TSTP Solution File: NUM489+3 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : NUM489+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n019.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:18:47 EDT 2022

% Result   : Theorem 2.77s 2.99s
% Output   : Refutation 2.77s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem  : NUM489+3 : TPTP v8.1.0. Released v4.0.0.
% 0.06/0.12  % Command  : sos-script %s
% 0.12/0.32  % Computer : n019.cluster.edu
% 0.12/0.32  % Model    : x86_64 x86_64
% 0.12/0.32  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.32  % Memory   : 8042.1875MB
% 0.12/0.32  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.32  % CPULimit : 300
% 0.12/0.32  % WCLimit  : 600
% 0.12/0.32  % DateTime : Thu Jul  7 13:14:08 EDT 2022
% 0.12/0.32  % CPUTime  : 
% 2.77/2.99  
% 2.77/2.99  -------- PROOF -------- 
% 2.77/2.99  % SZS status Unsatisfiable
% 2.77/2.99  % SZS output start Refutation
% 2.77/2.99  ----- Otter 3.2, August 2001 -----
% 2.77/2.99  The process was started by sandbox on n019.cluster.edu,
% 2.77/2.99  Thu Jul  7 13:14:08 2022
% 2.77/2.99  The command was "./sos".  The process ID is 956.
% 2.77/2.99  
% 2.77/2.99  set(prolog_style_variables).
% 2.77/2.99  set(auto).
% 2.77/2.99     dependent: set(auto1).
% 2.77/2.99     dependent: set(process_input).
% 2.77/2.99     dependent: clear(print_kept).
% 2.77/2.99     dependent: clear(print_new_demod).
% 2.77/2.99     dependent: clear(print_back_demod).
% 2.77/2.99     dependent: clear(print_back_sub).
% 2.77/2.99     dependent: set(control_memory).
% 2.77/2.99     dependent: assign(max_mem, 12000).
% 2.77/2.99     dependent: assign(pick_given_ratio, 4).
% 2.77/2.99     dependent: assign(stats_level, 1).
% 2.77/2.99     dependent: assign(pick_semantic_ratio, 3).
% 2.77/2.99     dependent: assign(sos_limit, 5000).
% 2.77/2.99     dependent: assign(max_weight, 60).
% 2.77/2.99  clear(print_given).
% 2.77/2.99  
% 2.77/2.99  formula_list(usable).
% 2.77/2.99  
% 2.77/2.99  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=11.
% 2.77/2.99  
% 2.77/2.99  This ia a non-Horn set with equality.  The strategy will be
% 2.77/2.99  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 2.77/2.99  unit deletion, with positive clauses in sos and nonpositive
% 2.77/2.99  clauses in usable.
% 2.77/2.99  
% 2.77/2.99     dependent: set(knuth_bendix).
% 2.77/2.99     dependent: set(para_from).
% 2.77/2.99     dependent: set(para_into).
% 2.77/2.99     dependent: clear(para_from_right).
% 2.77/2.99     dependent: clear(para_into_right).
% 2.77/2.99     dependent: set(para_from_vars).
% 2.77/2.99     dependent: set(eq_units_both_ways).
% 2.77/2.99     dependent: set(dynamic_demod_all).
% 2.77/2.99     dependent: set(dynamic_demod).
% 2.77/2.99     dependent: set(order_eq).
% 2.77/2.99     dependent: set(back_demod).
% 2.77/2.99     dependent: set(lrpo).
% 2.77/2.99     dependent: set(hyper_res).
% 2.77/2.99     dependent: set(unit_deletion).
% 2.77/2.99     dependent: set(factor).
% 2.77/2.99  
% 2.77/2.99  ------------> process usable:
% 2.77/2.99    Following clause subsumed by 21 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)|A=B| -sdtlseqdt0(A,B)| -aNaturalNumber0(C)|sdtpldt0(C,A)!=sdtpldt0(C,B).
% 2.77/2.99    Following clause subsumed by 22 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)|A=B| -sdtlseqdt0(A,B)| -aNaturalNumber0(C)|sdtpldt0(A,C)!=sdtpldt0(B,C).
% 2.77/2.99    Following clause subsumed by 23 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)| -aNaturalNumber0(C)|A=sz00|B=C| -sdtlseqdt0(B,C)|sdtasdt0(A,B)!=sdtasdt0(A,C).
% 2.77/2.99    Following clause subsumed by 24 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)| -aNaturalNumber0(C)|A=sz00|B=C| -sdtlseqdt0(B,C)|sdtasdt0(B,A)!=sdtasdt0(C,A).
