TSTP Solution File: NUM458+1 by Bliksem---1.12
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%------------------------------------------------------------------------------
% File : Bliksem---1.12
% Problem : NUM458+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : bliksem %s
% Computer : n019.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Mon Jul 18 06:22:27 EDT 2022
% Result : Theorem 0.75s 1.33s
% Output : Refutation 0.75s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12 % Problem : NUM458+1 : TPTP v8.1.0. Released v4.0.0.
% 0.04/0.13 % Command : bliksem %s
% 0.12/0.34 % Computer : n019.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % DateTime : Tue Jul 5 11:09:53 EDT 2022
% 0.12/0.34 % CPUTime :
% 0.75/1.33 *** allocated 10000 integers for termspace/termends
% 0.75/1.33 *** allocated 10000 integers for clauses
% 0.75/1.33 *** allocated 10000 integers for justifications
% 0.75/1.33 Bliksem 1.12
% 0.75/1.33
% 0.75/1.33
% 0.75/1.33 Automatic Strategy Selection
% 0.75/1.33
% 0.75/1.33
% 0.75/1.33 Clauses:
% 0.75/1.33
% 0.75/1.33 { && }.
% 0.75/1.33 { aNaturalNumber0( sz00 ) }.
% 0.75/1.33 { aNaturalNumber0( sz10 ) }.
% 0.75/1.33 { ! sz10 = sz00 }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), aNaturalNumber0( sdtpldt0
% 0.75/1.33 ( X, Y ) ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), aNaturalNumber0( sdtasdt0
% 0.75/1.33 ( X, Y ) ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), sdtpldt0( X, Y ) =
% 0.75/1.33 sdtpldt0( Y, X ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! aNaturalNumber0( Z ),
% 0.75/1.33 sdtpldt0( sdtpldt0( X, Y ), Z ) = sdtpldt0( X, sdtpldt0( Y, Z ) ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), sdtpldt0( X, sz00 ) = X }.
% 0.75/1.33 { ! aNaturalNumber0( X ), X = sdtpldt0( sz00, X ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), sdtasdt0( X, Y ) =
% 0.75/1.33 sdtasdt0( Y, X ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! aNaturalNumber0( Z ),
% 0.75/1.33 sdtasdt0( sdtasdt0( X, Y ), Z ) = sdtasdt0( X, sdtasdt0( Y, Z ) ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), sdtasdt0( X, sz10 ) = X }.
% 0.75/1.33 { ! aNaturalNumber0( X ), X = sdtasdt0( sz10, X ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), sdtasdt0( X, sz00 ) = sz00 }.
% 0.75/1.33 { ! aNaturalNumber0( X ), sz00 = sdtasdt0( sz00, X ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! aNaturalNumber0( Z ),
% 0.75/1.33 sdtasdt0( X, sdtpldt0( Y, Z ) ) = sdtpldt0( sdtasdt0( X, Y ), sdtasdt0( X
% 0.75/1.33 , Z ) ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! aNaturalNumber0( Z ),
% 0.75/1.33 sdtasdt0( sdtpldt0( Y, Z ), X ) = sdtpldt0( sdtasdt0( Y, X ), sdtasdt0( Z
% 0.75/1.33 , X ) ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! aNaturalNumber0( Z ), !
% 0.75/1.33 sdtpldt0( X, Y ) = sdtpldt0( X, Z ), Y = Z }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! aNaturalNumber0( Z ), !
% 0.75/1.33 sdtpldt0( Y, X ) = sdtpldt0( Z, X ), Y = Z }.
% 0.75/1.33 { ! aNaturalNumber0( X ), X = sz00, ! aNaturalNumber0( Y ), !
% 0.75/1.33 aNaturalNumber0( Z ), ! sdtasdt0( X, Y ) = sdtasdt0( X, Z ), Y = Z }.
% 0.75/1.33 { ! aNaturalNumber0( X ), X = sz00, ! aNaturalNumber0( Y ), !
