TSTP Solution File: NUM458+1 by SInE---0.4

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%------------------------------------------------------------------------------
% File     : SInE---0.4
% Problem  : NUM458+1 : TPTP v7.0.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : Source/sine.py -e eprover -t %d %s

% Computer : n142.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.625MB
% OS       : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan  8 15:21:24 EST 2018

% Result   : Theorem 0.06s
% Output   : CNFRefutation 0.06s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :   14
%            Number of leaves      :    5
% Syntax   : Number of formulae    :   28 (  12 unt;   0 def)
%            Number of atoms       :   98 (   5 equ)
%            Maximal formula atoms :   13 (   3 avg)
%            Number of connectives :  124 (  54   ~;  51   |;  16   &)
%                                         (   1 <=>;   2  =>;   0  <=;   0 <~>)
%            Maximal formula depth :   10 (   4 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    5 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-2 aty)
%            Number of variables   :   35 (   0 sgn  21   !;   3   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(1,axiom,
    aNaturalNumber0(sz00),
    file('/export/starexec/sandbox/tmp/tmpPN1dFA/sel_theBenchmark.p_1',mSortsC) ).

fof(5,axiom,
    ! [X1,X2] :
      ( ( aNaturalNumber0(X1)
        & aNaturalNumber0(X2) )
     => ( sdtlseqdt0(X1,X2)
      <=> ? [X3] :
            ( aNaturalNumber0(X3)
            & equal(sdtpldt0(X1,X3),X2) ) ) ),
    file('/export/starexec/sandbox/tmp/tmpPN1dFA/sel_theBenchmark.p_1',mDefLE) ).

fof(7,axiom,
    aNaturalNumber0(xm),
    file('/export/starexec/sandbox/tmp/tmpPN1dFA/sel_theBenchmark.p_1',m__718) ).

fof(13,conjecture,
    sdtlseqdt0(xm,xm),
    file('/export/starexec/sandbox/tmp/tmpPN1dFA/sel_theBenchmark.p_1',m__) ).

fof(14,axiom,
    ! [X1] :
      ( aNaturalNumber0(X1)
     => ( equal(sdtpldt0(X1,sz00),X1)
        & equal(X1,sdtpldt0(sz00,X1)) ) ),
    file('/export/starexec/sandbox/tmp/tmpPN1dFA/sel_theBenchmark.p_1',m_AddZero) ).

fof(22,negated_conjecture,
    ~ sdtlseqdt0(xm,xm),
    inference(assume_negation,[status(cth)],[13]) ).

fof(23,negated_conjecture,
    ~ sdtlseqdt0(xm,xm),
    inference(fof_simplification,[status(thm)],[22,theory(equality)]) ).

cnf(24,plain,
    aNaturalNumber0(sz00),
    inference(split_conjunct,[status(thm)],[1]) ).

fof(36,plain,
    ! [X1,X2] :
      ( ~ aNaturalNumber0(X1)
      | ~ aNaturalNumber0(X2)
      | ( ( ~ sdtlseqdt0(X1,X2)
          | ? [X3] :
              ( aNaturalNumber0(X3)
              & equal(sdtpldt0(X1,X3),X2) ) )
        & ( ! [X3] :
              ( ~ aNaturalNumber0(X3)
              | ~ equal(sdtpldt0(X1,X3),X2) )
          | sdtlseqdt0(X1,X2) ) ) ),
    inference(fof_nnf,[status(thm)],[5]) ).

fof(37,plain,
    ! [X4,X5] :
      ( ~ aNaturalNumber0(X4)
      | ~ aNaturalNumber0(X5)
      | ( ( ~ sdtlseqdt0(X4,X5)
          | ? [X6] :
              ( aNaturalNumber0(X6)
              & equal(sdtpldt0(X4,X6),X5) ) )
        & ( ! [X7] :
              ( ~ aNaturalNumber0(X7)
              | ~ equal(sdtpldt0(X4,X7),X5) )
          | sdtlseqdt0(X4,X5) ) ) ),
    inference(variable_rename,[status(thm)],[36]) ).

fof(38,plain,
    ! [X4,X5] :
      ( ~ aNaturalNumber0(X4)
      | ~ aNaturalNumber0(X5)
      | ( ( ~ sdtlseqdt0(X4,X5)
          | ( aNaturalNumber0(esk1_2(X4,X5))
            & equal(sdtpldt0(X4,esk1_2(X4,X5)),X5) ) )
        & ( ! [X7] :
              ( ~ aNaturalNumber0(X7)
              | ~ equal(sdtpldt0(X4,X7),X5) )
          | sdtlseqdt0(X4,X5) ) ) ),
    inference(skolemize,[status(esa)],[37]) ).

fof(39,plain,
    ! [X4,X5,X7] :
      ( ( ( ~ aNaturalNumber0(X7)
          | ~ equal(sdtpldt0(X4,X7),X5)
          | sdtlseqdt0(X4,X5) )
        & ( ~ sdtlseqdt0(X4,X5)
          | ( aNaturalNumber0(esk1_2(X4,X5))
            & equal(sdtpldt0(X4,esk1_2(X4,X5)),X5) ) ) )
      | ~ aNaturalNumber0(X4)
      | ~ aNaturalNumber0(X5) ),
    inference(shift_quantors,[status(thm)],[38]) ).

