TSTP Solution File: NUM472+1 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM472+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n010.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:26:32 EDT 2022

% Result   : Theorem 0.19s 0.46s
% Output   : Refutation 0.19s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   11 (   5 unt;   0 nHn;  11 RR)
%            Number of literals    :   26 (   0 equ;  21 neg)
%            Maximal clause size   :    5 (   2 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   5 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(4,axiom,
    aNaturalNumber0(xm),
    file('NUM472+1.p',unknown),
    [] ).

cnf(5,axiom,
    aNaturalNumber0(xn),
    file('NUM472+1.p',unknown),
    [] ).

cnf(13,axiom,
    ~ sdtlseqdt0(xm,sdtpldt0(xm,xn)),
    file('NUM472+1.p',unknown),
    [] ).

cnf(22,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(v)
    | aNaturalNumber0(sdtpldt0(v,u)) ),
    file('NUM472+1.p',unknown),
    [] ).

cnf(38,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(v)
    | ~ aNaturalNumber0(w)
    | ~ equal(sdtpldt0(v,w),u)
    | sdtlseqdt0(v,u) ),
    file('NUM472+1.p',unknown),
    [] ).

cnf(71,plain,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(xm)
    | ~ aNaturalNumber0(sdtpldt0(xm,xn))
    | ~ equal(sdtpldt0(xm,u),sdtpldt0(xm,xn)) ),
    inference(res,[status(thm),theory(equality)],[38,13]),
    [iquote('0:Res:38.4,13.0')] ).

cnf(74,plain,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(sdtpldt0(xm,xn))
    | ~ equal(sdtpldt0(xm,u),sdtpldt0(xm,xn)) ),
    inference(mrr,[status(thm)],[71,4]),
    [iquote('0:MRR:71.1,4.0')] ).

cnf(186,plain,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(xm)
    | ~ aNaturalNumber0(xn)
    | ~ equal(sdtpldt0(xm,u),sdtpldt0(xm,xn)) ),
    inference(sor,[status(thm)],[74,22]),
    [iquote('0:SoR:74.1,22.2')] ).

cnf(187,plain,
    ( ~ aNaturalNumber0(u)
    | ~ equal(sdtpldt0(xm,u),sdtpldt0(xm,xn)) ),
    inference(ssi,[status(thm)],[186,5,4]),
    [iquote('0:SSi:186.2,186.1,5.0,4.0')] ).

cnf(188,plain,
    ~ aNaturalNumber0(xn),
    inference(eqr,[status(thm),theory(equality)],[187]),
    [iquote('0:EqR:187.1')] ).

cnf(191,plain,
    $false,
    inference(ssi,[status(thm)],[188,5]),
    [iquote('0:SSi:188.0,5.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : NUM472+1 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.12  % Command  : run_spass %d %s
% 0.13/0.33  % Computer : n010.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Thu Jul  7 09:56:31 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 0.19/0.46  
% 0.19/0.46  SPASS V 3.9 
% 0.19/0.46  SPASS beiseite: Proof found.
% 0.19/0.46  % SZS status Theorem
% 0.19/0.46  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.19/0.46  SPASS derived 85 clauses, backtracked 0 clauses, performed 0 splits and kept 71 clauses.
% 0.19/0.46  SPASS allocated 97835 KBytes.
% 0.19/0.46  SPASS spent	0:00:00.12 on the problem.
% 0.19/0.46  		0:00:00.04 for the input.
% 0.19/0.46  		0:00:00.04 for the FLOTTER CNF translation.
% 0.19/0.46  		0:00:00.00 for inferences.
% 0.19/0.46  		0:00:00.00 for the backtracking.
% 0.19/0.46  		0:00:00.01 for the reduction.
% 0.19/0.46  
% 0.19/0.46  
% 0.19/0.46  Here is a proof with depth 3, length 11 :
% 0.19/0.46  % SZS output start Refutation
% See solution above
% 0.19/0.46  Formulae used in the proof : m__1324 m__ mSortsB mDefLE
% 0.19/0.46  
%------------------------------------------------------------------------------