% 0.75/1.33 aNaturalNumber0( Z ), ! sdtasdt0( Y, X ) = sdtasdt0( Z, X ), Y = Z }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! sdtpldt0( X, Y ) = sz00
% 0.75/1.33 , X = sz00 }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! sdtpldt0( X, Y ) = sz00
% 0.75/1.33 , Y = sz00 }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! sdtasdt0( X, Y ) = sz00
% 0.75/1.33 , X = sz00, Y = sz00 }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! sdtlseqdt0( X, Y ),
% 0.75/1.33 aNaturalNumber0( skol1( Z, T ) ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! sdtlseqdt0( X, Y ),
% 0.75/1.33 sdtpldt0( X, skol1( X, Y ) ) = Y }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! aNaturalNumber0( Z ), !
% 0.75/1.33 sdtpldt0( X, Z ) = Y, sdtlseqdt0( X, Y ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! sdtlseqdt0( X, Y ), ! Z
% 0.75/1.33 = sdtmndt0( Y, X ), aNaturalNumber0( Z ) }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! sdtlseqdt0( X, Y ), ! Z
% 0.75/1.33 = sdtmndt0( Y, X ), sdtpldt0( X, Z ) = Y }.
% 0.75/1.33 { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y ), ! sdtlseqdt0( X, Y ), !
% 0.75/1.33 aNaturalNumber0( Z ), ! sdtpldt0( X, Z ) = Y, Z = sdtmndt0( Y, X ) }.
% 0.75/1.33 { aNaturalNumber0( xm ) }.
% 0.75/1.33 { ! sdtlseqdt0( xm, xm ) }.
% 0.75/1.33
% 0.75/1.33 percentage equality = 0.336364, percentage horn = 0.909091
% 0.75/1.33 This is a problem with some equality
% 0.75/1.33
% 0.75/1.33
% 0.75/1.33
% 0.75/1.33 Options Used:
% 0.75/1.33
% 0.75/1.33 useres = 1
% 0.75/1.33 useparamod = 1
% 0.75/1.33 useeqrefl = 1
% 0.75/1.33 useeqfact = 1
% 0.75/1.33 usefactor = 1
% 0.75/1.33 usesimpsplitting = 0
% 0.75/1.33 usesimpdemod = 5
% 0.75/1.33 usesimpres = 3
% 0.75/1.33
% 0.75/1.33 resimpinuse = 1000
% 0.75/1.33 resimpclauses = 20000
% 0.75/1.33 substype = eqrewr
% 0.75/1.33 backwardsubs = 1
% 0.75/1.33 selectoldest = 5
% 0.75/1.33
% 0.75/1.33 litorderings [0] = split
% 0.75/1.33 litorderings [1] = extend the termordering, first sorting on arguments
% 0.75/1.33
% 0.75/1.33 termordering = kbo
% 0.75/1.33
% 0.75/1.33 litapriori = 0
% 0.75/1.33 termapriori = 1
% 0.75/1.33 litaposteriori = 0
% 0.75/1.33 termaposteriori = 0
% 0.75/1.33 demodaposteriori = 0
% 0.75/1.33 ordereqreflfact = 0
% 0.75/1.33
% 0.75/1.33 litselect = negord
% 0.75/1.33
% 0.75/1.33 maxweight = 15
% 0.75/1.33 maxdepth = 30000
% 0.75/1.33 maxlength = 115
% 0.75/1.33 maxnrvars = 195
% 0.75/1.33 excuselevel = 1
% 0.75/1.33 increasemaxweight = 1
% 0.75/1.33
% 0.75/1.33 maxselected = 10000000
% 0.75/1.33 maxnrclauses = 10000000
% 0.75/1.33
% 0.75/1.33 showgenerated = 0
% 0.75/1.33 showkept = 0
% 0.75/1.33 showselected = 0
% 0.75/1.33 showdeleted = 0
