.09  																																																																																							|-Branch one:
% 66.93/29.09  																																																																																							| (1257)  ~ (aNaturalNumber0(all_0_5_5) = all_22_0_27)
% 66.93/29.09  																																																																																							|
% 66.93/29.09  																																																																																								| From (554) and (1257) follows:
% 66.93/29.09  																																																																																								| (1258)  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 66.93/29.09  																																																																																								|
% 66.93/29.09  																																																																																								| Using (573) and (1258) yields:
% 66.93/29.09  																																																																																								| (615) $false
% 66.93/29.09  																																																																																								|
% 66.93/29.09  																																																																																								|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																							|-Branch two:
% 66.93/29.09  																																																																																							| (1260) aNaturalNumber0(all_0_5_5) = all_22_0_27
% 66.93/29.09  																																																																																							| (1261) all_26_2_37 = all_22_0_27
% 66.93/29.09  																																																																																							|
% 66.93/29.09  																																																																																								| Combining equations (572,1261) yields a new equation:
% 66.93/29.09  																																																																																								| (554) all_22_0_27 = 0
% 66.93/29.09  																																																																																								|
% 66.93/29.09  																																																																																								| Combining equations (554,1261) yields a new equation:
% 66.93/29.09  																																																																																								| (572) all_26_2_37 = 0
% 66.93/29.09  																																																																																								|
% 66.93/29.09  																																																																																								| From (554) and (1260) follows:
% 66.93/29.09  																																																																																								| (573) aNaturalNumber0(all_0_5_5) = 0
% 66.93/29.09  																																																																																								|
% 66.93/29.09  																																																																																								+-Applying beta-rule and splitting (277), into two cases.
% 66.93/29.09  																																																																																								|-Branch one:
% 66.93/29.09  																																																																																								| (1265)  ~ (aNaturalNumber0(xk) = all_22_0_27)
% 66.93/29.09  																																																																																								|
% 66.93/29.09  																																																																																									| From (554) and (1265) follows:
% 66.93/29.09  																																																																																									| (974)  ~ (aNaturalNumber0(xk) = 0)
% 66.93/29.09  																																																																																									|
% 66.93/29.09  																																																																																									| Using (972) and (974) yields:
% 66.93/29.09  																																																																																									| (615) $false
% 66.93/29.09  																																																																																									|
% 66.93/29.09  																																																																																									|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																								|-Branch two:
% 66.93/29.09  																																																																																								| (1268) aNaturalNumber0(xk) = all_22_0_27
% 66.93/29.09  																																																																																								| (1269) all_41_1_55 = all_22_0_27
% 66.93/29.09  																																																																																								|
% 66.93/29.09  																																																																																									| Combining equations (980,1269) yields a new equation:
% 66.93/29.09  																																																																																									| (554) all_22_0_27 = 0
% 66.93/29.09  																																																																																									|
% 66.93/29.09  																																																																																									| From (554) and (1268) follows:
% 66.93/29.09  																																																																																									| (972) aNaturalNumber0(xk) = 0
% 66.93/29.09  																																																																																									|
% 66.93/29.09  																																																																																									+-Applying beta-rule and splitting (301), into two cases.
% 66.93/29.09  																																																																																									|-Branch one:
% 66.93/29.09  																																																																																									| (1272)  ~ (aNaturalNumber0(xp) = all_36_3_53)
% 66.93/29.09  																																																																																									|
% 66.93/29.09  																																																																																										| From (480) and (1272) follows:
% 66.93/29.09  																																																																																										| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.09  																																																																																										|
% 66.93/29.09  																																																																																										| Using (12) and (1198) yields:
% 66.93/29.09  																																																																																										| (615) $false
% 66.93/29.09  																																																																																										|
% 66.93/29.09  																																																																																										|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																									|-Branch two:
% 66.93/29.09  																																																																																									| (1275) aNaturalNumber0(xp) = all_36_3_53
% 66.93/29.09  																																																																																									| (1276) all_36_3_53 = all_30_6_47
% 66.93/29.09  																																																																																									|
% 66.93/29.09  																																																																																										| Combining equations (480,1276) yields a new equation:
% 66.93/29.09  																																																																																										| (1242) all_30_6_47 = 0
% 66.93/29.09  																																																																																										|
% 66.93/29.09  																																																																																										| Combining equations (1242,1276) yields a new equation:
% 66.93/29.09  																																																																																										| (480) all_36_3_53 = 0
% 66.93/29.09  																																																																																										|
% 66.93/29.09  																																																																																										| From (480) and (1275) follows:
% 66.93/29.09  																																																																																										| (12) aNaturalNumber0(xp) = 0
% 66.93/29.09  																																																																																										|
% 66.93/29.09  																																																																																										+-Applying beta-rule and splitting (284), into two cases.
% 66.93/29.09  																																																																																										|-Branch one:
% 66.93/29.09  																																																																																										| (1280)  ~ (aNaturalNumber0(xp) = all_36_2_52)
% 66.93/29.09  																																																																																										|
% 66.93/29.09  																																																																																											| From (979) and (1280) follows:
% 66.93/29.09  																																																																																											| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.09  																																																																																											|
% 66.93/29.09  																																																																																											| Using (12) and (1198) yields:
% 66.93/29.09  																																																																																											| (615) $false
% 66.93/29.09  																																																																																											|
% 66.93/29.09  																																																																																											|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																										|-Branch two:
% 66.93/29.09  																																																																																										| (1283) aNaturalNumber0(xp) = all_36_2_52
% 66.93/29.09  																																																																																										| (979) all_36_2_52 = 0
% 66.93/29.09  																																																																																										|
% 66.93/29.09  																																																																																											| From (979) and (1283) follows:
% 66.93/29.09  																																																																																											| (12) aNaturalNumber0(xp) = 0
% 66.93/29.09  																																																																																											|
% 66.93/29.09  																																																																																											+-Applying beta-rule and splitting (260), into two cases.
% 66.93/29.09  																																																																																											|-Branch one:
% 66.93/29.09  																																																																																											| (1286)  ~ (aNaturalNumber0(xr) = all_26_2_37)
% 66.93/29.09  																																																																																											|
% 66.93/29.09  																																																																																												| From (572) and (1286) follows:
% 66.93/29.09  																																																																																												| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 66.93/29.09  																																																																																												|
% 66.93/29.09  																																																																																												| Using (10) and (1287) yields:
% 66.93/29.09  																																																																																												| (615) $false
% 66.93/29.09  																																																																																												|
% 66.93/29.09  																																																																																												|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																											|-Branch two:
% 66.93/29.09  																																																																																											| (1289) aNaturalNumber0(xr) = all_26_2_37
% 66.93/29.09  																																																																																											| (1290) all_41_2_56 = all_26_2_37
% 66.93/29.09  																																																																																											|
% 66.93/29.09  																																																																																												| Combining equations (253,1290) yields a new equation:
% 66.93/29.09  																																																																																												| (572) all_26_2_37 = 0
% 66.93/29.09  																																																																																												|
% 66.93/29.09  																																																																																												| Combining equations (572,1290) yields a new equation:
% 66.93/29.09  																																																																																												| (253) all_41_2_56 = 0
% 66.93/29.09  																																																																																												|
% 66.93/29.09  																																																																																												| From (572) and (1289) follows:
% 66.93/29.09  																																																																																												| (10) aNaturalNumber0(xr) = 0
% 66.93/29.09  																																																																																												|
% 66.93/29.09  																																																																																												+-Applying beta-rule and splitting (449), into two cases.
% 66.93/29.09  																																																																																												|-Branch one:
% 66.93/29.09  																																																																																												| (1294)  ~ (aNaturalNumber0(xn) = all_14_1_10)
% 66.93/29.09  																																																																																												|
% 66.93/29.09  																																																																																													| From (503) and (1294) follows:
% 66.93/29.09  																																																																																													| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.09  																																																																																													|
% 66.93/29.09  																																																																																													| Using (53) and (1144) yields:
% 66.93/29.09  																																																																																													| (615) $false
% 66.93/29.09  																																																																																													|
% 66.93/29.09  																																																																																													|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																												|-Branch two:
% 66.93/29.09  																																																																																												| (1297) aNaturalNumber0(xn) = all_14_1_10
% 66.93/29.09  																																																																																												| (1298) all_22_2_29 = all_14_1_10
% 66.93/29.09  																																																																																												|
% 66.93/29.09  																																																																																													| Combining equations (1298,510) yields a new equation:
% 66.93/29.09  																																																																																													| (502) all_14_1_10 = 0
% 66.93/29.09  																																																																																													|
% 66.93/29.09  																																																																																													| Simplifying 502 yields:
% 66.93/29.09  																																																																																													| (503) all_14_1_10 = 0
% 66.93/29.09  																																																																																													|
% 66.93/29.09  																																																																																													| From (503) and (1297) follows:
% 66.93/29.09  																																																																																													| (53) aNaturalNumber0(xn) = 0
% 66.93/29.09  																																																																																													|
% 66.93/29.09  																																																																																													+-Applying beta-rule and splitting (239), into two cases.
% 66.93/29.09  																																																																																													|-Branch one:
% 66.93/29.09  																																																																																													| (1258)  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 66.93/29.09  																																																																																													|
% 66.93/29.09  																																																																																														| Using (573) and (1258) yields:
% 66.93/29.09  																																																																																														| (615) $false
% 66.93/29.09  																																																																																														|
% 66.93/29.09  																																																																																														|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																													|-Branch two:
% 66.93/29.09  																																																																																													| (573) aNaturalNumber0(all_0_5_5) = 0
% 66.93/29.09  																																																																																													| (571) all_16_2_14 = 0
% 66.93/29.09  																																																																																													|
% 66.93/29.09  																																																																																														+-Applying beta-rule and splitting (369), into two cases.
% 66.93/29.09  																																																																																														|-Branch one:
% 66.93/29.09  																																																																																														| (1306)  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 66.93/29.09  																																																																																														|
% 66.93/29.09  																																																																																															| From (570) and (1306) follows:
% 66.93/29.09  																																																																																															| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.09  																																																																																															|
% 66.93/29.09  																																																																																															| Using (36) and (1191) yields:
% 66.93/29.09  																																																																																															| (615) $false
% 66.93/29.09  																																																																																															|
% 66.93/29.09  																																																																																															|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																														|-Branch two:
% 66.93/29.09  																																																																																														| (1309) aNaturalNumber0(xm) = all_12_0_6
% 66.93/29.09  																																																																																														| (1310) all_22_1_28 = all_12_0_6
% 66.93/29.09  																																																																																														|
% 66.93/29.09  																																																																																															| Combining equations (499,1310) yields a new equation:
% 66.93/29.09  																																																																																															| (570) all_12_0_6 = 0
% 66.93/29.09  																																																																																															|
% 66.93/29.09  																																																																																															| Combining equations (570,1310) yields a new equation:
% 66.93/29.09  																																																																																															| (499) all_22_1_28 = 0
% 66.93/29.09  																																																																																															|
% 66.93/29.09  																																																																																															| From (570) and (1309) follows:
% 66.93/29.09  																																																																																															| (36) aNaturalNumber0(xm) = 0
% 66.93/29.09  																																																																																															|
% 66.93/29.09  																																																																																															+-Applying beta-rule and splitting (358), into two cases.
% 66.93/29.09  																																																																																															|-Branch one:
% 66.93/29.09  																																																																																															| (1314)  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 66.93/29.09  																																																																																															|
% 66.93/29.09  																																																																																																| From (253) and (1314) follows:
% 66.93/29.09  																																																																																																| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.09  																																																																																																|
% 66.93/29.09  																																																																																																| Using (36) and (1191) yields:
% 66.93/29.09  																																																																																																| (615) $false
% 66.93/29.09  																																																																																																|
% 66.93/29.09  																																																																																																|-The branch is then unsatisfiable
% 66.93/29.09  																																																																																															|-Branch two:
% 66.93/29.09  																																																																																															| (1317) aNaturalNumber0(xm) = all_41_2_56
% 66.93/29.09  																																																																																															| (1318) all_41_2_56 = all_24_3_33
% 66.93/29.09  																																																																																															|
% 66.93/29.09  																																																																																																| Combining equations (253,1318) yields a new equation:
% 66.93/29.09  																																																																																																| (483) all_24_3_33 = 0
% 66.93/29.09  																																																																																																|
% 66.93/29.09  																																																																																																| Combining equations (483,1318) yields a new equation:
% 66.93/29.09  																																																																																																| (253) all_41_2_56 = 0
% 66.93/29.09  																																																																																																|
% 66.93/29.09  																																																																																																| From (253) and (1317) follows:
% 66.93/29.10  																																																																																																| (36) aNaturalNumber0(xm) = 0
% 66.93/29.10  																																																																																																|
% 66.93/29.10  																																																																																																+-Applying beta-rule and splitting (249), into two cases.
% 66.93/29.10  																																																																																																|-Branch one:
% 66.93/29.10  																																																																																																| (1322)  ~ (aNaturalNumber0(all_0_5_5) = all_36_1_51)
% 66.93/29.10  																																																																																																|
% 66.93/29.10  																																																																																																	| From (555) and (1322) follows:
% 66.93/29.10  																																																																																																	| (1258)  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 66.93/29.10  																																																																																																	|
% 66.93/29.10  																																																																																																	| Using (573) and (1258) yields:
% 66.93/29.10  																																																																																																	| (615) $false
% 66.93/29.10  																																																																																																	|
% 66.93/29.10  																																																																																																	|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																|-Branch two:
% 66.93/29.10  																																																																																																| (1325) aNaturalNumber0(all_0_5_5) = all_36_1_51
% 66.93/29.10  																																																																																																| (1326) all_36_1_51 = all_12_0_6
% 66.93/29.10  																																																																																																|
% 66.93/29.10  																																																																																																	| Combining equations (555,1326) yields a new equation:
% 66.93/29.10  																																																																																																	| (570) all_12_0_6 = 0
% 66.93/29.10  																																																																																																	|
% 66.93/29.10  																																																																																																	| Combining equations (570,1326) yields a new equation:
% 66.93/29.10  																																																																																																	| (555) all_36_1_51 = 0
% 66.93/29.10  																																																																																																	|
% 66.93/29.10  																																																																																																	| From (555) and (1325) follows:
% 66.93/29.10  																																																																																																	| (573) aNaturalNumber0(all_0_5_5) = 0
% 66.93/29.10  																																																																																																	|
% 66.93/29.10  																																																																																																	+-Applying beta-rule and splitting (340), into two cases.
% 66.93/29.10  																																																																																																	|-Branch one:
% 66.93/29.10  																																																																																																	| (1330)  ~ (aNaturalNumber0(xm) = all_36_3_53)
% 66.93/29.10  																																																																																																	|
% 66.93/29.10  																																																																																																		| From (480) and (1330) follows:
% 66.93/29.10  																																																																																																		| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.10  																																																																																																		|
% 66.93/29.10  																																																																																																		| Using (36) and (1191) yields:
% 66.93/29.10  																																																																																																		| (615) $false
% 66.93/29.10  																																																																																																		|
% 66.93/29.10  																																																																																																		|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																	|-Branch two:
% 66.93/29.10  																																																																																																	| (1333) aNaturalNumber0(xm) = all_36_3_53
% 66.93/29.10  																																																																																																	| (1334) all_36_3_53 = all_30_7_48
% 66.93/29.10  																																																																																																	|
% 66.93/29.10  																																																																																																		| Combining equations (480,1334) yields a new equation:
% 66.93/29.10  																																																																																																		| (331) all_30_7_48 = 0
% 66.93/29.10  																																																																																																		|
% 66.93/29.10  																																																																																																		| Combining equations (331,1334) yields a new equation:
% 66.93/29.10  																																																																																																		| (480) all_36_3_53 = 0
% 66.93/29.10  																																																																																																		|
% 66.93/29.10  																																																																																																		| From (480) and (1333) follows:
% 66.93/29.10  																																																																																																		| (36) aNaturalNumber0(xm) = 0
% 66.93/29.10  																																																																																																		|
% 66.93/29.10  																																																																																																		+-Applying beta-rule and splitting (393), into two cases.
% 66.93/29.10  																																																																																																		|-Branch one:
% 66.93/29.10  																																																																																																		| (1338)  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 66.93/29.10  																																																																																																		|
% 66.93/29.10  																																																																																																			| From (979) and (1338) follows:
% 66.93/29.10  																																																																																																			| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.10  																																																																																																			|
% 66.93/29.10  																																																																																																			| Using (36) and (1191) yields:
% 66.93/29.10  																																																																																																			| (615) $false
% 66.93/29.10  																																																																																																			|
% 66.93/29.10  																																																																																																			|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																		|-Branch two:
% 66.93/29.10  																																																																																																		| (1341) aNaturalNumber0(xm) = all_36_2_52
% 66.93/29.10  																																																																																																		| (1342) all_36_2_52 = all_12_1_7
% 66.93/29.10  																																																																																																		|
% 66.93/29.10  																																																																																																			| Combining equations (979,1342) yields a new equation:
% 66.93/29.10  																																																																																																			| (507) all_12_1_7 = 0
% 66.93/29.10  																																																																																																			|
% 66.93/29.10  																																																																																																			| Combining equations (507,1342) yields a new equation:
% 66.93/29.10  																																																																																																			| (979) all_36_2_52 = 0
% 66.93/29.10  																																																																																																			|
% 66.93/29.10  																																																																																																			| From (979) and (1341) follows:
% 66.93/29.10  																																																																																																			| (36) aNaturalNumber0(xm) = 0
% 66.93/29.10  																																																																																																			|
% 66.93/29.10  																																																																																																			+-Applying beta-rule and splitting (338), into two cases.
% 66.93/29.10  																																																																																																			|-Branch one:
% 66.93/29.10  																																																																																																			| (1306)  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 66.93/29.10  																																																																																																			|
% 66.93/29.10  																																																																																																				| From (570) and (1306) follows:
% 66.93/29.10  																																																																																																				| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.10  																																																																																																				|
% 66.93/29.10  																																																																																																				| Using (36) and (1191) yields:
% 66.93/29.10  																																																																																																				| (615) $false
% 66.93/29.10  																																																																																																				|
% 66.93/29.10  																																																																																																				|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																			|-Branch two:
% 66.93/29.10  																																																																																																			| (1309) aNaturalNumber0(xm) = all_12_0_6
% 66.93/29.10  																																																																																																			| (1350) all_30_7_48 = all_12_0_6
% 66.93/29.10  																																																																																																			|
% 66.93/29.10  																																																																																																				| Combining equations (331,1350) yields a new equation:
% 66.93/29.10  																																																																																																				| (570) all_12_0_6 = 0
% 66.93/29.10  																																																																																																				|
% 66.93/29.10  																																																																																																				| Combining equations (570,1350) yields a new equation:
% 66.93/29.10  																																																																																																				| (331) all_30_7_48 = 0
% 66.93/29.10  																																																																																																				|
% 66.93/29.10  																																																																																																				| From (570) and (1309) follows:
% 66.93/29.10  																																																																																																				| (36) aNaturalNumber0(xm) = 0
% 66.93/29.10  																																																																																																				|
% 66.93/29.10  																																																																																																				+-Applying beta-rule and splitting (396), into two cases.
% 66.93/29.10  																																																																																																				|-Branch one:
% 66.93/29.10  																																																																																																				| (1354)  ~ (aNaturalNumber0(xn) = all_26_0_35)
% 66.93/29.10  																																																																																																				|
% 66.93/29.10  																																																																																																					| From (594) and (1354) follows:
% 66.93/29.10  																																																																																																					| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.10  																																																																																																					|
% 66.93/29.10  																																																																																																					| Using (53) and (1144) yields:
% 66.93/29.10  																																																																																																					| (615) $false
% 66.93/29.10  																																																																																																					|
% 66.93/29.10  																																																																																																					|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																				|-Branch two:
% 66.93/29.10  																																																																																																				| (1357) aNaturalNumber0(xn) = all_26_0_35
% 66.93/29.10  																																																																																																				| (1358) all_30_8_49 = all_26_0_35
% 66.93/29.10  																																																																																																				|
% 66.93/29.10  																																																																																																					| Combining equations (516,1358) yields a new equation:
% 66.93/29.10  																																																																																																					| (594) all_26_0_35 = 0
% 66.93/29.10  																																																																																																					|
% 66.93/29.10  																																																																																																					| Combining equations (594,1358) yields a new equation:
% 66.93/29.10  																																																																																																					| (516) all_30_8_49 = 0
% 66.93/29.10  																																																																																																					|
% 66.93/29.10  																																																																																																					| From (594) and (1357) follows:
% 66.93/29.10  																																																																																																					| (53) aNaturalNumber0(xn) = 0
% 66.93/29.10  																																																																																																					|
% 66.93/29.10  																																																																																																					+-Applying beta-rule and splitting (357), into two cases.
% 66.93/29.10  																																																																																																					|-Branch one:
% 66.93/29.10  																																																																																																					| (1306)  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 66.93/29.10  																																																																																																					|
% 66.93/29.10  																																																																																																						| From (570) and (1306) follows:
% 66.93/29.10  																																																																																																						| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.10  																																																																																																						|
% 66.93/29.10  																																																																																																						| Using (36) and (1191) yields:
% 66.93/29.10  																																																																																																						| (615) $false
% 66.93/29.10  																																																																																																						|
% 66.93/29.10  																																																																																																						|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																					|-Branch two:
% 66.93/29.10  																																																																																																					| (1309) aNaturalNumber0(xm) = all_12_0_6
% 66.93/29.10  																																																																																																					| (1366) all_24_3_33 = all_12_0_6
% 66.93/29.10  																																																																																																					|
% 66.93/29.10  																																																																																																						| Combining equations (483,1366) yields a new equation:
% 66.93/29.10  																																																																																																						| (570) all_12_0_6 = 0
% 66.93/29.10  																																																																																																						|
% 66.93/29.10  																																																																																																						| Combining equations (570,1366) yields a new equation:
% 66.93/29.10  																																																																																																						| (483) all_24_3_33 = 0
% 66.93/29.10  																																																																																																						|
% 66.93/29.10  																																																																																																						| From (570) and (1309) follows:
% 66.93/29.10  																																																																																																						| (36) aNaturalNumber0(xm) = 0
% 66.93/29.10  																																																																																																						|
% 66.93/29.10  																																																																																																						+-Applying beta-rule and splitting (454), into two cases.
% 66.93/29.10  																																																																																																						|-Branch one:
% 66.93/29.10  																																																																																																						| (1370)  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 66.93/29.10  																																																																																																						|
% 66.93/29.10  																																																																																																							| From (555) and (1370) follows:
% 66.93/29.10  																																																																																																							| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.10  																																																																																																							|
% 66.93/29.10  																																																																																																							| Using (53) and (1144) yields:
% 66.93/29.10  																																																																																																							| (615) $false
% 66.93/29.10  																																																																																																							|
% 66.93/29.10  																																																																																																							|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																						|-Branch two:
% 66.93/29.10  																																																																																																						| (1373) aNaturalNumber0(xn) = all_36_1_51
% 66.93/29.10  																																																																																																						| (1374) all_36_1_51 = all_14_2_11
% 66.93/29.10  																																																																																																						|
% 66.93/29.10  																																																																																																							| Combining equations (555,1374) yields a new equation:
% 66.93/29.10  																																																																																																							| (451) all_14_2_11 = 0
% 66.93/29.10  																																																																																																							|
% 66.93/29.10  																																																																																																							| Combining equations (451,1374) yields a new equation:
% 66.93/29.10  																																																																																																							| (555) all_36_1_51 = 0
% 66.93/29.10  																																																																																																							|
% 66.93/29.10  																																																																																																							| From (555) and (1373) follows:
% 66.93/29.10  																																																																																																							| (53) aNaturalNumber0(xn) = 0
% 66.93/29.10  																																																																																																							|
% 66.93/29.10  																																																																																																							+-Applying beta-rule and splitting (347), into two cases.
% 66.93/29.10  																																																																																																							|-Branch one:
% 66.93/29.10  																																																																																																							| (1314)  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 66.93/29.10  																																																																																																							|
% 66.93/29.10  																																																																																																								| From (253) and (1314) follows:
% 66.93/29.10  																																																																																																								| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.10  																																																																																																								|
% 66.93/29.10  																																																																																																								| Using (36) and (1191) yields:
% 66.93/29.10  																																																																																																								| (615) $false
% 66.93/29.10  																																																																																																								|
% 66.93/29.10  																																																																																																								|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																							|-Branch two:
% 66.93/29.10  																																																																																																							| (1317) aNaturalNumber0(xm) = all_41_2_56
% 66.93/29.10  																																																																																																							| (1382) all_41_2_56 = all_28_1_39
% 66.93/29.10  																																																																																																							|
% 66.93/29.10  																																																																																																								| Combining equations (253,1382) yields a new equation:
% 66.93/29.10  																																																																																																								| (515) all_28_1_39 = 0
% 66.93/29.10  																																																																																																								|
% 66.93/29.10  																																																																																																								| Combining equations (515,1382) yields a new equation:
% 66.93/29.10  																																																																																																								| (253) all_41_2_56 = 0
% 66.93/29.10  																																																																																																								|
% 66.93/29.10  																																																																																																								| From (253) and (1317) follows:
% 66.93/29.10  																																																																																																								| (36) aNaturalNumber0(xm) = 0
% 66.93/29.10  																																																																																																								|
% 66.93/29.10  																																																																																																								+-Applying beta-rule and splitting (390), into two cases.
% 66.93/29.10  																																																																																																								|-Branch one:
% 66.93/29.10  																																																																																																								| (1386)  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 66.93/29.10  																																																																																																								|
% 66.93/29.10  																																																																																																									| From (572) and (1386) follows:
% 66.93/29.10  																																																																																																									| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.10  																																																																																																									|
% 66.93/29.10  																																																																																																									| Using (36) and (1191) yields:
% 66.93/29.10  																																																																																																									| (615) $false
% 66.93/29.10  																																																																																																									|
% 66.93/29.10  																																																																																																									|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																								|-Branch two:
% 66.93/29.10  																																																																																																								| (1389) aNaturalNumber0(xm) = all_26_2_37
% 66.93/29.10  																																																																																																								| (1390) all_26_2_37 = all_12_1_7
% 66.93/29.10  																																																																																																								|
% 66.93/29.10  																																																																																																									| Combining equations (572,1390) yields a new equation:
% 66.93/29.10  																																																																																																									| (507) all_12_1_7 = 0
% 66.93/29.10  																																																																																																									|
% 66.93/29.10  																																																																																																									| Combining equations (507,1390) yields a new equation:
% 66.93/29.10  																																																																																																									| (572) all_26_2_37 = 0
% 66.93/29.10  																																																																																																									|
% 66.93/29.10  																																																																																																									| From (572) and (1389) follows:
% 66.93/29.10  																																																																																																									| (36) aNaturalNumber0(xm) = 0
% 66.93/29.10  																																																																																																									|
% 66.93/29.10  																																																																																																									+-Applying beta-rule and splitting (376), into two cases.
% 66.93/29.10  																																																																																																									|-Branch one:
% 66.93/29.10  																																																																																																									| (1190)  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 66.93/29.10  																																																																																																									|
% 66.93/29.10  																																																																																																										| From (554) and (1190) follows:
% 66.93/29.10  																																																																																																										| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.10  																																																																																																										|
% 66.93/29.10  																																																																																																										| Using (36) and (1191) yields:
% 66.93/29.10  																																																																																																										| (615) $false
% 66.93/29.10  																																																																																																										|
% 66.93/29.10  																																																																																																										|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																									|-Branch two:
% 66.93/29.10  																																																																																																									| (1193) aNaturalNumber0(xm) = all_22_0_27
% 66.93/29.10  																																																																																																									| (1398) all_22_0_27 = all_14_1_10
% 66.93/29.10  																																																																																																									|
% 66.93/29.10  																																																																																																										| Combining equations (554,1398) yields a new equation:
% 66.93/29.10  																																																																																																										| (503) all_14_1_10 = 0
% 66.93/29.10  																																																																																																										|
% 66.93/29.10  																																																																																																										| Combining equations (503,1398) yields a new equation:
% 66.93/29.10  																																																																																																										| (554) all_22_0_27 = 0
% 66.93/29.10  																																																																																																										|
% 66.93/29.10  																																																																																																										| From (554) and (1193) follows:
% 66.93/29.10  																																																																																																										| (36) aNaturalNumber0(xm) = 0
% 66.93/29.10  																																																																																																										|
% 66.93/29.10  																																																																																																										+-Applying beta-rule and splitting (231), into two cases.
% 66.93/29.10  																																																																																																										|-Branch one:
% 66.93/29.10  																																																																																																										| (1322)  ~ (aNaturalNumber0(all_0_5_5) = all_36_1_51)
% 66.93/29.10  																																																																																																										|
% 66.93/29.10  																																																																																																											| From (555) and (1322) follows:
% 66.93/29.10  																																																																																																											| (1258)  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 66.93/29.10  																																																																																																											|
% 66.93/29.10  																																																																																																											| Using (573) and (1258) yields:
% 66.93/29.10  																																																																																																											| (615) $false
% 66.93/29.10  																																																																																																											|
% 66.93/29.10  																																																																																																											|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																										|-Branch two:
% 66.93/29.10  																																																																																																										| (1325) aNaturalNumber0(all_0_5_5) = all_36_1_51
% 66.93/29.10  																																																																																																										| (1406) all_36_1_51 = all_26_2_37
% 66.93/29.10  																																																																																																										|
% 66.93/29.10  																																																																																																											| Combining equations (555,1406) yields a new equation:
% 66.93/29.10  																																																																																																											| (572) all_26_2_37 = 0
% 66.93/29.10  																																																																																																											|
% 66.93/29.10  																																																																																																											| Combining equations (572,1406) yields a new equation:
% 66.93/29.10  																																																																																																											| (555) all_36_1_51 = 0
% 66.93/29.10  																																																																																																											|
% 66.93/29.10  																																																																																																											| From (555) and (1325) follows:
% 66.93/29.10  																																																																																																											| (573) aNaturalNumber0(all_0_5_5) = 0
% 66.93/29.10  																																																																																																											|
% 66.93/29.10  																																																																																																											+-Applying beta-rule and splitting (306), into two cases.
% 66.93/29.10  																																																																																																											|-Branch one:
% 66.93/29.10  																																																																																																											| (1213)  ~ (aNaturalNumber0(xp) = all_26_0_35)
% 66.93/29.10  																																																																																																											|
% 66.93/29.10  																																																																																																												| From (594) and (1213) follows:
% 66.93/29.10  																																																																																																												| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.10  																																																																																																												|
% 66.93/29.10  																																																																																																												| Using (12) and (1198) yields:
% 66.93/29.10  																																																																																																												| (615) $false
% 66.93/29.10  																																																																																																												|
% 66.93/29.10  																																																																																																												|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																											|-Branch two:
% 66.93/29.10  																																																																																																											| (1216) aNaturalNumber0(xp) = all_26_0_35
% 66.93/29.10  																																																																																																											| (1414) all_26_0_35 = all_26_1_36
% 66.93/29.10  																																																																																																											|
% 66.93/29.10  																																																																																																												| Combining equations (594,1414) yields a new equation:
% 66.93/29.10  																																																																																																												| (303) all_26_1_36 = 0
% 66.93/29.10  																																																																																																												|
% 66.93/29.10  																																																																																																												| Combining equations (303,1414) yields a new equation:
% 66.93/29.10  																																																																																																												| (594) all_26_0_35 = 0
% 66.93/29.10  																																																																																																												|
% 66.93/29.10  																																																																																																												| From (594) and (1216) follows:
% 66.93/29.10  																																																																																																												| (12) aNaturalNumber0(xp) = 0
% 66.93/29.10  																																																																																																												|
% 66.93/29.10  																																																																																																												+-Applying beta-rule and splitting (304), into two cases.
% 66.93/29.10  																																																																																																												|-Branch one:
% 66.93/29.10  																																																																																																												| (1418)  ~ (aNaturalNumber0(xp) = all_36_1_51)
% 66.93/29.10  																																																																																																												|
% 66.93/29.10  																																																																																																													| From (555) and (1418) follows:
% 66.93/29.10  																																																																																																													| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.10  																																																																																																													|
% 66.93/29.10  																																																																																																													| Using (12) and (1198) yields:
% 66.93/29.10  																																																																																																													| (615) $false
% 66.93/29.10  																																																																																																													|
% 66.93/29.10  																																																																																																													|-The branch is then unsatisfiable
% 66.93/29.10  																																																																																																												|-Branch two:
% 66.93/29.10  																																																																																																												| (1421) aNaturalNumber0(xp) = all_36_1_51
% 66.93/29.10  																																																																																																												| (1422) all_36_1_51 = all_26_1_36
% 66.93/29.10  																																																																																																												|
% 66.93/29.10  																																																																																																													| Combining equations (555,1422) yields a new equation:
% 66.93/29.10  																																																																																																													| (303) all_26_1_36 = 0
% 66.93/29.10  																																																																																																													|
% 66.93/29.10  																																																																																																													| Combining equations (303,1422) yields a new equation:
% 66.93/29.10  																																																																																																													| (555) all_36_1_51 = 0
% 66.93/29.10  																																																																																																													|
% 66.93/29.10  																																																																																																													| From (555) and (1421) follows:
% 66.93/29.10  																																																																																																													| (12) aNaturalNumber0(xp) = 0
% 66.93/29.10  																																																																																																													|
% 66.93/29.10  																																																																																																													+-Applying beta-rule and splitting (240), into two cases.
% 66.93/29.10  																																																																																																													|-Branch one:
% 66.93/29.10  																																																																																																													| (1322)  ~ (aNaturalNumber0(all_0_5_5) = all_36_1_51)
% 66.93/29.11  																																																																																																													|
% 66.93/29.11  																																																																																																														| From (555) and (1322) follows:
% 66.93/29.11  																																																																																																														| (1258)  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 66.93/29.11  																																																																																																														|
% 66.93/29.11  																																																																																																														| Using (573) and (1258) yields:
% 66.93/29.11  																																																																																																														| (615) $false
% 66.93/29.11  																																																																																																														|
% 66.93/29.11  																																																																																																														|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																													|-Branch two:
% 66.93/29.11  																																																																																																													| (1325) aNaturalNumber0(all_0_5_5) = all_36_1_51
% 66.93/29.11  																																																																																																													| (1430) all_36_1_51 = all_16_2_14
% 66.93/29.11  																																																																																																													|
% 66.93/29.11  																																																																																																														| Combining equations (555,1430) yields a new equation:
% 66.93/29.11  																																																																																																														| (571) all_16_2_14 = 0
% 66.93/29.11  																																																																																																														|
% 66.93/29.11  																																																																																																														| Combining equations (571,1430) yields a new equation:
% 66.93/29.11  																																																																																																														| (555) all_36_1_51 = 0
% 66.93/29.11  																																																																																																														|
% 66.93/29.11  																																																																																																														| From (555) and (1325) follows:
% 66.93/29.11  																																																																																																														| (573) aNaturalNumber0(all_0_5_5) = 0
% 66.93/29.11  																																																																																																														|
% 66.93/29.11  																																																																																																														+-Applying beta-rule and splitting (456), into two cases.
% 66.93/29.11  																																																																																																														|-Branch one:
% 66.93/29.11  																																																																																																														| (1245)  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 66.93/29.11  																																																																																																														|
% 66.93/29.11  																																																																																																															| From (572) and (1245) follows:
% 66.93/29.11  																																																																																																															| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.11  																																																																																																															|
% 66.93/29.11  																																																																																																															| Using (53) and (1144) yields:
% 66.93/29.11  																																																																																																															| (615) $false
% 66.93/29.11  																																																																																																															|
% 66.93/29.11  																																																																																																															|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																														|-Branch two:
% 66.93/29.11  																																																																																																														| (1248) aNaturalNumber0(xn) = all_26_2_37
% 66.93/29.11  																																																																																																														| (1438) all_26_2_37 = all_14_2_11
% 66.93/29.11  																																																																																																														|
% 66.93/29.11  																																																																																																															| Combining equations (572,1438) yields a new equation:
% 66.93/29.11  																																																																																																															| (451) all_14_2_11 = 0
% 66.93/29.11  																																																																																																															|
% 66.93/29.11  																																																																																																															| Combining equations (451,1438) yields a new equation:
% 66.93/29.11  																																																																																																															| (572) all_26_2_37 = 0
% 66.93/29.11  																																																																																																															|
% 66.93/29.11  																																																																																																															| From (572) and (1248) follows:
% 66.93/29.11  																																																																																																															| (53) aNaturalNumber0(xn) = 0
% 66.93/29.11  																																																																																																															|
% 66.93/29.11  																																																																																																															+-Applying beta-rule and splitting (259), into two cases.
% 66.93/29.11  																																																																																																															|-Branch one:
% 66.93/29.11  																																																																																																															| (1442)  ~ (aNaturalNumber0(xr) = all_26_0_35)
% 66.93/29.11  																																																																																																															|
% 66.93/29.11  																																																																																																																| From (594) and (1442) follows:
% 66.93/29.11  																																																																																																																| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 66.93/29.11  																																																																																																																|
% 66.93/29.11  																																																																																																																| Using (10) and (1287) yields:
% 66.93/29.11  																																																																																																																| (615) $false
% 66.93/29.11  																																																																																																																|
% 66.93/29.11  																																																																																																																|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																															|-Branch two:
% 66.93/29.11  																																																																																																															| (1445) aNaturalNumber0(xr) = all_26_0_35
% 66.93/29.11  																																																																																																															| (1446) all_41_2_56 = all_26_0_35
% 66.93/29.11  																																																																																																															|
% 66.93/29.11  																																																																																																																| Combining equations (253,1446) yields a new equation:
% 66.93/29.11  																																																																																																																| (594) all_26_0_35 = 0
% 66.93/29.11  																																																																																																																|
% 66.93/29.11  																																																																																																																| Combining equations (594,1446) yields a new equation:
% 66.93/29.11  																																																																																																																| (253) all_41_2_56 = 0
% 66.93/29.11  																																																																																																																|
% 66.93/29.11  																																																																																																																| From (594) and (1445) follows:
% 66.93/29.11  																																																																																																																| (10) aNaturalNumber0(xr) = 0
% 66.93/29.11  																																																																																																																|
% 66.93/29.11  																																																																																																																+-Applying beta-rule and splitting (222), into two cases.
% 66.93/29.11  																																																																																																																|-Branch one:
% 66.93/29.11  																																																																																																																| (1354)  ~ (aNaturalNumber0(xn) = all_26_0_35)
% 66.93/29.11  																																																																																																																|
% 66.93/29.11  																																																																																																																	| From (594) and (1354) follows:
% 66.93/29.11  																																																																																																																	| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.11  																																																																																																																	|
% 66.93/29.11  																																																																																																																	| Using (53) and (1144) yields:
% 66.93/29.11  																																																																																																																	| (615) $false
% 66.93/29.11  																																																																																																																	|
% 66.93/29.11  																																																																																																																	|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																																|-Branch two:
% 66.93/29.11  																																																																																																																| (1357) aNaturalNumber0(xn) = all_26_0_35
% 66.93/29.11  																																																																																																																| (594) all_26_0_35 = 0
% 66.93/29.11  																																																																																																																|
% 66.93/29.11  																																																																																																																	| From (594) and (1357) follows:
% 66.93/29.11  																																																																																																																	| (53) aNaturalNumber0(xn) = 0
% 66.93/29.11  																																																																																																																	|
% 66.93/29.11  																																																																																																																	+-Applying beta-rule and splitting (411), into two cases.
% 66.93/29.11  																																																																																																																	|-Branch one:
% 66.93/29.11  																																																																																																																	| (1370)  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 66.93/29.11  																																																																																																																	|
% 66.93/29.11  																																																																																																																		| From (555) and (1370) follows:
% 66.93/29.11  																																																																																																																		| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.11  																																																																																																																		|
% 66.93/29.11  																																																																																																																		| Using (53) and (1144) yields:
% 66.93/29.11  																																																																																																																		| (615) $false
% 66.93/29.11  																																																																																																																		|
% 66.93/29.11  																																																																																																																		|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																																	|-Branch two:
% 66.93/29.11  																																																																																																																	| (1373) aNaturalNumber0(xn) = all_36_1_51
% 66.93/29.11  																																																																																																																	| (1460) all_36_1_51 = all_28_2_40
% 66.93/29.11  																																																																																																																	|
% 66.93/29.11  																																																																																																																		| Combining equations (555,1460) yields a new equation:
% 66.93/29.11  																																																																																																																		| (514) all_28_2_40 = 0
% 66.93/29.11  																																																																																																																		|
% 66.93/29.11  																																																																																																																		| Combining equations (514,1460) yields a new equation:
% 66.93/29.11  																																																																																																																		| (555) all_36_1_51 = 0
% 66.93/29.11  																																																																																																																		|
% 66.93/29.11  																																																																																																																		| From (555) and (1373) follows:
% 66.93/29.11  																																																																																																																		| (53) aNaturalNumber0(xn) = 0
% 66.93/29.11  																																																																																																																		|
% 66.93/29.11  																																																																																																																		+-Applying beta-rule and splitting (298), into two cases.
% 66.93/29.11  																																																																																																																		|-Branch one:
% 66.93/29.11  																																																																																																																		| (1464)  ~ (aNaturalNumber0(xp) = all_16_2_14)
% 66.93/29.11  																																																																																																																		|
% 66.93/29.11  																																																																																																																			| From (571) and (1464) follows:
% 66.93/29.11  																																																																																																																			| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.11  																																																																																																																			|
% 66.93/29.11  																																																																																																																			| Using (12) and (1198) yields:
% 66.93/29.11  																																																																																																																			| (615) $false
% 66.93/29.11  																																																																																																																			|
% 66.93/29.11  																																																																																																																			|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																																		|-Branch two:
% 66.93/29.11  																																																																																																																		| (1467) aNaturalNumber0(xp) = all_16_2_14
% 66.93/29.11  																																																																																																																		| (1468) all_30_6_47 = all_16_2_14
% 66.93/29.11  																																																																																																																		|
% 66.93/29.11  																																																																																																																			| Combining equations (1242,1468) yields a new equation:
% 66.93/29.11  																																																																																																																			| (571) all_16_2_14 = 0
% 66.93/29.11  																																																																																																																			|
% 66.93/29.11  																																																																																																																			| Combining equations (571,1468) yields a new equation:
% 66.93/29.11  																																																																																																																			| (1242) all_30_6_47 = 0
% 66.93/29.11  																																																																																																																			|
% 66.93/29.11  																																																																																																																			| From (571) and (1467) follows:
% 66.93/29.11  																																																																																																																			| (12) aNaturalNumber0(xp) = 0
% 66.93/29.11  																																																																																																																			|
% 66.93/29.11  																																																																																																																			+-Applying beta-rule and splitting (470), into two cases.
% 66.93/29.11  																																																																																																																			|-Branch one:
% 66.93/29.11  																																																																																																																			| (1354)  ~ (aNaturalNumber0(xn) = all_26_0_35)
% 66.93/29.11  																																																																																																																			|
% 66.93/29.11  																																																																																																																				| From (594) and (1354) follows:
% 66.93/29.11  																																																																																																																				| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.11  																																																																																																																				|
% 66.93/29.11  																																																																																																																				| Using (53) and (1144) yields:
% 66.93/29.11  																																																																																																																				| (615) $false
% 66.93/29.11  																																																																																																																				|
% 66.93/29.11  																																																																																																																				|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																																			|-Branch two:
% 66.93/29.11  																																																																																																																			| (1357) aNaturalNumber0(xn) = all_26_0_35
% 66.93/29.11  																																																																																																																			| (1476) all_26_0_35 = all_12_2_8
% 66.93/29.11  																																																																																																																			|
% 66.93/29.11  																																																																																																																				| Combining equations (594,1476) yields a new equation:
% 66.93/29.11  																																																																																																																				| (508) all_12_2_8 = 0
% 66.93/29.11  																																																																																																																				|
% 66.93/29.11  																																																																																																																				| Combining equations (508,1476) yields a new equation:
% 66.93/29.11  																																																																																																																				| (594) all_26_0_35 = 0
% 66.93/29.11  																																																																																																																				|
% 66.93/29.11  																																																																																																																				| From (594) and (1357) follows:
% 66.93/29.11  																																																																																																																				| (53) aNaturalNumber0(xn) = 0
% 66.93/29.11  																																																																																																																				|
% 66.93/29.11  																																																																																																																				+-Applying beta-rule and splitting (457), into two cases.
% 66.93/29.11  																																																																																																																				|-Branch one:
% 66.93/29.11  																																																																																																																				| (1480)  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 66.93/29.11  																																																																																																																				|
% 66.93/29.11  																																																																																																																					| From (571) and (1480) follows:
% 66.93/29.11  																																																																																																																					| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.11  																																																																																																																					|
% 66.93/29.11  																																																																																																																					| Using (53) and (1144) yields:
% 66.93/29.11  																																																																																																																					| (615) $false
% 66.93/29.11  																																																																																																																					|
% 66.93/29.11  																																																																																																																					|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																																				|-Branch two:
% 66.93/29.11  																																																																																																																				| (1483) aNaturalNumber0(xn) = all_16_2_14
% 66.93/29.11  																																																																																																																				| (1484) all_16_2_14 = all_14_2_11
% 66.93/29.11  																																																																																																																				|
% 66.93/29.11  																																																																																																																					| From (571) and (1483) follows:
% 66.93/29.11  																																																																																																																					| (53) aNaturalNumber0(xn) = 0
% 66.93/29.11  																																																																																																																					|
% 66.93/29.11  																																																																																																																					+-Applying beta-rule and splitting (461), into two cases.
% 66.93/29.11  																																																																																																																					|-Branch one:
% 66.93/29.11  																																																																																																																					| (1143)  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 66.93/29.11  																																																																																																																					|
% 66.93/29.11  																																																																																																																						| From (515) and (1143) follows:
% 66.93/29.11  																																																																																																																						| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.11  																																																																																																																						|
% 66.93/29.11  																																																																																																																						| Using (53) and (1144) yields:
% 66.93/29.11  																																																																																																																						| (615) $false
% 66.93/29.11  																																																																																																																						|
% 66.93/29.11  																																																																																																																						|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																																					|-Branch two:
% 66.93/29.11  																																																																																																																					| (1146) aNaturalNumber0(xn) = all_28_1_39
% 66.93/29.11  																																																																																																																					| (1490) all_28_1_39 = all_14_2_11
% 66.93/29.11  																																																																																																																					|
% 66.93/29.11  																																																																																																																						| Combining equations (515,1490) yields a new equation:
% 66.93/29.11  																																																																																																																						| (451) all_14_2_11 = 0
% 66.93/29.11  																																																																																																																						|
% 66.93/29.11  																																																																																																																						| Combining equations (451,1490) yields a new equation:
% 66.93/29.11  																																																																																																																						| (515) all_28_1_39 = 0
% 66.93/29.11  																																																																																																																						|
% 66.93/29.11  																																																																																																																						| From (515) and (1146) follows:
% 66.93/29.11  																																																																																																																						| (53) aNaturalNumber0(xn) = 0
% 66.93/29.11  																																																																																																																						|
% 66.93/29.11  																																																																																																																						+-Applying beta-rule and splitting (448), into two cases.
% 66.93/29.11  																																																																																																																						|-Branch one:
% 66.93/29.11  																																																																																																																						| (1182)  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 66.93/29.11  																																																																																																																						|
% 66.93/29.11  																																																																																																																							| From (499) and (1182) follows:
% 66.93/29.11  																																																																																																																							| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.11  																																																																																																																							|
% 66.93/29.11  																																																																																																																							| Using (53) and (1144) yields:
% 66.93/29.11  																																																																																																																							| (615) $false
% 66.93/29.11  																																																																																																																							|
% 66.93/29.11  																																																																																																																							|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																																						|-Branch two:
% 66.93/29.11  																																																																																																																						| (1185) aNaturalNumber0(xn) = all_22_1_28
% 66.93/29.11  																																																																																																																						| (1498) all_22_1_28 = all_22_2_29
% 66.93/29.11  																																																																																																																						|
% 66.93/29.11  																																																																																																																							| Combining equations (499,1498) yields a new equation:
% 66.93/29.11  																																																																																																																							| (510) all_22_2_29 = 0
% 66.93/29.11  																																																																																																																							|
% 66.93/29.11  																																																																																																																							| Combining equations (510,1498) yields a new equation:
% 66.93/29.11  																																																																																																																							| (499) all_22_1_28 = 0
% 66.93/29.11  																																																																																																																							|
% 66.93/29.11  																																																																																																																							| From (499) and (1185) follows:
% 66.93/29.11  																																																																																																																							| (53) aNaturalNumber0(xn) = 0
% 66.93/29.11  																																																																																																																							|
% 66.93/29.11  																																																																																																																							+-Applying beta-rule and splitting (248), into two cases.
% 66.93/29.11  																																																																																																																							|-Branch one:
% 66.93/29.11  																																																																																																																							| (1502)  ~ (aNaturalNumber0(sz00) = all_12_0_6)
% 66.93/29.11  																																																																																																																							|
% 66.93/29.11  																																																																																																																								| From (570) and (1502) follows:
% 66.93/29.11  																																																																																																																								| (1503)  ~ (aNaturalNumber0(sz00) = 0)
% 66.93/29.11  																																																																																																																								|
% 66.93/29.11  																																																																																																																								| Using (41) and (1503) yields:
% 66.93/29.11  																																																																																																																								| (615) $false
% 66.93/29.11  																																																																																																																								|
% 66.93/29.11  																																																																																																																								|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																																							|-Branch two:
% 66.93/29.11  																																																																																																																							| (1505) aNaturalNumber0(sz00) = all_12_0_6
% 66.93/29.11  																																																																																																																							| (570) all_12_0_6 = 0
% 66.93/29.11  																																																																																																																							|
% 66.93/29.11  																																																																																																																								| From (570) and (1505) follows:
% 66.93/29.11  																																																																																																																								| (41) aNaturalNumber0(sz00) = 0
% 66.93/29.11  																																																																																																																								|
% 66.93/29.11  																																																																																																																								+-Applying beta-rule and splitting (261), into two cases.
% 66.93/29.11  																																																																																																																								|-Branch one:
% 66.93/29.11  																																																																																																																								| (1508)  ~ (aNaturalNumber0(xr) = all_12_0_6)
% 66.93/29.11  																																																																																																																								|
% 66.93/29.11  																																																																																																																									| From (570) and (1508) follows:
% 66.93/29.11  																																																																																																																									| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 66.93/29.11  																																																																																																																									|
% 66.93/29.11  																																																																																																																									| Using (10) and (1287) yields:
% 66.93/29.11  																																																																																																																									| (615) $false
% 66.93/29.11  																																																																																																																									|
% 66.93/29.11  																																																																																																																									|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																																								|-Branch two:
% 66.93/29.11  																																																																																																																								| (1511) aNaturalNumber0(xr) = all_12_0_6
% 66.93/29.11  																																																																																																																								| (1512) all_41_2_56 = all_12_0_6
% 66.93/29.11  																																																																																																																								|
% 66.93/29.11  																																																																																																																									| Combining equations (253,1512) yields a new equation:
% 66.93/29.11  																																																																																																																									| (570) all_12_0_6 = 0
% 66.93/29.11  																																																																																																																									|
% 66.93/29.11  																																																																																																																									| Combining equations (570,1512) yields a new equation:
% 66.93/29.11  																																																																																																																									| (253) all_41_2_56 = 0
% 66.93/29.11  																																																																																																																									|
% 66.93/29.11  																																																																																																																									| From (570) and (1511) follows:
% 66.93/29.11  																																																																																																																									| (10) aNaturalNumber0(xr) = 0
% 66.93/29.11  																																																																																																																									|
% 66.93/29.11  																																																																																																																									+-Applying beta-rule and splitting (345), into two cases.
% 66.93/29.11  																																																																																																																									|-Branch one:
% 66.93/29.11  																																																																																																																									| (1516)  ~ (aNaturalNumber0(xm) = all_36_1_51)
% 66.93/29.11  																																																																																																																									|
% 66.93/29.11  																																																																																																																										| From (555) and (1516) follows:
% 66.93/29.11  																																																																																																																										| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.11  																																																																																																																										|
% 66.93/29.11  																																																																																																																										| Using (36) and (1191) yields:
% 66.93/29.11  																																																																																																																										| (615) $false
% 66.93/29.11  																																																																																																																										|
% 66.93/29.11  																																																																																																																										|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																																									|-Branch two:
% 66.93/29.11  																																																																																																																									| (1519) aNaturalNumber0(xm) = all_36_1_51
% 66.93/29.11  																																																																																																																									| (1520) all_36_1_51 = all_28_1_39
% 66.93/29.11  																																																																																																																									|
% 66.93/29.11  																																																																																																																										| Combining equations (555,1520) yields a new equation:
% 66.93/29.11  																																																																																																																										| (515) all_28_1_39 = 0
% 66.93/29.11  																																																																																																																										|
% 66.93/29.11  																																																																																																																										| Combining equations (515,1520) yields a new equation:
% 66.93/29.11  																																																																																																																										| (555) all_36_1_51 = 0
% 66.93/29.11  																																																																																																																										|
% 66.93/29.11  																																																																																																																										| From (555) and (1519) follows:
% 66.93/29.11  																																																																																																																										| (36) aNaturalNumber0(xm) = 0
% 66.93/29.11  																																																																																																																										|
% 66.93/29.11  																																																																																																																										+-Applying beta-rule and splitting (265), into two cases.
