TSTP Solution File: NUM465+2 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM465+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n006.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:26:28 EDT 2022

% Result   : Theorem 0.37s 0.55s
% Output   : Refutation 0.37s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :   19
%            Number of leaves      :   14
% Syntax   : Number of clauses     :   38 (  18 unt;   9 nHn;  38 RR)
%            Number of literals    :   85 (   0 equ;  48 neg)
%            Maximal clause size   :    7 (   2 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    9 (   9 usr;   7 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    aNaturalNumber0(sz00),
    file('NUM465+2.p',unknown),
    [] ).

cnf(2,axiom,
    aNaturalNumber0(sz10),
    file('NUM465+2.p',unknown),
    [] ).

cnf(3,axiom,
    aNaturalNumber0(xm),
    file('NUM465+2.p',unknown),
    [] ).

cnf(4,axiom,
    aNaturalNumber0(xn),
    file('NUM465+2.p',unknown),
    [] ).

cnf(6,axiom,
    ~ equal(xm,sz00),
    file('NUM465+2.p',unknown),
    [] ).

cnf(9,axiom,
    ~ sdtlseqdt0(xn,sdtasdt0(xn,xm)),
    file('NUM465+2.p',unknown),
    [] ).

cnf(11,axiom,
    ( sdtlseqdt0(sz10,xm)
    | equal(xm,sz00) ),
    file('NUM465+2.p',unknown),
    [] ).

cnf(12,axiom,
    ( ~ aNaturalNumber0(u)
    | equal(sdtpldt0(u,sz00),u) ),
    file('NUM465+2.p',unknown),
    [] ).

cnf(14,axiom,
    ( ~ aNaturalNumber0(u)
    | equal(sdtasdt0(u,sz10),u) ),
    file('NUM465+2.p',unknown),
    [] ).

cnf(17,axiom,
    ( ~ aNaturalNumber0(u)
    | equal(sdtasdt0(sz00,u),sz00) ),
    file('NUM465+2.p',unknown),
    [] ).

cnf(21,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ equal(sdtpldt0(xn,u),sdtasdt0(xn,xm)) ),
    file('NUM465+2.p',unknown),
    [] ).

cnf(26,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(v)
    | ~ equal(u,v)
    | sdtlseqdt0(v,u) ),
    file('NUM465+2.p',unknown),
    [] ).

cnf(43,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(v)
    | ~ aNaturalNumber0(w)
    | ~ sdtlseqdt0(w,u)
    | equal(w,u)
    | sdtlseqdt0(sdtpldt0(w,v),sdtpldt0(u,v)) ),
    file('NUM465+2.p',unknown),
    [] ).

cnf(51,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(v)
    | ~ aNaturalNumber0(w)
    | ~ sdtlseqdt0(v,u)
    | equal(v,u)
    | equal(w,sz00)
    | sdtlseqdt0(sdtasdt0(w,v),sdtasdt0(w,u)) ),
    file('NUM465+2.p',unknown),
    [] ).

cnf(54,plain,
    sdtlseqdt0(sz10,xm),
    inference(mrr,[status(thm)],[11,6]),
    [iquote('0:MRR:11.1,6.0')] ).

cnf(63,plain,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(sz10)
    | ~ aNaturalNumber0(xm)
    | sdtlseqdt0(sdtasdt0(u,sz10),sdtasdt0(u,xm))
    | equal(u,sz00)
    | equal(xm,sz10) ),
    inference(res,[status(thm),theory(equality)],[54,51]),
    [iquote('0:Res:54.0,51.3')] ).

cnf(67,plain,
    ( ~ aNaturalNumber0(sz10)
    | ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(xm)
    | sdtlseqdt0(sdtpldt0(sz10,u),sdtpldt0(xm,u))
    | equal(xm,sz10) ),
    inference(res,[status(thm),theory(equality)],[54,43]),
    [iquote('0:Res:54.0,43.3')] ).

cnf(109,plain,
    ~ equal(sdtasdt0(xn,xm),sdtpldt0(xn,sz00)),
    inference(res,[status(thm),theory(equality)],[1,21]),
    [iquote('0:Res:1.0,21.0')] ).

cnf(136,plain,
    ( ~ aNaturalNumber0(u)
    | equal(xm,sz10)
    | sdtlseqdt0(sdtpldt0(sz10,u),sdtpldt0(xm,u)) ),
    inference(mrr,[status(thm)],[67,2,3]),
    [iquote('0:MRR:67.0,67.2,2.0,3.0')] ).

cnf(154,plain,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(sz10)
    | ~ aNaturalNumber0(xm)
    | sdtlseqdt0(u,sdtasdt0(u,xm))
    | equal(u,sz00)
    | equal(xm,sz10) ),
    inference(rew,[status(thm),theory(equality)],[14,63]),
    [iquote('0:Rew:14.1,63.3')] ).

cnf(155,plain,
    ( ~ aNaturalNumber0(u)
    | equal(u,sz00)
    | sdtlseqdt0(u,sdtasdt0(u,xm))
    | equal(xm,sz10) ),
    inference(mrr,[status(thm)],[154,2,3]),
    [iquote('0:MRR:154.1,154.2,2.0,3.0')] ).