% 0.75/1.33 showresimp = 1
% 0.75/1.33 showstatus = 2000
% 0.75/1.33
% 0.75/1.33 prologoutput = 0
% 0.75/1.33 nrgoals = 5000000
% 0.75/1.33 totalproof = 1
% 0.75/1.33
% 0.75/1.33 Symbols occurring in the translation:
% 0.75/1.33
% 0.75/1.33 {} [0, 0] (w:1, o:2, a:1, s:1, b:0),
% 0.75/1.33 . [1, 2] (w:1, o:18, a:1, s:1, b:0),
% 0.75/1.33 && [3, 0] (w:1, o:4, a:1, s:1, b:0),
% 0.75/1.33 ! [4, 1] (w:0, o:12, a:1, s:1, b:0),
% 0.75/1.33 = [13, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.75/1.33 ==> [14, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.75/1.33 aNaturalNumber0 [36, 1] (w:1, o:17, a:1, s:1, b:0),
% 0.75/1.33 sz00 [37, 0] (w:1, o:7, a:1, s:1, b:0),
% 0.75/1.33 sz10 [38, 0] (w:1, o:8, a:1, s:1, b:0),
% 0.75/1.33 sdtpldt0 [40, 2] (w:1, o:42, a:1, s:1, b:0),
% 0.75/1.33 sdtasdt0 [41, 2] (w:1, o:43, a:1, s:1, b:0),
% 0.75/1.33 sdtlseqdt0 [43, 2] (w:1, o:44, a:1, s:1, b:0),
% 0.75/1.33 sdtmndt0 [44, 2] (w:1, o:45, a:1, s:1, b:0),
% 0.75/1.33 xm [45, 0] (w:1, o:11, a:1, s:1, b:0),
% 0.75/1.33 skol1 [46, 2] (w:1, o:46, a:1, s:1, b:1).
% 0.75/1.33
% 0.75/1.33
% 0.75/1.33 Starting Search:
% 0.75/1.33
% 0.75/1.33 *** allocated 15000 integers for clauses
% 0.75/1.33 *** allocated 22500 integers for clauses
% 0.75/1.33 *** allocated 33750 integers for clauses
% 0.75/1.33 *** allocated 50625 integers for clauses
% 0.75/1.33 *** allocated 75937 integers for clauses
% 0.75/1.33 *** allocated 15000 integers for termspace/termends
% 0.75/1.33 Resimplifying inuse:
% 0.75/1.33 Done
% 0.75/1.33
% 0.75/1.33 *** allocated 22500 integers for termspace/termends
% 0.75/1.33 *** allocated 113905 integers for clauses
% 0.75/1.33 *** allocated 33750 integers for termspace/termends
% 0.75/1.33 *** allocated 170857 integers for clauses
% 0.75/1.33
% 0.75/1.33 Intermediate Status:
% 0.75/1.33 Generated: 12816
% 0.75/1.33 Kept: 2045
% 0.75/1.33 Inuse: 101
% 0.75/1.33 Deleted: 38
% 0.75/1.33 Deletedinuse: 13
% 0.75/1.33
% 0.75/1.33 Resimplifying inuse:
% 0.75/1.33 Done
% 0.75/1.33
% 0.75/1.33 *** allocated 50625 integers for termspace/termends
% 0.75/1.33
% 0.75/1.33 Bliksems!, er is een bewijs:
% 0.75/1.33 % SZS status Theorem
% 0.75/1.33 % SZS output start Refutation
% 0.75/1.33
% 0.75/1.33 (1) {G0,W2,D2,L1,V0,M1} I { aNaturalNumber0( sz00 ) }.
% 0.75/1.33 (8) {G0,W7,D3,L2,V1,M2} I { ! aNaturalNumber0( X ), sdtpldt0( X, sz00 ) ==>
% 0.75/1.33 X }.
% 0.75/1.33 (27) {G0,W14,D3,L5,V3,M5} I { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! aNaturalNumber0( Z ), ! sdtpldt0( X, Z ) = Y, sdtlseqdt0( X, Y )
% 0.75/1.33 }.
% 0.75/1.33 (31) {G0,W2,D2,L1,V0,M1} I { aNaturalNumber0( xm ) }.
% 0.75/1.33 (32) {G0,W3,D2,L1,V0,M1} I { ! sdtlseqdt0( xm, xm ) }.