fof(40,plain,
    ! [X4,X5,X7] :
      ( ( ~ aNaturalNumber0(X7)
        | ~ equal(sdtpldt0(X4,X7),X5)
        | sdtlseqdt0(X4,X5)
        | ~ aNaturalNumber0(X4)
        | ~ aNaturalNumber0(X5) )
      & ( aNaturalNumber0(esk1_2(X4,X5))
        | ~ sdtlseqdt0(X4,X5)
        | ~ aNaturalNumber0(X4)
        | ~ aNaturalNumber0(X5) )
      & ( equal(sdtpldt0(X4,esk1_2(X4,X5)),X5)
        | ~ sdtlseqdt0(X4,X5)
        | ~ aNaturalNumber0(X4)
        | ~ aNaturalNumber0(X5) ) ),
    inference(distribute,[status(thm)],[39]) ).

cnf(43,plain,
    ( sdtlseqdt0(X2,X1)
    | ~ aNaturalNumber0(X1)
    | ~ aNaturalNumber0(X2)
    | sdtpldt0(X2,X3) != X1
    | ~ aNaturalNumber0(X3) ),
    inference(split_conjunct,[status(thm)],[40]) ).

cnf(47,plain,
    aNaturalNumber0(xm),
    inference(split_conjunct,[status(thm)],[7]) ).

cnf(65,negated_conjecture,
    ~ sdtlseqdt0(xm,xm),
    inference(split_conjunct,[status(thm)],[23]) ).

fof(66,plain,
    ! [X1] :
      ( ~ aNaturalNumber0(X1)
      | ( equal(sdtpldt0(X1,sz00),X1)
        & equal(X1,sdtpldt0(sz00,X1)) ) ),
    inference(fof_nnf,[status(thm)],[14]) ).

fof(67,plain,
    ! [X2] :
      ( ~ aNaturalNumber0(X2)
      | ( equal(sdtpldt0(X2,sz00),X2)
        & equal(X2,sdtpldt0(sz00,X2)) ) ),
    inference(variable_rename,[status(thm)],[66]) ).

fof(68,plain,
    ! [X2] :
      ( ( equal(sdtpldt0(X2,sz00),X2)
        | ~ aNaturalNumber0(X2) )
      & ( equal(X2,sdtpldt0(sz00,X2))
        | ~ aNaturalNumber0(X2) ) ),
    inference(distribute,[status(thm)],[67]) ).

cnf(70,plain,
    ( sdtpldt0(X1,sz00) = X1
    | ~ aNaturalNumber0(X1) ),
    inference(split_conjunct,[status(thm)],[68]) ).

cnf(189,plain,
    ( sdtlseqdt0(X1,X2)
    | X1 != X2
    | ~ aNaturalNumber0(sz00)
    | ~ aNaturalNumber0(X1)
    | ~ aNaturalNumber0(X2) ),
    inference(spm,[status(thm)],[43,70,theory(equality)]) ).

cnf(194,plain,
    ( sdtlseqdt0(X1,X2)
    | X1 != X2
    | $false
    | ~ aNaturalNumber0(X1)
    | ~ aNaturalNumber0(X2) ),
    inference(rw,[status(thm)],[189,24,theory(equality)]) ).

cnf(195,plain,
    ( sdtlseqdt0(X1,X2)
    | X1 != X2
    | ~ aNaturalNumber0(X1)
    | ~ aNaturalNumber0(X2) ),
    inference(cn,[status(thm)],[194,theory(equality)]) ).

cnf(196,plain,
    ( sdtlseqdt0(X1,X1)
    | ~ aNaturalNumber0(X1) ),
    inference(er,[status(thm)],[195,theory(equality)]) ).

cnf(446,negated_conjecture,
    ~ aNaturalNumber0(xm),
    inference(spm,[status(thm)],[65,196,theory(equality)]) ).

cnf(447,negated_conjecture,
    $false,
    inference(rw,[status(thm)],[446,47,theory(equality)]) ).

cnf(448,negated_conjecture,
    $false,
    inference(cn,[status(thm)],[447,theory(equality)]) ).

cnf(449,negated_conjecture,
    $false,
    448,
    [proof] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : NUM458+1 : TPTP v7.0.0. Released v4.0.0.
% 0.00/0.04  % Command  : Source/sine.py -e eprover -t %d %s
% 0.02/0.23  % Computer : n142.star.cs.uiowa.edu
% 0.02/0.23  % Model    : x86_64 x86_64
% 0.02/0.23  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.23  % Memory   : 32218.625MB
% 0.02/0.23  % OS       : Linux 3.10.0-693.2.2.el7.x86_64
% 0.02/0.23  % CPULimit : 300
% 0.02/0.23  % DateTime : Fri Jan  5 04:31:14 CST 2018
% 0.06/0.23  % CPUTime  : 
% 0.06/0.27  % SZS status Started for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.06/0.27  --creating new selector for []
% 0.06/0.35  -running prover on /export/starexec/sandbox/tmp/tmpPN1dFA/sel_theBenchmark.p_1 with time limit 29
% 0.06/0.35  -running prover with command ['/export/starexec/sandbox/solver/bin/Source/./Source/PROVER/eproof.working', '-s', '-tLPO4', '-xAuto', '-tAuto', '--memory-limit=768', '--tptp3-format', '--cpu-limit=29', '/export/starexec/sandbox/tmp/tmpPN1dFA/sel_theBenchmark.p_1']
% 0.06/0.35  -prover status Theorem
% 0.06/0.35  Problem theBenchmark.p solved in phase 0.
% 0.06/0.35  % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.06/0.35  % SZS status Ended for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.06/0.35  Solved 1 out of 1.
% 0.06/0.35  # Problem is unsatisfiable (or provable), constructing proof object
% 0.06/0.35  # SZS status Theorem
% 0.06/0.35  # SZS output start CNFRefutation.
% See solution above
% 0.06/0.36  # SZS output end CNFRefutation
%------------------------------------------------------------------------------