TSTP Solution File: NUM490+3 by SOS---2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : SOS---2.0
% Problem : NUM490+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : sos-script %s
% Computer : n024.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:18:47 EDT 2022
% Result : Theorem 2.88s 3.09s
% Output : Refutation 2.88s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : NUM490+3 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.12 % Command : sos-script %s
% 0.12/0.33 % Computer : n024.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Thu Jul 7 19:27:29 EDT 2022
% 0.12/0.33 % CPUTime :
% 2.88/3.09
% 2.88/3.09 -------- PROOF --------
% 2.88/3.09 % SZS status Unsatisfiable
% 2.88/3.09 % SZS output start Refutation
% 2.88/3.09 ----- Otter 3.2, August 2001 -----
% 2.88/3.09 The process was started by sandbox on n024.cluster.edu,
% 2.88/3.09 Thu Jul 7 19:27:29 2022
% 2.88/3.09 The command was "./sos". The process ID is 14966.
% 2.88/3.09
% 2.88/3.09 set(prolog_style_variables).
% 2.88/3.09 set(auto).
% 2.88/3.09 dependent: set(auto1).
% 2.88/3.09 dependent: set(process_input).
% 2.88/3.09 dependent: clear(print_kept).
% 2.88/3.09 dependent: clear(print_new_demod).
% 2.88/3.09 dependent: clear(print_back_demod).
% 2.88/3.09 dependent: clear(print_back_sub).
% 2.88/3.09 dependent: set(control_memory).
% 2.88/3.09 dependent: assign(max_mem, 12000).
% 2.88/3.09 dependent: assign(pick_given_ratio, 4).
% 2.88/3.09 dependent: assign(stats_level, 1).
% 2.88/3.09 dependent: assign(pick_semantic_ratio, 3).
% 2.88/3.09 dependent: assign(sos_limit, 5000).
% 2.88/3.09 dependent: assign(max_weight, 60).
% 2.88/3.09 clear(print_given).
% 2.88/3.09
% 2.88/3.09 formula_list(usable).
% 2.88/3.09
% 2.88/3.09 SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=11.
% 2.88/3.09
% 2.88/3.09 This ia a non-Horn set with equality. The strategy will be
% 2.88/3.09 Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 2.88/3.09 unit deletion, with positive clauses in sos and nonpositive
% 2.88/3.09 clauses in usable.
% 2.88/3.09
% 2.88/3.09 dependent: set(knuth_bendix).
% 2.88/3.09 dependent: set(para_from).
% 2.88/3.09 dependent: set(para_into).
% 2.88/3.09 dependent: clear(para_from_right).
% 2.88/3.09 dependent: clear(para_into_right).
% 2.88/3.09 dependent: set(para_from_vars).
% 2.88/3.09 dependent: set(eq_units_both_ways).
% 2.88/3.09 dependent: set(dynamic_demod_all).
% 2.88/3.09 dependent: set(dynamic_demod).
% 2.88/3.09 dependent: set(order_eq).
% 2.88/3.09 dependent: set(back_demod).
% 2.88/3.09 dependent: set(lrpo).
% 2.88/3.09 dependent: set(hyper_res).
% 2.88/3.09 dependent: set(unit_deletion).
% 2.88/3.09 dependent: set(factor).
% 2.88/3.09
% 2.88/3.09 ------------> process usable:
% 2.88/3.09 Following clause subsumed by 21 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)|A=B| -sdtlseqdt0(A,B)| -aNaturalNumber0(C)|sdtpldt0(C,A)!=sdtpldt0(C,B).
% 2.88/3.09 Following clause subsumed by 22 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)|A=B| -sdtlseqdt0(A,B)| -aNaturalNumber0(C)|sdtpldt0(A,C)!=sdtpldt0(B,C).
% 2.88/3.09 Following clause subsumed by 23 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)| -aNaturalNumber0(C)|A=sz00|B=C| -sdtlseqdt0(B,C)|sdtasdt0(A,B)!=sdtasdt0(A,C).
% 2.88/3.09 Following clause subsumed by 24 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)| -aNaturalNumber0(C)|A=sz00|B=C| -sdtlseqdt0(B,C)|sdtasdt0(B,A)!=sdtasdt0(C,A).
% 2.88/3.09 405 back subsumes 399.
% 2.88/3.09 405 back subsumes 393.
% 2.88/3.09 405 back subsumes 387.
% 2.88/3.09 405 back subsumes 369.
% 2.88/3.09 435 back subsumes 432.