% 0.75/1.33 (1994) {G1,W10,D2,L4,V2,M4} R(27,1);d(8) { ! aNaturalNumber0( X ), !
% 0.75/1.33 aNaturalNumber0( Y ), sdtlseqdt0( X, Y ), ! X = Y }.
% 0.75/1.33 (2030) {G2,W5,D2,L2,V1,M2} F(1994);q { ! aNaturalNumber0( X ), sdtlseqdt0(
% 0.75/1.33 X, X ) }.
% 0.75/1.33 (2392) {G3,W0,D0,L0,V0,M0} R(2030,32);r(31) { }.
% 0.75/1.33
% 0.75/1.33
% 0.75/1.33 % SZS output end Refutation
% 0.75/1.33 found a proof!
% 0.75/1.33
% 0.75/1.33
% 0.75/1.33 Unprocessed initial clauses:
% 0.75/1.33
% 0.75/1.33 (2394) {G0,W1,D1,L1,V0,M1} { && }.
% 0.75/1.33 (2395) {G0,W2,D2,L1,V0,M1} { aNaturalNumber0( sz00 ) }.
% 0.75/1.33 (2396) {G0,W2,D2,L1,V0,M1} { aNaturalNumber0( sz10 ) }.
% 0.75/1.33 (2397) {G0,W3,D2,L1,V0,M1} { ! sz10 = sz00 }.
% 0.75/1.33 (2398) {G0,W8,D3,L3,V2,M3} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), aNaturalNumber0( sdtpldt0( X, Y ) ) }.
% 0.75/1.33 (2399) {G0,W8,D3,L3,V2,M3} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), aNaturalNumber0( sdtasdt0( X, Y ) ) }.
% 0.75/1.33 (2400) {G0,W11,D3,L3,V2,M3} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), sdtpldt0( X, Y ) = sdtpldt0( Y, X ) }.
% 0.75/1.33 (2401) {G0,W17,D4,L4,V3,M4} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! aNaturalNumber0( Z ), sdtpldt0( sdtpldt0( X, Y ), Z ) = sdtpldt0( X
% 0.75/1.33 , sdtpldt0( Y, Z ) ) }.
% 0.75/1.33 (2402) {G0,W7,D3,L2,V1,M2} { ! aNaturalNumber0( X ), sdtpldt0( X, sz00 ) =
% 0.75/1.33 X }.
% 0.75/1.33 (2403) {G0,W7,D3,L2,V1,M2} { ! aNaturalNumber0( X ), X = sdtpldt0( sz00, X
% 0.75/1.33 ) }.
% 0.75/1.33 (2404) {G0,W11,D3,L3,V2,M3} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), sdtasdt0( X, Y ) = sdtasdt0( Y, X ) }.
% 0.75/1.33 (2405) {G0,W17,D4,L4,V3,M4} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! aNaturalNumber0( Z ), sdtasdt0( sdtasdt0( X, Y ), Z ) = sdtasdt0( X
% 0.75/1.33 , sdtasdt0( Y, Z ) ) }.
% 0.75/1.33 (2406) {G0,W7,D3,L2,V1,M2} { ! aNaturalNumber0( X ), sdtasdt0( X, sz10 ) =
% 0.75/1.33 X }.
% 0.75/1.33 (2407) {G0,W7,D3,L2,V1,M2} { ! aNaturalNumber0( X ), X = sdtasdt0( sz10, X
% 0.75/1.33 ) }.
% 0.75/1.33 (2408) {G0,W7,D3,L2,V1,M2} { ! aNaturalNumber0( X ), sdtasdt0( X, sz00 ) =
% 0.75/1.33 sz00 }.
% 0.75/1.33 (2409) {G0,W7,D3,L2,V1,M2} { ! aNaturalNumber0( X ), sz00 = sdtasdt0( sz00
% 0.75/1.33 , X ) }.
% 0.75/1.33 (2410) {G0,W19,D4,L4,V3,M4} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! aNaturalNumber0( Z ), sdtasdt0( X, sdtpldt0( Y, Z ) ) = sdtpldt0(
% 0.75/1.33 sdtasdt0( X, Y ), sdtasdt0( X, Z ) ) }.