% 66.93/29.11  																																																																																																																										|-Branch one:
% 66.93/29.11  																																																																																																																										| (1524)  ~ (aNaturalNumber0(xr) = all_36_1_51)
% 66.93/29.11  																																																																																																																										|
% 66.93/29.11  																																																																																																																											| From (555) and (1524) follows:
% 66.93/29.11  																																																																																																																											| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 66.93/29.11  																																																																																																																											|
% 66.93/29.11  																																																																																																																											| Using (10) and (1287) yields:
% 66.93/29.11  																																																																																																																											| (615) $false
% 66.93/29.11  																																																																																																																											|
% 66.93/29.11  																																																																																																																											|-The branch is then unsatisfiable
% 66.93/29.11  																																																																																																																										|-Branch two:
% 66.93/29.11  																																																																																																																										| (1527) aNaturalNumber0(xr) = all_36_1_51
% 66.93/29.11  																																																																																																																										| (1528) all_36_1_51 = all_36_3_53
% 66.93/29.11  																																																																																																																										|
% 66.93/29.11  																																																																																																																											| Combining equations (555,1528) yields a new equation:
% 66.93/29.11  																																																																																																																											| (480) all_36_3_53 = 0
% 66.93/29.11  																																																																																																																											|
% 66.93/29.11  																																																																																																																											| Combining equations (480,1528) yields a new equation:
% 66.93/29.11  																																																																																																																											| (555) all_36_1_51 = 0
% 66.93/29.11  																																																																																																																											|
% 66.93/29.11  																																																																																																																											| From (555) and (1527) follows:
% 66.93/29.11  																																																																																																																											| (10) aNaturalNumber0(xr) = 0
% 66.93/29.11  																																																																																																																											|
% 66.93/29.11  																																																																																																																											+-Applying beta-rule and splitting (266), into two cases.
% 66.93/29.11  																																																																																																																											|-Branch one:
% 66.93/29.11  																																																																																																																											| (1532)  ~ (aNaturalNumber0(xr) = all_22_0_27)
% 66.93/29.11  																																																																																																																											|
% 66.93/29.11  																																																																																																																												| From (554) and (1532) follows:
% 66.93/29.11  																																																																																																																												| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 66.93/29.12  																																																																																																																												|
% 66.93/29.12  																																																																																																																												| Using (10) and (1287) yields:
% 66.93/29.12  																																																																																																																												| (615) $false
% 66.93/29.12  																																																																																																																												|
% 66.93/29.12  																																																																																																																												|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																											|-Branch two:
% 66.93/29.12  																																																																																																																											| (1535) aNaturalNumber0(xr) = all_22_0_27
% 66.93/29.12  																																																																																																																											| (1536) all_36_3_53 = all_22_0_27
% 66.93/29.12  																																																																																																																											|
% 66.93/29.12  																																																																																																																												| Combining equations (480,1536) yields a new equation:
% 66.93/29.12  																																																																																																																												| (554) all_22_0_27 = 0
% 66.93/29.12  																																																																																																																												|
% 66.93/29.12  																																																																																																																												| Combining equations (554,1536) yields a new equation:
% 66.93/29.12  																																																																																																																												| (480) all_36_3_53 = 0
% 66.93/29.12  																																																																																																																												|
% 66.93/29.12  																																																																																																																												| From (554) and (1535) follows:
% 66.93/29.12  																																																																																																																												| (10) aNaturalNumber0(xr) = 0
% 66.93/29.12  																																																																																																																												|
% 66.93/29.12  																																																																																																																												+-Applying beta-rule and splitting (297), into two cases.
% 66.93/29.12  																																																																																																																												|-Branch one:
% 66.93/29.12  																																																																																																																												| (1205)  ~ (aNaturalNumber0(xp) = all_26_2_37)
% 66.93/29.12  																																																																																																																												|
% 66.93/29.12  																																																																																																																													| From (572) and (1205) follows:
% 66.93/29.12  																																																																																																																													| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.12  																																																																																																																													|
% 66.93/29.12  																																																																																																																													| Using (12) and (1198) yields:
% 66.93/29.12  																																																																																																																													| (615) $false
% 66.93/29.12  																																																																																																																													|
% 66.93/29.12  																																																																																																																													|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																												|-Branch two:
% 66.93/29.12  																																																																																																																												| (1208) aNaturalNumber0(xp) = all_26_2_37
% 66.93/29.12  																																																																																																																												| (1544) all_30_6_47 = all_26_2_37
% 66.93/29.12  																																																																																																																												|
% 66.93/29.12  																																																																																																																													| Combining equations (1242,1544) yields a new equation:
% 66.93/29.12  																																																																																																																													| (572) all_26_2_37 = 0
% 66.93/29.12  																																																																																																																													|
% 66.93/29.12  																																																																																																																													| Combining equations (572,1544) yields a new equation:
% 66.93/29.12  																																																																																																																													| (1242) all_30_6_47 = 0
% 66.93/29.12  																																																																																																																													|
% 66.93/29.12  																																																																																																																													| From (572) and (1208) follows:
% 66.93/29.12  																																																																																																																													| (12) aNaturalNumber0(xp) = 0
% 66.93/29.12  																																																																																																																													|
% 66.93/29.12  																																																																																																																													+-Applying beta-rule and splitting (363), into two cases.
% 66.93/29.12  																																																																																																																													|-Branch one:
% 66.93/29.12  																																																																																																																													| (1548)  ~ (aNaturalNumber0(sz10) = all_22_1_28)
% 66.93/29.12  																																																																																																																													|
% 66.93/29.12  																																																																																																																														| From (499) and (1548) follows:
% 66.93/29.12  																																																																																																																														| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 66.93/29.12  																																																																																																																														|
% 66.93/29.12  																																																																																																																														| Using (16) and (1252) yields:
% 66.93/29.12  																																																																																																																														| (615) $false
% 66.93/29.12  																																																																																																																														|
% 66.93/29.12  																																																																																																																														|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																													|-Branch two:
% 66.93/29.12  																																																																																																																													| (1551) aNaturalNumber0(sz10) = all_22_1_28
% 66.93/29.12  																																																																																																																													| (499) all_22_1_28 = 0
% 66.93/29.12  																																																																																																																													|
% 66.93/29.12  																																																																																																																														| From (499) and (1551) follows:
% 66.93/29.12  																																																																																																																														| (16) aNaturalNumber0(sz10) = 0
% 66.93/29.12  																																																																																																																														|
% 66.93/29.12  																																																																																																																														+-Applying beta-rule and splitting (305), into two cases.
% 66.93/29.12  																																																																																																																														|-Branch one:
% 66.93/29.12  																																																																																																																														| (1554)  ~ (aNaturalNumber0(xp) = all_22_0_27)
% 66.93/29.12  																																																																																																																														|
% 66.93/29.12  																																																																																																																															| From (554) and (1554) follows:
% 66.93/29.12  																																																																																																																															| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.12  																																																																																																																															|
% 66.93/29.12  																																																																																																																															| Using (12) and (1198) yields:
% 66.93/29.12  																																																																																																																															| (615) $false
% 66.93/29.12  																																																																																																																															|
% 66.93/29.12  																																																																																																																															|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																														|-Branch two:
% 66.93/29.12  																																																																																																																														| (1557) aNaturalNumber0(xp) = all_22_0_27
% 66.93/29.12  																																																																																																																														| (1558) all_26_1_36 = all_22_0_27
% 66.93/29.12  																																																																																																																														|
% 66.93/29.12  																																																																																																																															| Combining equations (303,1558) yields a new equation:
% 66.93/29.12  																																																																																																																															| (554) all_22_0_27 = 0
% 66.93/29.12  																																																																																																																															|
% 66.93/29.12  																																																																																																																															| Combining equations (554,1558) yields a new equation:
% 66.93/29.12  																																																																																																																															| (303) all_26_1_36 = 0
% 66.93/29.12  																																																																																																																															|
% 66.93/29.12  																																																																																																																															| From (554) and (1557) follows:
% 66.93/29.12  																																																																																																																															| (12) aNaturalNumber0(xp) = 0
% 66.93/29.12  																																																																																																																															|
% 66.93/29.12  																																																																																																																															+-Applying beta-rule and splitting (236), into two cases.
% 66.93/29.12  																																																																																																																															|-Branch one:
% 66.93/29.12  																																																																																																																															| (1562)  ~ (aNaturalNumber0(xm) = all_16_2_14)
% 66.93/29.12  																																																																																																																															|
% 66.93/29.12  																																																																																																																																| From (571) and (1562) follows:
% 66.93/29.12  																																																																																																																																| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.12  																																																																																																																																|
% 66.93/29.12  																																																																																																																																| Using (36) and (1191) yields:
% 66.93/29.12  																																																																																																																																| (615) $false
% 66.93/29.12  																																																																																																																																|
% 66.93/29.12  																																																																																																																																|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																															|-Branch two:
% 66.93/29.12  																																																																																																																															| (1565) aNaturalNumber0(xm) = all_16_2_14
% 66.93/29.12  																																																																																																																															| (571) all_16_2_14 = 0
% 66.93/29.12  																																																																																																																															|
% 66.93/29.12  																																																																																																																																| From (571) and (1565) follows:
% 66.93/29.12  																																																																																																																																| (36) aNaturalNumber0(xm) = 0
% 66.93/29.12  																																																																																																																																|
% 66.93/29.12  																																																																																																																																+-Applying beta-rule and splitting (405), into two cases.
% 66.93/29.12  																																																																																																																																|-Branch one:
% 66.93/29.12  																																																																																																																																| (1568)  ~ (aNaturalNumber0(xn) = all_24_3_33)
% 66.93/29.12  																																																																																																																																|
% 66.93/29.12  																																																																																																																																	| From (483) and (1568) follows:
% 66.93/29.12  																																																																																																																																	| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.12  																																																																																																																																	|
% 66.93/29.12  																																																																																																																																	| Using (53) and (1144) yields:
% 66.93/29.12  																																																																																																																																	| (615) $false
% 66.93/29.12  																																																																																																																																	|
% 66.93/29.12  																																																																																																																																	|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																																|-Branch two:
% 66.93/29.12  																																																																																																																																| (1571) aNaturalNumber0(xn) = all_24_3_33
% 66.93/29.12  																																																																																																																																| (1572) all_30_8_49 = all_24_3_33
% 66.93/29.12  																																																																																																																																|
% 66.93/29.12  																																																																																																																																	| Combining equations (516,1572) yields a new equation:
% 66.93/29.12  																																																																																																																																	| (483) all_24_3_33 = 0
% 66.93/29.12  																																																																																																																																	|
% 66.93/29.12  																																																																																																																																	| Combining equations (483,1572) yields a new equation:
% 66.93/29.12  																																																																																																																																	| (516) all_30_8_49 = 0
% 66.93/29.12  																																																																																																																																	|
% 66.93/29.12  																																																																																																																																	| From (483) and (1571) follows:
% 66.93/29.12  																																																																																																																																	| (53) aNaturalNumber0(xn) = 0
% 66.93/29.12  																																																																																																																																	|
% 66.93/29.12  																																																																																																																																	+-Applying beta-rule and splitting (398), into two cases.
% 66.93/29.12  																																																																																																																																	|-Branch one:
% 66.93/29.12  																																																																																																																																	| (1480)  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 66.93/29.12  																																																																																																																																	|
% 66.93/29.12  																																																																																																																																		| From (571) and (1480) follows:
% 66.93/29.12  																																																																																																																																		| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.12  																																																																																																																																		|
% 66.93/29.12  																																																																																																																																		| Using (53) and (1144) yields:
% 66.93/29.12  																																																																																																																																		| (615) $false
% 66.93/29.12  																																																																																																																																		|
% 66.93/29.12  																																																																																																																																		|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																																	|-Branch two:
% 66.93/29.12  																																																																																																																																	| (1483) aNaturalNumber0(xn) = all_16_2_14
% 66.93/29.12  																																																																																																																																	| (1580) all_30_8_49 = all_16_2_14
% 66.93/29.12  																																																																																																																																	|
% 66.93/29.12  																																																																																																																																		| Combining equations (516,1580) yields a new equation:
% 66.93/29.12  																																																																																																																																		| (571) all_16_2_14 = 0
% 66.93/29.12  																																																																																																																																		|
% 66.93/29.12  																																																																																																																																		| Combining equations (571,1580) yields a new equation:
% 66.93/29.12  																																																																																																																																		| (516) all_30_8_49 = 0
% 66.93/29.12  																																																																																																																																		|
% 66.93/29.12  																																																																																																																																		| From (571) and (1483) follows:
% 66.93/29.12  																																																																																																																																		| (53) aNaturalNumber0(xn) = 0
% 66.93/29.12  																																																																																																																																		|
% 66.93/29.12  																																																																																																																																		+-Applying beta-rule and splitting (250), into two cases.
% 66.93/29.12  																																																																																																																																		|-Branch one:
% 66.93/29.12  																																																																																																																																		| (1257)  ~ (aNaturalNumber0(all_0_5_5) = all_22_0_27)
% 66.93/29.12  																																																																																																																																		|
% 66.93/29.12  																																																																																																																																			| From (554) and (1257) follows:
% 66.93/29.12  																																																																																																																																			| (1258)  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 66.93/29.12  																																																																																																																																			|
% 66.93/29.12  																																																																																																																																			| Using (573) and (1258) yields:
% 66.93/29.12  																																																																																																																																			| (615) $false
% 66.93/29.12  																																																																																																																																			|
% 66.93/29.12  																																																																																																																																			|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																																		|-Branch two:
% 66.93/29.12  																																																																																																																																		| (1260) aNaturalNumber0(all_0_5_5) = all_22_0_27
% 66.93/29.12  																																																																																																																																		| (1588) all_22_0_27 = all_12_0_6
% 66.93/29.12  																																																																																																																																		|
% 66.93/29.12  																																																																																																																																			| Combining equations (554,1588) yields a new equation:
% 66.93/29.12  																																																																																																																																			| (570) all_12_0_6 = 0
% 66.93/29.12  																																																																																																																																			|
% 66.93/29.12  																																																																																																																																			| Combining equations (570,1588) yields a new equation:
% 66.93/29.12  																																																																																																																																			| (554) all_22_0_27 = 0
% 66.93/29.12  																																																																																																																																			|
% 66.93/29.12  																																																																																																																																			| From (554) and (1260) follows:
% 66.93/29.12  																																																																																																																																			| (573) aNaturalNumber0(all_0_5_5) = 0
% 66.93/29.12  																																																																																																																																			|
% 66.93/29.12  																																																																																																																																			+-Applying beta-rule and splitting (397), into two cases.
% 66.93/29.12  																																																																																																																																			|-Branch one:
% 66.93/29.12  																																																																																																																																			| (1245)  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 66.93/29.12  																																																																																																																																			|
% 66.93/29.12  																																																																																																																																				| From (572) and (1245) follows:
% 66.93/29.12  																																																																																																																																				| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.12  																																																																																																																																				|
% 66.93/29.12  																																																																																																																																				| Using (53) and (1144) yields:
% 66.93/29.12  																																																																																																																																				| (615) $false
% 66.93/29.12  																																																																																																																																				|
% 66.93/29.12  																																																																																																																																				|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																																			|-Branch two:
% 66.93/29.12  																																																																																																																																			| (1248) aNaturalNumber0(xn) = all_26_2_37
% 66.93/29.12  																																																																																																																																			| (1596) all_30_8_49 = all_26_2_37
% 66.93/29.12  																																																																																																																																			|
% 66.93/29.12  																																																																																																																																				| Combining equations (516,1596) yields a new equation:
% 66.93/29.12  																																																																																																																																				| (572) all_26_2_37 = 0
% 66.93/29.12  																																																																																																																																				|
% 66.93/29.12  																																																																																																																																				| From (572) and (1248) follows:
% 66.93/29.12  																																																																																																																																				| (53) aNaturalNumber0(xn) = 0
% 66.93/29.12  																																																																																																																																				|
% 66.93/29.12  																																																																																																																																				+-Applying beta-rule and splitting (272), into two cases.
% 66.93/29.12  																																																																																																																																				|-Branch one:
% 66.93/29.12  																																																																																																																																				| (974)  ~ (aNaturalNumber0(xk) = 0)
% 66.93/29.12  																																																																																																																																				|
% 66.93/29.12  																																																																																																																																					| Using (972) and (974) yields:
% 66.93/29.12  																																																																																																																																					| (615) $false
% 66.93/29.12  																																																																																																																																					|
% 66.93/29.12  																																																																																																																																					|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																																				|-Branch two:
% 66.93/29.12  																																																																																																																																				| (972) aNaturalNumber0(xk) = 0
% 66.93/29.12  																																																																																																																																				| (980) all_41_1_55 = 0
% 66.93/29.12  																																																																																																																																				|
% 66.93/29.12  																																																																																																																																					+-Applying beta-rule and splitting (233), into two cases.
% 66.93/29.12  																																																																																																																																					|-Branch one:
% 66.93/29.12  																																																																																																																																					| (1603)  ~ (aNaturalNumber0(all_0_5_5) = all_26_0_35)
% 66.93/29.12  																																																																																																																																					|
% 66.93/29.12  																																																																																																																																						| From (594) and (1603) follows:
% 66.93/29.12  																																																																																																																																						| (1258)  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 66.93/29.12  																																																																																																																																						|
% 66.93/29.12  																																																																																																																																						| Using (573) and (1258) yields:
% 66.93/29.12  																																																																																																																																						| (615) $false
% 66.93/29.12  																																																																																																																																						|
% 66.93/29.12  																																																																																																																																						|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																																					|-Branch two:
% 66.93/29.12  																																																																																																																																					| (1606) aNaturalNumber0(all_0_5_5) = all_26_0_35
% 66.93/29.12  																																																																																																																																					| (1607) all_26_0_35 = all_26_2_37
% 66.93/29.12  																																																																																																																																					|
% 66.93/29.12  																																																																																																																																						| Combining equations (594,1607) yields a new equation:
% 66.93/29.12  																																																																																																																																						| (572) all_26_2_37 = 0
% 66.93/29.12  																																																																																																																																						|
% 66.93/29.12  																																																																																																																																						| Combining equations (572,1607) yields a new equation:
% 66.93/29.12  																																																																																																																																						| (594) all_26_0_35 = 0
% 66.93/29.12  																																																																																																																																						|
% 66.93/29.12  																																																																																																																																						| From (594) and (1606) follows:
% 66.93/29.12  																																																																																																																																						| (573) aNaturalNumber0(all_0_5_5) = 0
% 66.93/29.12  																																																																																																																																						|
% 66.93/29.12  																																																																																																																																						+-Applying beta-rule and splitting (375), into two cases.
% 66.93/29.12  																																																																																																																																						|-Branch one:
% 66.93/29.12  																																																																																																																																						| (1516)  ~ (aNaturalNumber0(xm) = all_36_1_51)
% 66.93/29.12  																																																																																																																																						|
% 66.93/29.12  																																																																																																																																							| From (555) and (1516) follows:
% 66.93/29.12  																																																																																																																																							| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.12  																																																																																																																																							|
% 66.93/29.12  																																																																																																																																							| Using (36) and (1191) yields:
% 66.93/29.12  																																																																																																																																							| (615) $false
% 66.93/29.12  																																																																																																																																							|
% 66.93/29.12  																																																																																																																																							|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																																						|-Branch two:
% 66.93/29.12  																																																																																																																																						| (1519) aNaturalNumber0(xm) = all_36_1_51
% 66.93/29.12  																																																																																																																																						| (1615) all_36_1_51 = all_14_1_10
% 66.93/29.12  																																																																																																																																						|
% 66.93/29.12  																																																																																																																																							| Combining equations (555,1615) yields a new equation:
% 66.93/29.12  																																																																																																																																							| (503) all_14_1_10 = 0
% 66.93/29.12  																																																																																																																																							|
% 66.93/29.12  																																																																																																																																							| Combining equations (503,1615) yields a new equation:
% 66.93/29.12  																																																																																																																																							| (555) all_36_1_51 = 0
% 66.93/29.12  																																																																																																																																							|
% 66.93/29.12  																																																																																																																																							| From (555) and (1519) follows:
% 66.93/29.12  																																																																																																																																							| (36) aNaturalNumber0(xm) = 0
% 66.93/29.12  																																																																																																																																							|
% 66.93/29.12  																																																																																																																																							+-Applying beta-rule and splitting (436), into two cases.
% 66.93/29.12  																																																																																																																																							|-Branch one:
% 66.93/29.12  																																																																																																																																							| (1619)  ~ (aNaturalNumber0(sz00) = all_22_2_29)
% 66.93/29.12  																																																																																																																																							|
% 66.93/29.12  																																																																																																																																								| From (510) and (1619) follows:
% 66.93/29.12  																																																																																																																																								| (1503)  ~ (aNaturalNumber0(sz00) = 0)
% 66.93/29.12  																																																																																																																																								|
% 66.93/29.12  																																																																																																																																								| Using (41) and (1503) yields:
% 66.93/29.12  																																																																																																																																								| (615) $false
% 66.93/29.12  																																																																																																																																								|
% 66.93/29.12  																																																																																																																																								|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																																							|-Branch two:
% 66.93/29.12  																																																																																																																																							| (1622) aNaturalNumber0(sz00) = all_22_2_29
% 66.93/29.12  																																																																																																																																							| (510) all_22_2_29 = 0
% 66.93/29.12  																																																																																																																																							|
% 66.93/29.12  																																																																																																																																								| From (510) and (1622) follows:
% 66.93/29.12  																																																																																																																																								| (41) aNaturalNumber0(sz00) = 0
% 66.93/29.12  																																																																																																																																								|
% 66.93/29.12  																																																																																																																																								+-Applying beta-rule and splitting (444), into two cases.
% 66.93/29.12  																																																																																																																																								|-Branch one:
% 66.93/29.12  																																																																																																																																								| (1229)  ~ (aNaturalNumber0(xn) = all_36_2_52)
% 66.93/29.12  																																																																																																																																								|
% 66.93/29.12  																																																																																																																																									| From (979) and (1229) follows:
% 66.93/29.12  																																																																																																																																									| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.12  																																																																																																																																									|
% 66.93/29.12  																																																																																																																																									| Using (53) and (1144) yields:
% 66.93/29.12  																																																																																																																																									| (615) $false
% 66.93/29.12  																																																																																																																																									|
% 66.93/29.12  																																																																																																																																									|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																																								|-Branch two:
% 66.93/29.12  																																																																																																																																								| (1232) aNaturalNumber0(xn) = all_36_2_52
% 66.93/29.12  																																																																																																																																								| (1629) all_36_2_52 = all_22_2_29
% 66.93/29.12  																																																																																																																																								|
% 66.93/29.12  																																																																																																																																									| Combining equations (979,1629) yields a new equation:
% 66.93/29.12  																																																																																																																																									| (510) all_22_2_29 = 0
% 66.93/29.12  																																																																																																																																									|
% 66.93/29.12  																																																																																																																																									| Combining equations (510,1629) yields a new equation:
% 66.93/29.12  																																																																																																																																									| (979) all_36_2_52 = 0
% 66.93/29.12  																																																																																																																																									|
% 66.93/29.12  																																																																																																																																									| From (979) and (1232) follows:
% 66.93/29.12  																																																																																																																																									| (53) aNaturalNumber0(xn) = 0
% 66.93/29.12  																																																																																																																																									|
% 66.93/29.12  																																																																																																																																									+-Applying beta-rule and splitting (415), into two cases.
% 66.93/29.12  																																																																																																																																									|-Branch one:
% 66.93/29.12  																																																																																																																																									| (1480)  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 66.93/29.12  																																																																																																																																									|
% 66.93/29.12  																																																																																																																																										| From (571) and (1480) follows:
% 66.93/29.12  																																																																																																																																										| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.12  																																																																																																																																										|
% 66.93/29.12  																																																																																																																																										| Using (53) and (1144) yields:
% 66.93/29.12  																																																																																																																																										| (615) $false
% 66.93/29.12  																																																																																																																																										|
% 66.93/29.12  																																																																																																																																										|-The branch is then unsatisfiable
% 66.93/29.12  																																																																																																																																									|-Branch two:
% 66.93/29.12  																																																																																																																																									| (1483) aNaturalNumber0(xn) = all_16_2_14
% 66.93/29.12  																																																																																																																																									| (1637) all_28_2_40 = all_16_2_14
% 66.93/29.13  																																																																																																																																									|
% 66.93/29.13  																																																																																																																																										| Combining equations (514,1637) yields a new equation:
% 66.93/29.13  																																																																																																																																										| (571) all_16_2_14 = 0
% 66.93/29.13  																																																																																																																																										|
% 66.93/29.13  																																																																																																																																										| From (571) and (1483) follows:
% 66.93/29.13  																																																																																																																																										| (53) aNaturalNumber0(xn) = 0
% 66.93/29.13  																																																																																																																																										|
% 66.93/29.13  																																																																																																																																										+-Applying beta-rule and splitting (332), into two cases.
% 66.93/29.13  																																																																																																																																										|-Branch one:
% 66.93/29.13  																																																																																																																																										| (1166)  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 66.93/29.13  																																																																																																																																										|
% 66.93/29.13  																																																																																																																																											| From (331) and (1166) follows:
% 66.93/29.13  																																																																																																																																											| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.13  																																																																																																																																											|
% 66.93/29.13  																																																																																																																																											| Using (53) and (1144) yields:
% 66.93/29.13  																																																																																																																																											| (615) $false
% 66.93/29.13  																																																																																																																																											|
% 66.93/29.13  																																																																																																																																											|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																										|-Branch two:
% 66.93/29.13  																																																																																																																																										| (1169) aNaturalNumber0(xn) = all_30_7_48
% 66.93/29.13  																																																																																																																																										| (331) all_30_7_48 = 0
% 66.93/29.13  																																																																																																																																										|
% 66.93/29.13  																																																																																																																																											| From (331) and (1169) follows:
% 66.93/29.13  																																																																																																																																											| (53) aNaturalNumber0(xn) = 0
% 66.93/29.13  																																																																																																																																											|
% 66.93/29.13  																																																																																																																																											+-Applying beta-rule and splitting (246), into two cases.
% 66.93/29.13  																																																																																																																																											|-Branch one:
% 66.93/29.13  																																																																																																																																											| (1646)  ~ (aNaturalNumber0(xn) = all_12_0_6)
% 66.93/29.13  																																																																																																																																											|
% 66.93/29.13  																																																																																																																																												| From (570) and (1646) follows:
% 66.93/29.13  																																																																																																																																												| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.13  																																																																																																																																												|
% 66.93/29.13  																																																																																																																																												| Using (53) and (1144) yields:
% 66.93/29.13  																																																																																																																																												| (615) $false
% 66.93/29.13  																																																																																																																																												|
% 66.93/29.13  																																																																																																																																												|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																											|-Branch two:
% 66.93/29.13  																																																																																																																																											| (1649) aNaturalNumber0(xn) = all_12_0_6
% 66.93/29.13  																																																																																																																																											| (570) all_12_0_6 = 0
% 66.93/29.13  																																																																																																																																											|
% 66.93/29.13  																																																																																																																																												| From (570) and (1649) follows:
% 66.93/29.13  																																																																																																																																												| (53) aNaturalNumber0(xn) = 0
% 66.93/29.13  																																																																																																																																												|
% 66.93/29.13  																																																																																																																																												+-Applying beta-rule and splitting (349), into two cases.
% 66.93/29.13  																																																																																																																																												|-Branch one:
% 66.93/29.13  																																																																																																																																												| (1338)  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 66.93/29.13  																																																																																																																																												|
% 66.93/29.13  																																																																																																																																													| From (979) and (1338) follows:
% 66.93/29.13  																																																																																																																																													| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.13  																																																																																																																																													|
% 66.93/29.13  																																																																																																																																													| Using (36) and (1191) yields:
% 66.93/29.13  																																																																																																																																													| (615) $false
% 66.93/29.13  																																																																																																																																													|
% 66.93/29.13  																																																																																																																																													|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																												|-Branch two:
% 66.93/29.13  																																																																																																																																												| (1341) aNaturalNumber0(xm) = all_36_2_52
% 66.93/29.13  																																																																																																																																												| (1656) all_36_2_52 = all_28_1_39
% 66.93/29.13  																																																																																																																																												|
% 66.93/29.13  																																																																																																																																													| Combining equations (979,1656) yields a new equation:
% 66.93/29.13  																																																																																																																																													| (515) all_28_1_39 = 0
% 66.93/29.13  																																																																																																																																													|
% 66.93/29.13  																																																																																																																																													| Combining equations (515,1656) yields a new equation:
% 66.93/29.13  																																																																																																																																													| (979) all_36_2_52 = 0
% 66.93/29.13  																																																																																																																																													|
% 66.93/29.13  																																																																																																																																													| From (979) and (1341) follows:
% 66.93/29.13  																																																																																																																																													| (36) aNaturalNumber0(xm) = 0
% 66.93/29.13  																																																																																																																																													|
% 66.93/29.13  																																																																																																																																													+-Applying beta-rule and splitting (307), into two cases.
% 66.93/29.13  																																																																																																																																													|-Branch one:
% 66.93/29.13  																																																																																																																																													| (1205)  ~ (aNaturalNumber0(xp) = all_26_2_37)
% 66.93/29.13  																																																																																																																																													|
% 66.93/29.13  																																																																																																																																														| From (572) and (1205) follows:
% 66.93/29.13  																																																																																																																																														| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.13  																																																																																																																																														|
% 66.93/29.13  																																																																																																																																														| Using (12) and (1198) yields:
% 66.93/29.13  																																																																																																																																														| (615) $false
% 66.93/29.13  																																																																																																																																														|
% 66.93/29.13  																																																																																																																																														|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																													|-Branch two:
% 66.93/29.13  																																																																																																																																													| (1208) aNaturalNumber0(xp) = all_26_2_37
% 66.93/29.13  																																																																																																																																													| (1664) all_26_1_36 = all_26_2_37
% 66.93/29.13  																																																																																																																																													|
% 66.93/29.13  																																																																																																																																														| Combining equations (303,1664) yields a new equation:
% 66.93/29.13  																																																																																																																																														| (572) all_26_2_37 = 0
% 66.93/29.13  																																																																																																																																														|
% 66.93/29.13  																																																																																																																																														| From (572) and (1208) follows:
% 66.93/29.13  																																																																																																																																														| (12) aNaturalNumber0(xp) = 0
% 66.93/29.13  																																																																																																																																														|
% 66.93/29.13  																																																																																																																																														+-Applying beta-rule and splitting (227), into two cases.
% 66.93/29.13  																																																																																																																																														|-Branch one:
% 66.93/29.13  																																																																																																																																														| (1386)  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 66.93/29.13  																																																																																																																																														|
% 66.93/29.13  																																																																																																																																															| From (572) and (1386) follows:
% 66.93/29.13  																																																																																																																																															| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.13  																																																																																																																																															|
% 66.93/29.13  																																																																																																																																															| Using (36) and (1191) yields:
% 66.93/29.13  																																																																																																																																															| (615) $false
% 66.93/29.13  																																																																																																																																															|
% 66.93/29.13  																																																																																																																																															|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																														|-Branch two:
% 66.93/29.13  																																																																																																																																														| (1389) aNaturalNumber0(xm) = all_26_2_37
% 66.93/29.13  																																																																																																																																														| (572) all_26_2_37 = 0
% 66.93/29.13  																																																																																																																																														|
% 66.93/29.13  																																																																																																																																															| From (572) and (1389) follows:
% 66.93/29.13  																																																																																																																																															| (36) aNaturalNumber0(xm) = 0
% 66.93/29.13  																																																																																																																																															|
% 66.93/29.13  																																																																																																																																															+-Applying beta-rule and splitting (460), into two cases.
% 66.93/29.13  																																																																																																																																															|-Branch one:
% 66.93/29.13  																																																																																																																																															| (1673)  ~ (aNaturalNumber0(xn) = all_41_1_55)
% 66.93/29.13  																																																																																																																																															|
% 66.93/29.13  																																																																																																																																																| From (980) and (1673) follows:
% 66.93/29.13  																																																																																																																																																| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.13  																																																																																																																																																|
% 66.93/29.13  																																																																																																																																																| Using (53) and (1144) yields:
% 66.93/29.13  																																																																																																																																																| (615) $false
% 66.93/29.13  																																																																																																																																																|
% 66.93/29.13  																																																																																																																																																|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																															|-Branch two:
% 66.93/29.13  																																																																																																																																															| (1676) aNaturalNumber0(xn) = all_41_1_55
% 66.93/29.13  																																																																																																																																															| (1677) all_41_1_55 = all_14_2_11
% 66.93/29.13  																																																																																																																																															|
% 66.93/29.13  																																																																																																																																																| Combining equations (980,1677) yields a new equation:
% 66.93/29.13  																																																																																																																																																| (451) all_14_2_11 = 0
% 66.93/29.13  																																																																																																																																																|
% 66.93/29.13  																																																																																																																																																| Combining equations (451,1677) yields a new equation:
% 66.93/29.13  																																																																																																																																																| (980) all_41_1_55 = 0
% 66.93/29.13  																																																																																																																																																|
% 66.93/29.13  																																																																																																																																																| From (980) and (1676) follows:
% 66.93/29.13  																																																																																																																																																| (53) aNaturalNumber0(xn) = 0
% 66.93/29.13  																																																																																																																																																|
% 66.93/29.13  																																																																																																																																																+-Applying beta-rule and splitting (243), into two cases.
% 66.93/29.13  																																																																																																																																																|-Branch one:
% 66.93/29.13  																																																																																																																																																| (1508)  ~ (aNaturalNumber0(xr) = all_12_0_6)
% 66.93/29.13  																																																																																																																																																|
% 66.93/29.13  																																																																																																																																																	| From (570) and (1508) follows:
% 66.93/29.13  																																																																																																																																																	| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 66.93/29.13  																																																																																																																																																	|
% 66.93/29.13  																																																																																																																																																	| Using (10) and (1287) yields:
% 66.93/29.13  																																																																																																																																																	| (615) $false
% 66.93/29.13  																																																																																																																																																	|
% 66.93/29.13  																																																																																																																																																	|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																																|-Branch two:
% 66.93/29.13  																																																																																																																																																| (1511) aNaturalNumber0(xr) = all_12_0_6
% 66.93/29.13  																																																																																																																																																| (570) all_12_0_6 = 0
% 66.93/29.13  																																																																																																																																																|
% 66.93/29.13  																																																																																																																																																	| From (570) and (1511) follows:
% 66.93/29.13  																																																																																																																																																	| (10) aNaturalNumber0(xr) = 0
% 66.93/29.13  																																																																																																																																																	|
% 66.93/29.13  																																																																																																																																																	+-Applying beta-rule and splitting (312), into two cases.
% 66.93/29.13  																																																																																																																																																	|-Branch one:
% 66.93/29.13  																																																																																																																																																	| (1280)  ~ (aNaturalNumber0(xp) = all_36_2_52)
% 66.93/29.13  																																																																																																																																																	|
% 66.93/29.13  																																																																																																																																																		| From (979) and (1280) follows:
% 66.93/29.13  																																																																																																																																																		| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 66.93/29.13  																																																																																																																																																		|
% 66.93/29.13  																																																																																																																																																		| Using (12) and (1198) yields:
% 66.93/29.13  																																																																																																																																																		| (615) $false
% 66.93/29.13  																																																																																																																																																		|
% 66.93/29.13  																																																																																																																																																		|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																																	|-Branch two:
% 66.93/29.13  																																																																																																																																																	| (1283) aNaturalNumber0(xp) = all_36_2_52
% 66.93/29.13  																																																																																																																																																	| (1691) all_36_2_52 = all_26_1_36
% 66.93/29.13  																																																																																																																																																	|
% 66.93/29.13  																																																																																																																																																		| Combining equations (979,1691) yields a new equation:
% 66.93/29.13  																																																																																																																																																		| (303) all_26_1_36 = 0
% 66.93/29.13  																																																																																																																																																		|
% 66.93/29.13  																																																																																																																																																		| Combining equations (303,1691) yields a new equation:
% 66.93/29.13  																																																																																																																																																		| (979) all_36_2_52 = 0
% 66.93/29.13  																																																																																																																																																		|
% 66.93/29.13  																																																																																																																																																		| From (979) and (1283) follows:
% 66.93/29.13  																																																																																																																																																		| (12) aNaturalNumber0(xp) = 0
% 66.93/29.13  																																																																																																																																																		|
% 66.93/29.13  																																																																																																																																																		+-Applying beta-rule and splitting (424), into two cases.
% 66.93/29.13  																																																																																																																																																		|-Branch one:
% 66.93/29.13  																																																																																																																																																		| (1695)  ~ (aNaturalNumber0(sz10) = all_24_4_34)
% 66.93/29.13  																																																																																																																																																		|
% 66.93/29.13  																																																																																																																																																			| From (511) and (1695) follows:
% 66.93/29.13  																																																																																																																																																			| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 66.93/29.13  																																																																																																																																																			|
% 66.93/29.13  																																																																																																																																																			| Using (16) and (1252) yields:
% 66.93/29.13  																																																																																																																																																			| (615) $false
% 66.93/29.13  																																																																																																																																																			|
% 66.93/29.13  																																																																																																																																																			|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																																		|-Branch two:
% 66.93/29.13  																																																																																																																																																		| (1698) aNaturalNumber0(sz10) = all_24_4_34
% 66.93/29.13  																																																																																																																																																		| (511) all_24_4_34 = 0
% 66.93/29.13  																																																																																																																																																		|
% 66.93/29.13  																																																																																																																																																			| From (511) and (1698) follows:
% 66.93/29.13  																																																																																																																																																			| (16) aNaturalNumber0(sz10) = 0
% 66.93/29.13  																																																																																																																																																			|
% 66.93/29.13  																																																																																																																																																			+-Applying beta-rule and splitting (402), into two cases.
% 66.93/29.13  																																																																																																																																																			|-Branch one:
% 66.93/29.13  																																																																																																																																																			| (1229)  ~ (aNaturalNumber0(xn) = all_36_2_52)
% 66.93/29.13  																																																																																																																																																			|
% 66.93/29.13  																																																																																																																																																				| From (979) and (1229) follows:
% 66.93/29.13  																																																																																																																																																				| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 66.93/29.13  																																																																																																																																																				|
% 66.93/29.13  																																																																																																																																																				| Using (53) and (1144) yields:
% 66.93/29.13  																																																																																																																																																				| (615) $false
% 66.93/29.13  																																																																																																																																																				|
% 66.93/29.13  																																																																																																																																																				|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																																			|-Branch two:
% 66.93/29.13  																																																																																																																																																			| (1232) aNaturalNumber0(xn) = all_36_2_52
% 66.93/29.13  																																																																																																																																																			| (1705) all_36_2_52 = all_30_8_49
% 66.93/29.13  																																																																																																																																																			|
% 66.93/29.13  																																																																																																																																																				| Combining equations (979,1705) yields a new equation:
% 66.93/29.13  																																																																																																																																																				| (516) all_30_8_49 = 0
% 66.93/29.13  																																																																																																																																																				|
% 66.93/29.13  																																																																																																																																																				| Combining equations (516,1705) yields a new equation:
% 66.93/29.13  																																																																																																																																																				| (979) all_36_2_52 = 0
% 66.93/29.13  																																																																																																																																																				|
% 66.93/29.13  																																																																																																																																																				| From (979) and (1232) follows:
% 66.93/29.13  																																																																																																																																																				| (53) aNaturalNumber0(xn) = 0
% 66.93/29.13  																																																																																																																																																				|
% 66.93/29.13  																																																																																																																																																				+-Applying beta-rule and splitting (283), into two cases.
% 66.93/29.13  																																																																																																																																																				|-Branch one:
% 66.93/29.13  																																																																																																																																																				| (974)  ~ (aNaturalNumber0(xk) = 0)
% 66.93/29.13  																																																																																																																																																				|
% 66.93/29.13  																																																																																																																																																					| Using (972) and (974) yields:
% 66.93/29.13  																																																																																																																																																					| (615) $false
% 66.93/29.13  																																																																																																																																																					|
% 66.93/29.13  																																																																																																																																																					|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																																				|-Branch two:
% 66.93/29.13  																																																																																																																																																				| (972) aNaturalNumber0(xk) = 0
% 66.93/29.13  																																																																																																																																																				| (979) all_36_2_52 = 0
% 66.93/29.13  																																																																																																																																																				|
% 66.93/29.13  																																																																																																																																																					+-Applying beta-rule and splitting (368), into two cases.
% 66.93/29.13  																																																																																																																																																					|-Branch one:
% 66.93/29.13  																																																																																																																																																					| (1562)  ~ (aNaturalNumber0(xm) = all_16_2_14)
% 66.93/29.13  																																																																																																																																																					|
% 66.93/29.13  																																																																																																																																																						| From (571) and (1562) follows:
% 66.93/29.13  																																																																																																																																																						| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 66.93/29.13  																																																																																																																																																						|
% 66.93/29.13  																																																																																																																																																						| Using (36) and (1191) yields:
% 66.93/29.13  																																																																																																																																																						| (615) $false
% 66.93/29.13  																																																																																																																																																						|
% 66.93/29.13  																																																																																																																																																						|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																																					|-Branch two:
% 66.93/29.13  																																																																																																																																																					| (1565) aNaturalNumber0(xm) = all_16_2_14
% 66.93/29.13  																																																																																																																																																					| (1717) all_22_1_28 = all_16_2_14
% 66.93/29.13  																																																																																																																																																					|
% 66.93/29.13  																																																																																																																																																						| Combining equations (499,1717) yields a new equation:
% 66.93/29.13  																																																																																																																																																						| (571) all_16_2_14 = 0
% 66.93/29.13  																																																																																																																																																						|
% 66.93/29.13  																																																																																																																																																						| From (571) and (1565) follows:
% 66.93/29.13  																																																																																																																																																						| (36) aNaturalNumber0(xm) = 0
% 66.93/29.13  																																																																																																																																																						|
% 66.93/29.13  																																																																																																																																																						+-Applying beta-rule and splitting (269), into two cases.
% 66.93/29.13  																																																																																																																																																						|-Branch one:
% 66.93/29.13  																																																																																																																																																						| (1720)  ~ (aNaturalNumber0(xr) = all_16_2_14)
% 66.93/29.13  																																																																																																																																																						|
% 66.93/29.13  																																																																																																																																																							| From (571) and (1720) follows:
% 66.93/29.13  																																																																																																																																																							| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 66.93/29.13  																																																																																																																																																							|
% 66.93/29.13  																																																																																																																																																							| Using (10) and (1287) yields:
% 66.93/29.13  																																																																																																																																																							| (615) $false
% 66.93/29.13  																																																																																																																																																							|
% 66.93/29.13  																																																																																																																																																							|-The branch is then unsatisfiable
% 66.93/29.13  																																																																																																																																																						|-Branch two:
% 66.93/29.13  																																																																																																																																																						| (1723) aNaturalNumber0(xr) = all_16_2_14
% 66.93/29.13  																																																																																																																																																						| (1724) all_36_3_53 = all_16_2_14
% 66.93/29.13  																																																																																																																																																						|
% 66.93/29.13  																																																																																																																																																							| Combining equations (480,1724) yields a new equation:
% 66.93/29.13  																																																																																																																																																							| (571) all_16_2_14 = 0
% 66.93/29.13  																																																																																																																																																							|
% 66.93/29.13  																																																																																																																																																							| Combining equations (571,1724) yields a new equation:
% 66.93/29.13  																																																																																																																																																							| (480) all_36_3_53 = 0
% 66.93/29.13  																																																																																																																																																							|
% 66.93/29.13  																																																																																																																																																							| From (571) and (1723) follows:
% 66.93/29.13  																																																																																																																																																							| (10) aNaturalNumber0(xr) = 0
% 66.93/29.13  																																																																																																																																																							|
% 66.93/29.13  																																																																																																																																																							+-Applying beta-rule and splitting (401), into two cases.
% 66.93/29.13  																																																																																																																																																							|-Branch one:
% 66.93/29.13  																																																																																																																																																							| (1728)  ~ (aNaturalNumber0(xn) = all_36_3_53)
% 66.93/29.13  																																																																																																																																																							|
% 66.93/29.13  																																																																																																																																																								| From (480) and (1728) follows:
% 66.93/29.13  																																																																																																																																																								| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.13  																																																																																																																																																								|
% 67.33/29.13  																																																																																																																																																								| Using (53) and (1144) yields:
% 67.33/29.13  																																																																																																																																																								| (615) $false
% 67.33/29.13  																																																																																																																																																								|
% 67.33/29.13  																																																																																																																																																								|-The branch is then unsatisfiable
% 67.33/29.13  																																																																																																																																																							|-Branch two:
% 67.33/29.13  																																																																																																																																																							| (1731) aNaturalNumber0(xn) = all_36_3_53
% 67.33/29.13  																																																																																																																																																							| (1732) all_36_3_53 = all_30_8_49
% 67.33/29.13  																																																																																																																																																							|
% 67.33/29.13  																																																																																																																																																								| Combining equations (480,1732) yields a new equation:
% 67.33/29.13  																																																																																																																																																								| (516) all_30_8_49 = 0
% 67.33/29.13  																																																																																																																																																								|
% 67.33/29.13  																																																																																																																																																								| Combining equations (516,1732) yields a new equation:
% 67.33/29.13  																																																																																																																																																								| (480) all_36_3_53 = 0
% 67.33/29.13  																																																																																																																																																								|
% 67.33/29.13  																																																																																																																																																								| From (480) and (1731) follows:
% 67.33/29.13  																																																																																																																																																								| (53) aNaturalNumber0(xn) = 0
% 67.33/29.13  																																																																																																																																																								|
% 67.33/29.13  																																																																																																																																																								+-Applying beta-rule and splitting (287), into two cases.
% 67.33/29.13  																																																																																																																																																								|-Branch one:
% 67.33/29.13  																																																																																																																																																								| (1265)  ~ (aNaturalNumber0(xk) = all_22_0_27)
% 67.33/29.13  																																																																																																																																																								|
% 67.33/29.13  																																																																																																																																																									| From (554) and (1265) follows:
% 67.33/29.13  																																																																																																																																																									| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.33/29.14  																																																																																																																																																									|
% 67.33/29.14  																																																																																																																																																									| Using (972) and (974) yields:
% 67.33/29.14  																																																																																																																																																									| (615) $false
% 67.33/29.14  																																																																																																																																																									|
% 67.33/29.14  																																																																																																																																																									|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																								|-Branch two:
% 67.33/29.14  																																																																																																																																																								| (1268) aNaturalNumber0(xk) = all_22_0_27
% 67.33/29.14  																																																																																																																																																								| (1740) all_36_2_52 = all_22_0_27
% 67.33/29.14  																																																																																																																																																								|
% 67.33/29.14  																																																																																																																																																									| Combining equations (979,1740) yields a new equation:
% 67.33/29.14  																																																																																																																																																									| (554) all_22_0_27 = 0
% 67.33/29.14  																																																																																																																																																									|
% 67.33/29.14  																																																																																																																																																									| Combining equations (554,1740) yields a new equation:
% 67.33/29.14  																																																																																																																																																									| (979) all_36_2_52 = 0
% 67.33/29.14  																																																																																																																																																									|
% 67.33/29.14  																																																																																																																																																									| From (554) and (1268) follows:
% 67.33/29.14  																																																																																																																																																									| (972) aNaturalNumber0(xk) = 0
% 67.33/29.14  																																																																																																																																																									|
% 67.33/29.14  																																																																																																																																																									+-Applying beta-rule and splitting (471), into two cases.
% 67.33/29.14  																																																																																																																																																									|-Branch one:
% 67.33/29.14  																																																																																																																																																									| (1245)  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 67.33/29.14  																																																																																																																																																									|
% 67.33/29.14  																																																																																																																																																										| From (572) and (1245) follows:
% 67.33/29.14  																																																																																																																																																										| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.14  																																																																																																																																																										|
% 67.33/29.14  																																																																																																																																																										| Using (53) and (1144) yields:
% 67.33/29.14  																																																																																																																																																										| (615) $false
% 67.33/29.14  																																																																																																																																																										|
% 67.33/29.14  																																																																																																																																																										|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																									|-Branch two:
% 67.33/29.14  																																																																																																																																																									| (1248) aNaturalNumber0(xn) = all_26_2_37
% 67.33/29.14  																																																																																																																																																									| (1748) all_26_2_37 = all_12_2_8
% 67.33/29.14  																																																																																																																																																									|
% 67.33/29.14  																																																																																																																																																										| Combining equations (572,1748) yields a new equation:
% 67.33/29.14  																																																																																																																																																										| (508) all_12_2_8 = 0
% 67.33/29.14  																																																																																																																																																										|
% 67.33/29.14  																																																																																																																																																										| Combining equations (508,1748) yields a new equation:
% 67.33/29.14  																																																																																																																																																										| (572) all_26_2_37 = 0
% 67.33/29.14  																																																																																																																																																										|
% 67.33/29.14  																																																																																																																																																										| From (572) and (1248) follows:
% 67.33/29.14  																																																																																																																																																										| (53) aNaturalNumber0(xn) = 0
% 67.33/29.14  																																																																																																																																																										|
% 67.33/29.14  																																																																																																																																																										+-Applying beta-rule and splitting (275), into two cases.
% 67.33/29.14  																																																																																																																																																										|-Branch one:
% 67.33/29.14  																																																																																																																																																										| (1673)  ~ (aNaturalNumber0(xn) = all_41_1_55)
% 67.33/29.14  																																																																																																																																																										|
% 67.33/29.14  																																																																																																																																																											| From (980) and (1673) follows:
% 67.33/29.14  																																																																																																																																																											| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.14  																																																																																																																																																											|
% 67.33/29.14  																																																																																																																																																											| Using (53) and (1144) yields:
% 67.33/29.14  																																																																																																																																																											| (615) $false
% 67.33/29.14  																																																																																																																																																											|
% 67.33/29.14  																																																																																																																																																											|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																										|-Branch two:
% 67.33/29.14  																																																																																																																																																										| (1676) aNaturalNumber0(xn) = all_41_1_55
% 67.33/29.14  																																																																																																																																																										| (980) all_41_1_55 = 0
% 67.33/29.14  																																																																																																																																																										|
% 67.33/29.14  																																																																																																																																																											| From (980) and (1676) follows:
% 67.33/29.14  																																																																																																																																																											| (53) aNaturalNumber0(xn) = 0
% 67.33/29.14  																																																																																																																																																											|
% 67.33/29.14  																																																																																																																																																											+-Applying beta-rule and splitting (467), into two cases.
% 67.33/29.14  																																																																																																																																																											|-Branch one:
% 67.33/29.14  																																																																																																																																																											| (1758)  ~ (aNaturalNumber0(sz10) = all_12_2_8)
% 67.33/29.14  																																																																																																																																																											|
% 67.33/29.14  																																																																																																																																																												| From (508) and (1758) follows:
% 67.33/29.14  																																																																																																																																																												| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 67.33/29.14  																																																																																																																																																												|
% 67.33/29.14  																																																																																																																																																												| Using (16) and (1252) yields:
% 67.33/29.14  																																																																																																																																																												| (615) $false
% 67.33/29.14  																																																																																																																																																												|
% 67.33/29.14  																																																																																																																																																												|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																											|-Branch two:
% 67.33/29.14  																																																																																																																																																											| (1761) aNaturalNumber0(sz10) = all_12_2_8
% 67.33/29.14  																																																																																																																																																											| (508) all_12_2_8 = 0
% 67.33/29.14  																																																																																																																																																											|
% 67.33/29.14  																																																																																																																																																												| From (508) and (1761) follows:
% 67.33/29.14  																																																																																																																																																												| (16) aNaturalNumber0(sz10) = 0
% 67.33/29.14  																																																																																																																																																												|
% 67.33/29.14  																																																																																																																																																												+-Applying beta-rule and splitting (273), into two cases.
% 67.33/29.14  																																																																																																																																																												|-Branch one:
% 67.33/29.14  																																																																																																																																																												| (1237)  ~ (aNaturalNumber0(xp) = all_41_1_55)
% 67.33/29.14  																																																																																																																																																												|
% 67.33/29.14  																																																																																																																																																													| From (980) and (1237) follows:
% 67.33/29.14  																																																																																																																																																													| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.33/29.14  																																																																																																																																																													|
% 67.33/29.14  																																																																																																																																																													| Using (12) and (1198) yields:
% 67.33/29.14  																																																																																																																																																													| (615) $false
% 67.33/29.14  																																																																																																																																																													|
% 67.33/29.14  																																																																																																																																																													|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																												|-Branch two:
% 67.33/29.14  																																																																																																																																																												| (1240) aNaturalNumber0(xp) = all_41_1_55
% 67.33/29.14  																																																																																																																																																												| (980) all_41_1_55 = 0
% 67.33/29.14  																																																																																																																																																												|
% 67.33/29.14  																																																																																																																																																													| From (980) and (1240) follows:
% 67.33/29.14  																																																																																																																																																													| (12) aNaturalNumber0(xp) = 0
% 67.33/29.14  																																																																																																																																																													|
% 67.33/29.14  																																																																																																																																																													+-Applying beta-rule and splitting (267), into two cases.
