TSTP Solution File: NUM490+3 by Etableau---0.67
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%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : NUM490+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n020.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 09:41:35 EDT 2022
% Result : Theorem 0.19s 0.38s
% Output : CNFRefutation 0.19s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 2
% Syntax : Number of formulae : 7 ( 4 unt; 0 def)
% Number of atoms : 10 ( 9 equ)
% Maximal formula atoms : 2 ( 1 avg)
% Number of connectives : 7 ( 4 ~; 2 |; 1 &)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 3 ( 2 avg)
% Maximal term depth : 3 ( 2 avg)
% Number of predicates : 2 ( 0 usr; 1 prp; 0-2 aty)
% Number of functors : 7 ( 7 usr; 4 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn 0 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(m__,conjecture,
( sdtpldt0(sdtasdt0(xp,xm),sdtasdt0(xr,xm)) = sdtasdt0(xn,xm)
| sdtasdt0(xr,xm) = sdtmndt0(sdtasdt0(xn,xm),sdtasdt0(xp,xm)) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',m__) ).
fof(m__1951,hypothesis,
sdtasdt0(xn,xm) = sdtpldt0(sdtasdt0(xp,xm),sdtasdt0(xr,xm)),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',m__1951) ).
fof(c_0_2,negated_conjecture,
~ ( sdtpldt0(sdtasdt0(xp,xm),sdtasdt0(xr,xm)) = sdtasdt0(xn,xm)
| sdtasdt0(xr,xm) = sdtmndt0(sdtasdt0(xn,xm),sdtasdt0(xp,xm)) ),
inference(assume_negation,[status(cth)],[m__]) ).
fof(c_0_3,negated_conjecture,
( sdtpldt0(sdtasdt0(xp,xm),sdtasdt0(xr,xm)) != sdtasdt0(xn,xm)
& sdtasdt0(xr,xm) != sdtmndt0(sdtasdt0(xn,xm),sdtasdt0(xp,xm)) ),
inference(fof_nnf,[status(thm)],[c_0_2]) ).
cnf(c_0_4,hypothesis,
sdtasdt0(xn,xm) = sdtpldt0(sdtasdt0(xp,xm),sdtasdt0(xr,xm)),
inference(split_conjunct,[status(thm)],[m__1951]) ).
cnf(c_0_5,negated_conjecture,
sdtpldt0(sdtasdt0(xp,xm),sdtasdt0(xr,xm)) != sdtasdt0(xn,xm),
inference(split_conjunct,[status(thm)],[c_0_3]) ).
cnf(c_0_6,hypothesis,
$false,
inference(sr,[status(thm)],[c_0_4,c_0_5]),
[proof] ).
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : NUM490+3 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.12 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.13/0.33 % Computer : n020.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % Memory : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % WCLimit : 600
% 0.13/0.33 % DateTime : Thu Jul 7 19:26:29 EDT 2022
% 0.13/0.33 % CPUTime :
% 0.19/0.38 # No SInE strategy applied
% 0.19/0.38 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PI_PS_S5PRR_S032N
% 0.19/0.38 # and selection function SelectUnlessUniqMax.
% 0.19/0.38 #
% 0.19/0.38 # Presaturation interreduction done
% 0.19/0.38
% 0.19/0.38 # Proof found!
% 0.19/0.38 # SZS status Theorem
% 0.19/0.38 # SZS output start CNFRefutation
% See solution above
% 0.19/0.38 # Training examples: 0 positive, 0 negative
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