% 0.75/1.33 (2411) {G0,W19,D4,L4,V3,M4} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! aNaturalNumber0( Z ), sdtasdt0( sdtpldt0( Y, Z ), X ) = sdtpldt0(
% 0.75/1.33 sdtasdt0( Y, X ), sdtasdt0( Z, X ) ) }.
% 0.75/1.33 (2412) {G0,W16,D3,L5,V3,M5} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! aNaturalNumber0( Z ), ! sdtpldt0( X, Y ) = sdtpldt0( X, Z ), Y = Z
% 0.75/1.33 }.
% 0.75/1.33 (2413) {G0,W16,D3,L5,V3,M5} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! aNaturalNumber0( Z ), ! sdtpldt0( Y, X ) = sdtpldt0( Z, X ), Y = Z
% 0.75/1.33 }.
% 0.75/1.33 (2414) {G0,W19,D3,L6,V3,M6} { ! aNaturalNumber0( X ), X = sz00, !
% 0.75/1.33 aNaturalNumber0( Y ), ! aNaturalNumber0( Z ), ! sdtasdt0( X, Y ) =
% 0.75/1.33 sdtasdt0( X, Z ), Y = Z }.
% 0.75/1.33 (2415) {G0,W19,D3,L6,V3,M6} { ! aNaturalNumber0( X ), X = sz00, !
% 0.75/1.33 aNaturalNumber0( Y ), ! aNaturalNumber0( Z ), ! sdtasdt0( Y, X ) =
% 0.75/1.33 sdtasdt0( Z, X ), Y = Z }.
% 0.75/1.33 (2416) {G0,W12,D3,L4,V2,M4} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! sdtpldt0( X, Y ) = sz00, X = sz00 }.
% 0.75/1.33 (2417) {G0,W12,D3,L4,V2,M4} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! sdtpldt0( X, Y ) = sz00, Y = sz00 }.
% 0.75/1.33 (2418) {G0,W15,D3,L5,V2,M5} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! sdtasdt0( X, Y ) = sz00, X = sz00, Y = sz00 }.
% 0.75/1.33 (2419) {G0,W11,D3,L4,V4,M4} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! sdtlseqdt0( X, Y ), aNaturalNumber0( skol1( Z, T ) ) }.
% 0.75/1.33 (2420) {G0,W14,D4,L4,V2,M4} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! sdtlseqdt0( X, Y ), sdtpldt0( X, skol1( X, Y ) ) = Y }.
% 0.75/1.33 (2421) {G0,W14,D3,L5,V3,M5} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! aNaturalNumber0( Z ), ! sdtpldt0( X, Z ) = Y, sdtlseqdt0( X, Y )
% 0.75/1.33 }.
% 0.75/1.33 (2422) {G0,W14,D3,L5,V3,M5} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! sdtlseqdt0( X, Y ), ! Z = sdtmndt0( Y, X ), aNaturalNumber0( Z )
% 0.75/1.33 }.
% 0.75/1.33 (2423) {G0,W17,D3,L5,V3,M5} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! sdtlseqdt0( X, Y ), ! Z = sdtmndt0( Y, X ), sdtpldt0( X, Z ) = Y
% 0.75/1.33 }.
% 0.75/1.33 (2424) {G0,W19,D3,L6,V3,M6} { ! aNaturalNumber0( X ), ! aNaturalNumber0( Y
% 0.75/1.33 ), ! sdtlseqdt0( X, Y ), ! aNaturalNumber0( Z ), ! sdtpldt0( X, Z ) = Y
% 0.75/1.33 , Z = sdtmndt0( Y, X ) }.
% 0.75/1.33 (2425) {G0,W2,D2,L1,V0,M1} { aNaturalNumber0( xm ) }.
% 0.75/1.33 (2426) {G0,W3,D2,L1,V0,M1} { ! sdtlseqdt0( xm, xm ) }.
