TSTP Solution File: NUM423+3 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM423+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:26:02 EDT 2022

% Result   : Theorem 0.20s 0.45s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   12 (   7 unt;   0 nHn;  12 RR)
%            Number of literals    :   17 (   0 equ;  11 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    7 (   7 usr;   4 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    aInteger0(sz00),
    file('NUM423+3.p',unknown),
    [] ).

cnf(3,axiom,
    aInteger0(xa),
    file('NUM423+3.p',unknown),
    [] ).

cnf(4,axiom,
    aInteger0(xq),
    file('NUM423+3.p',unknown),
    [] ).

cnf(14,axiom,
    ( ~ aInteger0(u)
    | equal(sdtasdt0(u,sz00),sz00) ),
    file('NUM423+3.p',unknown),
    [] ).

cnf(16,axiom,
    ( ~ aInteger0(u)
    | equal(sdtpldt0(u,smndt0(u)),sz00) ),
    file('NUM423+3.p',unknown),
    [] ).

cnf(24,axiom,
    ( ~ aInteger0(u)
    | ~ equal(sdtasdt0(xq,u),sdtpldt0(xa,smndt0(xa))) ),
    file('NUM423+3.p',unknown),
    [] ).

cnf(42,plain,
    ~ equal(sdtasdt0(xq,sz00),sdtpldt0(xa,smndt0(xa))),
    inference(res,[status(thm),theory(equality)],[1,24]),
    [iquote('0:Res:1.0,24.0')] ).

cnf(57,plain,
    ( ~ aInteger0(xq)
    | ~ equal(sdtpldt0(xa,smndt0(xa)),sz00) ),
    inference(spl,[status(thm),theory(equality)],[14,42]),
    [iquote('0:SpL:14.1,42.0')] ).

cnf(58,plain,
    ~ equal(sdtpldt0(xa,smndt0(xa)),sz00),
    inference(ssi,[status(thm)],[57,4]),
    [iquote('0:SSi:57.0,4.0')] ).

cnf(71,plain,
    ( ~ aInteger0(xa)
    | ~ equal(sz00,sz00) ),
    inference(spl,[status(thm),theory(equality)],[16,58]),
    [iquote('0:SpL:16.1,58.0')] ).

cnf(74,plain,
    ~ aInteger0(xa),
    inference(obv,[status(thm),theory(equality)],[71]),
    [iquote('0:Obv:71.1')] ).

cnf(75,plain,
    $false,
    inference(ssi,[status(thm)],[74,3]),
    [iquote('0:SSi:74.0,3.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : NUM423+3 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n015.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Tue Jul  5 18:46:18 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.20/0.45  
% 0.20/0.45  SPASS V 3.9 
% 0.20/0.45  SPASS beiseite: Proof found.
% 0.20/0.45  % SZS status Theorem
% 0.20/0.45  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.20/0.45  SPASS derived 32 clauses, backtracked 0 clauses, performed 0 splits and kept 45 clauses.
% 0.20/0.45  SPASS allocated 97737 KBytes.
% 0.20/0.45  SPASS spent	0:00:00.10 on the problem.
% 0.20/0.45  		0:00:00.04 for the input.
% 0.20/0.45  		0:00:00.03 for the FLOTTER CNF translation.
% 0.20/0.45  		0:00:00.00 for inferences.
% 0.20/0.45  		0:00:00.00 for the backtracking.
% 0.20/0.45  		0:00:00.00 for the reduction.
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  Here is a proof with depth 3, length 12 :
% 0.20/0.45  % SZS output start Refutation
% See solution above
% 0.20/0.45  Formulae used in the proof : mIntZero m__671 mMulZero mAddNeg m__
% 0.20/0.45  
%------------------------------------------------------------------------------