TSTP Solution File: NUM482+3 by Vampire-SAT---4.8

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%------------------------------------------------------------------------------
% File     : Vampire-SAT---4.8
% Problem  : NUM482+3 : TPTP v8.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : vampire --mode casc_sat -m 16384 --cores 7 -t %d %s

% Computer : n003.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Tue May 21 02:01:39 EDT 2024

% Result   : Theorem 0.15s 0.39s
% Output   : Refutation 0.15s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :   12
%            Number of leaves      :    6
% Syntax   : Number of formulae    :   24 (   7 unt;   0 def)
%            Number of atoms       :  169 (  69 equ)
%            Maximal formula atoms :   20 (   7 avg)
%            Number of connectives :  214 (  69   ~;  64   |;  71   &)
%                                         (   0 <=>;  10  =>;   0  <=;   0 <~>)
%            Maximal formula depth :   13 (   6 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    7 (   5 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   3 con; 0-2 aty)
%            Number of variables   :   48 (  30   !;  18   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(f337,plain,
    $false,
    inference(resolution,[],[f336,f189]) ).

fof(f189,plain,
    aNaturalNumber0(sz10),
    inference(cnf_transformation,[],[f3]) ).

fof(f3,axiom,
    ( sz00 != sz10
    & aNaturalNumber0(sz10) ),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',mSortsC_01) ).

fof(f336,plain,
    ~ aNaturalNumber0(sz10),
    inference(resolution,[],[f327,f173]) ).

fof(f173,plain,
    aNaturalNumber0(xk),
    inference(cnf_transformation,[],[f38]) ).

fof(f38,axiom,
    aNaturalNumber0(xk),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',m__1716) ).

fof(f327,plain,
    ( ~ aNaturalNumber0(xk)
    | ~ aNaturalNumber0(sz10) ),
    inference(resolution,[],[f326,f168]) ).

fof(f168,plain,
    isPrime0(xk),
    inference(cnf_transformation,[],[f131]) ).

fof(f131,plain,
    ( ! [X0] :
        ( ( ~ isPrime0(X0)
          & ( sP1(X0)
            | sz10 = X0
            | sz00 = X0 ) )
        | ( ~ doDivides0(X0,xk)
          & ! [X1] :
              ( sdtasdt0(X0,X1) != xk
              | ~ aNaturalNumber0(X1) ) )
        | ~ aNaturalNumber0(X0) )
    & isPrime0(xk)
    & ! [X2] :
        ( xk = X2
        | sz10 = X2
        | ( ~ doDivides0(X2,xk)
          & ! [X3] :
              ( xk != sdtasdt0(X2,X3)
              | ~ aNaturalNumber0(X3) ) )
        | ~ aNaturalNumber0(X2) ) ),
    inference(rectify,[],[f115]) ).

fof(f115,plain,
    ( ! [X2] :
        ( ( ~ isPrime0(X2)
          & ( sP1(X2)
            | sz10 = X2
            | sz00 = X2 ) )
        | ( ~ doDivides0(X2,xk)
          & ! [X5] :
              ( xk != sdtasdt0(X2,X5)
              | ~ aNaturalNumber0(X5) ) )
        | ~ aNaturalNumber0(X2) )
    & isPrime0(xk)
    & ! [X0] :
        ( xk = X0
        | sz10 = X0
        | ( ~ doDivides0(X0,xk)
          & ! [X1] :
              ( sdtasdt0(X0,X1) != xk
              | ~ aNaturalNumber0(X1) ) )
        | ~ aNaturalNumber0(X0) ) ),
    inference(definition_folding,[],[f48,f114,f113]) ).

fof(f113,plain,
    ! [X2,X3] :
      ( ? [X4] :
          ( sdtasdt0(X3,X4) = X2
          & aNaturalNumber0(X4) )
      | ~ sP0(X2,X3) ),
    introduced(predicate_definition_introduction,[new_symbols(naming,[sP0])]) ).

fof(f114,plain,
    ! [X2] :
      ( ? [X3] :
          ( X2 != X3
          & sz10 != X3
          & doDivides0(X3,X2)
          & sP0(X2,X3)
          & aNaturalNumber0(X3) )
      | ~ sP1(X2) ),
    introduced(predicate_definition_introduction,[new_symbols(naming,[sP1])]) ).

fof(f48,plain,
    ( ! [X2] :
        ( ( ~ isPrime0(X2)
          & ( ? [X3] :
                ( X2 != X3
                & sz10 != X3
                & doDivides0(X3,X2)
                & ? [X4] :
                    ( sdtasdt0(X3,X4) = X2
                    & aNaturalNumber0(X4) )
                & aNaturalNumber0(X3) )
            | sz10 = X2
            | sz00 = X2 ) )
        | ( ~ doDivides0(X2,xk)
          & ! [X5] :
              ( xk != sdtasdt0(X2,X5)
              | ~ aNaturalNumber0(X5) ) )
        | ~ aNaturalNumber0(X2) )
    & isPrime0(xk)
    & ! [X0] :
        ( xk = X0
        | sz10 = X0
        | ( ~ doDivides0(X0,xk)
          & ! [X1] :
              ( sdtasdt0(X0,X1) != xk
              | ~ aNaturalNumber0(X1) ) )
        | ~ aNaturalNumber0(X0) ) ),
    inference(flattening,[],[f47]) ).