% 0.75/1.33
% 0.75/1.33
% 0.75/1.33 Total Proof:
% 0.75/1.33
% 0.75/1.33 subsumption: (1) {G0,W2,D2,L1,V0,M1} I { aNaturalNumber0( sz00 ) }.
% 0.75/1.33 parent0: (2395) {G0,W2,D2,L1,V0,M1} { aNaturalNumber0( sz00 ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 end
% 0.75/1.33 permutation0:
% 0.75/1.33 0 ==> 0
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 subsumption: (8) {G0,W7,D3,L2,V1,M2} I { ! aNaturalNumber0( X ), sdtpldt0(
% 0.75/1.33 X, sz00 ) ==> X }.
% 0.75/1.33 parent0: (2402) {G0,W7,D3,L2,V1,M2} { ! aNaturalNumber0( X ), sdtpldt0( X
% 0.75/1.33 , sz00 ) = X }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := X
% 0.75/1.33 end
% 0.75/1.33 permutation0:
% 0.75/1.33 0 ==> 0
% 0.75/1.33 1 ==> 1
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 subsumption: (27) {G0,W14,D3,L5,V3,M5} I { ! aNaturalNumber0( X ), !
% 0.75/1.33 aNaturalNumber0( Y ), ! aNaturalNumber0( Z ), ! sdtpldt0( X, Z ) = Y,
% 0.75/1.33 sdtlseqdt0( X, Y ) }.
% 0.75/1.33 parent0: (2421) {G0,W14,D3,L5,V3,M5} { ! aNaturalNumber0( X ), !
% 0.75/1.33 aNaturalNumber0( Y ), ! aNaturalNumber0( Z ), ! sdtpldt0( X, Z ) = Y,
% 0.75/1.33 sdtlseqdt0( X, Y ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := X
% 0.75/1.33 Y := Y
% 0.75/1.33 Z := Z
% 0.75/1.33 end
% 0.75/1.33 permutation0:
% 0.75/1.33 0 ==> 0
% 0.75/1.33 1 ==> 1
% 0.75/1.33 2 ==> 2
% 0.75/1.33 3 ==> 3
% 0.75/1.33 4 ==> 4
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 subsumption: (31) {G0,W2,D2,L1,V0,M1} I { aNaturalNumber0( xm ) }.
% 0.75/1.33 parent0: (2425) {G0,W2,D2,L1,V0,M1} { aNaturalNumber0( xm ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 end
% 0.75/1.33 permutation0:
% 0.75/1.33 0 ==> 0
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 subsumption: (32) {G0,W3,D2,L1,V0,M1} I { ! sdtlseqdt0( xm, xm ) }.
% 0.75/1.33 parent0: (2426) {G0,W3,D2,L1,V0,M1} { ! sdtlseqdt0( xm, xm ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 end
% 0.75/1.33 permutation0:
% 0.75/1.33 0 ==> 0
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 eqswap: (2964) {G0,W14,D3,L5,V3,M5} { ! Z = sdtpldt0( X, Y ), !
% 0.75/1.33 aNaturalNumber0( X ), ! aNaturalNumber0( Z ), ! aNaturalNumber0( Y ),
% 0.75/1.33 sdtlseqdt0( X, Z ) }.
% 0.75/1.33 parent0[3]: (27) {G0,W14,D3,L5,V3,M5} I { ! aNaturalNumber0( X ), !
% 0.75/1.33 aNaturalNumber0( Y ), ! aNaturalNumber0( Z ), ! sdtpldt0( X, Z ) = Y,
% 0.75/1.33 sdtlseqdt0( X, Y ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := X
% 0.75/1.33 Y := Z
% 0.75/1.33 Z := Y
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 resolution: (2968) {G1,W12,D3,L4,V2,M4} { ! X = sdtpldt0( Y, sz00 ), !
% 0.75/1.33 aNaturalNumber0( Y ), ! aNaturalNumber0( X ), sdtlseqdt0( Y, X ) }.
% 0.75/1.33 parent0[3]: (2964) {G0,W14,D3,L5,V3,M5} { ! Z = sdtpldt0( X, Y ), !
