TSTP Solution File: NUM448+1 by DarwinFM---1.4.5

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : DarwinFM---1.4.5
% Problem  : NUM448+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Mon Jul 18 07:36:19 EDT 2022

% Result   : CounterSatisfiable 0.12s 0.38s
% Output   : FiniteModel 0.12s
% Verified : 
% SZS Type : FiniteModel
%            Domain size           :    2

% Comments : 
%------------------------------------------------------------------------------
fof(interpretation_domain,fi_domain,
    ! [X] :
      ( X = e1
      | X = e2 ) ).

fof(interpretation_domain_distinct,fi_domain,
    e1 != e2 ).

fof(interpretation_terms,fi_functors,
    ( cS1395 = e1
    & cS2043 = e1
    & cS2076 = e1
    & ! [X0,X1] : esk10_2(X0,X1) = e1
    & ! [X0,X1,X2] : esk11_3(X0,X1,X2) = e1
    & ! [X0,X1] : esk12_2(X0,X1) = e1
    & ! [X0] : esk13_1(X0) = e1
    & ! [X0] : esk14_1(X0) = e1
    & ! [X0] : esk15_1(X0) = e1
    & ! [X0] : esk16_1(X0) = e1
    & ! [X0,X1] : esk1_2(X0,X1) = e1
    & ! [X0] : esk2_1(X0) = e1
    & ! [X0,X1] : esk3_2(X0,X1) = e1
    & ! [X0,X1,X2] : esk4_3(X0,X1,X2) = e1
    & ! [X0,X1,X2] : esk5_3(X0,X1,X2) = e1
    & ! [X0] : esk6_1(X0) = e1
    & ! [X0,X1,X2] : esk7_3(X0,X1,X2) = e1
    & ! [X0,X1] : esk8_2(X0,X1) = e1
    & ! [X0,X1] : esk9_2(X0,X1) = e1
    & ! [X0] : sbsmnsldt0(X0) = e1
    & ! [X0,X1] : sdtasdt0(X0,X1) = e1
    & ! [X0,X1] : sdtbsmnsldt0(X0,X1) = e1
    & ! [X0,X1] : sdtpldt0(X0,X1) = e1
    & ! [X0,X1] : sdtslmnbsdt0(X0,X1) = e1
    & ! [X0] : smndt0(X0) = e1
    & ! [X0,X1] :
        ( stldt0(X0) = X1
      <=> ( ( X1 = e1
            & X0 != e1 )
          | ( X0 = e1
            & X1 = e2 ) ) )
    & sz00 = e1
    & sz10 = e1
    & ! [X0,X1] : szAzrzSzezqlpdtcmdtrp0(X0,X1) = e1
    & xS = e1 ) ).

fof(interpretation_atoms,fi_predicates,
    ( ! [X0,X1] :
        ( aDivisorOf0(X0,X1)
      <=> $false )
    & ! [X0,X1] :
        ( aElementOf0(X0,X1)
      <=> $false )
    & ! [X0] :
        ( aInteger0(X0)
      <=> X0 = e1 )
    & ! [X0] :
        ( aSet0(X0)
      <=> $false )
    & ! [X0,X1] :
        ( aSubsetOf0(X0,X1)
      <=> $false )
    & ! [X0] :
        ( isClosed0(X0)
      <=> $false )
    & ! [X0] :
        ( isFinite0(X0)
      <=> $false )
    & ! [X0] :
        ( isOpen0(X0)
      <=> $false )
    & ! [X0] :
        ( isPrime0(X0)
      <=> $false )
    & ! [X0,X1,X2] :
        ( sdteqdtlpzmzozddtrp0(X0,X1,X2)
      <=> $false ) ) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem  : NUM448+1 : TPTP v8.1.0. Released v4.0.0.
% 0.06/0.12  % Command  : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s
% 0.12/0.32  % Computer : n017.cluster.edu
% 0.12/0.32  % Model    : x86_64 x86_64
% 0.12/0.32  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.32  % Memory   : 8042.1875MB
% 0.12/0.32  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.32  % CPULimit : 300
% 0.12/0.32  % DateTime : Tue Jul  5 03:53:13 EDT 2022
% 0.12/0.32  % CPUTime  : 
% 0.12/0.32  Defaulting to tptp format.
% 0.12/0.38  SZS status CounterSatisfiable for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.12/0.38  
% 0.12/0.38  MODEL (TPTP):
% 0.12/0.38  SZS output start FiniteModel for /export/starexec/sandbox/benchmark/theBenchmark.p
% See solution above
%------------------------------------------------------------------------------