% 2.88/3.09 435 back subsumes 429.
% 2.88/3.09 435 back subsumes 426.
% 2.88/3.09 435 back subsumes 417.
% 2.88/3.09 486 back subsumes 480.
% 2.88/3.09 486 back subsumes 474.
% 2.88/3.09 486 back subsumes 468.
% 2.88/3.09 486 back subsumes 450.
% 2.88/3.09 516 back subsumes 513.
% 2.88/3.09 516 back subsumes 510.
% 2.88/3.09 516 back subsumes 507.
% 2.88/3.09 516 back subsumes 498.
% 2.88/3.09 567 back subsumes 561.
% 2.88/3.09 567 back subsumes 555.
% 2.88/3.09 567 back subsumes 549.
% 2.88/3.09 567 back subsumes 531.
% 2.88/3.09 597 back subsumes 594.
% 2.88/3.09 597 back subsumes 591.
% 2.88/3.09 597 back subsumes 588.
% 2.88/3.09 597 back subsumes 579.
% 2.88/3.09 648 back subsumes 642.
% 2.88/3.09 648 back subsumes 636.
% 2.88/3.09 648 back subsumes 630.
% 2.88/3.09 648 back subsumes 612.
% 2.88/3.09 678 back subsumes 675.
% 2.88/3.09 678 back subsumes 672.
% 2.88/3.09 678 back subsumes 669.
% 2.88/3.09 678 back subsumes 660.
% 2.88/3.09 729 back subsumes 723.
% 2.88/3.09 729 back subsumes 717.
% 2.88/3.09 729 back subsumes 711.
% 2.88/3.09 729 back subsumes 693.
% 2.88/3.09 759 back subsumes 756.
% 2.88/3.09 759 back subsumes 753.
% 2.88/3.09 759 back subsumes 750.
% 2.88/3.09 759 back subsumes 741.
% 2.88/3.09 810 back subsumes 804.
% 2.88/3.09 810 back subsumes 798.
% 2.88/3.09 810 back subsumes 792.
% 2.88/3.09 810 back subsumes 774.
% 2.88/3.09 840 back subsumes 837.
% 2.88/3.09 840 back subsumes 834.
% 2.88/3.09 840 back subsumes 831.
% 2.88/3.09 840 back subsumes 822.
% 2.88/3.09 891 back subsumes 885.
% 2.88/3.09 891 back subsumes 879.
% 2.88/3.09 891 back subsumes 873.
% 2.88/3.09 891 back subsumes 855.
% 2.88/3.09 921 back subsumes 918.
% 2.88/3.09 921 back subsumes 915.
% 2.88/3.09 921 back subsumes 912.
% 2.88/3.09 921 back subsumes 903.
% 2.88/3.09
% 2.88/3.09 ------------> process sos:
% 2.88/3.09
% 2.88/3.09 ----> UNIT CONFLICT at 2.73 sec ----> 1395 [binary,1393.1,280.1] {-} $F.
% 2.88/3.09
% 2.88/3.09 Length of proof is 1. Level of proof is 1.
% 2.88/3.09
% 2.88/3.09 ---------------- PROOF ----------------
% 2.88/3.09 % SZS status Theorem
% 2.88/3.09 % SZS output start Refutation
% 2.88/3.09
% 2.88/3.09 280 [] {-} sdtpldt0(sdtasdt0(xp,xm),sdtasdt0(xr,xm))!=sdtasdt0(xn,xm).
% 2.88/3.09 1392 [] {-} sdtasdt0(xn,xm)=sdtpldt0(sdtasdt0(xp,xm),sdtasdt0(xr,xm)).
% 2.88/3.09 1393 [copy,1392,flip.1] {-} sdtpldt0(sdtasdt0(xp,xm),sdtasdt0(xr,xm))=sdtasdt0(xn,xm).
% 2.88/3.09 1395 [binary,1393.1,280.1] {-} $F.
% 2.88/3.09
% 2.88/3.09 % SZS output end Refutation
% 2.88/3.09 ------------ end of proof -------------
% 2.88/3.09
% 2.88/3.09
% 2.88/3.09 Search stopped by max_proofs option.
% 2.88/3.09
% 2.88/3.09
% 2.88/3.09 Search stopped by max_proofs option.
% 2.88/3.09
% 2.88/3.09 ============ end of search ============
% 2.88/3.09
% 2.88/3.09 That finishes the proof of the theorem.
% 2.88/3.09
% 2.88/3.09 Process 14966 finished Thu Jul 7 19:27:31 2022
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