% 0.75/1.33 aNaturalNumber0( X ), ! aNaturalNumber0( Z ), ! aNaturalNumber0( Y ),
% 0.75/1.33 sdtlseqdt0( X, Z ) }.
% 0.75/1.33 parent1[0]: (1) {G0,W2,D2,L1,V0,M1} I { aNaturalNumber0( sz00 ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := Y
% 0.75/1.33 Y := sz00
% 0.75/1.33 Z := X
% 0.75/1.33 end
% 0.75/1.33 substitution1:
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 paramod: (2974) {G1,W12,D2,L5,V2,M5} { ! X = Y, ! aNaturalNumber0( Y ), !
% 0.75/1.33 aNaturalNumber0( Y ), ! aNaturalNumber0( X ), sdtlseqdt0( Y, X ) }.
% 0.75/1.33 parent0[1]: (8) {G0,W7,D3,L2,V1,M2} I { ! aNaturalNumber0( X ), sdtpldt0( X
% 0.75/1.33 , sz00 ) ==> X }.
% 0.75/1.33 parent1[0; 3]: (2968) {G1,W12,D3,L4,V2,M4} { ! X = sdtpldt0( Y, sz00 ), !
% 0.75/1.33 aNaturalNumber0( Y ), ! aNaturalNumber0( X ), sdtlseqdt0( Y, X ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := Y
% 0.75/1.33 end
% 0.75/1.33 substitution1:
% 0.75/1.33 X := X
% 0.75/1.33 Y := Y
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 eqswap: (2975) {G1,W12,D2,L5,V2,M5} { ! Y = X, ! aNaturalNumber0( Y ), !
% 0.75/1.33 aNaturalNumber0( Y ), ! aNaturalNumber0( X ), sdtlseqdt0( Y, X ) }.
% 0.75/1.33 parent0[0]: (2974) {G1,W12,D2,L5,V2,M5} { ! X = Y, ! aNaturalNumber0( Y )
% 0.75/1.33 , ! aNaturalNumber0( Y ), ! aNaturalNumber0( X ), sdtlseqdt0( Y, X ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := X
% 0.75/1.33 Y := Y
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 factor: (2976) {G1,W10,D2,L4,V2,M4} { ! X = Y, ! aNaturalNumber0( X ), !
% 0.75/1.33 aNaturalNumber0( Y ), sdtlseqdt0( X, Y ) }.
% 0.75/1.33 parent0[1, 2]: (2975) {G1,W12,D2,L5,V2,M5} { ! Y = X, ! aNaturalNumber0( Y
% 0.75/1.33 ), ! aNaturalNumber0( Y ), ! aNaturalNumber0( X ), sdtlseqdt0( Y, X )
% 0.75/1.33 }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := Y
% 0.75/1.33 Y := X
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 subsumption: (1994) {G1,W10,D2,L4,V2,M4} R(27,1);d(8) { ! aNaturalNumber0(
% 0.75/1.33 X ), ! aNaturalNumber0( Y ), sdtlseqdt0( X, Y ), ! X = Y }.
% 0.75/1.33 parent0: (2976) {G1,W10,D2,L4,V2,M4} { ! X = Y, ! aNaturalNumber0( X ), !
% 0.75/1.33 aNaturalNumber0( Y ), sdtlseqdt0( X, Y ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := X
% 0.75/1.33 Y := Y
% 0.75/1.33 end
% 0.75/1.33 permutation0:
% 0.75/1.33 0 ==> 3
% 0.75/1.33 1 ==> 0
% 0.75/1.33 2 ==> 1
% 0.75/1.33 3 ==> 2
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 eqswap: (2979) {G1,W10,D2,L4,V2,M4} { ! Y = X, ! aNaturalNumber0( X ), !
% 0.75/1.33 aNaturalNumber0( Y ), sdtlseqdt0( X, Y ) }.