% 2.77/2.99  404 back subsumes 398.
% 2.77/2.99  404 back subsumes 392.
% 2.77/2.99  404 back subsumes 386.
% 2.77/2.99  404 back subsumes 368.
% 2.77/2.99  434 back subsumes 431.
% 2.77/2.99  434 back subsumes 428.
% 2.77/2.99  434 back subsumes 425.
% 2.77/2.99  434 back subsumes 416.
% 2.77/2.99  485 back subsumes 479.
% 2.77/2.99  485 back subsumes 473.
% 2.77/2.99  485 back subsumes 467.
% 2.77/2.99  485 back subsumes 449.
% 2.77/2.99  515 back subsumes 512.
% 2.77/2.99  515 back subsumes 509.
% 2.77/2.99  515 back subsumes 506.
% 2.77/2.99  515 back subsumes 497.
% 2.77/2.99  566 back subsumes 560.
% 2.77/2.99  566 back subsumes 554.
% 2.77/2.99  566 back subsumes 548.
% 2.77/2.99  566 back subsumes 530.
% 2.77/2.99  596 back subsumes 593.
% 2.77/2.99  596 back subsumes 590.
% 2.77/2.99  596 back subsumes 587.
% 2.77/2.99  596 back subsumes 578.
% 2.77/2.99  647 back subsumes 641.
% 2.77/2.99  647 back subsumes 635.
% 2.77/2.99  647 back subsumes 629.
% 2.77/2.99  647 back subsumes 611.
% 2.77/2.99  677 back subsumes 674.
% 2.77/2.99  677 back subsumes 671.
% 2.77/2.99  677 back subsumes 668.
% 2.77/2.99  677 back subsumes 659.
% 2.77/2.99  728 back subsumes 722.
% 2.77/2.99  728 back subsumes 716.
% 2.77/2.99  728 back subsumes 710.
% 2.77/2.99  728 back subsumes 692.
% 2.77/2.99  758 back subsumes 755.
% 2.77/2.99  758 back subsumes 752.
% 2.77/2.99  758 back subsumes 749.
% 2.77/2.99  758 back subsumes 740.
% 2.77/2.99  809 back subsumes 803.
% 2.77/2.99  809 back subsumes 797.
% 2.77/2.99  809 back subsumes 791.
% 2.77/2.99  809 back subsumes 773.
% 2.77/2.99  839 back subsumes 836.
% 2.77/2.99  839 back subsumes 833.
% 2.77/2.99  839 back subsumes 830.
% 2.77/2.99  839 back subsumes 821.
% 2.77/2.99  890 back subsumes 884.
% 2.77/2.99  890 back subsumes 878.
% 2.77/2.99  890 back subsumes 872.
% 2.77/2.99  890 back subsumes 854.
% 2.77/2.99  920 back subsumes 917.
% 2.77/2.99  920 back subsumes 914.
% 2.77/2.99  920 back subsumes 911.
% 2.77/2.99  920 back subsumes 902.
% 2.77/2.99  
% 2.77/2.99  ------------> process sos:
% 2.77/2.99  
% 2.77/2.99  ----> UNIT CONFLICT at   2.65 sec ----> 1382 [binary,1380.1,281.1] {-} $F.
% 2.77/2.99  
% 2.77/2.99  Length of proof is 1.  Level of proof is 1.
% 2.77/2.99  
% 2.77/2.99  ---------------- PROOF ----------------
% 2.77/2.99  % SZS status Theorem
% 2.77/2.99  % SZS output start Refutation
% 2.77/2.99  
% 2.77/2.99  280 [] {-} xn!=sdtpldt0(xp,xr).
% 2.77/2.99  281 [copy,280,flip.1] {-} sdtpldt0(xp,xr)!=xn.
% 2.77/2.99  1380 [] {-} sdtpldt0(xp,xr)=xn.
% 2.77/2.99  1382 [binary,1380.1,281.1] {-} $F.
% 2.77/2.99  
% 2.77/2.99  % SZS output end Refutation
% 2.77/2.99  ------------ end of proof -------------
% 2.77/2.99  
% 2.77/2.99  
% 2.77/2.99  Search stopped by max_proofs option.
% 2.77/2.99  
% 2.77/2.99  
% 2.77/2.99  Search stopped by max_proofs option.
% 2.77/2.99  
% 2.77/2.99  ============ end of search ============
% 2.77/2.99  
% 2.77/2.99  That finishes the proof of the theorem.
% 2.77/2.99  
% 2.77/2.99  Process 956 finished Thu Jul  7 13:14:11 2022
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