fof(f47,plain,
    ( ! [X2] :
        ( ( ~ isPrime0(X2)
          & ( ? [X3] :
                ( X2 != X3
                & sz10 != X3
                & doDivides0(X3,X2)
                & ? [X4] :
                    ( sdtasdt0(X3,X4) = X2
                    & aNaturalNumber0(X4) )
                & aNaturalNumber0(X3) )
            | sz10 = X2
            | sz00 = X2 ) )
        | ( ~ doDivides0(X2,xk)
          & ! [X5] :
              ( xk != sdtasdt0(X2,X5)
              | ~ aNaturalNumber0(X5) ) )
        | ~ aNaturalNumber0(X2) )
    & isPrime0(xk)
    & ! [X0] :
        ( xk = X0
        | sz10 = X0
        | ( ~ doDivides0(X0,xk)
          & ! [X1] :
              ( sdtasdt0(X0,X1) != xk
              | ~ aNaturalNumber0(X1) ) )
        | ~ aNaturalNumber0(X0) ) ),
    inference(ennf_transformation,[],[f43]) ).

fof(f43,plain,
    ~ ( ( isPrime0(xk)
        & ! [X0] :
            ( ( ( doDivides0(X0,xk)
                | ? [X1] :
                    ( sdtasdt0(X0,X1) = xk
                    & aNaturalNumber0(X1) ) )
              & aNaturalNumber0(X0) )
           => ( xk = X0
              | sz10 = X0 ) ) )
     => ? [X2] :
          ( ( isPrime0(X2)
            | ( ! [X3] :
                  ( ( doDivides0(X3,X2)
                    & ? [X4] :
                        ( sdtasdt0(X3,X4) = X2
                        & aNaturalNumber0(X4) )
                    & aNaturalNumber0(X3) )
                 => ( X2 = X3
                    | sz10 = X3 ) )
              & sz10 != X2
              & sz00 != X2 ) )
          & ( doDivides0(X2,xk)
            | ? [X5] :
                ( xk = sdtasdt0(X2,X5)
                & aNaturalNumber0(X5) ) )
          & aNaturalNumber0(X2) ) ),
    inference(rectify,[],[f42]) ).

fof(f42,negated_conjecture,
    ~ ( ( isPrime0(xk)
        & ! [X0] :
            ( ( ( doDivides0(X0,xk)
                | ? [X1] :
                    ( sdtasdt0(X0,X1) = xk
                    & aNaturalNumber0(X1) ) )
              & aNaturalNumber0(X0) )
           => ( xk = X0
              | sz10 = X0 ) ) )
     => ? [X0] :
          ( ( isPrime0(X0)
            | ( ! [X1] :
                  ( ( doDivides0(X1,X0)
                    & ? [X2] :
                        ( sdtasdt0(X1,X2) = X0
                        & aNaturalNumber0(X2) )
                    & aNaturalNumber0(X1) )
                 => ( X0 = X1
                    | sz10 = X1 ) )
              & sz10 != X0
              & sz00 != X0 ) )
          & ( doDivides0(X0,xk)
            | ? [X1] :
                ( sdtasdt0(X0,X1) = xk
                & aNaturalNumber0(X1) ) )
          & aNaturalNumber0(X0) ) ),
    inference(negated_conjecture,[],[f41]) ).

fof(f41,conjecture,
    ( ( isPrime0(xk)
      & ! [X0] :
          ( ( ( doDivides0(X0,xk)
              | ? [X1] :
                  ( sdtasdt0(X0,X1) = xk
                  & aNaturalNumber0(X1) ) )
            & aNaturalNumber0(X0) )
         => ( xk = X0
            | sz10 = X0 ) ) )
   => ? [X0] :
        ( ( isPrime0(X0)
          | ( ! [X1] :
                ( ( doDivides0(X1,X0)
                  & ? [X2] :
                      ( sdtasdt0(X1,X2) = X0
                      & aNaturalNumber0(X2) )
                  & aNaturalNumber0(X1) )
               => ( X0 = X1
                  | sz10 = X1 ) )
            & sz10 != X0
            & sz00 != X0 ) )
        & ( doDivides0(X0,xk)
          | ? [X1] :
              ( sdtasdt0(X0,X1) = xk
              & aNaturalNumber0(X1) ) )
        & aNaturalNumber0(X0) ) ),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',m__) ).

fof(f326,plain,
    ( ~ isPrime0(xk)
    | ~ aNaturalNumber0(sz10)
    | ~ aNaturalNumber0(xk) ),
    inference(trivial_inequality_removal,[],[f325]) ).

fof(f325,plain,
    ( xk != xk
    | ~ isPrime0(xk)
    | ~ aNaturalNumber0(sz10)
    | ~ aNaturalNumber0(xk) ),
    inference(superposition,[],[f171,f320]) ).

