TSTP Solution File: NUM458+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM458+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:26:23 EDT 2022

% Result   : Theorem 0.19s 0.45s
% Output   : Refutation 0.19s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   11 (   4 unt;   0 nHn;  11 RR)
%            Number of literals    :   25 (   0 equ;  20 neg)
%            Maximal clause size   :    5 (   2 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   5 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    aNaturalNumber0(sz00),
    file('NUM458+1.p',unknown),
    [] ).

cnf(3,axiom,
    aNaturalNumber0(xm),
    file('NUM458+1.p',unknown),
    [] ).

cnf(4,axiom,
    ~ sdtlseqdt0(xm,xm),
    file('NUM458+1.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ aNaturalNumber0(u)
    | equal(sdtpldt0(u,sz00),u) ),
    file('NUM458+1.p',unknown),
    [] ).

cnf(21,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(v)
    | ~ aNaturalNumber0(w)
    | ~ equal(sdtpldt0(v,w),u)
    | sdtlseqdt0(v,u) ),
    file('NUM458+1.p',unknown),
    [] ).

cnf(34,plain,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(xm)
    | ~ aNaturalNumber0(xm)
    | ~ equal(sdtpldt0(xm,u),xm) ),
    inference(res,[status(thm),theory(equality)],[21,4]),
    [iquote('0:Res:21.4,4.0')] ).

cnf(35,plain,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(xm)
    | ~ equal(sdtpldt0(xm,u),xm) ),
    inference(obv,[status(thm),theory(equality)],[34]),
    [iquote('0:Obv:34.1')] ).

cnf(36,plain,
    ( ~ aNaturalNumber0(u)
    | ~ equal(sdtpldt0(xm,u),xm) ),
    inference(mrr,[status(thm)],[35,3]),
    [iquote('0:MRR:35.1,3.0')] ).

cnf(48,plain,
    ( ~ aNaturalNumber0(xm)
    | ~ aNaturalNumber0(sz00)
    | ~ equal(xm,xm) ),
    inference(spl,[status(thm),theory(equality)],[7,36]),
    [iquote('0:SpL:7.1,36.1')] ).

cnf(49,plain,
    ( ~ aNaturalNumber0(xm)
    | ~ aNaturalNumber0(sz00) ),
    inference(obv,[status(thm),theory(equality)],[48]),
    [iquote('0:Obv:48.2')] ).

cnf(50,plain,
    $false,
    inference(ssi,[status(thm)],[49,1,3]),
    [iquote('0:SSi:49.1,49.0,1.0,3.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : NUM458+1 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n027.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Tue Jul  5 11:21:42 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.19/0.45  
% 0.19/0.45  SPASS V 3.9 
% 0.19/0.45  SPASS beiseite: Proof found.
% 0.19/0.45  % SZS status Theorem
% 0.19/0.45  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.19/0.45  SPASS derived 13 clauses, backtracked 0 clauses, performed 0 splits and kept 34 clauses.
% 0.19/0.45  SPASS allocated 97758 KBytes.
% 0.19/0.45  SPASS spent	0:00:00.10 on the problem.
% 0.19/0.45  		0:00:00.04 for the input.
% 0.19/0.45  		0:00:00.03 for the FLOTTER CNF translation.
% 0.19/0.45  		0:00:00.00 for inferences.
% 0.19/0.45  		0:00:00.00 for the backtracking.
% 0.19/0.45  		0:00:00.00 for the reduction.
% 0.19/0.45  
% 0.19/0.45  
% 0.19/0.45  Here is a proof with depth 2, length 11 :
% 0.19/0.45  % SZS output start Refutation
% See solution above
% 0.19/0.45  Formulae used in the proof : mSortsC m__718 m__ m_AddZero mDefLE
% 0.19/0.45  
%------------------------------------------------------------------------------