% 0.75/1.33 parent0[3]: (1994) {G1,W10,D2,L4,V2,M4} R(27,1);d(8) { ! aNaturalNumber0( X
% 0.75/1.33 ), ! aNaturalNumber0( Y ), sdtlseqdt0( X, Y ), ! X = Y }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := X
% 0.75/1.33 Y := Y
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 factor: (2980) {G1,W8,D2,L3,V1,M3} { ! X = X, ! aNaturalNumber0( X ),
% 0.75/1.33 sdtlseqdt0( X, X ) }.
% 0.75/1.33 parent0[1, 2]: (2979) {G1,W10,D2,L4,V2,M4} { ! Y = X, ! aNaturalNumber0( X
% 0.75/1.33 ), ! aNaturalNumber0( Y ), sdtlseqdt0( X, Y ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := X
% 0.75/1.33 Y := X
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 eqrefl: (2981) {G0,W5,D2,L2,V1,M2} { ! aNaturalNumber0( X ), sdtlseqdt0( X
% 0.75/1.33 , X ) }.
% 0.75/1.33 parent0[0]: (2980) {G1,W8,D2,L3,V1,M3} { ! X = X, ! aNaturalNumber0( X ),
% 0.75/1.33 sdtlseqdt0( X, X ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := X
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 subsumption: (2030) {G2,W5,D2,L2,V1,M2} F(1994);q { ! aNaturalNumber0( X )
% 0.75/1.33 , sdtlseqdt0( X, X ) }.
% 0.75/1.33 parent0: (2981) {G0,W5,D2,L2,V1,M2} { ! aNaturalNumber0( X ), sdtlseqdt0(
% 0.75/1.33 X, X ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 X := X
% 0.75/1.33 end
% 0.75/1.33 permutation0:
% 0.75/1.33 0 ==> 0
% 0.75/1.33 1 ==> 1
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 resolution: (2982) {G1,W2,D2,L1,V0,M1} { ! aNaturalNumber0( xm ) }.
% 0.75/1.33 parent0[0]: (32) {G0,W3,D2,L1,V0,M1} I { ! sdtlseqdt0( xm, xm ) }.
% 0.75/1.33 parent1[1]: (2030) {G2,W5,D2,L2,V1,M2} F(1994);q { ! aNaturalNumber0( X ),
% 0.75/1.33 sdtlseqdt0( X, X ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 end
% 0.75/1.33 substitution1:
% 0.75/1.33 X := xm
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 resolution: (2983) {G1,W0,D0,L0,V0,M0} { }.
% 0.75/1.33 parent0[0]: (2982) {G1,W2,D2,L1,V0,M1} { ! aNaturalNumber0( xm ) }.
% 0.75/1.33 parent1[0]: (31) {G0,W2,D2,L1,V0,M1} I { aNaturalNumber0( xm ) }.
% 0.75/1.33 substitution0:
% 0.75/1.33 end
% 0.75/1.33 substitution1:
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 subsumption: (2392) {G3,W0,D0,L0,V0,M0} R(2030,32);r(31) { }.
% 0.75/1.33 parent0: (2983) {G1,W0,D0,L0,V0,M0} { }.
% 0.75/1.33 substitution0:
% 0.75/1.33 end
% 0.75/1.33 permutation0:
% 0.75/1.33 end
% 0.75/1.33
% 0.75/1.33 Proof check complete!
% 0.75/1.33
% 0.75/1.33 Memory use:
% 0.75/1.33
% 0.75/1.33 space for terms: 36631
% 0.75/1.33 space for clauses: 142613
% 0.75/1.33
% 0.75/1.33
% 0.75/1.33 clauses generated: 14075
% 0.75/1.33 clauses kept: 2393
% 0.75/1.33 clauses selected: 110
% 0.75/1.33 clauses deleted: 42
% 0.75/1.33 clauses inuse deleted: 17
% 0.75/1.33
% 0.75/1.33 subsentry: 16792
% 0.75/1.33 literals s-matched: 8490
% 0.75/1.33 literals matched: 7407
% 0.75/1.33 full subsumption: 4960
% 0.75/1.33
% 0.75/1.33 checksum: -1934581018
% 0.75/1.33
% 0.75/1.33
% 0.75/1.33 Bliksem ended
%------------------------------------------------------------------------------