fof(f320,plain,
    xk = sdtasdt0(xk,sz10),
    inference(resolution,[],[f196,f173]) ).

fof(f196,plain,
    ! [X0] :
      ( ~ aNaturalNumber0(X0)
      | sdtasdt0(X0,sz10) = X0 ),
    inference(cnf_transformation,[],[f54]) ).

fof(f54,plain,
    ! [X0] :
      ( ( sdtasdt0(sz10,X0) = X0
        & sdtasdt0(X0,sz10) = X0 )
      | ~ aNaturalNumber0(X0) ),
    inference(ennf_transformation,[],[f11]) ).

fof(f11,axiom,
    ! [X0] :
      ( aNaturalNumber0(X0)
     => ( sdtasdt0(sz10,X0) = X0
        & sdtasdt0(X0,sz10) = X0 ) ),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',m_MulUnit) ).

fof(f171,plain,
    ! [X0,X1] :
      ( sdtasdt0(X0,X1) != xk
      | ~ isPrime0(X0)
      | ~ aNaturalNumber0(X1)
      | ~ aNaturalNumber0(X0) ),
    inference(cnf_transformation,[],[f131]) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.13  % Problem    : NUM482+3 : TPTP v8.2.0. Released v4.0.0.
% 0.12/0.15  % Command    : vampire --mode casc_sat -m 16384 --cores 7 -t %d %s
% 0.15/0.36  % Computer : n003.cluster.edu
% 0.15/0.36  % Model    : x86_64 x86_64
% 0.15/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.36  % Memory   : 8042.1875MB
% 0.15/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36  % CPULimit   : 300
% 0.15/0.36  % WCLimit    : 300
% 0.15/0.36  % DateTime   : Mon May 20 03:45:23 EDT 2024
% 0.15/0.36  % CPUTime    : 
% 0.15/0.36  % (15737)Running in auto input_syntax mode. Trying TPTP
% 0.15/0.38  % (15743)WARNING: value z3 for option sas not known
% 0.15/0.38  % (15741)fmb+10_1_bce=on:fmbas=function:fmbsr=1.2:fde=unused:nm=0_846 on theBenchmark for (846ds/0Mi)
% 0.15/0.38  % (15744)fmb+10_1_bce=on:fmbsr=1.5:nm=32_533 on theBenchmark for (533ds/0Mi)
% 0.15/0.38  % (15745)ott+10_10:1_add=off:afr=on:amm=off:anc=all:bd=off:bs=on:fsr=off:irw=on:lma=on:msp=off:nm=4:nwc=4.0:sac=on:sp=reverse_frequency_531 on theBenchmark for (531ds/0Mi)
% 0.15/0.38  % (15746)ott-10_8_av=off:bd=preordered:bs=on:fsd=off:fsr=off:fde=unused:irw=on:lcm=predicate:lma=on:nm=4:nwc=1.7:sp=frequency_522 on theBenchmark for (522ds/0Mi)
% 0.15/0.38  % (15743)dis+2_11_add=large:afr=on:amm=off:bd=off:bce=on:fsd=off:fde=none:gs=on:gsaa=full_model:gsem=off:irw=on:msp=off:nm=4:nwc=1.3:sas=z3:sims=off:sac=on:sp=reverse_arity_569 on theBenchmark for (569ds/0Mi)
% 0.15/0.38  % (15742)fmb+10_1_bce=on:fmbdsb=on:fmbes=contour:fmbswr=3:fde=none:nm=0_793 on theBenchmark for (793ds/0Mi)
% 0.15/0.39  Detected minimum model sizes of [3]
% 0.15/0.39  Detected maximum model sizes of [max]
% 0.15/0.39  Detected minimum model sizes of [3]
% 0.15/0.39  Detected maximum model sizes of [max]
% 0.15/0.39  % (15747)ott+1_64_av=off:bd=off:bce=on:fsd=off:fde=unused:gsp=on:irw=on:lcm=predicate:lma=on:nm=2:nwc=1.1:sims=off:urr=on_497 on theBenchmark for (497ds/0Mi)
% 0.15/0.39  % (15746)First to succeed.
% 0.15/0.39  TRYING [3]
% 0.15/0.39  TRYING [3]
% 0.15/0.39  % (15746)Solution written to "/export/starexec/sandbox2/tmp/vampire-proof-15737"
% 0.15/0.39  % (15746)Refutation found. Thanks to Tanya!
% 0.15/0.39  % SZS status Theorem for theBenchmark
% 0.15/0.39  % SZS output start Proof for theBenchmark
% See solution above
% 0.15/0.39  % (15746)------------------------------
% 0.15/0.39  % (15746)Version: Vampire 4.8 (commit 3a798227e on 2024-05-03 07:42:47 +0200)
% 0.15/0.39  % (15746)Termination reason: Refutation
% 0.15/0.39  
% 0.15/0.39  % (15746)Memory used [KB]: 997
% 0.15/0.39  % (15746)Time elapsed: 0.010 s
% 0.15/0.39  % (15746)Instructions burned: 14 (million)
% 0.15/0.39  % (15737)Success in time 0.028 s
%------------------------------------------------------------------------------