% 67.33/29.14  																																																																																																																																																													|-Branch one:
% 67.33/29.14  																																																																																																																																																													| (1442)  ~ (aNaturalNumber0(xr) = all_26_0_35)
% 67.33/29.14  																																																																																																																																																													|
% 67.33/29.14  																																																																																																																																																														| From (594) and (1442) follows:
% 67.33/29.14  																																																																																																																																																														| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 67.33/29.14  																																																																																																																																																														|
% 67.33/29.14  																																																																																																																																																														| Using (10) and (1287) yields:
% 67.33/29.14  																																																																																																																																																														| (615) $false
% 67.33/29.14  																																																																																																																																																														|
% 67.33/29.14  																																																																																																																																																														|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																													|-Branch two:
% 67.33/29.14  																																																																																																																																																													| (1445) aNaturalNumber0(xr) = all_26_0_35
% 67.33/29.14  																																																																																																																																																													| (1774) all_36_3_53 = all_26_0_35
% 67.33/29.14  																																																																																																																																																													|
% 67.33/29.14  																																																																																																																																																														| Combining equations (480,1774) yields a new equation:
% 67.33/29.14  																																																																																																																																																														| (594) all_26_0_35 = 0
% 67.33/29.14  																																																																																																																																																														|
% 67.33/29.14  																																																																																																																																																														| Combining equations (594,1774) yields a new equation:
% 67.33/29.14  																																																																																																																																																														| (480) all_36_3_53 = 0
% 67.33/29.14  																																																																																																																																																														|
% 67.33/29.14  																																																																																																																																																														| From (594) and (1445) follows:
% 67.33/29.14  																																																																																																																																																														| (10) aNaturalNumber0(xr) = 0
% 67.33/29.14  																																																																																																																																																														|
% 67.33/29.14  																																																																																																																																																														+-Applying beta-rule and splitting (367), into two cases.
% 67.33/29.14  																																																																																																																																																														|-Branch one:
% 67.33/29.14  																																																																																																																																																														| (1386)  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 67.33/29.14  																																																																																																																																																														|
% 67.33/29.14  																																																																																																																																																															| From (572) and (1386) follows:
% 67.33/29.14  																																																																																																																																																															| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.14  																																																																																																																																																															|
% 67.33/29.14  																																																																																																																																																															| Using (36) and (1191) yields:
% 67.33/29.14  																																																																																																																																																															| (615) $false
% 67.33/29.14  																																																																																																																																																															|
% 67.33/29.14  																																																																																																																																																															|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																														|-Branch two:
% 67.33/29.14  																																																																																																																																																														| (1389) aNaturalNumber0(xm) = all_26_2_37
% 67.33/29.14  																																																																																																																																																														| (1782) all_26_2_37 = all_22_1_28
% 67.33/29.14  																																																																																																																																																														|
% 67.33/29.14  																																																																																																																																																															| Combining equations (572,1782) yields a new equation:
% 67.33/29.14  																																																																																																																																																															| (499) all_22_1_28 = 0
% 67.33/29.14  																																																																																																																																																															|
% 67.33/29.14  																																																																																																																																																															| Combining equations (499,1782) yields a new equation:
% 67.33/29.14  																																																																																																																																																															| (572) all_26_2_37 = 0
% 67.33/29.14  																																																																																																																																																															|
% 67.33/29.14  																																																																																																																																																															| From (572) and (1389) follows:
% 67.33/29.14  																																																																																																																																																															| (36) aNaturalNumber0(xm) = 0
% 67.33/29.14  																																																																																																																																																															|
% 67.33/29.14  																																																																																																																																																															+-Applying beta-rule and splitting (364), into two cases.
% 67.33/29.14  																																																																																																																																																															|-Branch one:
% 67.33/29.14  																																																																																																																																																															| (1786)  ~ (aNaturalNumber0(sz00) = all_22_1_28)
% 67.33/29.14  																																																																																																																																																															|
% 67.33/29.14  																																																																																																																																																																| From (499) and (1786) follows:
% 67.33/29.14  																																																																																																																																																																| (1503)  ~ (aNaturalNumber0(sz00) = 0)
% 67.33/29.14  																																																																																																																																																																|
% 67.33/29.14  																																																																																																																																																																| Using (41) and (1503) yields:
% 67.33/29.14  																																																																																																																																																																| (615) $false
% 67.33/29.14  																																																																																																																																																																|
% 67.33/29.14  																																																																																																																																																																|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																															|-Branch two:
% 67.33/29.14  																																																																																																																																																															| (1789) aNaturalNumber0(sz00) = all_22_1_28
% 67.33/29.14  																																																																																																																																																															| (499) all_22_1_28 = 0
% 67.33/29.14  																																																																																																																																																															|
% 67.33/29.14  																																																																																																																																																																| From (499) and (1789) follows:
% 67.33/29.14  																																																																																																																																																																| (41) aNaturalNumber0(sz00) = 0
% 67.33/29.14  																																																																																																																																																																|
% 67.33/29.14  																																																																																																																																																																+-Applying beta-rule and splitting (420), into two cases.
% 67.33/29.14  																																																																																																																																																																|-Branch one:
% 67.33/29.14  																																																																																																																																																																| (1166)  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 67.33/29.14  																																																																																																																																																																|
% 67.33/29.14  																																																																																																																																																																	| From (331) and (1166) follows:
% 67.33/29.14  																																																																																																																																																																	| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.14  																																																																																																																																																																	|
% 67.33/29.14  																																																																																																																																																																	| Using (53) and (1144) yields:
% 67.33/29.14  																																																																																																																																																																	| (615) $false
% 67.33/29.14  																																																																																																																																																																	|
% 67.33/29.14  																																																																																																																																																																	|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																																|-Branch two:
% 67.33/29.14  																																																																																																																																																																| (1169) aNaturalNumber0(xn) = all_30_7_48
% 67.33/29.14  																																																																																																																																																																| (1796) all_30_7_48 = all_28_2_40
% 67.33/29.14  																																																																																																																																																																|
% 67.33/29.14  																																																																																																																																																																	| Combining equations (331,1796) yields a new equation:
% 67.33/29.14  																																																																																																																																																																	| (514) all_28_2_40 = 0
% 67.33/29.14  																																																																																																																																																																	|
% 67.33/29.14  																																																																																																																																																																	| Combining equations (514,1796) yields a new equation:
% 67.33/29.14  																																																																																																																																																																	| (331) all_30_7_48 = 0
% 67.33/29.14  																																																																																																																																																																	|
% 67.33/29.14  																																																																																																																																																																	| From (331) and (1169) follows:
% 67.33/29.14  																																																																																																																																																																	| (53) aNaturalNumber0(xn) = 0
% 67.33/29.14  																																																																																																																																																																	|
% 67.33/29.14  																																																																																																																																																																	+-Applying beta-rule and splitting (412), into two cases.
% 67.33/29.14  																																																																																																																																																																	|-Branch one:
% 67.33/29.14  																																																																																																																																																																	| (1151)  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 67.33/29.14  																																																																																																																																																																	|
% 67.33/29.14  																																																																																																																																																																		| From (554) and (1151) follows:
% 67.33/29.14  																																																																																																																																																																		| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.14  																																																																																																																																																																		|
% 67.33/29.14  																																																																																																																																																																		| Using (53) and (1144) yields:
% 67.33/29.14  																																																																																																																																																																		| (615) $false
% 67.33/29.14  																																																																																																																																																																		|
% 67.33/29.14  																																																																																																																																																																		|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																																	|-Branch two:
% 67.33/29.14  																																																																																																																																																																	| (1154) aNaturalNumber0(xn) = all_22_0_27
% 67.33/29.14  																																																																																																																																																																	| (1804) all_28_2_40 = all_22_0_27
% 67.33/29.14  																																																																																																																																																																	|
% 67.33/29.14  																																																																																																																																																																		| Combining equations (514,1804) yields a new equation:
% 67.33/29.14  																																																																																																																																																																		| (554) all_22_0_27 = 0
% 67.33/29.14  																																																																																																																																																																		|
% 67.33/29.14  																																																																																																																																																																		| From (554) and (1154) follows:
% 67.33/29.14  																																																																																																																																																																		| (53) aNaturalNumber0(xn) = 0
% 67.33/29.14  																																																																																																																																																																		|
% 67.33/29.14  																																																																																																																																																																		+-Applying beta-rule and splitting (417), into two cases.
% 67.33/29.14  																																																																																																																																																																		|-Branch one:
% 67.33/29.14  																																																																																																																																																																		| (1174)  ~ (aNaturalNumber0(xn) = all_41_2_56)
% 67.33/29.14  																																																																																																																																																																		|
% 67.33/29.14  																																																																																																																																																																			| From (253) and (1174) follows:
% 67.33/29.14  																																																																																																																																																																			| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.14  																																																																																																																																																																			|
% 67.33/29.14  																																																																																																																																																																			| Using (53) and (1144) yields:
% 67.33/29.14  																																																																																																																																																																			| (615) $false
% 67.33/29.14  																																																																																																																																																																			|
% 67.33/29.14  																																																																																																																																																																			|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																																		|-Branch two:
% 67.33/29.14  																																																																																																																																																																		| (1177) aNaturalNumber0(xn) = all_41_2_56
% 67.33/29.14  																																																																																																																																																																		| (1811) all_41_2_56 = all_28_2_40
% 67.33/29.14  																																																																																																																																																																		|
% 67.33/29.14  																																																																																																																																																																			| Combining equations (253,1811) yields a new equation:
% 67.33/29.14  																																																																																																																																																																			| (514) all_28_2_40 = 0
% 67.33/29.14  																																																																																																																																																																			|
% 67.33/29.14  																																																																																																																																																																			| Combining equations (514,1811) yields a new equation:
% 67.33/29.14  																																																																																																																																																																			| (253) all_41_2_56 = 0
% 67.33/29.14  																																																																																																																																																																			|
% 67.33/29.14  																																																																																																																																																																			| From (253) and (1177) follows:
% 67.33/29.14  																																																																																																																																																																			| (53) aNaturalNumber0(xn) = 0
% 67.33/29.14  																																																																																																																																																																			|
% 67.33/29.14  																																																																																																																																																																			+-Applying beta-rule and splitting (339), into two cases.
% 67.33/29.14  																																																																																																																																																																			|-Branch one:
% 67.33/29.14  																																																																																																																																																																			| (1314)  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 67.33/29.14  																																																																																																																																																																			|
% 67.33/29.14  																																																																																																																																																																				| From (253) and (1314) follows:
% 67.33/29.14  																																																																																																																																																																				| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.14  																																																																																																																																																																				|
% 67.33/29.14  																																																																																																																																																																				| Using (36) and (1191) yields:
% 67.33/29.14  																																																																																																																																																																				| (615) $false
% 67.33/29.14  																																																																																																																																																																				|
% 67.33/29.14  																																																																																																																																																																				|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																																			|-Branch two:
% 67.33/29.14  																																																																																																																																																																			| (1317) aNaturalNumber0(xm) = all_41_2_56
% 67.33/29.14  																																																																																																																																																																			| (1819) all_41_2_56 = all_30_7_48
% 67.33/29.14  																																																																																																																																																																			|
% 67.33/29.14  																																																																																																																																																																				| Combining equations (253,1819) yields a new equation:
% 67.33/29.14  																																																																																																																																																																				| (331) all_30_7_48 = 0
% 67.33/29.14  																																																																																																																																																																				|
% 67.33/29.14  																																																																																																																																																																				| Combining equations (331,1819) yields a new equation:
% 67.33/29.14  																																																																																																																																																																				| (253) all_41_2_56 = 0
% 67.33/29.14  																																																																																																																																																																				|
% 67.33/29.14  																																																																																																																																																																				| From (253) and (1317) follows:
% 67.33/29.14  																																																																																																																																																																				| (36) aNaturalNumber0(xm) = 0
% 67.33/29.14  																																																																																																																																																																				|
% 67.33/29.14  																																																																																																																																																																				+-Applying beta-rule and splitting (342), into two cases.
% 67.33/29.14  																																																																																																																																																																				|-Branch one:
% 67.33/29.14  																																																																																																																																																																				| (1338)  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 67.33/29.14  																																																																																																																																																																				|
% 67.33/29.14  																																																																																																																																																																					| From (979) and (1338) follows:
% 67.33/29.14  																																																																																																																																																																					| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.14  																																																																																																																																																																					|
% 67.33/29.14  																																																																																																																																																																					| Using (36) and (1191) yields:
% 67.33/29.14  																																																																																																																																																																					| (615) $false
% 67.33/29.14  																																																																																																																																																																					|
% 67.33/29.14  																																																																																																																																																																					|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																																				|-Branch two:
% 67.33/29.14  																																																																																																																																																																				| (1341) aNaturalNumber0(xm) = all_36_2_52
% 67.33/29.14  																																																																																																																																																																				| (1827) all_36_2_52 = all_30_7_48
% 67.33/29.14  																																																																																																																																																																				|
% 67.33/29.14  																																																																																																																																																																					| Combining equations (979,1827) yields a new equation:
% 67.33/29.14  																																																																																																																																																																					| (331) all_30_7_48 = 0
% 67.33/29.14  																																																																																																																																																																					|
% 67.33/29.14  																																																																																																																																																																					| Combining equations (331,1827) yields a new equation:
% 67.33/29.14  																																																																																																																																																																					| (979) all_36_2_52 = 0
% 67.33/29.14  																																																																																																																																																																					|
% 67.33/29.14  																																																																																																																																																																					| From (979) and (1341) follows:
% 67.33/29.14  																																																																																																																																																																					| (36) aNaturalNumber0(xm) = 0
% 67.33/29.14  																																																																																																																																																																					|
% 67.33/29.14  																																																																																																																																																																					+-Applying beta-rule and splitting (238), into two cases.
% 67.33/29.14  																																																																																																																																																																					|-Branch one:
% 67.33/29.14  																																																																																																																																																																					| (1831)  ~ (aNaturalNumber0(sz10) = all_16_2_14)
% 67.33/29.14  																																																																																																																																																																					|
% 67.33/29.14  																																																																																																																																																																						| From (571) and (1831) follows:
% 67.33/29.14  																																																																																																																																																																						| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 67.33/29.14  																																																																																																																																																																						|
% 67.33/29.14  																																																																																																																																																																						| Using (16) and (1252) yields:
% 67.33/29.14  																																																																																																																																																																						| (615) $false
% 67.33/29.14  																																																																																																																																																																						|
% 67.33/29.14  																																																																																																																																																																						|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																																					|-Branch two:
% 67.33/29.14  																																																																																																																																																																					| (1834) aNaturalNumber0(sz10) = all_16_2_14
% 67.33/29.14  																																																																																																																																																																					| (571) all_16_2_14 = 0
% 67.33/29.14  																																																																																																																																																																					|
% 67.33/29.14  																																																																																																																																																																						| From (571) and (1834) follows:
% 67.33/29.14  																																																																																																																																																																						| (16) aNaturalNumber0(sz10) = 0
% 67.33/29.14  																																																																																																																																																																						|
% 67.33/29.14  																																																																																																																																																																						+-Applying beta-rule and splitting (437), into two cases.
% 67.33/29.14  																																																																																																																																																																						|-Branch one:
% 67.33/29.14  																																																																																																																																																																						| (1370)  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 67.33/29.14  																																																																																																																																																																						|
% 67.33/29.14  																																																																																																																																																																							| From (555) and (1370) follows:
% 67.33/29.14  																																																																																																																																																																							| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.14  																																																																																																																																																																							|
% 67.33/29.14  																																																																																																																																																																							| Using (53) and (1144) yields:
% 67.33/29.14  																																																																																																																																																																							| (615) $false
% 67.33/29.14  																																																																																																																																																																							|
% 67.33/29.14  																																																																																																																																																																							|-The branch is then unsatisfiable
% 67.33/29.14  																																																																																																																																																																						|-Branch two:
% 67.33/29.14  																																																																																																																																																																						| (1373) aNaturalNumber0(xn) = all_36_1_51
% 67.33/29.14  																																																																																																																																																																						| (1841) all_36_1_51 = all_22_2_29
% 67.33/29.14  																																																																																																																																																																						|
% 67.33/29.15  																																																																																																																																																																							| Combining equations (555,1841) yields a new equation:
% 67.33/29.15  																																																																																																																																																																							| (510) all_22_2_29 = 0
% 67.33/29.15  																																																																																																																																																																							|
% 67.33/29.15  																																																																																																																																																																							| Combining equations (510,1841) yields a new equation:
% 67.33/29.15  																																																																																																																																																																							| (555) all_36_1_51 = 0
% 67.33/29.15  																																																																																																																																																																							|
% 67.33/29.15  																																																																																																																																																																							| From (555) and (1373) follows:
% 67.33/29.15  																																																																																																																																																																							| (53) aNaturalNumber0(xn) = 0
% 67.33/29.15  																																																																																																																																																																							|
% 67.33/29.15  																																																																																																																																																																							+-Applying beta-rule and splitting (435), into two cases.
% 67.33/29.15  																																																																																																																																																																							|-Branch one:
% 67.33/29.15  																																																																																																																																																																							| (1845)  ~ (aNaturalNumber0(sz10) = all_22_2_29)
% 67.33/29.15  																																																																																																																																																																							|
% 67.33/29.15  																																																																																																																																																																								| From (510) and (1845) follows:
% 67.33/29.15  																																																																																																																																																																								| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 67.33/29.15  																																																																																																																																																																								|
% 67.33/29.15  																																																																																																																																																																								| Using (16) and (1252) yields:
% 67.33/29.15  																																																																																																																																																																								| (615) $false
% 67.33/29.15  																																																																																																																																																																								|
% 67.33/29.15  																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																							|-Branch two:
% 67.33/29.15  																																																																																																																																																																							| (1848) aNaturalNumber0(sz10) = all_22_2_29
% 67.33/29.15  																																																																																																																																																																							| (510) all_22_2_29 = 0
% 67.33/29.15  																																																																																																																																																																							|
% 67.33/29.15  																																																																																																																																																																								| From (510) and (1848) follows:
% 67.33/29.15  																																																																																																																																																																								| (16) aNaturalNumber0(sz10) = 0
% 67.33/29.15  																																																																																																																																																																								|
% 67.33/29.15  																																																																																																																																																																								+-Applying beta-rule and splitting (371), into two cases.
% 67.33/29.15  																																																																																																																																																																								|-Branch one:
% 67.33/29.15  																																																																																																																																																																								| (1851)  ~ (aNaturalNumber0(xm) = all_41_1_55)
% 67.33/29.15  																																																																																																																																																																								|
% 67.33/29.15  																																																																																																																																																																									| From (980) and (1851) follows:
% 67.33/29.15  																																																																																																																																																																									| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.15  																																																																																																																																																																									|
% 67.33/29.15  																																																																																																																																																																									| Using (36) and (1191) yields:
% 67.33/29.15  																																																																																																																																																																									| (615) $false
% 67.33/29.15  																																																																																																																																																																									|
% 67.33/29.15  																																																																																																																																																																									|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																								|-Branch two:
% 67.33/29.15  																																																																																																																																																																								| (1854) aNaturalNumber0(xm) = all_41_1_55
% 67.33/29.15  																																																																																																																																																																								| (1855) all_41_1_55 = all_22_1_28
% 67.33/29.15  																																																																																																																																																																								|
% 67.33/29.15  																																																																																																																																																																									| Combining equations (980,1855) yields a new equation:
% 67.33/29.15  																																																																																																																																																																									| (499) all_22_1_28 = 0
% 67.33/29.15  																																																																																																																																																																									|
% 67.33/29.15  																																																																																																																																																																									| Combining equations (499,1855) yields a new equation:
% 67.33/29.15  																																																																																																																																																																									| (980) all_41_1_55 = 0
% 67.33/29.15  																																																																																																																																																																									|
% 67.33/29.15  																																																																																																																																																																									| From (980) and (1854) follows:
% 67.33/29.15  																																																																																																																																																																									| (36) aNaturalNumber0(xm) = 0
% 67.33/29.15  																																																																																																																																																																									|
% 67.33/29.15  																																																																																																																																																																									+-Applying beta-rule and splitting (235), into two cases.
% 67.33/29.15  																																																																																																																																																																									|-Branch one:
% 67.33/29.15  																																																																																																																																																																									| (1464)  ~ (aNaturalNumber0(xp) = all_16_2_14)
% 67.33/29.15  																																																																																																																																																																									|
% 67.33/29.15  																																																																																																																																																																										| From (571) and (1464) follows:
% 67.33/29.15  																																																																																																																																																																										| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.33/29.15  																																																																																																																																																																										|
% 67.33/29.15  																																																																																																																																																																										| Using (12) and (1198) yields:
% 67.33/29.15  																																																																																																																																																																										| (615) $false
% 67.33/29.15  																																																																																																																																																																										|
% 67.33/29.15  																																																																																																																																																																										|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																									|-Branch two:
% 67.33/29.15  																																																																																																																																																																									| (1467) aNaturalNumber0(xp) = all_16_2_14
% 67.33/29.15  																																																																																																																																																																									| (571) all_16_2_14 = 0
% 67.33/29.15  																																																																																																																																																																									|
% 67.33/29.15  																																																																																																																																																																										| From (571) and (1467) follows:
% 67.33/29.15  																																																																																																																																																																										| (12) aNaturalNumber0(xp) = 0
% 67.33/29.15  																																																																																																																																																																										|
% 67.33/29.15  																																																																																																																																																																										+-Applying beta-rule and splitting (211), into two cases.
% 67.33/29.15  																																																																																																																																																																										|-Branch one:
% 67.33/29.15  																																																																																																																																																																										| (1370)  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 67.33/29.15  																																																																																																																																																																										|
% 67.33/29.15  																																																																																																																																																																											| From (555) and (1370) follows:
% 67.33/29.15  																																																																																																																																																																											| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.15  																																																																																																																																																																											|
% 67.33/29.15  																																																																																																																																																																											| Using (53) and (1144) yields:
% 67.33/29.15  																																																																																																																																																																											| (615) $false
% 67.33/29.15  																																																																																																																																																																											|
% 67.33/29.15  																																																																																																																																																																											|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																										|-Branch two:
% 67.33/29.15  																																																																																																																																																																										| (1373) aNaturalNumber0(xn) = all_36_1_51
% 67.33/29.15  																																																																																																																																																																										| (555) all_36_1_51 = 0
% 67.33/29.15  																																																																																																																																																																										|
% 67.33/29.15  																																																																																																																																																																											| From (555) and (1373) follows:
% 67.33/29.15  																																																																																																																																																																											| (53) aNaturalNumber0(xn) = 0
% 67.33/29.15  																																																																																																																																																																											|
% 67.33/29.15  																																																																																																																																																																											+-Applying beta-rule and splitting (335), into two cases.
% 67.33/29.15  																																																																																																																																																																											|-Branch one:
% 67.33/29.15  																																																																																																																																																																											| (1871)  ~ (aNaturalNumber0(xm) = all_26_0_35)
% 67.33/29.15  																																																																																																																																																																											|
% 67.33/29.15  																																																																																																																																																																												| From (594) and (1871) follows:
% 67.33/29.15  																																																																																																																																																																												| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.15  																																																																																																																																																																												|
% 67.33/29.15  																																																																																																																																																																												| Using (36) and (1191) yields:
% 67.33/29.15  																																																																																																																																																																												| (615) $false
% 67.33/29.15  																																																																																																																																																																												|
% 67.33/29.15  																																																																																																																																																																												|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																											|-Branch two:
% 67.33/29.15  																																																																																																																																																																											| (1874) aNaturalNumber0(xm) = all_26_0_35
% 67.33/29.15  																																																																																																																																																																											| (1875) all_30_7_48 = all_26_0_35
% 67.33/29.15  																																																																																																																																																																											|
% 67.33/29.15  																																																																																																																																																																												| Combining equations (331,1875) yields a new equation:
% 67.33/29.15  																																																																																																																																																																												| (594) all_26_0_35 = 0
% 67.33/29.15  																																																																																																																																																																												|
% 67.33/29.15  																																																																																																																																																																												| Combining equations (594,1875) yields a new equation:
% 67.33/29.15  																																																																																																																																																																												| (331) all_30_7_48 = 0
% 67.33/29.15  																																																																																																																																																																												|
% 67.33/29.15  																																																																																																																																																																												| From (594) and (1874) follows:
% 67.33/29.15  																																																																																																																																																																												| (36) aNaturalNumber0(xm) = 0
% 67.33/29.15  																																																																																																																																																																												|
% 67.33/29.15  																																																																																																																																																																												+-Applying beta-rule and splitting (419), into two cases.
% 67.33/29.15  																																																																																																																																																																												|-Branch one:
% 67.33/29.15  																																																																																																																																																																												| (1673)  ~ (aNaturalNumber0(xn) = all_41_1_55)
% 67.33/29.15  																																																																																																																																																																												|
% 67.33/29.15  																																																																																																																																																																													| From (980) and (1673) follows:
% 67.33/29.15  																																																																																																																																																																													| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.15  																																																																																																																																																																													|
% 67.33/29.15  																																																																																																																																																																													| Using (53) and (1144) yields:
% 67.33/29.15  																																																																																																																																																																													| (615) $false
% 67.33/29.15  																																																																																																																																																																													|
% 67.33/29.15  																																																																																																																																																																													|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																												|-Branch two:
% 67.33/29.15  																																																																																																																																																																												| (1676) aNaturalNumber0(xn) = all_41_1_55
% 67.33/29.15  																																																																																																																																																																												| (1883) all_41_1_55 = all_28_2_40
% 67.33/29.15  																																																																																																																																																																												|
% 67.33/29.15  																																																																																																																																																																													| Combining equations (980,1883) yields a new equation:
% 67.33/29.15  																																																																																																																																																																													| (514) all_28_2_40 = 0
% 67.33/29.15  																																																																																																																																																																													|
% 67.33/29.15  																																																																																																																																																																													| Combining equations (514,1883) yields a new equation:
% 67.33/29.15  																																																																																																																																																																													| (980) all_41_1_55 = 0
% 67.33/29.15  																																																																																																																																																																													|
% 67.33/29.15  																																																																																																																																																																													| From (980) and (1676) follows:
% 67.33/29.15  																																																																																																																																																																													| (53) aNaturalNumber0(xn) = 0
% 67.33/29.15  																																																																																																																																																																													|
% 67.33/29.15  																																																																																																																																																																													+-Applying beta-rule and splitting (352), into two cases.
% 67.33/29.15  																																																																																																																																																																													|-Branch one:
% 67.33/29.15  																																																																																																																																																																													| (1887)  ~ (aNaturalNumber0(sz00) = all_24_3_33)
% 67.33/29.15  																																																																																																																																																																													|
% 67.33/29.15  																																																																																																																																																																														| From (483) and (1887) follows:
% 67.33/29.15  																																																																																																																																																																														| (1503)  ~ (aNaturalNumber0(sz00) = 0)
% 67.33/29.15  																																																																																																																																																																														|
% 67.33/29.15  																																																																																																																																																																														| Using (41) and (1503) yields:
% 67.33/29.15  																																																																																																																																																																														| (615) $false
% 67.33/29.15  																																																																																																																																																																														|
% 67.33/29.15  																																																																																																																																																																														|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																													|-Branch two:
% 67.33/29.15  																																																																																																																																																																													| (1890) aNaturalNumber0(sz00) = all_24_3_33
% 67.33/29.15  																																																																																																																																																																													| (483) all_24_3_33 = 0
% 67.33/29.15  																																																																																																																																																																													|
% 67.33/29.15  																																																																																																																																																																														| From (483) and (1890) follows:
% 67.33/29.15  																																																																																																																																																																														| (41) aNaturalNumber0(sz00) = 0
% 67.33/29.15  																																																																																																																																																																														|
% 67.33/29.15  																																																																																																																																																																														+-Applying beta-rule and splitting (374), into two cases.
% 67.33/29.15  																																																																																																																																																																														|-Branch one:
% 67.33/29.15  																																																																																																																																																																														| (1294)  ~ (aNaturalNumber0(xn) = all_14_1_10)
% 67.33/29.15  																																																																																																																																																																														|
% 67.33/29.15  																																																																																																																																																																															| From (503) and (1294) follows:
% 67.33/29.15  																																																																																																																																																																															| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.15  																																																																																																																																																																															|
% 67.33/29.15  																																																																																																																																																																															| Using (53) and (1144) yields:
% 67.33/29.15  																																																																																																																																																																															| (615) $false
% 67.33/29.15  																																																																																																																																																																															|
% 67.33/29.15  																																																																																																																																																																															|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																														|-Branch two:
% 67.33/29.15  																																																																																																																																																																														| (1297) aNaturalNumber0(xn) = all_14_1_10
% 67.33/29.15  																																																																																																																																																																														| (503) all_14_1_10 = 0
% 67.33/29.15  																																																																																																																																																																														|
% 67.33/29.15  																																																																																																																																																																															| From (503) and (1297) follows:
% 67.33/29.15  																																																																																																																																																																															| (53) aNaturalNumber0(xn) = 0
% 67.33/29.15  																																																																																																																																																																															|
% 67.33/29.15  																																																																																																																																																																															+-Applying beta-rule and splitting (418), into two cases.
% 67.33/29.15  																																																																																																																																																																															|-Branch one:
% 67.33/29.15  																																																																																																																																																																															| (1728)  ~ (aNaturalNumber0(xn) = all_36_3_53)
% 67.33/29.15  																																																																																																																																																																															|
% 67.33/29.15  																																																																																																																																																																																| From (480) and (1728) follows:
% 67.33/29.15  																																																																																																																																																																																| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.15  																																																																																																																																																																																|
% 67.33/29.15  																																																																																																																																																																																| Using (53) and (1144) yields:
% 67.33/29.15  																																																																																																																																																																																| (615) $false
% 67.33/29.15  																																																																																																																																																																																|
% 67.33/29.15  																																																																																																																																																																																|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																															|-Branch two:
% 67.33/29.15  																																																																																																																																																																															| (1731) aNaturalNumber0(xn) = all_36_3_53
% 67.33/29.15  																																																																																																																																																																															| (1903) all_36_3_53 = all_28_2_40
% 67.33/29.15  																																																																																																																																																																															|
% 67.33/29.15  																																																																																																																																																																																| Combining equations (480,1903) yields a new equation:
% 67.33/29.15  																																																																																																																																																																																| (514) all_28_2_40 = 0
% 67.33/29.15  																																																																																																																																																																																|
% 67.33/29.15  																																																																																																																																																																																| Combining equations (514,1903) yields a new equation:
% 67.33/29.15  																																																																																																																																																																																| (480) all_36_3_53 = 0
% 67.33/29.15  																																																																																																																																																																																|
% 67.33/29.15  																																																																																																																																																																																| From (480) and (1731) follows:
% 67.33/29.15  																																																																																																																																																																																| (53) aNaturalNumber0(xn) = 0
% 67.33/29.15  																																																																																																																																																																																|
% 67.33/29.15  																																																																																																																																																																																+-Applying beta-rule and splitting (383), into two cases.
% 67.33/29.15  																																																																																																																																																																																|-Branch one:
% 67.33/29.15  																																																																																																																																																																																| (1338)  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 67.33/29.15  																																																																																																																																																																																|
% 67.33/29.15  																																																																																																																																																																																	| From (979) and (1338) follows:
% 67.33/29.15  																																																																																																																																																																																	| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.15  																																																																																																																																																																																	|
% 67.33/29.15  																																																																																																																																																																																	| Using (36) and (1191) yields:
% 67.33/29.15  																																																																																																																																																																																	| (615) $false
% 67.33/29.15  																																																																																																																																																																																	|
% 67.33/29.15  																																																																																																																																																																																	|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																																|-Branch two:
% 67.33/29.15  																																																																																																																																																																																| (1341) aNaturalNumber0(xm) = all_36_2_52
% 67.33/29.15  																																																																																																																																																																																| (1911) all_36_2_52 = all_14_1_10
% 67.33/29.15  																																																																																																																																																																																|
% 67.33/29.15  																																																																																																																																																																																	| Combining equations (979,1911) yields a new equation:
% 67.33/29.15  																																																																																																																																																																																	| (503) all_14_1_10 = 0
% 67.33/29.15  																																																																																																																																																																																	|
% 67.33/29.15  																																																																																																																																																																																	| Combining equations (503,1911) yields a new equation:
% 67.33/29.15  																																																																																																																																																																																	| (979) all_36_2_52 = 0
% 67.33/29.15  																																																																																																																																																																																	|
% 67.33/29.15  																																																																																																																																																																																	| From (979) and (1341) follows:
% 67.33/29.15  																																																																																																																																																																																	| (36) aNaturalNumber0(xm) = 0
% 67.33/29.15  																																																																																																																																																																																	|
% 67.33/29.15  																																																																																																																																																																																	+-Applying beta-rule and splitting (356), into two cases.
% 67.33/29.15  																																																																																																																																																																																	|-Branch one:
% 67.33/29.15  																																																																																																																																																																																	| (1562)  ~ (aNaturalNumber0(xm) = all_16_2_14)
% 67.33/29.15  																																																																																																																																																																																	|
% 67.33/29.15  																																																																																																																																																																																		| From (571) and (1562) follows:
% 67.33/29.15  																																																																																																																																																																																		| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.15  																																																																																																																																																																																		|
% 67.33/29.15  																																																																																																																																																																																		| Using (36) and (1191) yields:
% 67.33/29.15  																																																																																																																																																																																		| (615) $false
% 67.33/29.15  																																																																																																																																																																																		|
% 67.33/29.15  																																																																																																																																																																																		|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																																	|-Branch two:
% 67.33/29.15  																																																																																																																																																																																	| (1565) aNaturalNumber0(xm) = all_16_2_14
% 67.33/29.15  																																																																																																																																																																																	| (1919) all_24_3_33 = all_16_2_14
% 67.33/29.15  																																																																																																																																																																																	|
% 67.33/29.15  																																																																																																																																																																																		| Combining equations (483,1919) yields a new equation:
% 67.33/29.15  																																																																																																																																																																																		| (571) all_16_2_14 = 0
% 67.33/29.15  																																																																																																																																																																																		|
% 67.33/29.15  																																																																																																																																																																																		| Combining equations (571,1919) yields a new equation:
% 67.33/29.15  																																																																																																																																																																																		| (483) all_24_3_33 = 0
% 67.33/29.15  																																																																																																																																																																																		|
% 67.33/29.15  																																																																																																																																																																																		| From (571) and (1565) follows:
% 67.33/29.15  																																																																																																																																																																																		| (36) aNaturalNumber0(xm) = 0
% 67.33/29.15  																																																																																																																																																																																		|
% 67.33/29.15  																																																																																																																																																																																		+-Applying beta-rule and splitting (476), into two cases.
% 67.33/29.15  																																																																																																																																																																																		|-Branch one:
% 67.33/29.15  																																																																																																																																																																																		| (1568)  ~ (aNaturalNumber0(xn) = all_24_3_33)
% 67.33/29.15  																																																																																																																																																																																		|
% 67.33/29.15  																																																																																																																																																																																			| From (483) and (1568) follows:
% 67.33/29.15  																																																																																																																																																																																			| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.15  																																																																																																																																																																																			|
% 67.33/29.15  																																																																																																																																																																																			| Using (53) and (1144) yields:
% 67.33/29.15  																																																																																																																																																																																			| (615) $false
% 67.33/29.15  																																																																																																																																																																																			|
% 67.33/29.15  																																																																																																																																																																																			|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																																		|-Branch two:
% 67.33/29.15  																																																																																																																																																																																		| (1571) aNaturalNumber0(xn) = all_24_3_33
% 67.33/29.15  																																																																																																																																																																																		| (1927) all_24_3_33 = all_12_2_8
% 67.33/29.15  																																																																																																																																																																																		|
% 67.33/29.15  																																																																																																																																																																																			| Combining equations (483,1927) yields a new equation:
% 67.33/29.15  																																																																																																																																																																																			| (508) all_12_2_8 = 0
% 67.33/29.15  																																																																																																																																																																																			|
% 67.33/29.15  																																																																																																																																																																																			| Combining equations (508,1927) yields a new equation:
% 67.33/29.15  																																																																																																																																																																																			| (483) all_24_3_33 = 0
% 67.33/29.15  																																																																																																																																																																																			|
% 67.33/29.15  																																																																																																																																																																																			| From (483) and (1571) follows:
% 67.33/29.15  																																																																																																																																																																																			| (53) aNaturalNumber0(xn) = 0
% 67.33/29.15  																																																																																																																																																																																			|
% 67.33/29.15  																																																																																																																																																																																			+-Applying beta-rule and splitting (245), into two cases.
% 67.33/29.15  																																																																																																																																																																																			|-Branch one:
% 67.33/29.15  																																																																																																																																																																																			| (1306)  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 67.33/29.15  																																																																																																																																																																																			|
% 67.33/29.15  																																																																																																																																																																																				| From (570) and (1306) follows:
% 67.33/29.15  																																																																																																																																																																																				| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.15  																																																																																																																																																																																				|
% 67.33/29.15  																																																																																																																																																																																				| Using (36) and (1191) yields:
% 67.33/29.15  																																																																																																																																																																																				| (615) $false
% 67.33/29.15  																																																																																																																																																																																				|
% 67.33/29.15  																																																																																																																																																																																				|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																																			|-Branch two:
% 67.33/29.15  																																																																																																																																																																																			| (1309) aNaturalNumber0(xm) = all_12_0_6
% 67.33/29.15  																																																																																																																																																																																			| (570) all_12_0_6 = 0
% 67.33/29.15  																																																																																																																																																																																			|
% 67.33/29.15  																																																																																																																																																																																				| From (570) and (1309) follows:
% 67.33/29.15  																																																																																																																																																																																				| (36) aNaturalNumber0(xm) = 0
% 67.33/29.15  																																																																																																																																																																																				|
% 67.33/29.15  																																																																																																																																																																																				+-Applying beta-rule and splitting (214), into two cases.
% 67.33/29.15  																																																																																																																																																																																				|-Branch one:
% 67.33/29.15  																																																																																																																																																																																				| (1937)  ~ (aNaturalNumber0(all_0_3_3) = 0)
% 67.33/29.15  																																																																																																																																																																																				|
% 67.33/29.15  																																																																																																																																																																																					| Using (556) and (1937) yields:
% 67.33/29.15  																																																																																																																																																																																					| (615) $false
% 67.33/29.15  																																																																																																																																																																																					|
% 67.33/29.15  																																																																																																																																																																																					|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																																				|-Branch two:
% 67.33/29.15  																																																																																																																																																																																				| (556) aNaturalNumber0(all_0_3_3) = 0
% 67.33/29.15  																																																																																																																																																																																				| (555) all_36_1_51 = 0
% 67.33/29.15  																																																																																																																																																																																				|
% 67.33/29.15  																																																																																																																																																																																					+-Applying beta-rule and splitting (433), into two cases.
% 67.33/29.15  																																																																																																																																																																																					|-Branch one:
% 67.33/29.15  																																																																																																																																																																																					| (1159)  ~ (aNaturalNumber0(xn) = all_12_1_7)
% 67.33/29.15  																																																																																																																																																																																					|
% 67.33/29.15  																																																																																																																																																																																						| From (507) and (1159) follows:
% 67.33/29.15  																																																																																																																																																																																						| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.15  																																																																																																																																																																																						|
% 67.33/29.15  																																																																																																																																																																																						| Using (53) and (1144) yields:
% 67.33/29.15  																																																																																																																																																																																						| (615) $false
% 67.33/29.15  																																																																																																																																																																																						|
% 67.33/29.15  																																																																																																																																																																																						|-The branch is then unsatisfiable
% 67.33/29.15  																																																																																																																																																																																					|-Branch two:
% 67.33/29.15  																																																																																																																																																																																					| (1162) aNaturalNumber0(xn) = all_12_1_7
% 67.33/29.16  																																																																																																																																																																																					| (1945) all_24_4_34 = all_12_1_7
% 67.33/29.16  																																																																																																																																																																																					|
% 67.33/29.16  																																																																																																																																																																																						| Combining equations (511,1945) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																						| (507) all_12_1_7 = 0
% 67.33/29.16  																																																																																																																																																																																						|
% 67.33/29.16  																																																																																																																																																																																						| From (507) and (1162) follows:
% 67.33/29.16  																																																																																																																																																																																						| (53) aNaturalNumber0(xn) = 0
% 67.33/29.16  																																																																																																																																																																																						|
% 67.33/29.16  																																																																																																																																																																																						+-Applying beta-rule and splitting (226), into two cases.
% 67.33/29.16  																																																																																																																																																																																						|-Branch one:
% 67.33/29.16  																																																																																																																																																																																						| (1286)  ~ (aNaturalNumber0(xr) = all_26_2_37)
% 67.33/29.16  																																																																																																																																																																																						|
% 67.33/29.16  																																																																																																																																																																																							| From (572) and (1286) follows:
% 67.33/29.16  																																																																																																																																																																																							| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 67.33/29.16  																																																																																																																																																																																							|
% 67.33/29.16  																																																																																																																																																																																							| Using (10) and (1287) yields:
% 67.33/29.16  																																																																																																																																																																																							| (615) $false
% 67.33/29.16  																																																																																																																																																																																							|
% 67.33/29.16  																																																																																																																																																																																							|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																						|-Branch two:
% 67.33/29.16  																																																																																																																																																																																						| (1289) aNaturalNumber0(xr) = all_26_2_37
% 67.33/29.16  																																																																																																																																																																																						| (572) all_26_2_37 = 0
% 67.33/29.16  																																																																																																																																																																																						|
% 67.33/29.16  																																																																																																																																																																																							| From (572) and (1289) follows:
% 67.33/29.16  																																																																																																																																																																																							| (10) aNaturalNumber0(xr) = 0
% 67.33/29.16  																																																																																																																																																																																							|
% 67.33/29.16  																																																																																																																																																																																							+-Applying beta-rule and splitting (217), into two cases.
% 67.33/29.16  																																																																																																																																																																																							|-Branch one:
% 67.33/29.16  																																																																																																																																																																																							| (1954)  ~ (aNaturalNumber0(sz10) = all_22_0_27)
% 67.33/29.16  																																																																																																																																																																																							|
% 67.33/29.16  																																																																																																																																																																																								| From (554) and (1954) follows:
% 67.33/29.16  																																																																																																																																																																																								| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 67.33/29.16  																																																																																																																																																																																								|
% 67.33/29.16  																																																																																																																																																																																								| Using (16) and (1252) yields:
% 67.33/29.16  																																																																																																																																																																																								| (615) $false
% 67.33/29.16  																																																																																																																																																																																								|
% 67.33/29.16  																																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																							|-Branch two:
% 67.33/29.16  																																																																																																																																																																																							| (1957) aNaturalNumber0(sz10) = all_22_0_27
% 67.33/29.16  																																																																																																																																																																																							| (554) all_22_0_27 = 0
% 67.33/29.16  																																																																																																																																																																																							|
% 67.33/29.16  																																																																																																																																																																																								| From (554) and (1957) follows:
% 67.33/29.16  																																																																																																																																																																																								| (16) aNaturalNumber0(sz10) = 0
% 67.33/29.16  																																																																																																																																																																																								|
% 67.33/29.16  																																																																																																																																																																																								+-Applying beta-rule and splitting (320), into two cases.
% 67.33/29.16  																																																																																																																																																																																								|-Branch one:
% 67.33/29.16  																																																																																																																																																																																								| (1272)  ~ (aNaturalNumber0(xp) = all_36_3_53)
% 67.33/29.16  																																																																																																																																																																																								|
% 67.33/29.16  																																																																																																																																																																																									| From (480) and (1272) follows:
% 67.33/29.16  																																																																																																																																																																																									| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.33/29.16  																																																																																																																																																																																									|
% 67.33/29.16  																																																																																																																																																																																									| Using (12) and (1198) yields:
% 67.33/29.16  																																																																																																																																																																																									| (615) $false
% 67.33/29.16  																																																																																																																																																																																									|
% 67.33/29.16  																																																																																																																																																																																									|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																								|-Branch two:
% 67.33/29.16  																																																																																																																																																																																								| (1275) aNaturalNumber0(xp) = all_36_3_53
% 67.33/29.16  																																																																																																																																																																																								| (1964) all_36_3_53 = all_24_2_32
% 67.33/29.16  																																																																																																																																																																																								|
% 67.33/29.16  																																																																																																																																																																																									| Combining equations (480,1964) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																									| (493) all_24_2_32 = 0
% 67.33/29.16  																																																																																																																																																																																									|
% 67.33/29.16  																																																																																																																																																																																									| Combining equations (493,1964) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																									| (480) all_36_3_53 = 0
% 67.33/29.16  																																																																																																																																																																																									|
% 67.33/29.16  																																																																																																																																																																																									| From (480) and (1275) follows:
% 67.33/29.16  																																																																																																																																																																																									| (12) aNaturalNumber0(xp) = 0
% 67.33/29.16  																																																																																																																																																																																									|
% 67.33/29.16  																																																																																																																																																																																									+-Applying beta-rule and splitting (455), into two cases.
% 67.33/29.16  																																																																																																																																																																																									|-Branch one:
% 67.33/29.16  																																																																																																																																																																																									| (1151)  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 67.33/29.16  																																																																																																																																																																																									|
% 67.33/29.16  																																																																																																																																																																																										| From (554) and (1151) follows:
% 67.33/29.16  																																																																																																																																																																																										| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.16  																																																																																																																																																																																										|
% 67.33/29.16  																																																																																																																																																																																										| Using (53) and (1144) yields:
% 67.33/29.16  																																																																																																																																																																																										| (615) $false
% 67.33/29.16  																																																																																																																																																																																										|
% 67.33/29.16  																																																																																																																																																																																										|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																									|-Branch two:
% 67.33/29.16  																																																																																																																																																																																									| (1154) aNaturalNumber0(xn) = all_22_0_27
% 67.33/29.16  																																																																																																																																																																																									| (1972) all_22_0_27 = all_14_2_11
% 67.33/29.16  																																																																																																																																																																																									|
% 67.33/29.16  																																																																																																																																																																																										| Combining equations (554,1972) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																										| (451) all_14_2_11 = 0
% 67.33/29.16  																																																																																																																																																																																										|
% 67.33/29.16  																																																																																																																																																																																										| Combining equations (451,1972) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																										| (554) all_22_0_27 = 0
% 67.33/29.16  																																																																																																																																																																																										|
% 67.33/29.16  																																																																																																																																																																																										| From (554) and (1154) follows:
% 67.33/29.16  																																																																																																																																																																																										| (53) aNaturalNumber0(xn) = 0
% 67.33/29.16  																																																																																																																																																																																										|
% 67.33/29.16  																																																																																																																																																																																										+-Applying beta-rule and splitting (333), into two cases.
% 67.33/29.16  																																																																																																																																																																																										|-Branch one:
% 67.33/29.16  																																																																																																																																																																																										| (1976)  ~ (aNaturalNumber0(sz00) = all_30_7_48)
% 67.33/29.16  																																																																																																																																																																																										|
% 67.33/29.16  																																																																																																																																																																																											| From (331) and (1976) follows:
% 67.33/29.16  																																																																																																																																																																																											| (1503)  ~ (aNaturalNumber0(sz00) = 0)
% 67.33/29.16  																																																																																																																																																																																											|
% 67.33/29.16  																																																																																																																																																																																											| Using (41) and (1503) yields:
% 67.33/29.16  																																																																																																																																																																																											| (615) $false
% 67.33/29.16  																																																																																																																																																																																											|
% 67.33/29.16  																																																																																																																																																																																											|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																										|-Branch two:
% 67.33/29.16  																																																																																																																																																																																										| (1979) aNaturalNumber0(sz00) = all_30_7_48
% 67.33/29.16  																																																																																																																																																																																										| (331) all_30_7_48 = 0
% 67.33/29.16  																																																																																																																																																																																										|
% 67.33/29.16  																																																																																																																																																																																											| From (331) and (1979) follows:
% 67.33/29.16  																																																																																																																																																																																											| (41) aNaturalNumber0(sz00) = 0
% 67.33/29.16  																																																																																																																																																																																											|
% 67.33/29.16  																																																																																																																																																																																											+-Applying beta-rule and splitting (362), into two cases.
% 67.33/29.16  																																																																																																																																																																																											|-Branch one:
% 67.33/29.16  																																																																																																																																																																																											| (1182)  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 67.33/29.16  																																																																																																																																																																																											|
% 67.33/29.16  																																																																																																																																																																																												| From (499) and (1182) follows:
% 67.33/29.16  																																																																																																																																																																																												| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.16  																																																																																																																																																																																												|
% 67.33/29.16  																																																																																																																																																																																												| Using (53) and (1144) yields:
% 67.33/29.16  																																																																																																																																																																																												| (615) $false
% 67.33/29.16  																																																																																																																																																																																												|
% 67.33/29.16  																																																																																																																																																																																												|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																											|-Branch two:
% 67.33/29.16  																																																																																																																																																																																											| (1185) aNaturalNumber0(xn) = all_22_1_28
% 67.33/29.16  																																																																																																																																																																																											| (499) all_22_1_28 = 0
% 67.33/29.16  																																																																																																																																																																																											|
% 67.33/29.16  																																																																																																																																																																																												| From (499) and (1185) follows:
% 67.33/29.16  																																																																																																																																																																																												| (53) aNaturalNumber0(xn) = 0
% 67.33/29.16  																																																																																																																																																																																												|
% 67.33/29.16  																																																																																																																																																																																												+-Applying beta-rule and splitting (329), into two cases.
% 67.33/29.16  																																																																																																																																																																																												|-Branch one:
% 67.33/29.16  																																																																																																																																																																																												| (1280)  ~ (aNaturalNumber0(xp) = all_36_2_52)
% 67.33/29.16  																																																																																																																																																																																												|
% 67.33/29.16  																																																																																																																																																																																													| From (979) and (1280) follows:
% 67.33/29.16  																																																																																																																																																																																													| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.33/29.16  																																																																																																																																																																																													|
% 67.33/29.16  																																																																																																																																																																																													| Using (12) and (1198) yields:
% 67.33/29.16  																																																																																																																																																																																													| (615) $false
% 67.33/29.16  																																																																																																																																																																																													|
% 67.33/29.16  																																																																																																																																																																																													|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																												|-Branch two:
% 67.33/29.16  																																																																																																																																																																																												| (1283) aNaturalNumber0(xp) = all_36_2_52
% 67.33/29.16  																																																																																																																																																																																												| (1992) all_36_2_52 = all_16_1_13
% 67.33/29.16  																																																																																																																																																																																												|
% 67.33/29.16  																																																																																																																																																																																													| Combining equations (979,1992) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																													| (497) all_16_1_13 = 0
% 67.33/29.16  																																																																																																																																																																																													|
% 67.33/29.16  																																																																																																																																																																																													| Combining equations (497,1992) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																													| (979) all_36_2_52 = 0
% 67.33/29.16  																																																																																																																																																																																													|
% 67.33/29.16  																																																																																																																																																																																													| From (979) and (1283) follows:
% 67.33/29.16  																																																																																																																																																																																													| (12) aNaturalNumber0(xp) = 0
% 67.33/29.16  																																																																																																																																																																																													|
% 67.33/29.16  																																																																																																																																																																																													+-Applying beta-rule and splitting (431), into two cases.
% 67.33/29.16  																																																																																																																																																																																													|-Branch one:
% 67.33/29.16  																																																																																																																																																																																													| (1166)  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 67.33/29.16  																																																																																																																																																																																													|
% 67.33/29.16  																																																																																																																																																																																														| From (331) and (1166) follows:
% 67.33/29.16  																																																																																																																																																																																														| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.16  																																																																																																																																																																																														|
% 67.33/29.16  																																																																																																																																																																																														| Using (53) and (1144) yields:
% 67.33/29.16  																																																																																																																																																																																														| (615) $false
% 67.33/29.16  																																																																																																																																																																																														|
% 67.33/29.16  																																																																																																																																																																																														|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																													|-Branch two:
% 67.33/29.16  																																																																																																																																																																																													| (1169) aNaturalNumber0(xn) = all_30_7_48
% 67.33/29.16  																																																																																																																																																																																													| (2000) all_30_7_48 = all_24_4_34
% 67.33/29.16  																																																																																																																																																																																													|
% 67.33/29.16  																																																																																																																																																																																														| Combining equations (331,2000) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																														| (511) all_24_4_34 = 0
% 67.33/29.16  																																																																																																																																																																																														|
% 67.33/29.16  																																																																																																																																																																																														| Combining equations (511,2000) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																														| (331) all_30_7_48 = 0
% 67.33/29.16  																																																																																																																																																																																														|
% 67.33/29.16  																																																																																																																																																																																														| From (331) and (1169) follows:
% 67.33/29.16  																																																																																																																																																																																														| (53) aNaturalNumber0(xn) = 0
% 67.33/29.16  																																																																																																																																																																																														|
% 67.33/29.16  																																																																																																																																																																																														+-Applying beta-rule and splitting (406), into two cases.
