TSTP Solution File: NUM458+2 by Duper---1.0
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% File : Duper---1.0
% Problem : NUM458+2 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n026.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:55:44 EDT 2023
% Result : Theorem 108.50s 108.69s
% Output : Proof 108.50s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : NUM458+2 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14 % Command : duper %s
% 0.14/0.35 % Computer : n026.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Fri Aug 25 09:35:32 EDT 2023
% 0.14/0.36 % CPUTime :
% 108.50/108.69 SZS status Theorem for theBenchmark.p
% 108.50/108.69 SZS output start Proof for theBenchmark.p
% 108.50/108.69 Clause #1 (by assumption #[]): Eq (aNaturalNumber0 sz00) True
% 108.50/108.69 Clause #5 (by assumption #[]): Eq (∀ (W0 W1 : Iota), And (aNaturalNumber0 W0) (aNaturalNumber0 W1) → Eq (sdtpldt0 W0 W1) (sdtpldt0 W1 W0)) True
% 108.50/108.69 Clause #7 (by assumption #[]): Eq (∀ (W0 : Iota), aNaturalNumber0 W0 → And (Eq (sdtpldt0 W0 sz00) W0) (Eq W0 (sdtpldt0 sz00 W0))) True
% 108.50/108.69 Clause #19 (by assumption #[]): Eq (aNaturalNumber0 xm) True
% 108.50/108.69 Clause #20 (by assumption #[]): Eq (Not (Or (Exists fun W0 => And (aNaturalNumber0 W0) (Eq (sdtpldt0 xm W0) xm)) (sdtlseqdt0 xm xm))) True
% 108.50/108.69 Clause #56 (by clausification #[5]): ∀ (a : Iota), Eq (∀ (W1 : Iota), And (aNaturalNumber0 a) (aNaturalNumber0 W1) → Eq (sdtpldt0 a W1) (sdtpldt0 W1 a)) True
% 108.50/108.69 Clause #57 (by clausification #[56]): ∀ (a a_1 : Iota), Eq (And (aNaturalNumber0 a) (aNaturalNumber0 a_1) → Eq (sdtpldt0 a a_1) (sdtpldt0 a_1 a)) True
% 108.50/108.69 Clause #58 (by clausification #[57]): ∀ (a a_1 : Iota),
% 108.50/108.69 Or (Eq (And (aNaturalNumber0 a) (aNaturalNumber0 a_1)) False) (Eq (Eq (sdtpldt0 a a_1) (sdtpldt0 a_1 a)) True)
% 108.50/108.69 Clause #59 (by clausification #[58]): ∀ (a a_1 : Iota),
% 108.50/108.69 Or (Eq (Eq (sdtpldt0 a a_1) (sdtpldt0 a_1 a)) True)
% 108.50/108.69 (Or (Eq (aNaturalNumber0 a) False) (Eq (aNaturalNumber0 a_1) False))
% 108.50/108.69 Clause #60 (by clausification #[59]): ∀ (a a_1 : Iota),
% 108.50/108.69 Or (Eq (aNaturalNumber0 a) False) (Or (Eq (aNaturalNumber0 a_1) False) (Eq (sdtpldt0 a a_1) (sdtpldt0 a_1 a)))
% 108.50/108.69 Clause #61 (by superposition #[60, 19]): ∀ (a : Iota), Or (Eq (aNaturalNumber0 a) False) (Or (Eq (sdtpldt0 xm a) (sdtpldt0 a xm)) (Eq False True))
% 108.50/108.69 Clause #168 (by clausification #[7]): ∀ (a : Iota), Eq (aNaturalNumber0 a → And (Eq (sdtpldt0 a sz00) a) (Eq a (sdtpldt0 sz00 a))) True
% 108.50/108.69 Clause #169 (by clausification #[168]): ∀ (a : Iota), Or (Eq (aNaturalNumber0 a) False) (Eq (And (Eq (sdtpldt0 a sz00) a) (Eq a (sdtpldt0 sz00 a))) True)
% 108.50/108.69 Clause #170 (by clausification #[169]): ∀ (a : Iota), Or (Eq (aNaturalNumber0 a) False) (Eq (Eq a (sdtpldt0 sz00 a)) True)
% 108.50/108.69 Clause #172 (by clausification #[170]): ∀ (a : Iota), Or (Eq (aNaturalNumber0 a) False) (Eq a (sdtpldt0 sz00 a))
% 108.50/108.69 Clause #173 (by superposition #[172, 19]): Or (Eq xm (sdtpldt0 sz00 xm)) (Eq False True)
% 108.50/108.69 Clause #189 (by clausification #[173]): Eq xm (sdtpldt0 sz00 xm)
% 108.50/108.69 Clause #806 (by clausification #[20]): Eq (Or (Exists fun W0 => And (aNaturalNumber0 W0) (Eq (sdtpldt0 xm W0) xm)) (sdtlseqdt0 xm xm)) False
% 108.50/108.69 Clause #808 (by clausification #[806]): Eq (Exists fun W0 => And (aNaturalNumber0 W0) (Eq (sdtpldt0 xm W0) xm)) False
% 108.50/108.69 Clause #1580 (by clausification #[61]): ∀ (a : Iota), Or (Eq (aNaturalNumber0 a) False) (Eq (sdtpldt0 xm a) (sdtpldt0 a xm))
% 108.50/108.69 Clause #1582 (by superposition #[1580, 1]): Or (Eq (sdtpldt0 xm sz00) (sdtpldt0 sz00 xm)) (Eq False True)
% 108.50/108.69 Clause #1634 (by clausification #[1582]): Eq (sdtpldt0 xm sz00) (sdtpldt0 sz00 xm)
% 108.50/108.69 Clause #1635 (by forward demodulation #[1634, 189]): Eq (sdtpldt0 xm sz00) xm
% 108.50/108.69 Clause #36945 (by clausification #[808]): ∀ (a : Iota), Eq (And (aNaturalNumber0 a) (Eq (sdtpldt0 xm a) xm)) False
% 108.50/108.69 Clause #36946 (by clausification #[36945]): ∀ (a : Iota), Or (Eq (aNaturalNumber0 a) False) (Eq (Eq (sdtpldt0 xm a) xm) False)
% 108.50/108.69 Clause #36947 (by clausification #[36946]): ∀ (a : Iota), Or (Eq (aNaturalNumber0 a) False) (Ne (sdtpldt0 xm a) xm)
% 108.50/108.69 Clause #36949 (by superposition #[36947, 1]): Or (Ne (sdtpldt0 xm sz00) xm) (Eq False True)
% 108.50/108.69 Clause #37301 (by clausification #[36949]): Ne (sdtpldt0 xm sz00) xm
% 108.50/108.69 Clause #37302 (by forward demodulation #[37301, 1635]): Ne xm xm
% 108.50/108.69 Clause #37303 (by eliminate resolved literals #[37302]): False
% 108.50/108.69 SZS output end Proof for theBenchmark.p
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