TSTP Solution File: NUM464+1 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM464+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:26:27 EDT 2022

% Result   : Theorem 0.18s 0.45s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   11 (   8 unt;   2 nHn;  11 RR)
%            Number of literals    :   17 (   0 equ;   7 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   4 con; 0-0 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(2,axiom,
    aNaturalNumber0(sz10),
    file('NUM464+1.p',unknown),
    [] ).

cnf(3,axiom,
    aNaturalNumber0(xm),
    file('NUM464+1.p',unknown),
    [] ).

cnf(5,axiom,
    ~ equal(xm,sz00),
    file('NUM464+1.p',unknown),
    [] ).

cnf(6,axiom,
    ~ sdtlseqdt0(sz10,xm),
    file('NUM464+1.p',unknown),
    [] ).

cnf(9,axiom,
    ( ~ aNaturalNumber0(u)
    | sdtlseqdt0(u,u) ),
    file('NUM464+1.p',unknown),
    [] ).

cnf(19,axiom,
    ( ~ aNaturalNumber0(u)
    | equal(u,sz10)
    | equal(u,sz00)
    | sdtlseqdt0(sz10,u) ),
    file('NUM464+1.p',unknown),
    [] ).

cnf(51,plain,
    ( ~ aNaturalNumber0(xm)
    | equal(xm,sz00)
    | equal(xm,sz10) ),
    inference(res,[status(thm),theory(equality)],[19,6]),
    [iquote('0:Res:19.1,6.0')] ).

cnf(85,plain,
    equal(xm,sz10),
    inference(mrr,[status(thm)],[51,3,5]),
    [iquote('0:MRR:51.0,51.1,3.0,5.0')] ).

cnf(87,plain,
    ~ sdtlseqdt0(sz10,sz10),
    inference(rew,[status(thm),theory(equality)],[85,6]),
    [iquote('0:Rew:85.0,6.0')] ).

cnf(95,plain,
    ~ aNaturalNumber0(sz10),
    inference(res,[status(thm),theory(equality)],[9,87]),
    [iquote('0:Res:9.1,87.0')] ).

cnf(96,plain,
    $false,
    inference(ssi,[status(thm)],[95,2]),
    [iquote('0:SSi:95.0,2.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.11  % Problem  : NUM464+1 : TPTP v8.1.0. Released v4.0.0.
% 0.08/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n020.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Tue Jul  5 11:35:29 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.18/0.45  
% 0.18/0.45  SPASS V 3.9 
% 0.18/0.45  SPASS beiseite: Proof found.
% 0.18/0.45  % SZS status Theorem
% 0.18/0.45  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.18/0.45  SPASS derived 39 clauses, backtracked 0 clauses, performed 0 splits and kept 49 clauses.
% 0.18/0.45  SPASS allocated 97783 KBytes.
% 0.18/0.45  SPASS spent	0:00:00.10 on the problem.
% 0.18/0.45  		0:00:00.04 for the input.
% 0.18/0.45  		0:00:00.04 for the FLOTTER CNF translation.
% 0.18/0.45  		0:00:00.00 for inferences.
% 0.18/0.45  		0:00:00.00 for the backtracking.
% 0.18/0.45  		0:00:00.00 for the reduction.
% 0.18/0.45  
% 0.18/0.45  
% 0.18/0.45  Here is a proof with depth 1, length 11 :
% 0.18/0.45  % SZS output start Refutation
% See solution above
% 0.18/0.45  Formulae used in the proof : mSortsC_01 m__987 m__ mLERefl mLENTr
% 0.18/0.45  
%------------------------------------------------------------------------------