% 67.33/29.16  																																																																																																																																																																																														|-Branch one:
% 67.33/29.16  																																																																																																																																																																																														| (1182)  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 67.33/29.16  																																																																																																																																																																																														|
% 67.33/29.16  																																																																																																																																																																																															| From (499) and (1182) follows:
% 67.33/29.16  																																																																																																																																																																																															| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.16  																																																																																																																																																																																															|
% 67.33/29.16  																																																																																																																																																																																															| Using (53) and (1144) yields:
% 67.33/29.16  																																																																																																																																																																																															| (615) $false
% 67.33/29.16  																																																																																																																																																																																															|
% 67.33/29.16  																																																																																																																																																																																															|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																														|-Branch two:
% 67.33/29.16  																																																																																																																																																																																														| (1185) aNaturalNumber0(xn) = all_22_1_28
% 67.33/29.16  																																																																																																																																																																																														| (2008) all_30_8_49 = all_22_1_28
% 67.33/29.16  																																																																																																																																																																																														|
% 67.33/29.16  																																																																																																																																																																																															| Combining equations (516,2008) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																															| (499) all_22_1_28 = 0
% 67.33/29.16  																																																																																																																																																																																															|
% 67.33/29.16  																																																																																																																																																																																															| Combining equations (499,2008) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																															| (516) all_30_8_49 = 0
% 67.33/29.16  																																																																																																																																																																																															|
% 67.33/29.16  																																																																																																																																																																																															| From (499) and (1185) follows:
% 67.33/29.16  																																																																																																																																																																																															| (53) aNaturalNumber0(xn) = 0
% 67.33/29.16  																																																																																																																																																																																															|
% 67.33/29.16  																																																																																																																																																																																															+-Applying beta-rule and splitting (291), into two cases.
% 67.33/29.16  																																																																																																																																																																																															|-Branch one:
% 67.33/29.16  																																																																																																																																																																																															| (2012)  ~ (aNaturalNumber0(xk) = all_41_2_56)
% 67.33/29.16  																																																																																																																																																																																															|
% 67.33/29.16  																																																																																																																																																																																																| From (253) and (2012) follows:
% 67.33/29.16  																																																																																																																																																																																																| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.33/29.16  																																																																																																																																																																																																|
% 67.33/29.16  																																																																																																																																																																																																| Using (972) and (974) yields:
% 67.33/29.16  																																																																																																																																																																																																| (615) $false
% 67.33/29.16  																																																																																																																																																																																																|
% 67.33/29.16  																																																																																																																																																																																																|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																															|-Branch two:
% 67.33/29.16  																																																																																																																																																																																															| (2015) aNaturalNumber0(xk) = all_41_2_56
% 67.33/29.16  																																																																																																																																																																																															| (2016) all_41_2_56 = all_36_2_52
% 67.33/29.16  																																																																																																																																																																																															|
% 67.33/29.16  																																																																																																																																																																																																| Combining equations (253,2016) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																																| (979) all_36_2_52 = 0
% 67.33/29.16  																																																																																																																																																																																																|
% 67.33/29.16  																																																																																																																																																																																																| Combining equations (979,2016) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																																| (253) all_41_2_56 = 0
% 67.33/29.16  																																																																																																																																																																																																|
% 67.33/29.16  																																																																																																																																																																																																| From (253) and (2015) follows:
% 67.33/29.16  																																																																																																																																																																																																| (972) aNaturalNumber0(xk) = 0
% 67.33/29.16  																																																																																																																																																																																																|
% 67.33/29.16  																																																																																																																																																																																																+-Applying beta-rule and splitting (473), into two cases.
% 67.33/29.16  																																																																																																																																																																																																|-Branch one:
% 67.33/29.16  																																																																																																																																																																																																| (1673)  ~ (aNaturalNumber0(xn) = all_41_1_55)
% 67.33/29.16  																																																																																																																																																																																																|
% 67.33/29.16  																																																																																																																																																																																																	| From (980) and (1673) follows:
% 67.33/29.16  																																																																																																																																																																																																	| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.16  																																																																																																																																																																																																	|
% 67.33/29.16  																																																																																																																																																																																																	| Using (53) and (1144) yields:
% 67.33/29.16  																																																																																																																																																																																																	| (615) $false
% 67.33/29.16  																																																																																																																																																																																																	|
% 67.33/29.16  																																																																																																																																																																																																	|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																																|-Branch two:
% 67.33/29.16  																																																																																																																																																																																																| (1676) aNaturalNumber0(xn) = all_41_1_55
% 67.33/29.16  																																																																																																																																																																																																| (2024) all_41_1_55 = all_12_2_8
% 67.33/29.16  																																																																																																																																																																																																|
% 67.33/29.16  																																																																																																																																																																																																	| Combining equations (980,2024) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																																	| (508) all_12_2_8 = 0
% 67.33/29.16  																																																																																																																																																																																																	|
% 67.33/29.16  																																																																																																																																																																																																	| Combining equations (508,2024) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																																	| (980) all_41_1_55 = 0
% 67.33/29.16  																																																																																																																																																																																																	|
% 67.33/29.16  																																																																																																																																																																																																	| From (980) and (1676) follows:
% 67.33/29.16  																																																																																																																																																																																																	| (53) aNaturalNumber0(xn) = 0
% 67.33/29.16  																																																																																																																																																																																																	|
% 67.33/29.16  																																																																																																																																																																																																	+-Applying beta-rule and splitting (241), into two cases.
% 67.33/29.16  																																																																																																																																																																																																	|-Branch one:
% 67.33/29.16  																																																																																																																																																																																																	| (1603)  ~ (aNaturalNumber0(all_0_5_5) = all_26_0_35)
% 67.33/29.16  																																																																																																																																																																																																	|
% 67.33/29.16  																																																																																																																																																																																																		| From (594) and (1603) follows:
% 67.33/29.16  																																																																																																																																																																																																		| (1258)  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 67.33/29.16  																																																																																																																																																																																																		|
% 67.33/29.16  																																																																																																																																																																																																		| Using (573) and (1258) yields:
% 67.33/29.16  																																																																																																																																																																																																		| (615) $false
% 67.33/29.16  																																																																																																																																																																																																		|
% 67.33/29.16  																																																																																																																																																																																																		|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																																	|-Branch two:
% 67.33/29.16  																																																																																																																																																																																																	| (1606) aNaturalNumber0(all_0_5_5) = all_26_0_35
% 67.33/29.16  																																																																																																																																																																																																	| (2032) all_26_0_35 = all_16_2_14
% 67.33/29.16  																																																																																																																																																																																																	|
% 67.33/29.16  																																																																																																																																																																																																		| Combining equations (594,2032) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																																		| (571) all_16_2_14 = 0
% 67.33/29.16  																																																																																																																																																																																																		|
% 67.33/29.16  																																																																																																																																																																																																		| Combining equations (571,2032) yields a new equation:
% 67.33/29.16  																																																																																																																																																																																																		| (594) all_26_0_35 = 0
% 67.33/29.16  																																																																																																																																																																																																		|
% 67.33/29.16  																																																																																																																																																																																																		| From (594) and (1606) follows:
% 67.33/29.16  																																																																																																																																																																																																		| (573) aNaturalNumber0(all_0_5_5) = 0
% 67.33/29.16  																																																																																																																																																																																																		|
% 67.33/29.16  																																																																																																																																																																																																		+-Applying beta-rule and splitting (237), into two cases.
% 67.33/29.16  																																																																																																																																																																																																		|-Branch one:
% 67.33/29.16  																																																																																																																																																																																																		| (1480)  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 67.33/29.16  																																																																																																																																																																																																		|
% 67.33/29.16  																																																																																																																																																																																																			| From (571) and (1480) follows:
% 67.33/29.16  																																																																																																																																																																																																			| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.16  																																																																																																																																																																																																			|
% 67.33/29.16  																																																																																																																																																																																																			| Using (53) and (1144) yields:
% 67.33/29.16  																																																																																																																																																																																																			| (615) $false
% 67.33/29.16  																																																																																																																																																																																																			|
% 67.33/29.16  																																																																																																																																																																																																			|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																																		|-Branch two:
% 67.33/29.16  																																																																																																																																																																																																		| (1483) aNaturalNumber0(xn) = all_16_2_14
% 67.33/29.16  																																																																																																																																																																																																		| (571) all_16_2_14 = 0
% 67.33/29.16  																																																																																																																																																																																																		|
% 67.33/29.16  																																																																																																																																																																																																			| From (571) and (1483) follows:
% 67.33/29.16  																																																																																																																																																																																																			| (53) aNaturalNumber0(xn) = 0
% 67.33/29.16  																																																																																																																																																																																																			|
% 67.33/29.16  																																																																																																																																																																																																			+-Applying beta-rule and splitting (286), into two cases.
% 67.33/29.16  																																																																																																																																																																																																			|-Branch one:
% 67.33/29.16  																																																																																																																																																																																																			| (1229)  ~ (aNaturalNumber0(xn) = all_36_2_52)
% 67.33/29.16  																																																																																																																																																																																																			|
% 67.33/29.16  																																																																																																																																																																																																				| From (979) and (1229) follows:
% 67.33/29.16  																																																																																																																																																																																																				| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.16  																																																																																																																																																																																																				|
% 67.33/29.16  																																																																																																																																																																																																				| Using (53) and (1144) yields:
% 67.33/29.16  																																																																																																																																																																																																				| (615) $false
% 67.33/29.16  																																																																																																																																																																																																				|
% 67.33/29.16  																																																																																																																																																																																																				|-The branch is then unsatisfiable
% 67.33/29.16  																																																																																																																																																																																																			|-Branch two:
% 67.33/29.16  																																																																																																																																																																																																			| (1232) aNaturalNumber0(xn) = all_36_2_52
% 67.33/29.16  																																																																																																																																																																																																			| (979) all_36_2_52 = 0
% 67.33/29.16  																																																																																																																																																																																																			|
% 67.33/29.16  																																																																																																																																																																																																				| From (979) and (1232) follows:
% 67.33/29.16  																																																																																																																																																																																																				| (53) aNaturalNumber0(xn) = 0
% 67.33/29.16  																																																																																																																																																																																																				|
% 67.33/29.16  																																																																																																																																																																																																				+-Applying beta-rule and splitting (274), into two cases.
% 67.33/29.16  																																																																																																																																																																																																				|-Branch one:
% 67.33/29.16  																																																																																																																																																																																																				| (1851)  ~ (aNaturalNumber0(xm) = all_41_1_55)
% 67.33/29.16  																																																																																																																																																																																																				|
% 67.33/29.16  																																																																																																																																																																																																					| From (980) and (1851) follows:
% 67.33/29.17  																																																																																																																																																																																																					| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.17  																																																																																																																																																																																																					|
% 67.33/29.17  																																																																																																																																																																																																					| Using (36) and (1191) yields:
% 67.33/29.17  																																																																																																																																																																																																					| (615) $false
% 67.33/29.17  																																																																																																																																																																																																					|
% 67.33/29.17  																																																																																																																																																																																																					|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																				|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																				| (1854) aNaturalNumber0(xm) = all_41_1_55
% 67.33/29.17  																																																																																																																																																																																																				| (980) all_41_1_55 = 0
% 67.33/29.17  																																																																																																																																																																																																				|
% 67.33/29.17  																																																																																																																																																																																																					| From (980) and (1854) follows:
% 67.33/29.17  																																																																																																																																																																																																					| (36) aNaturalNumber0(xm) = 0
% 67.33/29.17  																																																																																																																																																																																																					|
% 67.33/29.17  																																																																																																																																																																																																					+-Applying beta-rule and splitting (309), into two cases.
% 67.33/29.17  																																																																																																																																																																																																					|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																					| (2054)  ~ (aNaturalNumber0(xp) = all_12_0_6)
% 67.33/29.17  																																																																																																																																																																																																					|
% 67.33/29.17  																																																																																																																																																																																																						| From (570) and (2054) follows:
% 67.33/29.17  																																																																																																																																																																																																						| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.33/29.17  																																																																																																																																																																																																						|
% 67.33/29.17  																																																																																																																																																																																																						| Using (12) and (1198) yields:
% 67.33/29.17  																																																																																																																																																																																																						| (615) $false
% 67.33/29.17  																																																																																																																																																																																																						|
% 67.33/29.17  																																																																																																																																																																																																						|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																					|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																					| (2057) aNaturalNumber0(xp) = all_12_0_6
% 67.33/29.17  																																																																																																																																																																																																					| (2058) all_26_1_36 = all_12_0_6
% 67.33/29.17  																																																																																																																																																																																																					|
% 67.33/29.17  																																																																																																																																																																																																						| Combining equations (303,2058) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																						| (570) all_12_0_6 = 0
% 67.33/29.17  																																																																																																																																																																																																						|
% 67.33/29.17  																																																																																																																																																																																																						| From (570) and (2057) follows:
% 67.33/29.17  																																																																																																																																																																																																						| (12) aNaturalNumber0(xp) = 0
% 67.33/29.17  																																																																																																																																																																																																						|
% 67.33/29.17  																																																																																																																																																																																																						+-Applying beta-rule and splitting (477), into two cases.
% 67.33/29.17  																																																																																																																																																																																																						|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																						| (1182)  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 67.33/29.17  																																																																																																																																																																																																						|
% 67.33/29.17  																																																																																																																																																																																																							| From (499) and (1182) follows:
% 67.33/29.17  																																																																																																																																																																																																							| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.17  																																																																																																																																																																																																							|
% 67.33/29.17  																																																																																																																																																																																																							| Using (53) and (1144) yields:
% 67.33/29.17  																																																																																																																																																																																																							| (615) $false
% 67.33/29.17  																																																																																																																																																																																																							|
% 67.33/29.17  																																																																																																																																																																																																							|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																						|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																						| (1185) aNaturalNumber0(xn) = all_22_1_28
% 67.33/29.17  																																																																																																																																																																																																						| (2065) all_22_1_28 = all_12_2_8
% 67.33/29.17  																																																																																																																																																																																																						|
% 67.33/29.17  																																																																																																																																																																																																							| Combining equations (499,2065) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																							| (508) all_12_2_8 = 0
% 67.33/29.17  																																																																																																																																																																																																							|
% 67.33/29.17  																																																																																																																																																																																																							| Combining equations (508,2065) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																							| (499) all_22_1_28 = 0
% 67.33/29.17  																																																																																																																																																																																																							|
% 67.33/29.17  																																																																																																																																																																																																							| From (499) and (1185) follows:
% 67.33/29.17  																																																																																																																																																																																																							| (53) aNaturalNumber0(xn) = 0
% 67.33/29.17  																																																																																																																																																																																																							|
% 67.33/29.17  																																																																																																																																																																																																							+-Applying beta-rule and splitting (255), into two cases.
% 67.33/29.17  																																																																																																																																																																																																							|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																							| (1314)  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 67.33/29.17  																																																																																																																																																																																																							|
% 67.33/29.17  																																																																																																																																																																																																								| From (253) and (1314) follows:
% 67.33/29.17  																																																																																																																																																																																																								| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.17  																																																																																																																																																																																																								|
% 67.33/29.17  																																																																																																																																																																																																								| Using (36) and (1191) yields:
% 67.33/29.17  																																																																																																																																																																																																								| (615) $false
% 67.33/29.17  																																																																																																																																																																																																								|
% 67.33/29.17  																																																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																							|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																							| (1317) aNaturalNumber0(xm) = all_41_2_56
% 67.33/29.17  																																																																																																																																																																																																							| (253) all_41_2_56 = 0
% 67.33/29.17  																																																																																																																																																																																																							|
% 67.33/29.17  																																																																																																																																																																																																								| From (253) and (1317) follows:
% 67.33/29.17  																																																																																																																																																																																																								| (36) aNaturalNumber0(xm) = 0
% 67.33/29.17  																																																																																																																																																																																																								|
% 67.33/29.17  																																																																																																																																																																																																								+-Applying beta-rule and splitting (413), into two cases.
% 67.33/29.17  																																																																																																																																																																																																								|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																								| (1354)  ~ (aNaturalNumber0(xn) = all_26_0_35)
% 67.33/29.17  																																																																																																																																																																																																								|
% 67.33/29.17  																																																																																																																																																																																																									| From (594) and (1354) follows:
% 67.33/29.17  																																																																																																																																																																																																									| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.17  																																																																																																																																																																																																									|
% 67.33/29.17  																																																																																																																																																																																																									| Using (53) and (1144) yields:
% 67.33/29.17  																																																																																																																																																																																																									| (615) $false
% 67.33/29.17  																																																																																																																																																																																																									|
% 67.33/29.17  																																																																																																																																																																																																									|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																								|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																								| (1357) aNaturalNumber0(xn) = all_26_0_35
% 67.33/29.17  																																																																																																																																																																																																								| (2079) all_28_2_40 = all_26_0_35
% 67.33/29.17  																																																																																																																																																																																																								|
% 67.33/29.17  																																																																																																																																																																																																									| Combining equations (514,2079) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																									| (594) all_26_0_35 = 0
% 67.33/29.17  																																																																																																																																																																																																									|
% 67.33/29.17  																																																																																																																																																																																																									| Combining equations (594,2079) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																									| (514) all_28_2_40 = 0
% 67.33/29.17  																																																																																																																																																																																																									|
% 67.33/29.17  																																																																																																																																																																																																									| From (594) and (1357) follows:
% 67.33/29.17  																																																																																																																																																																																																									| (53) aNaturalNumber0(xn) = 0
% 67.33/29.17  																																																																																																																																																																																																									|
% 67.33/29.17  																																																																																																																																																																																																									+-Applying beta-rule and splitting (441), into two cases.
% 67.33/29.17  																																																																																																																																																																																																									|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																									| (1480)  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 67.33/29.17  																																																																																																																																																																																																									|
% 67.33/29.17  																																																																																																																																																																																																										| From (571) and (1480) follows:
% 67.33/29.17  																																																																																																																																																																																																										| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.17  																																																																																																																																																																																																										|
% 67.33/29.17  																																																																																																																																																																																																										| Using (53) and (1144) yields:
% 67.33/29.17  																																																																																																																																																																																																										| (615) $false
% 67.33/29.17  																																																																																																																																																																																																										|
% 67.33/29.17  																																																																																																																																																																																																										|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																									|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																									| (1483) aNaturalNumber0(xn) = all_16_2_14
% 67.33/29.17  																																																																																																																																																																																																									| (2087) all_22_2_29 = all_16_2_14
% 67.33/29.17  																																																																																																																																																																																																									|
% 67.33/29.17  																																																																																																																																																																																																										| Combining equations (2087,510) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																										| (2088) all_16_2_14 = 0
% 67.33/29.17  																																																																																																																																																																																																										|
% 67.33/29.17  																																																																																																																																																																																																										| Simplifying 2088 yields:
% 67.33/29.17  																																																																																																																																																																																																										| (571) all_16_2_14 = 0
% 67.33/29.17  																																																																																																																																																																																																										|
% 67.33/29.17  																																																																																																																																																																																																										| From (571) and (1483) follows:
% 67.33/29.17  																																																																																																																																																																																																										| (53) aNaturalNumber0(xn) = 0
% 67.33/29.17  																																																																																																																																																																																																										|
% 67.33/29.17  																																																																																																																																																																																																										+-Applying beta-rule and splitting (474), into two cases.
% 67.33/29.17  																																																																																																																																																																																																										|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																										| (1229)  ~ (aNaturalNumber0(xn) = all_36_2_52)
% 67.33/29.17  																																																																																																																																																																																																										|
% 67.33/29.17  																																																																																																																																																																																																											| From (979) and (1229) follows:
% 67.33/29.17  																																																																																																																																																																																																											| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.17  																																																																																																																																																																																																											|
% 67.33/29.17  																																																																																																																																																																																																											| Using (53) and (1144) yields:
% 67.33/29.17  																																																																																																																																																																																																											| (615) $false
% 67.33/29.17  																																																																																																																																																																																																											|
% 67.33/29.17  																																																																																																																																																																																																											|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																										|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																										| (1232) aNaturalNumber0(xn) = all_36_2_52
% 67.33/29.17  																																																																																																																																																																																																										| (2095) all_36_2_52 = all_12_2_8
% 67.33/29.17  																																																																																																																																																																																																										|
% 67.33/29.17  																																																																																																																																																																																																											| Combining equations (979,2095) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																											| (508) all_12_2_8 = 0
% 67.33/29.17  																																																																																																																																																																																																											|
% 67.33/29.17  																																																																																																																																																																																																											| Combining equations (508,2095) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																											| (979) all_36_2_52 = 0
% 67.33/29.17  																																																																																																																																																																																																											|
% 67.33/29.17  																																																																																																																																																																																																											| From (979) and (1232) follows:
% 67.33/29.17  																																																																																																																																																																																																											| (53) aNaturalNumber0(xn) = 0
% 67.33/29.17  																																																																																																																																																																																																											|
% 67.33/29.17  																																																																																																																																																																																																											+-Applying beta-rule and splitting (318), into two cases.
% 67.33/29.17  																																																																																																																																																																																																											|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																											| (1464)  ~ (aNaturalNumber0(xp) = all_16_2_14)
% 67.33/29.17  																																																																																																																																																																																																											|
% 67.33/29.17  																																																																																																																																																																																																												| From (571) and (1464) follows:
% 67.33/29.17  																																																																																																																																																																																																												| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.33/29.17  																																																																																																																																																																																																												|
% 67.33/29.17  																																																																																																																																																																																																												| Using (12) and (1198) yields:
% 67.33/29.17  																																																																																																																																																																																																												| (615) $false
% 67.33/29.17  																																																																																																																																																																																																												|
% 67.33/29.17  																																																																																																																																																																																																												|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																											|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																											| (1467) aNaturalNumber0(xp) = all_16_2_14
% 67.33/29.17  																																																																																																																																																																																																											| (2103) all_24_2_32 = all_16_2_14
% 67.33/29.17  																																																																																																																																																																																																											|
% 67.33/29.17  																																																																																																																																																																																																												| Combining equations (493,2103) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																												| (571) all_16_2_14 = 0
% 67.33/29.17  																																																																																																																																																																																																												|
% 67.33/29.17  																																																																																																																																																																																																												| Combining equations (571,2103) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																												| (493) all_24_2_32 = 0
% 67.33/29.17  																																																																																																																																																																																																												|
% 67.33/29.17  																																																																																																																																																																																																												| From (571) and (1467) follows:
% 67.33/29.17  																																																																																																																																																																																																												| (12) aNaturalNumber0(xp) = 0
% 67.33/29.17  																																																																																																																																																																																																												|
% 67.33/29.17  																																																																																																																																																																																																												+-Applying beta-rule and splitting (464), into two cases.
% 67.33/29.17  																																																																																																																																																																																																												|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																												| (1294)  ~ (aNaturalNumber0(xn) = all_14_1_10)
% 67.33/29.17  																																																																																																																																																																																																												|
% 67.33/29.17  																																																																																																																																																																																																													| From (503) and (1294) follows:
% 67.33/29.17  																																																																																																																																																																																																													| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.17  																																																																																																																																																																																																													|
% 67.33/29.17  																																																																																																																																																																																																													| Using (53) and (1144) yields:
% 67.33/29.17  																																																																																																																																																																																																													| (615) $false
% 67.33/29.17  																																																																																																																																																																																																													|
% 67.33/29.17  																																																																																																																																																																																																													|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																												|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																												| (1297) aNaturalNumber0(xn) = all_14_1_10
% 67.33/29.17  																																																																																																																																																																																																												| (2111) all_14_1_10 = all_14_2_11
% 67.33/29.17  																																																																																																																																																																																																												|
% 67.33/29.17  																																																																																																																																																																																																													| Combining equations (503,2111) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																													| (451) all_14_2_11 = 0
% 67.33/29.17  																																																																																																																																																																																																													|
% 67.33/29.17  																																																																																																																																																																																																													| Combining equations (451,2111) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																													| (503) all_14_1_10 = 0
% 67.33/29.17  																																																																																																																																																																																																													|
% 67.33/29.17  																																																																																																																																																																																																													| From (503) and (1297) follows:
% 67.33/29.17  																																																																																																																																																																																																													| (53) aNaturalNumber0(xn) = 0
% 67.33/29.17  																																																																																																																																																																																																													|
% 67.33/29.17  																																																																																																																																																																																																													+-Applying beta-rule and splitting (213), into two cases.
% 67.33/29.17  																																																																																																																																																																																																													|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																													| (2115)  ~ (aNaturalNumber0(sz00) = all_36_1_51)
% 67.33/29.17  																																																																																																																																																																																																													|
% 67.33/29.17  																																																																																																																																																																																																														| From (555) and (2115) follows:
% 67.33/29.17  																																																																																																																																																																																																														| (1503)  ~ (aNaturalNumber0(sz00) = 0)
% 67.33/29.17  																																																																																																																																																																																																														|
% 67.33/29.17  																																																																																																																																																																																																														| Using (41) and (1503) yields:
% 67.33/29.17  																																																																																																																																																																																																														| (615) $false
% 67.33/29.17  																																																																																																																																																																																																														|
% 67.33/29.17  																																																																																																																																																																																																														|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																													|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																													| (2118) aNaturalNumber0(sz00) = all_36_1_51
% 67.33/29.17  																																																																																																																																																																																																													| (555) all_36_1_51 = 0
% 67.33/29.17  																																																																																																																																																																																																													|
% 67.33/29.17  																																																																																																																																																																																																														| From (555) and (2118) follows:
% 67.33/29.17  																																																																																																																																																																																																														| (41) aNaturalNumber0(sz00) = 0
% 67.33/29.17  																																																																																																																																																																																																														|
% 67.33/29.17  																																																																																																																																																																																																														+-Applying beta-rule and splitting (438), into two cases.
% 67.33/29.17  																																																																																																																																																																																																														|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																														| (1151)  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 67.33/29.17  																																																																																																																																																																																																														|
% 67.33/29.17  																																																																																																																																																																																																															| From (554) and (1151) follows:
% 67.33/29.17  																																																																																																																																																																																																															| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.17  																																																																																																																																																																																																															|
% 67.33/29.17  																																																																																																																																																																																																															| Using (53) and (1144) yields:
% 67.33/29.17  																																																																																																																																																																																																															| (615) $false
% 67.33/29.17  																																																																																																																																																																																																															|
% 67.33/29.17  																																																																																																																																																																																																															|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																														|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																														| (1154) aNaturalNumber0(xn) = all_22_0_27
% 67.33/29.17  																																																																																																																																																																																																														| (2125) all_22_0_27 = all_22_2_29
% 67.33/29.17  																																																																																																																																																																																																														|
% 67.33/29.17  																																																																																																																																																																																																															| Combining equations (554,2125) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																															| (510) all_22_2_29 = 0
% 67.33/29.17  																																																																																																																																																																																																															|
% 67.33/29.17  																																																																																																																																																																																																															| Combining equations (510,2125) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																															| (554) all_22_0_27 = 0
% 67.33/29.17  																																																																																																																																																																																																															|
% 67.33/29.17  																																																																																																																																																																																																															| From (554) and (1154) follows:
% 67.33/29.17  																																																																																																																																																																																																															| (53) aNaturalNumber0(xn) = 0
% 67.33/29.17  																																																																																																																																																																																																															|
% 67.33/29.17  																																																																																																																																																																																																															+-Applying beta-rule and splitting (355), into two cases.
% 67.33/29.17  																																																																																																																																																																																																															|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																															| (1386)  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 67.33/29.17  																																																																																																																																																																																																															|
% 67.33/29.17  																																																																																																																																																																																																																| From (572) and (1386) follows:
% 67.33/29.17  																																																																																																																																																																																																																| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.17  																																																																																																																																																																																																																|
% 67.33/29.17  																																																																																																																																																																																																																| Using (36) and (1191) yields:
% 67.33/29.17  																																																																																																																																																																																																																| (615) $false
% 67.33/29.17  																																																																																																																																																																																																																|
% 67.33/29.17  																																																																																																																																																																																																																|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																															|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																															| (1389) aNaturalNumber0(xm) = all_26_2_37
% 67.33/29.17  																																																																																																																																																																																																															| (2133) all_26_2_37 = all_24_3_33
% 67.33/29.17  																																																																																																																																																																																																															|
% 67.33/29.17  																																																																																																																																																																																																																| Combining equations (572,2133) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																																| (483) all_24_3_33 = 0
% 67.33/29.17  																																																																																																																																																																																																																|
% 67.33/29.17  																																																																																																																																																																																																																| Combining equations (483,2133) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																																| (572) all_26_2_37 = 0
% 67.33/29.17  																																																																																																																																																																																																																|
% 67.33/29.17  																																																																																																																																																																																																																| From (572) and (1389) follows:
% 67.33/29.17  																																																																																																																																																																																																																| (36) aNaturalNumber0(xm) = 0
% 67.33/29.17  																																																																																																																																																																																																																|
% 67.33/29.17  																																																																																																																																																																																																																+-Applying beta-rule and splitting (440), into two cases.
% 67.33/29.17  																																																																																																																																																																																																																|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																																| (1245)  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 67.33/29.17  																																																																																																																																																																																																																|
% 67.33/29.17  																																																																																																																																																																																																																	| From (572) and (1245) follows:
% 67.33/29.17  																																																																																																																																																																																																																	| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.17  																																																																																																																																																																																																																	|
% 67.33/29.17  																																																																																																																																																																																																																	| Using (53) and (1144) yields:
% 67.33/29.17  																																																																																																																																																																																																																	| (615) $false
% 67.33/29.17  																																																																																																																																																																																																																	|
% 67.33/29.17  																																																																																																																																																																																																																	|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																																|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																																| (1248) aNaturalNumber0(xn) = all_26_2_37
% 67.33/29.17  																																																																																																																																																																																																																| (2141) all_26_2_37 = all_22_2_29
% 67.33/29.17  																																																																																																																																																																																																																|
% 67.33/29.17  																																																																																																																																																																																																																	| Combining equations (572,2141) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																																	| (510) all_22_2_29 = 0
% 67.33/29.17  																																																																																																																																																																																																																	|
% 67.33/29.17  																																																																																																																																																																																																																	| Combining equations (510,2141) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																																	| (572) all_26_2_37 = 0
% 67.33/29.17  																																																																																																																																																																																																																	|
% 67.33/29.17  																																																																																																																																																																																																																	| From (572) and (1248) follows:
% 67.33/29.17  																																																																																																																																																																																																																	| (53) aNaturalNumber0(xn) = 0
% 67.33/29.17  																																																																																																																																																																																																																	|
% 67.33/29.17  																																																																																																																																																																																																																	+-Applying beta-rule and splitting (336), into two cases.
% 67.33/29.17  																																																																																																																																																																																																																	|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																																	| (1386)  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 67.33/29.17  																																																																																																																																																																																																																	|
% 67.33/29.17  																																																																																																																																																																																																																		| From (572) and (1386) follows:
% 67.33/29.17  																																																																																																																																																																																																																		| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.17  																																																																																																																																																																																																																		|
% 67.33/29.17  																																																																																																																																																																																																																		| Using (36) and (1191) yields:
% 67.33/29.17  																																																																																																																																																																																																																		| (615) $false
% 67.33/29.17  																																																																																																																																																																																																																		|
% 67.33/29.17  																																																																																																																																																																																																																		|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																																	|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																																	| (1389) aNaturalNumber0(xm) = all_26_2_37
% 67.33/29.17  																																																																																																																																																																																																																	| (2149) all_30_7_48 = all_26_2_37
% 67.33/29.17  																																																																																																																																																																																																																	|
% 67.33/29.17  																																																																																																																																																																																																																		| Combining equations (331,2149) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																																		| (572) all_26_2_37 = 0
% 67.33/29.17  																																																																																																																																																																																																																		|
% 67.33/29.17  																																																																																																																																																																																																																		| Combining equations (572,2149) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																																		| (331) all_30_7_48 = 0
% 67.33/29.17  																																																																																																																																																																																																																		|
% 67.33/29.17  																																																																																																																																																																																																																		| From (572) and (1389) follows:
% 67.33/29.17  																																																																																																																																																																																																																		| (36) aNaturalNumber0(xm) = 0
% 67.33/29.17  																																																																																																																																																																																																																		|
% 67.33/29.17  																																																																																																																																																																																																																		+-Applying beta-rule and splitting (459), into two cases.
% 67.33/29.17  																																																																																																																																																																																																																		|-Branch one:
% 67.33/29.17  																																																																																																																																																																																																																		| (1728)  ~ (aNaturalNumber0(xn) = all_36_3_53)
% 67.33/29.17  																																																																																																																																																																																																																		|
% 67.33/29.17  																																																																																																																																																																																																																			| From (480) and (1728) follows:
% 67.33/29.17  																																																																																																																																																																																																																			| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.17  																																																																																																																																																																																																																			|
% 67.33/29.17  																																																																																																																																																																																																																			| Using (53) and (1144) yields:
% 67.33/29.17  																																																																																																																																																																																																																			| (615) $false
% 67.33/29.17  																																																																																																																																																																																																																			|
% 67.33/29.17  																																																																																																																																																																																																																			|-The branch is then unsatisfiable
% 67.33/29.17  																																																																																																																																																																																																																		|-Branch two:
% 67.33/29.17  																																																																																																																																																																																																																		| (1731) aNaturalNumber0(xn) = all_36_3_53
% 67.33/29.17  																																																																																																																																																																																																																		| (2157) all_36_3_53 = all_14_2_11
% 67.33/29.17  																																																																																																																																																																																																																		|
% 67.33/29.17  																																																																																																																																																																																																																			| Combining equations (480,2157) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																																			| (451) all_14_2_11 = 0
% 67.33/29.17  																																																																																																																																																																																																																			|
% 67.33/29.17  																																																																																																																																																																																																																			| Combining equations (451,2157) yields a new equation:
% 67.33/29.17  																																																																																																																																																																																																																			| (480) all_36_3_53 = 0
% 67.33/29.17  																																																																																																																																																																																																																			|
% 67.33/29.17  																																																																																																																																																																																																																			| From (480) and (1731) follows:
% 67.33/29.17  																																																																																																																																																																																																																			| (53) aNaturalNumber0(xn) = 0
% 67.33/29.18  																																																																																																																																																																																																																			|
% 67.33/29.18  																																																																																																																																																																																																																			+-Applying beta-rule and splitting (337), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																			|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																			| (1562)  ~ (aNaturalNumber0(xm) = all_16_2_14)
% 67.33/29.18  																																																																																																																																																																																																																			|
% 67.33/29.18  																																																																																																																																																																																																																				| From (571) and (1562) follows:
% 67.33/29.18  																																																																																																																																																																																																																				| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.18  																																																																																																																																																																																																																				|
% 67.33/29.18  																																																																																																																																																																																																																				| Using (36) and (1191) yields:
% 67.33/29.18  																																																																																																																																																																																																																				| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																				|
% 67.33/29.18  																																																																																																																																																																																																																				|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																			|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																			| (1565) aNaturalNumber0(xm) = all_16_2_14
% 67.33/29.18  																																																																																																																																																																																																																			| (2165) all_30_7_48 = all_16_2_14
% 67.33/29.18  																																																																																																																																																																																																																			|
% 67.33/29.18  																																																																																																																																																																																																																				| Combining equations (331,2165) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																				| (571) all_16_2_14 = 0
% 67.33/29.18  																																																																																																																																																																																																																				|
% 67.33/29.18  																																																																																																																																																																																																																				| Combining equations (571,2165) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																				| (331) all_30_7_48 = 0
% 67.33/29.18  																																																																																																																																																																																																																				|
% 67.33/29.18  																																																																																																																																																																																																																				| From (571) and (1565) follows:
% 67.33/29.18  																																																																																																																																																																																																																				| (36) aNaturalNumber0(xm) = 0
% 67.33/29.18  																																																																																																																																																																																																																				|
% 67.33/29.18  																																																																																																																																																																																																																				+-Applying beta-rule and splitting (445), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																				|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																				| (1166)  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 67.33/29.18  																																																																																																																																																																																																																				|
% 67.33/29.18  																																																																																																																																																																																																																					| From (331) and (1166) follows:
% 67.33/29.18  																																																																																																																																																																																																																					| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.18  																																																																																																																																																																																																																					|
% 67.33/29.18  																																																																																																																																																																																																																					| Using (53) and (1144) yields:
% 67.33/29.18  																																																																																																																																																																																																																					| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																					|
% 67.33/29.18  																																																																																																																																																																																																																					|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																				|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																				| (1169) aNaturalNumber0(xn) = all_30_7_48
% 67.33/29.18  																																																																																																																																																																																																																				| (2173) all_30_7_48 = all_22_2_29
% 67.33/29.18  																																																																																																																																																																																																																				|
% 67.33/29.18  																																																																																																																																																																																																																					| Combining equations (331,2173) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																					| (510) all_22_2_29 = 0
% 67.33/29.18  																																																																																																																																																																																																																					|
% 67.33/29.18  																																																																																																																																																																																																																					| Combining equations (510,2173) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																					| (331) all_30_7_48 = 0
% 67.33/29.18  																																																																																																																																																																																																																					|
% 67.33/29.18  																																																																																																																																																																																																																					| From (331) and (1169) follows:
% 67.33/29.18  																																																																																																																																																																																																																					| (53) aNaturalNumber0(xn) = 0
% 67.33/29.18  																																																																																																																																																																																																																					|
% 67.33/29.18  																																																																																																																																																																																																																					+-Applying beta-rule and splitting (447), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																					|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																					| (1568)  ~ (aNaturalNumber0(xn) = all_24_3_33)
% 67.33/29.18  																																																																																																																																																																																																																					|
% 67.33/29.18  																																																																																																																																																																																																																						| From (483) and (1568) follows:
% 67.33/29.18  																																																																																																																																																																																																																						| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.18  																																																																																																																																																																																																																						|
% 67.33/29.18  																																																																																																																																																																																																																						| Using (53) and (1144) yields:
% 67.33/29.18  																																																																																																																																																																																																																						| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																						|
% 67.33/29.18  																																																																																																																																																																																																																						|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																					|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																					| (1571) aNaturalNumber0(xn) = all_24_3_33
% 67.33/29.18  																																																																																																																																																																																																																					| (2181) all_24_3_33 = all_22_2_29
% 67.33/29.18  																																																																																																																																																																																																																					|
% 67.33/29.18  																																																																																																																																																																																																																						| Combining equations (483,2181) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																						| (510) all_22_2_29 = 0
% 67.33/29.18  																																																																																																																																																																																																																						|
% 67.33/29.18  																																																																																																																																																																																																																						| Combining equations (510,2181) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																						| (483) all_24_3_33 = 0
% 67.33/29.18  																																																																																																																																																																																																																						|
% 67.33/29.18  																																																																																																																																																																																																																						| From (483) and (1571) follows:
% 67.33/29.18  																																																																																																																																																																																																																						| (53) aNaturalNumber0(xn) = 0
% 67.33/29.18  																																																																																																																																																																																																																						|
% 67.33/29.18  																																																																																																																																																																																																																						+-Applying beta-rule and splitting (458), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																						|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																						| (1174)  ~ (aNaturalNumber0(xn) = all_41_2_56)
% 67.33/29.18  																																																																																																																																																																																																																						|
% 67.33/29.18  																																																																																																																																																																																																																							| From (253) and (1174) follows:
% 67.33/29.18  																																																																																																																																																																																																																							| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.18  																																																																																																																																																																																																																							|
% 67.33/29.18  																																																																																																																																																																																																																							| Using (53) and (1144) yields:
% 67.33/29.18  																																																																																																																																																																																																																							| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																							|
% 67.33/29.18  																																																																																																																																																																																																																							|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																						|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																						| (1177) aNaturalNumber0(xn) = all_41_2_56
% 67.33/29.18  																																																																																																																																																																																																																						| (2189) all_41_2_56 = all_14_2_11
% 67.33/29.18  																																																																																																																																																																																																																						|
% 67.33/29.18  																																																																																																																																																																																																																							| Combining equations (253,2189) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																							| (451) all_14_2_11 = 0
% 67.33/29.18  																																																																																																																																																																																																																							|
% 67.33/29.18  																																																																																																																																																																																																																							| Combining equations (451,2189) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																							| (253) all_41_2_56 = 0
% 67.33/29.18  																																																																																																																																																																																																																							|
% 67.33/29.18  																																																																																																																																																																																																																							| From (253) and (1177) follows:
% 67.33/29.18  																																																																																																																																																																																																																							| (53) aNaturalNumber0(xn) = 0
% 67.33/29.18  																																																																																																																																																																																																																							|
% 67.33/29.18  																																																																																																																																																																																																																							+-Applying beta-rule and splitting (348), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																							|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																							| (1330)  ~ (aNaturalNumber0(xm) = all_36_3_53)
% 67.33/29.18  																																																																																																																																																																																																																							|
% 67.33/29.18  																																																																																																																																																																																																																								| From (480) and (1330) follows:
% 67.33/29.18  																																																																																																																																																																																																																								| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.18  																																																																																																																																																																																																																								|
% 67.33/29.18  																																																																																																																																																																																																																								| Using (36) and (1191) yields:
% 67.33/29.18  																																																																																																																																																																																																																								| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																								|
% 67.33/29.18  																																																																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																							|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																							| (1333) aNaturalNumber0(xm) = all_36_3_53
% 67.33/29.18  																																																																																																																																																																																																																							| (2197) all_36_3_53 = all_28_1_39
% 67.33/29.18  																																																																																																																																																																																																																							|
% 67.33/29.18  																																																																																																																																																																																																																								| Combining equations (480,2197) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																								| (515) all_28_1_39 = 0
% 67.33/29.18  																																																																																																																																																																																																																								|
% 67.33/29.18  																																																																																																																																																																																																																								| Combining equations (515,2197) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																								| (480) all_36_3_53 = 0
% 67.33/29.18  																																																																																																																																																																																																																								|
% 67.33/29.18  																																																																																																																																																																																																																								| From (480) and (1333) follows:
% 67.33/29.18  																																																																																																																																																																																																																								| (36) aNaturalNumber0(xm) = 0
% 67.33/29.18  																																																																																																																																																																																																																								|
% 67.33/29.18  																																																																																																																																																																																																																								+-Applying beta-rule and splitting (279), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																								|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																								| (2201)  ~ (aNaturalNumber0(xk) = all_26_2_37)
% 67.33/29.18  																																																																																																																																																																																																																								|
% 67.33/29.18  																																																																																																																																																																																																																									| From (572) and (2201) follows:
% 67.33/29.18  																																																																																																																																																																																																																									| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.33/29.18  																																																																																																																																																																																																																									|
% 67.33/29.18  																																																																																																																																																																																																																									| Using (972) and (974) yields:
% 67.33/29.18  																																																																																																																																																																																																																									| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																									|
% 67.33/29.18  																																																																																																																																																																																																																									|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																								|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																								| (2204) aNaturalNumber0(xk) = all_26_2_37
% 67.33/29.18  																																																																																																																																																																																																																								| (2205) all_41_1_55 = all_26_2_37
% 67.33/29.18  																																																																																																																																																																																																																								|
% 67.33/29.18  																																																																																																																																																																																																																									| Combining equations (980,2205) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																									| (572) all_26_2_37 = 0
% 67.33/29.18  																																																																																																																																																																																																																									|
% 67.33/29.18  																																																																																																																																																																																																																									| Combining equations (572,2205) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																									| (980) all_41_1_55 = 0
% 67.33/29.18  																																																																																																																																																																																																																									|
% 67.33/29.18  																																																																																																																																																																																																																									| From (572) and (2204) follows:
% 67.33/29.18  																																																																																																																																																																																																																									| (972) aNaturalNumber0(xk) = 0
% 67.33/29.18  																																																																																																																																																																																																																									|
% 67.33/29.18  																																																																																																																																																																																																																									+-Applying beta-rule and splitting (263), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																									|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																									| (1330)  ~ (aNaturalNumber0(xm) = all_36_3_53)
% 67.33/29.18  																																																																																																																																																																																																																									|
% 67.33/29.18  																																																																																																																																																																																																																										| From (480) and (1330) follows:
% 67.33/29.18  																																																																																																																																																																																																																										| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.18  																																																																																																																																																																																																																										|
% 67.33/29.18  																																																																																																																																																																																																																										| Using (36) and (1191) yields:
% 67.33/29.18  																																																																																																																																																																																																																										| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																										|
% 67.33/29.18  																																																																																																																																																																																																																										|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																									|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																									| (1333) aNaturalNumber0(xm) = all_36_3_53
% 67.33/29.18  																																																																																																																																																																																																																									| (480) all_36_3_53 = 0
% 67.33/29.18  																																																																																																																																																																																																																									|
% 67.33/29.18  																																																																																																																																																																																																																										| From (480) and (1333) follows:
% 67.33/29.18  																																																																																																																																																																																																																										| (36) aNaturalNumber0(xm) = 0
% 67.33/29.18  																																																																																																																																																																																																																										|
% 67.33/29.18  																																																																																																																																																																																																																										+-Applying beta-rule and splitting (325), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																										|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																										| (1464)  ~ (aNaturalNumber0(xp) = all_16_2_14)
% 67.33/29.18  																																																																																																																																																																																																																										|
% 67.33/29.18  																																																																																																																																																																																																																											| From (571) and (1464) follows:
% 67.33/29.18  																																																																																																																																																																																																																											| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.33/29.18  																																																																																																																																																																																																																											|
% 67.33/29.18  																																																																																																																																																																																																																											| Using (12) and (1198) yields:
% 67.33/29.18  																																																																																																																																																																																																																											| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																											|
% 67.33/29.18  																																																																																																																																																																																																																											|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																										|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																										| (1467) aNaturalNumber0(xp) = all_16_2_14
% 67.33/29.18  																																																																																																																																																																																																																										| (2219) all_16_1_13 = all_16_2_14
% 67.33/29.18  																																																																																																																																																																																																																										|
% 67.33/29.18  																																																																																																																																																																																																																											| Combining equations (497,2219) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																											| (571) all_16_2_14 = 0
% 67.33/29.18  																																																																																																																																																																																																																											|
% 67.33/29.18  																																																																																																																																																																																																																											| From (571) and (1467) follows:
% 67.33/29.18  																																																																																																																																																																																																																											| (12) aNaturalNumber0(xp) = 0
% 67.33/29.18  																																																																																																																																																																																																																											|
% 67.33/29.18  																																																																																																																																																																																																																											+-Applying beta-rule and splitting (296), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																											|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																											| (1213)  ~ (aNaturalNumber0(xp) = all_26_0_35)
% 67.33/29.18  																																																																																																																																																																																																																											|
% 67.33/29.18  																																																																																																																																																																																																																												| From (594) and (1213) follows:
% 67.33/29.18  																																																																																																																																																																																																																												| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.33/29.18  																																																																																																																																																																																																																												|
% 67.33/29.18  																																																																																																																																																																																																																												| Using (12) and (1198) yields:
% 67.33/29.18  																																																																																																																																																																																																																												| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																												|
% 67.33/29.18  																																																																																																																																																																																																																												|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																											|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																											| (1216) aNaturalNumber0(xp) = all_26_0_35
% 67.33/29.18  																																																																																																																																																																																																																											| (2226) all_30_6_47 = all_26_0_35
% 67.33/29.18  																																																																																																																																																																																																																											|
% 67.33/29.18  																																																																																																																																																																																																																												| Combining equations (1242,2226) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																												| (594) all_26_0_35 = 0
% 67.33/29.18  																																																																																																																																																																																																																												|
% 67.33/29.18  																																																																																																																																																																																																																												| From (594) and (1216) follows:
% 67.33/29.18  																																																																																																																																																																																																																												| (12) aNaturalNumber0(xp) = 0
% 67.33/29.18  																																																																																																																																																																																																																												|
% 67.33/29.18  																																																																																																																																																																																																																												+-Applying beta-rule and splitting (382), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																												|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																												| (1330)  ~ (aNaturalNumber0(xm) = all_36_3_53)
% 67.33/29.18  																																																																																																																																																																																																																												|
% 67.33/29.18  																																																																																																																																																																																																																													| From (480) and (1330) follows:
% 67.33/29.18  																																																																																																																																																																																																																													| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.18  																																																																																																																																																																																																																													|
% 67.33/29.18  																																																																																																																																																																																																																													| Using (36) and (1191) yields:
% 67.33/29.18  																																																																																																																																																																																																																													| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																													|
% 67.33/29.18  																																																																																																																																																																																																																													|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																												|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																												| (1333) aNaturalNumber0(xm) = all_36_3_53
% 67.33/29.18  																																																																																																																																																																																																																												| (2233) all_36_3_53 = all_14_1_10
% 67.33/29.18  																																																																																																																																																																																																																												|
% 67.33/29.18  																																																																																																																																																																																																																													| Combining equations (480,2233) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																													| (503) all_14_1_10 = 0
% 67.33/29.18  																																																																																																																																																																																																																													|
% 67.33/29.18  																																																																																																																																																																																																																													| Combining equations (503,2233) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																													| (480) all_36_3_53 = 0
% 67.33/29.18  																																																																																																																																																																																																																													|
% 67.33/29.18  																																																																																																																																																																																																																													| From (480) and (1333) follows:
% 67.33/29.18  																																																																																																																																																																																																																													| (36) aNaturalNumber0(xm) = 0
% 67.33/29.18  																																																																																																																																																																																																																													|
% 67.33/29.18  																																																																																																																																																																																																																													+-Applying beta-rule and splitting (209), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																													|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																													| (1418)  ~ (aNaturalNumber0(xp) = all_36_1_51)
% 67.33/29.18  																																																																																																																																																																																																																													|
% 67.33/29.18  																																																																																																																																																																																																																														| From (555) and (1418) follows:
% 67.33/29.18  																																																																																																																																																																																																																														| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.33/29.18  																																																																																																																																																																																																																														|
% 67.33/29.18  																																																																																																																																																																																																																														| Using (12) and (1198) yields:
% 67.33/29.18  																																																																																																																																																																																																																														| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																														|
% 67.33/29.18  																																																																																																																																																																																																																														|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																													|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																													| (1421) aNaturalNumber0(xp) = all_36_1_51
% 67.33/29.18  																																																																																																																																																																																																																													| (555) all_36_1_51 = 0
% 67.33/29.18  																																																																																																																																																																																																																													|
% 67.33/29.18  																																																																																																																																																																																																																														| From (555) and (1421) follows:
% 67.33/29.18  																																																																																																																																																																																																																														| (12) aNaturalNumber0(xp) = 0
% 67.33/29.18  																																																																																																																																																																																																																														|
% 67.33/29.18  																																																																																																																																																																																																																														+-Applying beta-rule and splitting (268), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																														|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																														| (1286)  ~ (aNaturalNumber0(xr) = all_26_2_37)
% 67.33/29.18  																																																																																																																																																																																																																														|
% 67.33/29.18  																																																																																																																																																																																																																															| From (572) and (1286) follows:
% 67.33/29.18  																																																																																																																																																																																																																															| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 67.33/29.18  																																																																																																																																																																																																																															|
% 67.33/29.18  																																																																																																																																																																																																																															| Using (10) and (1287) yields:
% 67.33/29.18  																																																																																																																																																																																																																															| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																															|
% 67.33/29.18  																																																																																																																																																																																																																															|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																														|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																														| (1289) aNaturalNumber0(xr) = all_26_2_37
% 67.33/29.18  																																																																																																																																																																																																																														| (2247) all_36_3_53 = all_26_2_37
% 67.33/29.18  																																																																																																																																																																																																																														|
% 67.33/29.18  																																																																																																																																																																																																																															| Combining equations (480,2247) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																															| (572) all_26_2_37 = 0
% 67.33/29.18  																																																																																																																																																																																																																															|
% 67.33/29.18  																																																																																																																																																																																																																															| Combining equations (572,2247) yields a new equation:
% 67.33/29.18  																																																																																																																																																																																																																															| (480) all_36_3_53 = 0
% 67.33/29.18  																																																																																																																																																																																																																															|
% 67.33/29.18  																																																																																																																																																																																																																															| From (572) and (1289) follows:
% 67.33/29.18  																																																																																																																																																																																																																															| (10) aNaturalNumber0(xr) = 0
% 67.33/29.18  																																																																																																																																																																																																																															|
% 67.33/29.18  																																																																																																																																																																																																																															+-Applying beta-rule and splitting (409), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																															|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																															| (2251)  ~ (aNaturalNumber0(sz10) = all_28_2_40)
% 67.33/29.18  																																																																																																																																																																																																																															|
% 67.33/29.18  																																																																																																																																																																																																																																| From (514) and (2251) follows:
% 67.33/29.18  																																																																																																																																																																																																																																| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 67.33/29.18  																																																																																																																																																																																																																																|
% 67.33/29.18  																																																																																																																																																																																																																																| Using (16) and (1252) yields:
% 67.33/29.18  																																																																																																																																																																																																																																| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																																|
% 67.33/29.18  																																																																																																																																																																																																																																|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																															|-Branch two:
% 67.33/29.18  																																																																																																																																																																																																																															| (2254) aNaturalNumber0(sz10) = all_28_2_40
% 67.33/29.18  																																																																																																																																																																																																																															| (514) all_28_2_40 = 0
% 67.33/29.18  																																																																																																																																																																																																																															|
% 67.33/29.18  																																																																																																																																																																																																																																| From (514) and (2254) follows:
% 67.33/29.18  																																																																																																																																																																																																																																| (16) aNaturalNumber0(sz10) = 0
% 67.33/29.18  																																																																																																																																																																																																																																|
% 67.33/29.18  																																																																																																																																																																																																																																+-Applying beta-rule and splitting (439), into two cases.
