TSTP Solution File: NUM430+3 by SnakeForV-SAT---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SnakeForV-SAT---1.0
% Problem  : NUM430+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_sat --cores 0 -t %d %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Aug 31 18:05:04 EDT 2022

% Result   : Theorem 0.18s 0.48s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    4
% Syntax   : Number of formulae    :   14 (   4 unt;   0 def)
%            Number of atoms       :   46 (  16 equ)
%            Maximal formula atoms :    8 (   3 avg)
%            Number of connectives :   40 (   8   ~;   3   |;  27   &)
%                                         (   0 <=>;   2  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    8 (   4 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    5 (   3 usr;   1 prp; 0-3 aty)
%            Number of functors    :    9 (   9 usr;   6 con; 0-2 aty)
%            Number of variables   :   11 (   3   !;   8   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(f137,plain,
    $false,
    inference(subsumption_resolution,[],[f136,f107]) ).

fof(f107,plain,
    aInteger0(sK0),
    inference(cnf_transformation,[],[f71]) ).

fof(f71,plain,
    ( aDivisorOf0(xq,sdtpldt0(xa,smndt0(xb)))
    & sdteqdtlpzmzozddtrp0(xb,xc,xq)
    & aDivisorOf0(xq,sdtpldt0(xb,smndt0(xc)))
    & aInteger0(sK0)
    & sdtpldt0(xb,smndt0(xc)) = sdtasdt0(xq,sK0)
    & sdteqdtlpzmzozddtrp0(xa,xb,xq)
    & aInteger0(sK1)
    & sdtpldt0(xa,smndt0(xb)) = sdtasdt0(xq,sK1) ),
    inference(skolemisation,[status(esa),new_symbols(skolem,[sK0,sK1])],[f31,f70,f69]) ).

fof(f69,plain,
    ( ? [X0] :
        ( aInteger0(X0)
        & sdtasdt0(xq,X0) = sdtpldt0(xb,smndt0(xc)) )
   => ( aInteger0(sK0)
      & sdtpldt0(xb,smndt0(xc)) = sdtasdt0(xq,sK0) ) ),
    introduced(choice_axiom,[]) ).

fof(f70,plain,
    ( ? [X1] :
        ( aInteger0(X1)
        & sdtpldt0(xa,smndt0(xb)) = sdtasdt0(xq,X1) )
   => ( aInteger0(sK1)
      & sdtpldt0(xa,smndt0(xb)) = sdtasdt0(xq,sK1) ) ),
    introduced(choice_axiom,[]) ).

fof(f31,plain,
    ( aDivisorOf0(xq,sdtpldt0(xa,smndt0(xb)))
    & sdteqdtlpzmzozddtrp0(xb,xc,xq)
    & aDivisorOf0(xq,sdtpldt0(xb,smndt0(xc)))
    & ? [X0] :
        ( aInteger0(X0)
        & sdtasdt0(xq,X0) = sdtpldt0(xb,smndt0(xc)) )
    & sdteqdtlpzmzozddtrp0(xa,xb,xq)
    & ? [X1] :
        ( aInteger0(X1)
        & sdtpldt0(xa,smndt0(xb)) = sdtasdt0(xq,X1) ) ),
    inference(rectify,[],[f23]) ).

fof(f23,axiom,
    ( sdteqdtlpzmzozddtrp0(xa,xb,xq)
    & aDivisorOf0(xq,sdtpldt0(xb,smndt0(xc)))
    & aDivisorOf0(xq,sdtpldt0(xa,smndt0(xb)))
    & ? [X0] :
        ( aInteger0(X0)
        & sdtasdt0(xq,X0) = sdtpldt0(xb,smndt0(xc)) )
    & ? [X0] :
        ( sdtasdt0(xq,X0) = sdtpldt0(xa,smndt0(xb))
        & aInteger0(X0) )
    & sdteqdtlpzmzozddtrp0(xb,xc,xq) ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',m__853) ).

fof(f136,plain,
    ~ aInteger0(sK0),
    inference(equality_resolution,[],[f134]) ).

fof(f134,plain,
    ! [X0] :
      ( sdtasdt0(xq,X0) != sdtasdt0(xq,sK0)
      | ~ aInteger0(X0) ),
    inference(forward_demodulation,[],[f83,f106]) ).

fof(f106,plain,
    sdtpldt0(xb,smndt0(xc)) = sdtasdt0(xq,sK0),
    inference(cnf_transformation,[],[f71]) ).

fof(f83,plain,
    ! [X0] :
      ( sdtasdt0(xq,X0) != sdtpldt0(xb,smndt0(xc))
      | ~ aInteger0(X0) ),
    inference(cnf_transformation,[],[f45]) ).

fof(f45,plain,
    ! [X0] :
      ( ~ aInteger0(X0)
      | sdtasdt0(xq,X0) != sdtpldt0(xb,smndt0(xc)) ),
    inference(ennf_transformation,[],[f26]) ).

fof(f26,negated_conjecture,
    ~ ? [X0] :
        ( aInteger0(X0)
        & sdtasdt0(xq,X0) = sdtpldt0(xb,smndt0(xc)) ),
    inference(negated_conjecture,[],[f25]) ).

fof(f25,conjecture,
    ? [X0] :
      ( aInteger0(X0)
      & sdtasdt0(xq,X0) = sdtpldt0(xb,smndt0(xc)) ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',m__) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem    : NUM430+3 : TPTP v8.1.0. Released v4.0.0.
% 0.10/0.13  % Command    : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_sat --cores 0 -t %d %s
% 0.13/0.33  % Computer : n027.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit   : 300
% 0.13/0.33  % WCLimit    : 300
% 0.13/0.33  % DateTime   : Tue Aug 30 06:46:31 EDT 2022
% 0.13/0.33  % CPUTime    : 
% 0.18/0.47  % (5311)ott+4_1:1_av=off:bd=off:nwc=5.0:s2a=on:s2at=2.0:slsq=on:slsqc=2:slsql=off:slsqr=1,2:sp=frequency:i=37:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/37Mi)
% 0.18/0.48  % (5311)First to succeed.
% 0.18/0.48  % (5311)Refutation found. Thanks to Tanya!
% 0.18/0.48  % SZS status Theorem for theBenchmark
% 0.18/0.48  % SZS output start Proof for theBenchmark
% See solution above
% 0.18/0.48  % (5311)------------------------------
% 0.18/0.48  % (5311)Version: Vampire 4.7 (commit 807e37dd9 on 2022-08-23 09:55:27 +0200)
% 0.18/0.48  % (5311)Linked with Z3 4.8.13.0 f03d756e086f81f2596157241e0decfb1c982299 z3-4.8.4-5390-gf03d756e0
% 0.18/0.48  % (5311)Termination reason: Refutation
% 0.18/0.48  
% 0.18/0.48  % (5311)Memory used [KB]: 1023
% 0.18/0.48  % (5311)Time elapsed: 0.108 s
% 0.18/0.48  % (5311)Instructions burned: 4 (million)
% 0.18/0.48  % (5311)------------------------------
% 0.18/0.49  % (5311)------------------------------
% 0.18/0.49  % (5308)Success in time 0.143 s
%------------------------------------------------------------------------------