cnf(166,plain,
    equal(xm,sz10),
    inference(spt,[spt(split,[position(s1)])],[136]),
    [iquote('1:Spt:136.1')] ).

cnf(168,plain,
    ~ equal(sdtasdt0(xn,sz10),sdtpldt0(xn,sz00)),
    inference(rew,[status(thm),theory(equality)],[166,109]),
    [iquote('1:Rew:166.0,109.0')] ).

cnf(234,plain,
    ( ~ aNaturalNumber0(xn)
    | ~ equal(sdtpldt0(xn,sz00),xn) ),
    inference(spl,[status(thm),theory(equality)],[14,168]),
    [iquote('1:SpL:14.1,168.0')] ).

cnf(239,plain,
    ( ~ aNaturalNumber0(xn)
    | ~ equal(xn,xn) ),
    inference(rew,[status(thm),theory(equality)],[12,234]),
    [iquote('1:Rew:12.1,234.1')] ).

cnf(240,plain,
    ~ aNaturalNumber0(xn),
    inference(obv,[status(thm),theory(equality)],[239]),
    [iquote('1:Obv:239.1')] ).

cnf(241,plain,
    $false,
    inference(ssi,[status(thm)],[240,4]),
    [iquote('1:SSi:240.0,4.0')] ).

cnf(244,plain,
    ~ equal(xm,sz10),
    inference(spt,[spt(split,[position(sa)])],[241,166]),
    [iquote('1:Spt:241.0,136.1,166.0')] ).

cnf(245,plain,
    ( ~ aNaturalNumber0(u)
    | sdtlseqdt0(sdtpldt0(sz10,u),sdtpldt0(xm,u)) ),
    inference(spt,[spt(split,[position(s2)])],[136]),
    [iquote('1:Spt:241.0,136.0,136.2')] ).

cnf(248,plain,
    ( ~ aNaturalNumber0(u)
    | equal(u,sz00)
    | sdtlseqdt0(u,sdtasdt0(u,xm)) ),
    inference(mrr,[status(thm)],[155,244]),
    [iquote('1:MRR:155.3,244.0')] ).

cnf(899,plain,
    ( ~ aNaturalNumber0(xn)
    | equal(xn,sz00) ),
    inference(res,[status(thm),theory(equality)],[248,9]),
    [iquote('1:Res:248.2,9.0')] ).

cnf(900,plain,
    equal(xn,sz00),
    inference(ssi,[status(thm)],[899,4]),
    [iquote('1:SSi:899.0,4.0')] ).

cnf(903,plain,
    ~ sdtlseqdt0(sz00,sdtasdt0(sz00,xm)),
    inference(rew,[status(thm),theory(equality)],[900,9]),
    [iquote('1:Rew:900.0,9.0')] ).

cnf(949,plain,
    ( ~ aNaturalNumber0(xm)
    | ~ sdtlseqdt0(sz00,sz00) ),
    inference(spl,[status(thm),theory(equality)],[17,903]),
    [iquote('1:SpL:17.1,903.0')] ).

cnf(952,plain,
    ~ sdtlseqdt0(sz00,sz00),
    inference(ssi,[status(thm)],[949,3]),
    [iquote('1:SSi:949.0,3.0')] ).

cnf(955,plain,
    ( ~ aNaturalNumber0(sz00)
    | ~ aNaturalNumber0(sz00)
    | ~ equal(sz00,sz00) ),
    inference(res,[status(thm),theory(equality)],[26,952]),
    [iquote('1:Res:26.3,952.0')] ).

cnf(957,plain,
    ~ aNaturalNumber0(sz00),
    inference(obv,[status(thm),theory(equality)],[955]),
    [iquote('1:Obv:955.2')] ).

cnf(958,plain,
    $false,
    inference(ssi,[status(thm)],[957,1]),
    [iquote('1:SSi:957.0,1.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : NUM465+2 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.13  % Command  : run_spass %d %s
% 0.12/0.34  % Computer : n006.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Wed Jul  6 00:31:22 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.37/0.55  
% 0.37/0.55  SPASS V 3.9 
% 0.37/0.55  SPASS beiseite: Proof found.
% 0.37/0.55  % SZS status Theorem
% 0.37/0.55  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.37/0.55  SPASS derived 560 clauses, backtracked 44 clauses, performed 1 splits and kept 322 clauses.
% 0.37/0.55  SPASS allocated 98399 KBytes.
% 0.37/0.55  SPASS spent	0:00:00.19 on the problem.
% 0.37/0.55  		0:00:00.04 for the input.
% 0.37/0.55  		0:00:00.04 for the FLOTTER CNF translation.
% 0.37/0.55  		0:00:00.01 for inferences.
% 0.37/0.55  		0:00:00.00 for the backtracking.
% 0.37/0.55  		0:00:00.07 for the reduction.
% 0.37/0.55  
% 0.37/0.55  
% 0.37/0.55  Here is a proof with depth 2, length 38 :
% 0.37/0.55  % SZS output start Refutation
% See solution above
% 0.37/0.55  Formulae used in the proof : mSortsC mSortsC_01 m__987 m__ m__1007 m_AddZero m_MulUnit m_MulZero mLETotal mMonAdd mMonMul
% 0.37/0.55  
%------------------------------------------------------------------------------