%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM480+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:26:38 EDT 2022

% Result   : Theorem 0.20s 0.55s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   11 (   9 unt;   0 nHn;  11 RR)
%            Number of literals    :   17 (   0 equ;   7 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    4 (   2 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    8 (   8 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(3,axiom,
    aNaturalNumber0(xl),
    file('NUM480+2.p',unknown),
    [] ).

cnf(6,axiom,
    aNaturalNumber0(xn),
    file('NUM480+2.p',unknown),
    [] ).

cnf(13,axiom,
    aNaturalNumber0(sdtsldt0(xm,xl)),
    file('NUM480+2.p',unknown),
    [] ).

cnf(27,axiom,
    equal(sdtasdt0(xl,sdtsldt0(sdtasdt0(xn,xm),xl)),sdtasdt0(xn,xm)),
    file('NUM480+2.p',unknown),
    [] ).

cnf(28,axiom,
    ~ equal(sdtasdt0(xl,sdtasdt0(xn,sdtsldt0(xm,xl))),sdtasdt0(xn,xm)),
    file('NUM480+2.p',unknown),
    [] ).

cnf(39,axiom,
    equal(sdtasdt0(xl,sdtsldt0(sdtasdt0(xn,xm),xl)),sdtasdt0(sdtasdt0(xl,xn),sdtsldt0(xm,xl))),
    file('NUM480+2.p',unknown),
    [] ).

cnf(53,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(v)
    | ~ aNaturalNumber0(w)
    | equal(sdtasdt0(sdtasdt0(w,v),u),sdtasdt0(w,sdtasdt0(v,u))) ),
    file('NUM480+2.p',unknown),
    [] ).

cnf(74,plain,
    equal(sdtasdt0(sdtasdt0(xl,xn),sdtsldt0(xm,xl)),sdtasdt0(xn,xm)),
    inference(rew,[status(thm),theory(equality)],[27,39]),
    [iquote('0:Rew:27.0,39.0')] ).

cnf(1221,plain,
    ( ~ aNaturalNumber0(sdtsldt0(xm,xl))
    | ~ aNaturalNumber0(xn)
    | ~ aNaturalNumber0(xl)
    | equal(sdtasdt0(xl,sdtasdt0(xn,sdtsldt0(xm,xl))),sdtasdt0(xn,xm)) ),
    inference(spr,[status(thm),theory(equality)],[53,74]),
    [iquote('0:SpR:53.3,74.0')] ).

cnf(1249,plain,
    equal(sdtasdt0(xl,sdtasdt0(xn,sdtsldt0(xm,xl))),sdtasdt0(xn,xm)),
    inference(ssi,[status(thm)],[1221,3,6,13]),
    [iquote('0:SSi:1221.2,1221.1,1221.0,3.0,6.0,13.0')] ).

cnf(1250,plain,
    $false,
    inference(mrr,[status(thm)],[1249,28]),
    [iquote('0:MRR:1249.0,28.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : NUM480+2 : TPTP v8.1.0. Released v4.0.0.
% 0.12/0.13  % Command  : run_spass %d %s
% 0.12/0.34  % Computer : n026.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Thu Jul  7 21:59:39 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.20/0.55  
% 0.20/0.55  SPASS V 3.9 
% 0.20/0.55  SPASS beiseite: Proof found.
% 0.20/0.55  % SZS status Theorem
% 0.20/0.55  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.20/0.55  SPASS derived 748 clauses, backtracked 98 clauses, performed 6 splits and kept 434 clauses.
% 0.20/0.55  SPASS allocated 98561 KBytes.
% 0.20/0.55  SPASS spent	0:00:00.19 on the problem.
% 0.20/0.55  		0:00:00.04 for the input.
% 0.20/0.55  		0:00:00.04 for the FLOTTER CNF translation.
% 0.20/0.55  		0:00:00.01 for inferences.
% 0.20/0.55  		0:00:00.00 for the backtracking.
% 0.20/0.55  		0:00:00.08 for the reduction.
% 0.20/0.55  
% 0.20/0.55  
% 0.20/0.55  Here is a proof with depth 1, length 11 :
% 0.20/0.55  % SZS output start Refutation
% See solution above
% 0.20/0.55  Formulae used in the proof : m__1524 m__1553 m__1594 m__ mMulAsso
% 0.20/0.55  
%------------------------------------------------------------------------------