% 67.33/29.18  																																																																																																																																																																																																																																|-Branch one:
% 67.33/29.18  																																																																																																																																																																																																																																| (1354)  ~ (aNaturalNumber0(xn) = all_26_0_35)
% 67.33/29.18  																																																																																																																																																																																																																																|
% 67.33/29.18  																																																																																																																																																																																																																																	| From (594) and (1354) follows:
% 67.33/29.18  																																																																																																																																																																																																																																	| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.18  																																																																																																																																																																																																																																	|
% 67.33/29.18  																																																																																																																																																																																																																																	| Using (53) and (1144) yields:
% 67.33/29.18  																																																																																																																																																																																																																																	| (615) $false
% 67.33/29.18  																																																																																																																																																																																																																																	|
% 67.33/29.18  																																																																																																																																																																																																																																	|-The branch is then unsatisfiable
% 67.33/29.18  																																																																																																																																																																																																																																|-Branch two:
% 67.33/29.19  																																																																																																																																																																																																																																| (1357) aNaturalNumber0(xn) = all_26_0_35
% 67.33/29.19  																																																																																																																																																																																																																																| (2261) all_26_0_35 = all_22_2_29
% 67.33/29.19  																																																																																																																																																																																																																																|
% 67.33/29.19  																																																																																																																																																																																																																																	| Combining equations (594,2261) yields a new equation:
% 67.33/29.19  																																																																																																																																																																																																																																	| (510) all_22_2_29 = 0
% 67.33/29.19  																																																																																																																																																																																																																																	|
% 67.33/29.19  																																																																																																																																																																																																																																	| Combining equations (510,2261) yields a new equation:
% 67.33/29.19  																																																																																																																																																																																																																																	| (594) all_26_0_35 = 0
% 67.33/29.19  																																																																																																																																																																																																																																	|
% 67.33/29.19  																																																																																																																																																																																																																																	| From (594) and (1357) follows:
% 67.33/29.19  																																																																																																																																																																																																																																	| (53) aNaturalNumber0(xn) = 0
% 67.33/29.19  																																																																																																																																																																																																																																	|
% 67.33/29.19  																																																																																																																																																																																																																																	+-Applying beta-rule and splitting (220), into two cases.
% 67.33/29.19  																																																																																																																																																																																																																																	|-Branch one:
% 67.33/29.19  																																																																																																																																																																																																																																	| (1442)  ~ (aNaturalNumber0(xr) = all_26_0_35)
% 67.33/29.19  																																																																																																																																																																																																																																	|
% 67.33/29.19  																																																																																																																																																																																																																																		| From (594) and (1442) follows:
% 67.33/29.19  																																																																																																																																																																																																																																		| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 67.33/29.19  																																																																																																																																																																																																																																		|
% 67.33/29.19  																																																																																																																																																																																																																																		| Using (10) and (1287) yields:
% 67.33/29.19  																																																																																																																																																																																																																																		| (615) $false
% 67.33/29.19  																																																																																																																																																																																																																																		|
% 67.33/29.19  																																																																																																																																																																																																																																		|-The branch is then unsatisfiable
% 67.33/29.19  																																																																																																																																																																																																																																	|-Branch two:
% 67.33/29.19  																																																																																																																																																																																																																																	| (1445) aNaturalNumber0(xr) = all_26_0_35
% 67.33/29.19  																																																																																																																																																																																																																																	| (594) all_26_0_35 = 0
% 67.33/29.19  																																																																																																																																																																																																																																	|
% 67.33/29.19  																																																																																																																																																																																																																																		| From (594) and (1445) follows:
% 67.33/29.19  																																																																																																																																																																																																																																		| (10) aNaturalNumber0(xr) = 0
% 67.33/29.19  																																																																																																																																																																																																																																		|
% 67.33/29.19  																																																																																																																																																																																																																																		+-Applying beta-rule and splitting (270), into two cases.
% 67.33/29.19  																																																																																																																																																																																																																																		|-Branch one:
% 67.33/29.19  																																																																																																																																																																																																																																		| (1508)  ~ (aNaturalNumber0(xr) = all_12_0_6)
% 67.33/29.19  																																																																																																																																																																																																																																		|
% 67.33/29.19  																																																																																																																																																																																																																																			| From (570) and (1508) follows:
% 67.33/29.19  																																																																																																																																																																																																																																			| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 67.33/29.19  																																																																																																																																																																																																																																			|
% 67.33/29.19  																																																																																																																																																																																																																																			| Using (10) and (1287) yields:
% 67.33/29.19  																																																																																																																																																																																																																																			| (615) $false
% 67.33/29.19  																																																																																																																																																																																																																																			|
% 67.33/29.19  																																																																																																																																																																																																																																			|-The branch is then unsatisfiable
% 67.33/29.19  																																																																																																																																																																																																																																		|-Branch two:
% 67.33/29.19  																																																																																																																																																																																																																																		| (1511) aNaturalNumber0(xr) = all_12_0_6
% 67.33/29.19  																																																																																																																																																																																																																																		| (2275) all_36_3_53 = all_12_0_6
% 67.33/29.19  																																																																																																																																																																																																																																		|
% 67.33/29.19  																																																																																																																																																																																																																																			| Combining equations (480,2275) yields a new equation:
% 67.33/29.19  																																																																																																																																																																																																																																			| (570) all_12_0_6 = 0
% 67.33/29.19  																																																																																																																																																																																																																																			|
% 67.33/29.19  																																																																																																																																																																																																																																			| Combining equations (570,2275) yields a new equation:
% 67.33/29.19  																																																																																																																																																																																																																																			| (480) all_36_3_53 = 0
% 67.33/29.19  																																																																																																																																																																																																																																			|
% 67.33/29.19  																																																																																																																																																																																																																																			| From (570) and (1511) follows:
% 67.33/29.19  																																																																																																																																																																																																																																			| (10) aNaturalNumber0(xr) = 0
% 67.33/29.19  																																																																																																																																																																																																																																			|
% 67.33/29.19  																																																																																																																																																																																																																																			+-Applying beta-rule and splitting (289), into two cases.
% 67.33/29.19  																																																																																																																																																																																																																																			|-Branch one:
% 67.33/29.19  																																																																																																																																																																																																																																			| (2279)  ~ (aNaturalNumber0(xk) = all_16_2_14)
% 67.33/29.19  																																																																																																																																																																																																																																			|
% 67.33/29.19  																																																																																																																																																																																																																																				| From (571) and (2279) follows:
% 67.33/29.19  																																																																																																																																																																																																																																				| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.33/29.19  																																																																																																																																																																																																																																				|
% 67.33/29.19  																																																																																																																																																																																																																																				| Using (972) and (974) yields:
% 67.33/29.19  																																																																																																																																																																																																																																				| (615) $false
% 67.33/29.19  																																																																																																																																																																																																																																				|
% 67.33/29.19  																																																																																																																																																																																																																																				|-The branch is then unsatisfiable
% 67.33/29.19  																																																																																																																																																																																																																																			|-Branch two:
% 67.33/29.19  																																																																																																																																																																																																																																			| (2282) aNaturalNumber0(xk) = all_16_2_14
% 67.33/29.19  																																																																																																																																																																																																																																			| (2283) all_36_2_52 = all_16_2_14
% 67.33/29.19  																																																																																																																																																																																																																																			|
% 67.33/29.19  																																																																																																																																																																																																																																				| Combining equations (979,2283) yields a new equation:
% 67.33/29.19  																																																																																																																																																																																																																																				| (571) all_16_2_14 = 0
% 67.33/29.19  																																																																																																																																																																																																																																				|
% 67.33/29.19  																																																																																																																																																																																																																																				| Combining equations (571,2283) yields a new equation:
% 67.33/29.19  																																																																																																																																																																																																																																				| (979) all_36_2_52 = 0
% 67.33/29.19  																																																																																																																																																																																																																																				|
% 67.33/29.19  																																																																																																																																																																																																																																				| From (571) and (2282) follows:
% 67.33/29.19  																																																																																																																																																																																																																																				| (972) aNaturalNumber0(xk) = 0
% 67.33/29.19  																																																																																																																																																																																																																																				|
% 67.33/29.19  																																																																																																																																																																																																																																				+-Applying beta-rule and splitting (395), into two cases.
% 67.33/29.19  																																																																																																																																																																																																																																				|-Branch one:
% 67.33/29.19  																																																																																																																																																																																																																																				| (2287)  ~ (aNaturalNumber0(sz10) = all_30_8_49)
% 67.33/29.19  																																																																																																																																																																																																																																				|
% 67.33/29.19  																																																																																																																																																																																																																																					| From (516) and (2287) follows:
% 67.33/29.19  																																																																																																																																																																																																																																					| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 67.33/29.19  																																																																																																																																																																																																																																					|
% 67.33/29.19  																																																																																																																																																																																																																																					| Using (16) and (1252) yields:
% 67.33/29.19  																																																																																																																																																																																																																																					| (615) $false
% 67.33/29.19  																																																																																																																																																																																																																																					|
% 67.33/29.19  																																																																																																																																																																																																																																					|-The branch is then unsatisfiable
% 67.33/29.19  																																																																																																																																																																																																																																				|-Branch two:
% 67.33/29.19  																																																																																																																																																																																																																																				| (2290) aNaturalNumber0(sz10) = all_30_8_49
% 67.33/29.19  																																																																																																																																																																																																																																				| (516) all_30_8_49 = 0
% 67.33/29.19  																																																																																																																																																																																																																																				|
% 67.33/29.19  																																																																																																																																																																																																																																					| From (516) and (2290) follows:
% 67.33/29.19  																																																																																																																																																																																																																																					| (16) aNaturalNumber0(sz10) = 0
% 67.33/29.19  																																																																																																																																																																																																																																					|
% 67.33/29.19  																																																																																																																																																																																																																																					+-Applying beta-rule and splitting (407), into two cases.
% 67.33/29.19  																																																																																																																																																																																																																																					|-Branch one:
% 67.33/29.19  																																																																																																																																																																																																																																					| (1294)  ~ (aNaturalNumber0(xn) = all_14_1_10)
% 67.33/29.19  																																																																																																																																																																																																																																					|
% 67.33/29.19  																																																																																																																																																																																																																																						| From (503) and (1294) follows:
% 67.33/29.19  																																																																																																																																																																																																																																						| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.19  																																																																																																																																																																																																																																						|
% 67.33/29.19  																																																																																																																																																																																																																																						| Using (53) and (1144) yields:
% 67.33/29.19  																																																																																																																																																																																																																																						| (615) $false
% 67.33/29.19  																																																																																																																																																																																																																																						|
% 67.33/29.19  																																																																																																																																																																																																																																						|-The branch is then unsatisfiable
% 67.33/29.19  																																																																																																																																																																																																																																					|-Branch two:
% 67.33/29.19  																																																																																																																																																																																																																																					| (1297) aNaturalNumber0(xn) = all_14_1_10
% 67.33/29.19  																																																																																																																																																																																																																																					| (2297) all_30_8_49 = all_14_1_10
% 67.33/29.19  																																																																																																																																																																																																																																					|
% 67.33/29.19  																																																																																																																																																																																																																																						| Combining equations (516,2297) yields a new equation:
% 67.33/29.19  																																																																																																																																																																																																																																						| (503) all_14_1_10 = 0
% 67.33/29.19  																																																																																																																																																																																																																																						|
% 67.33/29.19  																																																																																																																																																																																																																																						| From (503) and (1297) follows:
% 67.33/29.19  																																																																																																																																																																																																																																						| (53) aNaturalNumber0(xn) = 0
% 67.33/29.19  																																																																																																																																																																																																																																						|
% 67.33/29.19  																																																																																																																																																																																																																																						+-Applying beta-rule and splitting (294), into two cases.
% 67.33/29.19  																																																																																																																																																																																																																																						|-Branch one:
% 67.33/29.19  																																																																																																																																																																																																																																						| (1418)  ~ (aNaturalNumber0(xp) = all_36_1_51)
% 67.33/29.19  																																																																																																																																																																																																																																						|
% 67.33/29.19  																																																																																																																																																																																																																																							| From (555) and (1418) follows:
% 67.33/29.19  																																																																																																																																																																																																																																							| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.33/29.19  																																																																																																																																																																																																																																							|
% 67.33/29.19  																																																																																																																																																																																																																																							| Using (12) and (1198) yields:
% 67.33/29.19  																																																																																																																																																																																																																																							| (615) $false
% 67.33/29.19  																																																																																																																																																																																																																																							|
% 67.33/29.19  																																																																																																																																																																																																																																							|-The branch is then unsatisfiable
% 67.33/29.19  																																																																																																																																																																																																																																						|-Branch two:
% 67.33/29.19  																																																																																																																																																																																																																																						| (1421) aNaturalNumber0(xp) = all_36_1_51
% 67.33/29.19  																																																																																																																																																																																																																																						| (2304) all_36_1_51 = all_30_6_47
% 67.33/29.19  																																																																																																																																																																																																																																						|
% 67.33/29.19  																																																																																																																																																																																																																																							| Combining equations (555,2304) yields a new equation:
% 67.33/29.19  																																																																																																																																																																																																																																							| (1242) all_30_6_47 = 0
% 67.33/29.19  																																																																																																																																																																																																																																							|
% 67.33/29.19  																																																																																																																																																																																																																																							| Combining equations (1242,2304) yields a new equation:
% 67.33/29.19  																																																																																																																																																																																																																																							| (555) all_36_1_51 = 0
% 67.33/29.19  																																																																																																																																																																																																																																							|
% 67.33/29.19  																																																																																																																																																																																																																																							| From (555) and (1421) follows:
% 67.33/29.19  																																																																																																																																																																																																																																							| (12) aNaturalNumber0(xp) = 0
% 67.33/29.19  																																																																																																																																																																																																																																							|
% 67.33/29.19  																																																																																																																																																																																																																																							+-Applying beta-rule and splitting (353), into two cases.
% 67.33/29.19  																																																																																																																																																																																																																																							|-Branch one:
% 67.33/29.19  																																																																																																																																																																																																																																							| (1190)  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 67.33/29.19  																																																																																																																																																																																																																																							|
% 67.33/29.19  																																																																																																																																																																																																																																								| From (554) and (1190) follows:
% 67.33/29.19  																																																																																																																																																																																																																																								| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.33/29.19  																																																																																																																																																																																																																																								|
% 67.33/29.19  																																																																																																																																																																																																																																								| Using (36) and (1191) yields:
% 67.33/29.19  																																																																																																																																																																																																																																								| (615) $false
% 67.33/29.19  																																																																																																																																																																																																																																								|
% 67.33/29.19  																																																																																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.33/29.19  																																																																																																																																																																																																																																							|-Branch two:
% 67.33/29.19  																																																																																																																																																																																																																																							| (1193) aNaturalNumber0(xm) = all_22_0_27
% 67.33/29.19  																																																																																																																																																																																																																																							| (2312) all_24_3_33 = all_22_0_27
% 67.33/29.19  																																																																																																																																																																																																																																							|
% 67.33/29.19  																																																																																																																																																																																																																																								| Combining equations (483,2312) yields a new equation:
% 67.33/29.19  																																																																																																																																																																																																																																								| (554) all_22_0_27 = 0
% 67.33/29.19  																																																																																																																																																																																																																																								|
% 67.33/29.19  																																																																																																																																																																																																																																								| From (554) and (1193) follows:
% 67.33/29.19  																																																																																																																																																																																																																																								| (36) aNaturalNumber0(xm) = 0
% 67.33/29.19  																																																																																																																																																																																																																																								|
% 67.33/29.19  																																																																																																																																																																																																																																								+-Applying beta-rule and splitting (264), into two cases.
% 67.33/29.19  																																																																																																																																																																																																																																								|-Branch one:
% 67.33/29.19  																																																																																																																																																																																																																																								| (1728)  ~ (aNaturalNumber0(xn) = all_36_3_53)
% 67.33/29.19  																																																																																																																																																																																																																																								|
% 67.33/29.19  																																																																																																																																																																																																																																									| From (480) and (1728) follows:
% 67.33/29.19  																																																																																																																																																																																																																																									| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.19  																																																																																																																																																																																																																																									|
% 67.33/29.19  																																																																																																																																																																																																																																									| Using (53) and (1144) yields:
% 67.33/29.19  																																																																																																																																																																																																																																									| (615) $false
% 67.33/29.19  																																																																																																																																																																																																																																									|
% 67.33/29.19  																																																																																																																																																																																																																																									|-The branch is then unsatisfiable
% 67.33/29.19  																																																																																																																																																																																																																																								|-Branch two:
% 67.33/29.19  																																																																																																																																																																																																																																								| (1731) aNaturalNumber0(xn) = all_36_3_53
% 67.33/29.19  																																																																																																																																																																																																																																								| (480) all_36_3_53 = 0
% 67.33/29.19  																																																																																																																																																																																																																																								|
% 67.33/29.19  																																																																																																																																																																																																																																									| From (480) and (1731) follows:
% 67.33/29.19  																																																																																																																																																																																																																																									| (53) aNaturalNumber0(xn) = 0
% 67.33/29.19  																																																																																																																																																																																																																																									|
% 67.33/29.19  																																																																																																																																																																																																																																									+-Applying beta-rule and splitting (403), into two cases.
% 67.33/29.19  																																																																																																																																																																																																																																									|-Branch one:
% 67.33/29.19  																																																																																																																																																																																																																																									| (1166)  ~ (aNaturalNumber0(xn) = all_30_7_48)
% 67.33/29.19  																																																																																																																																																																																																																																									|
% 67.33/29.19  																																																																																																																																																																																																																																										| From (331) and (1166) follows:
% 67.33/29.19  																																																																																																																																																																																																																																										| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.33/29.19  																																																																																																																																																																																																																																										|
% 67.33/29.19  																																																																																																																																																																																																																																										| Using (53) and (1144) yields:
% 67.33/29.19  																																																																																																																																																																																																																																										| (615) $false
% 67.33/29.19  																																																																																																																																																																																																																																										|
% 67.33/29.19  																																																																																																																																																																																																																																										|-The branch is then unsatisfiable
% 67.33/29.19  																																																																																																																																																																																																																																									|-Branch two:
% 67.54/29.19  																																																																																																																																																																																																																																									| (1169) aNaturalNumber0(xn) = all_30_7_48
% 67.54/29.19  																																																																																																																																																																																																																																									| (2325) all_30_7_48 = all_30_8_49
% 67.54/29.19  																																																																																																																																																																																																																																									|
% 67.54/29.19  																																																																																																																																																																																																																																										| Combining equations (331,2325) yields a new equation:
% 67.54/29.19  																																																																																																																																																																																																																																										| (516) all_30_8_49 = 0
% 67.54/29.19  																																																																																																																																																																																																																																										|
% 67.54/29.19  																																																																																																																																																																																																																																										| Combining equations (516,2325) yields a new equation:
% 67.54/29.19  																																																																																																																																																																																																																																										| (331) all_30_7_48 = 0
% 67.54/29.19  																																																																																																																																																																																																																																										|
% 67.54/29.19  																																																																																																																																																																																																																																										| From (331) and (1169) follows:
% 67.54/29.19  																																																																																																																																																																																																																																										| (53) aNaturalNumber0(xn) = 0
% 67.54/29.19  																																																																																																																																																																																																																																										|
% 67.54/29.19  																																																																																																																																																																																																																																										+-Applying beta-rule and splitting (299), into two cases.
% 67.54/29.19  																																																																																																																																																																																																																																										|-Branch one:
% 67.54/29.19  																																																																																																																																																																																																																																										| (2054)  ~ (aNaturalNumber0(xp) = all_12_0_6)
% 67.54/29.19  																																																																																																																																																																																																																																										|
% 67.54/29.19  																																																																																																																																																																																																																																											| From (570) and (2054) follows:
% 67.54/29.19  																																																																																																																																																																																																																																											| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.19  																																																																																																																																																																																																																																											|
% 67.54/29.19  																																																																																																																																																																																																																																											| Using (12) and (1198) yields:
% 67.54/29.19  																																																																																																																																																																																																																																											| (615) $false
% 67.54/29.19  																																																																																																																																																																																																																																											|
% 67.54/29.19  																																																																																																																																																																																																																																											|-The branch is then unsatisfiable
% 67.54/29.19  																																																																																																																																																																																																																																										|-Branch two:
% 67.54/29.19  																																																																																																																																																																																																																																										| (2057) aNaturalNumber0(xp) = all_12_0_6
% 67.54/29.19  																																																																																																																																																																																																																																										| (2333) all_30_6_47 = all_12_0_6
% 67.54/29.19  																																																																																																																																																																																																																																										|
% 67.54/29.19  																																																																																																																																																																																																																																											| Combining equations (1242,2333) yields a new equation:
% 67.54/29.19  																																																																																																																																																																																																																																											| (570) all_12_0_6 = 0
% 67.54/29.19  																																																																																																																																																																																																																																											|
% 67.54/29.19  																																																																																																																																																																																																																																											| From (570) and (2057) follows:
% 67.54/29.19  																																																																																																																																																																																																																																											| (12) aNaturalNumber0(xp) = 0
% 67.54/29.19  																																																																																																																																																																																																																																											|
% 67.54/29.19  																																																																																																																																																																																																																																											+-Applying beta-rule and splitting (372), into two cases.
% 67.54/29.19  																																																																																																																																																																																																																																											|-Branch one:
% 67.54/29.19  																																																																																																																																																																																																																																											| (1338)  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 67.54/29.19  																																																																																																																																																																																																																																											|
% 67.54/29.19  																																																																																																																																																																																																																																												| From (979) and (1338) follows:
% 67.54/29.19  																																																																																																																																																																																																																																												| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.19  																																																																																																																																																																																																																																												|
% 67.54/29.19  																																																																																																																																																																																																																																												| Using (36) and (1191) yields:
% 67.54/29.19  																																																																																																																																																																																																																																												| (615) $false
% 67.54/29.19  																																																																																																																																																																																																																																												|
% 67.54/29.19  																																																																																																																																																																																																																																												|-The branch is then unsatisfiable
% 67.54/29.19  																																																																																																																																																																																																																																											|-Branch two:
% 67.54/29.19  																																																																																																																																																																																																																																											| (1341) aNaturalNumber0(xm) = all_36_2_52
% 67.54/29.19  																																																																																																																																																																																																																																											| (2340) all_36_2_52 = all_22_1_28
% 67.54/29.19  																																																																																																																																																																																																																																											|
% 67.54/29.19  																																																																																																																																																																																																																																												| Combining equations (979,2340) yields a new equation:
% 67.54/29.19  																																																																																																																																																																																																																																												| (499) all_22_1_28 = 0
% 67.54/29.19  																																																																																																																																																																																																																																												|
% 67.54/29.19  																																																																																																																																																																																																																																												| Combining equations (499,2340) yields a new equation:
% 67.54/29.19  																																																																																																																																																																																																																																												| (979) all_36_2_52 = 0
% 67.54/29.19  																																																																																																																																																																																																																																												|
% 67.54/29.19  																																																																																																																																																																																																																																												| From (979) and (1341) follows:
% 67.54/29.19  																																																																																																																																																																																																																																												| (36) aNaturalNumber0(xm) = 0
% 67.54/29.19  																																																																																																																																																																																																																																												|
% 67.54/29.19  																																																																																																																																																																																																																																												+-Applying beta-rule and splitting (387), into two cases.
% 67.54/29.19  																																																																																																																																																																																																																																												|-Branch one:
% 67.54/29.19  																																																																																																																																																																																																																																												| (1516)  ~ (aNaturalNumber0(xm) = all_36_1_51)
% 67.54/29.19  																																																																																																																																																																																																																																												|
% 67.54/29.19  																																																																																																																																																																																																																																													| From (555) and (1516) follows:
% 67.54/29.19  																																																																																																																																																																																																																																													| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.19  																																																																																																																																																																																																																																													|
% 67.54/29.19  																																																																																																																																																																																																																																													| Using (36) and (1191) yields:
% 67.54/29.19  																																																																																																																																																																																																																																													| (615) $false
% 67.54/29.19  																																																																																																																																																																																																																																													|
% 67.54/29.19  																																																																																																																																																																																																																																													|-The branch is then unsatisfiable
% 67.54/29.19  																																																																																																																																																																																																																																												|-Branch two:
% 67.54/29.19  																																																																																																																																																																																																																																												| (1519) aNaturalNumber0(xm) = all_36_1_51
% 67.54/29.19  																																																																																																																																																																																																																																												| (2348) all_36_1_51 = all_12_1_7
% 67.54/29.19  																																																																																																																																																																																																																																												|
% 67.54/29.19  																																																																																																																																																																																																																																													| Combining equations (555,2348) yields a new equation:
% 67.54/29.19  																																																																																																																																																																																																																																													| (507) all_12_1_7 = 0
% 67.54/29.19  																																																																																																																																																																																																																																													|
% 67.54/29.19  																																																																																																																																																																																																																																													| Combining equations (507,2348) yields a new equation:
% 67.54/29.19  																																																																																																																																																																																																																																													| (555) all_36_1_51 = 0
% 67.54/29.19  																																																																																																																																																																																																																																													|
% 67.54/29.19  																																																																																																																																																																																																																																													| From (555) and (1519) follows:
% 67.54/29.19  																																																																																																																																																																																																																																													| (36) aNaturalNumber0(xm) = 0
% 67.54/29.19  																																																																																																																																																																																																																																													|
% 67.54/29.19  																																																																																																																																																																																																																																													+-Applying beta-rule and splitting (388), into two cases.
% 67.54/29.19  																																																																																																																																																																																																																																													|-Branch one:
% 67.54/29.19  																																																																																																																																																																																																																																													| (1190)  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 67.54/29.19  																																																																																																																																																																																																																																													|
% 67.54/29.19  																																																																																																																																																																																																																																														| From (554) and (1190) follows:
% 67.54/29.19  																																																																																																																																																																																																																																														| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.19  																																																																																																																																																																																																																																														|
% 67.54/29.19  																																																																																																																																																																																																																																														| Using (36) and (1191) yields:
% 67.54/29.19  																																																																																																																																																																																																																																														| (615) $false
% 67.54/29.19  																																																																																																																																																																																																																																														|
% 67.54/29.19  																																																																																																																																																																																																																																														|-The branch is then unsatisfiable
% 67.54/29.19  																																																																																																																																																																																																																																													|-Branch two:
% 67.54/29.19  																																																																																																																																																																																																																																													| (1193) aNaturalNumber0(xm) = all_22_0_27
% 67.54/29.19  																																																																																																																																																																																																																																													| (2356) all_22_0_27 = all_12_1_7
% 67.54/29.19  																																																																																																																																																																																																																																													|
% 67.54/29.19  																																																																																																																																																																																																																																														| Combining equations (554,2356) yields a new equation:
% 67.54/29.19  																																																																																																																																																																																																																																														| (507) all_12_1_7 = 0
% 67.54/29.19  																																																																																																																																																																																																																																														|
% 67.54/29.19  																																																																																																																																																																																																																																														| Combining equations (507,2356) yields a new equation:
% 67.54/29.19  																																																																																																																																																																																																																																														| (554) all_22_0_27 = 0
% 67.54/29.19  																																																																																																																																																																																																																																														|
% 67.54/29.19  																																																																																																																																																																																																																																														| From (554) and (1193) follows:
% 67.54/29.19  																																																																																																																																																																																																																																														| (36) aNaturalNumber0(xm) = 0
% 67.54/29.19  																																																																																																																																																																																																																																														|
% 67.54/29.19  																																																																																																																																																																																																																																														+-Applying beta-rule and splitting (256), into two cases.
% 67.54/29.19  																																																																																																																																																																																																																																														|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																														| (1174)  ~ (aNaturalNumber0(xn) = all_41_2_56)
% 67.54/29.20  																																																																																																																																																																																																																																														|
% 67.54/29.20  																																																																																																																																																																																																																																															| From (253) and (1174) follows:
% 67.54/29.20  																																																																																																																																																																																																																																															| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																															|
% 67.54/29.20  																																																																																																																																																																																																																																															| Using (53) and (1144) yields:
% 67.54/29.20  																																																																																																																																																																																																																																															| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																															|
% 67.54/29.20  																																																																																																																																																																																																																																															|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																														|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																														| (1177) aNaturalNumber0(xn) = all_41_2_56
% 67.54/29.20  																																																																																																																																																																																																																																														| (253) all_41_2_56 = 0
% 67.54/29.20  																																																																																																																																																																																																																																														|
% 67.54/29.20  																																																																																																																																																																																																																																															| From (253) and (1177) follows:
% 67.54/29.20  																																																																																																																																																																																																																																															| (53) aNaturalNumber0(xn) = 0
% 67.54/29.20  																																																																																																																																																																																																																																															|
% 67.54/29.20  																																																																																																																																																																																																																																															+-Applying beta-rule and splitting (429), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																															|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																															| (1673)  ~ (aNaturalNumber0(xn) = all_41_1_55)
% 67.54/29.20  																																																																																																																																																																																																																																															|
% 67.54/29.20  																																																																																																																																																																																																																																																| From (980) and (1673) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																|
% 67.54/29.20  																																																																																																																																																																																																																																																| Using (53) and (1144) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																|
% 67.54/29.20  																																																																																																																																																																																																																																																|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																															|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																															| (1676) aNaturalNumber0(xn) = all_41_1_55
% 67.54/29.20  																																																																																																																																																																																																																																															| (2370) all_41_1_55 = all_24_4_34
% 67.54/29.20  																																																																																																																																																																																																																																															|
% 67.54/29.20  																																																																																																																																																																																																																																																| Combining equations (980,2370) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																| (511) all_24_4_34 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																|
% 67.54/29.20  																																																																																																																																																																																																																																																| Combining equations (511,2370) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																| (980) all_41_1_55 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																|
% 67.54/29.20  																																																																																																																																																																																																																																																| From (980) and (1676) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																| (53) aNaturalNumber0(xn) = 0
% 67.54/29.20  																																																																																																																																																																																																																																																|
% 67.54/29.20  																																																																																																																																																																																																																																																+-Applying beta-rule and splitting (422), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																																|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																																| (1182)  ~ (aNaturalNumber0(xn) = all_22_1_28)
% 67.54/29.20  																																																																																																																																																																																																																																																|
% 67.54/29.20  																																																																																																																																																																																																																																																	| From (499) and (1182) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																	| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																	|
% 67.54/29.20  																																																																																																																																																																																																																																																	| Using (53) and (1144) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																	| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																	|
% 67.54/29.20  																																																																																																																																																																																																																																																	|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																																|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																																| (1185) aNaturalNumber0(xn) = all_22_1_28
% 67.54/29.20  																																																																																																																																																																																																																																																| (2378) all_28_2_40 = all_22_1_28
% 67.54/29.20  																																																																																																																																																																																																																																																|
% 67.54/29.20  																																																																																																																																																																																																																																																	| Combining equations (514,2378) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																	| (499) all_22_1_28 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																	|
% 67.54/29.20  																																																																																																																																																																																																																																																	| Combining equations (499,2378) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																	| (514) all_28_2_40 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																	|
% 67.54/29.20  																																																																																																																																																																																																																																																	| From (499) and (1185) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																	| (53) aNaturalNumber0(xn) = 0
% 67.54/29.20  																																																																																																																																																																																																																																																	|
% 67.54/29.20  																																																																																																																																																																																																																																																	+-Applying beta-rule and splitting (354), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																																	|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																																	| (1871)  ~ (aNaturalNumber0(xm) = all_26_0_35)
% 67.54/29.20  																																																																																																																																																																																																																																																	|
% 67.54/29.20  																																																																																																																																																																																																																																																		| From (594) and (1871) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																		| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																		|
% 67.54/29.20  																																																																																																																																																																																																																																																		| Using (36) and (1191) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																		| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																		|
% 67.54/29.20  																																																																																																																																																																																																																																																		|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																																	|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																																	| (1874) aNaturalNumber0(xm) = all_26_0_35
% 67.54/29.20  																																																																																																																																																																																																																																																	| (2386) all_26_0_35 = all_24_3_33
% 67.54/29.20  																																																																																																																																																																																																																																																	|
% 67.54/29.20  																																																																																																																																																																																																																																																		| Combining equations (594,2386) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																		| (483) all_24_3_33 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																		|
% 67.54/29.20  																																																																																																																																																																																																																																																		| Combining equations (483,2386) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																		| (594) all_26_0_35 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																		|
% 67.54/29.20  																																																																																																																																																																																																																																																		| From (594) and (1874) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																		| (36) aNaturalNumber0(xm) = 0
% 67.54/29.20  																																																																																																																																																																																																																																																		|
% 67.54/29.20  																																																																																																																																																																																																																																																		+-Applying beta-rule and splitting (225), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																																		|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																																		| (2390)  ~ (aNaturalNumber0(all_0_4_4) = all_22_0_27)
% 67.54/29.20  																																																																																																																																																																																																																																																		|
% 67.54/29.20  																																																																																																																																																																																																																																																			| From (554) and (2390) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																			| (2391)  ~ (aNaturalNumber0(all_0_4_4) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																			|
% 67.54/29.20  																																																																																																																																																																																																																																																			| Using (595) and (2391) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																			| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																			|
% 67.54/29.20  																																																																																																																																																																																																																																																			|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																																		|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																																		| (2393) aNaturalNumber0(all_0_4_4) = all_22_0_27
% 67.54/29.20  																																																																																																																																																																																																																																																		| (2394) all_26_0_35 = all_22_0_27
% 67.54/29.20  																																																																																																																																																																																																																																																		|
% 67.54/29.20  																																																																																																																																																																																																																																																			| Combining equations (594,2394) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																			| (554) all_22_0_27 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																			|
% 67.54/29.20  																																																																																																																																																																																																																																																			| Combining equations (554,2394) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																			| (594) all_26_0_35 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																			|
% 67.54/29.20  																																																																																																																																																																																																																																																			| From (554) and (2393) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																			| (595) aNaturalNumber0(all_0_4_4) = 0
% 67.54/29.20  																																																																																																																																																																																																																																																			|
% 67.54/29.20  																																																																																																																																																																																																																																																			+-Applying beta-rule and splitting (366), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																																			|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																																			| (1871)  ~ (aNaturalNumber0(xm) = all_26_0_35)
% 67.54/29.20  																																																																																																																																																																																																																																																			|
% 67.54/29.20  																																																																																																																																																																																																																																																				| From (594) and (1871) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																				| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																				|
% 67.54/29.20  																																																																																																																																																																																																																																																				| Using (36) and (1191) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																				| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																				|
% 67.54/29.20  																																																																																																																																																																																																																																																				|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																																			|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																																			| (1874) aNaturalNumber0(xm) = all_26_0_35
% 67.54/29.20  																																																																																																																																																																																																																																																			| (2402) all_26_0_35 = all_22_1_28
% 67.54/29.20  																																																																																																																																																																																																																																																			|
% 67.54/29.20  																																																																																																																																																																																																																																																				| Combining equations (594,2402) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																				| (499) all_22_1_28 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																				|
% 67.54/29.20  																																																																																																																																																																																																																																																				| Combining equations (499,2402) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																				| (594) all_26_0_35 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																				|
% 67.54/29.20  																																																																																																																																																																																																																																																				| From (594) and (1874) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																				| (36) aNaturalNumber0(xm) = 0
% 67.54/29.20  																																																																																																																																																																																																																																																				|
% 67.54/29.20  																																																																																																																																																																																																																																																				+-Applying beta-rule and splitting (310), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																																				|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																																				| (1197)  ~ (aNaturalNumber0(xp) = all_41_2_56)
% 67.54/29.20  																																																																																																																																																																																																																																																				|
% 67.54/29.20  																																																																																																																																																																																																																																																					| From (253) and (1197) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																					| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																					|
% 67.54/29.20  																																																																																																																																																																																																																																																					| Using (12) and (1198) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																					| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																					|
% 67.54/29.20  																																																																																																																																																																																																																																																					|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																																				|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																																				| (1200) aNaturalNumber0(xp) = all_41_2_56
% 67.54/29.20  																																																																																																																																																																																																																																																				| (2410) all_41_2_56 = all_26_1_36
% 67.54/29.20  																																																																																																																																																																																																																																																				|
% 67.54/29.20  																																																																																																																																																																																																																																																					| Combining equations (253,2410) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																					| (303) all_26_1_36 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																					|
% 67.54/29.20  																																																																																																																																																																																																																																																					| Combining equations (303,2410) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																					| (253) all_41_2_56 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																					|
% 67.54/29.20  																																																																																																																																																																																																																																																					| From (253) and (1200) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																					| (12) aNaturalNumber0(xp) = 0
% 67.54/29.20  																																																																																																																																																																																																																																																					|
% 67.54/29.20  																																																																																																																																																																																																																																																					+-Applying beta-rule and splitting (229), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																																					|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																																					| (2414)  ~ (aNaturalNumber0(sz00) = all_26_2_37)
% 67.54/29.20  																																																																																																																																																																																																																																																					|
% 67.54/29.20  																																																																																																																																																																																																																																																						| From (572) and (2414) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																						| (1503)  ~ (aNaturalNumber0(sz00) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																						|
% 67.54/29.20  																																																																																																																																																																																																																																																						| Using (41) and (1503) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																						| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																						|
% 67.54/29.20  																																																																																																																																																																																																																																																						|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																																					|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																																					| (2417) aNaturalNumber0(sz00) = all_26_2_37
% 67.54/29.20  																																																																																																																																																																																																																																																					| (572) all_26_2_37 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																					|
% 67.54/29.20  																																																																																																																																																																																																																																																						| From (572) and (2417) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																						| (41) aNaturalNumber0(sz00) = 0
% 67.54/29.20  																																																																																																																																																																																																																																																						|
% 67.54/29.20  																																																																																																																																																																																																																																																						+-Applying beta-rule and splitting (280), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																																						|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																																						| (2279)  ~ (aNaturalNumber0(xk) = all_16_2_14)
% 67.54/29.20  																																																																																																																																																																																																																																																						|
% 67.54/29.20  																																																																																																																																																																																																																																																							| From (571) and (2279) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																							| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																							|
% 67.54/29.20  																																																																																																																																																																																																																																																							| Using (972) and (974) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																							| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																							|
% 67.54/29.20  																																																																																																																																																																																																																																																							|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																																						|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																																						| (2282) aNaturalNumber0(xk) = all_16_2_14
% 67.54/29.20  																																																																																																																																																																																																																																																						| (2424) all_41_1_55 = all_16_2_14
% 67.54/29.20  																																																																																																																																																																																																																																																						|
% 67.54/29.20  																																																																																																																																																																																																																																																							| Combining equations (980,2424) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																							| (571) all_16_2_14 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																							|
% 67.54/29.20  																																																																																																																																																																																																																																																							| Combining equations (571,2424) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																							| (980) all_41_1_55 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																							|
% 67.54/29.20  																																																																																																																																																																																																																																																							| From (571) and (2282) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																							| (972) aNaturalNumber0(xk) = 0
% 67.54/29.20  																																																																																																																																																																																																																																																							|
% 67.54/29.20  																																																																																																																																																																																																																																																							+-Applying beta-rule and splitting (443), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																																							|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																																							| (1728)  ~ (aNaturalNumber0(xn) = all_36_3_53)
% 67.54/29.20  																																																																																																																																																																																																																																																							|
% 67.54/29.20  																																																																																																																																																																																																																																																								| From (480) and (1728) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																								| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																								|
% 67.54/29.20  																																																																																																																																																																																																																																																								| Using (53) and (1144) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																								| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																								|
% 67.54/29.20  																																																																																																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																																							|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																																							| (1731) aNaturalNumber0(xn) = all_36_3_53
% 67.54/29.20  																																																																																																																																																																																																																																																							| (2432) all_36_3_53 = all_22_2_29
% 67.54/29.20  																																																																																																																																																																																																																																																							|
% 67.54/29.20  																																																																																																																																																																																																																																																								| Combining equations (480,2432) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																								| (510) all_22_2_29 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																								|
% 67.54/29.20  																																																																																																																																																																																																																																																								| Combining equations (510,2432) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																								| (480) all_36_3_53 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																								|
% 67.54/29.20  																																																																																																																																																																																																																																																								| From (480) and (1731) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																								| (53) aNaturalNumber0(xn) = 0
% 67.54/29.20  																																																																																																																																																																																																																																																								|
% 67.54/29.20  																																																																																																																																																																																																																																																								+-Applying beta-rule and splitting (278), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																																								|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																																								| (2436)  ~ (aNaturalNumber0(xk) = all_26_0_35)
% 67.54/29.20  																																																																																																																																																																																																																																																								|
% 67.54/29.20  																																																																																																																																																																																																																																																									| From (594) and (2436) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																									| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																									|
% 67.54/29.20  																																																																																																																																																																																																																																																									| Using (972) and (974) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																									| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																									|
% 67.54/29.20  																																																																																																																																																																																																																																																									|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																																								|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																																								| (2439) aNaturalNumber0(xk) = all_26_0_35
% 67.54/29.20  																																																																																																																																																																																																																																																								| (2440) all_41_1_55 = all_26_0_35
% 67.54/29.20  																																																																																																																																																																																																																																																								|
% 67.54/29.20  																																																																																																																																																																																																																																																									| Combining equations (980,2440) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																									| (594) all_26_0_35 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																									|
% 67.54/29.20  																																																																																																																																																																																																																																																									| Combining equations (594,2440) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																									| (980) all_41_1_55 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																									|
% 67.54/29.20  																																																																																																																																																																																																																																																									| From (594) and (2439) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																									| (972) aNaturalNumber0(xk) = 0
% 67.54/29.20  																																																																																																																																																																																																																																																									|
% 67.54/29.20  																																																																																																																																																																																																																																																									+-Applying beta-rule and splitting (215), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																																									|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																																									| (1190)  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 67.54/29.20  																																																																																																																																																																																																																																																									|
% 67.54/29.20  																																																																																																																																																																																																																																																										| From (554) and (1190) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																										| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																										|
% 67.54/29.20  																																																																																																																																																																																																																																																										| Using (36) and (1191) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																										| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																										|
% 67.54/29.20  																																																																																																																																																																																																																																																										|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																																									|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																																									| (1193) aNaturalNumber0(xm) = all_22_0_27
% 67.54/29.20  																																																																																																																																																																																																																																																									| (554) all_22_0_27 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																									|
% 67.54/29.20  																																																																																																																																																																																																																																																										| From (554) and (1193) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																										| (36) aNaturalNumber0(xm) = 0
% 67.54/29.20  																																																																																																																																																																																																																																																										|
% 67.54/29.20  																																																																																																																																																																																																																																																										+-Applying beta-rule and splitting (315), into two cases.
% 67.54/29.20  																																																																																																																																																																																																																																																										|-Branch one:
% 67.54/29.20  																																																																																																																																																																																																																																																										| (1554)  ~ (aNaturalNumber0(xp) = all_22_0_27)
% 67.54/29.20  																																																																																																																																																																																																																																																										|
% 67.54/29.20  																																																																																																																																																																																																																																																											| From (554) and (1554) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																											| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.20  																																																																																																																																																																																																																																																											|
% 67.54/29.20  																																																																																																																																																																																																																																																											| Using (12) and (1198) yields:
% 67.54/29.20  																																																																																																																																																																																																																																																											| (615) $false
% 67.54/29.20  																																																																																																																																																																																																																																																											|
% 67.54/29.20  																																																																																																																																																																																																																																																											|-The branch is then unsatisfiable
% 67.54/29.20  																																																																																																																																																																																																																																																										|-Branch two:
% 67.54/29.20  																																																																																																																																																																																																																																																										| (1557) aNaturalNumber0(xp) = all_22_0_27
% 67.54/29.20  																																																																																																																																																																																																																																																										| (2454) all_24_2_32 = all_22_0_27
% 67.54/29.20  																																																																																																																																																																																																																																																										|
% 67.54/29.20  																																																																																																																																																																																																																																																											| Combining equations (493,2454) yields a new equation:
% 67.54/29.20  																																																																																																																																																																																																																																																											| (554) all_22_0_27 = 0
% 67.54/29.20  																																																																																																																																																																																																																																																											|
% 67.54/29.20  																																																																																																																																																																																																																																																											| From (554) and (1557) follows:
% 67.54/29.20  																																																																																																																																																																																																																																																											| (12) aNaturalNumber0(xp) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																											|
% 67.54/29.21  																																																																																																																																																																																																																																																											+-Applying beta-rule and splitting (360), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																											|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																											| (1338)  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 67.54/29.21  																																																																																																																																																																																																																																																											|
% 67.54/29.21  																																																																																																																																																																																																																																																												| From (979) and (1338) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																												| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																												|
% 67.54/29.21  																																																																																																																																																																																																																																																												| Using (36) and (1191) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																												| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																												|
% 67.54/29.21  																																																																																																																																																																																																																																																												|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																											|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																											| (1341) aNaturalNumber0(xm) = all_36_2_52
% 67.54/29.21  																																																																																																																																																																																																																																																											| (2461) all_36_2_52 = all_24_3_33
% 67.54/29.21  																																																																																																																																																																																																																																																											|
% 67.54/29.21  																																																																																																																																																																																																																																																												| Combining equations (979,2461) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																												| (483) all_24_3_33 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																												|
% 67.54/29.21  																																																																																																																																																																																																																																																												| Combining equations (483,2461) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																												| (979) all_36_2_52 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																												|
% 67.54/29.21  																																																																																																																																																																																																																																																												| From (979) and (1341) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																												| (36) aNaturalNumber0(xm) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																												|
% 67.54/29.21  																																																																																																																																																																																																																																																												+-Applying beta-rule and splitting (276), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																												|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																												| (2465)  ~ (aNaturalNumber0(xk) = all_36_1_51)
% 67.54/29.21  																																																																																																																																																																																																																																																												|
% 67.54/29.21  																																																																																																																																																																																																																																																													| From (555) and (2465) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																													| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																													|
% 67.54/29.21  																																																																																																																																																																																																																																																													| Using (972) and (974) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																													| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																													|
% 67.54/29.21  																																																																																																																																																																																																																																																													|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																												|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																												| (2468) aNaturalNumber0(xk) = all_36_1_51
% 67.54/29.21  																																																																																																																																																																																																																																																												| (2469) all_41_1_55 = all_36_1_51
% 67.54/29.21  																																																																																																																																																																																																																																																												|
% 67.54/29.21  																																																																																																																																																																																																																																																													| Combining equations (980,2469) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																													| (555) all_36_1_51 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																													|
% 67.54/29.21  																																																																																																																																																																																																																																																													| Combining equations (555,2469) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																													| (980) all_41_1_55 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																													|
% 67.54/29.21  																																																																																																																																																																																																																																																													| From (555) and (2468) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																													| (972) aNaturalNumber0(xk) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																													|
% 67.54/29.21  																																																																																																																																																																																																																																																													+-Applying beta-rule and splitting (300), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																													|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																													| (1197)  ~ (aNaturalNumber0(xp) = all_41_2_56)
% 67.54/29.21  																																																																																																																																																																																																																																																													|
% 67.54/29.21  																																																																																																																																																																																																																																																														| From (253) and (1197) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																														| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																														|
% 67.54/29.21  																																																																																																																																																																																																																																																														| Using (12) and (1198) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																														| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																														|
% 67.54/29.21  																																																																																																																																																																																																																																																														|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																													|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																													| (1200) aNaturalNumber0(xp) = all_41_2_56
% 67.54/29.21  																																																																																																																																																																																																																																																													| (2477) all_41_2_56 = all_30_6_47
% 67.54/29.21  																																																																																																																																																																																																																																																													|
% 67.54/29.21  																																																																																																																																																																																																																																																														| Combining equations (253,2477) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																														| (1242) all_30_6_47 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																														|
% 67.54/29.21  																																																																																																																																																																																																																																																														| Combining equations (1242,2477) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																														| (253) all_41_2_56 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																														|
% 67.54/29.21  																																																																																																																																																																																																																																																														| From (253) and (1200) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																														| (12) aNaturalNumber0(xp) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																														|
% 67.54/29.21  																																																																																																																																																																																																																																																														+-Applying beta-rule and splitting (281), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																														|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																														| (2012)  ~ (aNaturalNumber0(xk) = all_41_2_56)
% 67.54/29.21  																																																																																																																																																																																																																																																														|
% 67.54/29.21  																																																																																																																																																																																																																																																															| From (253) and (2012) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																															| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																															|
% 67.54/29.21  																																																																																																																																																																																																																																																															| Using (972) and (974) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																															| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																															|
% 67.54/29.21  																																																																																																																																																																																																																																																															|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																														|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																														| (2015) aNaturalNumber0(xk) = all_41_2_56
% 67.54/29.21  																																																																																																																																																																																																																																																														| (2485) all_41_1_55 = all_41_2_56
% 67.54/29.21  																																																																																																																																																																																																																																																														|
% 67.54/29.21  																																																																																																																																																																																																																																																															| Combining equations (980,2485) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																															| (253) all_41_2_56 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																															|
% 67.54/29.21  																																																																																																																																																																																																																																																															| Combining equations (253,2485) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																															| (980) all_41_1_55 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																															|
% 67.54/29.21  																																																																																																																																																																																																																																																															| From (253) and (2015) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																															| (972) aNaturalNumber0(xk) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																															|
% 67.54/29.21  																																																																																																																																																																																																																																																															+-Applying beta-rule and splitting (247), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																															|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																															| (2489)  ~ (aNaturalNumber0(sz10) = all_12_0_6)
% 67.54/29.21  																																																																																																																																																																																																																																																															|
% 67.54/29.21  																																																																																																																																																																																																																																																																| From (570) and (2489) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																																|
% 67.54/29.21  																																																																																																																																																																																																																																																																| Using (16) and (1252) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																																| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																																|
% 67.54/29.21  																																																																																																																																																																																																																																																																|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																															|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																															| (2492) aNaturalNumber0(sz10) = all_12_0_6
% 67.54/29.21  																																																																																																																																																																																																																																																															| (570) all_12_0_6 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																															|
% 67.54/29.21  																																																																																																																																																																																																																																																																| From (570) and (2492) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																| (16) aNaturalNumber0(sz10) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																|
% 67.54/29.21  																																																																																																																																																																																																																																																																+-Applying beta-rule and splitting (224), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																																|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																																| (2495)  ~ (aNaturalNumber0(all_0_4_4) = all_36_1_51)
% 67.54/29.21  																																																																																																																																																																																																																																																																|
% 67.54/29.21  																																																																																																																																																																																																																																																																	| From (555) and (2495) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																	| (2391)  ~ (aNaturalNumber0(all_0_4_4) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																																	|
% 67.54/29.21  																																																																																																																																																																																																																																																																	| Using (595) and (2391) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																																	| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																																	|
% 67.54/29.21  																																																																																																																																																																																																																																																																	|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																																|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																																| (2498) aNaturalNumber0(all_0_4_4) = all_36_1_51
% 67.54/29.21  																																																																																																																																																																																																																																																																| (2499) all_36_1_51 = all_26_0_35
% 67.54/29.21  																																																																																																																																																																																																																																																																|
% 67.54/29.21  																																																																																																																																																																																																																																																																	| Combining equations (555,2499) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																																	| (594) all_26_0_35 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																	|
% 67.54/29.21  																																																																																																																																																																																																																																																																	| Combining equations (594,2499) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																																	| (555) all_36_1_51 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																	|
% 67.54/29.21  																																																																																																																																																																																																																																																																	| From (555) and (2498) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																	| (595) aNaturalNumber0(all_0_4_4) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																	|
% 67.54/29.21  																																																																																																																																																																																																																																																																	+-Applying beta-rule and splitting (223), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																																	|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																																	| (2391)  ~ (aNaturalNumber0(all_0_4_4) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																																	|
% 67.54/29.21  																																																																																																																																																																																																																																																																		| Using (595) and (2391) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																																		| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																																		|
% 67.54/29.21  																																																																																																																																																																																																																																																																		|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																																	|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																																	| (595) aNaturalNumber0(all_0_4_4) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																	| (594) all_26_0_35 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																	|
% 67.54/29.21  																																																																																																																																																																																																																																																																		+-Applying beta-rule and splitting (453), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																																		|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																																		| (2507)  ~ (aNaturalNumber0(sz00) = all_14_2_11)
% 67.54/29.21  																																																																																																																																																																																																																																																																		|
% 67.54/29.21  																																																																																																																																																																																																																																																																			| From (451) and (2507) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																			| (1503)  ~ (aNaturalNumber0(sz00) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																																			|
% 67.54/29.21  																																																																																																																																																																																																																																																																			| Using (41) and (1503) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																																			| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																																			|
% 67.54/29.21  																																																																																																																																																																																																																																																																			|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																																		|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																																		| (2510) aNaturalNumber0(sz00) = all_14_2_11
% 67.54/29.21  																																																																																																																																																																																																																																																																		| (451) all_14_2_11 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																		|
% 67.54/29.21  																																																																																																																																																																																																																																																																			| From (451) and (2510) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																			| (41) aNaturalNumber0(sz00) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																			|
% 67.54/29.21  																																																																																																																																																																																																																																																																			+-Applying beta-rule and splitting (262), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																																			|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																																			| (1272)  ~ (aNaturalNumber0(xp) = all_36_3_53)
% 67.54/29.21  																																																																																																																																																																																																																																																																			|
% 67.54/29.21  																																																																																																																																																																																																																																																																				| From (480) and (1272) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																				| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																																				|
% 67.54/29.21  																																																																																																																																																																																																																																																																				| Using (12) and (1198) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																																				| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																																				|
% 67.54/29.21  																																																																																																																																																																																																																																																																				|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																																			|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																																			| (1275) aNaturalNumber0(xp) = all_36_3_53
% 67.54/29.21  																																																																																																																																																																																																																																																																			| (480) all_36_3_53 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																			|
% 67.54/29.21  																																																																																																																																																																																																																																																																				| From (480) and (1275) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																				| (12) aNaturalNumber0(xp) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																				|
% 67.54/29.21  																																																																																																																																																																																																																																																																				+-Applying beta-rule and splitting (381), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																																				|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																																				| (1314)  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 67.54/29.21  																																																																																																																																																																																																																																																																				|
% 67.54/29.21  																																																																																																																																																																																																																																																																					| From (253) and (1314) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																					| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																																					|
% 67.54/29.21  																																																																																																																																																																																																																																																																					| Using (36) and (1191) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																																					| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																																					|
% 67.54/29.21  																																																																																																																																																																																																																																																																					|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																																				|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																																				| (1317) aNaturalNumber0(xm) = all_41_2_56
% 67.54/29.21  																																																																																																																																																																																																																																																																				| (2523) all_41_2_56 = all_14_1_10
% 67.54/29.21  																																																																																																																																																																																																																																																																				|
% 67.54/29.21  																																																																																																																																																																																																																																																																					| Combining equations (253,2523) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																																					| (503) all_14_1_10 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																					|
% 67.54/29.21  																																																																																																																																																																																																																																																																					| Combining equations (503,2523) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																																					| (253) all_41_2_56 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																					|
% 67.54/29.21  																																																																																																																																																																																																																																																																					| From (253) and (1317) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																					| (36) aNaturalNumber0(xm) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																					|
% 67.54/29.21  																																																																																																																																																																																																																																																																					+-Applying beta-rule and splitting (428), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																																					|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																																					| (1646)  ~ (aNaturalNumber0(xn) = all_12_0_6)
% 67.54/29.21  																																																																																																																																																																																																																																																																					|
% 67.54/29.21  																																																																																																																																																																																																																																																																						| From (570) and (1646) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																						| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																																						|
% 67.54/29.21  																																																																																																																																																																																																																																																																						| Using (53) and (1144) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																																						| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																																						|
% 67.54/29.21  																																																																																																																																																																																																																																																																						|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																																					|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																																					| (1649) aNaturalNumber0(xn) = all_12_0_6
% 67.54/29.21  																																																																																																																																																																																																																																																																					| (2531) all_24_4_34 = all_12_0_6
% 67.54/29.21  																																																																																																																																																																																																																																																																					|
% 67.54/29.21  																																																																																																																																																																																																																																																																						| Combining equations (511,2531) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																																						| (570) all_12_0_6 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																						|
% 67.54/29.21  																																																																																																																																																																																																																																																																						| From (570) and (1649) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																						| (53) aNaturalNumber0(xn) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																						|
% 67.54/29.21  																																																																																																																																																																																																																																																																						+-Applying beta-rule and splitting (446), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																																						|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																																						| (1143)  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 67.54/29.21  																																																																																																																																																																																																																																																																						|
% 67.54/29.21  																																																																																																																																																																																																																																																																							| From (515) and (1143) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																							| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																																							|
% 67.54/29.21  																																																																																																																																																																																																																																																																							| Using (53) and (1144) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																																							| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																																							|
% 67.54/29.21  																																																																																																																																																																																																																																																																							|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																																						|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																																						| (1146) aNaturalNumber0(xn) = all_28_1_39
% 67.54/29.21  																																																																																																																																																																																																																																																																						| (2538) all_28_1_39 = all_22_2_29
% 67.54/29.21  																																																																																																																																																																																																																																																																						|
% 67.54/29.21  																																																																																																																																																																																																																																																																							| Combining equations (515,2538) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																																							| (510) all_22_2_29 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																							|
% 67.54/29.21  																																																																																																																																																																																																																																																																							| Combining equations (510,2538) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																																							| (515) all_28_1_39 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																							|
% 67.54/29.21  																																																																																																																																																																																																																																																																							| From (515) and (1146) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																							| (53) aNaturalNumber0(xn) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																							|
% 67.54/29.21  																																																																																																																																																																																																																																																																							+-Applying beta-rule and splitting (212), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																																							|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																																							| (2542)  ~ (aNaturalNumber0(sz10) = all_36_1_51)
% 67.54/29.21  																																																																																																																																																																																																																																																																							|
% 67.54/29.21  																																																																																																																																																																																																																																																																								| From (555) and (2542) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																								| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																																								|
% 67.54/29.21  																																																																																																																																																																																																																																																																								| Using (16) and (1252) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																																								| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																																								|
% 67.54/29.21  																																																																																																																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																																							|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																																							| (2545) aNaturalNumber0(sz10) = all_36_1_51
% 67.54/29.21  																																																																																																																																																																																																																																																																							| (555) all_36_1_51 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																							|
% 67.54/29.21  																																																																																																																																																																																																																																																																								| From (555) and (2545) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																								| (16) aNaturalNumber0(sz10) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																								|
% 67.54/29.21  																																																																																																																																																																																																																																																																								+-Applying beta-rule and splitting (425), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																																								|-Branch one:
% 67.54/29.21  																																																																																																																																																																																																																																																																								| (1370)  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 67.54/29.21  																																																																																																																																																																																																																																																																								|
% 67.54/29.21  																																																																																																																																																																																																																																																																									| From (555) and (1370) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																									| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.21  																																																																																																																																																																																																																																																																									|
% 67.54/29.21  																																																																																																																																																																																																																																																																									| Using (53) and (1144) yields:
% 67.54/29.21  																																																																																																																																																																																																																																																																									| (615) $false
% 67.54/29.21  																																																																																																																																																																																																																																																																									|
% 67.54/29.21  																																																																																																																																																																																																																																																																									|-The branch is then unsatisfiable
% 67.54/29.21  																																																																																																																																																																																																																																																																								|-Branch two:
% 67.54/29.21  																																																																																																																																																																																																																																																																								| (1373) aNaturalNumber0(xn) = all_36_1_51
% 67.54/29.21  																																																																																																																																																																																																																																																																								| (2552) all_36_1_51 = all_24_4_34
% 67.54/29.21  																																																																																																																																																																																																																																																																								|
% 67.54/29.21  																																																																																																																																																																																																																																																																									| Combining equations (555,2552) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																																									| (511) all_24_4_34 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																									|
% 67.54/29.21  																																																																																																																																																																																																																																																																									| Combining equations (511,2552) yields a new equation:
% 67.54/29.21  																																																																																																																																																																																																																																																																									| (555) all_36_1_51 = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																									|
% 67.54/29.21  																																																																																																																																																																																																																																																																									| From (555) and (1373) follows:
% 67.54/29.21  																																																																																																																																																																																																																																																																									| (53) aNaturalNumber0(xn) = 0
% 67.54/29.21  																																																																																																																																																																																																																																																																									|
% 67.54/29.21  																																																																																																																																																																																																																																																																									+-Applying beta-rule and splitting (230), into two cases.
% 67.54/29.21  																																																																																																																																																																																																																																																																									|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																									| (1258)  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																									|
% 67.54/29.22  																																																																																																																																																																																																																																																																										| Using (573) and (1258) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																										| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																										|
% 67.54/29.22  																																																																																																																																																																																																																																																																										|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																									|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																									| (573) aNaturalNumber0(all_0_5_5) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																									| (572) all_26_2_37 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																									|
% 67.54/29.22  																																																																																																																																																																																																																																																																										+-Applying beta-rule and splitting (221), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																										|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																										| (1213)  ~ (aNaturalNumber0(xp) = all_26_0_35)
% 67.54/29.22  																																																																																																																																																																																																																																																																										|
% 67.54/29.22  																																																																																																																																																																																																																																																																											| From (594) and (1213) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																											| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																											|
% 67.54/29.22  																																																																																																																																																																																																																																																																											| Using (12) and (1198) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																											| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																											|
% 67.54/29.22  																																																																																																																																																																																																																																																																											|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																										|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																										| (1216) aNaturalNumber0(xp) = all_26_0_35
% 67.54/29.22  																																																																																																																																																																																																																																																																										| (594) all_26_0_35 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																										|
% 67.54/29.22  																																																																																																																																																																																																																																																																											| From (594) and (1216) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																											| (12) aNaturalNumber0(xp) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																											|
% 67.54/29.22  																																																																																																																																																																																																																																																																											+-Applying beta-rule and splitting (389), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																											|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																											| (1871)  ~ (aNaturalNumber0(xm) = all_26_0_35)
% 67.54/29.22  																																																																																																																																																																																																																																																																											|
% 67.54/29.22  																																																																																																																																																																																																																																																																												| From (594) and (1871) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																												| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																												|
% 67.54/29.22  																																																																																																																																																																																																																																																																												| Using (36) and (1191) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																												| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																												|
% 67.54/29.22  																																																																																																																																																																																																																																																																												|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																											|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																											| (1874) aNaturalNumber0(xm) = all_26_0_35
% 67.54/29.22  																																																																																																																																																																																																																																																																											| (2570) all_26_0_35 = all_12_1_7
% 67.54/29.22  																																																																																																																																																																																																																																																																											|
% 67.54/29.22  																																																																																																																																																																																																																																																																												| Combining equations (594,2570) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																												| (507) all_12_1_7 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																												|
% 67.54/29.22  																																																																																																																																																																																																																																																																												| Combining equations (507,2570) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																												| (594) all_26_0_35 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																												|
% 67.54/29.22  																																																																																																																																																																																																																																																																												| From (594) and (1874) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																												| (36) aNaturalNumber0(xm) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																												|
% 67.54/29.22  																																																																																																																																																																																																																																																																												+-Applying beta-rule and splitting (365), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																												|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																												| (1190)  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 67.54/29.22  																																																																																																																																																																																																																																																																												|
% 67.54/29.22  																																																																																																																																																																																																																																																																													| From (554) and (1190) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																													| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																													|
% 67.54/29.22  																																																																																																																																																																																																																																																																													| Using (36) and (1191) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																													| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																													|
% 67.54/29.22  																																																																																																																																																																																																																																																																													|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																												|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																												| (1193) aNaturalNumber0(xm) = all_22_0_27
% 67.54/29.22  																																																																																																																																																																																																																																																																												| (2578) all_22_0_27 = all_22_1_28
% 67.54/29.22  																																																																																																																																																																																																																																																																												|
% 67.54/29.22  																																																																																																																																																																																																																																																																													| Combining equations (554,2578) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																													| (499) all_22_1_28 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																													|
% 67.54/29.22  																																																																																																																																																																																																																																																																													| Combining equations (499,2578) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																													| (554) all_22_0_27 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																													|
% 67.54/29.22  																																																																																																																																																																																																																																																																													| From (554) and (1193) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																													| (36) aNaturalNumber0(xm) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																													|
% 67.54/29.22  																																																																																																																																																																																																																																																																													+-Applying beta-rule and splitting (285), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																													|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																													| (1338)  ~ (aNaturalNumber0(xm) = all_36_2_52)
% 67.54/29.22  																																																																																																																																																																																																																																																																													|
% 67.54/29.22  																																																																																																																																																																																																																																																																														| From (979) and (1338) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																														| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																														|
% 67.54/29.22  																																																																																																																																																																																																																																																																														| Using (36) and (1191) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																														| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																														|
% 67.54/29.22  																																																																																																																																																																																																																																																																														|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																													|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																													| (1341) aNaturalNumber0(xm) = all_36_2_52
% 67.54/29.22  																																																																																																																																																																																																																																																																													| (979) all_36_2_52 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																													|
% 67.54/29.22  																																																																																																																																																																																																																																																																														| From (979) and (1341) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																														| (36) aNaturalNumber0(xm) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																														|
% 67.54/29.22  																																																																																																																																																																																																																																																																														+-Applying beta-rule and splitting (468), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																														|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																														| (1370)  ~ (aNaturalNumber0(xn) = all_36_1_51)
% 67.54/29.22  																																																																																																																																																																																																																																																																														|
% 67.54/29.22  																																																																																																																																																																																																																																																																															| From (555) and (1370) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																															| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																															|
% 67.54/29.22  																																																																																																																																																																																																																																																																															| Using (53) and (1144) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																															| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																															|
% 67.54/29.22  																																																																																																																																																																																																																																																																															|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																														|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																														| (1373) aNaturalNumber0(xn) = all_36_1_51
% 67.54/29.22  																																																																																																																																																																																																																																																																														| (2592) all_36_1_51 = all_12_2_8
% 67.54/29.22  																																																																																																																																																																																																																																																																														|
% 67.54/29.22  																																																																																																																																																																																																																																																																															| Combining equations (555,2592) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																															| (508) all_12_2_8 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																															|
% 67.54/29.22  																																																																																																																																																																																																																																																																															| Combining equations (508,2592) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																															| (555) all_36_1_51 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																															|
% 67.54/29.22  																																																																																																																																																																																																																																																																															| From (555) and (1373) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																															| (53) aNaturalNumber0(xn) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																															|
% 67.54/29.22  																																																																																																																																																																																																																																																																															+-Applying beta-rule and splitting (328), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																															|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																															| (1272)  ~ (aNaturalNumber0(xp) = all_36_3_53)
% 67.54/29.22  																																																																																																																																																																																																																																																																															|
% 67.54/29.22  																																																																																																																																																																																																																																																																																| From (480) and (1272) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																																|
% 67.54/29.22  																																																																																																																																																																																																																																																																																| Using (12) and (1198) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																																| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																																|
% 67.54/29.22  																																																																																																																																																																																																																																																																																|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																															|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																															| (1275) aNaturalNumber0(xp) = all_36_3_53
% 67.54/29.22  																																																																																																																																																																																																																																																																															| (2600) all_36_3_53 = all_16_1_13
% 67.54/29.22  																																																																																																																																																																																																																																																																															|
% 67.54/29.22  																																																																																																																																																																																																																																																																																| Combining equations (480,2600) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																																| (497) all_16_1_13 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																|
% 67.54/29.22  																																																																																																																																																																																																																																																																																| Combining equations (497,2600) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																																| (480) all_36_3_53 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																|
% 67.54/29.22  																																																																																																																																																																																																																																																																																| From (480) and (1275) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																| (12) aNaturalNumber0(xp) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																|
% 67.54/29.22  																																																																																																																																																																																																																																																																																+-Applying beta-rule and splitting (257), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																																|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																																| (1524)  ~ (aNaturalNumber0(xr) = all_36_1_51)
% 67.54/29.22  																																																																																																																																																																																																																																																																																|
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| From (555) and (1524) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																																	|
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| Using (10) and (1287) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																																	|
% 67.54/29.22  																																																																																																																																																																																																																																																																																	|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																																|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																																| (1527) aNaturalNumber0(xr) = all_36_1_51
% 67.54/29.22  																																																																																																																																																																																																																																																																																| (2608) all_41_2_56 = all_36_1_51
% 67.54/29.22  																																																																																																																																																																																																																																																																																|
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| Combining equations (253,2608) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| (555) all_36_1_51 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																	|
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| Combining equations (555,2608) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| (253) all_41_2_56 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																	|
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| From (555) and (1527) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| (10) aNaturalNumber0(xr) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																	|
% 67.54/29.22  																																																																																																																																																																																																																																																																																	+-Applying beta-rule and splitting (351), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																																	|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| (1568)  ~ (aNaturalNumber0(xn) = all_24_3_33)
% 67.54/29.22  																																																																																																																																																																																																																																																																																	|
% 67.54/29.22  																																																																																																																																																																																																																																																																																		| From (483) and (1568) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																		| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																																		|
% 67.54/29.22  																																																																																																																																																																																																																																																																																		| Using (53) and (1144) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																																		| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																																		|
% 67.54/29.22  																																																																																																																																																																																																																																																																																		|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																																	|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| (1571) aNaturalNumber0(xn) = all_24_3_33
% 67.54/29.22  																																																																																																																																																																																																																																																																																	| (483) all_24_3_33 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																	|
% 67.54/29.22  																																																																																																																																																																																																																																																																																		| From (483) and (1571) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																		| (53) aNaturalNumber0(xn) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																		|
% 67.54/29.22  																																																																																																																																																																																																																																																																																		+-Applying beta-rule and splitting (391), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																																		|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																																		| (1306)  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 67.54/29.22  																																																																																																																																																																																																																																																																																		|
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| From (570) and (1306) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																																			|
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| Using (36) and (1191) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																																			|
% 67.54/29.22  																																																																																																																																																																																																																																																																																			|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																																		|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																																		| (1309) aNaturalNumber0(xm) = all_12_0_6
% 67.54/29.22  																																																																																																																																																																																																																																																																																		| (2622) all_12_0_6 = all_12_1_7
% 67.54/29.22  																																																																																																																																																																																																																																																																																		|
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| Combining equations (2622,570) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| (506) all_12_1_7 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																			|
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| Simplifying 506 yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| (507) all_12_1_7 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																			|
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| From (570) and (1309) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| (36) aNaturalNumber0(xm) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																			|
% 67.54/29.22  																																																																																																																																																																																																																																																																																			+-Applying beta-rule and splitting (452), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																																			|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| (2626)  ~ (aNaturalNumber0(sz10) = all_14_2_11)
% 67.54/29.22  																																																																																																																																																																																																																																																																																			|
% 67.54/29.22  																																																																																																																																																																																																																																																																																				| From (451) and (2626) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																				| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																																				|
% 67.54/29.22  																																																																																																																																																																																																																																																																																				| Using (16) and (1252) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																																				| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																																				|
% 67.54/29.22  																																																																																																																																																																																																																																																																																				|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																																			|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| (2629) aNaturalNumber0(sz10) = all_14_2_11
% 67.54/29.22  																																																																																																																																																																																																																																																																																			| (451) all_14_2_11 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																			|
% 67.54/29.22  																																																																																																																																																																																																																																																																																				| From (451) and (2629) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																				| (16) aNaturalNumber0(sz10) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																				|
% 67.54/29.22  																																																																																																																																																																																																																																																																																				+-Applying beta-rule and splitting (426), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																																				|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																																				| (1151)  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 67.54/29.22  																																																																																																																																																																																																																																																																																				|
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| From (554) and (1151) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																																					|
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| Using (53) and (1144) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																																					|
% 67.54/29.22  																																																																																																																																																																																																																																																																																					|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																																				|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																																				| (1154) aNaturalNumber0(xn) = all_22_0_27
% 67.54/29.22  																																																																																																																																																																																																																																																																																				| (2636) all_24_4_34 = all_22_0_27
% 67.54/29.22  																																																																																																																																																																																																																																																																																				|
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| Combining equations (511,2636) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| (554) all_22_0_27 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																					|
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| Combining equations (554,2636) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| (511) all_24_4_34 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																					|
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| From (554) and (1154) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| (53) aNaturalNumber0(xn) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																					|
% 67.54/29.22  																																																																																																																																																																																																																																																																																					+-Applying beta-rule and splitting (234), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																																					|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| (1720)  ~ (aNaturalNumber0(xr) = all_16_2_14)
% 67.54/29.22  																																																																																																																																																																																																																																																																																					|
% 67.54/29.22  																																																																																																																																																																																																																																																																																						| From (571) and (1720) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																						| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																																						|
% 67.54/29.22  																																																																																																																																																																																																																																																																																						| Using (10) and (1287) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																																						| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																																						|
% 67.54/29.22  																																																																																																																																																																																																																																																																																						|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																																					|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| (1723) aNaturalNumber0(xr) = all_16_2_14
% 67.54/29.22  																																																																																																																																																																																																																																																																																					| (571) all_16_2_14 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																					|
% 67.54/29.22  																																																																																																																																																																																																																																																																																						| From (571) and (1723) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																						| (10) aNaturalNumber0(xr) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																						|
% 67.54/29.22  																																																																																																																																																																																																																																																																																						+-Applying beta-rule and splitting (359), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																																						|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																																						| (1851)  ~ (aNaturalNumber0(xm) = all_41_1_55)
% 67.54/29.22  																																																																																																																																																																																																																																																																																						|
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| From (980) and (1851) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																																							|
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| Using (36) and (1191) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																																							|
% 67.54/29.22  																																																																																																																																																																																																																																																																																							|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																																						|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																																						| (1854) aNaturalNumber0(xm) = all_41_1_55
% 67.54/29.22  																																																																																																																																																																																																																																																																																						| (2650) all_41_1_55 = all_24_3_33
% 67.54/29.22  																																																																																																																																																																																																																																																																																						|
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| Combining equations (980,2650) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| (483) all_24_3_33 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																							|
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| Combining equations (483,2650) yields a new equation:
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| (980) all_41_1_55 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																							|
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| From (980) and (1854) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| (36) aNaturalNumber0(xm) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																							|
% 67.54/29.22  																																																																																																																																																																																																																																																																																							+-Applying beta-rule and splitting (208), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																																							|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| (1524)  ~ (aNaturalNumber0(xr) = all_36_1_51)
% 67.54/29.22  																																																																																																																																																																																																																																																																																							|
% 67.54/29.22  																																																																																																																																																																																																																																																																																								| From (555) and (1524) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																								| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																																								|
% 67.54/29.22  																																																																																																																																																																																																																																																																																								| Using (10) and (1287) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																																								| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																																								|
% 67.54/29.22  																																																																																																																																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																																							|-Branch two:
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| (1527) aNaturalNumber0(xr) = all_36_1_51
% 67.54/29.22  																																																																																																																																																																																																																																																																																							| (555) all_36_1_51 = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																							|
% 67.54/29.22  																																																																																																																																																																																																																																																																																								| From (555) and (1527) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																								| (10) aNaturalNumber0(xr) = 0
% 67.54/29.22  																																																																																																																																																																																																																																																																																								|
% 67.54/29.22  																																																																																																																																																																																																																																																																																								+-Applying beta-rule and splitting (210), into two cases.
% 67.54/29.22  																																																																																																																																																																																																																																																																																								|-Branch one:
% 67.54/29.22  																																																																																																																																																																																																																																																																																								| (1516)  ~ (aNaturalNumber0(xm) = all_36_1_51)
% 67.54/29.22  																																																																																																																																																																																																																																																																																								|
% 67.54/29.22  																																																																																																																																																																																																																																																																																									| From (555) and (1516) follows:
% 67.54/29.22  																																																																																																																																																																																																																																																																																									| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.22  																																																																																																																																																																																																																																																																																									|
% 67.54/29.22  																																																																																																																																																																																																																																																																																									| Using (36) and (1191) yields:
% 67.54/29.22  																																																																																																																																																																																																																																																																																									| (615) $false
% 67.54/29.22  																																																																																																																																																																																																																																																																																									|
% 67.54/29.22  																																																																																																																																																																																																																																																																																									|-The branch is then unsatisfiable
% 67.54/29.22  																																																																																																																																																																																																																																																																																								|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																								| (1519) aNaturalNumber0(xm) = all_36_1_51
% 67.54/29.23  																																																																																																																																																																																																																																																																																								| (555) all_36_1_51 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																								|
% 67.54/29.23  																																																																																																																																																																																																																																																																																									| From (555) and (1519) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																									| (36) aNaturalNumber0(xm) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																									|
% 67.54/29.23  																																																																																																																																																																																																																																																																																									+-Applying beta-rule and splitting (378), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																									|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																									| (1386)  ~ (aNaturalNumber0(xm) = all_26_2_37)
% 67.54/29.23  																																																																																																																																																																																																																																																																																									|
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| From (572) and (1386) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																										|
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| Using (36) and (1191) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																										|
% 67.54/29.23  																																																																																																																																																																																																																																																																																										|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																									|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																									| (1389) aNaturalNumber0(xm) = all_26_2_37
% 67.54/29.23  																																																																																																																																																																																																																																																																																									| (2670) all_26_2_37 = all_14_1_10
% 67.54/29.23  																																																																																																																																																																																																																																																																																									|
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| Combining equations (572,2670) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| (503) all_14_1_10 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																										|
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| Combining equations (503,2670) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| (572) all_26_2_37 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																										|
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| From (572) and (1389) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| (36) aNaturalNumber0(xm) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																										|
% 67.54/29.23  																																																																																																																																																																																																																																																																																										+-Applying beta-rule and splitting (416), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																										|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| (1646)  ~ (aNaturalNumber0(xn) = all_12_0_6)
% 67.54/29.23  																																																																																																																																																																																																																																																																																										|
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| From (570) and (1646) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																											|
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| Using (53) and (1144) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																											|
% 67.54/29.23  																																																																																																																																																																																																																																																																																											|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																										|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| (1649) aNaturalNumber0(xn) = all_12_0_6
% 67.54/29.23  																																																																																																																																																																																																																																																																																										| (2678) all_28_2_40 = all_12_0_6
% 67.54/29.23  																																																																																																																																																																																																																																																																																										|
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| Combining equations (514,2678) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| (570) all_12_0_6 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																											|
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| Combining equations (570,2678) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| (514) all_28_2_40 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																											|
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| From (570) and (1649) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| (53) aNaturalNumber0(xn) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																											|
% 67.54/29.23  																																																																																																																																																																																																																																																																																											+-Applying beta-rule and splitting (462), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																											|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| (1568)  ~ (aNaturalNumber0(xn) = all_24_3_33)
% 67.54/29.23  																																																																																																																																																																																																																																																																																											|
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| From (483) and (1568) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																												|
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| Using (53) and (1144) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																												|
% 67.54/29.23  																																																																																																																																																																																																																																																																																												|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																											|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| (1571) aNaturalNumber0(xn) = all_24_3_33
% 67.54/29.23  																																																																																																																																																																																																																																																																																											| (2686) all_24_3_33 = all_14_2_11
% 67.54/29.23  																																																																																																																																																																																																																																																																																											|
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| Combining equations (483,2686) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| (451) all_14_2_11 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																												|
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| Combining equations (451,2686) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| (483) all_24_3_33 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																												|
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| From (483) and (1571) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| (53) aNaturalNumber0(xn) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																												|
% 67.54/29.23  																																																																																																																																																																																																																																																																																												+-Applying beta-rule and splitting (344), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																												|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| (2690)  ~ (aNaturalNumber0(sz10) = all_28_1_39)
% 67.54/29.23  																																																																																																																																																																																																																																																																																												|
% 67.54/29.23  																																																																																																																																																																																																																																																																																													| From (515) and (2690) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																													| (1252)  ~ (aNaturalNumber0(sz10) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																													|
% 67.54/29.23  																																																																																																																																																																																																																																																																																													| Using (16) and (1252) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																													| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																													|
% 67.54/29.23  																																																																																																																																																																																																																																																																																													|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																												|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| (2693) aNaturalNumber0(sz10) = all_28_1_39
% 67.54/29.23  																																																																																																																																																																																																																																																																																												| (515) all_28_1_39 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																												|
% 67.54/29.23  																																																																																																																																																																																																																																																																																													+-Applying beta-rule and splitting (282), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																													|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																													| (2695)  ~ (aNaturalNumber0(xk) = all_36_3_53)
% 67.54/29.23  																																																																																																																																																																																																																																																																																													|
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| From (480) and (2695) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																														|
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| Using (972) and (974) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																														|
% 67.54/29.23  																																																																																																																																																																																																																																																																																														|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																													|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																													| (2698) aNaturalNumber0(xk) = all_36_3_53
% 67.54/29.23  																																																																																																																																																																																																																																																																																													| (2699) all_41_1_55 = all_36_3_53
% 67.54/29.23  																																																																																																																																																																																																																																																																																													|
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| Combining equations (980,2699) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| (480) all_36_3_53 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																														|
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| Combining equations (480,2699) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| (980) all_41_1_55 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																														|
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| From (480) and (2698) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| (972) aNaturalNumber0(xk) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																														|
% 67.54/29.23  																																																																																																																																																																																																																																																																																														+-Applying beta-rule and splitting (465), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																														|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| (1159)  ~ (aNaturalNumber0(xn) = all_12_1_7)
% 67.54/29.23  																																																																																																																																																																																																																																																																																														|
% 67.54/29.23  																																																																																																																																																																																																																																																																																															| From (507) and (1159) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																															| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																															|
% 67.54/29.23  																																																																																																																																																																																																																																																																																															| Using (53) and (1144) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																															| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																															|
% 67.54/29.23  																																																																																																																																																																																																																																																																																															|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																														|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| (1162) aNaturalNumber0(xn) = all_12_1_7
% 67.54/29.23  																																																																																																																																																																																																																																																																																														| (2707) all_14_2_11 = all_12_1_7
% 67.54/29.23  																																																																																																																																																																																																																																																																																														|
% 67.54/29.23  																																																																																																																																																																																																																																																																																															| Combining equations (451,2707) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																															| (507) all_12_1_7 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																															|
% 67.54/29.23  																																																																																																																																																																																																																																																																																															| From (507) and (1162) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																															| (53) aNaturalNumber0(xn) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																															|
% 67.54/29.23  																																																																																																																																																																																																																																																																																															+-Applying beta-rule and splitting (346), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																															|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																															| (1190)  ~ (aNaturalNumber0(xm) = all_22_0_27)
% 67.54/29.23  																																																																																																																																																																																																																																																																																															|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| From (554) and (1190) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| Using (36) and (1191) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																																|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																															|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																															| (1193) aNaturalNumber0(xm) = all_22_0_27
% 67.54/29.23  																																																																																																																																																																																																																																																																																															| (2714) all_28_1_39 = all_22_0_27
% 67.54/29.23  																																																																																																																																																																																																																																																																																															|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| Combining equations (515,2714) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| (554) all_22_0_27 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| Combining equations (554,2714) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| (515) all_28_1_39 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| From (554) and (1193) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| (36) aNaturalNumber0(xm) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																+-Applying beta-rule and splitting (343), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																																|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| (1143)  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	| From (515) and (1143) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	| Using (53) and (1144) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																																|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| (1146) aNaturalNumber0(xn) = all_28_1_39
% 67.54/29.23  																																																																																																																																																																																																																																																																																																| (515) all_28_1_39 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	| From (515) and (1146) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	| (53) aNaturalNumber0(xn) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	+-Applying beta-rule and splitting (319), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	| (1197)  ~ (aNaturalNumber0(xp) = all_41_2_56)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| From (253) and (1197) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| Using (12) and (1198) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	| (1200) aNaturalNumber0(xp) = all_41_2_56
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	| (2728) all_41_2_56 = all_24_2_32
% 67.54/29.23  																																																																																																																																																																																																																																																																																																	|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| Combining equations (253,2728) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| (493) all_24_2_32 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| Combining equations (493,2728) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| (253) all_41_2_56 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| From (253) and (1200) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| (12) aNaturalNumber0(xp) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		+-Applying beta-rule and splitting (254), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| (1197)  ~ (aNaturalNumber0(xp) = all_41_2_56)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			| From (253) and (1197) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			| Using (12) and (1198) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| (1200) aNaturalNumber0(xp) = all_41_2_56
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		| (253) all_41_2_56 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																		|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			| From (253) and (1200) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			| (12) aNaturalNumber0(xp) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			+-Applying beta-rule and splitting (377), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			| (1871)  ~ (aNaturalNumber0(xm) = all_26_0_35)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| From (594) and (1871) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| Using (36) and (1191) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			| (1874) aNaturalNumber0(xm) = all_26_0_35
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			| (2742) all_26_0_35 = all_14_1_10
% 67.54/29.23  																																																																																																																																																																																																																																																																																																			|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| Combining equations (594,2742) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| (503) all_14_1_10 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| Combining equations (503,2742) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| (594) all_26_0_35 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| From (594) and (1874) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| (36) aNaturalNumber0(xm) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				+-Applying beta-rule and splitting (251), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| (1603)  ~ (aNaturalNumber0(all_0_5_5) = all_26_0_35)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					| From (594) and (1603) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					| (1258)  ~ (aNaturalNumber0(all_0_5_5) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					| Using (573) and (1258) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| (1606) aNaturalNumber0(all_0_5_5) = all_26_0_35
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				| (2750) all_26_0_35 = all_12_0_6
% 67.54/29.23  																																																																																																																																																																																																																																																																																																				|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					| Combining equations (594,2750) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					| (570) all_12_0_6 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					| Combining equations (570,2750) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					| (594) all_26_0_35 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					+-Applying beta-rule and splitting (427), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					| (1480)  ~ (aNaturalNumber0(xn) = all_16_2_14)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						| From (571) and (1480) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						| Using (53) and (1144) yields:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						| (615) $false
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						|-The branch is then unsatisfiable
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					|-Branch two:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					| (1483) aNaturalNumber0(xn) = all_16_2_14
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					| (2757) all_24_4_34 = all_16_2_14
% 67.54/29.23  																																																																																																																																																																																																																																																																																																					|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						| Combining equations (511,2757) yields a new equation:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						| (571) all_16_2_14 = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						| From (571) and (1483) follows:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						| (53) aNaturalNumber0(xn) = 0
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						+-Applying beta-rule and splitting (295), into two cases.
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						|-Branch one:
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						| (1554)  ~ (aNaturalNumber0(xp) = all_22_0_27)
% 67.54/29.23  																																																																																																																																																																																																																																																																																																						|
% 67.54/29.23  																																																																																																																																																																																																																																																																																																							| From (554) and (1554) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							| Using (12) and (1198) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																						|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																						| (1557) aNaturalNumber0(xp) = all_22_0_27
% 67.54/29.24  																																																																																																																																																																																																																																																																																																						| (2764) all_30_6_47 = all_22_0_27
% 67.54/29.24  																																																																																																																																																																																																																																																																																																						|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							| Combining equations (1242,2764) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							| (554) all_22_0_27 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							| From (554) and (1557) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							| (12) aNaturalNumber0(xp) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							+-Applying beta-rule and splitting (410), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							| (2767)  ~ (aNaturalNumber0(sz00) = all_28_2_40)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								| From (514) and (2767) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								| (1503)  ~ (aNaturalNumber0(sz00) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								| Using (41) and (1503) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							| (2770) aNaturalNumber0(sz00) = all_28_2_40
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							| (514) all_28_2_40 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																							|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								+-Applying beta-rule and splitting (414), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								| (1245)  ~ (aNaturalNumber0(xn) = all_26_2_37)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									| From (572) and (1245) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									| Using (53) and (1144) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								| (1248) aNaturalNumber0(xn) = all_26_2_37
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								| (2776) all_28_2_40 = all_26_2_37
% 67.54/29.24  																																																																																																																																																																																																																																																																																																								|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									| Combining equations (514,2776) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									| (572) all_26_2_37 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									| From (572) and (1248) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									| (53) aNaturalNumber0(xn) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									+-Applying beta-rule and splitting (308), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									| (1464)  ~ (aNaturalNumber0(xp) = all_16_2_14)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										| From (571) and (1464) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										| Using (12) and (1198) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									| (1467) aNaturalNumber0(xp) = all_16_2_14
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									| (2783) all_26_1_36 = all_16_2_14
% 67.54/29.24  																																																																																																																																																																																																																																																																																																									|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										| Combining equations (303,2783) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										| (571) all_16_2_14 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										| From (571) and (1467) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										| (12) aNaturalNumber0(xp) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										+-Applying beta-rule and splitting (399), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										| (1646)  ~ (aNaturalNumber0(xn) = all_12_0_6)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											| From (570) and (1646) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											| Using (53) and (1144) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										| (1649) aNaturalNumber0(xn) = all_12_0_6
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										| (2790) all_30_8_49 = all_12_0_6
% 67.54/29.24  																																																																																																																																																																																																																																																																																																										|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											| Combining equations (516,2790) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											| (570) all_12_0_6 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											| From (570) and (1649) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											| (53) aNaturalNumber0(xn) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											+-Applying beta-rule and splitting (216), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											| (1151)  ~ (aNaturalNumber0(xn) = all_22_0_27)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												| From (554) and (1151) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												| Using (53) and (1144) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											| (1154) aNaturalNumber0(xn) = all_22_0_27
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											| (554) all_22_0_27 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																											|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												| From (554) and (1154) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												| (53) aNaturalNumber0(xn) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												+-Applying beta-rule and splitting (432), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												| (1143)  ~ (aNaturalNumber0(xn) = all_28_1_39)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| From (515) and (1143) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| Using (53) and (1144) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												| (1146) aNaturalNumber0(xn) = all_28_1_39
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												| (2803) all_28_1_39 = all_24_4_34
% 67.54/29.24  																																																																																																																																																																																																																																																																																																												|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| Combining equations (515,2803) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| (511) all_24_4_34 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| Combining equations (511,2803) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| (515) all_28_1_39 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| From (515) and (1146) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| (53) aNaturalNumber0(xn) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													+-Applying beta-rule and splitting (258), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| (1532)  ~ (aNaturalNumber0(xr) = all_22_0_27)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														| From (554) and (1532) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														| (1287)  ~ (aNaturalNumber0(xr) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														| Using (10) and (1287) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| (1535) aNaturalNumber0(xr) = all_22_0_27
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													| (2811) all_41_2_56 = all_22_0_27
% 67.54/29.24  																																																																																																																																																																																																																																																																																																													|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														| Combining equations (253,2811) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														| (554) all_22_0_27 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														| Combining equations (554,2811) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														| (253) all_41_2_56 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														+-Applying beta-rule and splitting (341), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														| (1851)  ~ (aNaturalNumber0(xm) = all_41_1_55)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| From (980) and (1851) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| Using (36) and (1191) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														| (1854) aNaturalNumber0(xm) = all_41_1_55
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														| (2818) all_41_1_55 = all_30_7_48
% 67.54/29.24  																																																																																																																																																																																																																																																																																																														|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| Combining equations (980,2818) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| (331) all_30_7_48 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| Combining equations (331,2818) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| (980) all_41_1_55 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| From (980) and (1854) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| (36) aNaturalNumber0(xm) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															+-Applying beta-rule and splitting (292), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| (2695)  ~ (aNaturalNumber0(xk) = all_36_3_53)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| From (480) and (2695) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| Using (972) and (974) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| (2698) aNaturalNumber0(xk) = all_36_3_53
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															| (2826) all_36_2_52 = all_36_3_53
% 67.54/29.24  																																																																																																																																																																																																																																																																																																															|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| Combining equations (979,2826) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| (480) all_36_3_53 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| Combining equations (480,2826) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| (979) all_36_2_52 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| From (480) and (2698) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| (972) aNaturalNumber0(xk) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																+-Applying beta-rule and splitting (288), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| (2436)  ~ (aNaturalNumber0(xk) = all_26_0_35)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| From (594) and (2436) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| Using (972) and (974) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| (2439) aNaturalNumber0(xk) = all_26_0_35
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																| (2834) all_36_2_52 = all_26_0_35
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| Combining equations (979,2834) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| (594) all_26_0_35 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| Combining equations (594,2834) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| (979) all_36_2_52 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| From (594) and (2439) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| (972) aNaturalNumber0(xk) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	+-Applying beta-rule and splitting (380), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| (1306)  ~ (aNaturalNumber0(xm) = all_12_0_6)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| From (570) and (1306) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| Using (36) and (1191) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| (1309) aNaturalNumber0(xm) = all_12_0_6
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	| (2842) all_14_1_10 = all_12_0_6
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| Combining equations (503,2842) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| (570) all_12_0_6 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| Combining equations (570,2842) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| (503) all_14_1_10 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| From (570) and (1309) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| (36) aNaturalNumber0(xm) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		+-Applying beta-rule and splitting (323), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| (1213)  ~ (aNaturalNumber0(xp) = all_26_0_35)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| From (594) and (1213) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| Using (12) and (1198) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| (1216) aNaturalNumber0(xp) = all_26_0_35
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		| (2850) all_26_0_35 = all_16_1_13
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																		|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| Combining equations (594,2850) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| (497) all_16_1_13 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| Combining equations (497,2850) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| (594) all_26_0_35 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| From (594) and (1216) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| (12) aNaturalNumber0(xp) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			+-Applying beta-rule and splitting (478), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| (1294)  ~ (aNaturalNumber0(xn) = all_14_1_10)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				| From (503) and (1294) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				| Using (53) and (1144) yields:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				| (615) $false
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				|-The branch is then unsatisfiable
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			|-Branch two:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| (1297) aNaturalNumber0(xn) = all_14_1_10
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			| (2858) all_14_1_10 = all_12_2_8
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																			|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				| Combining equations (503,2858) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				| (508) all_12_2_8 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				| Combining equations (508,2858) yields a new equation:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				| (503) all_14_1_10 = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				| From (503) and (1297) follows:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				| (53) aNaturalNumber0(xn) = 0
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				+-Applying beta-rule and splitting (472), into two cases.
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				|-Branch one:
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				| (1174)  ~ (aNaturalNumber0(xn) = all_41_2_56)
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																				|
% 67.54/29.24  																																																																																																																																																																																																																																																																																																																					| From (253) and (1174) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| Using (53) and (1144) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																				|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																				| (1177) aNaturalNumber0(xn) = all_41_2_56
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																				| (2866) all_41_2_56 = all_12_2_8
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																				|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| Combining equations (253,2866) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| (508) all_12_2_8 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| Combining equations (508,2866) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| (253) all_41_2_56 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| From (253) and (1177) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| (53) aNaturalNumber0(xn) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					+-Applying beta-rule and splitting (317), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| (1205)  ~ (aNaturalNumber0(xp) = all_26_2_37)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| From (572) and (1205) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| Using (12) and (1198) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| (1208) aNaturalNumber0(xp) = all_26_2_37
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					| (2874) all_26_2_37 = all_24_2_32
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																					|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| Combining equations (572,2874) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| (493) all_24_2_32 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| Combining equations (493,2874) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| (572) all_26_2_37 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| From (572) and (1208) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| (12) aNaturalNumber0(xp) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						+-Applying beta-rule and splitting (392), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| (1314)  ~ (aNaturalNumber0(xm) = all_41_2_56)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| From (253) and (1314) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| Using (36) and (1191) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| (1317) aNaturalNumber0(xm) = all_41_2_56
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						| (2882) all_41_2_56 = all_12_1_7
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																						|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| Combining equations (253,2882) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| (507) all_12_1_7 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| Combining equations (507,2882) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| (253) all_41_2_56 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| From (253) and (1317) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| (36) aNaturalNumber0(xm) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							+-Applying beta-rule and splitting (379), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| (1562)  ~ (aNaturalNumber0(xm) = all_16_2_14)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								| From (571) and (1562) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								| Using (36) and (1191) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| (1565) aNaturalNumber0(xm) = all_16_2_14
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							| (2890) all_16_2_14 = all_14_1_10
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																							|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								| From (571) and (1565) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								| (36) aNaturalNumber0(xm) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								+-Applying beta-rule and splitting (370), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								| (1330)  ~ (aNaturalNumber0(xm) = all_36_3_53)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									| From (480) and (1330) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									| (1191)  ~ (aNaturalNumber0(xm) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									| Using (36) and (1191) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								| (1333) aNaturalNumber0(xm) = all_36_3_53
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								| (2896) all_36_3_53 = all_22_1_28
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																								|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									| Combining equations (480,2896) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									| (499) all_22_1_28 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									| Combining equations (499,2896) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									| (480) all_36_3_53 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									+-Applying beta-rule and splitting (326), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									| (2054)  ~ (aNaturalNumber0(xp) = all_12_0_6)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										| From (570) and (2054) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										| Using (12) and (1198) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									| (2057) aNaturalNumber0(xp) = all_12_0_6
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									| (2903) all_16_1_13 = all_12_0_6
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																									|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										| Combining equations (497,2903) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										| (570) all_12_0_6 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										| From (570) and (2057) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										| (12) aNaturalNumber0(xp) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										+-Applying beta-rule and splitting (314), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										| (1418)  ~ (aNaturalNumber0(xp) = all_36_1_51)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| From (555) and (1418) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| Using (12) and (1198) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										| (1421) aNaturalNumber0(xp) = all_36_1_51
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										| (2910) all_36_1_51 = all_24_2_32
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																										|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| Combining equations (555,2910) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| (493) all_24_2_32 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| Combining equations (493,2910) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| (555) all_36_1_51 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| From (555) and (1421) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| (12) aNaturalNumber0(xp) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											+-Applying beta-rule and splitting (385), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| (1159)  ~ (aNaturalNumber0(xn) = all_12_1_7)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												| From (507) and (1159) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												| Using (53) and (1144) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| (1162) aNaturalNumber0(xn) = all_12_1_7
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											| (507) all_12_1_7 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																											|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												| From (507) and (1162) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												| (53) aNaturalNumber0(xn) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												+-Applying beta-rule and splitting (290), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												| (2920)  ~ (aNaturalNumber0(xk) = all_12_0_6)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													| From (570) and (2920) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													| Using (972) and (974) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												| (2923) aNaturalNumber0(xk) = all_12_0_6
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												| (2924) all_36_2_52 = all_12_0_6
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																												|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													| Combining equations (979,2924) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													| (570) all_12_0_6 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													| From (570) and (2923) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													| (972) aNaturalNumber0(xk) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													+-Applying beta-rule and splitting (442), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													| (1646)  ~ (aNaturalNumber0(xn) = all_12_0_6)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														| From (570) and (1646) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														| (1144)  ~ (aNaturalNumber0(xn) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														| Using (53) and (1144) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													| (1649) aNaturalNumber0(xn) = all_12_0_6
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													| (2931) all_22_2_29 = all_12_0_6
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																													|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														| Combining equations (2931,510) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														| (2932) all_12_0_6 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														| Simplifying 2932 yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														| (570) all_12_0_6 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														+-Applying beta-rule and splitting (322), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														| (1554)  ~ (aNaturalNumber0(xp) = all_22_0_27)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| From (554) and (1554) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| Using (12) and (1198) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														| (1557) aNaturalNumber0(xp) = all_22_0_27
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														| (2938) all_22_0_27 = all_16_1_13
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																														|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| Combining equations (554,2938) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| (497) all_16_1_13 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| Combining equations (497,2938) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| (554) all_22_0_27 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| From (554) and (1557) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| (12) aNaturalNumber0(xp) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															+-Applying beta-rule and splitting (311), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| (1272)  ~ (aNaturalNumber0(xp) = all_36_3_53)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| From (480) and (1272) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| Using (12) and (1198) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| (1275) aNaturalNumber0(xp) = all_36_3_53
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															| (2946) all_36_3_53 = all_26_1_36
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																															|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| Combining equations (480,2946) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| (303) all_26_1_36 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| Combining equations (303,2946) yields a new equation:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| (480) all_36_3_53 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| From (480) and (1275) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| (12) aNaturalNumber0(xp) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																+-Applying beta-rule and splitting (244), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| (2054)  ~ (aNaturalNumber0(xp) = all_12_0_6)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	| From (570) and (2054) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	| (1198)  ~ (aNaturalNumber0(xp) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	| Using (12) and (1198) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| (2057) aNaturalNumber0(xp) = all_12_0_6
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																| (570) all_12_0_6 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	| From (570) and (2057) follows:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	| (12) aNaturalNumber0(xp) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	+-Applying beta-rule and splitting (218), into two cases.
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	|-Branch one:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	| (1937)  ~ (aNaturalNumber0(all_0_3_3) = 0)
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																		| Using (556) and (1937) yields:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																		| (615) $false
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																		|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																		|-The branch is then unsatisfiable
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	|-Branch two:
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	| (556) aNaturalNumber0(all_0_3_3) = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	| (554) all_22_0_27 = 0
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																	|
% 67.54/29.25  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (81) with xk, all_432_0_148 and discharging atoms doDivides0(all_432_0_148, xk) = 0, yields:
% 67.70/29.25  																																																																																																																																																																																																																																																																																																																																		| (2960) xk = sz00 |  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(all_432_0_148, xk) = v2 & aNaturalNumber0(all_432_0_148) = v0 & aNaturalNumber0(xk) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.70/29.25  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.25  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (81) with xk, all_386_0_142 and discharging atoms doDivides0(all_386_0_142, xk) = 0, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2961) xk = sz00 |  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(all_386_0_142, xk) = v2 & aNaturalNumber0(all_386_0_142) = v0 & aNaturalNumber0(xk) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (45) with all_0_3_3, xk, xp, all_21_2_26, xr and discharging atoms sdtasdt0(xr, all_21_2_26) = xk, sdtasdt0(xk, xp) = all_0_3_3, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2962)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtasdt0(all_21_2_26, xp) = v3 & sdtasdt0(xr, v3) = v4 & aNaturalNumber0(all_21_2_26) = v1 & aNaturalNumber0(xr) = v0 & aNaturalNumber0(xp) = v2 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_0_3_3))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (37) with xp, all_36_0_50, all_0_3_3, xk and discharging atoms doDivides0(xk, all_0_3_3) = all_36_0_50, sdtasdt0(xk, xp) = all_0_3_3, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2963) all_36_0_50 = 0 |  ? [v0] :  ? [v1] : (( ~ (v0 = 0) & aNaturalNumber0(xp) = v0) | (aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xk) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0))))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (7) with all_0_3_3, xp, xp, xk and discharging atoms doDivides0(xp, all_0_3_3) = 0, sdtasdt0(xk, xp) = all_0_3_3, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2964)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] : (isPrime0(xp) = v3 & doDivides0(xp, xk) = v7 & doDivides0(xp, xp) = v8 & iLess0(v5, all_0_4_4) = v6 & sdtpldt0(v4, xp) = v5 & sdtpldt0(xk, xp) = v4 & aNaturalNumber0(xk) = v0 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xp) = v1 & ( ~ (v6 = 0) |  ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v8 = 0 | v7 = 0))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (45) with xp, xp, all_186_2_128, all_186_2_128, xp and discharging atoms sdtasdt0(xp, all_186_2_128) = xp, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2965)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtasdt0(all_186_2_128, all_186_2_128) = v3 & sdtasdt0(xp, v3) = v4 & aNaturalNumber0(all_186_2_128) = v2 & aNaturalNumber0(all_186_2_128) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = xp))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (7) with xp, xp, all_186_2_128, xp and discharging atoms doDivides0(xp, xp) = 0, sdtasdt0(xp, all_186_2_128) = xp, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2966)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] : (isPrime0(xp) = v3 & doDivides0(xp, all_186_2_128) = v8 & doDivides0(xp, xp) = v7 & iLess0(v5, all_0_4_4) = v6 & sdtpldt0(v4, xp) = v5 & sdtpldt0(xp, all_186_2_128) = v4 & aNaturalNumber0(all_186_2_128) = v1 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xp) = v0 & ( ~ (v6 = 0) |  ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v8 = 0 | v7 = 0))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (7) with xp, all_208_0_135, all_186_2_128, xp and discharging atoms doDivides0(all_208_0_135, xp) = 0, sdtasdt0(xp, all_186_2_128) = xp, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2967)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] :  ? [v5] :  ? [v6] :  ? [v7] :  ? [v8] : (isPrime0(all_208_0_135) = v3 & doDivides0(all_208_0_135, all_186_2_128) = v8 & doDivides0(all_208_0_135, xp) = v7 & iLess0(v5, all_0_4_4) = v6 & sdtpldt0(v4, all_208_0_135) = v5 & sdtpldt0(xp, all_186_2_128) = v4 & aNaturalNumber0(all_208_0_135) = v2 & aNaturalNumber0(all_186_2_128) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v6 = 0) |  ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v8 = 0 | v7 = 0))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (27) with xp, all_186_2_128, xp and discharging atoms sdtasdt0(xp, all_186_2_128) = xp, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2968)  ? [v0] :  ? [v1] :  ? [v2] : (sdtasdt0(all_186_2_128, xp) = v2 & aNaturalNumber0(all_186_2_128) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = xp))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (45) with all_0_3_3, xp, xk, all_186_2_128, xp and discharging atoms sdtasdt0(xp, all_186_2_128) = xp, sdtasdt0(xp, xk) = all_0_3_3, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2969)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtasdt0(all_186_2_128, xk) = v3 & sdtasdt0(xp, v3) = v4 & aNaturalNumber0(all_186_2_128) = v1 & aNaturalNumber0(xk) = v2 & aNaturalNumber0(xp) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_0_3_3))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (78) with all_179_3_103, xp, all_179_4_104 and discharging atoms sdtpldt0(all_179_4_104, xp) = all_179_3_103, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2970)  ? [v0] :  ? [v1] :  ? [v2] : (sdtpldt0(xp, all_179_4_104) = v2 & aNaturalNumber0(all_179_4_104) = v0 & aNaturalNumber0(xp) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = all_179_3_103))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (43) with all_179_3_103, xp, all_179_4_104 and discharging atoms sdtpldt0(all_179_4_104, xp) = all_179_3_103, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2971)  ? [v0] :  ? [v1] :  ? [v2] : (aNaturalNumber0(all_179_3_103) = v2 & aNaturalNumber0(all_179_4_104) = v0 & aNaturalNumber0(xp) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (49) with all_0_4_4, all_24_1_31, xn, xp, xm and discharging atoms sdtpldt0(all_24_1_31, xn) = all_0_4_4, sdtpldt0(xm, xp) = all_24_1_31, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2972)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(xp, xn) = v3 & sdtpldt0(xm, v3) = v4 & aNaturalNumber0(xp) = v1 & aNaturalNumber0(xm) = v0 & aNaturalNumber0(xn) = v2 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_0_4_4))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (40) with xp, xm, all_19_2_20, xp and discharging atoms doDivides0(xp, xp) = 0, sdtpldt0(all_19_2_20, xm) = xp, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2973)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (doDivides0(xp, all_19_2_20) = v3 & doDivides0(xp, xm) = v4 & aNaturalNumber0(all_19_2_20) = v1 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xm) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = 0))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (40) with xp, xn, all_18_2_17, xp and discharging atoms doDivides0(xp, xp) = 0, sdtpldt0(all_18_2_17, xn) = xp, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2974)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (doDivides0(xp, all_18_2_17) = v3 & doDivides0(xp, xn) = v4 & aNaturalNumber0(all_18_2_17) = v1 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xn) = v2 & ( ~ (v3 = 0) |  ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = 0))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (49) with all_179_4_104, xp, xk, all_19_2_20, xm and discharging atoms sdtpldt0(xp, xk) = all_179_4_104, sdtpldt0(xm, all_19_2_20) = xp, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2975)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(all_19_2_20, xk) = v3 & sdtpldt0(xm, v3) = v4 & aNaturalNumber0(all_19_2_20) = v1 & aNaturalNumber0(xk) = v2 & aNaturalNumber0(xm) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_179_4_104))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (49) with all_179_4_104, xp, xk, all_18_2_17, xn and discharging atoms sdtpldt0(xp, xk) = all_179_4_104, sdtpldt0(xn, all_18_2_17) = xp, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2976)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(all_18_2_17, xk) = v3 & sdtpldt0(xn, v3) = v4 & aNaturalNumber0(all_18_2_17) = v1 & aNaturalNumber0(xk) = v2 & aNaturalNumber0(xn) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_179_4_104))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (49) with all_179_3_103, all_179_4_104, xp, xk, xp and discharging atoms sdtpldt0(all_179_4_104, xp) = all_179_3_103, sdtpldt0(xp, xk) = all_179_4_104, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2977)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(xk, xp) = v3 & sdtpldt0(xp, v3) = v4 & aNaturalNumber0(xk) = v1 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xp) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_179_3_103))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (49) with all_179_4_104, xp, xk, xm, all_19_2_20 and discharging atoms sdtpldt0(all_19_2_20, xm) = xp, sdtpldt0(xp, xk) = all_179_4_104, yields:
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| (2978)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(all_19_2_20, v3) = v4 & sdtpldt0(xm, xk) = v3 & aNaturalNumber0(all_19_2_20) = v0 & aNaturalNumber0(xk) = v2 & aNaturalNumber0(xm) = v1 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_179_4_104))
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.70/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (49) with all_179_4_104, xp, xk, xn, all_18_2_17 and discharging atoms sdtpldt0(all_18_2_17, xn) = xp, sdtpldt0(xp, xk) = all_179_4_104, yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2979)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(all_18_2_17, v3) = v4 & sdtpldt0(xn, xk) = v3 & aNaturalNumber0(all_18_2_17) = v0 & aNaturalNumber0(xk) = v2 & aNaturalNumber0(xn) = v1 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | v4 = all_179_4_104))
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (78) with all_179_4_104, xk, xp and discharging atoms sdtpldt0(xp, xk) = all_179_4_104, yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2980)  ? [v0] :  ? [v1] :  ? [v2] : (sdtpldt0(xk, xp) = v2 & aNaturalNumber0(xk) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = all_179_4_104))
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (43) with all_179_4_104, xk, xp and discharging atoms sdtpldt0(xp, xk) = all_179_4_104, yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2981)  ? [v0] :  ? [v1] :  ? [v2] : (aNaturalNumber0(all_179_4_104) = v2 & aNaturalNumber0(xk) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (24) with all_161_1_68, all_0_5_5, xp, xm, xn and discharging atoms sdtpldt0(xn, xp) = all_161_1_68, sdtpldt0(xn, xm) = all_0_5_5, yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2982) xp = xm |  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(xp, xn) = v4 & sdtpldt0(xm, xn) = v3 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xm) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | ( ~ (v4 = v3) &  ~ (all_161_1_68 = all_0_5_5))))
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (78) with all_161_1_68, xp, xn and discharging atoms sdtpldt0(xn, xp) = all_161_1_68, yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2983)  ? [v0] :  ? [v1] :  ? [v2] : (sdtpldt0(xp, xn) = v2 & aNaturalNumber0(xp) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = all_161_1_68))
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (43) with all_161_1_68, xp, xn and discharging atoms sdtpldt0(xn, xp) = all_161_1_68, yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2984)  ? [v0] :  ? [v1] :  ? [v2] : (aNaturalNumber0(all_161_1_68) = v2 & aNaturalNumber0(xp) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2984) with all_2334_0_168, all_2334_1_169, all_2334_2_170 yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2985) aNaturalNumber0(all_161_1_68) = all_2334_0_168 & aNaturalNumber0(xp) = all_2334_1_169 & aNaturalNumber0(xn) = all_2334_2_170 & ( ~ (all_2334_1_169 = 0) |  ~ (all_2334_2_170 = 0) | all_2334_0_168 = 0)
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (2985) yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2986) aNaturalNumber0(all_161_1_68) = all_2334_0_168
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2987) aNaturalNumber0(xp) = all_2334_1_169
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2988) aNaturalNumber0(xn) = all_2334_2_170
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2989)  ~ (all_2334_1_169 = 0) |  ~ (all_2334_2_170 = 0) | all_2334_0_168 = 0
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2983) with all_2336_0_171, all_2336_1_172, all_2336_2_173 yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2990) sdtpldt0(xp, xn) = all_2336_0_171 & aNaturalNumber0(xp) = all_2336_1_172 & aNaturalNumber0(xn) = all_2336_2_173 & ( ~ (all_2336_1_172 = 0) |  ~ (all_2336_2_173 = 0) | all_2336_0_171 = all_161_1_68)
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (2990) yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2991) sdtpldt0(xp, xn) = all_2336_0_171
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2992) aNaturalNumber0(xp) = all_2336_1_172
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2993) aNaturalNumber0(xn) = all_2336_2_173
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2994)  ~ (all_2336_1_172 = 0) |  ~ (all_2336_2_173 = 0) | all_2336_0_171 = all_161_1_68
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2976) with all_2352_0_197, all_2352_1_198, all_2352_2_199, all_2352_3_200, all_2352_4_201 yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2995) sdtpldt0(all_18_2_17, xk) = all_2352_1_198 & sdtpldt0(xn, all_2352_1_198) = all_2352_0_197 & aNaturalNumber0(all_18_2_17) = all_2352_3_200 & aNaturalNumber0(xk) = all_2352_2_199 & aNaturalNumber0(xn) = all_2352_4_201 & ( ~ (all_2352_2_199 = 0) |  ~ (all_2352_3_200 = 0) |  ~ (all_2352_4_201 = 0) | all_2352_0_197 = all_179_4_104)
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (2995) yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2996) aNaturalNumber0(all_18_2_17) = all_2352_3_200
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2997) aNaturalNumber0(xk) = all_2352_2_199
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2998) sdtpldt0(xn, all_2352_1_198) = all_2352_0_197
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (2999) sdtpldt0(all_18_2_17, xk) = all_2352_1_198
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (3000) aNaturalNumber0(xn) = all_2352_4_201
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (3001)  ~ (all_2352_2_199 = 0) |  ~ (all_2352_3_200 = 0) |  ~ (all_2352_4_201 = 0) | all_2352_0_197 = all_179_4_104
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2981) with all_2356_0_205, all_2356_1_206, all_2356_2_207 yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (3002) aNaturalNumber0(all_179_4_104) = all_2356_0_205 & aNaturalNumber0(xk) = all_2356_1_206 & aNaturalNumber0(xp) = all_2356_2_207 & ( ~ (all_2356_1_206 = 0) |  ~ (all_2356_2_207 = 0) | all_2356_0_205 = 0)
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3002) yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (3003) aNaturalNumber0(all_179_4_104) = all_2356_0_205
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (3004) aNaturalNumber0(xk) = all_2356_1_206
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (3005) aNaturalNumber0(xp) = all_2356_2_207
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (3006)  ~ (all_2356_1_206 = 0) |  ~ (all_2356_2_207 = 0) | all_2356_0_205 = 0
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2980) with all_2358_0_208, all_2358_1_209, all_2358_2_210 yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (3007) sdtpldt0(xk, xp) = all_2358_0_208 & aNaturalNumber0(xk) = all_2358_1_209 & aNaturalNumber0(xp) = all_2358_2_210 & ( ~ (all_2358_1_209 = 0) |  ~ (all_2358_2_210 = 0) | all_2358_0_208 = all_179_4_104)
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3007) yields:
% 67.71/29.26  																																																																																																																																																																																																																																																																																																																																		| (3008) sdtpldt0(xk, xp) = all_2358_0_208
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3009) aNaturalNumber0(xk) = all_2358_1_209
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3010) aNaturalNumber0(xp) = all_2358_2_210
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3011)  ~ (all_2358_1_209 = 0) |  ~ (all_2358_2_210 = 0) | all_2358_0_208 = all_179_4_104
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2978) with all_2360_0_211, all_2360_1_212, all_2360_2_213, all_2360_3_214, all_2360_4_215 yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3012) sdtpldt0(all_19_2_20, all_2360_1_212) = all_2360_0_211 & sdtpldt0(xm, xk) = all_2360_1_212 & aNaturalNumber0(all_19_2_20) = all_2360_4_215 & aNaturalNumber0(xk) = all_2360_2_213 & aNaturalNumber0(xm) = all_2360_3_214 & ( ~ (all_2360_2_213 = 0) |  ~ (all_2360_3_214 = 0) |  ~ (all_2360_4_215 = 0) | all_2360_0_211 = all_179_4_104)
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3012) yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3013) aNaturalNumber0(xm) = all_2360_3_214
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3014) sdtpldt0(xm, xk) = all_2360_1_212
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3015) sdtpldt0(all_19_2_20, all_2360_1_212) = all_2360_0_211
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3016) aNaturalNumber0(all_19_2_20) = all_2360_4_215
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3017)  ~ (all_2360_2_213 = 0) |  ~ (all_2360_3_214 = 0) |  ~ (all_2360_4_215 = 0) | all_2360_0_211 = all_179_4_104
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3018) aNaturalNumber0(xk) = all_2360_2_213
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2975) with all_2364_0_219, all_2364_1_220, all_2364_2_221, all_2364_3_222, all_2364_4_223 yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3019) sdtpldt0(all_19_2_20, xk) = all_2364_1_220 & sdtpldt0(xm, all_2364_1_220) = all_2364_0_219 & aNaturalNumber0(all_19_2_20) = all_2364_3_222 & aNaturalNumber0(xk) = all_2364_2_221 & aNaturalNumber0(xm) = all_2364_4_223 & ( ~ (all_2364_2_221 = 0) |  ~ (all_2364_3_222 = 0) |  ~ (all_2364_4_223 = 0) | all_2364_0_219 = all_179_4_104)
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3019) yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3020) aNaturalNumber0(xk) = all_2364_2_221
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3021) sdtpldt0(all_19_2_20, xk) = all_2364_1_220
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3022)  ~ (all_2364_2_221 = 0) |  ~ (all_2364_3_222 = 0) |  ~ (all_2364_4_223 = 0) | all_2364_0_219 = all_179_4_104
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3023) aNaturalNumber0(xm) = all_2364_4_223
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3024) aNaturalNumber0(all_19_2_20) = all_2364_3_222
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3025) sdtpldt0(xm, all_2364_1_220) = all_2364_0_219
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2974) with all_2376_0_249, all_2376_1_250, all_2376_2_251, all_2376_3_252, all_2376_4_253 yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3026) doDivides0(xp, all_18_2_17) = all_2376_1_250 & doDivides0(xp, xn) = all_2376_0_249 & aNaturalNumber0(all_18_2_17) = all_2376_3_252 & aNaturalNumber0(xp) = all_2376_4_253 & aNaturalNumber0(xn) = all_2376_2_251 & ( ~ (all_2376_1_250 = 0) |  ~ (all_2376_2_251 = 0) |  ~ (all_2376_3_252 = 0) |  ~ (all_2376_4_253 = 0) | all_2376_0_249 = 0)
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3026) yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3027)  ~ (all_2376_1_250 = 0) |  ~ (all_2376_2_251 = 0) |  ~ (all_2376_3_252 = 0) |  ~ (all_2376_4_253 = 0) | all_2376_0_249 = 0
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3028) doDivides0(xp, all_18_2_17) = all_2376_1_250
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3029) aNaturalNumber0(xn) = all_2376_2_251
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3030) doDivides0(xp, xn) = all_2376_0_249
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3031) aNaturalNumber0(xp) = all_2376_4_253
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3032) aNaturalNumber0(all_18_2_17) = all_2376_3_252
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2972) with all_2378_0_254, all_2378_1_255, all_2378_2_256, all_2378_3_257, all_2378_4_258 yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3033) sdtpldt0(xp, xn) = all_2378_1_255 & sdtpldt0(xm, all_2378_1_255) = all_2378_0_254 & aNaturalNumber0(xp) = all_2378_3_257 & aNaturalNumber0(xm) = all_2378_4_258 & aNaturalNumber0(xn) = all_2378_2_256 & ( ~ (all_2378_2_256 = 0) |  ~ (all_2378_3_257 = 0) |  ~ (all_2378_4_258 = 0) | all_2378_0_254 = all_0_4_4)
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3033) yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3034) aNaturalNumber0(xm) = all_2378_4_258
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3035)  ~ (all_2378_2_256 = 0) |  ~ (all_2378_3_257 = 0) |  ~ (all_2378_4_258 = 0) | all_2378_0_254 = all_0_4_4
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3036) sdtpldt0(xm, all_2378_1_255) = all_2378_0_254
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3037) aNaturalNumber0(xn) = all_2378_2_256
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3038) sdtpldt0(xp, xn) = all_2378_1_255
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3039) aNaturalNumber0(xp) = all_2378_3_257
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2968) with all_2380_0_259, all_2380_1_260, all_2380_2_261 yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3040) sdtasdt0(all_186_2_128, xp) = all_2380_0_259 & aNaturalNumber0(all_186_2_128) = all_2380_1_260 & aNaturalNumber0(xp) = all_2380_2_261 & ( ~ (all_2380_1_260 = 0) |  ~ (all_2380_2_261 = 0) | all_2380_0_259 = xp)
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3040) yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3041) sdtasdt0(all_186_2_128, xp) = all_2380_0_259
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3042) aNaturalNumber0(all_186_2_128) = all_2380_1_260
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3043) aNaturalNumber0(xp) = all_2380_2_261
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3044)  ~ (all_2380_1_260 = 0) |  ~ (all_2380_2_261 = 0) | all_2380_0_259 = xp
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2967) with all_2382_0_262, all_2382_1_263, all_2382_2_264, all_2382_3_265, all_2382_4_266, all_2382_5_267, all_2382_6_268, all_2382_7_269, all_2382_8_270 yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3045) isPrime0(all_208_0_135) = all_2382_5_267 & doDivides0(all_208_0_135, all_186_2_128) = all_2382_0_262 & doDivides0(all_208_0_135, xp) = all_2382_1_263 & iLess0(all_2382_3_265, all_0_4_4) = all_2382_2_264 & sdtpldt0(all_2382_4_266, all_208_0_135) = all_2382_3_265 & sdtpldt0(xp, all_186_2_128) = all_2382_4_266 & aNaturalNumber0(all_208_0_135) = all_2382_6_268 & aNaturalNumber0(all_186_2_128) = all_2382_7_269 & aNaturalNumber0(xp) = all_2382_8_270 & ( ~ (all_2382_2_264 = 0) |  ~ (all_2382_5_267 = 0) |  ~ (all_2382_6_268 = 0) |  ~ (all_2382_7_269 = 0) |  ~ (all_2382_8_270 = 0) | all_2382_0_262 = 0 | all_2382_1_263 = 0)
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3045) yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3046) aNaturalNumber0(xp) = all_2382_8_270
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3047) sdtpldt0(xp, all_186_2_128) = all_2382_4_266
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3048) sdtpldt0(all_2382_4_266, all_208_0_135) = all_2382_3_265
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3049) aNaturalNumber0(all_208_0_135) = all_2382_6_268
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3050) doDivides0(all_208_0_135, xp) = all_2382_1_263
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3051) iLess0(all_2382_3_265, all_0_4_4) = all_2382_2_264
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3052) doDivides0(all_208_0_135, all_186_2_128) = all_2382_0_262
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3053) isPrime0(all_208_0_135) = all_2382_5_267
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3054)  ~ (all_2382_2_264 = 0) |  ~ (all_2382_5_267 = 0) |  ~ (all_2382_6_268 = 0) |  ~ (all_2382_7_269 = 0) |  ~ (all_2382_8_270 = 0) | all_2382_0_262 = 0 | all_2382_1_263 = 0
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3055) aNaturalNumber0(all_186_2_128) = all_2382_7_269
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2966) with all_2384_0_271, all_2384_1_272, all_2384_2_273, all_2384_3_274, all_2384_4_275, all_2384_5_276, all_2384_6_277, all_2384_7_278, all_2384_8_279 yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3056) isPrime0(xp) = all_2384_5_276 & doDivides0(xp, all_186_2_128) = all_2384_0_271 & doDivides0(xp, xp) = all_2384_1_272 & iLess0(all_2384_3_274, all_0_4_4) = all_2384_2_273 & sdtpldt0(all_2384_4_275, xp) = all_2384_3_274 & sdtpldt0(xp, all_186_2_128) = all_2384_4_275 & aNaturalNumber0(all_186_2_128) = all_2384_7_278 & aNaturalNumber0(xp) = all_2384_6_277 & aNaturalNumber0(xp) = all_2384_8_279 & ( ~ (all_2384_2_273 = 0) |  ~ (all_2384_5_276 = 0) |  ~ (all_2384_6_277 = 0) |  ~ (all_2384_7_278 = 0) |  ~ (all_2384_8_279 = 0) | all_2384_0_271 = 0 | all_2384_1_272 = 0)
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3056) yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3057) aNaturalNumber0(all_186_2_128) = all_2384_7_278
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3058) isPrime0(xp) = all_2384_5_276
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3059) aNaturalNumber0(xp) = all_2384_6_277
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3060)  ~ (all_2384_2_273 = 0) |  ~ (all_2384_5_276 = 0) |  ~ (all_2384_6_277 = 0) |  ~ (all_2384_7_278 = 0) |  ~ (all_2384_8_279 = 0) | all_2384_0_271 = 0 | all_2384_1_272 = 0
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3061) doDivides0(xp, all_186_2_128) = all_2384_0_271
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3062) doDivides0(xp, xp) = all_2384_1_272
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3063) iLess0(all_2384_3_274, all_0_4_4) = all_2384_2_273
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3064) sdtpldt0(all_2384_4_275, xp) = all_2384_3_274
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3065) aNaturalNumber0(xp) = all_2384_8_279
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3066) sdtpldt0(xp, all_186_2_128) = all_2384_4_275
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2977) with all_2388_0_283, all_2388_1_284, all_2388_2_285, all_2388_3_286, all_2388_4_287 yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3067) sdtpldt0(xk, xp) = all_2388_1_284 & sdtpldt0(xp, all_2388_1_284) = all_2388_0_283 & aNaturalNumber0(xk) = all_2388_3_286 & aNaturalNumber0(xp) = all_2388_2_285 & aNaturalNumber0(xp) = all_2388_4_287 & ( ~ (all_2388_2_285 = 0) |  ~ (all_2388_3_286 = 0) |  ~ (all_2388_4_287 = 0) | all_2388_0_283 = all_179_3_103)
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3067) yields:
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3068) sdtpldt0(xk, xp) = all_2388_1_284
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3069) aNaturalNumber0(xk) = all_2388_3_286
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3070) sdtpldt0(xp, all_2388_1_284) = all_2388_0_283
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3071) aNaturalNumber0(xp) = all_2388_2_285
% 67.71/29.27  																																																																																																																																																																																																																																																																																																																																		| (3072) aNaturalNumber0(xp) = all_2388_4_287
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3073)  ~ (all_2388_2_285 = 0) |  ~ (all_2388_3_286 = 0) |  ~ (all_2388_4_287 = 0) | all_2388_0_283 = all_179_3_103
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2979) with all_2399_0_312, all_2399_1_313, all_2399_2_314, all_2399_3_315, all_2399_4_316 yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3074) sdtpldt0(all_18_2_17, all_2399_1_313) = all_2399_0_312 & sdtpldt0(xn, xk) = all_2399_1_313 & aNaturalNumber0(all_18_2_17) = all_2399_4_316 & aNaturalNumber0(xk) = all_2399_2_314 & aNaturalNumber0(xn) = all_2399_3_315 & ( ~ (all_2399_2_314 = 0) |  ~ (all_2399_3_315 = 0) |  ~ (all_2399_4_316 = 0) | all_2399_0_312 = all_179_4_104)
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3074) yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3075) sdtpldt0(xn, xk) = all_2399_1_313
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3076) aNaturalNumber0(all_18_2_17) = all_2399_4_316
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3077) aNaturalNumber0(xn) = all_2399_3_315
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3078)  ~ (all_2399_2_314 = 0) |  ~ (all_2399_3_315 = 0) |  ~ (all_2399_4_316 = 0) | all_2399_0_312 = all_179_4_104
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3079) sdtpldt0(all_18_2_17, all_2399_1_313) = all_2399_0_312
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3080) aNaturalNumber0(xk) = all_2399_2_314
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2964) with all_2408_0_336, all_2408_1_337, all_2408_2_338, all_2408_3_339, all_2408_4_340, all_2408_5_341, all_2408_6_342, all_2408_7_343, all_2408_8_344 yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3081) isPrime0(xp) = all_2408_5_341 & doDivides0(xp, xk) = all_2408_1_337 & doDivides0(xp, xp) = all_2408_0_336 & iLess0(all_2408_3_339, all_0_4_4) = all_2408_2_338 & sdtpldt0(all_2408_4_340, xp) = all_2408_3_339 & sdtpldt0(xk, xp) = all_2408_4_340 & aNaturalNumber0(xk) = all_2408_8_344 & aNaturalNumber0(xp) = all_2408_6_342 & aNaturalNumber0(xp) = all_2408_7_343 & ( ~ (all_2408_2_338 = 0) |  ~ (all_2408_5_341 = 0) |  ~ (all_2408_6_342 = 0) |  ~ (all_2408_7_343 = 0) |  ~ (all_2408_8_344 = 0) | all_2408_0_336 = 0 | all_2408_1_337 = 0)
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3081) yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3082) isPrime0(xp) = all_2408_5_341
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3083) aNaturalNumber0(xp) = all_2408_6_342
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3084) iLess0(all_2408_3_339, all_0_4_4) = all_2408_2_338
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3085) doDivides0(xp, xk) = all_2408_1_337
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3086)  ~ (all_2408_2_338 = 0) |  ~ (all_2408_5_341 = 0) |  ~ (all_2408_6_342 = 0) |  ~ (all_2408_7_343 = 0) |  ~ (all_2408_8_344 = 0) | all_2408_0_336 = 0 | all_2408_1_337 = 0
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3087) sdtpldt0(xk, xp) = all_2408_4_340
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3088) aNaturalNumber0(xk) = all_2408_8_344
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3089) aNaturalNumber0(xp) = all_2408_7_343
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3090) sdtpldt0(all_2408_4_340, xp) = all_2408_3_339
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3091) doDivides0(xp, xp) = all_2408_0_336
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2962) with all_2410_0_345, all_2410_1_346, all_2410_2_347, all_2410_3_348, all_2410_4_349 yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3092) sdtasdt0(all_21_2_26, xp) = all_2410_1_346 & sdtasdt0(xr, all_2410_1_346) = all_2410_0_345 & aNaturalNumber0(all_21_2_26) = all_2410_3_348 & aNaturalNumber0(xr) = all_2410_4_349 & aNaturalNumber0(xp) = all_2410_2_347 & ( ~ (all_2410_2_347 = 0) |  ~ (all_2410_3_348 = 0) |  ~ (all_2410_4_349 = 0) | all_2410_0_345 = all_0_3_3)
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3092) yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3093)  ~ (all_2410_2_347 = 0) |  ~ (all_2410_3_348 = 0) |  ~ (all_2410_4_349 = 0) | all_2410_0_345 = all_0_3_3
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3094) sdtasdt0(all_21_2_26, xp) = all_2410_1_346
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3095) aNaturalNumber0(xp) = all_2410_2_347
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3096) aNaturalNumber0(all_21_2_26) = all_2410_3_348
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3097) sdtasdt0(xr, all_2410_1_346) = all_2410_0_345
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3098) aNaturalNumber0(xr) = all_2410_4_349
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2965) with all_2414_0_359, all_2414_1_360, all_2414_2_361, all_2414_3_362, all_2414_4_363 yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3099) sdtasdt0(all_186_2_128, all_186_2_128) = all_2414_1_360 & sdtasdt0(xp, all_2414_1_360) = all_2414_0_359 & aNaturalNumber0(all_186_2_128) = all_2414_2_361 & aNaturalNumber0(all_186_2_128) = all_2414_3_362 & aNaturalNumber0(xp) = all_2414_4_363 & ( ~ (all_2414_2_361 = 0) |  ~ (all_2414_3_362 = 0) |  ~ (all_2414_4_363 = 0) | all_2414_0_359 = xp)
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3099) yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3100) aNaturalNumber0(xp) = all_2414_4_363
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3101) sdtasdt0(xp, all_2414_1_360) = all_2414_0_359
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3102)  ~ (all_2414_2_361 = 0) |  ~ (all_2414_3_362 = 0) |  ~ (all_2414_4_363 = 0) | all_2414_0_359 = xp
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3103) aNaturalNumber0(all_186_2_128) = all_2414_3_362
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3104) sdtasdt0(all_186_2_128, all_186_2_128) = all_2414_1_360
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3105) aNaturalNumber0(all_186_2_128) = all_2414_2_361
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2971) with all_2421_0_379, all_2421_1_380, all_2421_2_381 yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3106) aNaturalNumber0(all_179_3_103) = all_2421_0_379 & aNaturalNumber0(all_179_4_104) = all_2421_2_381 & aNaturalNumber0(xp) = all_2421_1_380 & ( ~ (all_2421_1_380 = 0) |  ~ (all_2421_2_381 = 0) | all_2421_0_379 = 0)
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3106) yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3107) aNaturalNumber0(all_179_3_103) = all_2421_0_379
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3108) aNaturalNumber0(all_179_4_104) = all_2421_2_381
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3109) aNaturalNumber0(xp) = all_2421_1_380
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3110)  ~ (all_2421_1_380 = 0) |  ~ (all_2421_2_381 = 0) | all_2421_0_379 = 0
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2969) with all_2423_0_382, all_2423_1_383, all_2423_2_384, all_2423_3_385, all_2423_4_386 yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3111) sdtasdt0(all_186_2_128, xk) = all_2423_1_383 & sdtasdt0(xp, all_2423_1_383) = all_2423_0_382 & aNaturalNumber0(all_186_2_128) = all_2423_3_385 & aNaturalNumber0(xk) = all_2423_2_384 & aNaturalNumber0(xp) = all_2423_4_386 & ( ~ (all_2423_2_384 = 0) |  ~ (all_2423_3_385 = 0) |  ~ (all_2423_4_386 = 0) | all_2423_0_382 = all_0_3_3)
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3111) yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3112) aNaturalNumber0(all_186_2_128) = all_2423_3_385
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3113) aNaturalNumber0(xp) = all_2423_4_386
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3114) aNaturalNumber0(xk) = all_2423_2_384
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3115)  ~ (all_2423_2_384 = 0) |  ~ (all_2423_3_385 = 0) |  ~ (all_2423_4_386 = 0) | all_2423_0_382 = all_0_3_3
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3116) sdtasdt0(all_186_2_128, xk) = all_2423_1_383
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3117) sdtasdt0(xp, all_2423_1_383) = all_2423_0_382
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2970) with all_2425_0_387, all_2425_1_388, all_2425_2_389 yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3118) sdtpldt0(xp, all_179_4_104) = all_2425_0_387 & aNaturalNumber0(all_179_4_104) = all_2425_2_389 & aNaturalNumber0(xp) = all_2425_1_388 & ( ~ (all_2425_1_388 = 0) |  ~ (all_2425_2_389 = 0) | all_2425_0_387 = all_179_3_103)
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3118) yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3119) sdtpldt0(xp, all_179_4_104) = all_2425_0_387
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3120) aNaturalNumber0(all_179_4_104) = all_2425_2_389
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3121) aNaturalNumber0(xp) = all_2425_1_388
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3122)  ~ (all_2425_1_388 = 0) |  ~ (all_2425_2_389 = 0) | all_2425_0_387 = all_179_3_103
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating (2973) with all_2435_0_412, all_2435_1_413, all_2435_2_414, all_2435_3_415, all_2435_4_416 yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3123) doDivides0(xp, all_19_2_20) = all_2435_1_413 & doDivides0(xp, xm) = all_2435_0_412 & aNaturalNumber0(all_19_2_20) = all_2435_3_415 & aNaturalNumber0(xp) = all_2435_4_416 & aNaturalNumber0(xm) = all_2435_2_414 & ( ~ (all_2435_1_413 = 0) |  ~ (all_2435_2_414 = 0) |  ~ (all_2435_3_415 = 0) |  ~ (all_2435_4_416 = 0) | all_2435_0_412 = 0)
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Applying alpha-rule on (3123) yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3124) aNaturalNumber0(xm) = all_2435_2_414
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3125) doDivides0(xp, xm) = all_2435_0_412
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3126) aNaturalNumber0(all_19_2_20) = all_2435_3_415
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3127)  ~ (all_2435_1_413 = 0) |  ~ (all_2435_2_414 = 0) |  ~ (all_2435_3_415 = 0) |  ~ (all_2435_4_416 = 0) | all_2435_0_412 = 0
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3128) doDivides0(xp, all_19_2_20) = all_2435_1_413
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3129) aNaturalNumber0(xp) = all_2435_4_416
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xk, all_2408_8_344, all_2423_2_384 and discharging atoms aNaturalNumber0(xk) = all_2423_2_384, aNaturalNumber0(xk) = all_2408_8_344, yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3130) all_2423_2_384 = all_2408_8_344
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xk, all_2388_3_286, all_2408_8_344 and discharging atoms aNaturalNumber0(xk) = all_2408_8_344, aNaturalNumber0(xk) = all_2388_3_286, yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3131) all_2408_8_344 = all_2388_3_286
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xk, all_2364_2_221, all_2399_2_314 and discharging atoms aNaturalNumber0(xk) = all_2399_2_314, aNaturalNumber0(xk) = all_2364_2_221, yields:
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| (3132) all_2399_2_314 = all_2364_2_221
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.28  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xk, all_2364_2_221, all_2388_3_286 and discharging atoms aNaturalNumber0(xk) = all_2388_3_286, aNaturalNumber0(xk) = all_2364_2_221, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3133) all_2388_3_286 = all_2364_2_221
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xk, all_2360_2_213, all_2364_2_221 and discharging atoms aNaturalNumber0(xk) = all_2364_2_221, aNaturalNumber0(xk) = all_2360_2_213, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3134) all_2364_2_221 = all_2360_2_213
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xk, all_2358_1_209, all_2399_2_314 and discharging atoms aNaturalNumber0(xk) = all_2399_2_314, aNaturalNumber0(xk) = all_2358_1_209, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3135) all_2399_2_314 = all_2358_1_209
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xk, all_2356_1_206, 0 and discharging atoms aNaturalNumber0(xk) = all_2356_1_206, aNaturalNumber0(xk) = 0, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3136) all_2356_1_206 = 0
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xk, all_2356_1_206, all_2399_2_314 and discharging atoms aNaturalNumber0(xk) = all_2399_2_314, aNaturalNumber0(xk) = all_2356_1_206, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3137) all_2399_2_314 = all_2356_1_206
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xk, all_2352_2_199, all_2423_2_384 and discharging atoms aNaturalNumber0(xk) = all_2423_2_384, aNaturalNumber0(xk) = all_2352_2_199, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3138) all_2423_2_384 = all_2352_2_199
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2425_1_388, all_2435_4_416 and discharging atoms aNaturalNumber0(xp) = all_2435_4_416, aNaturalNumber0(xp) = all_2425_1_388, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3139) all_2435_4_416 = all_2425_1_388
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2423_4_386, all_2435_4_416 and discharging atoms aNaturalNumber0(xp) = all_2435_4_416, aNaturalNumber0(xp) = all_2423_4_386, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3140) all_2435_4_416 = all_2423_4_386
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2421_1_380, all_2423_4_386 and discharging atoms aNaturalNumber0(xp) = all_2423_4_386, aNaturalNumber0(xp) = all_2421_1_380, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3141) all_2423_4_386 = all_2421_1_380
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2410_2_347, all_2414_4_363 and discharging atoms aNaturalNumber0(xp) = all_2414_4_363, aNaturalNumber0(xp) = all_2410_2_347, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3142) all_2414_4_363 = all_2410_2_347
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2408_6_342, 0 and discharging atoms aNaturalNumber0(xp) = all_2408_6_342, aNaturalNumber0(xp) = 0, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3143) all_2408_6_342 = 0
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2408_7_343, all_2410_2_347 and discharging atoms aNaturalNumber0(xp) = all_2410_2_347, aNaturalNumber0(xp) = all_2408_7_343, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3144) all_2410_2_347 = all_2408_7_343
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2388_2_285, all_2408_6_342 and discharging atoms aNaturalNumber0(xp) = all_2408_6_342, aNaturalNumber0(xp) = all_2388_2_285, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3145) all_2408_6_342 = all_2388_2_285
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2388_4_287, all_2421_1_380 and discharging atoms aNaturalNumber0(xp) = all_2421_1_380, aNaturalNumber0(xp) = all_2388_4_287, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3146) all_2421_1_380 = all_2388_4_287
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2388_4_287, all_2408_7_343 and discharging atoms aNaturalNumber0(xp) = all_2408_7_343, aNaturalNumber0(xp) = all_2388_4_287, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3147) all_2408_7_343 = all_2388_4_287
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2384_6_277, all_2435_4_416 and discharging atoms aNaturalNumber0(xp) = all_2435_4_416, aNaturalNumber0(xp) = all_2384_6_277, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3148) all_2435_4_416 = all_2384_6_277
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2384_8_279, all_2388_2_285 and discharging atoms aNaturalNumber0(xp) = all_2388_2_285, aNaturalNumber0(xp) = all_2384_8_279, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3149) all_2388_2_285 = all_2384_8_279
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2382_8_270, all_2414_4_363 and discharging atoms aNaturalNumber0(xp) = all_2414_4_363, aNaturalNumber0(xp) = all_2382_8_270, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3150) all_2414_4_363 = all_2382_8_270
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2380_2_261, all_2384_8_279 and discharging atoms aNaturalNumber0(xp) = all_2384_8_279, aNaturalNumber0(xp) = all_2380_2_261, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3151) all_2384_8_279 = all_2380_2_261
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2378_3_257, all_2380_2_261 and discharging atoms aNaturalNumber0(xp) = all_2380_2_261, aNaturalNumber0(xp) = all_2378_3_257, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3152) all_2380_2_261 = all_2378_3_257
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2358_2_210, all_2378_3_257 and discharging atoms aNaturalNumber0(xp) = all_2378_3_257, aNaturalNumber0(xp) = all_2358_2_210, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3153) all_2378_3_257 = all_2358_2_210
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2358_2_210, all_2376_4_253 and discharging atoms aNaturalNumber0(xp) = all_2376_4_253, aNaturalNumber0(xp) = all_2358_2_210, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3154) all_2376_4_253 = all_2358_2_210
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2356_2_207, all_2376_4_253 and discharging atoms aNaturalNumber0(xp) = all_2376_4_253, aNaturalNumber0(xp) = all_2356_2_207, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3155) all_2376_4_253 = all_2356_2_207
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2336_1_172, all_2388_4_287 and discharging atoms aNaturalNumber0(xp) = all_2388_4_287, aNaturalNumber0(xp) = all_2336_1_172, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3156) all_2388_4_287 = all_2336_1_172
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2336_1_172, all_2376_4_253 and discharging atoms aNaturalNumber0(xp) = all_2376_4_253, aNaturalNumber0(xp) = all_2336_1_172, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3157) all_2376_4_253 = all_2336_1_172
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Instantiating formula (46) with xp, all_2334_1_169, all_2388_4_287 and discharging atoms aNaturalNumber0(xp) = all_2388_4_287, aNaturalNumber0(xp) = all_2334_1_169, yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3158) all_2388_4_287 = all_2334_1_169
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3148,3139) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3159) all_2425_1_388 = all_2384_6_277
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3140,3139) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3160) all_2425_1_388 = all_2423_4_386
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3160,3159) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3161) all_2423_4_386 = all_2384_6_277
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3161 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3162) all_2423_4_386 = all_2384_6_277
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3130,3138) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3163) all_2408_8_344 = all_2352_2_199
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3163 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3164) all_2408_8_344 = all_2352_2_199
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3141,3162) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3165) all_2421_1_380 = all_2384_6_277
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3165 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3166) all_2421_1_380 = all_2384_6_277
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3146,3166) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3167) all_2388_4_287 = all_2384_6_277
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3167 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3168) all_2388_4_287 = all_2384_6_277
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3142,3150) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3169) all_2410_2_347 = all_2382_8_270
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3169 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3170) all_2410_2_347 = all_2382_8_270
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3144,3170) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3171) all_2408_7_343 = all_2382_8_270
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3171 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3172) all_2408_7_343 = all_2382_8_270
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3145,3143) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3173) all_2388_2_285 = 0
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3173 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3174) all_2388_2_285 = 0
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3147,3172) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3175) all_2388_4_287 = all_2382_8_270
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3175 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3176) all_2388_4_287 = all_2382_8_270
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3131,3164) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3177) all_2388_3_286 = all_2352_2_199
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3177 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3178) all_2388_3_286 = all_2352_2_199
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3137,3135) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3179) all_2358_1_209 = all_2356_1_206
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3132,3135) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3180) all_2364_2_221 = all_2358_1_209
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3180 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3181) all_2364_2_221 = all_2358_1_209
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3149,3174) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3182) all_2384_8_279 = 0
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3182 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3183) all_2384_8_279 = 0
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3133,3178) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3184) all_2364_2_221 = all_2352_2_199
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3184 yields:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3185) all_2364_2_221 = all_2352_2_199
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3158,3168) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3186) all_2384_6_277 = all_2334_1_169
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3156,3168) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3187) all_2384_6_277 = all_2336_1_172
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3176,3168) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3188) all_2384_6_277 = all_2382_8_270
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3186,3188) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3189) all_2382_8_270 = all_2334_1_169
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3187,3188) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3190) all_2382_8_270 = all_2336_1_172
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3151,3183) yields a new equation:
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		| (3191) all_2380_2_261 = 0
% 67.71/29.29  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3191 yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3192) all_2380_2_261 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3190,3189) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3193) all_2336_1_172 = all_2334_1_169
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3193 yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3194) all_2336_1_172 = all_2334_1_169
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3152,3192) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3195) all_2378_3_257 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3195 yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3196) all_2378_3_257 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3153,3196) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3197) all_2358_2_210 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3197 yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3198) all_2358_2_210 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3157,3155) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3199) all_2356_2_207 = all_2336_1_172
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3154,3155) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3200) all_2358_2_210 = all_2356_2_207
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3200 yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3201) all_2358_2_210 = all_2356_2_207
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3181,3134) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3202) all_2360_2_213 = all_2358_1_209
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3185,3134) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3203) all_2360_2_213 = all_2352_2_199
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3202,3203) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3204) all_2358_1_209 = all_2352_2_199
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3204 yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3205) all_2358_1_209 = all_2352_2_199
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3179,3205) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3206) all_2356_1_206 = all_2352_2_199
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3206 yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3207) all_2356_1_206 = all_2352_2_199
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3201,3198) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3208) all_2356_2_207 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3208 yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3209) all_2356_2_207 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3136,3207) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3210) all_2352_2_199 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3199,3209) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3211) all_2336_1_172 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3211 yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3212) all_2336_1_172 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Combining equations (3194,3212) yields a new equation:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3213) all_2334_1_169 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| Simplifying 3213 yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3214) all_2334_1_169 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| From (3210) and (2997) follows:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (972) aNaturalNumber0(xk) = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| From (3214) and (2987) follows:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (12) aNaturalNumber0(xp) = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		+-Applying beta-rule and splitting (2982), into two cases.
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|-Branch one:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3217) xp = xm
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| Equations (3217) can reduce 80 to:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| (159) $false
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			|-The branch is then unsatisfiable
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|-Branch two:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (80)  ~ (xp = xm)
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		| (3220)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : (sdtpldt0(xp, xn) = v4 & sdtpldt0(xm, xn) = v3 & aNaturalNumber0(xp) = v2 & aNaturalNumber0(xm) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0) | ( ~ (v4 = v3) &  ~ (all_161_1_68 = all_0_5_5))))
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																		|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| Instantiating (3220) with all_2473_0_452, all_2473_1_453, all_2473_2_454, all_2473_3_455, all_2473_4_456 yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| (3221) sdtpldt0(xp, xn) = all_2473_0_452 & sdtpldt0(xm, xn) = all_2473_1_453 & aNaturalNumber0(xp) = all_2473_2_454 & aNaturalNumber0(xm) = all_2473_3_455 & aNaturalNumber0(xn) = all_2473_4_456 & ( ~ (all_2473_2_454 = 0) |  ~ (all_2473_3_455 = 0) |  ~ (all_2473_4_456 = 0) | ( ~ (all_2473_0_452 = all_2473_1_453) &  ~ (all_161_1_68 = all_0_5_5)))
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| Applying alpha-rule on (3221) yields:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| (3222) aNaturalNumber0(xp) = all_2473_2_454
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| (3223) sdtpldt0(xm, xn) = all_2473_1_453
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| (3224)  ~ (all_2473_2_454 = 0) |  ~ (all_2473_3_455 = 0) |  ~ (all_2473_4_456 = 0) | ( ~ (all_2473_0_452 = all_2473_1_453) &  ~ (all_161_1_68 = all_0_5_5))
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| (3225) sdtpldt0(xp, xn) = all_2473_0_452
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| (3226) aNaturalNumber0(xn) = all_2473_4_456
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| (3227) aNaturalNumber0(xm) = all_2473_3_455
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			|
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			+-Applying beta-rule and splitting (2963), into two cases.
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			|-Branch one:
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			| (3228) all_36_0_50 = 0
% 67.71/29.30  																																																																																																																																																																																																																																																																																																																																			|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				| Equations (3228) can reduce 1051 to:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				| (159) $false
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				|-The branch is then unsatisfiable
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																			|-Branch two:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																			| (1051)  ~ (all_36_0_50 = 0)
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																			| (3231)  ? [v0] :  ? [v1] : (( ~ (v0 = 0) & aNaturalNumber0(xp) = v0) | (aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xk) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0))))
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																			|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				| Instantiating (3231) with all_2495_0_457, all_2495_1_458 yields:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				| (3232) ( ~ (all_2495_1_458 = 0) & aNaturalNumber0(xp) = all_2495_1_458) | (aNaturalNumber0(all_0_3_3) = all_2495_0_457 & aNaturalNumber0(xk) = all_2495_1_458 & ( ~ (all_2495_0_457 = 0) |  ~ (all_2495_1_458 = 0)))
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				+-Applying beta-rule and splitting (2961), into two cases.
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				|-Branch one:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				| (168) xk = sz00
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| Equations (168) can reduce 13 to:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (159) $false
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|-The branch is then unsatisfiable
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				|-Branch two:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				| (13)  ~ (xk = sz00)
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				| (3236)  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(all_386_0_142, xk) = v2 & aNaturalNumber0(all_386_0_142) = v0 & aNaturalNumber0(xk) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																				|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| Instantiating (3236) with all_2542_0_462, all_2542_1_463, all_2542_2_464 yields:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (3237) sdtlseqdt0(all_386_0_142, xk) = all_2542_0_462 & aNaturalNumber0(all_386_0_142) = all_2542_2_464 & aNaturalNumber0(xk) = all_2542_1_463 & ( ~ (all_2542_1_463 = 0) |  ~ (all_2542_2_464 = 0) | all_2542_0_462 = 0)
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| Applying alpha-rule on (3237) yields:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (3238) sdtlseqdt0(all_386_0_142, xk) = all_2542_0_462
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (3239) aNaturalNumber0(all_386_0_142) = all_2542_2_464
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (3240) aNaturalNumber0(xk) = all_2542_1_463
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (3241)  ~ (all_2542_1_463 = 0) |  ~ (all_2542_2_464 = 0) | all_2542_0_462 = 0
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| Instantiating formula (46) with xk, all_2542_1_463, 0 and discharging atoms aNaturalNumber0(xk) = all_2542_1_463, aNaturalNumber0(xk) = 0, yields:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (3242) all_2542_1_463 = 0
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| Instantiating formula (46) with xp, all_2473_2_454, 0 and discharging atoms aNaturalNumber0(xp) = all_2473_2_454, aNaturalNumber0(xp) = 0, yields:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (3243) all_2473_2_454 = 0
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| From (3242) and (3240) follows:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (972) aNaturalNumber0(xk) = 0
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| From (3243) and (3222) follows:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (12) aNaturalNumber0(xp) = 0
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					+-Applying beta-rule and splitting (2960), into two cases.
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|-Branch one:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (168) xk = sz00
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																						| Equations (168) can reduce 13 to:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																						| (159) $false
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																						|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																						|-The branch is then unsatisfiable
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|-Branch two:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (13)  ~ (xk = sz00)
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					| (3249)  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(all_432_0_148, xk) = v2 & aNaturalNumber0(all_432_0_148) = v0 & aNaturalNumber0(xk) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																					|
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																						| Instantiating (3249) with all_2924_0_473, all_2924_1_474, all_2924_2_475 yields:
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																						| (3250) sdtlseqdt0(all_432_0_148, xk) = all_2924_0_473 & aNaturalNumber0(all_432_0_148) = all_2924_2_475 & aNaturalNumber0(xk) = all_2924_1_474 & ( ~ (all_2924_1_474 = 0) |  ~ (all_2924_2_475 = 0) | all_2924_0_473 = 0)
% 67.80/29.30  																																																																																																																																																																																																																																																																																																																																						|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						| Applying alpha-rule on (3250) yields:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						| (3251) sdtlseqdt0(all_432_0_148, xk) = all_2924_0_473
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						| (3252) aNaturalNumber0(all_432_0_148) = all_2924_2_475
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						| (3253) aNaturalNumber0(xk) = all_2924_1_474
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						| (3254)  ~ (all_2924_1_474 = 0) |  ~ (all_2924_2_475 = 0) | all_2924_0_473 = 0
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						+-Applying beta-rule and splitting (3232), into two cases.
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						|-Branch one:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						| (3255)  ~ (all_2495_1_458 = 0) & aNaturalNumber0(xp) = all_2495_1_458
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| Applying alpha-rule on (3255) yields:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3256)  ~ (all_2495_1_458 = 0)
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3257) aNaturalNumber0(xp) = all_2495_1_458
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| Instantiating formula (46) with xp, all_2495_1_458, 0 and discharging atoms aNaturalNumber0(xp) = all_2495_1_458, aNaturalNumber0(xp) = 0, yields:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3258) all_2495_1_458 = 0
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| Equations (3258) can reduce 3256 to:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (159) $false
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|-The branch is then unsatisfiable
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						|-Branch two:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						| (3260) aNaturalNumber0(all_0_3_3) = all_2495_0_457 & aNaturalNumber0(xk) = all_2495_1_458 & ( ~ (all_2495_0_457 = 0) |  ~ (all_2495_1_458 = 0))
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																						|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| Applying alpha-rule on (3260) yields:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3261) aNaturalNumber0(all_0_3_3) = all_2495_0_457
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3262) aNaturalNumber0(xk) = all_2495_1_458
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3263)  ~ (all_2495_0_457 = 0) |  ~ (all_2495_1_458 = 0)
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| Instantiating formula (46) with all_0_3_3, all_2495_0_457, 0 and discharging atoms aNaturalNumber0(all_0_3_3) = all_2495_0_457, aNaturalNumber0(all_0_3_3) = 0, yields:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3264) all_2495_0_457 = 0
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| Instantiating formula (46) with xk, all_2924_1_474, 0 and discharging atoms aNaturalNumber0(xk) = all_2924_1_474, aNaturalNumber0(xk) = 0, yields:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3265) all_2924_1_474 = 0
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| Instantiating formula (46) with xk, all_2495_1_458, all_2924_1_474 and discharging atoms aNaturalNumber0(xk) = all_2924_1_474, aNaturalNumber0(xk) = all_2495_1_458, yields:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3266) all_2924_1_474 = all_2495_1_458
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| Combining equations (3266,3265) yields a new equation:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3267) all_2495_1_458 = 0
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| Simplifying 3267 yields:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3258) all_2495_1_458 = 0
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							+-Applying beta-rule and splitting (3263), into two cases.
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|-Branch one:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3269)  ~ (all_2495_0_457 = 0)
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																								| Equations (3264) can reduce 3269 to:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																								| (159) $false
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																								|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|-Branch two:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3264) all_2495_0_457 = 0
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							| (3256)  ~ (all_2495_1_458 = 0)
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																							|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																								| Equations (3258) can reduce 3256 to:
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																								| (159) $false
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																								|
% 67.80/29.31  																																																																																																																																																																																																																																																																																																																																								|-The branch is then unsatisfiable
% 67.80/29.32  																																																																					|-Branch two:
% 67.80/29.32  																																																																					| (3274) doDivides0(xp, xm) = 0
% 67.80/29.33  																																																																					| (3275) xm = sz00 |  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(xp, xm) = v2 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xm) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.80/29.33  																																																																					|
% 67.80/29.33  																																																																						+-Applying beta-rule and splitting (3275), into two cases.
% 67.80/29.33  																																																																						|-Branch one:
% 67.80/29.33  																																																																						| (3276) xm = sz00
% 67.80/29.33  																																																																						|
% 67.80/29.33  																																																																							| Equations (3276) can reduce 1102 to:
% 67.80/29.33  																																																																							| (159) $false
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							|-The branch is then unsatisfiable
% 67.80/29.33  																																																																						|-Branch two:
% 67.80/29.33  																																																																						| (1102)  ~ (xm = sz00)
% 67.80/29.33  																																																																						| (3279)  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(xp, xm) = v2 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xm) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.80/29.33  																																																																						|
% 67.80/29.33  																																																																							| Instantiating (3279) with all_542_0_479, all_542_1_480, all_542_2_481 yields:
% 67.80/29.33  																																																																							| (3280) sdtlseqdt0(xp, xm) = all_542_0_479 & aNaturalNumber0(xp) = all_542_2_481 & aNaturalNumber0(xm) = all_542_1_480 & ( ~ (all_542_1_480 = 0) |  ~ (all_542_2_481 = 0) | all_542_0_479 = 0)
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							| Applying alpha-rule on (3280) yields:
% 67.80/29.33  																																																																							| (3281) sdtlseqdt0(xp, xm) = all_542_0_479
% 67.80/29.33  																																																																							| (3282) aNaturalNumber0(xp) = all_542_2_481
% 67.80/29.33  																																																																							| (3283) aNaturalNumber0(xm) = all_542_1_480
% 67.80/29.33  																																																																							| (3284)  ~ (all_542_1_480 = 0) |  ~ (all_542_2_481 = 0) | all_542_0_479 = 0
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							| Instantiating formula (17) with xp, xm, all_542_0_479, all_0_1_1 and discharging atoms sdtlseqdt0(xp, xm) = all_542_0_479, sdtlseqdt0(xp, xm) = all_0_1_1, yields:
% 67.80/29.33  																																																																							| (3285) all_542_0_479 = all_0_1_1
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							| Instantiating formula (46) with xp, all_542_2_481, 0 and discharging atoms aNaturalNumber0(xp) = all_542_2_481, aNaturalNumber0(xp) = 0, yields:
% 67.80/29.33  																																																																							| (3286) all_542_2_481 = 0
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							| Instantiating formula (46) with xm, all_542_1_480, 0 and discharging atoms aNaturalNumber0(xm) = all_542_1_480, aNaturalNumber0(xm) = 0, yields:
% 67.80/29.33  																																																																							| (3287) all_542_1_480 = 0
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							+-Applying beta-rule and splitting (3284), into two cases.
% 67.80/29.33  																																																																							|-Branch one:
% 67.80/29.33  																																																																							| (3288)  ~ (all_542_1_480 = 0)
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																								| Equations (3287) can reduce 3288 to:
% 67.80/29.33  																																																																								| (159) $false
% 67.80/29.33  																																																																								|
% 67.80/29.33  																																																																								|-The branch is then unsatisfiable
% 67.80/29.33  																																																																							|-Branch two:
% 67.80/29.33  																																																																							| (3287) all_542_1_480 = 0
% 67.80/29.33  																																																																							| (3291)  ~ (all_542_2_481 = 0) | all_542_0_479 = 0
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																								+-Applying beta-rule and splitting (3291), into two cases.
% 67.80/29.33  																																																																								|-Branch one:
% 67.80/29.33  																																																																								| (3292)  ~ (all_542_2_481 = 0)
% 67.80/29.33  																																																																								|
% 67.80/29.33  																																																																									| Equations (3286) can reduce 3292 to:
% 67.80/29.33  																																																																									| (159) $false
% 67.80/29.33  																																																																									|
% 67.80/29.33  																																																																									|-The branch is then unsatisfiable
% 67.80/29.33  																																																																								|-Branch two:
% 67.80/29.33  																																																																								| (3286) all_542_2_481 = 0
% 67.80/29.33  																																																																								| (3295) all_542_0_479 = 0
% 67.80/29.33  																																																																								|
% 67.80/29.33  																																																																									| Combining equations (3295,3285) yields a new equation:
% 67.80/29.33  																																																																									| (3296) all_0_1_1 = 0
% 67.80/29.33  																																																																									|
% 67.80/29.33  																																																																									| Equations (3296) can reduce 23 to:
% 67.80/29.33  																																																																									| (159) $false
% 67.80/29.33  																																																																									|
% 67.80/29.33  																																																																									|-The branch is then unsatisfiable
% 67.80/29.33  																																																																				|-Branch two:
% 67.80/29.33  																																																																				| (3298) doDivides0(xp, xn) = 0
% 67.80/29.33  																																																																				| (3299) xn = sz00 |  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(xp, xn) = v2 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xn) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.80/29.33  																																																																				|
% 67.80/29.33  																																																																					+-Applying beta-rule and splitting (105), into two cases.
% 67.80/29.33  																																																																					|-Branch one:
% 67.80/29.33  																																																																					| (3300) xn = sz00
% 67.80/29.33  																																																																					|
% 67.80/29.33  																																																																						| Equations (3300) can reduce 1101 to:
% 67.80/29.33  																																																																						| (159) $false
% 67.80/29.33  																																																																						|
% 67.80/29.33  																																																																						|-The branch is then unsatisfiable
% 67.80/29.33  																																																																					|-Branch two:
% 67.80/29.33  																																																																					| (1101)  ~ (xn = sz00)
% 67.80/29.33  																																																																					| (3303) xn = sz10 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xn) = 0 & aNaturalNumber0(v0) = 0)
% 67.80/29.33  																																																																					|
% 67.80/29.33  																																																																						+-Applying beta-rule and splitting (3299), into two cases.
% 67.80/29.33  																																																																						|-Branch one:
% 67.80/29.33  																																																																						| (3300) xn = sz00
% 67.80/29.33  																																																																						|
% 67.80/29.33  																																																																							| Equations (3300) can reduce 1101 to:
% 67.80/29.33  																																																																							| (159) $false
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							|-The branch is then unsatisfiable
% 67.80/29.33  																																																																						|-Branch two:
% 67.80/29.33  																																																																						| (1101)  ~ (xn = sz00)
% 67.80/29.33  																																																																						| (3307)  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(xp, xn) = v2 & aNaturalNumber0(xp) = v0 & aNaturalNumber0(xn) = v1 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.80/29.33  																																																																						|
% 67.80/29.33  																																																																							| Instantiating (3307) with all_538_0_487, all_538_1_488, all_538_2_489 yields:
% 67.80/29.33  																																																																							| (3308) sdtlseqdt0(xp, xn) = all_538_0_487 & aNaturalNumber0(xp) = all_538_2_489 & aNaturalNumber0(xn) = all_538_1_488 & ( ~ (all_538_1_488 = 0) |  ~ (all_538_2_489 = 0) | all_538_0_487 = 0)
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							| Applying alpha-rule on (3308) yields:
% 67.80/29.33  																																																																							| (3309) sdtlseqdt0(xp, xn) = all_538_0_487
% 67.80/29.33  																																																																							| (3310) aNaturalNumber0(xp) = all_538_2_489
% 67.80/29.33  																																																																							| (3311) aNaturalNumber0(xn) = all_538_1_488
% 67.80/29.33  																																																																							| (3312)  ~ (all_538_1_488 = 0) |  ~ (all_538_2_489 = 0) | all_538_0_487 = 0
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							| Instantiating formula (17) with xp, xn, all_538_0_487, all_0_2_2 and discharging atoms sdtlseqdt0(xp, xn) = all_538_0_487, sdtlseqdt0(xp, xn) = all_0_2_2, yields:
% 67.80/29.33  																																																																							| (3313) all_538_0_487 = all_0_2_2
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							| Instantiating formula (46) with xp, all_538_2_489, 0 and discharging atoms aNaturalNumber0(xp) = all_538_2_489, aNaturalNumber0(xp) = 0, yields:
% 67.80/29.33  																																																																							| (3314) all_538_2_489 = 0
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							| Instantiating formula (46) with xn, all_538_1_488, 0 and discharging atoms aNaturalNumber0(xn) = all_538_1_488, aNaturalNumber0(xn) = 0, yields:
% 67.80/29.33  																																																																							| (3315) all_538_1_488 = 0
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																							+-Applying beta-rule and splitting (3312), into two cases.
% 67.80/29.33  																																																																							|-Branch one:
% 67.80/29.33  																																																																							| (3316)  ~ (all_538_1_488 = 0)
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																								| Equations (3315) can reduce 3316 to:
% 67.80/29.33  																																																																								| (159) $false
% 67.80/29.33  																																																																								|
% 67.80/29.33  																																																																								|-The branch is then unsatisfiable
% 67.80/29.33  																																																																							|-Branch two:
% 67.80/29.33  																																																																							| (3315) all_538_1_488 = 0
% 67.80/29.33  																																																																							| (3319)  ~ (all_538_2_489 = 0) | all_538_0_487 = 0
% 67.80/29.33  																																																																							|
% 67.80/29.33  																																																																								+-Applying beta-rule and splitting (3319), into two cases.
% 67.80/29.33  																																																																								|-Branch one:
% 67.80/29.33  																																																																								| (3320)  ~ (all_538_2_489 = 0)
% 67.80/29.33  																																																																								|
% 67.80/29.33  																																																																									| Equations (3314) can reduce 3320 to:
% 67.80/29.33  																																																																									| (159) $false
% 67.80/29.33  																																																																									|
% 67.80/29.33  																																																																									|-The branch is then unsatisfiable
% 67.80/29.33  																																																																								|-Branch two:
% 67.80/29.33  																																																																								| (3314) all_538_2_489 = 0
% 67.80/29.33  																																																																								| (3323) all_538_0_487 = 0
% 67.80/29.33  																																																																								|
% 67.80/29.33  																																																																									| Combining equations (3323,3313) yields a new equation:
% 67.80/29.33  																																																																									| (3324) all_0_2_2 = 0
% 67.80/29.33  																																																																									|
% 67.80/29.33  																																																																									| Equations (3324) can reduce 39 to:
% 67.80/29.33  																																																																									| (159) $false
% 67.80/29.33  																																																																									|
% 67.80/29.33  																																																																									|-The branch is then unsatisfiable
% 67.80/29.33  																																																																			|-Branch two:
% 67.80/29.33  																																																																			| (3326) sdtasdt0(sz00, xn) = all_0_3_3
% 67.80/29.33  																																																																			| (3327)  ? [v0] :  ? [v1] : (sdtasdt0(xn, sz00) = v1 & aNaturalNumber0(xn) = v0 & ( ~ (v0 = 0) | (v1 = sz00 & all_0_3_3 = sz00)))
% 67.80/29.33  																																																																			|
% 67.80/29.33  																																																																				| Instantiating (3327) with all_523_0_495, all_523_1_496 yields:
% 67.80/29.33  																																																																				| (3328) sdtasdt0(xn, sz00) = all_523_0_495 & aNaturalNumber0(xn) = all_523_1_496 & ( ~ (all_523_1_496 = 0) | (all_523_0_495 = sz00 & all_0_3_3 = sz00))
% 67.80/29.33  																																																																				|
% 67.80/29.33  																																																																				| Applying alpha-rule on (3328) yields:
% 67.80/29.33  																																																																				| (3329) sdtasdt0(xn, sz00) = all_523_0_495
% 67.80/29.33  																																																																				| (3330) aNaturalNumber0(xn) = all_523_1_496
% 67.80/29.33  																																																																				| (3331)  ~ (all_523_1_496 = 0) | (all_523_0_495 = sz00 & all_0_3_3 = sz00)
% 67.80/29.33  																																																																				|
% 67.80/29.33  																																																																				+-Applying beta-rule and splitting (3331), into two cases.
% 67.80/29.33  																																																																				|-Branch one:
% 67.80/29.33  																																																																				| (3332)  ~ (all_523_1_496 = 0)
% 67.80/29.33  																																																																				|
% 67.80/29.33  																																																																					| Instantiating formula (46) with xn, all_523_1_496, 0 and discharging atoms aNaturalNumber0(xn) = all_523_1_496, aNaturalNumber0(xn) = 0, yields:
% 67.80/29.33  																																																																					| (3333) all_523_1_496 = 0
% 67.80/29.33  																																																																					|
% 67.80/29.33  																																																																					| Equations (3333) can reduce 3332 to:
% 67.80/29.33  																																																																					| (159) $false
% 67.80/29.33  																																																																					|
% 67.80/29.33  																																																																					|-The branch is then unsatisfiable
% 67.80/29.33  																																																																				|-Branch two:
% 67.80/29.33  																																																																				| (3333) all_523_1_496 = 0
% 67.80/29.33  																																																																				| (3336) all_523_0_495 = sz00 & all_0_3_3 = sz00
% 67.80/29.33  																																																																				|
% 67.80/29.33  																																																																					| Applying alpha-rule on (3336) yields:
% 67.80/29.33  																																																																					| (3337) all_523_0_495 = sz00
% 67.80/29.33  																																																																					| (1089) all_0_3_3 = sz00
% 67.80/29.33  																																																																					|
% 67.80/29.34  																																																																					| Equations (1089) can reduce 1087 to:
% 67.80/29.34  																																																																					| (159) $false
% 67.80/29.34  																																																																					|
% 67.80/29.34  																																																																					|-The branch is then unsatisfiable
% 67.80/29.34  																																																																	|-Branch two:
% 67.80/29.34  																																																																	| (3340) sdtasdt0(sz00, xm) = all_0_3_3
% 67.80/29.34  																																																																	| (3341)  ? [v0] :  ? [v1] : (sdtasdt0(xm, sz00) = v1 & aNaturalNumber0(xm) = v0 & ( ~ (v0 = 0) | (v1 = sz00 & all_0_3_3 = sz00)))
% 67.80/29.34  																																																																	|
% 67.80/29.34  																																																																		| Instantiating (3341) with all_509_0_497, all_509_1_498 yields:
% 67.80/29.34  																																																																		| (3342) sdtasdt0(xm, sz00) = all_509_0_497 & aNaturalNumber0(xm) = all_509_1_498 & ( ~ (all_509_1_498 = 0) | (all_509_0_497 = sz00 & all_0_3_3 = sz00))
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																		| Applying alpha-rule on (3342) yields:
% 67.80/29.34  																																																																		| (3343) sdtasdt0(xm, sz00) = all_509_0_497
% 67.80/29.34  																																																																		| (3344) aNaturalNumber0(xm) = all_509_1_498
% 67.80/29.34  																																																																		| (3345)  ~ (all_509_1_498 = 0) | (all_509_0_497 = sz00 & all_0_3_3 = sz00)
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																		+-Applying beta-rule and splitting (90), into two cases.
% 67.80/29.34  																																																																		|-Branch one:
% 67.80/29.34  																																																																		| (1089) all_0_3_3 = sz00
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																			| Equations (1089) can reduce 1087 to:
% 67.80/29.34  																																																																			| (159) $false
% 67.80/29.34  																																																																			|
% 67.80/29.34  																																																																			|-The branch is then unsatisfiable
% 67.80/29.34  																																																																		|-Branch two:
% 67.80/29.34  																																																																		| (1087)  ~ (all_0_3_3 = sz00)
% 67.80/29.34  																																																																		| (1092)  ? [v0] :  ? [v1] :  ? [v2] : (sdtlseqdt0(xp, all_0_3_3) = v2 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0) | v2 = 0))
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																			+-Applying beta-rule and splitting (3345), into two cases.
% 67.80/29.34  																																																																			|-Branch one:
% 67.80/29.34  																																																																			| (3350)  ~ (all_509_1_498 = 0)
% 67.80/29.34  																																																																			|
% 67.80/29.34  																																																																				| Instantiating formula (46) with xm, all_509_1_498, 0 and discharging atoms aNaturalNumber0(xm) = all_509_1_498, aNaturalNumber0(xm) = 0, yields:
% 67.80/29.34  																																																																				| (3351) all_509_1_498 = 0
% 67.80/29.34  																																																																				|
% 67.80/29.34  																																																																				| Equations (3351) can reduce 3350 to:
% 67.80/29.34  																																																																				| (159) $false
% 67.80/29.34  																																																																				|
% 67.80/29.34  																																																																				|-The branch is then unsatisfiable
% 67.80/29.34  																																																																			|-Branch two:
% 67.80/29.34  																																																																			| (3351) all_509_1_498 = 0
% 67.80/29.34  																																																																			| (3354) all_509_0_497 = sz00 & all_0_3_3 = sz00
% 67.80/29.34  																																																																			|
% 67.80/29.34  																																																																				| Applying alpha-rule on (3354) yields:
% 67.80/29.34  																																																																				| (3355) all_509_0_497 = sz00
% 67.80/29.34  																																																																				| (1089) all_0_3_3 = sz00
% 67.80/29.34  																																																																				|
% 67.80/29.34  																																																																				| Equations (1089) can reduce 1087 to:
% 67.80/29.34  																																																																				| (159) $false
% 67.80/29.34  																																																																				|
% 67.80/29.34  																																																																				|-The branch is then unsatisfiable
% 67.80/29.34  																																																																|-Branch two:
% 67.80/29.34  																																																																| (3358) doDivides0(xp, all_0_3_3) = all_456_0_152 & aNaturalNumber0(all_0_3_3) = all_456_1_153 & aNaturalNumber0(xp) = all_456_2_154 & ( ~ (all_456_0_152 = 0) |  ~ (all_456_1_153 = 0) |  ~ (all_456_2_154 = 0))
% 67.80/29.34  																																																																|
% 67.80/29.34  																																																																	| Applying alpha-rule on (3358) yields:
% 67.80/29.34  																																																																	| (3359) doDivides0(xp, all_0_3_3) = all_456_0_152
% 67.80/29.34  																																																																	| (3360) aNaturalNumber0(all_0_3_3) = all_456_1_153
% 67.80/29.34  																																																																	| (3361) aNaturalNumber0(xp) = all_456_2_154
% 67.80/29.34  																																																																	| (3362)  ~ (all_456_0_152 = 0) |  ~ (all_456_1_153 = 0) |  ~ (all_456_2_154 = 0)
% 67.80/29.34  																																																																	|
% 67.80/29.34  																																																																	| Instantiating formula (32) with xp, all_0_3_3, all_456_0_152, 0 and discharging atoms doDivides0(xp, all_0_3_3) = all_456_0_152, doDivides0(xp, all_0_3_3) = 0, yields:
% 67.80/29.34  																																																																	| (3363) all_456_0_152 = 0
% 67.80/29.34  																																																																	|
% 67.80/29.34  																																																																	| Instantiating formula (46) with all_0_3_3, all_456_1_153, 0 and discharging atoms aNaturalNumber0(all_0_3_3) = all_456_1_153, aNaturalNumber0(all_0_3_3) = 0, yields:
% 67.80/29.34  																																																																	| (3364) all_456_1_153 = 0
% 67.80/29.34  																																																																	|
% 67.80/29.34  																																																																	| Instantiating formula (46) with xp, all_456_2_154, 0 and discharging atoms aNaturalNumber0(xp) = all_456_2_154, aNaturalNumber0(xp) = 0, yields:
% 67.80/29.34  																																																																	| (1085) all_456_2_154 = 0
% 67.80/29.34  																																																																	|
% 67.80/29.34  																																																																	+-Applying beta-rule and splitting (3362), into two cases.
% 67.80/29.34  																																																																	|-Branch one:
% 67.80/29.34  																																																																	| (3366)  ~ (all_456_0_152 = 0)
% 67.80/29.34  																																																																	|
% 67.80/29.34  																																																																		| Equations (3363) can reduce 3366 to:
% 67.80/29.34  																																																																		| (159) $false
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																		|-The branch is then unsatisfiable
% 67.80/29.34  																																																																	|-Branch two:
% 67.80/29.34  																																																																	| (3363) all_456_0_152 = 0
% 67.80/29.34  																																																																	| (3369)  ~ (all_456_1_153 = 0) |  ~ (all_456_2_154 = 0)
% 67.80/29.34  																																																																	|
% 67.80/29.34  																																																																		+-Applying beta-rule and splitting (3369), into two cases.
% 67.80/29.34  																																																																		|-Branch one:
% 67.80/29.34  																																																																		| (3370)  ~ (all_456_1_153 = 0)
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																			| Equations (3364) can reduce 3370 to:
% 67.80/29.34  																																																																			| (159) $false
% 67.80/29.34  																																																																			|
% 67.80/29.34  																																																																			|-The branch is then unsatisfiable
% 67.80/29.34  																																																																		|-Branch two:
% 67.80/29.34  																																																																		| (3364) all_456_1_153 = 0
% 67.80/29.34  																																																																		| (3373)  ~ (all_456_2_154 = 0)
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																			| Equations (1085) can reduce 3373 to:
% 67.80/29.34  																																																																			| (159) $false
% 67.80/29.34  																																																																			|
% 67.80/29.34  																																																																			|-The branch is then unsatisfiable
% 67.80/29.34  																																																															|-Branch two:
% 67.80/29.34  																																																															| (3375) sdtasdt0(xp, all_20_2_23) = sz00
% 67.80/29.34  																																																															| (3376) all_20_2_23 = sz00 | xp = sz00 |  ? [v0] :  ? [v1] : (aNaturalNumber0(all_20_2_23) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0)))
% 67.80/29.34  																																																															|
% 67.80/29.34  																																																																+-Applying beta-rule and splitting (3376), into two cases.
% 67.80/29.34  																																																																|-Branch one:
% 67.80/29.34  																																																																| (982) all_20_2_23 = sz00
% 67.80/29.34  																																																																|
% 67.80/29.34  																																																																	| Combining equations (982,968) yields a new equation:
% 67.80/29.34  																																																																	| (168) xk = sz00
% 67.80/29.34  																																																																	|
% 67.80/29.34  																																																																	| Equations (168) can reduce 13 to:
% 67.80/29.34  																																																																	| (159) $false
% 67.80/29.34  																																																																	|
% 67.80/29.34  																																																																	|-The branch is then unsatisfiable
% 67.80/29.34  																																																																|-Branch two:
% 67.80/29.34  																																																																| (985)  ~ (all_20_2_23 = sz00)
% 67.80/29.34  																																																																| (3381) xp = sz00 |  ? [v0] :  ? [v1] : (aNaturalNumber0(all_20_2_23) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0)))
% 67.80/29.34  																																																																|
% 67.80/29.34  																																																																	+-Applying beta-rule and splitting (3381), into two cases.
% 67.80/29.34  																																																																	|-Branch one:
% 67.80/29.34  																																																																	| (181) xp = sz00
% 67.80/29.34  																																																																	|
% 67.80/29.34  																																																																		| Equations (181) can reduce 86 to:
% 67.80/29.34  																																																																		| (159) $false
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																		|-The branch is then unsatisfiable
% 67.80/29.34  																																																																	|-Branch two:
% 67.80/29.34  																																																																	| (86)  ~ (xp = sz00)
% 67.80/29.34  																																																																	| (3385)  ? [v0] :  ? [v1] : (aNaturalNumber0(all_20_2_23) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v1 = 0) |  ~ (v0 = 0)))
% 67.80/29.34  																																																																	|
% 67.80/29.34  																																																																		| Instantiating (3385) with all_489_0_505, all_489_1_506 yields:
% 67.80/29.34  																																																																		| (3386) aNaturalNumber0(all_20_2_23) = all_489_0_505 & aNaturalNumber0(xp) = all_489_1_506 & ( ~ (all_489_0_505 = 0) |  ~ (all_489_1_506 = 0))
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																		| Applying alpha-rule on (3386) yields:
% 67.80/29.34  																																																																		| (3387) aNaturalNumber0(all_20_2_23) = all_489_0_505
% 67.80/29.34  																																																																		| (3388) aNaturalNumber0(xp) = all_489_1_506
% 67.80/29.34  																																																																		| (3389)  ~ (all_489_0_505 = 0) |  ~ (all_489_1_506 = 0)
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																		| From (968) and (3387) follows:
% 67.80/29.34  																																																																		| (3390) aNaturalNumber0(xk) = all_489_0_505
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																		| Instantiating formula (46) with xk, all_489_0_505, 0 and discharging atoms aNaturalNumber0(xk) = all_489_0_505, aNaturalNumber0(xk) = 0, yields:
% 67.80/29.34  																																																																		| (3391) all_489_0_505 = 0
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																		| Instantiating formula (46) with xp, all_489_1_506, 0 and discharging atoms aNaturalNumber0(xp) = all_489_1_506, aNaturalNumber0(xp) = 0, yields:
% 67.80/29.34  																																																																		| (3392) all_489_1_506 = 0
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																		+-Applying beta-rule and splitting (3389), into two cases.
% 67.80/29.34  																																																																		|-Branch one:
% 67.80/29.34  																																																																		| (3393)  ~ (all_489_0_505 = 0)
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																			| Equations (3391) can reduce 3393 to:
% 67.80/29.34  																																																																			| (159) $false
% 67.80/29.34  																																																																			|
% 67.80/29.34  																																																																			|-The branch is then unsatisfiable
% 67.80/29.34  																																																																		|-Branch two:
% 67.80/29.34  																																																																		| (3391) all_489_0_505 = 0
% 67.80/29.34  																																																																		| (3396)  ~ (all_489_1_506 = 0)
% 67.80/29.34  																																																																		|
% 67.80/29.34  																																																																			| Equations (3392) can reduce 3396 to:
% 67.80/29.34  																																																																			| (159) $false
% 67.80/29.34  																																																																			|
% 67.80/29.34  																																																																			|-The branch is then unsatisfiable
% 67.80/29.34  																																																										|-Branch two:
% 67.80/29.34  																																																										| (3228) all_36_0_50 = 0
% 67.80/29.34  																																																										| (3399)  ~ (all_36_1_51 = 0) |  ~ (all_36_2_52 = 0) |  ~ (all_36_3_53 = 0)
% 67.80/29.34  																																																										|
% 67.80/29.34  																																																											+-Applying beta-rule and splitting (3399), into two cases.
% 67.80/29.34  																																																											|-Branch one:
% 67.80/29.34  																																																											| (3400)  ~ (all_36_1_51 = 0)
% 67.80/29.34  																																																											|
% 67.80/29.34  																																																												| Equations (555) can reduce 3400 to:
% 67.80/29.34  																																																												| (159) $false
% 67.80/29.34  																																																												|
% 67.80/29.34  																																																												|-The branch is then unsatisfiable
% 67.80/29.34  																																																											|-Branch two:
% 67.80/29.34  																																																											| (555) all_36_1_51 = 0
% 67.80/29.34  																																																											| (3403)  ~ (all_36_2_52 = 0) |  ~ (all_36_3_53 = 0)
% 67.80/29.34  																																																											|
% 67.80/29.34  																																																												+-Applying beta-rule and splitting (3403), into two cases.
% 67.80/29.34  																																																												|-Branch one:
% 67.80/29.34  																																																												| (3404)  ~ (all_36_2_52 = 0)
% 67.80/29.34  																																																												|
% 67.80/29.34  																																																													| Equations (979) can reduce 3404 to:
% 67.80/29.34  																																																													| (159) $false
% 67.80/29.34  																																																													|
% 67.80/29.34  																																																													|-The branch is then unsatisfiable
% 67.80/29.34  																																																												|-Branch two:
% 67.80/29.34  																																																												| (979) all_36_2_52 = 0
% 67.80/29.34  																																																												| (3407)  ~ (all_36_3_53 = 0)
% 67.80/29.34  																																																												|
% 67.80/29.34  																																																													| Equations (480) can reduce 3407 to:
% 67.80/29.34  																																																													| (159) $false
% 67.80/29.34  																																																													|
% 67.80/29.34  																																																													|-The branch is then unsatisfiable
% 67.80/29.35  																																																			|-Branch two:
% 67.80/29.35  																																																			| (3409)  ~ (all_58_0_58 = xp)
% 67.80/29.35  																																																			| (3410) all_58_0_58 = sz10 |  ? [v0] : (( ~ (v0 = 0) & aNaturalNumber0(all_58_0_58) = v0) | ( ~ (v0 = 0) & aNaturalNumber0(xp) = v0))
% 67.80/29.35  																																																			|
% 67.80/29.35  																																																				+-Applying beta-rule and splitting (3410), into two cases.
% 67.80/29.35  																																																				|-Branch one:
% 67.80/29.35  																																																				| (771) all_58_0_58 = sz10
% 67.80/29.35  																																																				|
% 67.80/29.35  																																																					| Equations (771) can reduce 201 to:
% 67.80/29.35  																																																					| (159) $false
% 67.80/29.35  																																																					|
% 67.80/29.35  																																																					|-The branch is then unsatisfiable
% 67.80/29.35  																																																				|-Branch two:
% 67.80/29.35  																																																				| (201)  ~ (all_58_0_58 = sz10)
% 67.80/29.35  																																																				| (3414)  ? [v0] : (( ~ (v0 = 0) & aNaturalNumber0(all_58_0_58) = v0) | ( ~ (v0 = 0) & aNaturalNumber0(xp) = v0))
% 67.80/29.35  																																																				|
% 67.80/29.35  																																																					| Instantiating (3414) with all_433_0_552 yields:
% 67.80/29.35  																																																					| (3415) ( ~ (all_433_0_552 = 0) & aNaturalNumber0(all_58_0_58) = all_433_0_552) | ( ~ (all_433_0_552 = 0) & aNaturalNumber0(xp) = all_433_0_552)
% 67.80/29.35  																																																					|
% 67.80/29.35  																																																					+-Applying beta-rule and splitting (3415), into two cases.
% 67.80/29.35  																																																					|-Branch one:
% 67.80/29.35  																																																					| (3416)  ~ (all_433_0_552 = 0) & aNaturalNumber0(all_58_0_58) = all_433_0_552
% 67.80/29.35  																																																					|
% 67.80/29.35  																																																						| Applying alpha-rule on (3416) yields:
% 67.80/29.35  																																																						| (3417)  ~ (all_433_0_552 = 0)
% 67.80/29.35  																																																						| (3418) aNaturalNumber0(all_58_0_58) = all_433_0_552
% 67.80/29.35  																																																						|
% 67.80/29.35  																																																						| Instantiating formula (46) with all_58_0_58, all_433_0_552, 0 and discharging atoms aNaturalNumber0(all_58_0_58) = all_433_0_552, aNaturalNumber0(all_58_0_58) = 0, yields:
% 67.80/29.35  																																																						| (3419) all_433_0_552 = 0
% 67.80/29.35  																																																						|
% 67.80/29.35  																																																						| Equations (3419) can reduce 3417 to:
% 67.80/29.35  																																																						| (159) $false
% 67.80/29.35  																																																						|
% 67.80/29.35  																																																						|-The branch is then unsatisfiable
% 67.80/29.35  																																																					|-Branch two:
% 67.80/29.35  																																																					| (3421)  ~ (all_433_0_552 = 0) & aNaturalNumber0(xp) = all_433_0_552
% 67.80/29.35  																																																					|
% 67.80/29.35  																																																						| Applying alpha-rule on (3421) yields:
% 67.80/29.35  																																																						| (3417)  ~ (all_433_0_552 = 0)
% 67.80/29.35  																																																						| (3423) aNaturalNumber0(xp) = all_433_0_552
% 67.80/29.35  																																																						|
% 67.80/29.35  																																																						| Instantiating formula (46) with xp, all_433_0_552, 0 and discharging atoms aNaturalNumber0(xp) = all_433_0_552, aNaturalNumber0(xp) = 0, yields:
% 67.80/29.35  																																																						| (3419) all_433_0_552 = 0
% 67.80/29.35  																																																						|
% 67.80/29.35  																																																						| Equations (3419) can reduce 3417 to:
% 67.80/29.35  																																																						| (159) $false
% 67.80/29.35  																																																						|
% 67.80/29.35  																																																						|-The branch is then unsatisfiable
% 67.80/29.35  																																																|-Branch two:
% 67.80/29.35  																																																| (3426) aNaturalNumber0(xr) = all_21_2_26 & aNaturalNumber0(xk) = all_21_1_25 & ( ~ (all_21_1_25 = 0) |  ~ (all_21_2_26 = 0))
% 67.80/29.35  																																																|
% 67.80/29.35  																																																	| Applying alpha-rule on (3426) yields:
% 67.80/29.35  																																																	| (3427) aNaturalNumber0(xr) = all_21_2_26
% 67.80/29.35  																																																	| (3428) aNaturalNumber0(xk) = all_21_1_25
% 67.80/29.35  																																																	| (3429)  ~ (all_21_1_25 = 0) |  ~ (all_21_2_26 = 0)
% 67.80/29.35  																																																	|
% 67.80/29.35  																																																	+-Applying beta-rule and splitting (651), into two cases.
% 67.80/29.35  																																																	|-Branch one:
% 67.80/29.35  																																																	| (974)  ~ (aNaturalNumber0(xk) = 0)
% 67.80/29.35  																																																	|
% 67.80/29.35  																																																		| Using (972) and (974) yields:
% 67.80/29.35  																																																		| (615) $false
% 67.80/29.35  																																																		|
% 67.80/29.35  																																																		|-The branch is then unsatisfiable
% 67.80/29.35  																																																	|-Branch two:
% 67.80/29.35  																																																	| (972) aNaturalNumber0(xk) = 0
% 67.80/29.35  																																																	| (996) xk = sz10 | xk = sz00 |  ? [v0] : (isPrime0(v0) = 0 & doDivides0(v0, xk) = 0 & aNaturalNumber0(v0) = 0)
% 67.80/29.35  																																																	|
% 67.80/29.35  																																																		| Instantiating formula (46) with xr, all_21_2_26, 0 and discharging atoms aNaturalNumber0(xr) = all_21_2_26, aNaturalNumber0(xr) = 0, yields:
% 67.80/29.35  																																																		| (3434) all_21_2_26 = 0
% 67.80/29.35  																																																		|
% 67.80/29.35  																																																		| Instantiating formula (46) with xk, all_21_1_25, 0 and discharging atoms aNaturalNumber0(xk) = all_21_1_25, aNaturalNumber0(xk) = 0, yields:
% 67.80/29.35  																																																		| (990) all_21_1_25 = 0
% 67.80/29.35  																																																		|
% 67.80/29.35  																																																		+-Applying beta-rule and splitting (3429), into two cases.
% 67.80/29.35  																																																		|-Branch one:
% 67.80/29.35  																																																		| (3436)  ~ (all_21_1_25 = 0)
% 67.80/29.35  																																																		|
% 67.80/29.35  																																																			| Equations (990) can reduce 3436 to:
% 67.80/29.35  																																																			| (159) $false
% 67.80/29.35  																																																			|
% 67.80/29.35  																																																			|-The branch is then unsatisfiable
% 67.80/29.35  																																																		|-Branch two:
% 67.80/29.35  																																																		| (990) all_21_1_25 = 0
% 67.80/29.35  																																																		| (3439)  ~ (all_21_2_26 = 0)
% 67.80/29.35  																																																		|
% 67.80/29.35  																																																			| Equations (3434) can reduce 3439 to:
% 67.80/29.35  																																																			| (159) $false
% 67.80/29.35  																																																			|
% 67.80/29.35  																																																			|-The branch is then unsatisfiable
% 67.80/29.35  																																													|-Branch two:
% 67.80/29.35  																																													| (3441)  ~ (all_20_2_23 = xk)
% 67.80/29.35  																																													| (3442)  ? [v0] :  ? [v1] :  ? [v2] : (( ~ (v0 = 0) & aNaturalNumber0(all_20_2_23) = v0) | (doDivides0(xp, all_0_3_3) = v2 & aNaturalNumber0(all_0_3_3) = v1 & aNaturalNumber0(xp) = v0 & ( ~ (v2 = 0) |  ~ (v1 = 0) |  ~ (v0 = 0))))
% 67.80/29.35  																																													|
% 67.80/29.35  																																														| Instantiating (3442) with all_369_0_572, all_369_1_573, all_369_2_574 yields:
% 67.80/29.35  																																														| (3443) ( ~ (all_369_2_574 = 0) & aNaturalNumber0(all_20_2_23) = all_369_2_574) | (doDivides0(xp, all_0_3_3) = all_369_0_572 & aNaturalNumber0(all_0_3_3) = all_369_1_573 & aNaturalNumber0(xp) = all_369_2_574 & ( ~ (all_369_0_572 = 0) |  ~ (all_369_1_573 = 0) |  ~ (all_369_2_574 = 0)))
% 67.80/29.35  																																														|
% 67.80/29.35  																																														+-Applying beta-rule and splitting (3443), into two cases.
% 67.80/29.35  																																														|-Branch one:
% 67.80/29.35  																																														| (3444)  ~ (all_369_2_574 = 0) & aNaturalNumber0(all_20_2_23) = all_369_2_574
% 67.80/29.35  																																														|
% 67.80/29.35  																																															| Applying alpha-rule on (3444) yields:
% 67.80/29.35  																																															| (3445)  ~ (all_369_2_574 = 0)
% 67.80/29.35  																																															| (3446) aNaturalNumber0(all_20_2_23) = all_369_2_574
% 67.80/29.35  																																															|
% 67.80/29.35  																																															| Instantiating formula (46) with all_20_2_23, all_369_2_574, 0 and discharging atoms aNaturalNumber0(all_20_2_23) = all_369_2_574, aNaturalNumber0(all_20_2_23) = 0, yields:
% 67.80/29.35  																																															| (3447) all_369_2_574 = 0
% 67.80/29.35  																																															|
% 67.80/29.35  																																															| Equations (3447) can reduce 3445 to:
% 67.80/29.35  																																															| (159) $false
% 67.80/29.35  																																															|
% 67.80/29.35  																																															|-The branch is then unsatisfiable
% 67.80/29.35  																																														|-Branch two:
% 67.80/29.35  																																														| (3449) doDivides0(xp, all_0_3_3) = all_369_0_572 & aNaturalNumber0(all_0_3_3) = all_369_1_573 & aNaturalNumber0(xp) = all_369_2_574 & ( ~ (all_369_0_572 = 0) |  ~ (all_369_1_573 = 0) |  ~ (all_369_2_574 = 0))
% 67.80/29.35  																																														|
% 67.80/29.35  																																															| Applying alpha-rule on (3449) yields:
% 67.80/29.35  																																															| (3450) doDivides0(xp, all_0_3_3) = all_369_0_572
% 67.80/29.35  																																															| (3451) aNaturalNumber0(all_0_3_3) = all_369_1_573
% 67.80/29.35  																																															| (3452) aNaturalNumber0(xp) = all_369_2_574
% 67.80/29.35  																																															| (3453)  ~ (all_369_0_572 = 0) |  ~ (all_369_1_573 = 0) |  ~ (all_369_2_574 = 0)
% 67.80/29.35  																																															|
% 67.80/29.35  																																															| Instantiating formula (32) with xp, all_0_3_3, all_369_0_572, 0 and discharging atoms doDivides0(xp, all_0_3_3) = all_369_0_572, doDivides0(xp, all_0_3_3) = 0, yields:
% 67.80/29.35  																																															| (3454) all_369_0_572 = 0
% 67.80/29.35  																																															|
% 67.80/29.35  																																															| Instantiating formula (46) with all_0_3_3, all_369_1_573, 0 and discharging atoms aNaturalNumber0(all_0_3_3) = all_369_1_573, aNaturalNumber0(all_0_3_3) = 0, yields:
% 67.80/29.35  																																															| (3455) all_369_1_573 = 0
% 67.80/29.35  																																															|
% 67.80/29.35  																																															| Instantiating formula (46) with xp, all_369_2_574, 0 and discharging atoms aNaturalNumber0(xp) = all_369_2_574, aNaturalNumber0(xp) = 0, yields:
% 67.80/29.35  																																															| (3447) all_369_2_574 = 0
% 67.80/29.35  																																															|
% 67.80/29.35  																																															+-Applying beta-rule and splitting (3453), into two cases.
% 67.80/29.35  																																															|-Branch one:
% 67.80/29.35  																																															| (3457)  ~ (all_369_0_572 = 0)
% 67.80/29.35  																																															|
% 67.80/29.35  																																																| Equations (3454) can reduce 3457 to:
% 67.80/29.35  																																																| (159) $false
% 67.80/29.35  																																																|
% 67.80/29.35  																																																|-The branch is then unsatisfiable
% 67.80/29.35  																																															|-Branch two:
% 67.80/29.35  																																															| (3454) all_369_0_572 = 0
% 67.80/29.35  																																															| (3460)  ~ (all_369_1_573 = 0) |  ~ (all_369_2_574 = 0)
% 67.80/29.35  																																															|
% 67.80/29.35  																																																+-Applying beta-rule and splitting (3460), into two cases.
% 67.80/29.35  																																																|-Branch one:
% 67.80/29.35  																																																| (3461)  ~ (all_369_1_573 = 0)
% 67.80/29.35  																																																|
% 67.88/29.35  																																																	| Equations (3455) can reduce 3461 to:
% 67.88/29.35  																																																	| (159) $false
% 67.88/29.35  																																																	|
% 67.88/29.35  																																																	|-The branch is then unsatisfiable
% 67.88/29.35  																																																|-Branch two:
% 67.88/29.35  																																																| (3455) all_369_1_573 = 0
% 67.88/29.35  																																																| (3445)  ~ (all_369_2_574 = 0)
% 67.88/29.35  																																																|
% 67.88/29.35  																																																	| Equations (3447) can reduce 3445 to:
% 67.88/29.35  																																																	| (159) $false
% 67.88/29.35  																																																	|
% 67.88/29.35  																																																	|-The branch is then unsatisfiable
% 67.88/29.36  																																											|-Branch two:
% 67.88/29.36  																																											| (3466) aNaturalNumber0(all_58_0_58) = all_186_2_128 & aNaturalNumber0(xp) = all_186_1_127 & ( ~ (all_186_1_127 = 0) |  ~ (all_186_2_128 = 0))
% 67.88/29.36  																																											|
% 67.88/29.36  																																												| Applying alpha-rule on (3466) yields:
% 67.88/29.36  																																												| (3467) aNaturalNumber0(all_58_0_58) = all_186_2_128
% 67.88/29.36  																																												| (3468) aNaturalNumber0(xp) = all_186_1_127
% 67.88/29.36  																																												| (3469)  ~ (all_186_1_127 = 0) |  ~ (all_186_2_128 = 0)
% 67.88/29.36  																																												|
% 67.88/29.36  																																												| Instantiating formula (46) with all_58_0_58, all_186_2_128, 0 and discharging atoms aNaturalNumber0(all_58_0_58) = all_186_2_128, aNaturalNumber0(all_58_0_58) = 0, yields:
% 67.88/29.36  																																												| (3470) all_186_2_128 = 0
% 67.88/29.36  																																												|
% 67.88/29.36  																																												| Instantiating formula (46) with xp, all_186_1_127, 0 and discharging atoms aNaturalNumber0(xp) = all_186_1_127, aNaturalNumber0(xp) = 0, yields:
% 67.88/29.36  																																												| (961) all_186_1_127 = 0
% 67.88/29.36  																																												|
% 67.88/29.36  																																												+-Applying beta-rule and splitting (3469), into two cases.
% 67.88/29.36  																																												|-Branch one:
% 67.88/29.36  																																												| (3472)  ~ (all_186_1_127 = 0)
% 67.88/29.36  																																												|
% 67.88/29.36  																																													| Equations (961) can reduce 3472 to:
% 67.88/29.36  																																													| (159) $false
% 67.88/29.36  																																													|
% 67.88/29.36  																																													|-The branch is then unsatisfiable
% 67.88/29.36  																																												|-Branch two:
% 67.88/29.36  																																												| (961) all_186_1_127 = 0
% 67.88/29.36  																																												| (3475)  ~ (all_186_2_128 = 0)
% 67.88/29.36  																																												|
% 67.88/29.36  																																													| Equations (3470) can reduce 3475 to:
% 67.88/29.36  																																													| (159) $false
% 67.88/29.36  																																													|
% 67.88/29.36  																																													|-The branch is then unsatisfiable
% 67.88/29.36  																																	|-Branch two:
% 67.88/29.36  																																	| (3477)  ~ (all_53_0_57 = xr)
% 67.88/29.36  																																	| (3478) all_53_0_57 = sz10 |  ? [v0] : (( ~ (v0 = 0) & aNaturalNumber0(all_53_0_57) = v0) | ( ~ (v0 = 0) & aNaturalNumber0(xr) = v0))
% 67.88/29.36  																																	|
% 67.88/29.36  																																		+-Applying beta-rule and splitting (3478), into two cases.
% 67.88/29.36  																																		|-Branch one:
% 67.88/29.36  																																		| (779) all_53_0_57 = sz10
% 67.88/29.36  																																		|
% 67.88/29.36  																																			| Equations (779) can reduce 203 to:
% 67.88/29.36  																																			| (159) $false
% 67.88/29.36  																																			|
% 67.88/29.36  																																			|-The branch is then unsatisfiable
% 67.88/29.36  																																		|-Branch two:
% 67.88/29.36  																																		| (203)  ~ (all_53_0_57 = sz10)
% 67.88/29.36  																																		| (3482)  ? [v0] : (( ~ (v0 = 0) & aNaturalNumber0(all_53_0_57) = v0) | ( ~ (v0 = 0) & aNaturalNumber0(xr) = v0))
% 67.88/29.36  																																		|
% 67.88/29.36  																																			| Instantiating (3482) with all_241_0_575 yields:
% 67.88/29.36  																																			| (3483) ( ~ (all_241_0_575 = 0) & aNaturalNumber0(all_53_0_57) = all_241_0_575) | ( ~ (all_241_0_575 = 0) & aNaturalNumber0(xr) = all_241_0_575)
% 67.88/29.36  																																			|
% 67.88/29.36  																																			+-Applying beta-rule and splitting (3483), into two cases.
% 67.88/29.36  																																			|-Branch one:
% 67.88/29.36  																																			| (3484)  ~ (all_241_0_575 = 0) & aNaturalNumber0(all_53_0_57) = all_241_0_575
% 67.88/29.36  																																			|
% 67.88/29.36  																																				| Applying alpha-rule on (3484) yields:
% 67.88/29.36  																																				| (3485)  ~ (all_241_0_575 = 0)
% 67.88/29.36  																																				| (3486) aNaturalNumber0(all_53_0_57) = all_241_0_575
% 67.88/29.36  																																				|
% 67.88/29.36  																																				| Instantiating formula (46) with all_53_0_57, all_241_0_575, 0 and discharging atoms aNaturalNumber0(all_53_0_57) = all_241_0_575, aNaturalNumber0(all_53_0_57) = 0, yields:
% 67.88/29.36  																																				| (3487) all_241_0_575 = 0
% 67.88/29.36  																																				|
% 67.88/29.36  																																				| Equations (3487) can reduce 3485 to:
% 67.88/29.36  																																				| (159) $false
% 67.88/29.36  																																				|
% 67.88/29.36  																																				|-The branch is then unsatisfiable
% 67.88/29.36  																																			|-Branch two:
% 67.88/29.36  																																			| (3489)  ~ (all_241_0_575 = 0) & aNaturalNumber0(xr) = all_241_0_575
% 67.88/29.36  																																			|
% 67.88/29.36  																																				| Applying alpha-rule on (3489) yields:
% 67.88/29.36  																																				| (3485)  ~ (all_241_0_575 = 0)
% 67.88/29.36  																																				| (3491) aNaturalNumber0(xr) = all_241_0_575
% 67.88/29.36  																																				|
% 67.88/29.36  																																				| Instantiating formula (46) with xr, all_241_0_575, 0 and discharging atoms aNaturalNumber0(xr) = all_241_0_575, aNaturalNumber0(xr) = 0, yields:
% 67.88/29.36  																																				| (3487) all_241_0_575 = 0
% 67.88/29.36  																																				|
% 67.88/29.36  																																				| Equations (3487) can reduce 3485 to:
% 67.88/29.36  																																				| (159) $false
% 67.88/29.36  																																				|
% 67.88/29.36  																																				|-The branch is then unsatisfiable
% 67.88/29.36  												|-Branch two:
% 67.88/29.36  												| (3494) aNaturalNumber0(all_0_3_3) = all_20_1_22 & aNaturalNumber0(xp) = all_20_2_23 & ( ~ (all_20_1_22 = 0) |  ~ (all_20_2_23 = 0))
% 67.88/29.36  												|
% 67.88/29.36  													| Applying alpha-rule on (3494) yields:
% 67.88/29.36  													| (3495) aNaturalNumber0(all_0_3_3) = all_20_1_22
% 67.88/29.36  													| (3496) aNaturalNumber0(xp) = all_20_2_23
% 67.88/29.36  													| (3497)  ~ (all_20_1_22 = 0) |  ~ (all_20_2_23 = 0)
% 67.88/29.36  													|
% 67.88/29.36  													| Instantiating formula (46) with all_0_3_3, all_20_1_22, 0 and discharging atoms aNaturalNumber0(all_0_3_3) = all_20_1_22, aNaturalNumber0(all_0_3_3) = 0, yields:
% 67.88/29.36  													| (559) all_20_1_22 = 0
% 67.88/29.36  													|
% 67.88/29.36  													| Instantiating formula (46) with xp, all_20_2_23, 0 and discharging atoms aNaturalNumber0(xp) = all_20_2_23, aNaturalNumber0(xp) = 0, yields:
% 67.88/29.36  													| (3499) all_20_2_23 = 0
% 67.88/29.36  													|
% 67.88/29.36  													+-Applying beta-rule and splitting (3497), into two cases.
% 67.88/29.36  													|-Branch one:
% 67.88/29.36  													| (3500)  ~ (all_20_1_22 = 0)
% 67.88/29.36  													|
% 67.88/29.36  														| Equations (559) can reduce 3500 to:
% 67.88/29.36  														| (159) $false
% 67.88/29.36  														|
% 67.88/29.36  														|-The branch is then unsatisfiable
% 67.88/29.36  													|-Branch two:
% 67.88/29.36  													| (559) all_20_1_22 = 0
% 67.88/29.36  													| (3503)  ~ (all_20_2_23 = 0)
% 67.88/29.36  													|
% 67.88/29.36  														| Equations (3499) can reduce 3503 to:
% 67.88/29.36  														| (159) $false
% 67.88/29.36  														|
% 67.88/29.36  														|-The branch is then unsatisfiable
% 67.88/29.36  								|-Branch two:
% 67.88/29.36  								| (3505) aNaturalNumber0(xp) = all_19_1_19 & aNaturalNumber0(xm) = all_19_2_20 & ( ~ (all_19_1_19 = 0) |  ~ (all_19_2_20 = 0))
% 67.88/29.36  								|
% 67.88/29.36  									| Applying alpha-rule on (3505) yields:
% 67.88/29.36  									| (3506) aNaturalNumber0(xp) = all_19_1_19
% 67.88/29.36  									| (3507) aNaturalNumber0(xm) = all_19_2_20
% 67.88/29.36  									| (3508)  ~ (all_19_1_19 = 0) |  ~ (all_19_2_20 = 0)
% 67.88/29.36  									|
% 67.88/29.36  									| Instantiating formula (46) with xp, all_19_1_19, 0 and discharging atoms aNaturalNumber0(xp) = all_19_1_19, aNaturalNumber0(xp) = 0, yields:
% 67.88/29.36  									| (540) all_19_1_19 = 0
% 67.88/29.36  									|
% 67.88/29.36  									| Instantiating formula (46) with xm, all_19_2_20, 0 and discharging atoms aNaturalNumber0(xm) = all_19_2_20, aNaturalNumber0(xm) = 0, yields:
% 67.88/29.36  									| (3510) all_19_2_20 = 0
% 67.88/29.36  									|
% 67.88/29.36  									+-Applying beta-rule and splitting (3508), into two cases.
% 67.88/29.36  									|-Branch one:
% 67.88/29.36  									| (3511)  ~ (all_19_1_19 = 0)
% 67.88/29.36  									|
% 67.88/29.36  										| Equations (540) can reduce 3511 to:
% 67.88/29.36  										| (159) $false
% 67.88/29.36  										|
% 67.88/29.36  										|-The branch is then unsatisfiable
% 67.88/29.36  									|-Branch two:
% 67.88/29.36  									| (540) all_19_1_19 = 0
% 67.88/29.36  									| (3514)  ~ (all_19_2_20 = 0)
% 67.88/29.36  									|
% 67.88/29.36  										| Equations (3510) can reduce 3514 to:
% 67.88/29.36  										| (159) $false
% 67.88/29.36  										|
% 67.88/29.36  										|-The branch is then unsatisfiable
% 67.88/29.36  						|-Branch two:
% 67.88/29.36  						| (3516) aNaturalNumber0(xp) = all_18_1_16 & aNaturalNumber0(xn) = all_18_2_17 & ( ~ (all_18_1_16 = 0) |  ~ (all_18_2_17 = 0))
% 67.88/29.36  						|
% 67.88/29.36  							| Applying alpha-rule on (3516) yields:
% 67.88/29.36  							| (3517) aNaturalNumber0(xp) = all_18_1_16
% 67.88/29.36  							| (3518) aNaturalNumber0(xn) = all_18_2_17
% 67.88/29.36  							| (3519)  ~ (all_18_1_16 = 0) |  ~ (all_18_2_17 = 0)
% 67.88/29.36  							|
% 67.88/29.36  							| Instantiating formula (46) with xp, all_18_1_16, 0 and discharging atoms aNaturalNumber0(xp) = all_18_1_16, aNaturalNumber0(xp) = 0, yields:
% 67.88/29.36  							| (531) all_18_1_16 = 0
% 67.88/29.36  							|
% 67.88/29.36  							| Instantiating formula (46) with xn, all_18_2_17, 0 and discharging atoms aNaturalNumber0(xn) = all_18_2_17, aNaturalNumber0(xn) = 0, yields:
% 67.88/29.36  							| (3521) all_18_2_17 = 0
% 67.88/29.36  							|
% 67.88/29.36  							+-Applying beta-rule and splitting (3519), into two cases.
% 67.88/29.36  							|-Branch one:
% 67.88/29.36  							| (3522)  ~ (all_18_1_16 = 0)
% 67.88/29.36  							|
% 67.88/29.36  								| Equations (531) can reduce 3522 to:
% 67.88/29.36  								| (159) $false
% 67.88/29.36  								|
% 67.88/29.36  								|-The branch is then unsatisfiable
% 67.88/29.36  							|-Branch two:
% 67.88/29.36  							| (531) all_18_1_16 = 0
% 67.88/29.36  							| (3525)  ~ (all_18_2_17 = 0)
% 67.88/29.36  							|
% 67.88/29.37  								| Equations (3521) can reduce 3525 to:
% 67.88/29.37  								| (159) $false
% 67.88/29.37  								|
% 67.88/29.37  								|-The branch is then unsatisfiable
% 67.88/29.37  % SZS output end Proof for theBenchmark
% 67.88/29.37  
% 67.88/29.37  28710ms
%------------------------------------------------------------------------------